What would be the resulting molarity of a solution made by dissolving 25.4 grams of KOH in enough water to make a 985-milliliter solution? Show all of the work needed to solve this problem.

When a compound containing c, h, and o is completely combusted in air, the reactant besides the hydrocarbon that is involved in the reaction is, O2(g).

Hydrocarbons burn in air to form water and carbon dioxide as the only products.

That is;

For hydrocarbons with carbon and hydrogen

For the compound containing carbon, hydrogen and oxygen  

Examples  

Propane which is an alkane burns in air to form water and mineral salt.

C3H8(g) + O2(g) = CO2(g) + H2O(l)

Ethanol is a hydrocarbon in the homologous series of alcohols. It burns in air to form carbon(IV)oxide and water.

C2H5OH(l) + 3O2(g) = 2CO2(g) + 3H2O(l)

Keywords: Combustion, hydrocarbons  

Level: High school

Subject: Chemistry  

Topic: Organic chemistry  

Sub-topic: Combustion of hydrocarbons

Answer:

B. It allows scientists to predict things about objects that are too small to see.

Explanation:

Hello,

In science, we're always looking for the study of tinier things as long as we're interested about what the matter is made of. Several atomic models such as Bohr's, Rutherford's, Dalton's and the actual one have been proposed in order for us to understand how the protons, neutrons and electrons are assembled into the atom because they are too small to see (about 0.5 fm) thus, with that better understanding, we can research and develop novel applications for new materials based on the micromolecular behavior of the atom.

Best regards.

To find the number of moles of silver atoms in the silver ring, divide the number of particles by Avogadro's number.

To find the number of moles of silver atoms in the silver ring, we can use Avogadro's number. Avogadro's number tells us that 1 mole of any substance contains 6.022 x 10^23 particles. In this case, we are given that the silver ring contains 5.15 x 10^22 silver atoms. We can use the following equation:

Number of moles = Number of particles / Avogadro's number

Substituting the given values, we get:

Number of moles = 5.15 x 10^22 silver atoms / (6.022 x 10^23 atoms/mol) ≈ 0.0855 mol ≈ 0.086 mol (rounded to two significant figures)

https://brainly.com/question/12160954

#SPJ2

Final answer:

When determining the percent acetic acid in vinegar, measuring the mass of vinegar is preferred over volume because mass is not affected by temperature and concentration changes. The mass can be used to calculate moles of acetic acid, which is then used to find molarity or mole fraction.

Explanation:

In the analysis of vinegar, it is often more accurate to measure the mass of the vinegar sample rather than the volume because mass is not affected by temperature or concentration variations as volume can be. When determining the percent acetic acid in vinegar, we can use the sample's mass to calculate the number of moles of acetic acid present. Let's say we have a sample where the concentration of acetic acid was previously found to be 0.839 Molarity (M). If we find that a certain volume of vinegar contains 75.6 g of acetic acid, we can use the molarity and the mass of acetic acid to determine the volume of the vinegar solution.

To calculate the mole fraction of acetic acid in the solution, the masses of both acetic acid and water in the sample are required. Using an example from LibreTexts, if 100.0 g of vinegar contains 3.78 g of acetic acid, then there are 96.2 g of water in the solution. From the masses, we determine the moles of acetic acid and water and then divide the number of moles of acetic acid by the total number of moles of substances in the sample to get the mole fraction.

oxygen (O) and chlorine (Cl)

As the electronegativity of an element increases It is more likely to make an ionic bond. e.g. the metallic elements. On the moderate values of electronegativity, elements tend to make covalent bond.

Oxygen and chlorine will make covalent bond because the electronegativity difference between these two elements is 0,5 so there bond will be covalent in nature.

Percent yield or yield is mathematically defined as:

Yield = Actual amount / Theoretical amount

So to solve the yield, let us first calculate the theoretical amount of POCl3 produced. The balanced chemical reaction for this is:

6 PCl5 + P4O10  --->  10 POCl3

Since P4O10 is stated to be supplied in large amount, then PCl5 becomes the limiting reactant.

So we calculate for POCl3 based on PCl5. To do this let us convert the amount into moles: (molar mass PCl5 = 208.24 g/mol)

n PCl5 = 42.66 grams / (208.24 g/mol)

n PCl5 = 0.205 mol

Now based on the stoichiometric ratio of the reaction:

n POCl3 = 0.205 mol (10 POCl3 / 6 PCl5)
n POCl3 = 0.3414 mol POCl3

Converting to mass (molar mass POCl3 = 153.33 g/mol)

m POCl3 = 0.3414 mol (153.33 g/mol)

m POCl3 = 52.35 g

Calculating for yield:

Yield = 47.22 g/ 52.35 g

Yield = 0.902

%Yield = 90.2 %                      (ANSWER)

The percent yield of POCl₃ is calculated by dividing the actual yield (47.22 grams) by the theoretical yield (52.36 grams), then multiplying by 100 to obtain a percent yield of 90.18%.

To calculate the percent yield of POCl₃, we first need the balanced chemical equation for the reaction between PCl₅ and P₄O₁₀. The equation is:

6 PCl₅ + P₄O₁₀ → 10 POCl₃

Next, we will convert the mass of PCl₅ to moles:

Molar mass of PCl₅ = 208.24 g/mol

Moles of PCl₅ = 42.66 g / 208.24 g/mol = 0.2049 moles

Using the stoichiometry of the balanced equation, we calculate the theoretical yield of POCl₃:

For every mole of PCl₅, (10/6) moles of POCl₃ are produced. Therefore, the moles of POCl₃ produced from 0.2049 moles of PCl₅ are:

Moles of POCl₃ = 0.2049 moles PCl₅ × (10/6) = 0.3415 moles

Molar mass of POCl₃ = 153.33 g/mol

Theoretical yield of POCl₃ = 0.3415 moles × 153.33 g/mol = 52.36 grams

Now, we can calculate the percent yield:

Percent yield = (Actual yield / Theoretical yield) × 100

Percent yield = (47.22 g / 52.36 g) × 100 = 90.18%

Therefore, the percent yield of POCl₃ is 90.18%.

To find the maximum mass of S8 produced, we first convert mass of the reactants to moles, then use stoichiometry to find the amount of S8 each can produce. The reactant that produces the least S8 is the limiting reactant. Finally, we convert the moles of S8 to grams.

The calculation for maximum mass of S8 that can be produced in the reaction 8SO2 + 16H2S = 3S8 + 16H2O, first requires understanding of how to use stoichiometry and limiting reactants concept. We start by converting the given mass of the reactants (87.0 g) to moles using their molar mass. For SO2, it's 64 g/mol and for H2S, it's 34 g/mol. We get 1.36 mol of SO2 and 2.56 mol of H2S.

Then, by using the stoichiometric coefficients present in the balanced equation, we'll find the amount of S8 that can be produced by each reactant. The limiting reactant is the one which produces least amount of product. In this case, it's SO2. Finally, we convert the moles of S8 to grams using its molar mass (256 g/mol).

https://brainly.com/question/34828728

#SPJ11

Answer:

[tex]S_2O_3[/tex]

Explanation:

Hello,

Nomenclature, is a powerful tool in chemistry to name chemical compounds to successfully distinguish among the thousands and thousands of existing molecular compounds. In rule to stipulate a chemical name y is via specifying the amount of the composing elements into the molecule, thus, the prefix di, accounts for two atoms and the prefix tri for three (this is related with the valence electrons the element has), in such a way, disulfur trioxide is represented with two sulfur atoms and three oxygen atoms, this is:

[tex]S_2O_3[/tex]

Which would be a novel molecule since the sulfur has been reported to have +2,+4 and +6 as the positive oxidation states which are possible to dovetail with oxygen as it is negative.

Kind regards.

The number of molecules of carbon dioxide present in 243.6 g of carbon dioxide is 3.33 × 10²⁴ molecules

From the question,

We are to determine the number of molecules of carbon dioxide that are in 243.6g of carbon dioxide

First, we will determine the number of moles of carbon dioxide present

Using the formula,

[tex]Number\ of\ moles\ = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of carbon dioxide = 44.01 g/mol

Number of moles of carbon dioxide = [tex]\frac{243.6}{44.01}[/tex]

Number of moles of carbon dioxide = 5.5351 moles

Now, for the number of molecules,

Using the formula,

Number of molecules = Number of moles × Avogadro's constant

Number of molecules = 5.5351 × 6.022 × 10²³

Number of molecules of carbon dioxide = 3.33 × 10²⁴ molecules

Hence, the number of molecules of carbon dioxide present in 243.6 g of carbon dioxide is 3.33 × 10²⁴ molecules

Learn more on calculating number of molecules here: https://brainly.com/question/14464650

The hydroxide ion concentration in the solution is calculated to be 2.857 × 10^-11 M using the ion product of water (Kw) and the given hydronium ion concentration.

To calculate the hydroxide ion concentration in an aqueous solution that contains 3.50 Ã 10^-4 M in hydronium ion, you can use the relationship between the hydronium ion [H3O+] and hydroxide ion [OH-] concentrations in water which is known as the ion product of water (Kw).

At 25°C the ion product of water, Kw is 1.0 × 10-14 M^2. These ions are related through the equation [H3O+][OH-]= Kw, which is the mathematical representation of the ion product of water at a particular temperature.

Substitute the given hydronium ion concentration into the equation to calculate the hydroxide ion concentration: [OH-] = Kw / [H3O+]. So, [OH-] = (1.0 × 10-14 M^2) / (3.50 × 10^-4 M) = 2.857 × 10^-11 M. So, the hydroxide ion concentration in the solution is 2.857 × 10^-11 M.

https://brainly.com/question/4617925

#SPJ11

Answer: A.

Explanation:  it makes some inexpensive materials look more appealing

1.5625.10²⁰ electrons are flowing through this device in 5 s

Electric current is the amount of electric charge that flows each unit of time

Electric current can also be a ratio between voltage and resistance

Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points

Electrons will flow through the conducting wire that functions as a conductor

The electric current itself can be divided into direct current (DC) or alternating current (AC)

Can be formulated:

[tex]{\displaystyle I = {\frac {Q} {t}},}[/tex]

Where

I is the electric current, Ampere (A)

Q is the electric charge, coulomb (C)

t is time, seconds (s)

An electric device delivers a current of 5 A within 5 s, so the charge is:

Q = I x t

Q = 5 x 5

Q = 25 C

Because 1 electron (e) has a charge of 1.60 × 10⁻¹⁹ C, so the total number of electrons flowing:

= 25 C: 1.60 × 10⁻¹⁹ C

= 15.625.10¹⁹

= 1.5625.10²⁰ e

electric field

https://brainly.com/question/2080732

magnetism

https://brainly.com/question/10809295

2.0x10 ^ 20 electrons to pass through a point

https://brainly.com/question/334342

Keywords: electric current, electric charge, electrons, coulombs, amperes, seconds

Final answer:

To calculate the pH at different points in the titration of HCl with NaOH, you need to consider the moles of reactants and products and use the Henderson-Hasselbalch equation.

Explanation:

In a titration of 25.00 mL of 0.150 M HCl with 0.250 M NaOH, the pH can be calculated at different points:

(a) When neutralization is 50% complete, we can assume that half of the HCl has reacted with NaOH. This means that the moles of HCl neutralized is half of the initial moles present. Use this information to calculate the moles of NaOH consumed and the remaining HCl. From there, you can use the Henderson-Hasselbalch equation to calculate the pH.

(b) When 1.00 mL of NaOH is added beyond the equivalence point, you can assume that all of the HCl has been neutralized and there is excess NaOH. Calculate the moles of NaOH consumed based on the volume added and use it to determine the concentration of NaOH remaining. Then, use the concentration of NaOH and the hydroxide ion concentration to calculate the pH.

Solid solutions are formed only by solutes and solid solvents. In everyday life, the main examples of this type of solution are metallic alloys.

2) Liquid Solutions

Liquid solutions have liquid solvent, usually water, and solutes can be solid, liquid or gaseous.

3) Gaseous solutions

This kind of solution is formed by the only mixture of gases. Air is an example, as its approximate composition is 78% nitrogen gas, 21% oxygen gas and 1% of other gases.

To find the grams of phosphorus that contain the same number of molecules as 7.88 g of sulfur, use the concept of molar mass and Avogadro's number.

To determine the grams of phosphorus that contain the same number of molecules as 7.88 g of sulfur, we need to use the concept of molar mass and Avogadro's number. First, we calculate the number of moles of sulfur by dividing its mass by its molar mass. Then, we use the molar ratio between sulfur and phosphorus from their molecular formulas to calculate the number of moles of phosphorus. Finally, we multiply the number of moles of phosphorus by its molar mass to obtain the grams of phosphorus.

Step 1: Calculate the moles of sulfur:

moles of sulfur = mass of sulfur / molar mass of sulfur

Step 2: Calculate the moles of phosphorus:

moles of phosphorus = moles of sulfur × (molar ratio of phosphorus/sulfur)

Step 3: Calculate the grams of phosphorus:

grams of phosphorus = moles of phosphorus × molar mass of phosphorus

After performing these calculations using the given values, the grams of phosphorus that contain the same number of molecules as 7.88 g of sulfur is obtained.

https://brainly.com/question/30340401

#SPJ11

Final answer:

The ratio of the frequency of effective collisions for a reaction at higher to lower temperature can be found using the Arrhenius equation, which illustrates that the reaction rate increases with temperature due to more molecules having sufficient energy to overcome the activation energy barrier.

Explanation:

The question revolves around the concept known as the Arrhenius equation, which describes how the rate of a chemical reaction is affected by changes in temperature and activation energy. The ratio 'f' represents the frequency of effective collisions leading to a reaction. The Arrhenius equation suggests that as temperature increases, the rate constant of the reaction also increases because a greater fraction of molecules will have the necessary energy to overcome the activation energy barrier.

To calculate the ratio of the frequency of effective collisions at two different temperatures for a reaction with an activation energy (Ea) of 205 kJ/mol, we use the Arrhenius equation:

K = Ae-(Ea/RT)

Where K is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant (8.314 J/mol K), and T is the temperature in kelvins. By taking the ratio of the rate constants at 505 K and 485 K (K2/K1), we can find the ratio of 'f' at the higher temperature to the lower temperature.

The analysis of the change in reaction mechanism with temperature typically shows that, as seen with a reaction with a lower activation energy of 54 kJ/mol, a temperature increase, even by 10 degrees Celsius, can significantly impact the reaction rate, often doubling it. While the exact ratio of 'f' would require computation, the concept remains that the reaction rate will increase with temperature due to the exponential factor in the Arrhenius equation.

Correctly balancing a chemical equation involves adding coefficients to ensure the number of atoms for each element is equal on both sides. As the given equation has a typo, a general method for balancing equations and an example with sodium and chlorine was described.

The question asks about balancing a particular chemical equation to find the coefficient of NaI. However, the given equation seems to have a typographical error and is not complete. In the context of this question, let's address a general approach on how to balance a chemical equation:

Write down the unbalanced equation.

Determine the number of atoms of each element in the reactants and products.

Adjust coefficients (not subscripts) to get the same number of atoms of each element on both sides.

Repeat steps until all elements are balanced.

Check to ensure that the total charge is the same on both sides if the equation includes ionic species.

For example, the equation for the reaction of sodium (Na) with chlorine gas (Cl2) to form sodium chloride (NaCl) is balanced by placing a '2' in front of Na and NaCl:

2 Na (s) + Cl₂ (g) → 2 NaCl (s)

In this balanced equation, we see that the number of sodium and chlorine atoms are equal on both sides, confirming that the equation is correctly balanced.