What is the difference between kinetic and potential energy? what is the difference between kinetic and potential energy? kinetic energy is stored energy and has the capacity to do work; potential energy is expressed through motion. kinetic energy may eventually become potential energy, but potential energy cannot become kinetic energy. kinetic energy and potential energy are synonymous; they are defined as the capacity to do work, actively putting matter into motion. kinetic energy is energy in action, while potential energy is stored energy?

The components of the cup's weight that are parallel and perpendicular to the plane of the table can be found using trigonometry.

The magnitude of the component of the weight parallel to the slope is w|| = w*sin(25°) = mg*sin(25°), and the magnitude of the component of the weight perpendicular to the slope is w1 = w*cos(25°) = mg*cos(25°).

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A solar-powered car converts light energy into mechanical energy. Therefore, option (B) is correct.

A solar car is a vehicle running on electricity produced by the conversion of sunlight into useful energy. Solar cars are a combination of aerodynamics, laws of motion, and clean converted energy.

Solar panels help in the conversion of solar power into usable electricity that is stored in batteries. These batteries are used as the fuel which we need to run the vehicles.

A solar car only depends on the photovoltaic cells to absorb the sunlight and transform it into usable energy to power the engine. Photovoltaic cells are based on the principle of solar thermal energy by converting solar energy instead of thermal conversion, directly to usable electricity.

Solar cars have solar panels to be mounted on the surfaces absorbing maximum sun rays, which are generally on the rooftop. The photovoltaic cells comprise Silicon, Galium, Indium, and Nitrogen gas.

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Final answer:

The car's acceleration can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. By rearranging the formula, we can find the car's acceleration to be 2 m/s².

Explanation:

The acceleration of a car can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). In this case, the net force acting on the car is 5000 N and the mass of the car is 2500 kg. Using the formula, we can rearrange it to solve for acceleration:

a = F / m

Substituting the given values, we have:
a = 5000 N / 2500 kg

Simplifying the equation gives:
a = 2 m/s²

Therefore, the car's acceleration is 2 m/s².

Answer:

weight of the rock on Uranus is 218 Newton.

Explanation:

Weight of the object is given by,

Weight = mass × gravitational acceleration

For Uranus,

gravitational acceleration = 8.7 [tex]\frac{m}{s^{2} }[/tex]

thus,

Weight of rock on Uranus is,

Weight = mass × gravitational acceleration

Weight = 25 × 8.7

Weight = 217.5 Newton

Thus, weight of the rock on Uranus is 218 Newton.

Answer:

B

Explanation:

Edge 2021

Answer:

Explanation:

When an object is moving around a circular path with a uniform speed the motion os said to be uniform cicular motion. It is the example of accelerated motion as the direction of motion keeps on changing every instant.

When a body is in uniform circular motion, it experiences a force towards the centre of circular path, this force is called centripetal force.

The formula of centripetal force is given by

F = mv^2 / r

Where m is the mass of body, V be the speed of body and R be the radius of circular path

F = 11 × 3.5 × 3.5 / 0.6

F = 224.58 N

Answer:

The process of estimating values between measured data points is called. interpolation.

Explanation:

The shell dropped by the seagull would be moving at a speed of approximately 16.7 m/s when it hits the ground. This calculation is based on the physics concept of final velocity in a free-fall motion.

In this scenario, the concept of kinematics, an aspect of Physics, will be employed. Particularly, we'll be focusing on free fall motion. The speed of the shell just before hitting the ground can be calculated using the equation for the final velocity in free fall: v = √(2gs) where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s² on Earth), and s is the height from which the object is dropped.

Substituting the given values (s = 14.0m, g = 9.81m/s²) into the equation, the calculation should look like this:

v = √(2*9.81*14.0) ≈ 16.7 m/s

So, the shell should be moving at approximately 16.7 m/s when it hits the rocks below.

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Sample Response: Pick a reference point on the line to be the zero position. Determine the direction and measure the distance from zero in standard units.

-The reference point is set on the line.

-The distance from that reference point can be used to describe movement.

-Standard units of measurement can be used to identify the distance from the reference point.

To determine the change in atmospheric pressure, apply the formula for hydrostatic pressure, p = hdg, where h is height (279m), d is air density (1.29 kg/m³), and g is acceleration due to gravity (9.81 m/s²). The product gives you the change in pressure in Pascals (Pa).

The calculation of the change in pressure as the barometer is taken from the base to the top of the 279m tower involves using the formula for hydrostatic pressure. This formula is given by p = hdg, where h is the height of the fluid column, d is the fluid density and g is the acceleration due to gravity. In this case, the fluid is air.

Given that the density (d) of air is approximately 1.29 kg/m³, the height of the tower (h) is 279 m, and g (the acceleration due to gravity) is 9.81 m/s², you would calculate the change in pressure by simply plugging these values into the formula: p = 1.29 kg/m³ * 279 m * 9.81 m/s². Once you have multiplied these numbers together, the answer will give you the change in atmospheric pressure in Pascals (Pa).

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Answer:

The correct statement is “A solstice because the Earth is very close to the Sun”

Explanation:

The solstice occurs when the sun is closer or further from one of the Earth's hemispheres, increasing the duration of the day in one part of the world, and decreasing its duration in the other. That is, during the solstice, the sun is closer to one of the hemispheres, causing the day to have a longer duration, while the night is longer in the other hemisphere.

In the case of the equinox, the sun is on the equator line, so the day and night in both hemispheres have the same duration. At that time the part of the Earth closest to the Sun is the equator.

The solstice is caused because the axis on which our planet rotates on itself is slightly inclined with respect to the translation plane, this is its trajectory around the Sun.

That implies that different regions of the globe receive more or less light at different times of the year.

The equinox like the solstice is presented twice a year, marking the entrance of the seasons. The sunny days are longer during the summer solstice, while the nights are longer during the winter solstice. The equinox occurs at the beginning of autumn and spring, when the sun is closer to the equator.

So the correct statement is “A solstice because the Earth is very close to the Sun”

The energy released from the burning of the Hindenburg's hydrogen can be calculated using Einstein's theory of relativity and the mass of hydrogen converted into helium. However, actual values may vary.

To answer your question, we need to calculate the amount of energy produced when hydrogen is converted into helium. From the provided reference, when 1 kilogram of hydrogen is converted into helium, the mass of the helium is only 0.9929 kilogram, and 0.0071 kilogram of material is converted into energy. This conversion is guided by Einstein's theory of relativity, which states that energy equals mass times the speed of light squared. So, the energy released by the conversion of just 1 kilogram of hydrogen into helium can be calculated using the formula E=mc² (where 'm' is mass and 'c' is the speed of light). Therefore, applying the numbers, the energy evolved would be 0.0071 kg * (3 * 10⁸ m/s)². However, please note that real-world values can be different due to various factors like loss of gas, incomplete reaction, etc.

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The energy of [tex]\( 2.45 \times 10^9 \text{ kJ} \)[/tex] is evolved when the hydrogen gas is used to fill the Hindenburg.

To calculate the energy evolved when the hydrogen gas used to fill the Hindenburg burned, we need to know the combustion reaction and the energy released per mole of hydrogen gas.

The combustion reaction of hydrogen gas is:

[tex]\[ 2H_2(g) + O_2(g) \rightarrow 2H_2O(g) \][/tex]

The enthalpy change [tex](\(\Delta H\))[/tex] for this reaction is approximately [tex]\(-286 \text{ kJ/mol}\) of \(H_2\)[/tex].

Using the ideal gas law PV = nRT to find the number of moles (n) of [tex]\(H_2\)[/tex]:

P = 1.00 atm

[tex]\[ V = 2.09 \times 10^8 \text{ L} \][/tex]

[tex]\[ R = 0.0821 \text{ L} \cdot \text{atm} / \text{mol} \cdot \text{K} \][/tex]

T = 298.25 K

[tex]\[ n = \frac{PV}{RT} \][/tex]

[tex]\[ n = \frac{(1.00 \text{ atm})(2.09 \times 10^8 \text{ L})}{(0.0821 \text{ L} \cdot \text{atm} / \text{mol} \cdot \text{K})(298.25 \text{ K})} \][/tex]

[tex]\[ n = \frac{2.09 \times 10^8}{24.45} \][/tex]

[tex]\[ n \approx 8.55 \times 10^6 \text{ moles} \][/tex]

Now, calculate the total energy evolved when this amount of hydrogen burns:

[tex]\[ \text{Energy evolved} = n \times \Delta H \][/tex]

[tex]\[ \text{Energy evolved} = (8.55 \times 10^6 \text{ moles}) \times (-286 \text{ kJ/mol}) \][/tex]

[tex]\[ \text{Energy evolved} = -2.45 \times 10^9 \text{ kJ} \][/tex]

The negative sign indicates that energy is released, so the total energy evolved is [tex]\[ 2.45 \times 10^9 \text{ kJ} \][/tex].

The equation we can use here is:

v^2 = v0^2 + 2 a d

where v is final velocity, v0 is intial velocity, a is acceleration and d is distance

14^2 = 8^2 + 2 a (44)

a = 1.5 m/s^2

The acceleration of the car travelling in a straight line is [tex]\fbox{\begin\\1.5\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\end{minispace}}[/tex].

Further Explanation:

A car travelling in a straight line with a constant uniform acceleration will always follow the Newton’s law of motion.

Given:

The initial velocity of the car is [tex]8\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex].

The final velocity of the car is [tex]14\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex].

The total distance covered by the car is [tex]44\,{\text{m}}[/tex].

Concept:

The car is following the Newton’s law of motion. As per the Newton's laws of motion, the motion of a body is governed by the three equations of motion.

To calculate the uniform acceleration of car when initial velocity, final velocity, and distance covered by car given, the equation of motion we can use here is:

[tex]\fbox{\begin\\v^2 = {u^2} + 2as\end{minispace}}[/tex]

Rearrange the above equation for value of acceleration :

[tex]a=\dfrac{{{v^2}-{u^2}}}{{2s}}[/tex]

Here, [tex]s[/tex] is the distance covered by car, [tex]u[/tex] is the given initial velocity of the car, [tex]v[/tex] is the given final velocity of the car and [tex]a[/tex] is the acceleration of the car.

Substitute [tex]14\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}[/tex] for [tex]v[/tex], [tex]8\,{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}[/tex] for [tex]u[/tex] and [tex]44\,{\text{m}}[/tex] for [tex]s[/tex] in the above equation.

[tex]\begin{aligned}a&=\dfrac{{{{\left({14\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}\right)}^2}-{{\left({8\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}\right)}^2}}}{{2\times44}}\\&=1.5\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\\end{aligned}[/tex]

Thus, the acceleration of the car travelling in a straight line is [tex]\fbox{\begin\\1.5\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\end{minispace}}[/tex].

Learn more:

1.  Conservation of momentum https://brainly.com/question/9484203

2.  Motion of a ball under the gravity https://brainly.com/question/10934170

3. The motion of a body under the friction force https://brainly.com/question/4033012

Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Initial speed of 8.0 m/s,Newton's law, motion, distance, final speed of 14.0 m/s, car travelling in a straight line, accelerates uniformly and distance of 44 m.

Answer:

The answer is D) A Reactant!

Explanation:

The answer is D because just like water, salt is made up of two different components. Making it a reactant!

Answer:

Meter

Liter

Kilogram

A source of sound is kept in a jar in a vacuum. Air is slowly introduced in to the jar. The loudness of the sound increases gradually  because the air is slowly introduced in to the jar as sound needs a physical medium and in a vacuum there is none.

The pitch of the sound is an important property where the perception of frequency of sound occur by human ear within the range of human hearing, higher the frequency of the sound the higher is its pitch and a lower frequency means a lower pitch.

The loudness of sound can be determined by amplitude of the sound which  is a measure of the magnitude of the maximum disturbance of sound.

The speed of the sound can be detrained as  the sound waves travel through the medium is called the speed of sound and it is different for different mediums, travels fastest in solids.

When sound waves hit the surface of a solid  it reflects back to the same medium as it follows laws of reflection, Timbre is the another  property of sound which is used to differentiate sounds of the same frequency.

For more details  sound, visit

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Answer:

1) the bird sitting on the tree is not moving, hence he has not kinetic energy. By the fact that the bird is high in the tree you can see that it has some potential energy (wich in this case depends on the height) and the bird has potential energy because has the ability  of doing work (lije jumping down for example)

2) the cook is moving, because he needs to do it in order to prepare the meal, then he has kinetic energy and is doing work (because he puts the energy in order to move himself) the answer is "kinetic energy because he is making the meal.

3) Ok, when you stretch the bow, it wants to return to his original shape, then you are creating elastical energy in the bow, and you are using mechanical energy to stretch the bow.  Then when the bow releases his elastical energy (also you can think that when the string is pushing the arrow, it is applying mechanical energy on the arrow), it propulsates the arrow, creating now kinetic energy into the arrow.

The correct answer is mechanical to elastic, because you need to first use mechanical energy in order to stretch the bow and create the elastic energy, and then mechanical again when the string starts to impulse the arrow.

The distance is 17 km

The displacement of the boat is about 12 km at 70° S of W

[tex]\texttt{ }[/tex]

Vector is quantity that has magnitude and direction.

One example of a vector is displacement.

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

This problem is about Vector Diagram.

On his fishing trip Justin rides in a boat 12 km south.

[tex]d_1 = -12 \widehat{j}[/tex]

[tex]\texttt{ }[/tex]

The fish aren’t biting so they go 4 km west.

[tex]d_2 = -4 \widehat{i}[/tex]

[tex]\texttt{ }[/tex]

They then follow a school of fish 1 km north.

[tex]d_3 = 1 \widehat{j}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{Total Distance} = 12 + 4 + 1 = 17 \texttt{ km}[/tex]

[tex]\texttt{ }[/tex]

[tex]d = d_1 + d_2 + d_3[/tex]

[tex]d = -12 \widehat{j} - 4 \widehat{i} + 1 \widehat{j}[/tex]

[tex]d = -4 \widehat{i} - 11 \widehat{j}[/tex]

[tex]\texttt{Total Displacement} = \sqrt{4^2 + 11^2} = \sqrt{137} \approx 12 \texttt{ km}[/tex]

[tex]\texttt{Direction of Displacement} = \theta = \tan^{-1} \frac{11}{4} \approx 70^o \texttt{ south of west}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Vectors

[tex]\texttt{ }[/tex]

Keywords: Local , Race , Driver , Road , Finish , Line , Displacement , Vector , Degree , North , West , South , Kilometres

The acceleration of the box is -2.12 m/s^2.

To find the acceleration of the box, we need to calculate the net force acting on it. The net force is the difference between the applied force and the force of kinetic friction. The force of kinetic friction can be calculated by multiplying the coefficient of kinetic friction by the normal force, which is the weight of the box. The weight of the box is mass multiplied by the acceleration due to gravity. With this information, we can plug in the given values and calculate the acceleration.

Therefore, the acceleration of the box is -2.12 m/s2.

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To find the acceleration of the box, you subtract the frictional force from the applied force, then divide by the box's mass. In this case, the acceleration is found to be 5.8 m/s².

To find the acceleration of the box, we need to apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In this case, the net force is the applied force minus the force of friction. Given the normal force (created by the box's weight) is 25 N, the force of friction would be the coefficient of kinetic friction (0.3) multiplied by the normal force. That equals 0.3 * 25 = 7.5N.

Then, the net force is the applied force (22 N) minus this frictional force: 22 - 7.5 = 14.5 N. Since force equals mass times acceleration (F = ma), you can find the acceleration (a) by dividing the net force by the mass. Remember that the mass should be calculated by dividing the weight by gravitational acceleration (m = N/g). The mass is 2.5 kg. Therefore, the acceleration (a) would be F/m = 14.5 N divided by 2.5 kg= 5.8 m/s².

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Answer:

A ray of light passing from medium A to B will bend toward the normal.

Explanation: Plato user

The component of force which is parallel to the path of the motion is 10N * cos25 = 9.06 N 
This component is the only "effective" force, and it is the one doing work. 

Work = force * distance

Work = 9.06 N * 30 m

Work = 2.7×10^2 J

Answer:

2.7×10^2 Joules

Explanation: