What is the energy of a photon of this light, in ev ?

Answer:

the Answer is D 117 newtons

Explanation:

kelvin is the right answer

Answer: A, B, C, E

Explanation:

Plastics have a number of properties that make them useful solutions to many complex problems in the world, such as being chemically resistant, durable, non-reactive, and easy to manufacture, which are options A, B, C, and E.

Plastics have a number of properties that make them a popular choice in many industries, such as chemical resistance, which is one of the most important properties of plastics, as they can resist a wide range of chemicals, including acids, bases, and solvents, which makes them ideal for use in chemical processing, pharmaceuticals, and food packaging. Durability is another important property of plastics.

They are resistant to wear and tear, impact, and weathering, which makes them suitable for use in various applications, such as building materials, automotive parts, and toys. Plastics are also non-reactive, which means that they do not react with other materials.

Hence, the correct answers are chemically resistant, durable, non-reactive, and easy to manufacture, which are options A, B, C, and E.

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Bedrock

The answer is "Heterogeneous mixture because the filings and particles of sand and salt are distributed randomly in the mixture."

A mixture is a mix of at least two substances in any extent. This is not quite the same as a compound, which comprises of substances in settled extents.

A heterogeneous mixture is formed when the chemicals in the blend are not consistently conveyed all through the blend. For example, on the off chance that you add sand to salt, no measure of crushing can make sand and salt frame a homogeneous blend like salt and water. In this way, we can state that a blend of sand and salt will shape a heterogeneous mixture.

-Heterogeneous mixture because the filings and particles of sand and salt are distributed randomly in the mixture

The position vector with magnitude [tex]10 \ m[/tex] points to the right and up. its x-component is  [tex]6.0\ m[/tex] and its y-component is  [tex]8\ m[/tex].

A vector is a physics term for a quantity with both magnitude (size) and direction. Physical quantities including each of these properties are represented by vectors, such as displacement, velocity, force, and acceleration.

The resultant vector is the vector that is created when two or more vectors are added together. It depicts the final result of mixing the various vectors. The vector addition of the various vectors yields the resultant vector.

Given:

Magnitude = [tex]10 \ m[/tex]

x- component = [tex]6\ m[/tex]

The resultant vector is given as:

[tex]r = sqrt(x^2+y^2)\\10 = sqrt(6^2+y^2)\\y^2 = 100-36\\y = 8\ m[/tex]

Hence, the position vector with magnitude  [tex]10 \ m[/tex] points to the right and up. its x-component is [tex]6.0\ m[/tex] and its y-component is [tex]8\ m[/tex].

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Its orbital period is about 5.6 hours

[tex]\texttt{ }[/tex]

Newton's gravitational law states that the force of attraction between two objects can be formulated as follows:

[tex]\large {\boxed {F = G \frac{m_1 ~ m_2}{R^2}} }[/tex]

F = Gravitational Force ( Newton )

G = Gravitational Constant ( 6.67 × 10⁻¹¹ Nm² / kg² )

m = Object's Mass ( kg )

R = Distance Between Objects ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

speed of satellite = v = 5000 m/s

mass of earth = M = 6 × 10²⁴ kg

Asked:

orbital period = T = ?

Solution:

[tex]\Sigma F = ma[/tex]

[tex]G \frac{ M m} { R^2 } = m \frac{v^2}{R}[/tex]

[tex]G \frac{ M } { R^2 } = \frac{v^2}{R}[/tex]

[tex]G \frac{ M } { R } = v^2 [/tex]

[tex]R = G \frac{ M } { v^2 } [/tex]

[tex]2 \pi R = 2 \pi G \frac{ M } { v^2 } [/tex]

[tex]\frac{ 2 \pi R }{ v } = (2 \pi G \frac{ M } { v^2 } ) \div v[/tex]

[tex]T = 2 \pi G \frac{ M } { v^3 }[/tex]

[tex]T = 2 \pi \times 6.67 \times 10^{-11} \times \frac{ 6 \times 10^{24} } { 5000^3 }[/tex]

[tex]T \approx 20116 \texttt{ s}[/tex]

[tex]T \approx 5.6 \texttt{ hours}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Gravitational Fields

The orbital period of a satellite moving at 5000 m/s in a circular orbit around Earth is approximately 8500 seconds.

To find the orbital period (T) of a satellite moving in a circular orbit at a speed of 5000 m/s, we need to use the formula for orbital speed:

[tex]v = \frac{2\pi r}{T}[/tex]

Here, v is the orbital speed, and r is the radius of the orbit. We can rearrange this formula to solve for the period (T):

[tex]T = \frac{2\pi r}{v}[/tex]

First, we need to find the radius of the satellite's orbit. Assuming the satellite is close to Earth's surface, we'll use Earth's radius plus an additional small altitude:

r = 6371 km + 400km = 6.771 x 10⁶ m

Now, substitute the values into the formula:

[tex]T = \frac{2\pi (6.771 \times 10^6 \, \text{m})}{5000 \, \text{m/s}}[/tex]

Calculating this gives:

T ≈ 8515.68 seconds

Expressing the answer with two significant figures:

T ≈ 8500 seconds

The orbital period of a satellite moving at 5000 m/s in a circular orbit around Earth is approximately 8500 seconds. This calculation uses the Earth's radius and the orbital speed provided.

The angular speed at twice the initial radius becomes half of the initial angular speed.

Further Explanation:

Speed is the measure of a quantity of an object the tells how fast the object is moving in the other words we can define the speed that it is the distance covered by an body divided by the time taken to cover that distance. It is a quantity with only magnitude so it is a scalar quantity.

Given:

The certain angular speed is [tex]{\omega _2}[/tex].

The radius is [tex]r[/tex].

Concept:

The expression for the linear motion can be written as:

[tex]\fbox{\begin\\v=\dfrac{s}{t}\end{minispace}}[/tex]                               …… (1)

Here, [tex]v[/tex] is the linear speed, [tex]s[/tex] is the total distance covered and [tex]t[/tex] is the time taken to cover to distance.

The expression for the circular speed can be written as:

[tex]\fbox{\begin\\\omega=\dfrac{\theta }{t}\end{minispace}}[/tex]

Here, [tex]\omega[/tex] is the circular speed and [tex]\theta[/tex] is the angular displacement.

The expression for the total distance covered in term of angular displacement is:

[tex]s=\theta r[/tex]

Substitute [tex]\theta r[/tex] for [tex]s[/tex] in equation (1)

[tex]\begin{aligned}v&=\frac{{\theta r}}{t}\hfill\\v&=\frac{\theta }{t}\cdot r\hfill\\v&=\omega\cdot r\hfill\\\omega&=\frac{v}{r} \hfill\\ \end{aligned}[/tex]

From above expression the angular speed is inversely proportional to the radius.

[tex]\fbox{\begin\\\omega\propto\dfrac{1}{r}\end{minispace}}[/tex]

That is if the radius increases the angular speed decreases and if the radius decreases the angular speed increases.

Considered the linear speed remain content.

Case 1:

The angular speed is given by

[tex]{\omega _1}=\dfrac{v}{r}[/tex]                                                               …… (2)

Case 2:

The radius is double that is [tex]2r[/tex].

The angular speed is given by

[tex]{\omega _2}=\dfrac{v}{{2r}}[/tex]                                                         …… (3)

Divide equation (2) by equation (3).

[tex]\begin{aligned}\frac{{{\omega _2}}}{{{\omega _1}}}&=\frac{{\frac{v}{{2r}}}}{{\frac{v}{r}}}\hfill\\\frac{{{\omega _2}}}{{{\omega _1}}}&=\frac{1}{2}\hfill\\{\omega _2}&=\frac{{{\omega _1}}}{2}\hfill\\\end{aligned}[/tex]

Therefore, the angular speed at twice the initial radius becomes half of the initial angular speed.

Learn more:

1. Angular speed https://brainly.in/question/7744338

2. Angular velocity https://brainly.com/question/11209367

3. Angular speed https://brainly.com/question/4721004

Answer Details:

Grade: college

Subject: Physics

Chapter: Kinematics

Keywords:

Certain, angular speed, w2, radius, r, twice, w1/2, half, initial angular speed.

Answer: The answer is B. Add more solute (took test)

Explanation:

Answer:

It's definitely B add more solute.

Explanation:

In physics, some data points may need to be ignored just before and after a collision. This is done to remove errors and focus on the specific moment of collision.

In physics, it may be necessary to ignore some of the data points just before and just after a collision for various reasons. One reason is to remove outliers or errors in the measurements that could skew the results. For example, if there is a sudden spike or dip in the data due to a measurement error, it would be necessary to exclude those points to ensure accurate analysis.

Another reason is to focus on the specific moment of collision. By excluding the data points surrounding the collision, it allows for a clearer observation and analysis of the collision itself. This is important for understanding the dynamics and effects of the collision.

Therefore, it is not necessary to ignore both sets of data equally, but rather selectively remove data points that may introduce errors or hinder the analysis of the collision.

The answer is: That matter is indivisible and indestructible

Through his experiment, Henri Becquerel found that matters can be stored within another object, (He took potassium uranyl sulfate and put it under the sun and then put the substance within photographic plates that he cover with black paper, ) . Curie found that over time matters would decay and eventually gone.

The data transmission rate of the Eurostar rail service train, London to Paris via Chunnel  is  11516003 bite/second.

Transfer rate is a common metric for gauging how quickly data or information moves from one place to another.

Amount of of data stored in single-side = 8.54-gbyte.

Mass of the one double-layer DVDs= 0.015 g.

Total mass of DVDs = 10⁴ kg.

Total number of DVDs = 10⁴  ÷ 0.015  = 666667

Total amount of data =  666667 × 2 × 8.54 × 1024 × 8 bite

Total time taken = 2 hour 15 min = 2.25 hour = (2.25 × 3600) s = 8100 second

The data transmission rate is = (666667 × 2 × 8.54 × 1024 × 8) ÷ 8100 bite/second

= 11516003 bite/second.

Therefore, the data transmission rate of the Eurostar rail service train, London to Paris via Chunnel is  11516003 bite/second.

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If a 0.14-kg baseball is dropped from rest from a height of 2.0 m above the ground, then the magnitude of its momentum just before it hits the ground would be  0.8764 kg - m / s.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem if a 0.14-kg baseball is dropped from rest from a height of 2.0 m above the ground.

The velocity just before hitting the ground = √ ( 2 × 9.8 × 2)

                                                                       = 6.26 m / s

The magnitude of its momentum just before it hits the ground = 0.14 × 6.26

= 0.8764 kg - m / s

Thus, the magnitude of its momentum just before it hits the ground would be  0.8764 kg - m/s

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To balance the 90-kg load, a counterweight with a mass of 90 kg is required.

To balance the system, the torque exerted by the 90-kg load, l, must be equal to the torque exerted by the counterweight, s. The torque is given by the product of the force and the lever arm. Since the distance from the fulcrum to the load is x=450 mm, the torque exerted by the load is (90 kg)(9.8 m/s^2)(0.45 m). To balance this torque, the counterweight must exert an equal torque but in the opposite direction. Therefore, the mass of the counterweight can be calculated using the equation:

torque load = torque counterweight
(90 kg)(9.8 m/s^2)(0.45 m) = mass counterweight(9.8 m/s^2)(0.45 m)

Simplifying and solving for the mass of the counterweight, we have:

mass counterweight = (90 kg)(0.45 m) / 0.45 m = 90 kg

Therefore, the mass of the counterweight required to balance the 90-kg load is 90 kg.

Final answer:

In a chemical equation, an absent coefficient in front of a chemical formula indicates that the understood number is '1', signifying one mole of the substance in the reaction.

Explanation:

When there is no number in front of a chemical formula in a chemical equation, it is understood that the number is '1'. In a balanced chemical equation, coefficients are used to indicate the mole ratio in which the reactants combine to form products. If a chemical formula has no coefficient written before it, we assume the coefficient is 1. This means one mole of the substance is involved in the reaction. Coefficients are particularly important as they reflect the relative numbers of molecules or formula units in the reactants and products.

The component of the gravitational force parallel to the hill is mg⋅sin(65°). The acceleration of the rollercoaster down the hill is (mg⋅sin(65°))/m.

To determine the value of the component of the gravitational force parallel to the hill, we can use trigonometry. The component of the weight parallel to the hill is given by the equation mg⋅sinθ. In this case, θ is 65 degrees. So the value of the component of the gravitational force parallel to the hill is mg⋅sin(65°).

To find the acceleration of the rollercoaster down the hill, we can use Newton's second law, which states that force equals mass times acceleration. In this case, the force is the component of the gravitational force parallel to the hill, and the mass is given as 300 kg with passengers. So the acceleration is a = F/m = (mg⋅sin(65°))/m.

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