what types of charge does a proton have ?

Hi!

The correct options would be:

1. Cathode - reduction

The cathode is the negatively charged electrode, and so has an excess of electrons. Cations (positively charged ions) are attracted to the cathode, and gain electrons to acquire a neutral charge. The process in which a gain of electron occurs is called reduction.

2. Anode - oxidation

The opposite occurs at the anode which is positively charged and attracts negatively charged ions, anions. These anions lose their electrons at the anode to acquire a neutral charge, and the process involving loss of electrons is known as oxidation.

3. Salt Bridge - ion transport

Salt bridge is a physical connection between the the anodic and cathodic half cells in an electrochemical cell and is a pathway that facilitates the flow of ions back and forth these half cells. Salt bridge is involved in maintaining a neutral condition in the electrochemical cells, and its absence would result in the accumulation of positive charge in the anodic cell, and negative charge in the cathodic cell.

4. Wire - electron transport

Wires have a universal role of being a pathway for the transport of electrons in circuit. This role is also the same in the wires involved in an electrochemical cells where they are used to transport electrons from the anodic half cell, and this electron transport results in the generation of electricity in the internal circuit of the electrochemical cell.

Hope this helps!

Answer: 1-2, 2-1, 3-3, 4-4

Explanation:

1. planet A is an inner planet as its distance from sun is 1.52 AU.

2. Planet B is an outer planet as its distance from sun is 19.22 AU.

3. planet A is Mars as it has only 2 moons.

4. planet B is Uranus because it has 27 moons.

Hence, 1-2, 2-1, 3-3, 4-4

A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. Compounds contain different elements in a fixed ratio arranged in a defined manner through chemical bonds.

The properties of the compound are different from the properties of the elements that make it up.

When elements combine in a specified ratio, compounds are formed. These compounds differ markedly from the elements that compose them.

As elements combine to form compounds, the individual properties of the combining elements are no longer observed. Only the properties of the compound formed is now observed.

Hence, the properties of the compound are different from the properties of the elements that make it up.

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Answer:

Br2 + S2O32- + 5H2O –> 2Br- + 2SO4 + 10H+ + 6e

Explanation:

So, if we were to count the number of atoms on both sides, it would be: 2 Br, 2S, 3O, 2H, 1O | 1 Br, 1S, 4O, 1H. Because O appears with S and H on the reactant side of the equation, you would combine the count. This means that instead of 3O and 1O its 4O (3+1=4 so 4 oxygen atoms). So the count is: 2 Br, 2S, 4O, 2H | 1 Br, 1S, 4O, 1H.

Now it helps to look at the atoms that have the same number on both sides of the equation so you can see which atoms you don't have to worry about. The O count is the same on both sides, but since it's associated with S and H on the reactant side of the equation, you do have to worry about it on the product side. All right so far?

It's also easier to leave the solitary atoms alone until the end, so here we'll fix the count for Br towards the end since its alone on both sides of the equation. For right now, let's look at S. As part of the reactant, there are 2 of them, but only 1 as part of the product. This means that we must have another S atom on the product side, so the equation would be:

Br2 + S2O3 2- + H2O –> Br- + 2SO4 + H+ with the count as 2 Br, 2S, 4O, 2H | 1 Br, 2S, 4O, 1H

However, this also affects O on the product side, making the count be 8O since 2•4=8.

The count is thus 2 Br, 2S, 4O, 2H | 1 Br, 2S, 8O, 1H.

At this point, the count is incorrect for O, Br, and H. To fix the count for O, you need to increase the number of O atoms without adjusting S. To do that, you would only increase the number of water molecules instead of the S2O3 molecule. You need 8 O on the reactant side and so far you only have 4, so that means you must have 5H2O molecules (it would give you 5O in addition to the 3 from S2O3). Now the O count is set and the equation look like this:

Br2 + S2O3 2- + 5H2O –> Br- + 2SO4 + H+ with the count 2 Br, 2S, 8O, 5H | 1 Br, 2S, 8O, 1H.

You now need to adjust the H and Br count. On the product side, you have 1 H as well as 1 Br when you need 5H and 2Br. The adjustments are made on the product side and because both atoms are by themselves this makes it easy! Just have 10H and 2Br on the product side so the atoms are balanced (remember that its H2 on the reactant side)! The equation now looks like this:

Br2 + S2O3 2- + 5H2O –> 2Br- + 2SO4 + 10H+ with the count 2 Br, 2S, 8O, 10H | 2 Br, 2S, 8O, 10H. As you can see, the count shows you that both sides have the same amount of each type of atom. Now we need to look at the charges.

To figure out the amount of charge on each side, just look at the exponential number (small number above last atom of molecule) and add them together. On the reactant side, there is only a charge of -2 because of one S2O3 with a charge of -2 (1• -2= -2); Br2 and 5H2O are inert, charge-wise.

However, on the product side there is a total charge of 4. This is because 2•-1 + 2•-2 + 10•1= -2 + -4 +10= -6 +10= 4. To make the charge balanced, you need to adjust the side with the larger number to make it equal the smaller one. This is because of the electrons which have a negative charge, thus bring the number down. So how do you get 4 to become -2? You would subtract 6, so this means that there are 6 electrons on the product side.

All together, the equation looks like this:

Br2 + S2O32- + 5H2O –> 2Br- + 2SO4 + 10H+ + 6e

Answer : The percent composition of Na, O and H elements are 57.47%, 40% and 2.52% respectively.

Solution : Given,

Molar mass of sodium = 22.99 g/mole

Molar mass of oxygen = 16 g/mole

Molar mass of hydrogen = 1.008 g/mole

First we have to calculate the molar mass of NaOH.

[tex]\text{ Molar mass of NaOH}=\text{ Mass of Na}+\text{ Mass of O}+\text{ Mass of H}[/tex]

[tex]\text{ Molar mass of NaOH}=22.99+16+1.008=39.998g/mole[/tex]

Now we have to calculate the percent composition of all the elements.

[tex]\%\text{ composition of Na}=\frac{\text{ Molar mass of Na}}{\text{ Molar mass of NaOH}}\times 100=\frac{22.99}{39.998}\times 100=57.47\%[/tex]

[tex]\%\text{ composition of O}=\frac{\text{ Molar mass of O}}{\text{ Molar mass of NaOH}}\times 100=\frac{16}{39.998}\times 100=40\%[/tex]

[tex]\%\text{ composition of H}=\frac{\text{ Molar mass of H}}{\text{ Molar mass of NaOH}}\times 100=\frac{1.008}{39.998}\times 100=2.52\%[/tex]

Therefore, the percent composition of Na, O and H elements are 57.47%, 40% and 2.52% respectively.

The percent compositions of Sodium, Oxygen, and Hydrogen in NaOH are 57.5%, 40%, and 2.5% respectively, based on their atomic masses and the molar mass of NaOH from the periodic table.

The percent composition of an element in a compound can be calculated using the atomic masses found on the periodic table and the molecular formula of the compound. The compound in question here is Sodium Hydroxide, or NaOH.

Firstly, let's find out the molar mass of NaOH. Sodium (Na) has an atomic weight of approximately 23 g/mol, Oxygen (O) is about 16 g/mol, and Hydrogen (H) is about 1 g/mol. Therefore, the molar mass of NaOH is 23 + 16 + 1 = 40 g/mol.

To find the percent composition, divide the atomic mass of each element by the total mass of the compound, then multiply by 100%. For Sodium: (23/40)*100% = 57.5%, for Oxygen: (16/40)*100% = 40%, and for Hydrogen: (1/40)*100% = 2.5%.

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B is a double replacement reaction where OH and Br switch places.

Hm, this could be more than one option, but gaining electrons makes a negative charge, so

If atoms of a halogen nonmetal (Group 17) gains one electron, the atoms the have "a negative one charge".

Answer:

Atoms of a halogen nonmetal gain one electron, the atom has a -1 charge.

Explanation:

The halogen non-metals of Group 17 have 7 valence electrons in their valence shell.

For an element to complete its octet and reach the stable configuration, 8 electrons are required. On gaining an electron the must be an impartment of a negative charge onto the element.

For group 17 elements to complete the octet they need to withdraw one atom. So the charge must be 1.

Since they are accepting the electron, they impart a negative charge.

So, group 17 halogen metals on gaining 1 electron have a -1 charge.

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The correct answer is option A, that is, HCl.  

An acid refers to an ion or molecule possessing the tendency of donating a hydrogen ion or a proton, or alternatively, exhibiting a tendency of producing a covalent bond with a pair of electrons. The aqueous Arrhenius acids exhibit characteristic features that offer a practical illustration of an acid.  

The acids can turn blue litmus paper red, can form aqueous solutions with a sour taste, and reacts with bases and some kind of metals to produce salts. One of the general aqueous acids is HCl (hydrochloric acid) that is found in the stomach and stimulates digestive enzymes.  

Among the options given, HCl (Hydrochloric acid) is considered to be an acid because it is listed under strong acids and releases hydrogen ions (H+) in aqueous solution, unlike the other options which are strong bases.

Looking at the list provided, we can identify HCl (Hydrochloric acid) as an acid. Bases are compounds that, in aqueous solution, release hydroxide ions (OH-), whereas acids are compounds that release hydrogen ions (H+) in aqueous solution. From the provided lists and examples in the reference information

HCl is listed under strong acids, clearly indicating it as an acidic compound

KOH (Potassium hydroxide), NaOH (Sodium hydroxide), and Ca(OH)2 (Calcium hydroxide) are mentioned as strong bases, hence they are not considered acids.

Therefore, the correct answer to which of the following is considered to be an acid is A) HCl.

Sb2 as a standalone molecule is unusual. While Antimony (Sb) usually forms a trigonal pyramidal molecule, the exact structure and polarity depend on the other atoms in the molecule.

The geometry name for Sb2 seems to be incorrect as it is unusual for antimony (Sb) to form a molecule with itself. Assuming it was intended to be SbF3 or similar, antimony typically forms bonds that result in a trigonal pyramidal molecular structure due to the electron geometry and polar bonds. However, the correct molecular structure and polar/non-polar status depends on the other atoms in the molecule.

As per the reference, antimony can form antimony(III) sulfide, which is also known as Sb2S3. Antimony typically has an oxidation state of +3 or +5 as it has 5 valence electrons, meaning in most of its compounds, it will form 3 covalent bonds and leave 2 electrons unshared, resulting in a trigonal pyramidal shape with sp³ hybridization, which will likely be a polar molecule due to the unequal sharing of electrons between Sb and other atoms.

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I think it is oxidation number

Propane is a hydrocarbon and it will burn in presence of oxygen (it will undergo combustion) to give carbon dioxide and water (all in gas phase).

In presence of oxygen the carbon gets oxidized to carbon dioxide and hydrogen to water.

The general equation for a hydrocarbon undergoing combustion is

[tex]CxHy(g)  + (x+\frac{y}{4})O_{2}  ---> xCO_{2}(g)   +\frac{y}{2}H_{2}O(g)[/tex]

Here we are studying the combustion of propane so

x = 3

y = 8  

Propane has molecular formula of C3H8

Therefore the balanced equation will be

[tex]C3H8(g)  + (3+\frac{8}{4})O_{2}  ---> 3CO_{2}(g)   +\frac{8}{2}H_{2}O(g)[/tex]

Or

[tex]C3H8(g)  +   5O_{2} (g)  ---> 3CO_{2}(g) + 4H_{2}O(g)[/tex]

Answer:

B

Explanation:

its right

valance refers to the total number of electrons that exist in the orbitals that occupy the outermost energy level of an atom. you pretty much got it!

C. Nonmetals are usually gases at room temperature. Only a few nonmetals are solid, and one (Bromine) is liquid.

Nonmetals are elements that are generally poor conductors of heat and electricity, so (A), on your far left of the periodic table

They are also typically gases or brittle solids at room temperature. Nonmetals are found on the right side of the periodic table, with the exception of hydrogen, which is found in the top left corner.

Nonmetals are an important part of the periodic table, and they play a role in many different compounds and materials. For example, oxygen is a nonmetal that is essential for life. Carbon is a nonmetal that is used to make plastics and other materials.

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A volcanic eruption

Answer:

-- Determine solubility of compounds using

generalized solubility rules.

-- Determine the equilibrium concentration.

-- Write the dissociation equation for equilibrium.

-- To find the formula for Ksp  , write the product

of the concentrations of the ions formed.

-- Raise the concentrations to the correct power

based on the associated coefficients.

Explanation:

This was the checklist on edge. 2021. (There was one more thing, but it had a picture and it wouldn't load in sooo...ya. Sowwy -.-)

Protons= 88

Neutrons= 138.

The weight of an element is comprised of entirely protons and neutrons. To get the protons look at the atomic number on the periodic table (88) and those are your protons. To get the neutrons take the weight of the isotope that you have and subtract the protons, giving you 138.

speed of light=wavelength*frequency

3*10^8m/s=wavelength*1.20*10^13

wavelength=3*10^8/1.2*10^13

=10^-5/0.4=2.5*10^-5m

10 i think not sure

Answer:

47 %  

Step-by-step explanation:

The formula for relative humidity (RH) consists of three parts:

[tex]a_{d} = 6.112e^{\frac{17.502T_{d} }{240.97+T_{d}}}[/tex]

[tex]a_{w} = 6.112e^{\frac{17.502T_{w} }{240.97+T_{w}}}[/tex]

[tex]RH = \frac{ a_{w}-0.668 745(1+0.00115T_{w})(T_{d}-T_{w})}{a_{d}}\times100[/tex]

Data:

[tex]T_{d} = 28 ^{\circ}\text{C}; T_{w} = 20^{\circ}\text{C}[/tex]

Calculations:

[tex]a_{d} = 6.112e^{\frac{17.502\times28}{240.97+ 28}}[/tex]

[tex]a_{d} = 6.112e^{\frac{490.1}{238.97}}[/tex]

[tex]a_{d} = 6.112e^{1.822}[/tex]

[tex]a_{d} = 6.112\times 6.184[/tex]

[tex]a_{d} = 37.88[/tex]

[tex]a_{w} = 6.112e^{\frac{17.502\times20}{240.97+ 20}}[/tex]

[tex]a_{w} = 6.112e^{\frac{350.0}{260.97}}[/tex]

[tex]a_{w} = 6.112e^{1.341}[/tex]

[tex]a_{w} = 6.112\times 3.824[/tex]

[tex]a _{w} = 23.37[/tex]

[tex]RH = \frac{ 23.37 - 0.668 745(1+0.00115\times20)(28 - 20)}{37.88}\times100[/tex]

[tex]RH = \frac{ 23.37 - 0.668 745(1+0.02300)\times8}{37.88}\times100[/tex]

[tex]RH = \frac{ 23.37 - 0.668 745\times1.02300\times8}{37.88}\times100[/tex]

[tex]RH = \frac{ 23.37 - 5.4738}{37.88}\times100[/tex]

[tex]RH = \frac{ 17.90}{37.88}\times100[/tex]

[tex]RH = 47.3 \%[/tex]

It's much easier to use a RH table (see below) and get the same result.

Proton and an electron .

The mass of protons and neutrons are both 1 amu (atomic mass unit). The mass of the electron is 0.00054. Therefore, when determining the isotopes when given mass, you only focus on the neutrons as they are the subatomic particles that are significantly affecting the atomic mass.

Final answer:

The mass of an electron is about 1836 times less than that of a proton or a neutron, meaning protons and neutrons contribute the most to an atom's mass. Electrons are significantly lighter and do not significantly contribute to the atomic mass.

Explanation:

When comparing the mass of an electron to that of protons and neutrons, we observe that electrons are significantly lighter in mass. A proton has a mass of approximately 1.0073 atomic mass units (amu), while a neutron is a bit heavier with a mass of about 1.0087 amu. In contrast, an electron has a mass of roughly 0.00055 amu. This means that the mass of a proton or a neutron is about 1836 times greater than that of an electron. Consequently, protons and neutrons account for nearly all of an atom's mass, with the mass of electrons being almost negligible in comparison.

Electrons and protons also have electrical charges that are equal in magnitude but opposite in sign, with electrons having a charge of -1 and protons a charge of +1. Neutrons, on the other hand, are electrically neutral and do not bear any charge. Despite their small mass, electrons play a critical role in defining the chemical properties of atoms due to their negative charge and involvement in chemical bonds.

Answer is: the average net change in temperature is 4°C.

the average net change = the average high - the average low.

the average net change = -6°C - (-10°C).

the average net change = 4°C.

Temperature is the intensity of heat present in a substance and a thermometer is a device that measures temperature or a temperature gradient.

The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.

The average net change in temperature in Nuuk in January, from the high to the low, is 4 degrees Celsius. This is determined by subtracting the average low temperature from the average high temperature.

In Nuuk, the average net change in temperature in January from high to low is calculated by subtracting the average low temperature from the average high temperature. Therefore, with an average high of -6 Celsius and an average low of -10 Celsius, the net change is 4 degrees Celsius. This is a routine method for determining the daily temperature range in a specific location, particularly useful in meteorology and climatology studies.

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Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

                           H = 1g

                           O = 16g

Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

             Mass of O in glucose = [tex]\frac{6x16}{180}[/tex]  x 55

                                                  = [tex]\frac{96}{180}[/tex] x 55

                                                  = 0.53 x 55

            Mass of oxygen in glucose = 29.3g

The answer cvould be syrup

Syrup, Honey, Milk, and Soda.

Answer is: 2. exothermic.

There are two types of reaction:  

1) exothermic reaction (chemical reaction that releases more energy than it absorbs).  

For example, ΔH(reaction) = -225 kJ/mol; this is exothermic reaction.

2) endothermic reaction (chemical reaction that absorbs more energy than it releases).

Hydrogen peroxide (H₂O₂):

1) have molecular structure.

2) it is higly reactive, it is not physically and chemically stable.

3) has low boiling point (around 150°C), because weak covalent bonds.

4) dissolve in water, because it has polar bond.

I believe a and d are both compounds. Sorry I couldn't help you much.

Answer:coal and oil

Explanation:

ILL FREAKING DIE FROM LOVE lol

That would e awesome

If it is three moles of NaOH i.e 3 NaOH

The number of atoms in each mole = 3 moles atoms

so total moles of atom = 9 moles of atom

in each mole of atoms = 6.023 X 10^23 atoms

so total atoms in three moles of NaOH = 9 X 6.023 X 10^23 atoms

= 5.4207 X 10^24 atoms

X rays have the shortest wavelength among the given options, while ultraviolet radiation enables your body to make vitamin D.

The answer to the first question is D) X rays because X-rays have the shortest wavelength among the options given. X-rays have a wavelength range of 0.01 - 10 nanometers, which is shorter than the wavelengths of green light, radio waves, and infrared radiation.

The answer to the second question is A) ultraviolet radiation. When your skin is exposed to ultraviolet (UV) radiation from sunlight, it triggers a series of chemical reactions in your body that produce vitamin D.

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Carbons starting from the left end:

Refer to the sketch attached.

The hybridization of a carbon atom depends on the number of electron domains that it has.

Each chemical bond counts as one single electron domain. This is the case for all chemical bonds: single, double, or triple. Each lone pair also counts as one electron domain. However, lone pairs are seldom seen on carbon atoms.

Each carbon atom has four valence electrons. It can form up to four chemical bonds. As a result, a carbon atom can have up to four electron domains. It has a minimum of two electron domains, with either two double bonds or one single bond and one triple bond.

Starting from the left end (H₂C=CH-) of the molecule:

Carbon atoms in a molecule can exhibit different kinds of hybridization, including sp³ and sp, leading to different molecular geometries such as tetrahedral and linear. For example, in acetylene, the carbon atoms have sp hybridization, forming a triple bond. In contrast, in a molecule like methane, the carbon atom undergoes sp³ hybridization, forming a tetrahedral structure.

In the context of the given molecule, we observe various types of hybridization in the carbon atoms. Specifically, carbon atoms 1 and 4 exhibit sp³ hybridization, indicated by their tetrahedral structure created by four single bonds. On the other hand, carbon atoms 2 and 3 are involved in a triple bond, leading to a linear geometry that signifies sp hybridization.

For instance, consider the molecule acetylene (H-C=C-H), where the two carbon atoms are attached by a triple bond due to sp hybridization. The sp hybrid orbitals of both carbon atoms form a σ bond between them and with the hydrogen atoms, while the remaining unhybridized p orbitals overlap side by side to form two π bonds.

Another form of hybridization can be observed in a molecule like CH4, where the carbon atom is surrounded by four hydrogen atoms, demonstrating sp³ hybridization. This tetrahedral structure gives methane its distinct shape. Overall, the type of hybridization a carbon atom undergoes is pivotal in determining the molecular geometry of the compound it forms.

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