Answer:
When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line.
Explanation:
The reaction 2CH4(g)⇌C2H2(g)+3H2(g) has an equilibrium constant of K = 0.154. If 6.30 mol of CH4, 4.20 mol of C2H2, and 11.15 mol of H2 are added to a reaction vessel with a volume of 6.00 L , what net reaction will occur?
Answer:
C₂H₂ + 3H₂ ⟶ 2CH₄
Explanation:
The initial concentrations are:
[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹
[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹
[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹
2CH₄ ⇌ C₂H₂ + 3H₂
I/mol·L⁻¹: 1.05 0.700 1.858
[tex]Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07[/tex]
Q > K
That means we have too many products.
The reaction will go to the left to get rid of the excess products.
C₂H₂ + 3H₂ ⟶ 2CH₄
According to Boyle's law, how would you reduce the volume of a gas?
a) by decreasing its temperature
b) by decreasing its pressure
c) by increasing its pressure
Final answer:
According to Boyle's law, the volume of a gas can be reduced by increasing its pressure, assuming constant temperature and amount of gas. This relationship demonstrates that volume and pressure are inversely proportional to each other. The correct option is c.
Explanation:
According to Boyle's law, to reduce the volume of a gas, one would need to increase its pressure, provided the temperature and the amount of the gas remain constant. Boyle's law explains that the volume of a gas is inversely proportional to its pressure; thus, decreasing the volume leads to an increase in pressure. This relationship is visually represented in graphs that plot pressure against volume.
When Boyle's law is applied to a specific amount of gas at a constant temperature, pressing down on the plunger of an airtight syringe will decrease the volume of the gas and simultaneously increase its pressure. Conversely, pulling the plunger out will increase the volume and the pressure will decrease accordingly.
I WILL MARK THE BRAINILEST As a roller coaster goes down hill,
Question 4 options:
kinetic energy is converted into potential energy
potential energy is converted into Kinetic energy
electrical energy is converted into potential energy
potential energy is convered into electrical energy
Question 5 (1 point)
You pull into the gas station to fill up your car with gas. During this time the car has what kind of energy?
Question 5 options:
Kinetic energy only
both potential and kinetic energy
potential energy only
Neither
Question 6 (1 point)
The maxium kinetic energy of a box sliding from the top of the ramp to the bottom of the ramp is.
Question 6 options:
at the top
at the bottom
in the middle
stored equality with all locations
Answer:
4: B
5: C
6: B
Explanation:
Q4) Potential Energy is changed into Kinetic Energy
Q5) Potential Energy only
Q6)At the bottom
Hope it helps :)
How do the small bodies in the solar system differ from one another?
The solar system has small bodies categorized mainly as asteroids and comets. Asteroids are rocky bodies found mostly between Mars and Jupiter, while comets are made of frozen gases and reside within distant, cooler regions. Other bodies include moons and ring systems around giant planets.
Explanation:The solar system consists of various small bodies, each categorized due to their composition and location. Primarily, there are two classes, asteroids and comets.
Asteroids are primarily rocky bodies that orbit the Sun and are mostly found in the space between Mars and Jupiter, although a few cross the orbits of planets like Earth. These are remnants from when the solar system was forming, even predating the planets. Some small moons are actually captured asteroids - the moons of Mars, for instance.
Another class, comets, are primarily made of various frozen gases such as water, carbon dioxide, and carbon monoxide. Like asteroids, comets are remnants from the formation of the solar system. However, they were formed in distant, cooler regions of the solar system and continue to remain in these regions.
Besides these, we also have moons that orbit planets, and ring systems around the giant planets which are made up of countless small bodies, and still-smaller objects with masses less than about 1/100th the mass of the Sun, which are also called planets.
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What is the inverse molar mass of carbon
Final answer:
The inverse molar mass of carbon, based on its average molar mass of 12.011 g/mol, is approximately 0.08326 mol/g. This value is useful for calculating the number of moles in a given mass of carbon.
Explanation:
The inverse molar mass of carbon refers to the number of moles per gram rather than grams per mole. Since the average molar mass of carbon is 12.011 g/mol, the inverse molar mass would be 1 divided by 12.011 g/mol. Conducting this calculation provides the inverse:
1 / 12.011 g/mol ≈ 0.08326 mol/g
This value represents the number of moles of carbon present in one gram of carbon. The fractional abundance of isotopes does not affect this conversion, as it is based on the average molar mass listed on the periodic table.
When performing chemical calculations, the inverse molar mass is useful for finding the amount of substance when you have a given mass. In this case, the inverse molar mass of carbon can be used to quickly determine how many moles of carbon there are in a sample by simply multiplying the mass of the sample by 0.08326 mol/g.
Final answer:
The inverse molar mass of carbon is approximately 0.08326 mol/g, which is calculated by taking the reciprocal of the average molar mass of carbon (12.011 g/mol).
Explanation:
The inverse molar mass of carbon refers to the reciprocal of the molar mass of carbon. Since the average molar mass of carbon is listed as 12.011 g/mol, the inverse molar mass would be 1 divided by 12.011 g/mol. Therefore, the inverse molar mass of carbon is approximately 0.08326 mol/g.
It's important to remember that when calculating the inverse molar mass, we are essentially determining how many moles of carbon are present in one gram. This value can be useful in various chemistry calculations, particularly in stoichiometry where conversion between mass and moles is frequently required.
In what type of reaction or process does heat flow into the system?
Answer:
Endothermic
Explanation:
Answer:
Endothermic
Explanation:
Correct on edge!
excuse me what is 6=2(y+2) ?
Distribute the 2 through the parentheses
on the right side of the equation.
2(y) is 2y and 2(2) is 4.
So the problem now reads 6 = 2y + 4.
Now we can subtract 4 from both
sides of the equation to get 2 = 2y.
Now divide both sides of the
equation by 2 and 1 = y.
Chemistry Convert the following measurement
Answer:
Explanation:
8.97 x 10⁵ [tex]\frac{m}{s^2}[/tex]
= 8.97 x 10² x 10⁵ [tex]\frac{cm}{s^2}[/tex]
= 8.97 x 10² x 10⁵cm /(10³ms)²
= 8.97 x10 x 10⁶cm / 10⁶ ms²
= .897 x 10² [tex]\frac{cm}{ms^2}[/tex]
89.7 cm/ms^2
Explanation:
1 m/s^2 = 0.0001 cm/ms^2
So, 8.97 x 10^5 m/s^2 = 89.7 cm/ms^2
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Look at the chart showing the daily stock data for WebTrend Inc.’s stock over the past month, and read this stock analyst’s view of the stock:
10 points !
Stock analyst: There is a downward trend of the data with the peak price achieved on March 13. Investors are interested in WebTrend Inc. as demonstrated by the increase in trading volume.
Which statement is a fair conclusion based on the chart and the analyst’s comments about the WebTrend stock?
A.
The stock price increased and volume decreased on April 3.
B.
One month is not enough time to determine whether the price is at a low.
C.
The price has been falling, so an investor can assume it will begin to rise again soon.
D.
When the price change is negative for the day, an investor can assume the trading volume will decrease.
Answer: The answer to this question is B if you are taking the test on Plato.
Answer:
One month is not enough time to determine whether the price is at a low.
Explanation:
The equation to perform the calculation is shown
below.
3.45 mol KMnO, X
8 mol H2O
2 mol KMnO4
Did you set up the equation correctly?
0
Yes, and I got the correct answer.
Yes, but I got the wrong answer because I
made a mathematical error.
No, I did rt set up the equation correctly.
Answer: yes, and I got the correct answer
Explanation:
Yes, the equation has been set up correctly and the right answer is obtain. Therefore, option A is correct.
What is balance equation ?The balance equation is defined as when the total mass of the reactant is exactly equal to the total mass of the product. By the law of conservation of mass for balance equation both reactant and products mass are same.
The given equation for the reaction of potassium permanganate has been given as follows :
2 KMnO₄ + 16 HCl ⇒ 2MnCl₂ + 5Cl₂ + 8H₂O
The amount of water formed from 3.45 mol potassium per magnate has been given as follows:
2mol KMnO₄ = 8 mole of H₂O
3.45 mol KMnO₄ = 3.45 × 8/2 mole of H₂O
The given equation has been similar to the equation set up. Hence,the equation has been set up correctly and got the answer right.
Thus, option A is correct.
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Which is the term for the different forms of a gene for a given trait?
o phenotype
recessive
alleles
O homozygous
The term for the different forms of a gene for a given trait is alleles. Therefore, option C is correct.
What are alleles ?Leading texts on genetics and evolution define an allele as a different variation of the same sequence of nucleotides at the same location on a long DNA molecule. "The chromosomal or genomic location of a gene or any other genetic element is called a locus, and alternative DNA sequences at a locus are called alleles.
Any one of two or more genes that may alternately appear at a specific position on a chromosome is known as an allele, also known as an allelomorph. The expression of a specific trait may be influenced by a single allele, many alleles, or pairs of alleles.
A kind of gene is an allele. Individual qualities are determined by genes. Alleles play a part in the diversity of phenotypic expression.
Thus, option C is correct.
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A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the ammonia?
Answer:
The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
Explanation:
Using the formula
Ca Va = Cb Vb
Cb = 0.32 M
Vb = 50 mL = 50/1000 = 0.050L
Ca = 0.5 M
Va =?
Substituting for Va in the equation, we obtain:
Va = Cb Vb / Ca
Va = 0.32 * 0.05 / 0.5
Va = 0.016 / 0.5
Va = 0.032 L
The volume of HCl to be added to completely react with the ammonia is 0.032 L or 32mL
Sulfurous acid, H2SO3, breaks down into water (H20) and sulfur dioxide (SO2).
If only one molecule of sulfurous acid was involved in a chemical reaction, how many sulfur (S) atoms would be in the
products?
Answer:
1 atom of sulfur
Explanation:
Answer:
1 atom and sulfur
Explanation:
la la lalalala
HELP!!!
While taking his clothes out of the dryer, Charles finds a sock clinging to his sweater.
What is the best explanation for this common phenomenon?
A. In the dryer, both the sock and the sweater lost electrons.
B. In the dryer, both the sock and the sweater gained electrons.
C. In the dryer, either the sock or the sweater gained electrons while the other item lost electrons.
D. The cause of static cling is an unsolved scientific mystery.
Answer:
C. In the dryer, either the sock or the sweater gained electrons while the other item lost electrons.
The best explanation for the phenomenon of a sock clinging to a sweater in the dryer is that in the dryer, either the sock or the sweater gained electrons while the other item lost electrons, option C.
What is static electricity ?Static electricity occurs when two objects with different electrical charges come into contact and then separate. In the dryer, friction between the clothes causes electrons to be transferred from one surface to another, resulting in an imbalance of electrical charges.
The sock and the sweater have different tendencies to gain or lose electrons, which can create a charge imbalance that causes them to be attracted to each other.
This attraction, known as static cling, can be seen in other situations where two objects with different electrical charges come into contact, such as when you rub a balloon on your hair and it sticks to a wall. Where one gets positive charge and the other getting negative charge.
Therefore, option C is correct.
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Why are the optimum conditions for the Haber process a temperature of 450°C and pressure of 200 atmospheres?
Answer:
See explanation.
Explanation:
Hello,
Haber process is defined as the widely acknowledged productive process of ammonia by the reaction:
[tex]N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)[/tex]
Which is carried out in gaseous phase. Thus, by means of the Le Chatelier's principle, it is possible to know that its standard enthalpy of reaction is -45.90 kJ/mol (NIST webbook) for which it is an exothermic chemical reaction, for that reason less ammonia will be produced at high temperature, nonetheless, the temperature should not be too low since the reaction rate significantly decrease, therefore, the optimum found temperature is 450 °C.
Moreover, since there are more moles (3+1=4) at the reactants and less moles at the products (2), increasing the pressure of the reaction increases the yield of ammonia, nonetheless, higher pressures involve the purchasing of more expensive equipment to withstand the high-pressures, for that reason, the best found pressure has been set as 200 atm.
Best regards.
Answer:
Lower temperature and higher pressure favours the forward reaction in the Haber process
Explanation:
The equation of the Haber process for the production of ammonia is;
3H2(g) + N2(g) ⇄2NH3(g)
The Haber process involves the combination of hydrogen gas and nitrogen gas in a ratio of 3:1.
In the Haber process, the forward reaction is exothermic, hence the reverse reaction is endothermic. The implication of this is, as temperature is increased, the position of equilibrium moves to the left, and the yield of ammonia decreases. Decrease in temperature will favour the forward reaction. Hence the process is operated at a lower temperature of 450°C.
Secondly, the total number of volumes on the reactant side is 4 volumes whereas the total number of volumes on the product side is 2 volumes. Increase in pressure will favour the direction producing a lesser total volume. Hence increasing the pressure to about 200 atmospheres will favour the forward reaction thus more ammonia is produced
If a neutral compound is composed of carbon and hydrogen and you know that it has exactly 2 carbons connected by a double bond, how many hydrogens will the compound have?
A. 4
B. 8
C. 2
D. 6
Answer: The answer is A. 4
Explanation: I just had this question on a quiz
The compound with two carbon atoms connected by a double bond is an alkene known as ethene or ethylene, and it has 4 hydrogens. The general formula for alkenes (CnH2n) confirms this, as 2 carbons (n=2) would correspond to 4 hydrogens.
Explanation:In the world of organic chemistry, a compound with two carbon atoms connected by a double bond is known as an alkene. The simplest alkene is ethene (also known as ethylene), which consists of 2 carbon (C) atoms connected by a double bond and 4 hydrogen (H) molecules. According to the general formula for alkenes, which is CnH2n, if n=2 (representing the 2 carbon atoms), the corresponding number of hydrogen atoms is 2*2, which equals to 4. Therefore, the correct answer is A. 4.
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How many grams are there in 2.50 moles of potassium nitrate KNO3
Answer: 252.77 g of potassium nitrate
Explanation:
2.50 mol KNO3 x __101.108 g__ = 252.77 g of KNO3
1 mol KNO3
The mass and the amount of substance of any sample of the known compound is called as molar mass. 252.77grams are there in 2.50 moles of potassium nitrate KNO₃.
What is molar mass ?The term molar mass is defined as the ratio between the mass and the amount of substance of any sample of the known compound. A mole of any substance is 6.022 × 10²³ molecules.
1 mole = 6.022 × 10²³ elementary entities.
The molar mass of a substance is calculated by adding the quality atomic masses in g/mol of the constituent atoms. Molar mass is represented by the symbol "M".
The molar mass of KNO₃ is 101.108 gram
1 mol KNO₃ = 101.108 gram
Then,
2.50 mol KNO₃ x __101.108 g__ = 252.77 g of KNO₃
Thus, 252.77grams are there in 2.50 moles of potassium nitrate KNO₃.
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which of the following graphs have the same wavelengths
Answer:
i think the answer is graph 2 and 4
Explanation:
i took the same test and asked for help, not 100% sure about the answer but thats what i chose and i got a good grade. hope it helps
Note the molecular mass of a copper(I) oxide molecule in the image below. What is the mass of 8.250 moles of Cu2O?
Answer : The mass of copper(I) oxide is, 1180.5 grams.
Explanation : Given,
Moles of copper(I) oxide = 8.250 mol
Molar mass of copper(I) oxide = 143.09 g/mol
Formula used:
[tex]\text{ Mass of copper(I) oxide}=\text{ Moles of copper(I) oxide}\times \text{ Molar mass of copper(I) oxide}[/tex]
Now put all the given values in this formula, we get:
[tex]\text{ Mass of copper(I) oxide}=(8.250moles)\times (143.09g/mole)=1180.5g[/tex]
Therefore, the mass of copper(I) oxide is, 1180.5 grams.
How many liters would you need to make a 1 m solution if you have 6 mil of sodium hydroxide
Answer:
6 liters
Explanation:
6 mol/1 M=6 L
-got it correct
-plz mark brainliest
The volume required to prepare 1 M of NaOH solution is 6 L.
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
With the above formula, we can obtain the volume required as follow:
Molarity = 1 MMole of NaOH = 6 molesVolume =?Molarity = mole / Volume
1 = 6 / Volume
Cross multiply
1 × Volume = 6
Volume = 6 L
Thus, 6 L is required to prepare the solution.
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how do mass and height of an object affect the gravititational potential energy
A. Mass and height have same effect on gravitational potential energy
B. Height has a greater effect than mass on gravitational potential energy
C. Height has almost 10 times the effect on gravitational potential energy that mass has
D. Mass has a greater effect than height on gravitational potential energy
Mass and height have the same effect on gravitational potential energy.
The way mass and height of an object affect the gravitational potential energy is that: A. Mass and height have same effect on gravitational potential energy.
Energy can be defined as the ability or capacity of an object or body to perform (do) work. Thus, energy is typically measured in Joules (J).
Basically, the two (2) main types of energy are;
Kinetic energy (K.E). Gravitational potential energy (G.P.E).Gravitational potential energy (G.P.E) can be defined as the energy possessed by an object or body due to its position (height) above planet Earth.
Mathematically, gravitational potential energy (G.P.E) is given by the formula;
[tex]G.P.E = mgh[/tex]
Where:
G.P.E is the gravitational potential energy. m is the mass of an object. g is the acceleration due to gravity. h is the height of an object.This ultimately implies that, gravitational potential energy (G.P.E) is highly dependent on both the mass of an object, height of an object, and the acceleration due to gravity.
In conclusion, both mass and height typically have same effect on gravitational potential energy (G.P.E).
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Element p is soft and brittle does not conduct electricity .Element q is hard , malleable and ductile.Which one of them is a non metal ?Will there be difference in nature of the oxides of p and q
Answer:
Element P is a nonmetal
There will be a difference in the nature of oxides formed by P and Q.
Explanation:
Nonmetals are known to be brittle. Nonmetals do not conduct electricity due to a large gap between the valence band and the conduction band. Metals have little difference between the valence and the conduction band hence they are good conductors of electricity. Metals are also known to be malleable and ductile unlike nonmetals.
Metal form basic oxides which dissolve in water to give alkaline solutions. Nonmetals form acidic oxides which dissolve in water to give alkaline solutions. Hence there is a difference between metal oxides (oxides of element Q) and nonmetal oxides (oxides of element P).
(i) Based on the graph, determine the order of the decomposition reaction of cyclobutane at 1270 K. Justify your answer.
(ii) Calculate the time, in milliseconds, that it would take for 99 percent of the original cyclobutane at 1270 K to decompose.
Another alkane with a ring structure is cyclopentane, C5H10(g). Cyclopentane reacts with
chlorine, Cl2(g) , to produce C2H9Cl(g) and HCl(g) . Following is a representation of a proposed mechanism for the reaction.
*kinetics table attached
(d) Write a rate law for the reaction that is consistent with the mechanism. Justify your answer.
(e) A student claims that, Cl2(g), is a catalyst in the reaction. Explain why the student’s claim is
false.
Answer:
(c)(i) The order of the reaction based on the graph provided is first order.
(ii) 99% of the cyclobutane would have decomposed in 53.15 milliseconds.
d) Rate = K [Cl₂]
K = rate constant
The justification is presented in the Explanation provided below.
e) A catalyst is a substance that alters the rate of a reaction without participating or being used up in the reaction.
Cl₂ is one of the reactants in the reaction, hence, it participates actively and is used up in the process of the reaction, hence, it cannot be termed as a catalyst for the reaction.
So, this shows why the student's claim is false.
Explanation:
To investigate the order of a reaction, a method of trial and error is usually employed as the general equations for the amount of reactant left for various orders are known.
So, the behaviour of the plot of maybe the concentration of reactant with time, or the plot of the natural logarithm of the concentration of reactant with time.
The graph given is evidently an exponential function. It is a graph of the concentration of cyclobutane declining exponentially with time. This aligns with the gemeral expression of the concentration of reactants for a first order reaction.
C(t) = C₀ e⁻ᵏᵗ
where C(t) = concentration of the reactant at any time
C₀ = Initial concentration of cyclobutane = 1.60 mol/L
k = rate constant
The rate constant for a first order reaction is given
k = (In 2)/T
where T = half life of the reaction. It is the time taken for the concentration of the reactant to fall to half of its initial concentration.
From the graph, when the concentration of reactant reaches half of its initial concentration, that is, when C(t) = 0.80 mol/L, time = 8.0 milliseconds = 0.008 s
k = (In 2)/0.008 = (0.693/0.008) = 86.64 /s
(ii) Calculate the time, in milliseconds, that it would take for 99 percent of the original cyclobutane at 1270 K to decompose
C(t) = C₀ e⁻ᵏᵗ
when 99% of the cyclobutane has decomposed, there's only 1% left
C(t) = 0.01C₀
k = 86.64 /s
t = ?
0.01C₀ = C₀ e⁻ᵏᵗ
e⁻ᵏᵗ = 0.01
In e⁻ᵏᵗ = In 0.01 = -4.605
-kt = -4.605
t = (4.605/k) = (4.605/86.64) = 0.05315 s = 53.15 milliseconds.
d) The reaction mechanism for the reaction of cyclopentane and chlorine gas is given as
Cl₂ → 2Cl (slow)
Cl + C₅H₁₀ → HCl + C₅H₉ (fast)
C₅H₉ + Cl → C₅H₉Cl (fast)
The rate law for a reaction is obtained from the slow step amongst the the elementary reactions or reaction mechanism for the reaction. After writing the rate law from the slow step, any intermediates that appear in the rate law is then substituted for, using the other reaction steps.
For This reaction, the slow step is the first elementary reaction where Chlorine gas dissociates into 2 Chlorine atoms. Hence, the rate law is
Rate = K [Cl₂]
K = rate constant
Since, no intermediates appear in this rate law, no further simplification is necessary.
The obtained rate law indicates that the reaction is first order with respect to the concentration of the Chlorine gas and zero order with respect to cyclopentane.
e) A catalyst is a substance that alters the rate of a reaction without participating or being used up in the reaction.
Cl₂ is one of the reactants in the reaction, hence, it participates actively and is used up in the process of the reaction, hence, it cannot be termed as a catalyst for the reaction.
So, this shows why the student's claim is false.
Hope this Helps!!!
(i) The order of reaction is first order.
(ii) It requires 53.15 miliseconds for 99% decomposition.
(d) Rate law = k [[tex]\rm Cl_2[/tex]].
(e) Chlorine gas is the reactant. Thus student claim is false.
(i) The order of reaction can be determined with the help of a graph. The graph depicts the exponential behavior of decomposition of cyclobutane with respect to time.
The graph depicts the reaction to be of first-order kinetics. The general concentration expression can be:
[tex]\rm C_(_t_)\;=\;C_(_0_)\;e^-^k^t[/tex]
Where, [tex]\rm C_(_t_)[/tex] = concentration at time t
[tex]\rm C_(_0_)[/tex] = initial concentration 1.60 mol/liter
k = rate constant
for first order reaction,
k = In [tex]\rm \frac{2}{Half\;time}[/tex]
From the graph, half time = 0.008 sec
k = In [tex]\rm \frac{2}{0.008}[/tex]
k = 86.64 / sec.
(ii) The time required for 99% decomposition can be calculated, by calculating the [tex]\rm C_(_t_)[/tex] for left 1 % solution.
[tex]\rm C_(_t_)\;=0.01\;C_(_0_)[/tex]
0.01 [tex]\rm C_(_0_)[/tex] = [tex]\rm C_(_0_)[/tex] [tex]\rm e^-^k^t[/tex]
-kt = -4.605
t = 53.15 miliseconds
(d) The rate law is obtained against the reaction.
In rate law, the intermediates that appear in the reaction are removed, and the equation has been formed.
The slow step is the formation of Chlorine. Thus the rate law will be:
Rate = k [[tex]\rm Cl_2[/tex]]
(e) The catalyst function in improvising the rate of the reaction. Since, the reaction has chlorine as the part of the reactant, it is consumed in the reaction and thus does not act as a catalyst. Thus the claim of the student is false.
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if I add 1.50 L of water to 250 mL of a 12.5 M NaOH solution, what will the molarity of the diluted solution be?
Answer:
The molarity of the diluted solution is 1.786 M
Explanation:
Dilution is a process in which you always start with a concentrated solution to which a greater volume of solvent is added. This modifies the concentration and volume of the resulting solution, but the amount of solute used to prepare the initial solution remains the same.
In summary, in a dilution the amount of solute does not vary, but the volume of the solvent varies: when more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
The following rule is fulfilled:
Vinicial x Cinicial = Vfinal x Cfinal
where:
Vinicial = Initial volume. Cinicial = Initial concentration Vfinal = Final volume Cfinal = Final concentrationIn this case:
Vinicial= 250 mL= 0.25 L (Being 1 L=1000 mL)Cinicial= 12.5 MVfinal= 1.5 L+ 0.25 L=1.75 LCfinal= ?Replacing:
0.25 L* 12.5 M= 1.75 L* Cfinal
Solving:
[tex]Cfinal=\frac{0.25 L* 12.5 M}{1.75 L}[/tex]
Cfinal= 1.786 M
The molarity of the diluted solution is 1.786 M
What continent have only one climate?
Answer: antarctica
Explanation: it stays cold year round never gets warm
Answer:
Antarctica
Explanation:
Antarctica is covered with ice year round. Therefore, I do believe that it is a frozen desert all year round.
please someone help
How many moles of hydrogen ions are formed in the ionization of 0.250 moles of H2SO4? ( do not write the units. Answer in standard form)
H2SO4 ⟶ 2H+ + SO42-
Answer:
Explanation:
0.500. I'm 100% sure this is the correct answer.
Answer:
0.500
Explanation:
First the equation is
H2S04 = 2H+ + S04-
In this equation Liters will stay the same throughout and there is a ration value. Since hydrogen has a coefficent of 2, you must multiple 0.250 by 2 which gets you the value of 0.500 which is the answer to your question..
A mixture of gases at a total pressure of 725 mmHg contains nitrogen, carbon dioxide, helium, and oxygen. The partial pressure of carbon dioxide is 175 mmHg, the partial pressure of nitrogen is 355 mmHg, and the partial pressure of helium is 15 mmHg. What is the partial pressure of oxygen?
Answer: The partial pressure of oxygen is 180 mm Hg
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
[tex]p_{total}=p_{N_2}+p_{CO_2}+p_{He}+p_{O_2}[/tex]
Given : [tex]p_{total}[/tex] =total pressure of gases = 725 mm Hg
[tex]p_{N_2}[/tex] = partial pressure of nitrogen = 355 mm Hg
[tex]p_{CO_2}[/tex] = partial pressure of carbon dioxide = 175 mm Hg
[tex]p_{He}[/tex] = partial pressure of helium = 15 mm Hg
[tex]p_{O_2}[/tex] = partial pressure of oxygen = ?
putting in the values we get:
[tex]725=355+175+15+p_{O_2}[/tex]
[tex]p_{O_2}=180mmHg[/tex]
The partial pressure of oxygen is 180 mm Hg
2Al(s)+ 3Pb(N03) 2(aq) 2Al(N03)3(aq) + 3Pb (s)How many molecules of Pb(N03) 2 are used in the reaction? How many oxygen atoms are used in the reaction? How many moles of Al(N03)3 are formed? What is the mole ratio of Pb(N03) 2 to Al(N03)3?
Answer:
A. 1.806x10^24 molecules of Pb(NO3)2
B. 18 oxygen atoms.
C. 2 moles of Al(NO3)3.
D. The mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2
Explanation:
The balanced equation for the reaction is given below:
2Al(s) + 3Pb(NO3)2(aq) —> 2Al(NO3)3(aq) + 3Pb (s)
A. Determination of the number molecules of Pb(NO3)2 used in the reaction. This is illustrated below.
From the balanced equation above, 3 moles of Pb(NO3)2 were used in reaction.
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules.
Now, if 1 mole of Pb(NO3)2 contains 6.02x10^23 molecules,
then, 3 moles of Pb(NO3)2 will contain = 3 x 6.02x10^23 = 1.806x10^24 molecules.
Therefore, 1.806x10^24 molecules of Pb(NO3)2 is used in the reaction.
B. Determination of the number of oxygen atom used in the reaction.
This is illustrated below:
To obtain the number of oxygen atom used in the reaction, we simply do a head count of the oxygen atom in the reactant.
The reactant containing oxygen is Pb(NO3)2 and there are 3 moles of it according to the balanced equation.
There are a total of 18 oxygen atom in 3 moles of Pb(NO3)2. Therefore, 18 oxygen atoms are used in the reaction.
C. Determination of the number of mole of Al(NO3)3 formed.
From the balanced equation above, 2 moles of Al(NO3)3 are formed
D. Determination of the mole ratio of Pb(N03)2 to Al(N03)3
From the balanced, 3 moles of Pb(N03)2 reacted and 2 moles of Al(N03)3 are produced.
Therefore, the mole ratio of Pb(N03)2 to Al(N03)3 is 3 : 2
A graduated cylinder with water has a mass of 534.26 g. The graduated cylinder itself has a mass of 214.36 g. What is the mass of just the water?
Answer: 319.9g
Explanation:
Mass of graduated cylinder with water = 534.26g
Mass of graduated cylinder = 214.36g
Mass of just water = Mass of graduated cylinder with water - Mass of graduated cylinder.
Mass of just water = 534.26g - 214.36 g = 319.9g
The reaction below was carried out in an acidic solution.
[+103 —>12
Which statement is true about this equation?
Although it is unbalanced, it can be balanced by using the half-reaction method.
It has been balanced by using the half-reaction method.
It has been balanced by directly using spectator ions.
Although it is unbalanced, it can be balanced by directly using spectator ions.
Answer:
Although it is unbalanced, it can be balanced by using the half-reaction method
Explanation:
Skeleton half-reaction: IO₃⁻ ⟶ I₂
Balance atoms other than O and H: 2IO₃⁻ ⟶ I₂
Balance O: 2IO₃⁻ ⟶ I₂ + 6H₂O
Balance H: 2IO₃⁻ + 12 H⁺ ⟶ I₂ + 6H₂O
Balance charge: 2IO₃⁻ + 12 H⁺ + 10e⁻ ⟶ I₂ + 6H₂O
A and C are wrong. The original equation is not balanced. It has 3 O on he left and none on the right.
D is wrong. You can't balance any equation by using spectator ions.
A. Although it is unbalanced, it can be balanced by using the half-reaction method.
what is half-reaction method?The half-reaction approach is a manner to balance redox reactions. It involves breaking the general equation down into an oxidation element and a discount component. ChemistryStoichiometry of Oxidation-discount Reactions.
example: Zn and Cu Galvanic cell
at the Zn anode, oxidation takes place (the metal loses electrons). that is represented within the following oxidation 1/2 reaction (note that the electrons are on the product's aspect): Zn(s) → Zn2+ + 2e. at the Cu cathode, reduction takes place (electrons are accepted)
Learn more about half-reaction method here
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