What salt is formed by the reaction of potassium hydroxide and hydrochloric acid?

Use the D = M/V equation, in which Density can be found by dividing Mass/Volume.

To solve, first find a rectangular prism tub that is filled to a certain level. Next, place the rock inside to find the amount of displacement (or how high the water level goes up.) In this way, you can find the volume of the rock.

Next, solve for the Mass. This can be found by dividing the total weight from the gravitational pull. This would give you the mass.

Finally, to find Density, divide the Mass found with the Volume. This would give you your final answer

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Wind, air that moves to the ground

Since it is round, and in the asteroid belt, he has most likely found a Dwarf planet. This is because it is round, so it might be round because of it's gravity.

Answer:

A. a new dwarf planet

Explanation:

The correct answer is option A, that is, transport fluid.  

The lymphatic system refers to a network of organs and tissues, which helps in getting rid of the body wastes, toxins, and other undesired elements. However, the main activity of the lymphatic system is to transport lymph, that is, a fluid comprising infection-fighting white blood cells, all through the body.  

The lymphatic system mainly comprises of lymphatic vessels that are identical to the circulatory system's capillaries and veins. The vessels are associated with lymph nodes, where the filtration of lymph is done. The adenoids, tonsils, thymus, and spleen are all the components of the lymphatic system.  

Beryllium.

All four elements are found in the second column to the left of a periodic table. They are group 2 elements.

The 1st ionization energy generally decrease down each group.

Elements in each group have the same number of electrons in the outermost occupied electron shell. Electrons in the inner shell shield those in the outer shell from attractions from the nucleus, known as the shielding effect. The number of protons in each atom increase by more than 8 in each period. However, due to this effect, electrons in the outermost shell experience a far weaker force pulling them towards the center of the atom. For atoms of the four group 2 elements, electrons in the outermost layer would behave as if there's only two protons inside their nucleus. As a result, their end up with rather similar ionization energies.

Despite the same effective charge on each electron, the mean radius of the electrons increase down the group. Beryllium is in the second period; its electrons occupy only two electron shells in the ground state. On the contrary, strontium is in the fifth period; its electrons occupy up to five electrons shells in its ground state. The strength of electrostatic attraction decreases as the two charges move apart. As a result, outermost electrons in beryllium are way more attached to the nucleus than those in strontium.

FYI, the 1st ionization energy of the four elements are shown below:

The element with the highest first ionization energy among the choices is; Beryllium, Be

The ionization energy of an element is the energy required to remove one of the electrons in its outermost shell.

The first ionization energy of elements is inversely proportional to the atomic radii of elements.

This is so because a lesser atomic radius corresponds to greater electrostatic attraction between the electron and the nucleus of the atom.

We must also state that the atomic radius of elements in the periodic table increases down a group and decreases across a period.

In essence, the smaller the atom of an element, the larger is its first ionization energy.

The element with the highest first ionization energy is the smallest element and is therefore Beryllium, Be.

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it would come from your mom and dad

Answer:

A) X-rays

Step-by-step explanation:

Ultraviolet rays have a frequency range of 10¹⁵ Hz to 10¹⁷ Hz.

X-rays have a frequency range of 10¹⁷ Hz to 10²⁰ Hz, so they have a higher frequency than UV waves.

B) is wrong. The frequency range of infrared light is 10¹³ Hz to 4 × 10¹⁴ Hz.

C) is wrong. The frequency range of microwaves is 3 ×10¹¹ Hz to 10¹³ Hz.

D) is wrong. The frequency range of microwaves is 4 ×10¹⁴ Hz to 7.5 × 10¹⁴ Hz.

The X-rays has a frequency greater than ultraviolet waves.  

• The range of all the kinds of electromagnetic radiation is known as the electromagnetic spectrum.  

• The types of the electromagnetic waves, which makes up the electromagnetic spectrum are the visible light, microwaves, infrared light, UV rays, X-rays, and gamma rays.  

• The energy of the waves is directly proportional to its frequency and inversely proportional to their wavelengths.  

• The radiowaves exhibits the photons with least energies, followed by microwaves, infrared rays, visible, UV rays, X-rays, and the most energetic of all the waves is the gamma rays.  

• The wavelengths of the UV rays is smaller than infrared waves, microwaves, and visible light, however, it is greater than X-rays and gamma rays.  

• Thus, the frequencies of UV rays is more than the infrared waves, microwaves, and visible light, but is lesser than the frequencies of X-rays and gamma rays.  

Thus, of the mentioned options, X-rays will possess greater frequency than UV rays.  

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B. atoms must be electro negative.

Answer:

The answer is A.

Explanation:

This is a specific type of polar interaction that is established between two atoms with high electronegativity, usually between O or N, and an atom of H. In the case of oxygen, with a total of 8 electrons, two pairs of solitary electrons are presented and can act as acceptors of two hydrogen bridges. Nitrogen has one less electron and therefore has only one pair of solitary electrons to form a hydrogen bridge. These orbitals have a high negative charge density, and can, therefore, bind to the positive charge of hydrogen.

The interatomic distance between the hydrogen and the acceptor is less than the sum of its Van der Waals radius. The atomic radius of N and O are relatively small.

Have a nice day!

Answer:1) Volume of [tex]AgNO_3[/tex] required is 55.98 mL.

2) 0.62577 grams of [tex]Ag_3PO_4[/tex] is produced.

Explanation:

[tex]3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)[/tex]

1) Molarity of [tex]AgNO_3,M_1=0.225 M[/tex]

Volume of [tex]AgNO_3.V_1=?[/tex]

Molarity of [tex]Na_3PO_4,M_2=0.135 M[/tex]

Volume of [tex]Na_3PO_4,V_2=31.1 mL=0.0311 L[/tex]

[tex]Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}[/tex]

[tex]\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles[/tex]

According to reaction, 1 mole of [tex]Na_3PO_4[/tex] reacts with 3 mole of [tex]AgNO_3[/tex], then, 0.0041985 moles of [tex]Na_3PO_4[/tex] will react with:

[tex]\frac{3}{1}\times 0.0041985[/tex] moles of [tex]AgNO_3[/tex] that is 0.0125955 moles.

[tex]M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}[/tex]

[tex]V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL[/tex]

Volume of [tex]AgNO_3[/tex] required is 55.98 mL.

2)

[tex]Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}[/tex]

Number of moles of [tex]AgNO_3=0.195\times 0.023 L=0.004485 moles[/tex]

According to reaction, 3 moles of [tex]AgNO_3[/tex] gives 1 mole of [tex]Ag_3PO_4[/tex], then 0.004485 moles of [tex]AgNO_3[/tex] will give:[tex]\frac{1}{3}\times 0.004485[/tex] moles of [tex]Ag_3PO_4[/tex] that is 0.001495 moles.

Mass of [tex]Ag_3PO_4[/tex] =

Moles of [tex]Ag_3PO_4[/tex] × Molar Mass of [tex]Ag_3PO_4[/tex]

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of [tex]Ag_3PO_4[/tex] is produced.

Answer:

Honey

Explanation:

Backing soda:

Backing soda is a compound that is made up of only one kind of salt called NaHCO3 or sodium  hydrogen carbonate. All the molecules  of NaHCO3  are identical and we know that a mixture is something made up of two or more than two kinds of things, therefore baking soda cannot be referred to as mixture.

Carbon:

Carbon is not a mixture because its just an element that composed diffreent compounds by reacting with different other elements. In its oure form carbon is not a mixture, but if it is combined with some other substance it can form mixture.

Orange juice:

It depends on what kind of orange juice we are talking about. If we are talking about pure orange juice that is made from fresh oranges,then no - it cannot be called as mixture. However, if sugars,flavors and other preservatives are added like those available in market then it can be a mixture.

Honey:

Honey is a mixture of at-least 181 types of components in which most of all are sugars. These components mix through complex process and give the honey its specific sugary taste. You can see some of the constituent components of honey in attached figure.

Hope it help!

The correct option is:

how elements arrange within a compound  

Structural formula are like models because they show how elements arrange within a compound.  

    The grams of  Fe₂O₃   that are formed is  47.68 g

calculation

Step 1: write   the equation for reaction

4 Fe +3O₂ → 2 Fe₂O₃

Step 2: find  the  moles  of Fe

moles = mass÷  molar mass

 = 33.4 g÷55.8 g/mol =0.5986 moles

Step 3 : use the mole ratio to determine the moles of Fe₂O₃

That is  from  equation above Fe:Fe₂O₃  is 4:2 therefore the moles of Fe₂O₃ is  =  0.5986 moles x 2/4 =0.2993 moles

Step 4 : find the mass  of Fe₂O₃

mass = mass x molar mass

The molar mass of Fe₂O₃  = (55.8 x 2 +(15.9 x3) = 159.3 g/mol

mass is therefore =  0.2993 moles x 159.3 g/mol =47.68 g

Answer:

47.8 g

Explanation:

The number of Ml  of C₅H₈  that can  be  made  from 366  ml  C₅H₁₂  is 314.7 ml  of C₅H₈

  calculation

 step  1: write  the  equation for  formation of C₅H₈

C₅H₁₂  →  C₅H₈  + 2 H₂

Step 2: find the mass of C₅H₁₂

mass = density × volume

= 0.620 g/ml × 366 ml =226.92 g

Step 3: find moles  Of  C₅H₁₂

moles  = mass÷  molar mass

from periodic table the  molar mass of  C₅H₁₂ = (12 x5) +(  1 x12) = 72 g/mol

moles = 226.92 g÷ 72 g/mol =3.152 moles

Step 4: use the  mole ratio  to determine the  moles of C₅H₈

C₅H₁₂:C₅H₈  is 1:1  from equation above

Therefore the  moles of C₅H₈  is also = 3.152  moles

Step 5: find the mass  of C₅H₈

mass = moles x molar mass

from periodic table the  molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol

= 3.152  moles x 68 g/mol = 214.34 g

Step 6: find Ml of  C₅H₈

=mass / density

= 214.34 g/0.681 g/ml = 314.7 ml

You can produce approximately 2.144 mL of C₅H₈ from 366 mL of C₅H₁₂.

This is calculated through conversion of mass using densities of the two substances.

To find out how many milliliters of C₅H₈ can be made from 366 mL of C₅H₁₂, you need to follow these steps:

Therefore, you can produce approximately 2.144 mL of C₅H₈ from 366 mL of C₅H₁₂.

Correct question is: How many milliliters of C₅H₈ can be made from 366 mL C₅H₁₂ ?
density of C₅H₁₂ = 0.620 g/mL
density of C₅H₈ = 0.681 g/mL
density of H₂ = 0.0899g/L

A pair of oxygen atoms can form an O2 molecule in which each atom has a total of eight valence electrons by sharing two pairs of electrons. The term covalent bond is used to describe the bonds in compounds that result from the sharing of one or more pairs of electrons.

Based on the question and the given data, philosophy and religion.

The azimuthal quantum number (l) determines its orbital angular momentum and describes the shape of the orbital.

s-orbitals (for example 1s, 2s) are spherically symmetric around the nucleus of the atom.

p-orbitals are dumb-bell shaped. l = 0,1...n-1, when l = 1, that is p subshell.

d-orbitals are butterfly shaped.

The  number of molecules of isopently acetate is  4.63  x 10¹⁵  molecules

 calculation

Step 1:  find the moles of isopently acetate( C₇H₁₄O₂)

moles  =  mass÷  molar mass

From periodic table the molar mass of C₇H₁₄O₂

= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol

moles = 1 x10⁻⁶ g÷ 130 g/mol =  7  x 10⁻⁹ moles

step 2 ; use the Avogadro's  law  constant to calculate the number of molecules

That  is according to Avogadro's law  1 mole  = 6.02 x 10²³  molecules

                                                          7 x 10⁻⁹ moles = ?  molecules

by cross multiplication

= { (7 x 10⁻⁹ moles x  6.02 x10²³  molecules) / 1  mole} = 4.63 x 10¹⁵  molecules

To determine the number of molecules of isoamyl acetate in a 1x10⁻⁶g bee sting, calculate the molar mass, convert mass to moles, and multiply by Avogadro's number to find approximately 4.625x10¹⁵ molecules.

To determine how many molecules of isoamyl acetate (isopentyl acetate) C₇H₁₄O₂ are released in 1x10⁻⁶g during a typical bee sting, we first need to calculate the molar mass of C₇H₁₄O₂. The molar mass is given by the sum of the atomic masses of all the atoms in one molecule of the substance. This is calculated as:

7 carbons (C) times 12.01 g/mol = 84.07 g/mol

14 hydrogens (H) times 1.008 g/mol = 14.112 g/mol

2 oxygens (O) times 16.00 g/mol = 32.00 g/mol

Adding these together gives a molar mass of 130.182 g/mol for isoamyl acetate.

Next, we use the following formula to convert the mass of the substance to moles:
moles = mass (g) / molar mass (g/mol)
= 1x10⁻⁶g / 130.182 g/mol
moles = 7.68x10⁻⁹ moles of C₇H₁₄O₂.
Finally, to find the number of molecules, we multiply the moles of the substance by Avogadro's number (6.022x10²³ molecules/mol):
number of molecules = 7.68x10⁻⁹ moles x 6.022x10²³ molecules/mol
number of molecules = 4.625x10¹⁵ molecules of C₇H₁₄O₂.
The number of molecules of isoamyl acetate released in 1x10⁻⁶g during a typical bee sting is approximately 4.625x10¹⁵.

 The statement  which  is true  about  the reactivity  of  element  with          1S²2S²2P⁶3S¹   is

 it is reactive   because it has to lose one  electron  to have  a full  outermost  energy  level.

Explanation

Answer:

C. It is reactive because it has to lose one electron to have a full outermost energy level.  

Answer: 3 times lesser

     a and b are inversely proportional,

                                                a ∝ (1/b)

                                                or a  =  k/b                 where k =constant ,

                                             if a is 3 times increased  what happens to b ?

                                                  b is 3 times less.

Answer:

10.3 °C

Step-by-step explanation:

This is an isolated system so

heat gained by ice + heat lost by water = 0

Heat to warm ice + heat to melt ice + heat to warm melt + heat lost by water = 0

     q₁     +     q₂        +      q₃      +     q₄      = 0

n₁C₁ΔT₁ + n₁ΔH_fus + n₁C₃ΔT₃ + n₄C₃ΔT₄  = 0

Step 1: Calculate q₁

n₁ = 40.0 g × 1/18.02

n₁ = 2.220 mol

C₁ = 37.7 J·K⁻¹mol⁻¹

ΔT₁ = T_f – T_i  

ΔT₁ = 0.0 – (-15)

ΔT₁ = 15 °C = 15 K

q₁ = 2.220 × 37.7 × 15  

q₁ = 1255 J

q₁ = 1.255 kJ

===============

Step 2. Calculate q₂

ΔH_fus = 6.01 kJ·mol⁻¹

q₂ = 2.220 × 6.01

q₂ = 13.34 kJ

===============

Step 3: Calculate q₃

C₃ = 75.3 J·K⁻¹mol⁻¹

ΔT₃ = T_f – T_i  = x – 0 °C  

ΔT₃ = x °C = x K

q₃ = 2.220 × 75.3 × x

q₃ = 167x J

q₃ = 0.167x kJ

===============

Step 4. Calculate q₄

n₄ = 265 × 1/18.02

n₄ = 14.71 mol

ΔT₄ = T_f – T_i  = x – 25.0 °C  

q₄ = 14.71 × 75.3 × (x – 25.0)

q₄ = 1107 × (x – 25.0)

q₄ = 1107x  – 27 680 J

q₄ = 1.107x – 27.68 kJ

===============

Step 5. Solve for x

1.255 + 13.34 + 0.167x + 1.107x - 27.68 = 0

1.274x - 13.08 = 0

1.274x = 13.08

x = 13.08/1.274

x = 10.3 °C

The final temperature is -10.3 °C.

Answer:- The mole ratio of D to A is 3:2.

Explanations:- Mole ratio for a chemical equation is the ratio of the coefficients of the molecules. Coefficients are the numbers used to balance the chemical equations.

For the given generic chemical equation, the coefficient of molecule A is 2 and the coefficient of D is 3. It means 2 molecules of A react with 3 molecules of D. So, the mole ratio of A to D is 2:3.

Since, we are asked about the mole ratio of D to A so we will write the coefficient of D first and hence the mole ratio of D to A is 3:2.

The product of the chemical reaction 2 H₂ + O₂ → 2 H₂O is water (H₂O), which is a result of two moles of hydrogen reacting with one mole of oxygen.

The product of the chemical reaction 2 H₂ + O₂ → 2 H₂O is water (H₂O). This represents a composition reaction where two molecules of hydrogen gas (H₂) react with one molecule of oxygen gas (O₂) to produce two molecules of water (H₂O). A key point to remember is that balanced chemical equations reflect not only the molecular count but also the molar amounts of the substances involved. Hence, we can say that two moles of hydrogen react with one mole of oxygen to yield two moles of water.

Answer:- [tex]1s^22s^22p^63s^23p^6[/tex]

Explanations:- Atomic number of chlrone(Cl) is 17 it means it has 17 electrons. It's electron configuration is: [tex]1s^22s^22p^63s^23p^5[/tex] .

Chloride ion is formed when Cl accepts one electron:

[tex]Cl+e^-\rightarrow Cl^-[/tex]

So, electrons for the chloride ion = 17+1 = 18

If we look at the electron configuration of Cl then 3p is still vacant as there are 5 electrons in it and it could have maximum 6 electrons. So, this 18th electron goes to 3p and the electron configuration of chloride ion becomes:

[tex]1s^22s^22p^63s^23p^6[/tex] .

Average atomic mass of an element is a sum of the product of the isotope mass and its relative abundance.

For example: Chlorine has 2 isotopes with the following abundances

Cl(35): Atomic mass = 34.9688 amu; Abundance = 75.78%

Cl(37): Atomic mass = 36.9659 amu; Abundance = 24.22 %

Average atomic mass of Cl = 34.9688(0.7578) + 36.9659(0.2422) =

                                             = 26.4993 + 8.9531 = 35.4524 amu

Thus, the term “ average atomic mass “ is a weighted average so it is calculated differently from a normal average

Electrons is your answer

Answer: C.

electrons

Explanation: edmentum

Valcano i your answer i believe

 The  average mass  of nitrogen   is  14

         calculation

 step 1 :  multiply each percentage  by mass  number

 14 x 99.6  =1394

15 x 0.4 =   6

Step 2: add them up

 1394 + 6  = 1400

step 3: Then  divide by 100

= 1400/100 = 14

Answer:The average atomic mass of nitrogen is 14.004

Explanation:

Abundance of nitrogen-14 = 99.6 %

Fractional abundance[tex]=\frac{99.6}{100}=0.996[/tex]

Abundance of nitrogen-15 = 0.4 %

Fractional abundance[tex]=\frac{0.4}{100}=0.004[/tex]

Average atomic mass of an element =

[tex]\sum(\text{atomic mass of an isotopes}\times (\text{fractional abundance}))[/tex]

Average atomic mass of nitrogen =

[tex]14\times 0.996+15\times 0.004amu=14.004[/tex]

The approximate atomic mass of nitrogen is 14.004