What is the chemical formula for the compound formed between sodium and oxygen?

Given, equilibrium constant  Kp = 0.0870

Pressure of PCl₃ = 0.50 atm

Pressure of Cl₂ =  0.50 atm

Pressure of PCl₅ = 0.20 atm

Reaction quotient, Q =  [tex]\frac{0.20 atm}{0.50 atm x 0.50 atm}[/tex]

Q = 0.8

Q > K, net reaction is to the left

Q= K, no net reaction

Q < K, net reaction is to the right

Q = 0.8  and Kp = 0.0870

Q is greater than K, so the net reaction is to the left or to the reactant side.

Therefore, the reaction must proceed to the left or to the reactant side in order to reach equilibrium.

Your answer is A. Let me know if you need anything else!

Final answer:

In ethylene, both carbon atoms are sp2 hybridized and form a planar shape with 120° bond angles. In allene, the central carbon is sp hybridized with 180° bond angles, while the terminal carbons are sp2 hybridized with 120° bond angles, with hydrogen atoms at the central carbon in perpendicular planes.

Explanation:

Hybridization of Carbon Atoms in Hydrocarbons

When determining hybridization at carbon atoms within hydrocarbons such as ethylene (C2H4) or allene (H2C=C=CH2), we consider the number of atoms directly bonded to a carbon atom. In ethylene, both carbon atoms are sp2 hybridized because they each make three sigma (σ) bonds - two to hydrogen atoms and one to each other - and one pi (π) bond is shared between them, forming a double bond (C=C). As for allene, the central carbon is sp hybridized due to possessing two π bonds, one with each of the adjacent carbons, while the terminal carbon atoms are sp2 hybridized.

There are multiple types of bonds in a C=C bond; a σ bond and a π bond. A C=C bond includes one σ bond that results from the head-on overlap of sp2 hybrid orbitals and one π bond that results from the side-to-side overlap of the unhybridized p orbitals.

The shape of the ethene molecule is planar with approximately 120° bond angles due to the sp2 hybridization. In contrast, the allene molecule has a more complex structure where the central carbon has 180° bond angles, and the terminal carbons have 120° bond angles. The hydrogen atoms on the central carbon of allene are in perpendicular planes to each other due to the nature of its hybridization.

In a hydrocarbon, each carbon atom is sp3 hybridized, forming sigma bonds. There are no pi bonds, and all bond angles are approximately 109.5°, representing tetrahedral geometry.

(a) The hybridization at each carbon atom in a hydrocarbon can be determined using the formula "Hybridization = 1/2(V + M - C + A)," where V is the number of valence electrons, M is the number of monovalent atoms, C is the cation charge, and A is the anion charge. For carbon in a hydrocarbon, V = 4, M = 4, and C = A = 0 for neutral carbon. Substituting these values, the hybridization is 1/2(4 + 4 - 0 + 0) = 1/2(8) = 4. Therefore, each carbon atom in the hydrocarbon is sp3 hybridized.

(b) In a hydrocarbon, each bond formed between carbon atoms is a sigma (σ) bond. Thus, the number of sigma bonds is equal to the number of single bonds in the molecule.

(c) A hydrocarbon consists only of single bonds, so there are no pi (π) bonds.

(d) In a hydrocarbon, all the bond angles are approximately 109.5°, corresponding to the tetrahedral geometry of sp3 hybridized carbon atoms.

The question probable may be:

In the hydrocarbon (a) what is the hybridization at each carbon atom in the molecule? (b) how many s bonds are there in the molecule? (c) how many p bonds? (d) identify all the 120° bond angles in the molecule.

The mass of Mg consumed is approximately 26.28 g.

The balanced chemical equation for the reaction between magnesium (Mg) and nitrogen ([tex]\rm N_2[/tex]) to produce magnesium nitride ([tex]\rm Mg_3N_2[/tex]) is:

[tex]\rm \[3 \text{Mg} + \text{N}_2 \rightarrow \text{Mg}_3\text{N}_2\][/tex]

Given:

Mass of [tex]\rm N_2[/tex] = 10.1 g

Molar mass of [tex]\rm N_2[/tex] = 28.02 g/mol (molar mass of nitrogen)

Using stoichiometry, we can determine the moles of [tex]\rm N_2[/tex]:

Moles of [tex]\rm N_2[/tex] = Mass / Molar mass = 10.1 g / 28.02 g/mol ≈ 0.3602 mol

From the balanced equation, we see that 3 moles of Mg react with 1 mole of [tex]\rm N_2[/tex] to produce 1 mole of [tex]\rm Mg_3N_2[/tex].

Therefore, the moles of Mg consumed are: Moles of Mg = 3 * Moles of [tex]\rm N_2[/tex] = 3 * 0.3602 mol = 1.0806 mol

The molar mass of Mg is 24.31 g/mol (molar mass of magnesium), so the mass of Mg consumed is:

Mass of Mg = Moles of Mg * Molar mass = 1.0806 mol * 24.31 g/mol ≈ 26.28 g

Therefore, the mass of Mg consumed is approximately 26.28 g.

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In this reaction, 3 mg of magnesium reacts with nitrogen gas to produce magnesium nitride. The mass of Mg consumed is 26.3 g.

In the given reaction, 3 mg of magnesium reacts with nitrogen gas (N2) to produce magnesium nitride (Mg3N2). To determine the mass of Mg consumed, we need to calculate the molar mass of Mg and the molar ratio between Mg and N2. The molar mass of Mg is 24.31 g/mol. Since the balanced equation shows a 3:1 ratio between Mg and N2, we divide the mass of N2 (10.1 g) by the molar mass of N2 (28.01 g/mol) to get the moles of N2 and then multiply that by the molar ratio to find the moles of Mg consumed. Finally, we multiply the moles of Mg consumed by the molar mass of Mg to get the mass consumed.

Calculation:
Mass of N2 = 10.1 g
Molar mass of N2 = 28.01 g/mol
Moles of N2 = (mass of N2) / (molar mass of N2) = 10.1 g / 28.01 g/mol = 0.3608 mol
Moles of Mg consumed = (moles of N2) x (molar ratio) = 0.3608 mol x 3/1 = 1.0824 mol
Mass consumed = (moles of Mg consumed) x (molar mass of Mg) = 1.0824 mol x 24.31 g/mol = 26.3 g

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The mass of 5.40 × 10^21 platinum atoms is approximately 1.75 grams. This is calculated using Avogadro's number and the molar mass of platinum.

To calculate the mass of 5.40×1021 platinum atoms, first, we need to understand that the atomic mass of platinum is approximately 195.08 u (atomic mass units). In chemistry, one mole of any substance contains Avogadro's number (6.022 × 1023) of particles (atoms, molecules, ions, etc). Therefore, the molar mass of platinum is 195.08 g/mol, meaning that 1 mole of platinum atoms (6.022 × 1023 atoms) has a mass of 195.08 grams.

First, we find out how many moles 5.40×1021 platinum atoms constitute.

5.40 × 1021 atoms/ (6.022 × 1023 atoms/mol) = 0.00897 moles

Since the mass of 1 mole platinum is 195.08 g, therefore:

Mass = Moles × Molar mass = 0.00897 moles × 195.08 g/mol = 1.75 g

Therefore, the mass of 5.40 × 1021 platinum atoms is approximately 1.75 grams.

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Answer:

The lower the pressure the lower the temperature, thus, at 3000 m the pressure is lower, therefore the boiling temperature is lower than at 0 m.

Explanation:

Hello,

In this case, the boiling point of water at the sea level is about 100 °C whereas at 3000 m is about 89.5 °C since the pressure at higher altitudes is less than the atmospheric pressure. In such a way, considering a directly proportional relationship between pressure and temperature, the higher the pressure the higher temperature (sea level) whereas the lower the pressure the lower the temperature (at 3000 m)

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Final answer:

The black colored precipitate formed when Fe(NO3)2(aq) and Na2S(aq) are mixed is Iron(II) sulfide, represented by the compound FeS.

Explanation:

When Fe(NO3)2(aq) and Na2S(aq) are mixed, a precipitation reaction occurs. According to solubility rules, sulfides are generally insoluble, except for those of group 1 elements (like Na) and ammonium. Iron sulfide, which is not an exception to this rule, will precipitate as a solid. The black colored precipitate that forms is likely to be FeS (Iron(II) sulfide).

The relevant reaction can be represented by the ionic equation: Fe2+ (aq) + S2- (aq) → FeS (s), where the precipitate is the insoluble iron(II) sulfide.

While the information provided with the question includes several reactions and solubility examples, the key to answering this specific question is understanding the solubility of sulfides and that iron can form a black colored sulfide precipitate.

Answer:

Your answer is Mg(NO3)2, in water Mg(NO3)2(aq) → Mg2+(aq) + 2NO3-(aq)

Explanation:

Answer:

The root will turn 90 degrees downward, and the stem will curl 90 degrees upwards.

Explanation:

Answer:

The root will curl down, and the stem will curl up.

this is for exabit A

It is known that at if a gas is identified to be as ideal gas then, at STP, the volume of 1 mole of that gas is equal to 22.4 L. Using this fact and the given volume in this item, we determine the number of moles as that below.

                n = (11.2 L of argon)(1 mol argon / 22.4 L of argon)

                 n = 0.5 moles

Answer: 0.5 moles 

Choosing Group 2A (alkaline earth metals) of the periodic table, and focusing on the element calcium (Ca).

The research:

Element: Calcium (Ca)

1. Data Table:

| Property | Value |

|-----------------------------------|------------------------|

| Element name | Calcium |

| Element symbol | Ca |

| Atomic number | 20 |

| Atomic mass | 40.08 u |

| Melting point | 842°C |

| Boiling point | 1484°C |

| Electronegativity | 1.00 |

| Atomic radius | 197 pm |

| Ionic radius | 100 pm (2+) |

| First ionization energy | 590.6 kJ/mol |

2. Graphs:

- Ionic Radius vs Atomic Number:

Graph of Ionic Radius (pm) on the y-axis and Atomic Number on the x-axis is attached below.

- First Ionization Energy vs Atomic Number:

Graph of First Ionization Energy (kJ/mol) on the y-axis and Atomic Number on the x-axis is attached below.

3. Analysis:

The graph of ionic radius versus atomic number for Group 2A elements will show a decreasing trend as atomic number increases.

This is because, as you move down the group, the number of electron shells increases, leading to a greater distance between the outer electrons and the nucleus, resulting in a larger ionic radius.

On the other hand, the graph of first ionization energy versus atomic number will show an increasing trend. This is because, as you move down the group, the outermost electrons are further away from the nucleus, experiencing weaker attractive forces, thus requiring more energy to remove them, resulting in higher ionization energies.

These relationships align with the periodic trends studied, where atomic size increases down a group, leading to decreasing ionization energy.

4. Description of Calcium:

- Date of Discovery: Calcium was discovered by Sir Humphry Davy in 1808.

- Discoverer: Sir Humphry Davy.

- Location of Discovery: It was discovered in England.

- Discovery Method: Davy electrolyzed a mixture of lime (calcium oxide) and mercuric oxide, yielding calcium amalgam, from which he isolated calcium by evaporating the mercury.

- Unique Properties: Calcium is a silvery-white, alkaline earth metal. It is essential for living organisms, playing a vital role in bones, teeth, and muscle function. It is also highly reactive with water, forming calcium hydroxide and hydrogen gas.

- Uses/Products: Calcium has various uses, including in the production of steel, as a deoxidizer, and in the production of calcium compounds used in agriculture, pharmaceuticals, and construction materials.

Answer: c) temperature

Explanation:

Kinetic energy is the energy possessed by an object by virtue of its motion.

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

[tex]K=\frac{3RT}{2}[/tex]

From above, it is visible that kinetic energy is directly related to the temperature of the system. So, if temperature is more, average kinetic energy of the system is more and vice-versa.