Answer:
6
Step-by-step explanation:
***If choosing one of each, this is the answer*** This wasn't clearly asked for in the question though
When counting the number of arrangements of multiple choices, multiply the number of choices of each item together.
(3)(2)(1) = 6
Here is them listed..
Green ball 1, red ball 1, white ball
Green ball 1, red ball 2, white ball
Green ball 2, red ball 1, white ball
Green ball 2, red ball 2, white ball
Green ball 3, red ball 1, white ball
Green ball 3, red ball 2, white ball
Please answer this question, will give brainliest!
See the attached picture:
The figure below is Circle E. Line CF is tangent at point C.
Find the measure of Angle ECF.
Find the measure of Angle AKB.
Find the measure of Angle ACF.
Answer:
Part 1) [tex]m<ECF=90\°[/tex]
Part 2) [tex]m<AKB=77.5\°[/tex]
Part 3) [tex]m<ACF=75\°[/tex]
Step-by-step explanation:
Part 1) Find the measure of angle ECF
we know that
CF is tangent at point C
so
the radius EC is perpendicular to the tangent CF
therefore
[tex]m<ECF=90\°[/tex]
Part 2) Find the measure of angle AKB
we know that
The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite
[tex]m<AKB=\frac{1}{2}(arc\ AB+arc\ DC)[/tex]
substitute the values
[tex]m<AKB=\frac{1}{2}(50\°+105\°)=77.5\°[/tex]
Part 3) Find the measure of angle ACF
we know that
The inscribed angle is half that of the arc it comprises
[tex]m<ACF=\frac{1}{2}(arc\ AB+arc\ BF)[/tex]
substitute the values
[tex]m<ACF=\frac{1}{2}(50\°+100\°)=75\°[/tex]
Answer:
∠ ECF = 90°
∠AKB = 77.5°
∠ACF = 75°
Step-by-step explanation:
The given figure is a circle E.
Line CF is tangent at point C.
(1) To find measures of angle ECF
Since line FC is tangent at point C and radius ECis always perpendicular to the tengent.
So ∠ ECF = 90°
(2) Measure of angle AKB
By theorem of angle formed by two interesting chords.
∠ AKB = [tex]\frac{1}{2}[/tex] (arc AB + arc CD)
= [tex]\frac{1}{2}[/tex] (50 + 105) = [tex]\frac{1}{2}(155)[/tex]
∠AKB = 77.5°
(3) Measure of angle ACF
Since tangent chord angle = [tex]\frac{1}{2}[/tex] (intercepted arc)
m (∠ACF) = [tex]\frac{1}{2}[/tex] (m arc AB + m arc BC)
= [tex]\frac{1}{2}(50+100)[/tex]
[tex]\frac{1}{2}(150)[/tex]
∠ACF = 75°
Find the polar equation of the conic with the focus at the pole, directrix y = -6, and eccentricity 4
Answer:
Choice B is correct
Step-by-step explanation:
The eccentricity of the conic section is given as 4 and thus the conic section is a hyperbola. Hyperbolas are the only conic sections with an eccentricity greater than 1.
Next, the directrix of this hyperbola is located at y = -6 implying that the hyperbola will be opening upwards. Consequently, the polar equation of this hyperbola will be of the form;
[tex]r=\frac{k}{1-4sin(theta)}[/tex]
The value of k in the numerator is the product of eccentricity and the absolute value of the directrix;
k= 4*6 = 24
The polar equation is thus given by alternative B
Answer:
B
Step-by-step explanation:
edge
Which equation is represented by the intersection of the graph below?
Answer:
tan(x) = 1
Step-by-step explanation:
The red curve(s) are y=tan(x). The horizontal line is y=1, so the point(s) of intersection are where tan(x) = 1.
_____
Sine and cosine do not have infinite range.
The range of secant excludes (-1, 1), so the only remaining possibility for the red curve is tan(x).
If the first step in the solution of the equation -x+6=5-3x is "subtract 5" then what would the next step be?
the next step would be add x to both sides to get x isolated
Answer:
i thought it was a but its b
Step-by-step explanation:
got it right on my test
the d string on a violin has a frequency of 293 hz when it is in tune. calculate the period.
Answer:The Time (period) is 0.003 s
Step-by-step explanation:
The period is equal to Time.
the formula for calculating Time (period) is:
Time (period)= 1/frequency
frequency= 293 hz
Time (period) = 1/293
= 0.003 s
Answer:
Period = 0.0034 seconds
Step-by-step explanation:
It is given that,
The d string on a violin has a frequency of 293 Hz when it is in tune. We have to find its period. The relationship between the time period and the frequency is given by :
[tex]T=\dfrac{1}{\nu}[/tex]
Here, [tex]\nu=293\ Hz[/tex]
So,
[tex]T=\dfrac{1}{293\ Hz}[/tex]
T = 0.0034 seconds
Hence, the period of the d string on a violin is 0.0034 seconds.
what degree of rotation will cause the triangle below to map onto itself
360 is the answer for sure
How to put Twelve birds are 3 more than twice the number of birds Rhonda saw yesterday as an equation
First set up birds is +3 than 2x the number of birds Rhonda saw
Rhonda's birds = r
Current set of birds = c
c = 2r + 3
Current birds are equal to three more than double the amount of birds rhonda saw
If your 5’3 and someone is 5 inches taller than you, how tall are they?
Answer:
5 foot 8
Step-by-step explanation:
The natural remedy echinacea is reputed to boost the immune system, which will reduce flu and colds. A 6-month study was undertaken to determine whether the remedy works. From this study, the following probability distribution of the number of respiratory infections per year (X) for echinacea users was produced: X 0 1 2 3 4 P(X) 0.343 0.322 0.201 0.076 0.058 Find the following probabilities: A. An echinacea user has more than one infection per year B. An echinacea user has no infections per year C. An echinacea user has between one and three (inclusive) infections per year
Answer:
A) 0.335; B) 0.343; C) 0.599
Step-by-step explanation:
For part A,
To find the probability that the user has more than one infection per year, we can either add together the probabilities for 2, 3, 4 and 5; or we can add together the probabilities for 0 and 1 and subtract them from 1:
1-(P(X = 0)+P(X = 1))
= 1-(0.343+0.322) = 1-0.665 = 0.335
For part B,
The probability that the user has no infections per year is P(X = 0); this is 0.343.
For part C,
The probability that the user has between 1 and 3 infections (inclusive) per year is
P(1 ≤ X ≤ 3) = 0.322+0.201+0.076 = 0.599
The probabilities are as follows: A. An echinacea user is likely to experience more than one infection per year with probability 0.335. B. The likelihood of an echinacea user having no infections per year is 0.343. C. The probability that an echinacea user has between one and three infections, inclusive, is 0.599.
Explanation:This question relates to probability distribution in mathematics. Here's how to find the probabilities:
Probablility A (more than one infection per year): We sum the probabilities of having 2, 3 or 4 infections. 0.201 (for 2 infections) + 0.076 (for 3) + 0.058 (for 4) = 0.335. Probability B (no infections per year): Given directly in the distribution, the probability of having zero infections is 0.343. Probability C (between one and three infections, inclusive): We add the probabilities of having 1, 2, or 3 infections. So, 0.322 (for 1 infection) + 0.201 (for 2) + 0.076 (for 3) = 0.599. Learn more about Probability Distribution here:https://brainly.com/question/32733554
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Consider that the length of rectangle A is 10 cm and its width is 6 cm. Which rectangle is similar to rectangle A? A) A rectangle with a length of 9 cm and a width of 6 cm. B) A rectangle with a length of 15 cm and a width of 9 cm. C) A rectangle with a length of 14 cm and a width of 7 cm. D) A rectangle with a length of 12 cm and a width of 8 cm.
Answer:
B) A rectangle with a length of 15 cm and a width of 9 cm
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional
Verify each cases
case A) A rectangle with a length of 9 cm and a width of 6 cm
[tex]\frac{10}{9}\neq \frac{6}{6}[/tex]
therefore
The rectangle case A) is not similar to rectangle A
case B) A rectangle with a length of 15 cm and a width of 9 cm
[tex]\frac{10}{15}=\frac{6}{9}[/tex]
[tex]\frac{2}{3}=\frac{2}{3}[/tex]
therefore
The rectangle case B) is similar to rectangle A
case C) A rectangle with a length of 14 cm and a width of 7 cm
[tex]\frac{10}{14}\neq \frac{6}{7}[/tex]
therefore
The rectangle case C) is not similar to rectangle A
case D) A rectangle with a length of 12 cm and a width of 8 cm
[tex]\frac{10}{12}\neq \frac{6}{8}[/tex]
therefore
The rectangle case D) is not similar to rectangle A
Answer:
A rectangle with a length of 15 cm and a width of 9 cm.
Step-by-step explanation:
In similar rectangles, the ratios of the corresponding sides are equal.In similar rectangles, the ratios of the corresponding sides are equal.
[tex]\frac{length}{width}[/tex] → [tex]\frac{10}{6}[/tex] = [tex]\frac{5}{3}[/tex] and [tex]\frac{15}{9}[/tex] = [tex]\frac{5}{3}[/tex]
Choose the graph which matches the function f(x) 2^x+2
Answer is C
If x=0, f(x) (or y) is 2^(0+2)=2²=4
So find the graph that runs through the point (0,4)
Graph C is the graph that represents the exponential function f(x) = 2ˣ⁺²
Which graph matches the function?
We want to find the graph that matches the function:
f(x) = 2ˣ⁺²
First, we can see that when x = 0 we have:
f(0) = 2² = 4
So we need to find the graph that intercepts the y-axis at y = 4. From the given options we can see a single graph that does that, which is option B, so we can conclude that B is the correct option.
Solve the equation. Round to the nearest hundredth. Show work.
[tex]4e^{5x} - e^{-x} = -3e^{2x}[/tex]
Answer:
The value of x = -0.46
Step-by-step explanation:
∵ [tex]4e^{5x}-e^{-x}=-3e^{2x}[/tex] ÷ [tex]e^{-x}[/tex]
∴ [tex]\frac{4e^{5x}}{e^{-x}}-\frac{e^{-x}}{e^{-x}}=\frac{-3e^{2x}}{e^{-x}}[/tex]
* Subtract the power of the same bases
∴ [tex]4e^{6x}-1=-3e^{3x}[/tex]
* Let [tex]e^{3x}=y[/tex]
∴ [tex]e^{6x}=y^{2}[/tex]
∴ 4y² - 1 = -3y
∴ 4y² + 3y - 1 = 0 ⇒ factorize
∴ (4y - 1)(y + 1) = 0
∴ y + 1 = 0 ⇒ y = -1
∴ 4y - 1 = 0 ⇒ 4y = 1 ⇒ y = 1/4
∵ [tex]y=e^{3x}[/tex]
∴ y = -1 refused ([tex]e^{ax}[/tex] never gives -ve value)
∴ [tex]e^{3x}=1/4[/tex] ⇒ insert ln in both sides
∵ [tex]lne^{ax}=axln(e)=ax[/tex] ⇒ ln(e) = 1
∴ 3xln(e) = ln(1/4)
∴ 3x = ln(1/4)
∴ x = [ln(1/4)] ÷ 3 = -0.46
The hour hand on a clock turns through an angle of 30° each hour.What is the measure of the total turn that the hour hand makes in 2 hours?
Answer:
60
Step-by-step explanation:
Since it turns 30 degrees each hour, it is simply 2 * 30 which is 60.
Alan takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $98 per credit hour, and at Pinewood, class fees are $115 per credit hour. Alan is taking a combined total of 19 credit hours at the two schools.
Suppose that he is taking w credit hours at Westside. Write an expression for the combined total dollar amount he paid for his class fees.
Total he payed (in dolllars) = ?
Answer:
Step-by-step explanation: If w is hours at Westside, then (18-w) is the number of hours taken at Pinewood.
Cost to westside = 98w. Cost to Pinewood = 115(18-w).
Total cost = 98w + 115(18 - w) = 2070 - 17w.
[I guess there should be some constraints like 0 > w > 18]
I put it as "greater than" rather than "greater than or equal" because the problem states he takes classes at both schools, hence he has to take at least something at Westside, and similarly he has to take something at Pinewood so he would not take all 18 hours at Westside.
Answer:
98 × w + $115(19-w)
Step-by-step explanation:
We are given that Alan takes classes at both Westside Community College, where class fees are $98 per credit hour, and Pinewood Community College, where class fees are $115 per credit hour.
If Alan is taking a total of 19 credit hours at the two mentioned schools, we are to write an expression for the combined total dollar amount he paid for his class fees.
Considering the fees per credit hour mentioned for each school, we can write the total payed fees as:
[tex]98 \times w + $115(19-w)[/tex]
A certain shade of blue is made by mixing 1.5 quarts of blue paint with 5 quarts of white paint. If you need a total of 16.25 gallons of this shade of blue paint, how much of each color should you mix
To create 16.25 gallons of a certain shade of blue paint, based on a ratio of 1.5 quarts of blue to 5 quarts of white, one would need to mix 15 quarts of blue paint with 50 quarts of white paint.
The student is asking how to scale a recipe for paint, which involves a ratio of blue paint to white paint, to create a specific amount of a new shade of blue. Given that the original ratio is 1.5 quarts of blue paint to 5 quarts of white paint, and the goal is to mix up 16.25 gallons of this shade, we need to calculate the amount of each color needed.
Step-by-Step Explanation:
First, identify the total number of quarts needed since the question includes quarts and gallons. Since there are 4 quarts in a gallon, multiply 16.25 gallons by 4 to convert to quarts.
16.25 gallons imes 4 = 65 quarts
Next, calculate the ratio of blue to total quarts, and white to total quarts. The original recipe has 1.5 quarts of blue paint out of a total of 6.5 quarts, as 1.5 quarts of blue plus 5 quarts of white equals 6.5 quarts.
Determine the proportions: Blue Paint = (1.5 / 6.5) times Total Quarts and White Paint = (5 / 6.5) times Total Quarts.
Calculate the required amounts: Blue Paint = (1.5 / 6.5) times 65 quarts = 15 quarts and White Paint = (5 / 6.5) times 65 quarts = 50 quarts.
In conclusion, to mix 16.25 gallons of the shade of blue paint, 15 quarts of blue paint and 50 quarts of white paint are required.
You would need 19.5 quarts of blue paint and 65 - 19.5 = 45.5 quarts of white paint to make a total of 16.25 gallons of the shade of blue paint.
To find out how much of each color should be mixed, we first need to convert the total amount needed into quarts.
16.25 gallons * 4 quarts/gallon = 65 quarts
Now, since the ratio of blue paint to white paint is 1.5:5, we can set up a proportion to find out how much of each color should be used:
1.5/5 = x/65
Cross multiplying:
5x = 1.5 * 65
5x = 97.5
x = 97.5 / 5
x = 19.5
So, you would need 19.5 quarts of blue paint and 65 - 19.5 = 45.5 quarts of white paint to make a total of 16.25 gallons of the shade of blue paint.
Triangle ABC is similar to triangle PQR, as shown below: Two similar triangles ABC and PQR are shown. Triangle ABC has sides AB = c, BC = a, and AC = b. Triangle PQR has sides PQ = r, QR = p, and PR = q. Angle CAB is congruent to angle RPQ. Angle ABC is congruent to angle RQP. Angle ACB is congruent to angle QRP. Which ratio is equal to r:c? c:p p:a r:a q:c
Answer:
p:a
Step-by-step explanation:
given: AB=c, BC=a, CA=b
PQ=r, QP=p, PR=q
also , ∠CAB ≅ ∠RPQ,--------- (1)
, ∠ABC ≅ ∠RQP,---------(2)
and, ∠ACB ≅ ∠QRP,---------(3)
FROM (1), (2) AND (3),
we can say that a=p, b=q, c=r
therefore, the triangles are congruent (S.S.S congruence criteria),
also then, r:c=1
then the ratio equal to r:c, will be p:a ( since p=a and p:a would be =1)
Answer:
i believe that the answer is P:A if it is not I'm sorry
Step-by-step explanation:
Becky graphs a system of two linear equations and determines that (1,5) and (3,7) are solutions. What does the graph of the system look like? How many solutions are possible? A) curve; two solutions B) two lines; one solution C) two lines; two solutions D) one line; infinitely many
Answer:
D
Step-by-step explanation:
I got it right
There infinitely many solutions are possible. Option D is correct.
What are simultaneous linear equations?Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.
Here,
For two intersecting lines, it is not possible that the lines have only two solutions, either the lines have one solution or the lines have infinitely many solutions,
In our case line have infinitely many solutions,
Because the equations of the lines are the same.
Now,
The equation of the line is given as,
y - y₁ = m (x - x₁)
y - 5 = [7-5 / 3-1] (x - 1)
y = x - 1 + 5
y = x + 4
Thus, there infinitely many solutions are possible. Option D is correct.
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Please answer this question, will give brainliest!
Answer:
6.63 cm
Step-by-step explanation:
The segments within the circle form a right angle. Triangle CRS as a right triangle must follow the Pythagorean theorem which says the square of each leg adds to the square of the hypotenuse.
a² + b² = c²
Here a is unknown, b = 10 and c = 12.
a² + 10² = 12²
a² + 100 = 144
a² = 44
a = √44 = 6.63
Two cards are drawn without replacement from standard deck of 52 cards. What is the probability that the first card is a spade and the second card is a heart and are these events independent?
103 / 204; Yes, they are independent events
1 / 17; No, they are dependent events
1 / 2; Yes, they are independent events
13 / 204; No, they are dependent events
Answer:
13 / 204; No, they are dependent events
Step-by-step explanation:
Total number of cards in the deck = 52
Total number of spades in the deck = 13
Total number of hearts in the deck = 13
Part 1: Calculating the Probability
Picking up the first card:
When picking the first card i.e spade, we have the option to pick 13 cards out of 52. So the probability will be 13/52
When first card is picked, the total number of cards will be reduced to 51 because we are not placing the card back in the deck
Picking up the second card:
When picking up the second card i.e. heart, we have the option to pick 13 cards out of 51. So the probability will be 13/51
The probability of picking a spade and then a heart is = 13/52 x 13/51 = 13/204
Part 2: Independent or Not
Note that, picking up a spade and not replacing it back is changing the probability of picking up a heart. In normal cases, picking up a heart from a deck will have the probability of 13/52, but since the we are not placing the card back the probability is changed to 13/51
Since, the probability of picking a heart is being changed by the previous event, we say that the two events are dependent.
Therefore, the correct answer will be final option: 13 / 204; No, they are dependent events
For a school drama performance, student tickets cost $5 each and adult tickets cost $10 each. The sellers collected $3,570 from 512 tickets sold. If c is the number of student tickets sold, which equation can be used to find the amount of tickets sold of each type?
Answer:
The number of adult tickets sold is a=202\ tickets
The number of student tickets sold is c=310\ tickets
Step-by-step explanation:
c------> the number of student tickets sold
a-----> the number of adult tickets sold
we know that
a+c=512 -----> equation A
5c+10a=3,70-----> equation B
therefore
the solution is
the number of adult tickets sold is a= 202 tickets
the number of student tickets sold is c= 310 tickets
A factory can produce 100 bracelets every 15 minutes. How many bracelets can the factory produce in three and a half hours?
Answer:
1,400 bracelets in 3 and a half hours
Step-by-step explanation:
First you have to find how many minutes are in 3 and a half hours. 1 hour is 60 minutes, so 60 + 60 + 60 is 3 hours or 180 minutes and 30 minutes is a half an hour. Therefore 3 and a half hours equals 210 minutes. Set up an equal proportion: 100 bracelets / 15 min = x bracelets / 210 min. Use algebra to solve: 100 * 210 = 15x → 21000 = 15x → 1400 = x.
1400 bracelets can the factory produce in three and a half hours.
What is Unitary Method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.
For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.
12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.
As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.
This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.
Given:
A factory can produce 100 bracelets every 15 minutes.
So, In one minutes the factory produced
= 100 /15
= 20/3
Now, In three and a half hours ( 210 minutes) the factory can make
= 20/3 x 210
= 20 x 70
= 1400
Hence, In three and a half hours 1400 bracelets can be made.
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Evaluate the log without a calculator ( Show your work )
The problem is in the image. I don't know how to write it.
Answer:
4
Step-by-step explanation:
Given in the question a logarithm expression
[tex]7^(log_{49}16 )[/tex]
We will use Exponent of Log Rule
[tex]b^(log_{b}k ) = k[/tex]
here b = 7
k = 16
So suppose
[tex]7^(log_{49}16 ) = x\\Take square on both sides\\(7^(log_{49}16 ) )^{2} = x^2\\49^(log_{49}16)= x^2[/tex]
Now, according to the rule
16 = x²
to find x only take square root on both sides of the equation
x = √16
x = 4
so [tex]7^(log_{49}16 )[/tex] = 4
What is the solution to the compound inequality 3x − 8 ≥ −5 and 2x − 7 < 5?
x ≤ 1 and x > 6
1 ≤ x < 6
x > 1 and x > 6
1 < x < 6
1<x<6 or its x>1 and x>6
The solution to the compound inequality is given by:
[tex]1\leq x<6[/tex]
Step-by-step explanation:The compound inequality is given by:
[tex]3x-8\geq -5[/tex] and
[tex]2x-7<5[/tex]
On solving the first inequality i.e.[tex]3x-8\geq -5[/tex]
on adding both side of the inequality by 8 we get:
[tex]3x\geq -5+8\\\\i.e.\\\\3x\geq 3[/tex]
Now on dividing both side of the inequality by 3 we get:
[tex]x\geq 1[/tex]
The second inequality is given by:[tex]2x-7<5[/tex]
On adding both side of the inequality by 7 we get:
[tex]2x<5+7\\\\i.e.\\\\2x<12[/tex]
on dividing both side of the inequality by 2 we get:
[tex]x<6[/tex]
Hence, the solution of the compound inequality is:
[tex]1\leq x<6[/tex]
-2(-25)+2y=44 solve for y please!!! semi-urgent! I will give the correct answer brainliest!!!
Answer:
y = -3
Step-by-step explanation:
First, subtract 44 from both sides of the equation to set it equal to 0. This will give you 6 + 2y = 0. Then, subtract 6 from both sides, leaving you with 2y = -6. Then just divide both sides by 2 to isolate the y and give you your answer. -6 divided by 2 is -3. y = -3
Suppose a 95% confidence interval for μ turns out to be (1,000, 2,100). give a definition of what it means to be "95% confident" as an inference.
Answer:
In repeated sampling, 95% of the intervals constructed would contain the population mean.
A jar contains 30 marbles. It has 10 red, 6 black and 14 green marbles. Two marbles are drawn, the first is not returned before the second one is drawn. What is the probability that both marbles are green?
P(Both Green) =
14 / 169
P(Both Green) =
91 / 435
P(Both Green) =
7 / 15
P(Both Green) =
49 / 225
Answer:
The correct answer option is P (both green) = 91 / 435
Step-by-step explanation:
We are given that in a jar containing 30 marbles, 10 are red, 6 are black and 14 are green.
Two marbles are drawn and the second one is drawn without returning the first marble and we are to find the probability of getting green marbles both time.
P (both green) = [tex] \frac { 1 4 } { 3 0 } \times \frac { 1 3 } { 2 9 } [/tex] = 91 / 435
HELP ASAP What is the simplified value of the exponential expression 216^1/3
Answer:
Final simplified expression is 6.
Step-by-step explanation:
We have been given an expression [tex]216^{\frac{1}{3}}[/tex].
Now we need to simplify [tex]216^{\frac{1}{3}}[/tex] So let's do that by factoring 216 first so that we can have same repeating factor thrice
[tex]216^{\frac{1}{3}}[/tex]
[tex]=(6*6*6)^{\frac{1}{3}}[/tex]
[tex]=(6^3)^{\frac{1}{3}}[/tex]
Apply formula [tex](x^m)^n= x^{m*n}[/tex]
[tex]=6^{3*\frac{1}{3}}[/tex]
[tex]=6^{1}[/tex]
[tex]=6[/tex]
Hence final simplified form is 6.
Suppose y varies directly with x. If y = –4 when x = 8, what is the equation of direct variation? Complete the steps to write the equation of direct variation. Start with the equation of direct variation y = kx. Substitute in the given values for x and y to get . Solve for k to get . Write the direct variation equation with the value found for k. The equation is
Answer:
y = -1/2 x
Step-by-step explanation:
Follow the directions "Complete the steps to write the equation of direct variation. Start with the equation of direct variation y = kx. Substitute in the given values for x and y to get . Solve for k to get . Write the direct variation equation with the value found for k."
y = kx substitute y = -4 and x = 8.
-4 = k*8
-4/8 = k
-1/2 = k
So the equation is y = -1/2(x).
Answer:
1. Start with the equation of direct variation y = kx.
2.Substitute in the given values for x and y to get: -4=k(8)
3. Solve for k to get: -1/2
4. Write the direct variation equation with the value found for k. The equation is: y=(-1/2)x
Step-by-step explanation:
I just did it on e2020
What is the equation of the line, in slope-intercept form, that passes through the point (6,−1) and is perpendicular to the line y=2x−7?
A)y=2x+13
B)y=−12x+2
C)y=12x−4
D)y=12x+132
did you mean to put. y= -1/2x+2 for choice b? because that's what I got as a solution