What method can be used to write the equation of a line in slope-intercept form given two points?

89.87 is 215% of approximately 41.8. This is found by converting 215% to a decimal (2.15) and dividing the given number (89.87) by this decimal.

The student's question relates to an application of percentages. To work out this problem, we must first understand that in this context, 215% is equivalent to 2.15 when transformed into a decimal. We then divide the given number, 89.87, by 2.15 to find the original value. The calculation would be as follows: 89.87 ÷ 2.15, which equates to approximately 41.8. Therefore, 89.87 is 215% of the number 41.8.

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Answer:

10 or answer B.

Step-by-step explanation:

(a) The formula for the sum of the first n even positive integers is n(n+1) and (b) the formula has been proved with an example.

Arithmetic progression is the sequence of numbers that has a fixed common difference between any two consecutive numbers.

For the given situation,

Part (a):

The sum of even numbers formula is obtained by using the sum of terms in an arithmetic progression formula.

Sum of Even Numbers Formula = n(n+1),

where n is the number of terms in the series.

Part (b):

Let us consider the even positive numbers,

2,4,6,8,10,.......

Now take first 5 positive numbers 2,4,6,8,10

By using the formula, n=5

Sum of n even positive integers = [tex]n(n+1)[/tex]

⇒ [tex]5(5+1)[/tex]

⇒ [tex]5(6)[/tex]

⇒ [tex]30[/tex].

Now add the first 5 positive numbers without the formula,

⇒ [tex]2+4+6+8+10=30[/tex]

Hence we can conclude, that the formula for the sum of the first n even positive integers is n(n+1) and the formula has been proved with an example.

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The formula for the sum of the first n even positive integers is S = n(n+1). This was derived by recognizing the pattern of the series and using the formula for the sum of an arithmetic series. The proof by induction confirms the validity of our formula.

The problem asks us to find and prove a formula for the sum of the first n even positive integers. To find the formula, we recognize that the first n even integers can be represented as 2, 4, 6, ..., 2n. Hence, the sum S of the first n even integers can be written as S = 2 + 4 + 6 + ... + 2n. This is an arithmetic series with the first term a = 2 and the common difference d = 2. The sum of an arithmetic series can be given by the formula S = n/2 [2a + (n-1)d], substituting a = 2 and d = 2, we get S = n/2 [2*2 + (n-1)2] = n[2 + 2(n-1)], which simplifies to S = n(n+1).

To prove this formula, we use induction. For n=1, the sum is 2, which matches our formula 1(1+1) = 2. Assuming the formula holds for n = k, for n = k+1, the sum would include one more term, 2(k+1), so the new sum is S + 2(k+1) which upon simplification, verifies our formula for all n.

Answer:

[tex]-2\sqrt{1+\cos(x)}+C[/tex]

Step-by-step explanation:

[tex]\boxed{\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))}[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{\sin(x)}{\sqrt{1+\cos(x)}}\;\text{d}x[/tex]

To evaluate the given integral, we can use the method of substitution.

Integration by substitution is a way of integrating a function of a function by simplifying the integral. To integrate by substitution, write part of the function in terms of u, where u is some function of x.

Use the substitution u = 1 + cos(x).

Start by differentiating u with respect to x:

[tex]\begin{aligned}u&=1+\cos(x)\\\\\dfrac{\text{d}u}{\text{d}x}&=0-\sin(x)\\\\\dfrac{\text{d}u}{\text{d}x}&=-\sin(x)\end{aligned}[/tex]

Now rearrange the equation for du/dx to get dx on its own:

[tex]\text{d}u=-\sin(x)\:\text{d}x[/tex]

[tex]\text{d}x=-\dfrac{1}{\sin(x)}\:\text{d}u[/tex]

Substitute everything into the original expression:

[tex]\begin{aligned}\displaystyle \int \dfrac{\sin(x)}{\sqrt{1+\cos(x)}}\;\text{d}x&=\int \dfrac{\sin(x)}{\sqrt{u}}\cdot -\dfrac{1}{\sin(x)}\:\text{d}u\\\\ &=\int -\dfrac{1}{\sqrt{u}}\:\text{d}u\end{aligned}[/tex]

Simplify the integral and evaluate:

                              [tex]\begin{aligned}&=\displaystyle \int -u^{-\frac{1}{2}}\:\text{d}u\\\\&=\dfrac{-u^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+C\\\\&=\dfrac{-u^{\frac{1}{2}}}{\frac{1}{2}}+C\\\\&=-2\sqrt{u}+C\end{aligned}[/tex]

[tex]\textsf{Finally, substitute $u=1+\cos(x)$ back in:}[/tex]

                              [tex]=-2\sqrt{1+\cos(x)}+C[/tex]

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Commission is calculated by multiplying sales revenue by the commission rate; this incentivizes sales, aiming to balance salary, commission, and overall business objectives like profitability and customer satisfaction.

The formula for calculating commission is usually based on the sales revenue multiplied by the commission rate. If, for example, a sales employee sells $10,000 worth of products and the commission rate is 5%, the calculation would be $10,000 x 0.05 = $500.

Commissions serve as a motivational tool in sales. They provide sales employees with an incentive to increase sales, as their earnings are directly linked to the success of their efforts. Optimal sales volume, profitability, and customer satisfaction are central to a well-balanced compensation plan that incorporates both a base salary and a commission structure.

The numbers in order from least to greatest are:

To order the numbers from least to greatest, we need to convert them all to decimals.

25/7 = 3.57142857...

√12 = 3.4641016151377544

49 V4 = 49/4 = 12.25

Therefore, the numbers in order from least to greatest are:

√12,

3.6,

25/7,

49 √4

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The number that can be added to √7 to get a rational number is -√7.

A number of the form a/b where a and b are integers and b ≠ 0 is called a rational number.

The given number is √7.

√7 is an irrational number.

Note that the square root of prime numbers is irrational, therefore, to get a rational number by addition, the only way is to add the negative reciprocal of the given irrational number.

The negative reciprocal of √7 is -√7, therefore, add -√7 to √7:

√7 + (-√7) = 0 (a rational number).

Hence, the number that can be added to √7 to get a rational number is -√7.

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The equation (a) y = 3/4x, equation (b) y = 0.6x, equation (d) y = 2/3x are correct option because they have greater rate than A

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

We have;

Relationship B has a greater rate than Relationship A.

From the graph, the rate of A or slope will be:

A(m) = (4-2)/(8-4) = 2/4

A(m) =1/2 = 0.5

From the given option, the equation  y = 3/4x, y = 0.6x, and y = 2/3x has a greater rate than A which is 3/4, 0.6, and 2/3 respectively.

Thus, the equation (a) y = 3/4x, equation (b) y = 0.6x, equation (d) y = 2/3x are correct option because they have greater rate than A

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Answer:

[tex]10x^2-25x-35[/tex]

Step-by-step explanation:

The FOIL method is used to multiply two binomials.

FOIL stand for:

First : Multiply the first term in each set of parenthesis.

Outer : Multiply the outer term in each set of parenthesis.

Inner : Multiply the inner term in each set of parenthesis.

Last: Multiply the last term in each set of parenthesis.

Given that:

[tex](2x-7)(5x+5)[/tex]

Using the foil method:

[tex]2x(5x+5)-7(5x+5)[/tex]     [Using distributive property]

⇒[tex]10x^2+10x -(35x+35)[/tex]

⇒[tex]10x^2+10x -35x-35[/tex]

Combine like terms:

⇒[tex]10x^2-25x-35[/tex]

Therefore, the product of (2x – 7)(5x+5) using FOIL method is, [tex]10x^2-25x-35[/tex]

To write the height h of the rectangle as a function of x, you need to understand the relationship between the height and the other variables involved.

To write the height h of the rectangle as a function of x, you need to understand the relationship between the height and the other variables involved. In a rectangle, the height is typically perpendicular to the base.

So, if we assume that x represents the base length, then the height h can be written as a function of x using an equation.

For example, if the rectangle has a fixed width, the height can be calculated using the following equation: h = f(x), where f is the function that describes the relationship between the base length x and the height h.

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Answer:

d. 96

Step-by-step explanation:

on usa test prep

Answer:

Option 2 - log base 2 of 6 over log base 2 of 3

Step-by-step explanation:

Given : Expression [tex]\log_3 6[/tex]

To find : Write the expression as a  logarithm of base 2?

Solution :

Expression [tex]\log_3 6[/tex]

Applying the change-of-base formula,

[tex]\log_a(x)= \frac{\log_b(x)}{\log_b(a)}[/tex]

On comparing, a = 3, x = 6, b = 2

Substitute in the formula,

[tex]\log_3 (6)= \frac{\log_2(6)}{\log_2(3)}[/tex]

Therefore, Option 2 is correct.

Option 2 - log base 2 of 6 over log base 2 of 3

To prove that (x-s-t) is a factor of the polynomial $x^3 - s^3 - t^3 -3st(s+t)$, we applied the factor theorem which states that (x-c) will be a factor of a polynomial if f(c) equals zero. By substituting x with (s+t) into the polynomial, we got a value of zero, confirming that (x-s-t) is indeed a factor.

To prove that (x-s-t) is a factor of $x^3 - s^3 -t^3 -3st(s+t)$, we can use the factor theorem. According to the factor theorem, a polynomial f(x) has a factor (x-c) if and only if f(c) equals zero.

Given the polynomial $x^3 - s^3 - t^3 -3st(s+t)$, we substitute (x = s + t) into the polynomial, thus:

$f(s + t) = (s + t)^3 -s^3 -t^3 - 3st(s + t)$.

After simplifying the equation, we obtain:

$s^3 + 3s^2t +3st^2  + t^3 - s^3 - t^3 - 3st^2 - 3s^2t$.

When we cancel out the like terms, the result is 0. Therefore,

$(x - s - t)$ is a factor of the given polynomial $x^3 - s^3 -t^3 -3st(s+t)$. This proves our result according to the Factor theorem.

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800 students participated at a charity bike rally

What are mathematics operations?

• A mathematical operation is a function that converts a set of zero or more input values (also called "b" or "arguments") into a defined output value. The number of operands determines the operation's arity. Most commonly studied operations are binary operations (i.e., operations of arity 2), such as addition and multiplication, and unary operations (i.e., operations of arity 1), such as additive and multiplicative inverses.

• Zero-arity operations, or nullary operations, are constants, and mixed products are arity three operations, or ternary operations.

It is given that :

there are 1200 students population of Heartsworth Middle School.

and, 2/3 of the student participated in a charity bike rally That is :

(2 x 1200)/ 3 = 2400/3 = 800 students

Therefore, 800 students participated at a charity bike rally.

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Answer:

0.625

Step-by-step explanation:

We are given that

Kesia knows =[tex]\frac{1}{4}=0.25[/tex]

We have to determine the decimal equivalent to [tex]\frac{5}{8}[/tex] using given decimal value.

[tex]\frac{5}{8}[/tex] can be written as

[tex]\frac{5}{8}=\frac{2}{8}+\frac{2}{8}+\frac{\frac{1}{4}}{2}[/tex]

[tex]\frac{5}{8}=\frac{1}{4}+\frac{1}{4}+\frac{\frac{1}{4}}{2}[/tex]

[tex]\frac{5}{8}=0.25+0.25+\frac{0.25}{2}[/tex]

[tex]\frac{5}{8}=0.50+\frac{0.25}{2}[/tex]

[tex]\frac{5}{8}=0.625[/tex]

Hence,[tex]\frac{5}{8}=0.625/tex]

The set of statements always have the same truth value will be Conditional and Contrapositive i.e. Option [tex](D)[/tex] .

Conditional and Contrapositive : If the conditional statement is “If P then Q.” Then converse of the conditional statement is “If Q then P.” The contrapositive of the conditional statement is “If not Q then not P.” The inverse of the conditional statement is “If not P then not Q.”

So,

As per given options,

Option [tex](B)[/tex] and [tex](C)[/tex] have inverse, so they have nothing to do with inverse.

Now,

So, according to the above mentioned definition,

Option [tex](D)[/tex] Conditional and Contrapositive is the correct option.

Hence, we can say that the set of statements always have the same truth value will be Conditional and Contrapositive Option [tex](D)[/tex] .

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