What part of an atom can change during a nuclear reaction but cannot change during a chemical reaction

Answer: Option D

Explanation: The cellular respiration and photosynthesis both is performed by the plants. The process of photosynthesis can be defined as the process by which the carbon dioxide and sunlight is used by the plants to make food( glucose) and releases oxygen.

This process convert light energy into chemical energy. The product formed is stored in the form of starch.

The cellular respiration breaks down the glucose and provides energy for the cells to do work.

A motorcycle turning around a corner is not in a state of equilibrium. So, option 2 is correct.

The state of equilibrium of an object is defined as its condition in which all the external forces acting on it are balanced. The state where Newton's first law is valid.

Here,

The state of equilibrium means that Newton's first law is valid in the situation.

That means the net force acting on an object in equilibrium will be zero.

Case-1

A racecar maintaining a constant velocity.

Here, the racecar is moving with a constant velocity. That means it will not accelerate. So, the acceleration of the racecar will be zero. Hence, the net force acting on it is also zero. Therefore, it is in equilibrium.

Case-2

A motorcycle turning around a corner.

When the motorcycle turns around a corner, it will follow a circular motion and as a result, there will be centripetal force experienced by the motorcycle. As a result, the direction of the velocity changes. Therefore, the motorcycle will not be in a state of equilibrium.

Case-3

A chandelier hanging from the ceiling

Since, the chandelier is hanging from the ceiling and it does not fall, it means that the gravitational force becomes balanced by the tension in the rope. Hence, it is under equilibrium.

Case-4

A hot-air balloon floating with a constant velocity while maintaining its height.

In this case, the hot air balloon is floating at the height due to the force of buoyancy. Since, the balloon is moving with a constant velocity, there is no acceleration and hence zero net force. So, it is in equilibrium.

Hence,

A motorcycle turning around a corner is not in a state of equilibrium.

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Answer:ultraviolet radiation

Explanation:answer for A P E X

The maximum height reached by the ball is 14.45 meter.

Velocity is the direction at which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.

Given parameters:

Initial velocity of the ball in upward direction= 17.0 m/s.

Final speed of the ball at maximum height = 0.

Mass of the ball = 0.30 kg.

We know that acceleration due to gravity: g = 10.0 m/s²

From principle of energy conservation:

Initial kinetic energy = final potential energy

1/2 × mv² = mgH

H = v²/2g

= 17.0²/(2×10)

= 14.45 meter.

Hence, the maximum height reached by the ball is 14.45 meter.

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Construction lines are essential for maintaining the accuracy and integrity of designs in fields like engineering, architecture, and mapping. Erasing such lines can lead to misunderstandings and inaccurate representations, potentially causing disastrous outcomes in the physical construction or interpretation of structures and mappings.

Construction lines should not be erased because they serve as foundational elements for a design, representing the initial guidelines that contribute to the final drawing or structure. For example, in topographic map interpretation, contour lines are crucial as they indicate the elevation and shape of the terrain, and erasing them would eliminate critical information required for understanding landform shapes and gradients. Similarly, when engaging in geological mapping, one must ensure that a geologic trace does not cross a topographic contour except where the structural and topographic contours intersect, preserving the accuracy of geological interpretations.

Moreover, the principles of geometry are deeply rooted in the correct understanding and depiction of lines and spaces. As in engineering and architecture, where accurate measurements and representations are foundational to the construction process, any disruption or erasing of essential lines can lead to disastrous outcomes, undermining the integrity of the structures being designed or built. Thus, construction lines must be preserved to maintain a clear and accurate representation of designs, allowing for their proper understanding, interpretation, and implementation.

Answer:6x9.8m/sx2=117.6

Explanation:

Explanation:

It is given that,

Initial position of the Apple, [tex]h_o=1.4\ m[/tex]

Initial velocity, u = 3.1 m/s

Position of friend, Y = 4.2 m

Using second equation of motion as :

[tex]Y=ut-\dfrac{1}{2}gt^2+h_o[/tex]

[tex]4.2=3.1t-\dfrac{1}{2}\times 9.8t^2+1.4[/tex]    

[tex]3.1t-4.9t^2-2.8=0[/tex]..............(1)

On solving the above quadratic equation we get t = 2.02 seconds

Since, the value of t is real. So, the apple will reach a friend in a tree house. Hence, this is the required solution.                                    

Answer:

[tex]v = 68.7 m/s[/tex]

angle made with the vertical

[tex]\theta = 21.3 degree[/tex]

Explanation:

Velocity of rain with respect to the car with vertical direction makes 38 degree angle

so let say rain velocity is

[tex]v_r = v_x\hat i + v_y \hat j[/tex]

[tex]v_{rc} = v_r - v_c[/tex]

[tex]v_{rc} = (v_x + 25)\hat i + v_y[/tex]

now we have

[tex]tan38 = \frac{v_x + 25}{v_y}[/tex]

while return to home

[tex]v_{rc} = (v_x - 25)\hat i + v_y[/tex]

now the angle with vertical is zero

so we have

[tex]v_x = 25[/tex]

now we have

[tex]tan38 = \frac{50}{v_y}[/tex]

[tex]v_y = 64 m/s[/tex]

so we have

[tex]v_r = 25 \hat i + 64 \hat j[/tex]

now magnitude of the speed is

[tex]v = \sqrt{25^2 + 64^2}[/tex]

[tex]v = 68.7 m/s[/tex]

angle made with the vertical

[tex]\theta = tan^{-1}\frac{25}{64}[/tex]

[tex]\theta = 21.3 degree[/tex]

In Freud’s conception, consciousness can be broken up into three distinct bands: the conscious level, the preconscious level, and the unconscious level.  The conscious level, where we process our perceptions and thoughts, is like the part of the iceberg that is above the water.  We are aware of our conscious level, just as we are aware of the top layer of an iceberg. The next level of consciousness, the preconscious level, is just below the surface of our consciousness and can be accessed when it is needed to recall memories and facts. This is similar to the level of the iceberg directly under the water: you can perceive it if you look carefully and are close enough. The last level of consciousness is the unconscious level, which a person has no active knowledge of.  Like the vast underwater portion of an iceberg, the unconscious level is unseen but can be very influential.  The unconscious mind has many urges, instincts, and desires, which it is constantly demanding be met. The unconscious mind can influence the behavior of an individual, sometimes in the disastrous ways an iceberg can threaten a ship.

Freud compared the mind to an iceberg to represent the conscious and unconscious aspects of our mind. The small, visible part of an iceberg represents the small portion of our mind that is conscious. The vast, hidden part represents our larger unconscious mind. Unconscious desires or urges may inadvertently reveal themselves, such as in a Freudian slip.

Sigmund Freud's conception of consciousness compared to an iceberg represents a recognition that much of our mental process occurs outside our conscious awareness. Only about one-tenth of our mind - comparable to the visible tip of the iceberg - is conscious, while the rest is hidden in the unconscious. The unconscious mind contains mental activity that we are unaware of and cannot readily access. It harbors our unacceptable urges and desires that are repressed or suppressed from our conscious thought. These contents could sometimes unintentionally reveal themselves, as in the case of a Freudian slip.

A Freudian slip is an error in speech or action that is interpreted as occurring due to the interference of an unconscious subdued wish, conflict, or train of thought. This concept is part of Freud's psychoanalytic theory and is used as evidence of the unconscious mind. For example, making unintended slips, like substituting another word for the one we meant to say, are seen as unconscious desires or urges accidentally slipping out.

Freud also proposed three components of our personality: the id, ego, and superego. The id and superego reside in the unconscious, while the ego mediates between them and our conscious understanding. The complex interaction between these components influences our behavior and personality.

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A skater moves with an initial velocity of 2 m/s, and a final velocity of 7 m/s by which he covers 12 meters, so the acceleration will be 1.875 m/s².

A vector measurement of the direction and speed of the motion is what is meant by the term "velocity" in physics. In more detail, the rate of change in an object's position relative to a frame of reference and time can also be described as the object's velocity.

Velocity, which is defined as the rate of motion of an object in a specific direction, tells us how quickly an object is traveling. The speed at which anything is traveling is determined by this.

Given information according to the question,

Initial velocity, u = 2 m/s

Final velocity, v= 7 m/s

Distance, d = 12 m

Use the equation of motion to find the acceleration of the skater,

v² - u² = 2as

7² - 2² = 24a

a = 45/24

a = 1.875 m/s².

Therefore, the acceleration of the skater is 1.875 m/s².

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We want to study the vertical motion of a stone, to do it, we will find the motion equations of the stone.

We will find that the average velocity in the given interval is 224 ft/s.

-----------------------------

First, we need to find the acceleration of the stone.

The only force acting on the stone (ignoring air resistance) will be the gravitational force, then the acceleration of the stone will be equal to the gravitational acceleration.

[tex]a(t) = -32ft/s^2[/tex]

To get the velocity equation we need to integrate over time, such that the constant of integration will be equal to the initial velocity, which we know is equal to 400ft/s

Then we get:

[tex]v(t) = (-32 ft/s^2)*t + 400ft/s[/tex]

To get the position equation we integrate again, this time the constant of integration will be the initial position, 10 ft.

[tex]p(t) = (-16ft/s^2)*t^2 + (400ft/s)*t + 10ft[/tex]

Now the average velocity is defined as the quotient between the displacement and the time it took to do that displacement, then the average velocity will be:

[tex]av = \frac{p(8s) - p(3s)}{8s - 3s} \\\\av = \frac{( (-16ft/s^2)*(8s)^2 + (400ft/s)*8s + 10ft) - ((-16ft/s^2)*(3s)^2 + (400ft/s)*3s + 10ft)}{5s} = 224 ft/s[/tex]

Thus the average velocity in that interval is 224 ft/s

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Final answer:

To find the average velocity of a stone launched from a slingshot between 3 and 8 seconds, calculate the positions at both times using the given formula and then divide the change in position by the time interval. The average velocity is found to be 224 ft/s.

Explanation:

The question involves calculating the average velocity of a stone launched from a slingshot over a given time interval. Using the formula for the position of an object moving under constant acceleration, s(t) = s0 + v0t - 1/2gt², where s0 is the initial position, v0 is the initial velocity, g is the acceleration due to gravity (32 ft/s²), and t is the time in seconds, we can find the position of the stone at 3 seconds and 8 seconds. Substituting the given values into the formula, we get:

Position at 3 seconds: s(3) = 10 + 400(3) - 1/2(32)(3²) = 10 + 1200 - 144 = 1066 ft.

Position at 8 seconds: s(8) = 10 + 400(8) - 1/2(32)(8²) = 10 + 3200 - 1024 = 2186 ft.

The average velocity over the interval [3, 8] is calculated as the change in position divided by the change in time, which is (2186 - 1066)/(8 - 3) = 1120/5 = 224 ft/s.

Final answer:

To find the final speed with given acceleration and distance, use the equation v^2 = u^2 + 2as. If the initial speed is zero, it simplifies to v^2 = 2as. Then, solve for v by taking the square root.

Explanation:

How to Find Speed with Acceleration and Distance:

To determine the final speed of an object when you are given its acceleration and the distance it has traveled, you can use one of the equations of motion that relate these variables. However, the exact method will depend on whether the initial speed is zero or a known value different from zero.

If Initial Speed is Zero:

You can use the equation v^2 = u^2 + 2as, where v is the final speed, u is the initial speed (zero in this case), a is the acceleration, and s is the distance traveled. Since u is zero, the equation simplifies to v^2 = 2as. You then solve for v by taking the square root of the product of the acceleration and twice the distance.

If Initial Speed is Known:

If you have a known initial speed, use the full equation v^2 = u^2 + 2as without simplifying it. Input the known values and solve for v as previously described.

Remember to work with S.I. units (metres per second squared for acceleration and metres for distance) for consistency and to get the speed in metres per second.

Serbian-American engineer and physicist Nikola Tesla (1856-1943) made dozens of breakthroughs in the production, transmission and application of electric power.

He invented the first alternating current (AC) motor which is used all over the world in business, factories and power plants.

He developed AC generation and transmission technology that we still have as the main form of delivering power to all consumers nowdays.

The free-fall acceleration on the moon's surface is about 1.58 m/s²

[tex]\texttt{ }[/tex]

Newton's gravitational law states that the force of attraction between two objects can be formulated as follows:

[tex]\large {\boxed {F = G \frac{m_1 ~ m_2}{R^2}} }[/tex]

F = Gravitational Force ( Newton )

G = Gravitational Constant ( 6.67 × 10⁻¹¹ Nm² / kg² )

m = Object's Mass ( kg )

R = Distance Between Objects ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

Period of Satellite = T = 110 min = 6600 s

Radius of Moon = R = 1.74 × 10⁶ m

Asked:

free-fall acceleration on the moon's surface = g = ?

Solution:

[tex]\Sigma F = ma[/tex]

[tex]G \frac{ M m} { R^2 } = m \omega^2 R[/tex]

[tex]G \frac { M } { R^2 } = \omega^2 R[/tex]

[tex]g = \omega^2 R[/tex]

[tex]g = (\frac{2 \pi }{ T} )^2 R[/tex]

[tex]g = ( \frac {2\pi} { 6600 } )^2 \times ( 1.74 \times 10^6 )[/tex]

[tex]g \approx 1.58 \texttt{ m/s}^2[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Gravitational Fields