Answer:
y = 8.1
Step-by-step explanation:
y+2.9=11
Subtract 2.9 from each side
y+2.9-2.9 = 11-2.9
y =8.1
There are 250 economy class seats on board. The airline sells some economy class seats at a discount price of $440 in advance and reserve a number of seats to sell at the full price of $770. Suppose that Dallas One Airline can always sell all discount tickets, and the demand for full price tickets is normally distributed with a mean of 100 and a standard deviation of 25. What is the probability that there will be no empty seat when the Dallas One Airline uses the optimal protection level? Choose the closest number.
Answer:
Check the explanation
Step-by-step explanation:
Cost of over reserving full cost tickets, Co = $440 ( empty seats as we cannot get even the discounted revenue)
Cost of under reserving Cu = 770-440 = $330 ( because you sell more discounted tickets)
Now critical ratio = Cu / (Cu+Co) = 330/770 = 0.42857
Now for above critical ratio ,z = -0.18 ( refer standard normal distribution table)
Optimal protection level = mean +z*standard deviation = 100-0.18*25 = 95.5 = 96
The possible costs include: all the above. You may need to provide compensation to passenger and make alternative travel arrangements. Also passenger won't be happy by over booking and their will be loss of good will.
help?? question is above^^ 12 points
Answer:
61/495
Step-by-step explanation:
Simplify 2/3 - 5/6 times 8
please answer
Answer:
-6
Step-by-step explanation:
simplify
Mason and Christian go to the movie theater and purchase refreshments for their friends. Mason spends a total of $45.75 on 3 bags of popcorn and 6 drinks. Christian spends a total of $71.50 on 6 bags of popcorn and 4 drinks. Write a system of equations that can be used to find the price of one bag of popcorn and the price of one drink. Using these equations, determine and state the price of a drink, to the nearest cent.
Answer:
A bag of popcorn costs $10.25One drink costs $2,5Step-by-step explanation:
Let the cost of a bag of popcorn=p
Let the cost of a drink=d
Mason spends a total of $45.75 on 3 bags of popcorn and 6 drinks.
Therefore: 3p+6d=45.75Christian spends a total of $71.50 on 6 bags of popcorn and 4 drinks.
Therefore: 6p+4d=71.50The required system of equations is:
3p+6d=45.756p+4d=71.50Multiply the first equation by 2 to eliminate p
6p+12d=91.5
6p+4d=71.50
Subtract
8d=20
d=20/8=$2.5
Substitute d=2.5 into any of the equations to obtain p.
6p+12d=91.5
6p+12(2.5)=91.5
6p=91.5-12(2.5)
6p=91.5-30
6p=61.5
Divide both sides by 6
p=$10.25
Therefore:
A bag of popcorn costs $10.25One drink costs $2,5Giving brainliest for CORRECT awnser. Am I correct?
Step-by-step explanation:
-13 > x - 43
-13 + 43 > x
30 > x
Kevin has 6 cups of flour. It takes 3/8 cup of flour to make one cake. How many cakes can Kevin make?
Answer:
16 cakes
Step-by-step explanation:
If you do 6 divided by 3/8, you would get 16, which is the amount of cakes that Kevin will be able to make.
A city council is considering funding a proposal to create a new city park. The council members will fund the proposal if they conclude that more than 60 percent of the city residents support the proposal. A survey of 2,000 randomly selected city residents will be conducted to investigate the level of support for the proposal. Let X represent the number of city residents in the sample who support the proposal. Assume that X is a binomial random variable.
Determine the mean and the standard deviation of the random variable X, assuming that 60 percent of city henudng proosal to create a new city park.
Answer:
The mean of the the random variable X is 1200.
The standard deviation of the random variable X is 21.91.
Step-by-step explanation:
The random variable X is defined as the number of city residents in the sample who support the proposal.
The random variable X follows a Binomial distribution with parameters n = 2000 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
np ≥ 10 n(1 - p) ≥ 10Check the conditions as follows:
[tex]np=2000\times 0.60=1200>10\\\\n(1-p)=2000\times (1-0.60)=800>10[/tex]
Thus, a Normal approximation to binomial can be applied.
So, the random variable X can be approximate by the Normal distribution .
Compute the mean of X as follows:
[tex]\mu=np[/tex]
[tex]=2000\times 0.60\\=1200[/tex]
The mean of the the random variable X is 1200.
Compute the standard deviation of X as follows:
[tex]\sigma=\sqrt{np(1-p)}[/tex]
[tex]=\sqrt{2000\times 0.60\times (1-0.60)}\\=\sqrt{480}\\=21.9089\\\approx 21.91[/tex]
The standard deviation of the random variable X is 21.91.
9.what is 24/32 reduced
Rectangleville's limits form a perfectly rectangular shape whose length is 20 kilometers and width is 12 kilometers. It has a population density of 320 people per square kilometer? What is the population of Rectangleville?
Answer:
Step-by-step explanation:
answer 76800
length- 20
width- 12
20x12=240
240x320(people)= 76800
The population of given Rectangleville is 76800.
What is Area of Rectangle?The area of Rectangle is length times of width.
Given that Rectangleville's limits form a perfectly rectangular shape whose length is 20 kilometers and width is 12 kilometers
length is 20 km
width is 12 km
Area of rectangleville = Length × width
=20x12
=240 square kilometer.
Now It has a population density of 320 people per square kilometer
We need to find the population.
To find this we need to multiply two hundred forty with three hundred twenty.
240x320
= 76800
Hence, the population of given Rectangleville is 76800.
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An entrepreneur is having a design group produce at least eight samples of a new kind of fastener that he wants to market. It costs $6.00 to produce each metal fastener and $10.00 to produce each plastic fastener. He wants to have at least two of each version of the fastener and needs to have all the samples 58 hours from now. It takes 5 hours to produce each metal sample and 4 hours to produce each plastic sample. To minimize the cost of the samples, how many of each kind should the entrepreneur order? What will be the cost of the samples? To minimize the cost of the samples, how many of each type of sample should the entrepreneur order? The entrepreneur should order ___ metal samples and ___ plastic samples.
Answer:
b
Step-by-step explanation:
1. The face of a brick is 3 1/2 inches by 8 inches. Suppose you want to create a
brick pathway that is 56 inches wide by 20 inches long. How many 3 1/2 inch by 8
inch bricks would you need?
Answer:
40 bricks
Step-by-step explanation:
3 1/2×8
=28
56×20
=1,120
1,120÷28
=40 bricks
Multiplication mod 29 by 30 is equivalent to standard multiplication by ___
?
Figure out what value is ___.
PLS HELP ITS A GRADE!!!
A person recently read that 84% of cat owners are women. How large a sample should the researcher take if she wishes to be 90% confident that her proportion is within 3% of the true population proportion?
Answer:
405
Step-by-step explanation:
To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.
[tex]n=\frac{(z_{\frac{\alpha }{2} })^{2} *p*q }{E^2}[/tex]
The values that are given are p = 0.84 and E = 0.03.
You can solve for the critical value which is equal to the z-score of (1 - confidence level)/2. Use the calculator function of invNorm to find the z-score. The value will given with a negative sign, but you can ignore that.
(1 - 0.9) = 0.1/2 = 0.05
invNorm(0.05, 0, 1) = 1.645
You can also solve for q which is 1 - p. For this problem q = 1 - 0.84 = 0.16
Plug the values into the equation and solve for n.
[tex]n =\frac{(1.645)^2*0.84*0.16}{(0.03)^2}\\n= 404.0997333[/tex]
Round up to the next number, giving you 405.
A company has 270 employees.60% are men and 40% are women.how many more men work then women?
Answer:
that is the solution to the question
graph the following line f(x)=-2/3x+4
Answer:
Ermm here I graphed it :)
Sorry for dark mode..
The graph on the right shows two angles that
share the same terminal side: 45° and -315º.
Together, the angles form a circle.
What if you subtract the angle measures?
45°-(-3159) =
-315º – 45º =
Answer:
45°-(315°) = 360°
-315°-45°=-360°
Second part: WOULD
Step-by-step explanation:
Trust me I gotchu
Subtracting angles involves accounting for the directions implied by their positive or negative signs. The subtraction of 45°-(-315°) equates to an addition, giving a resultant angle of 360°. Conversely, -315° – 45° provides a resultant angle of -360°.
Explanation:The question involves the mathematical concept of angles, specifically, subtracting them. Here, we are dealing with angles of 45° and -315°. When subtracting angles, consider the directions indicated by the positive and negative signs. A positive angle is measured counterclockwise from the initial side to the terminal side, while a negative angle is measured clockwise.
So, for 45°-(-315°), you're essentially adding 45 and 315 because subtracting a negative number becomes the addition of the positive equivalent. This gives you a resultant angle of 360°.
And in the case of -315° – 45°, you're subtracting 45 from -315 which gives you a resultant angle of -360°.
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A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30, and s = 10. Based on this information, and using a 95% confidence level, which of the following statements is true? a. The margin of error is approximately 4.68. b. The margin of error is approximately 3.24. c. The standard deviation of the sampling distribution of is .50. d. The critical value is 1.96. e. The critical value is 1.7921.
Answer:
b) The margin of error is approximately 3.24
e) The critical value is 1.7921.
Step-by-step explanation:
Step(i):-
Given sample size 'n' =20
Given sample standard deviation 's' = 10
Margin of error
The margin of error is determined by
[tex]M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }[/tex]
The level of significance ∝ =0.95
The degrees of freedom = n-1 = 20-1=19
t₀.₉₅ = 1.729
[tex]M.E = \frac{1.729 X10 }{\sqrt{20} }[/tex]
Margin of error = 3.866
Step(ii):-
Margin of error
The margin of error is determined by
[tex]M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }[/tex]
Given another sample size n =30
The level of significance ∝ =0.95
The degrees of freedom = n-1 = 30-1=29
t₀.₉₅ = 1.70
[tex]M.E = \frac{1.7021 X10 }{\sqrt{30} } =3.24[/tex]
Margin of error = 3.24
How are the measures of angles, arcs and segments formed by secant lines that intersect within a circle related?
Answer:
The answers below ._.
Step-by-step explanation:
A secant is a line that intersects a circle in exactly two points. When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.
The formation of secant lines that intersect within a circle is related when a secant and a tangent or two tangents intersect each other outside a circle.
What is a secant line?A secant line is a straight line that connects two points on a curve. The secant line approaches a tangent line when the two points are drawn together.
So, If a tangent and a secant, or two tangents intersect at the exterior side of a circle, the angle created has a measure equal to one-half the positive difference between the intercepted arcs' measures.
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In ideal conditions, 200 colony-forming units (cfu) of E. coli can grow to 400 cfu in 20 minutes, to 800 cfu in 40 minutes, and to 1600 cfu in an hour.
Part A: Jenny says that the E. coli growth can be modeled with an exponential function. Do you agree? Justify your answer.
Part B: Write the equation that models the function.Immersive Reader
Answer:
(a)Yes, it is an exponential function.
(b)[tex]P(t)=200\cdot 2^{t/20}[/tex]
Step-by-step explanation:
(a)A population grows exponentially if it increases by a common ratio(called the growth ratio). We can see from the given information that the population of E.coli doubles every 20 minutes, therefore it is an exponential growth with a growth ratio of 2.
(b)The population, P(t) at any time t of an initial population, [tex]P_o[/tex] with a growth ratio of r over a period k can be modeled using the function:
[tex]P(t)=P_o\cdot r^{t/k}[/tex]
In this Case:
[tex]P_o[/tex]=200
Growth rate,r=2
Growth Period,k=20 minutes
Therefore, the equation that models the function is:
[tex]P(t)=200\cdot 2^{t/20}[/tex] , t is in minutes
Jenny is correct that E. coli growth can be modeled with an exponential function, characterized by doubling in population size at regular time intervals. An equation representing this growth is N(t) = N0 x 2^(t/20), where N0 is the initial amount of E. coli and t is time in minutes.
I agree with Jenny, the E. coli growth can indeed be modeled with an exponential function. This is supported by the fact that the E. coli population doubles after each consistent time period (20 minutes). In an exponential growth model, the rate of increase of a population is proportional to the current population size, which means as the population gets larger, it grows at an even faster rate.
Part B: Equation of Exponential Growth:
The exponential growth model for a population starting with N0 individuals and a growth rate r can be described by the equation N(t) = N0ert, where N(t) is the population at time t, N0 is the initial population size, e is the base of the natural logarithm, and r is the growth rate per unit time. For E. coli, with a doubling time of 20 minutes, the growth rate can be calculated using the doubling formula: Td = ln(2)/r, solving for r gives r = ln(2) / 20 minutes. The continuous exponential growth equation can be simplified to a discrete model for this case: N(t) = N0 * 2(t/20), where t is given in minutes.
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números primos y de los números compuestos, a lo que dos estudiantes responden: Paola: he descubierto que cualquier número compuesto par se puede escribir como la multiplicación de factores primos. Edwin: he descubierto que cualquier número compuesto impar se puede escribir como la suma de dos números primos. La profesora pide a los estudiantes que examinen las ideas expuestas por Paola y Edwin y verifiquen si son verdaderas o falsas. De acuerdo con las afirmaciones hechas por Paola y Edwin es CORRECTO afirmar que A. ambas afirmaciones son falsas. B. ambas afirmaciones son verdaderas. C. la afirmación de Paola es falsa y la de Edwin es verdadera. D. la afirmación de Paola es verdadera y la de Edwin es falsa. The math teacher asks two students to describe the things they found interesting about the prime and composite numbers, to which two students respond:
Paola: I have discovered that any even compound number can be written as the multiplication of prime factors.
Edwin: I have discovered that any odd compound number can be written as the sum of two prime numbers.
The teacher asks students to examine the ideas put forth by Paola and Edwin and check to see if they are true or false.
According to the statements made by Paola and Edwin, it is CORRECT to affirm that
TO.
both statements are false.
B.
both statements are true.
C.
Paola's statement is false and Edwin's is true.
D.
Paola's statement is true and Edwin's is false.
Answer:
Respuesta D
Step-by-step explanation:
Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.
Esta afirmación es cierta, pues es un caso de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.
Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.
Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene
[tex] 2k+1+2m+1 = 2(km+1)[/tex]
Es decir, la suma de dos números impares es siempre par.
Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.
Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede descomponer como la suma de dos números primos.
One number is six less than a second number. Six times the first is 8 more than 4 times the second. Find the numbers.
To find the values of the two numbers, we can set up a system of equations based on the given information and then solve for x and y. The first number is 16 and the second number is 22.
Explanation:Let's represent the first number as x and the second number as y.
We can set up two equations based on the given information.
The first equation is: x = y - 6
The second equation is: 6x = 4y + 8
Now we can solve this system of equations to find the values of x and y.
Substituting the first equation into the second equation, we get: 6(y - 6) = 4y + 8
Simplifying, we get: 6y - 36 = 4y + 8
Bringing like terms together, we have: 6y - 4y = 8 + 36
Combining like terms, we get: 2y = 44
Dividing both sides by 2, we have: y = 22
Now substitute y = 22 back into the first equation: x = 22 - 6
Simplifying, we get: x = 16
Therefore, the first number is 16 and the second number is 22.
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Find the volume of the composite solid. ft3 pls help!! ::)))):):):):):):)
Answer:
54
Step-by-step explanation:
because it is
Answer: The volume of the composite solid is about 589.5 cubic feet.
Step-by-step explanation:
The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is registered to vote. Suppose that 513513 employed persons and 604604 unemployed persons are independently and randomly selected, and that 287287 of the employed persons and 280280 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers ( p1p1 ), who have registered to vote, exceeds the percentage of unemployed workers ( p2p2 ), who have registered to vote? Use a significance level of α=0.05α=0.05 for the test.
Answer:
We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.
Step-by-step explanation:
We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.
Let [tex]p_1[/tex] = percentage of employed workers who have registered to vote.
[tex]p_2[/tex] = percentage of unemployed workers who have registered to vote.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex] {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1>p_2[/tex] {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}
The test statistics that would be used here Two-sample z test for proportions;
T.S. = [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] ~ N(0,1)
where, [tex]\hat p_1[/tex] = sample proportion of employed workers who have registered to vote = [tex]\frac{287}{513}[/tex] = 0.56
[tex]\hat p_2[/tex] = sample proportion of unemployed workers who have registered to vote = [tex]\frac{280}{604}[/tex] = 0.46
[tex]n_1[/tex] = sample of employed persons = 513
[tex]n_2[/tex] = sample of unemployed persons = 604
So, the test statistics = [tex]\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }[/tex]
= 3.349
The value of z test statistics is 3.349.
Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.
Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.
In the right triangle shown, DF=EF=3DF=EF=3D, F, equals, E, F, equals, 3.
How long is DEDED, E?
The length of side DE in the right triangle shown is 4.24 units.
We can use the Pythagorean Theorem to solve for the length of DE, since we know the lengths of the other two sides.
The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
The hypotenuse of the triangle is DE, and the other two sides are DF and EF. We know that DF = EF = 3 units. Therefore, we can set up the following equation:
[tex]DE^2 = DF^2 + EF^2[/tex]
Substituting in the known values, we get:
[tex]DE^2 = 3^2 + 3^2[/tex]
[tex]DE^2 = 9 + 9[/tex]
[tex]DE^2 = 18[/tex]
Taking the square root of both sides, we get the length of DE:
DE = √18
DE ≈ 4.24 units
Therefore, the length of side DE in the right triangle shown is 4.24 units.
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Question
A) 77°
C) 109°
B) 167°
D) 150°
Answer:
Wat is the question?
Step-by-step explanation:
Solve the following equation algebraically: x^2 = 180
Answer:
x = ± 6sqrt(5)
Step-by-step explanation:
x^2 = 180
Take the square root of each side
sqrt(x^2) = ±sqrt(180)
x =±sqrt(36)sqrt(5)
x = ± 6sqrt(5)
Answer:
Edge 2020
A
-13.42, 13.42
Step-by-step explanation:
he United States Marine Corps is reviewing its orders for uniforms because it has a surplus of uniforms for tall men recruits and a shortage for shorter men recruits. Its review involves data for 772 men recruits between the ages of 18 to 24. That sample group has a mean height of 69.7 inches with a population standard deviation of 2.8 inches. Construct a 99% confidence interval for the mean height of all men recruits between the ages 18 and 24.
Answer:
The 99% confidence interval for the mean height of all men recruits between the ages 18 and 24 is between 69.44 inches and 69.96 inches.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.99}{2} = 0.005[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.005 = 0.995[/tex], so [tex]z = 2.575[/tex]
Now, find the margin of error M as such
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 2.575\frac{2.8}{\sqrt{772}} = 0.26[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 69.7 - 0.26 = 69.44 inches
The upper end of the interval is the sample mean added to M. So it is 69.7 + 0.26 = 69.96 inches
The 99% confidence interval for the mean height of all men recruits between the ages 18 and 24 is between 69.44 inches and 69.96 inches.
In 2015 college students at a large state university completed a survey about their academic and
personal life. Questions ranged from "How many credits are you registered for this semester?" to
"Would you define yourself as a vegetarian?"
The researcher randomly selected 325 students from the university: 312 responded to the survey.
Prompt
The cell-phone datafile is available in the Data section below.
Here is the research question for this lab.
Based on a recent study, roughly 80% of college students in the U.S. own a smartphone. Is
the proportion of smartphone owners lower at this university?
Respond to each of the following in your initial post. Be sure to number each answer to which
question it answers.
1. State your hypotheses in symbolic form and in words. (The following should be clear in your
answer: the population of interest and the meaning of the proportion pin terms of the variable
Cell.) You do not need to write the notation, you can just write:
o Null:
o Alternate:
Answer:
The null hypothesis is represemted as
Null: p ≥ 0.80
The alternative hypothesis is given as
Alternative: p < 0.80
Step-by-step explanation:
For hypothesis testing, the first thing to define is the null and alternative hypothesis.
In hypothesis testing, especially one comparing two sets of data, the null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test. It usually maintains that, with random chance responsible for the outcome or results of any experimental study/hypothesis testing, its statement is true.
The alternative hypothesis usually confirms the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test. It usually maintains that significant factors other than random chance, affect the outcome or results of the experimental study/hypothesis testing and result in its own statement.
For this question, the survey that involved comparison was the proportion of US students at the university that owned a smartphone and the proportion of college students in the US that own a smartphone (80%).
Specifically, we want to check if the proportionof smartphone owners at the university is lower than the overall proportion of smartphone owners amongst US college students (80%).
Hence,
The null hypothesis would be that there isn't significant evidence to conclude that the proportion of smartphone owners is lower at this university than the general proportion of smartphone owners amongst college students.
That is, the proportion of smartphone users at this university isn't lower than the proportion of college students in the U.S. that own a smartphone or the proportion of smartphone owners at this university is higher than or equal to the proportion of college students in the U.S. that own a smartphone.
The alternative hypothesis is then that there is significant evidence to conclude that the proportion of smartphone users at this university is lower than the proportion of college students in the U.S. that own a smartphone.
Mathematically,
The null hypothesis is represemted as
Null: p ≥ 0.80
The alternative hypothesis is given as
Alternative: p < 0.80
Hope this Helps!!!
The null hypothesis states that the proportion of smartphone owners at the university is not lower than 80%, while the alternative hypothesis states that the proportion is lower. A hypothesis test can be conducted using the data from the survey to determine if the proportion is significantly lower.
Explanation:The research question is whether the proportion of smartphone owners at this university is lower than the national average of 80%. We can state the hypotheses as:
Null Hypothesis (H0): The proportion of smartphone owners at this university is not lower than 80%.
Alternative Hypothesis (Ha): The proportion of smartphone owners at this university is lower than 80%.
To test these hypotheses, we need to analyze the data from the survey and perform a hypothesis test. We can use statistical software to calculate the proportion of smartphone owners at the university and conduct the test.
1. Add and write in standard form.
(2x2 - 6x3 + 4) + (2x3 + 3x2 + 4)
Answer:
because I said one is the best number
Step-by-step explanation:
[tex](2x^2-6x^3+4)+(2x^3+3x^2+4)[/tex]
Since this is addition, you can just easily combine the terms.
[tex](2x^2+3x^2)+(-6x^3+2x^3)+(4+4)[/tex]
[tex]5x^2 -4x^3+8[/tex]
Now, all we have to do is put it in standard form meaning the exponents have to go in descending order. Largest exponent to smallest exponent.
[tex]-4x^3+5x^2+8[/tex]
So, this is your answer in standard form.
What is the opposite of -0.8
Answer:
0.8
Step-by-step explanation:
the opposite of a negative is the positive version of the number
Answer:
the opposite of -0.8 is 0.8
Step-by-step explanation:
opposite of a negative number is the same number but positive or vice verse