What is g at a point in the earth's gravitational field where a 10 kg mass weighs 95 n?
The figure shows the speed of a person's body as he does a chin-up. Assume the motion is vertical and the mass of the person's body is 64.0 kg. determine the force exerted by the chin-up bar on his body at t = 0s; t = 0.5s; t = 1.1s; and t = 1.6s
The force exerted by the chin-up bar on the person's body depends on the acceleration. At certain times, the force is 0 N, while at other times it can be calculated using the formula Force = Mass x Acceleration.
Explanation:The force exerted by the chin-up bar on the person's body can be calculated using the equation:
Force = Mass x Acceleration
At t = 0s, the person's body is at rest, so the acceleration is 0. Therefore, the force exerted by the bar is 0 N.
At t = 0.5s, the person's body is moving upward with a constant speed. Since the velocity is constant, the acceleration is 0 and the force exerted by the bar is 0 N.
At t = 1.1s, the person's body is moving upward with an increasing speed. The acceleration can be calculated using the change in velocity over time, and then substituted into the force equation to find the force exerted by the bar.
At t = 1.6s, the person's body is moving upward with a decreasing speed. The acceleration can be calculated using the change in velocity over time, and then substituted into the force equation to find the force exerted by the bar.
Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time (t), find the body's position at time (t). a=16 cos4t, v(0)=2, s(0)=5 OR See attachment. ...?
Answer:
s = - 4 cos 4t + 2t + 6.
Explanation:
a = dv/dt = 16 cos 4t ,
dv = 16 cos 4t dt
integrating on both sides
v = 16 x sin 4t /4 + c
= 4 sin 4t + c
when t = 0 , v = 2
2 = 0 + c
c = 2
v = 4 sin 4t + 2
ds/dt = 4 sin 4t + 2
ds = ( 4 sin 4t + 2) dt
integrating on both sides
s = - 4 cos 4t/4 + 2t + k
= - cos 4t + 2t + k
when t = 0 s = 5
5 = -1 + 0 + k
k = 6
s = - 4 cos 4t + 2t + 6.
Ans.
A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 37° north of east just after the collision, how fast was the car initially traveling? Assume that any other unbalanced forces are negligible.
what is the correct answer
34 m/s
17 m/s
26 m/s
68 m/s
...?
The car was initially traveling at approximately 22.02 m/s.
Explanation:To solve this problem, we can break it down into horizontal and vertical components. Let's call the initial velocity of the car 'v.'
The car's horizontal velocity after the collision is given by its initial velocity multiplied by the cosine of the angle, which is 28 m/s * cos(37°). The truck's horizontal velocity after the collision is 0 m/s since it was initially stationary.
Since no horizontal forces act on the system after the collision, the momentum in the horizontal direction is conserved. Thus, the sum of the initial flat rates of the car and the truck must equal the final horizontal velocity. Therefore, m * v = m * (28 m/s * cos(37°)), where 'm' represents the mass of the car and the truck.
If we divide both sides of the equation by 'm', we get v = 28 m/s * cos(37°). Evaluating this expression, we find v ≈ 22.02 m/s.
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how to select a direction for the EMF included In a moving conductor?
Fleming's right-hand rule (for generators) shows the direction of induced current when a conductor moves in a magnetic field. It can be used to determine the direction of current in a generator's windings.
When a conductor such as a wire attached to a circuit moves through a magnetic field, an electric current is induced in the wire due to Faraday's law of induction. The current in the wire can have two possible directions. Fleming's right-hand rule gives which direction the current flows
The right hand is held with the thumb, first finger and second finger mutually perpendicular to each other (at right angles.
The thumb is pointed in the direction of motion of the conductor. You have done 3,404 J of work with a force of 37 N on a 46-kg object. Over what distance did you do the work?
A. 92 m
B. 150 m
C. 3131 m
D. 1702 m
^_^ ...?
what is the reasonable estimate of the average kinetic energy of an athlete during a 100m race that takes 10s ?
The Kinetic energy of the athlete will be 50 times of the mass of the athlete.
We have a athlete who completed a 100m race in 10 seconds.
We to estimate the average kinetic energy of the athlete.
What is the formula to calculate the Kinetic energy of any moving body?The formula to calculate the kinetic energy of any moving body is -
K.E. = [tex]\frac{1}{2} mv^{2}[/tex]
According to question -
Distance covered by athlete = 100 meters
Time taken by the athlete = 10 seconds
Let's assume the mass of the athlete = M Kg
Consider the formula for the Kinetic energy of the body -
K.E. = [tex]\frac{1}{2} mv^{2}[/tex]
We know that -
v = [tex]\frac{distance}{time} = \frac{x}{t}[/tex]
Substituting the value of velocity in equation of kinetic energy -
K.E = [tex]\frac{1}{2} m(\frac{x}{t}) ^{2}[/tex]
We can see that the kinetic energy of the athlete is -
K.E. [tex]\alpha\; (\frac{x}{t})^{2}[/tex]
Greater the square of the ratio of x and t, greater will be the kinetic energy.
K.E. = 0.5 x M x 10 x 10
K.E. = 50M
Hence, the Kinetic energy of the athlete will be 50 times of the mass of the athlete.
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Two charged particles Q1 and Q2 are a distance r apart with Q2=5Q1.Compare the forces they exert on one another when F1 is the force Q2 exerts on Q1 and F2 is the force Q1 exerts on Q2
a)F2=-5F1
b)F2=5F1
c)F2=F1
d)F2=-F1
The forces that two charged particles exert on each other are equal in magnitude and opposite in direction, so F2 = -F1, where F2 is the force Q1 exerts on Q2, and F1 is the force Q2 exerts on Q1.
Explanation:When two charged particles Q1 and Q2, with Q2 being 5 times the charge of Q1, are separated by a distance r, the force they exert on each other can be determined using Coulomb's law. According to Coulomb's law, the magnitude of the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Since Q2 is 5 times Q1, we have Q2 = 5Q1. However, the force that Q2 exerts on Q1 (F1) is equal in magnitude and opposite in direction to the force that Q1 exerts on Q2 (F2) due to Newton's third law of motion, which states that every action has an equal and opposite reaction.
Therefore, the correct answer to the question is F2 = -F1. This indicates that the forces are equal in magnitude but opposite in direction. The negative sign simply denotes the opposite direction of the force, not that the magnitude of the force is negative.
According to Coulomb's law and Newton's third law, two charged particles exert forces of equal magnitude but opposite directions on each other, so if Q2 = 5Q1, then F2 = -F1.
Explanation:When considering two charged particles exerting forces on each other, it's important to apply Coulomb's law, which states that the force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Additionally, Newton's third law of motion tells us that for every action, there is an equal and opposite reaction. This means that if a charge Q2 exerts a force F1 on Q1, then Q1 must exert a force F2 of equal magnitude but in the opposite direction on Q2.
Given that Q2 = 5Q1 and they are a distance r apart, Coulomb's law would indicate that the magnitudes of the forces each charge exerts on the other (F1 and F2) would be equal. Thus, the correct answer is F2 = -F1, where the negative sign indicates the forces have opposite directions.
According to newton's first law of motion, which force is expected to cause a body to accelerate
Answer: The answer to this question is Unbalanced force.
Explanation: There are two types of forces:
1. Balanced force: When two forces equal in their magnitude act opposite to each other are known as balanced force. The net force is equal to 0.
2. Unbalanced force: When two forces acting opposite to each other are not equal in magnitude results in the unbalanced force. The net force of this is not equal to 0. Direction of force is in the direction of net force.
Now, according to Newton's first law of motion, which says that force is the product of the object's mass and acceleration. The force should have some value and hence it cannot be equal to zero. therefore the force must be Unbalanced force.
According to Newton's second law of motion, a net external force causes a body to accelerate, with the acceleration being directly proportional to the force and inversely proportional to its mass.
According to Newton's second law of motion, a force is expected to cause a body to accelerate when it acts upon the body. This law can be summarized by the equation Fnet = ma, where Fnet denotes the net force acting on the body, m stands for mass, and a signifies acceleration. Therefore, the linear acceleration of a rigid body is directly proportional to the net force acting on it and inversely proportional to its mass. It is important to note that the acceleration occurs in the same direction as the net external force. In simple terms, if you apply a net external force to an object, it will accelerate, and the magnitude of this acceleration can be calculated by dividing the net force by the object’s mass.
A 0.150 kg ball on the end of a 1.10 m long cord (negligible mass)is swung in a vertical circle..
(a) what is the minimum speed the ball must have at the top of its arc so that the ball continues moving in a circle?
calculate the tension in the cord at the bottom of the arc assuming the ball is moving at twice the speed of part (a) ...?
Answer:
[tex]v = 3.28 m/s[/tex]
Explanation:
At the top position of the arc if ball continue in its circular path then we can say that tension force must be zero at that position for the minimum value of the speed.
So we will have
[tex]T + mg = \frac{mv^2}{R}[/tex]
so if minimum speed is required to complete the circle T = 0
[tex]0 + mg = \frac{mv^2}{R}[/tex]
so we will have
[tex]v = \sqrt{Rg}[/tex]
again we will have
[tex]v = \sqrt{1.10\times 9.81}[/tex]
[tex]v = 3.28 m/s[/tex]
A student librarian lifts a 2.2 kg book from the floor to a height of 1.25 m. He carries the book 8.0 m to the stacks and places the book on a shelf that is.35 m above the floor. How much work does he do on the book?
I understand most of it, but I am unsure of what distance to use. Please help? ...?
Answer:
[tex]W_{tot}=W_{1}+W_{2}=mgh_{2}=7.55[J][/tex]
Explanation:
The work done on an object is the scalar product between force and displacement. So we can write the work:
[tex]W=F\cdot d=Fd[/tex]
In our case F and d are parallels then we have a common product of their magnitudes.
Now, the total work will be the sum these two works:
Work done when the student librarian lifts a 2.2 kg book from the floor to a height of h₁=1.25 m.Work done when he places the book on a shelf that is h₂=0.35 m above the floor.Let's recall that the force in this problem is just the weight of the book. F=m*g
The first work will be: [tex]W_{1}=mgh_{1}[/tex]. F and h1 are parallelsThe second work will be:[tex]W_{2}=-mg(h_{1}-h_{2})[/tex] is negative because the vector force and the vector displacement are anti parallels.Finally, the total work will be the sum of W₁ and W₂.
[tex]W_{tot}=W_{1}+W_{2}=mgh_{2}=2.2*9.81*0.35=7.55[J][/tex]
I hope it helps you!
To calculate the work done on the book, the student librarian must use the formula W = mgh for each segment of lifting the book vertically. The total work done is the sum of the work for lifting the book to 1.25 m and then to 0.35 m. The horizontal distance carried does not contribute to work against gravity.
Explanation:The work done on the book by the student librarian can be calculated by considering the work done against gravity to lift the book to different heights. The distance carried horizontally does not involve work against gravity under the assumption that there is no horizontal force like friction opposing the motion. The work done to lift the book from the floor to 1.25 m can be calculated using the formula W = mgh, where m is the mass of the book, g is the acceleration due to gravity (approximately 9.8 m/s2), and h is the height.
The initial lift is W = 2.2 kg × 9.8 m/s2 × 1.25 m. When placing the book from the carried position to a shelf at 0.35 m height, the work done is W = 2.2 kg × 9.8 m/s2 × 0.35 m since the vertical displacement is from 1.25 m to 0.35 m, not the full 1.25 m again.
The total work done on the book is the sum of these two amounts of work. Please note that the gravitational constant (g) could be given or assumed in this context. The exact value used may vary slightly depending on the context of the problem.
Is it professional a cyber crime
Which of the following is a balanced equation?
N2 + 3H2 ⇒ 2NH3
3N2 + 3H2 ⇒ 2NH3
N2 + H2 ⇒ 2NH3
The correct balanced equation is N₂ + 3H₂ ⇒ 2NH3, which represents the chemical reaction where one mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia. The coefficients reflect the simplest whole number ratio for the stoichiometry of the reaction.
Explanation:The balanced chemical equation among the given options is N₂ (g) + 3H₂ (g) ⇒ 2NH3 (g). This reflects the stoichiometry of the reaction where each nitrogen molecule (N₂) reacts with three hydrogen molecules (3H₂) to form two molecules of ammonia (2NH3). The coefficients indicate the mole ratio needed for the reaction to occur, which is also demonstrated through models showing the combination of gas volumes following the reaction stoichiometry. Alternatively, the equation 3N2 + 9H2 → 6NH3 is not balanced at the simplest ratio. After dividing each coefficient by the greatest common factor (3), the previous balanced equation is obtained, which is the preferred simplified form. This balanced equation can be used to establish an equilibrium in a sealed container, showcasing the relationship between changes in the concentrations of the species involved, as determined by the stoichiometry.
Final answer:
The balanced chemical equation for the synthesis of ammonia from nitrogen and hydrogen is N₂ (g) + 3H₂ (g) → 2NH3 (g), which follows the stoichiometric ratio of 1:3:2.
Explanation:
The balanced equation for the reaction between nitrogen (N₂) and hydrogen (H₂) to form ammonia (NH₃) is N₂ (g) + 3H₂ (g) → 2NH3 (g). This equation satisfies the law of conservation of mass, meaning that the number of atoms for each element is the same on both the reactant and product sides of the equation. One mole of nitrogen gas reacts with three moles of hydrogen gas to yield two moles of ammonia gas, indicating a mole ratio of 1:3:2, respectively. The equation shows ammonia molecules are produced from nitrogen and hydrogen molecules in a 2:3 ratio, reflecting the stoichiometry of the reaction.
The waves with the longest wavelengths in the electromagnetic spectrum are
a. infrared rays.
b. x-rays.
c. gamma rays.
d. radio waves.
Which of the following processes is most affected by pressure?
A. freezing
B. boiling
C. melting Which of the following processes is most affected by pressure?
A. freezing
B. boiling
C. melting
Answer:
The answer is: B. boiling.
Explanation:
The value of the melting and boiling points are affected by the value of the atmospheric pressure.
The Celsius degree is the unit corresponding to the melting and boiling temperatures of water at 1 atm pressure. Celsius: Melting 0 ℃, Boil 100 ℃.
When a food is frozen at normal atmospheric pressure, its temperature drops to 0 ° C, at which time the water begins to turn into ice.
Normally, the atmospheric pressure that exists at sea level is taken as a reference. There it takes a value of 1 atmosphere.
Therefore, although the pressure is 1 atmosphere for all processes, the one that needs more temperature is the Boiling, which is 100 ° C.
The answer is: B. boiling.
An unbalanced 16-n force is applied to a 2 kg mass what is the acceleration of the mass
Newton's third law with magnetic forces?
Now while I was studying more about this matter, as I asked before when two bar magnets attract do they both their forces on each other? The answer was "YES." Now, let me go indepth with this more and more, when two bar magnets of un-equal forces attract! Do they equally apply the same force or no?
Imagine Magnet A capable of applying 50N of force while magnet B is applying 10N of force, they both attract! I think the two forces add up! What do you all think?
A mover uses a ramp to push a stereo into the moving van. The ramp is 3 meters long and 1.5 meters high. What is the ima of this ramp?
The Ideal Mechanical Advantage (IMA) of the ramp used to move the stereo is 2. This is calculated by dividing the length of the ramp (3 meters) by its height (1.5 meters).
Explanation:The question is asking for the Ideal Mechanical Advantage (IMA) of the ramp, also known as an inclined plane, used in moving the stereo. The IMA for an inclined plane, or ramp, can be calculated using the formula IMA = length of slope / height of slope. In this scenario, the length of the ramp is 3 meters and the height is 1.5 meters. Plugging these values into the formula, the IMA is calculated as 3 / 1.5 = 2. This means that the ramp multiplies the force applied to the stereo by two, making the task of loading the stereo easier.
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Why is it important for scientist to repeat an experiment several times?
When our bodies get warmed up, _____________ increases to the muscles that need it.
A mechanical device requires 420 J of work to do 230 J of work to lift a crate. What is the efficiency of the device? In percentage please.
The efficiency of the machine is 54.76%.
The efficiency of a machine refers to the amount of useful work that is done by the machine. Efficiency is usually expressed as a percentage.
From the question;
Work output= 230 J
Work input= 420 J
We know that efficiency = Work output/work input × 100/1
efficiency =230 J/420 J × 100/1
efficiency = 54.76%
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If you drop a tennis ball from the top of a ladder, at what rate will it accelerate
Please help.: Sliding from left to right in a straight line on a horizontal steel surface, an aluminum block weighing 20 newtons is acted on by a 2.4 newton friction force. The block will be brought to rest by the friction force in a distance of 10 meters. Determine the magnitude of the acceleration of the block as it is brought to rest by the friction force. (Show all work)
Answer:
-1.176 m/s²
Explanation:
Given:
weight of aluminium block is w = 20.0 N
frictional force, f = 2.4 N
final velocity, v = 0
distance covered, d = 10 m
From Newton's second equation of motion,
F = ma
where, m is the mass and a is the acceleration.
mass of the block, m g = 20.0 N
m = 2.04 kg
The block is brought to rest by friction force:
f =- m a
⇒ 2.4 N = -(2.04 kg)(a)
⇒a = -1.176 m/s²
A wave has a wavelength of 45 meters and a period of 9.0 seconds. What is the frequency of the wave?
Answer: The correct answer is 0.11 Hz.
Explanation:
The relation between frequency of the wave and time period is as follows;
[tex]f=\frac{1}{T}[/tex]
Here, f is the frequency of the wave and T is the time period.
Here, the frequency is inversely proportional to the time period.
It is given in the problem that a wave has a wavelength of 45 meters and a period of 9.0 seconds.
Calculate the frequency of the wave.
[tex]f=\frac{1}{T}[/tex]
Put T= 9 s.
[tex]f=\frac{1}{9}[/tex]
f=0.11 Hz
Therefore, the frequency of the wave is 0.11 Hz.
Stan does 178 J of work lifting himself 0.5 m. What is Stan’s mass? The acceleration of gravity is 9.8 m/s 2 . Answer in units of kg
Answer:
The mass is 36.33 kilograms.Explanation:
The work is defined as the force needed to move an object a certain distance, if there's no change of position, there's no work.
In this case, the work is defined:
[tex]W=Fd[/tex]
Where [tex]F[/tex] is the weight defined with the following equation
[tex]F=W=mg[/tex]
Now, we'll replace all given values and solve for [tex]m[/tex]:
[tex]W=mgy\\178=m(9.8)(0.5)\\m=\frac{178}{4.9}=36.33 kg[/tex]
Therefore, the mass is 36.33 kilograms.
Which of these most likely causes an annular solar eclipse?
A.moon moving closer to Earth than sun and forming a triangle
B.Earth moving closer to sun than moon and forming a triangle
C.the moon at apogee coming between Earth and the sun along a straight line
D.the moon at perigee coming between Earth and the sun along a straight line
Answer:
C.the moon at apogee coming between Earth and the sun along a straight line
Explanation:
As we know that Earth rotate about the sun in elliptical orbit as one of the planet.
While moon rotate about the Earth similarly as one of the satellite around it
now when moon, Sun and Earth all lie in the same line such that position of moon is between the positions of Sun and Earth then in this case the light coming from sun is totally bounded by the position of moon
This situation of moon is known as Solar Eclipse
so here during the motion if the moon at apogee coming between Earth and the sun along a straight line then it is the most likely cause of annular solar eclipse.
a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done? a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?
Final answer:
The work done by a person who exerted a force of 500 Newtons to move a full wheelbarrow over a distance of 30 meters is 15000 Joules.
Explanation:
If a person exerted a force of 500 Newtons (F = 500 N) to move a full wheelbarrow over a distance of 30 meters (d = 30 m), the work done can be calculated using the formula:
Work (W) = Force (F) × Distance (d)
Plugging in the given values, we get:
W = (500 N) × (30 m) = 15000 Joules (J)
The work done is therefore 15000 Joules, which demonstrates the transfer of energy through force applied over a distance.
Which of the following frictionless ramps (A, B, or C) will give the ball the greatest speed at the bottom of the ramp? Explain.
The frictionless ramp A will give the ball the greatest speed at the bottom of the ramp.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its si unit is m/sec.
The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule. Ball has the most potential energy due to her position at C.
The potential energy is mainly dependent upon the height of the object.
Potential energy = mgh
The potential energy gets converted into kinetic energy at the bottom. If the ramp is frictionless the potential energy completely gets converted into kinetic energy.
The kinetic energy results in the motion of the body.
Hence frictionless ramp A will give the ball the greatest speed at the bottom of the ramp.
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If you were asked to design the most efficient nuclear fission reactor possible, what ratio of U-235 to U-238 would you use? Explain why?
The most efficient nuclear fission reactor would require a higher ratio of U-235 to U-238 due to the higher fissionability of U-235.
Explanation:The most efficient nuclear fission reactor would require a higher ratio of U-235 to U-238.
U-235 is the fissile isotope of uranium and readily undergoes fission, producing a large amount of energy. U-238, on the other hand, is a fertile isotope that can be converted into plutonium-239, which is also highly fissionable. By increasing the ratio of U-235 to U-238, more U-235 will be available for fission reactions, leading to a higher energy output and efficiency.
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earth and the moon are kept in their respective orbits due to the influence of ?
a) inertia b) gravity c) both inertia and gravity d) neither inertia and gravity
Answer:
it is cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
Explanation:
becai=use i know