What is the length of chord cd in 0 below

Answer:

91 is a composite number

Step-by-step explanation:

A prime number is the positive number, which has factors 1 and itself.

Example : 1,3,5,7

Clearly 91 is not a prime number, as its factors are:

91 = 1,7,13,91

It has more than 2 factors (1 and itself), hence 91 is a composite number.

Composite number is the number which has factors other than 1 and itself.

Answer:

91 is composite

Step-by-step explanation:

its factors are 1, 7, 13, 91

Answer:

3rd

Step-by-step explanation:

Just look at the second equation in each system (no need to look at the others). The third is the only one that makes sense. The total value means the number of coins multiplied by value of each. The value in dollars is $9.35

If the value in the equation is in dollars, the variables must be multiplied by values in dollars. You can't multiply with 5 cents per nickle to equal 935 dollars. Makes no sense.

Answer:

C

Step-by-step explanation:

The Answer is C

Answer:

they each get $5.75 for lunch

Step-by-step explanation:

9.25 x 90 students = 832.50

832.50 -315 = 517.50

517.50 / 90 = 5.75

Answer:

D

Step-by-step explanation:

y>-3x+1                                 Negative slope

y<x+2                                   Positive slope

< or > have dotted line

< or > have a solid line

> or > means solutions are above the line

< or < means solutions are below the line

The one with negative slope has a dotted line and solutions above it.

The one with positive slope has a solid line and solutions below it.

to find the slope for the first one, use the formula [tex]\frac{y2-y1}{x2-x1}[/tex]

(It's the slope formula)

so... [tex]3=y2, 3=y1, 2=x2, 10=x1[/tex]

then plug in... [tex]\frac{3-3}{2-10} =\frac{0}{-8} = 0[/tex]

this line has a slope of 0

As for the miles problem, to find mph, the miles have to be at 1.

so... [tex]4x=242\\x=60.5[/tex]

therefore, he drove 60.5 mph

Answer:

Step-by-step explanation:

An estimate is usually a guess, but I somehow think that's not what you want.

She starts with 4 2/3 cups of batter. When she divides it into two, one of the batters has 2 1/4 cups. That's the one she puts blueberries in.

The other batter is the one you are interested in. How big is it?

Estimate: One

The estimated size would be 4 2/3 - 2 1/3 = 2 1/3 which is an estimate. It is just taking the closest number to use so you don't have to grab your calculator.

Actual Size: Two

4 2/3 - 2 1/4 is the size of the second batter. Since 2/3 is greater than 1/4 you need only subtract the whole numbers and then the fractions.

Whole number subtraction: 4 - 2 = 2

Fraction subtraction: 2/3 - 1/4

Find the Lowest common multiple between 3 and 4: It is 12. 3 and 4 are prime to each other. They have nothing in common.

So the actual size of the batter containing the walnuts is 2 5/12

Hello.

The answer is: Bounded.

This is correct because 32 is the endpoint and the real number of Y.

Have a nice day.

Answer:c. bounded,

Step-by-step explanation: got it correct on edge.

Answer:

No, the solution discussed in question is not correct.

Step-by-step explanation:

Length of the garden ,l= 80 feet

Breadth of the garden ,b= 40 feet

Area of the rectangle = l × b

Area of the garden = A

[tex]A=l\times b = 80 ft\times 40 ft = 3,200 ft^2[/tex]

Area covered by 1 bag of seeds of grass = [tex]25 yard^2=225 ft^2[/tex]

[tex]1 yard^2 = 9 ft^2[/tex]

Bags of seed of grass covering area of [tex]3,200 ft^2[/tex]:

[tex]\frac{3200 ft^2}{225 ft^2}=14.22[/tex]

14.22 bags of seed of grass will occupy the area covered by the garden.

A quadratic function can not have a maximum and minimum value. It can only take on one of those. The quadratic only makes one turn, so if the quadratic opens upwards, there is a minimum. If the quadratic opens downwards, there is a maximum.

A quadratic function can have either a maximum value or a minimum value, but not both.

A quadratic function can have either a maximum value or a minimum value, but not both. Whether it has a maximum or minimum value depends on the coefficient of the quadratic term (a) in the function. If a is positive, the graph of the quadratic function opens upwards and has a minimum value. If a is negative, the graph opens downwards and has a maximum value.

For example, the function y = x² has a minimum value of 0 at the vertex of the parabola, while the function y = -x^2 has a maximum value of 0 at the vertex.

Therefore, a quadratic function cannot have both a maximum value and a minimum value.

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Answer: 2/1 is the rate of change.

Step-by-step explanation: 1/4 and 2/6. Take these 2 numbers. 2-1=1 and 6-4=2. Therefore we get 2/1.

only know number 1 sorryyyy

1 . 11^2⋅√58

Answer:

1. [tex]18 \cdot \sqrt{638}[/tex]

2. [tex]\frac{y^{3}}{2 x^4}[/tex]

3. [tex]\frac{2 x^2}{3 y z^{−7}} [/tex]

Step-by-step explanation:

1. Assuming the expression is:

[tex]3 \cdot \sqrt{22} \cdot \sqrt{58} \cdot \sqrt{18}[/tex]

Express the radicands as multiplication of prime numbers:

[tex]3 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot \sqrt{3^2 \cdot 2}[/tex]

Distribute the radicals over the multiplication where a power is present:

[tex]3 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot \sqrt{3^2} \cdot \sqrt{2}[/tex]

[tex]3 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot 3 \cdot \sqrt{2}[/tex]

[tex]9 \cdot \sqrt{11 \cdot 2} \cdot \sqrt{2 \cdot 29} \cdot \sqrt{2}[/tex]

Apply the inverse of distributive property of radicals over multiplication:

[tex]9 \cdot \sqrt{11 \cdot 2 \cdot 2 \cdot 29\cdot 2}[/tex]

[tex]9 \cdot \sqrt{11 \cdot 2^2 \cdot 29\cdot 2}[/tex]

[tex]9 \cdot \sqrt{11 \cdot 29\cdot 2} \cdot \sqrt{2^2} [/tex]

[tex]9 \cdot \sqrt{638} \cdot 2 [/tex]

[tex]18 \cdot \sqrt{638}[/tex]

2. Assuming the expression is:

[tex](2 x^4 y^{-3})^{-1}[/tex]

Distribute the exponent over the multiplication

[tex]2^{-1} \cdot {(x^4)}^{-1} \cdot {(y^{-3})}^{-1}[/tex]

[tex]\frac{1}{2} \cdot x^{-4} \cdot y^{3}[/tex]

[tex]\frac{1}{2} \cdot \frac{1}{x^4} \cdot y^{3}[/tex]

[tex]\frac{y^{3}}{2 x^4}[/tex]

3. Assuming the expression is:

[tex]\frac{2 x^4y^{-4}z^{-3}}{3 x^2 y^{-3} z^4}[/tex]

Group by similar terms and simplify:

[tex]\frac{2}{3} \cdot \frac{x^4}{x^2} \cdot \frac{y^{-4}}{y^{-3}} \cdot \frac{z^{-3}}{z^4}[/tex]

[tex]\frac{2}{3} \cdot x^2 \cdot y^{-1} \cdot z^{-7}[/tex]

[tex]\frac{2 x^2}{3 y z^{-7}} [/tex]

The ratios 8/7 and 9/7 are not equivalent. Using cross multiplication, we find that the cross products are different, signaling that these two ratios are not equivalent.

To determine whether the ratios 8/7 and 9/7 are equivalent, we can cross multiply. In this case, if the two products are equal then the ratios would be equivalent.

Cross multiplication is a method used to test if two ratios are equivalent. It involves multiplying the numerator of the first fraction by the denominator of the second fraction and comparing that product with the product of the denominator of the first fraction and the numerator of the second fraction. If the two products are equal, then the two fractions are equivalent.

Using this method, the cross products of the ratios 8/7 and 9/7 are (8 * 7) and (9 * 7), which are 56 and 63, respectively. Since these two products are not equal, the two ratios are not equivalent.

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The answer is C) $250

Answer:

The answer is 250 dollars. to find this do 25 times 1000. the placement is 25 over 100 and x as in the amount were trying find over 1000.

Step-by-step explanation:

Answer:

The sum of the interior angles of a triangle is 180 degrees.

d. Scalene

e. Isosceles

f. Isosceles

g. Equilateral

h. Scalene

i. Equilateral

j. Right

l. Acute

m. Obtuse - doesn't add to 180 not a triangle

n. Acute - doesn't add to 180 not a triangle

o. Obtuse

Step-by-step explanation:

The interior angles of a triangle add to 180 degrees. There are two ways we classify triangle by side lengths and angle measures.

Side lengths: Compare the side lengths and see if any are equal to determine the type.

Angle Measures: Compare the angles measures to 90 degrees.

Answer:

D) |x| = a and |y| = b

Step-by-step explanation:

Given the numbers x = a and y = –b

Absolute function always gives the output as a positive number

Absolute function of |-x|= x

For example |5|= 5  and |-5| = 5

Given x=a

|x| = |a| = a, so |x| = a

Given y=-b

|y| = |-b| = b , so |y| = b

Hence, |x| = a and |y| = b

Answer:

Step-by-step explanation:

The table tells you that for every 1 package, you have 16 tortillas. Thus, the function is y = 16x.

y = amount of tortillas and x = number of packages

To find the number of packages for 64 tortillas, divide 64 by 16-- which gives you 4. Instead of "3" packages, change that number to "4".

To find the amount of tortillas in 8 packages, multiply 8 by 16-- which gives you 128 tortillas. Instead of "46", replace that amount with 128.

Divide 144 tortillas by 16, which gives you 9. The answer you gave is correct.

Multiply 10 packages by 16, which gives you 160-- your answer is also correct here.

Answer:

1 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

​a

​​ x

​b

​​ =x

​a+b

​​  

{a}^{2}+bb=289a

​2

​​ +bb=289

2 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

​a

​​ x

​b

​​ =x

​a+b

​​  

{a}^{2}+{b}^{2}=289a

​2

​​ +b

​2

​​ =289

3 Subtract {b}^{2}b

​2

​​  from both sides

{a}^{2}=289-{b}^{2}a

​2

​​ =289−b

​2

​​  

4 Take the square root of both sides

a=\pm \sqrt{289-{b}^{2}}a=±√

​289−b

​2

​​  

​

​​  

5 Rewrite 289-{b}^{2}289−b

​2

​​  in the form {a}^{2}-{b}^{2}a

​2

​​ −b

​2

​​ , where a=17a=17 and b=bb=b

a=\pm \sqrt{{17}^{2}-{b}^{2}}a=±√

​17

​2

​​ −b

​2

​​

6 Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)a

​2

​​ −b

​2

​​ =(a+b)(a−b)

a=\pm \sqrt{(17+b)(17-b)}a=±√

​(17+b)(17−b)

Answer:

The number is -1.

Step-by-step explanation:

Let the number be represented by n.

Then "9 is added to twice a number and this sum is multiplied by 6" is represented by 2n + 9, and

" the number is multiplied by 7 and 14 is added to the product" is

7n + 14.

Then the complete equation is 2n + 9 = 7n + 14.

We must solve this for n.  To accomplish this, subtract 2n from both sides, obtaining 9 = 5n + 14.  Then subtract 14 from both sides, obtaining

-5 = 5n.  Then n must be -1.

Answer:

The number is -8

Step-by-step explanation:

Developing an equation

Read these phrases a little a time.

Solution

Answer:

None of these

Step-by-step explanation:

y-5\√(2y2 - 7y -15)

On simplifying 2y2 - 7y -15, we get  

2y2 – (10-3)y -15

= 2y2 – 10y -3y-15

= 2y(y-5)-3(y-5)

= (2y-3)(y-5)

On squaring nominator and denominator we get  

(y-5)2/(2y-3)(y-5)

= (y-5)/(2y-3)

So the quotient becomes, 5/2  

While the remainder becomes 2.5

Answer:

I think its A

Step-by-step explanation:

Answer:

The answer is p · 9

Step-by-step explanation:

Product means multiplication

Answer:

The answer is p · 9

but, on gradpoint the answer is 9p

Step-by-step explanation:

Final answer:

To simplify 50% of one-twentieth of the product of 12 and 5z plus 5, you first calculate the product (60z), take one-twentieth (3z), find 50% of that (1.5z), and then add 5 to get the simplified expression 1.5z + 5.

Explanation:

The question asks to simplify the expression 50% of one-twentieth of the product of 12 and 5z plus 5. Here are the steps to simplify this expression:

Firstly, calculate the product of 12 and 5z, which is 60z.

Then, find one-twentieth of this product, which is 60z / 20 = 3z.

50% of 3z is 1.5z.

Finally, add 5 to 1.5z, which gives you 1.5z + 5 as the simplified expression.

So, the simplified expression is 1.5z + 5.

50% of one-twentieth of the product of (12) and[tex]\(5z + 5\) is \( \frac{3z}{2} + \frac{3}{2} \).[/tex]

To calculate 50% of one-twentieth of the product of [tex]\(12\) and \(5z + 5\)[/tex], we'll follow these steps:

Step 1: Calculate the product of [tex]\(12\) and \(5z + 5\)[/tex].

[tex]\[ \text{Product} = 12 \times (5z + 5) \][/tex]

Step 2: Calculate one-twentieth of the product.

[tex]\[ \text{One-twentieth of the product} = \frac{\text{Product}}{20} \][/tex]

Step 3: Calculate 50% (or half) of one-twentieth of the product.

[tex]{50% of one-twentieth of the product}[/tex] = [tex]\frac{1}{2} \times \frac{\text{Product}}{20} \][/tex]

Now, let's perform the calculations step by step:

Step 1: Calculate the product of [tex]\(12\) and \(5z + 5\):[/tex]

[tex]\[ \text{Product} = 12 \times (5z + 5) \][/tex]

[tex]\[ = 12 \times 5z + 12 \times 5 \][/tex]

[tex]\[ = 60z + 60 \][/tex]

Step 2: Calculate one-twentieth of the product:

[tex]\[ \text{One-twentieth of the product} = \frac{60z + 60}{20} \][/tex]

[tex]\[ = \frac{60z}{20} + \frac{60}{20} \][/tex]

[tex]\[ = 3z + 3 \][/tex]

Step 3: Calculate 50% of one-twentieth of the product:

{50% of one-twentieth of the product} =[tex]\frac{1}{2} \times \left(3z + 3\right) \][/tex]

[tex]\[ = \frac{1}{2} \times 3z + \frac{1}{2} \times 3 \][/tex]

[tex]\[ = \frac{3z}{2} + \frac{3}{2} \][/tex]

So, 50% of one-twentieth of the product of (12) and[tex]\(5z + 5\) is \( \frac{3z}{2} + \frac{3}{2} \).[/tex]

Answer:

X = apple

y = orange

4x + 4y = 10

6x + 6y = 12

Step-by-step explanation:

Answer:

4a+4r = 10

6a + 6r = 12

No solutions

Step-by-step explanation:

a = cost of the apple

r = cost of the orange

4a+4r = 10

6a + 6r = 12

Divide the first  equation by 2 and the second equation by 6

2a+2r = 5

a +r = 2

Multiply the second equation by -2 so we can eliminate a

-2a -2r = -4

Add the first equation

2a+2r = 5

-2a -2r = -4

---------------------

0 = 1

This system is inconsistent and has no solutions

Answer:

x = $4400

Step-by-step explanation:

If we want their pay to be the same, the equations have to be equal

g(x)=240+0.06x = f(x)=130+0.085x

240 + .06x = 130+0.085x

Subtract .06x from each side.

240 + .06x - .06x = 130+0.085x-.06x

240 = 130 +.025x

Subtract 130 from each side

240-130 = 130-130 +.025x

110 = .025x

Divide each side by .025 to isolate x

110/.025 = .025x/.025

4400 =x

Answer:

[tex]-2,\ -1,\ -\dfrac{1}{2},\ 3.[/tex]

Step-by-step explanation:

Consider polynomial [tex]2x^4+x^3-14x^2-19x-6.[/tex]

If x=-2 is its zero, then you can divide the polynomial [tex]2x^4+x^3-14x^2-19x-6[/tex] by [tex]x+2[/tex] and get

[tex]2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).[/tex]

If x=-1, then the polynomial [tex]2x^4+x^3-14x^2-19x-6[/tex] can be rewritten as

[tex]2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).[/tex]

The quadratic polynomial has roots

[tex]x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.[/tex]

Then the polynomial [tex]2x^4+x^3-14x^2-19x-6[/tex] has zeros [tex]-2,\ -1,\ -\dfrac{1}{2},\ 3.[/tex]

The value of x is 30.

We are given that lines l and m are parallel. We are asked to find the value of x.

Since we are given that l and m are parallel, we can use the property of alternate exterior angles.

This property states that when two lines are cut by a transversal, the alternate exterior angles are congruent.

In the diagram, we see that ∠A and 2x+15 ∘  are alternate exterior angles. Therefore, we have:  

∠A=2x+15 ∘

We are also given that ∠A=75 ∘ .

Substituting this value into the equation above, we get:

75 ∘ =2x+15 ∘

Solving for x, we get:

2x=75 −15 ∘

2x=60 ∘

x= 60/2 ∘

x=30∘

Therefore, the value of x is 30 ∘ .

Answer:

Side AB

Step-by-step explanation:

Draw two congruent quadrilaterals.

Label the sides of one A,B,C,and D.

Label the sides of the other E,F,G,and H

Because the sides match up with the order in which they appear in if they are congruent, The first two letters(E and F) should be equivalent to the first two letters of the other shape(A and B).