Heat energy released here
Q = mass x specific heat capacity of water x deltaT
= 25.0 x 4.184 x (-10.0)
= - 1046 Joules
1046 Joules of heat energy is released in this process.
Answer: The amount of heat released is -1046 J
Explanation:
To calculate the amount of heat released, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat released = ?
m = mass of water = 25.0 g
c = specific heat capacity of water = 4.184 J/g.°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(10.0-20.0)^oC=-10.0^oC[/tex]
Putting values in above equation, we get:
[tex]q=25.0g\times 4.184J/g.^oC\times (-10.0^oC)\\\\q=-1046J[/tex]
Hence, the amount of heat released is -1046 J
Which statement about gases is true? A. They are made up of particles that always move very slowly. B. They are made up of particles that travel in a curved path when in motion. C. They are made up of hard spheres that vibrate quickly in stationary positions. D. They are made up of hard spheres that are in random motion.
Answer: D. They are made up of hard spheres that are in random motion.
Explanation:
A gas is a state of aggregation of matter in which, under certain conditions of temperature and pressure, its molecules interact weakly with each other, without forming molecular bonds, adopting the shape and volume of the container that contains them and tending to separate everything possible because of its high concentration of kinetic energy.
The molecules of a gas are practically free and have the ability to be distributed throughout the space in which they are contained because the gravitational forces and attraction between them are practically negligible compared to the speed at which they move. .
Therefore, gas molecules do not travel specific trajectories or vibrate in a stationary position, instead they move quickly and randomly through the entire space of the container that contains them.
The true statement about gases is that they are made up of hard spheres that are in random motion, which is option D.
Among the given options, statement D is true. Gases are composed of particles, such as atoms or molecules, that are in constant random motion. These particles move in straight lines until they collide with other particles or the walls of the container, where they undergo elastic collisions. The random motion of gas particles is responsible for their ability to fill the entire volume of the container and to exert pressure on the container walls.
Hence, the correct option is option d.
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Which of the following models best describes the arrangement of valence electrons in metals?
(1 point)
A body-centered cube
Octets of electrons
A rigid array of electrons
A sea of electrons
The arrangement of valence electrons in metals can be best described by the
A sea of electrons.
How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? Fe2O3(s) + 3CO(g) --> 3CO2(g) + 2Fe(s)
Please SHOW WORK so I can understand the concept
The grams of carbon monoxide is 148. 68 g
calculation
Fe₂O₃(s) + 3CO (g) → 3 CO₂(g) + 2Fe (s)
Step 1: find the moles of CO
moles = mass÷ molar mass
from periodic table the molar mass of Fe =56 g/mol
moles = 198.5 g÷ 56 g/mol =3.54 moles
Step 2 : use the mole ratio to determine the moles of Co
from given equation Co: Fe is 3: 2
therefore the moles of CO = 3.54 moles x 3/2= 5.31 moles
Step 3 Find mass of Co
mass = moles × molar mass
from periodic table the molar mass of CO = 12+ 16 = 28 g/mol
= 5.31 moles × 28 g/mol = 148.68 g
The _______ elements tend to lose electrons and form positive ions, while the _______ elements tend to gain electrons and form negative ions.
The electropositive elements or metals elements tend to lose electrons and form positive ions, while the electronegative elements or non-metals tend to gain electrons and form negative ions.
What are metals?Metals are electropositive elements with extra electrons in their atom. Hence, they easily loss electron to achieve octet. Metals donate electrons to electron deficient non-metals forming ionic compounds.
Non -metal are located in right side of the periodic table. Except group 18 elements all the non-metals are electron deficient. Some of them such as oxygen, nitrogen, fluorine are highly electronegative and easily gain electrons from metal atoms forming ionic compounds or share electrons from other non-metals forming covalent compounds.
Therefore, metallic elements tend to lose electrons and form positive ions, while the electronegative elements or non-metals tend to gain electrons and form negative ions.
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Metals lose electrons and form positive ions, while non-metals gain electrons and form negative ions due to their atomic structure.
Explanation:The metals elements tend to lose electrons and form positive ions, while the non-metals elements tend to gain electrons and form negative ions. This is due to the atomic structure of these elements. Metals have fewer electrons in their outer shell, and thus they can easily lose them to become stable, which leads to the formation of positively charged ions. On the other hand, non-metals have more electrons in their outer shell and thus they need more electrons to become stable. As a result, they tend to receive electrons, forming negatively charged ions.
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**answer asap with explanation please
The table shows the nature of the reactants and products formed in a certain type of chemical reaction.
Nature of Reactants and Products
Reactants
Ionic compound + Ionic compound
Products
Ionic compound + Ionic compound
Which of the following is true about this type of chemical reaction?
It is a single replacement reaction, and all four compounds are different.
It is a double replacement reaction, and all four compounds are different.
It is a single replacement reaction, and each compound has the same set of ions.
It is a double replacement reaction, and each compound has the same set of ions.
Answer:
It is a double replacement reaction, and all four compounds are different.
Step-by-step explanation:
The equation for the reaction is
[tex]\underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{reactants}} \longrightarrow \underbrace{\hbox{ ionic compound + ionic compound}}_{\hbox{products}}[/tex]
This must be a double replacement reaction, in which the metal cations trade partners and all four compounds are different.
(A) and (C) are wrong, because single replacements involve elements in reactions of the type
element + compound ⟶ element + compound
(D) is wrong because, if each compound retained the same set of ions, there would be no reaction.
Answer:
It is a double replacement reaction, and all four compounds are different.
Explanation:
Just took the FLVS 4.03 Single and Double Replacement Reactions quiz. I got a 100.
Click the button within the activity, and analyze the relationship between the two reactions that are displayed. The reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, ΔH, is an extensive property. Using this property, calculate the change in enthalpy for Reaction 2. Reaction 1: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g), ΔH1=â’2043 kJ Reaction 2: 6C3H8(g)+30O2(g)→18CO2(g)+24H2O(g), ΔH2=?
Answer:
-12 258 kJ
Step-by-step explanation:
Reaction 1: C₃H₈(g)+5O2(g) ⟶ 3CO₂(g)+ 4H₂O(g); ΔH₁ = - 2 043 kJ
Reaction 2: 6C₃H₈(g)+30O2(g) ⟶ 18CO₂(g)+ 24H₂O(g); ΔH₂ = -12 258 kJ
Reaction 2 is Reaction 1 multiplied by 6.
ΔH is an extensive property, so you must also multiply ΔH by 6.
Final answer:
The enthalpy change for Reaction 2 is calculated by multiplying the given enthalpy change for Reaction 1 by the factor of six. Since enthalpy is an extensive property, Reaction 2's enthalpy change is –12258 kJ.
Explanation:
ΔH, or change in enthalpy, is an extensive property, which means it is proportional to the amounts of reactants and products in a reaction. In the student's question, we need to calculate the enthalpy change for Reaction 2 based on the given enthalpy change for Reaction 1. We are given that the enthalpy change for Reaction 1, which is the combustion of propane [tex](C_3H_8)[/tex], is [tex]\Delta H_1 = -2043 kJ[/tex]:
[tex]C_3H_8(g) + 5O_2(g) \rightarrow 3CO_2(g) + 4H_2O(g), \Delta 2 \Delta H_1 = -2043 kJ[/tex]
For Reaction 2, the equation is the same but scaled up by a factor of six:
[tex]6C_3H_8(g) + 30O_2(g) \rightarrow 18CO_2(g) + 24H_2O(g), \Delta 2 \Delta H_2 = ?[/tex]
To find ΔH2, we multiply ΔH1 by the scaling factor, which is six, because enthalpy is an extensive property:
[tex]\Delta H_2 = 6 \times \Delta H_1 = 6 \times (-2043 kJ) = -12258 kJ[/tex]
Therefore, the enthalpy change for Reaction 2 is ΔH2 = –12258 kJ.
Which one of these is the accepted name for the compound n2o5?
a. dinitrogen oxide
b. nitrogen pentaoxide
c. dinitrogen pentoxide
d. dinitrogen pentaoxide
The accepted name for N2O5 is dinitrogen pentoxide.
The accepted name for the compound N2O5 is dinitrogen pentoxide. It is formed by the combination of two nitrogen atoms and five oxygen atoms. The prefix 'di' indicates that there are two nitrogen atoms, and the prefix 'pento' indicates that there are five oxygen atoms.
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You mix 145 grams of water with 200 grams of ethanol to make a solution. What is the solute and what is the solvent?
The greater amount is the solvent and the lesser amount is the solute.
Hence ethanol(200g) which is the greater amount is the solvent here.
And water (145g) which is lesser is the solute here.
Which explanation best compares the movement of particles in the three states of matter? A. Particles in a gas can only vibrate. In a solid, they slide against each other. In a liquid, they move freely, bouncing and bumping into each other. B. Particles in a solid can only vibrate. In a liquid, they slide against each other. In a gas, they move freely, bouncing and bumping into each other. C. Particles in a liquid can only vibrate. In a gas, they slide against each other. In a solid, they move freely, bouncing and bumping into each other. D. Particles in a solid can only vibrate. In a gas, they slide against each other. In a liquid, they move freely, bouncing and bumping into each other. E. Particles in a liquid can only vibrate. In a solid, they slide against each other. In a gas they move freely, bouncing and bumping into each other.
Answer:
e
Explanation:
You need to produce a buffer solution that has a pH of 5.40. You already have a solution that contains 10. mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pKa of acetic acid is 4.74. Express your answer numerically in millimoles. View Available Hint(s)
Answer:
46. mmol
Step-by-step explanation:
The equation for the equilibrium is:
HA + H₂O ⇌ A⁻ + H₃O⁺
The solution is a buffer, so we can use the Henderson-Hasselbalch equation:
pH = pKa + log([A⁻]/[HA])
5.40 = 4.74 + log([A⁻]/(10.) Subtract 4.74 from each side
0.66 = log([A⁻]/(10.) Take the antilog of each dide
[A⁻]/10. = 10 ^0.66
[A⁻]/10. = 4.57 Multiply each side by 10.
[A⁻] = 46. mmol
You will add 46. mmol of sodium acetate.
The amount of acetate needed to add to the solution is ; 46 mmol
Given data:
pH of buffer solution = 5.4
volume of Solution ( H A ) = 10 mmol
pKa of acetic acid = 4.74
Given that the solution is a buffer solution we will apply Henderson-Hasselbalch equation:
pH = [tex]pKa + log ( [A^-] / [HA] )[/tex] -------- ( 1 )
Insert values into equation 1
[tex]5.40 = 4.74 + log([A^-]/(10 )[/tex]
0.66 = [tex]log([A^-]/(10.)[/tex] -------- ( 2 ) ( after subtracting pKa value from both side )
∴ [tex][A^-]/10. = 10^{0.66}[/tex] ----- ( 3 ) ( antilog )
Multiply both sides of equation 3 by 10
[tex][A^-] = 46 mmol[/tex].
Hence we can conclude that the amount of acetate needed to add to the solution is 46 mmol
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The molar mass of a solid carboxylic acid is determined by titrating a known mass of the acid with a standardized solution of NaOH to a phenolphthalein endpoint. Which errors will lead to a molar mass that is smaller than the actual molar mass? I. Some of the acid is spilled when being transferred into the titration flask. II.The endpoint is recorded when the solution is dark red in color rather than light pink.
In a titration, a molar mass lower than the actual one could be obtained by spilling part of the acid before titration or recording a dark red color instead of a light pink as the endpoint. These errors would lower the calculated molar mass because either too little acid or too much NaOH is assumed for the reaction.
Explanation:In a titration experiment with a carboxylic acid and a standardized NaOH solution, there are factors that could lead to the measurement of a molar mass that is smaller than its actual value.
Error I: If some of the carboxylic acid is spilled when being transferred into the titration flask, this will decrease the amount of acid available for titration. This leads to an underestimation of the amount of NaOH needed for neutralization and therefore a smaller calculation for molar mass.
Error II: If the endpoint of the titration is recorded when the color is dark red rather than light pink, this means that the end-point has been overshot – too much NaOH has been added. This excess amount would lead to the calculation of a smaller molar mass since an increased volume of NaOH is wrongly assumed to have neutralized the acid.
Titration analysis therefore requires real accuracy both in process and observation to avoid such errors. It is important to determine and record the right endpoint based on a distinct, recognized color change with the suitable indicator, in this case, a change from colorless to light pink with phenolphthalein.
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The correct answer is that both errors I and II will lead to a molar mass that is smaller than the actual molar mass.
I. Some of the acid is spilled when being transferred into the titration flask.
When some of the acid is spilled, the mass of the acid that is actually titrated is less than the mass that was intended to be titrated.
Since molar mass is calculated by dividing the mass of the substance by the number of moles of that substance, a smaller mass will result in a smaller calculated molar mass if the number of moles is not adjusted accordingly.
The molar mass (M) is given by:
[tex]\[ M = \frac{m}{n} \][/tex]
where m is the mass of the acid and n is the number of moles of the acid.
If the mass m is smaller due to spillage, and n remains the same (because the titre does not change), then the calculated molar mass M will be smaller.
II. The endpoint is recorded when the solution is dark red in color rather than light pink.
Phenolphthalein is a common acid-base indicator that is colorless in acidic solutions and pink in basic solutions.
The endpoint of the titration is reached when the solution changes from colorless to light pink, indicating that the acid has been neutralized by the NaOH.
If the endpoint is recorded when the solution is dark red, it means that the titration has continued past the true endpoint, adding excess NaOH.
This excess NaOH will not react with the acid (since it's already been neutralized), but it will be included in the calculation of the moles of NaOH used.
The number of moles of acid [tex](\( n_{acid} \))[/tex] is calculated using the moles of NaOH [tex](\( n_{NaOH} \))[/tex] used to reach the endpoint:
[tex]\[ n_{acid} = n_{NaOH} \][/tex]
If [tex]\( n_{NaOH} \)[/tex] is overestimated due to continuing the titration past the endpoint, then [tex]\( n_{acid} \)[/tex] will also be overestimated. Since the mass of the acid m remains unchanged, the calculated molar mass M will be smaller:
[tex]\[ M = \frac{m}{n_{acid}} \][/tex]
In conclusion, both spilling some of the acid and recording the endpoint too late will result in a calculated molar mass that is smaller than the actual molar mass of the carboxylic acid.
Which of the following theories provides information concerning both molecular shape and molecular bonding?
A. molecular orbital theory
B. VSEPR theory
C. quantum mechanical theory
D. Bohr atomic theory
(Not D )
Final answer:
The VSEPR theory provides information about molecular shape and bonding by predicting electron pairs' arrangement around central atoms in a molecule. So the correct option is B.
Explanation:
The theory that provides information about both molecular shape and molecular bonding is the valence-shell electron-pair repulsion (VSEPR) theory. The VSEPR theory predicts the arrangement of electron pairs around each central atom and usually the correct arrangement of atoms in a molecule. This theory considers electron-pair repulsions to determine the geometry of the molecule, which is essential for understanding molecular bonding and shape.
To reconcile the geometries of s, p, and d atomic orbitals with molecular shapes, we introduce the concept of hybrid orbitals. Hybridization is an extension of VSEPR theory and valence bond theory, providing a more complete understanding of how atomic orbitals combine to form the electronic structure of molecules.
the equation below shows the decomposition of lead nitrate. how many grams of oxygen are produced when 11.5g NO2 is formed?
2Pb(NO3)2(s) -> 2PbO(s) + 4NO2(g) + O2(g)
Answer: 2 g
Explanation: [tex]2Pb(NO_3)_2(s)\rightarrow 2PbO(s)+4NO_2(g)+O_2(g)[/tex]
As can be seen from the balanced chemical equation, 2 moles of lead nitrate produce 4 moles of nitrogen dioxide.
[tex]2\times 331.2g=662.4g[/tex] of lead nitrate produces [tex]4\times 46=184g[/tex] of nitrogen dioxide.
184 g of nitrogen dioxide will be produced by 662.4 g of lead nitrate
So 11.5 g of nitrogen dioxide will be produced by=[tex]\frac{662.4}{184}\times {11.5}=41.4 g[/tex] of lead nitrate
As can be seen from the balanced chemical equation, 2 moles of lead nitrate produce 1 mole of oxygen.
[tex]2\times 331.2g=662.4g[/tex] of lead nitrate produces 32 g of oxygen.
41.4 g of lead nitrate produces =[tex]\frac{32}{662.4}\times {41.4}=2g[/tex] of oxygen.
N the reactant side of the chemical equation, there are carbon atoms, hydrogen atoms, and oxygen atoms. In the product side of the chemical equation, there are carbon atoms, hydrogen atoms, and oxygen atoms. The number and kinds of atoms on both sides of the chemical equation are . So, this chemical equation is .
Answer: If the number and kinds of atoms on both sides of the chemical equation are same, the chemical equation is called as balanced chemical equation.
If the number and kinds of atoms on both sides of the chemical equation are different, the chemical equation is called as skeletal chemical equation.
[tex]CH_4+O_2\rightarrow CO_2+H_2O[/tex]
As the number of atoms on both sides of the chemical equation are different, the above equation represents a skeletal chemical equation.
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
As the chemical equations must follow the law of conservation of mass, the number of atoms on both sides of the above chemical equation must be same so as the mass is same on both sides of the equation. So the equation was balanced.
Answer:
In the reactant side of the chemical equation, there are 4 carbon atoms, 12 hydrogen atoms, and 14 oxygen atoms. In the product side of the chemical equation, there are 4 carbon atoms, 12 hydrogen atoms, and 14 oxygen atoms. The number and kinds of atoms on both sides of the chemical equation are the same . So, this chemical equation is balanced
Explanation:
The reactants have 4 carbon atoms, 14 oxygen atoms, and 12 hydrogen atoms. The product has the same numbers and kinds of atoms. So, the equation is balanced.
The following chemical equation describes the chemical reaction of hydrogen gas and oxygen gas to create water 2H2 + O2 = 2H2O Use what you know about molar relationships to explain how scientists can predict the amount of water produced if they know the amounts of hydrogen and oxygen gases they have to react.
Answer: [tex]2H_2+O_2\rightarrow 2H_2O[/tex]
The molar relationship says that every 1 mole of an element or compound weighs equal to its molecular weight.
As 1 mole of molecular hydrogen [tex]H_2[/tex] weighs 2 g.
2 moles of molecular hydrogen will weigh[tex]=\frac{2}{1}\times {2}=4g[/tex]
1 mole of molecular oxygen [tex]O_2[/tex] weighs 32 g
1 mole of water [tex] H_2O[/tex] weighs = 18g
2 moles of water [tex] H_2O[/tex] weigh=[tex]\frac{18}{1}\times {2}=36g[/tex]
As can be seen from the balanced chemical equation above, 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.
Thus 4g of [tex]H_2[/tex] combines with 32 g of [tex]O_2[/tex] to give 36 moles of [tex] H_2O[/tex].
The study of chemicals and bonds is called chemistry. There are different types of elements, and these are metals and nonmetals.
The correct answer is 36 mole
What is a mole?A standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.
According to the question, the 2 moles of water react with the mass of water:-
[tex]\frac{18}{1}*2 = 36g[/tex].
Hence, 36 g is used to react with hydrogen and oxygen.
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Which of the following describes the specific copper ion in the compound, CuS?
Cupride ion
Copper (I) ion
Copper (II) ion
Cupride (I) ion
In the equation: MgCl2 + Na3P --> write the chemical formula for the compound that will be formed that contains Mg
3MgCl2 + 2Na3P => Mg3P2 + 6NaCl
What is the net ionic equation for the reaction that is represented by the following total ionic equation?
Problem >>> Image 1
A. >>> Image 2
B. >>> Image 3
C. >>> Image 4
D. >>> Image 5
Answer:
B. >>> Image 3
Step-by-step explanation:
Ionic equation :
6Na⁺(aq) + 2PO₄³⁻(aq) + 3Ca²⁺(aq) + 6Cl⁻(aq) ⟶ 6Na⁺(aq) + 6Cl⁻(aq) + Ca₃(PO₄)₂(s)
=====
Net ionic equation:
Cancel all ions that appear on both sides of the reaction arrow (underlined).
6Na⁺(aq) + 2PO₄³⁻(aq) + 3Ca²⁺(aq) + 6Cl⁻(aq) ⟶ 6Na⁺(aq) + 6Cl⁻(aq) + Ca₃(PO₄)₂(s)
3Ca²⁺(aq) + 2PO₄³⁻(aq )⟶ Ca₃(PO₄)₂(s)
A. >>> Image 2 is wrong, because it is the molecular equation
C. >>> Image 4 is wrong, because it is not balanced.
D. >>> Image 5 is wrong, because the phosphate ion behaves as a unit. It does not break up into phosphorus and oxide ions.
Answer:
B is correct
Explanation:
Edge
Is it true that Organisms need water, vitamins and minerals. But they do not need salt to function.
When the products of a reaction have more energy than the reactants:
the reaction is exothermic
the reaction is endothermic
the reactants gave up energy
the H is positive
If an element in a chemical reaction loses electrons, which of the following describes what happens to that element?
A. It is combusted
B. It is reduced
C. It is rusted
D. It is oxidized
Answer : The correct option is, (D) it is oxidized.
Explanation :
On the basis of electrons, there are two types of reactions :
(1) Oxidation reaction (2) Reduction reaction
Oxidation reaction : When an element loses electrons in a chemical reaction then that element gets oxidized in the chemical reaction and its oxidation number increases.
Reduction reaction : When an element gains electrons in a chemical reaction then that element gets reduced in the chemical reaction and its oxidation number decreases.
Hence, the correct answer is (D).
A 110. ml solution of 0.340 m hcl(aq) is mixed with a solution of 330. ml of 0.150 m hno3(aq). the solution is then diluted to a final volume of 1.00 l. how many moles of h+ are present in the final solution?
The total number of moles of H+ in the mixed solution is 0.079 in the mixed volume of 0.4 L. Thus the number of moles in 1 l solution is 0.197.
What is molarity?Molarity of a solution is the ratio of number of moles to the volume of solution in liters. Molarity is a temperature dependant term. This is the most common concentration term.
Here, the number of moles in 110 ml of 0.340 M HCl is calculated as follows:
number of moles = molarity × volume
= 0.340 × 0.1 l
= 0.034 moles.
Number of moles in 330 ml of 0.15 m nitric acid is 0.3 × 0.15 = 0.045.
Total number of moles in the mixed solution = 0.034 + 0.045 = 0.079. This is the number of moles in the mixed solution of 0.4 L
Hence, the number of moles in 1 liter is 0.4 × 0.079 = 0.197 moles.
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What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, and 42.13% oxygen. The empirical formula is FeSO. Reset Next
Empirical Formula is Fe1S1O4
(the numbers are suppose to be subscript)
Answer: [tex]FeSO_4[/tex]
Solution : Given,
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of Fe = 36.76 g
Mass of S = 21.11 g
Mass of O = 42.13 g
Step 1 : convert given masses into moles.
Moles of Fe =[tex] \frac{\text{ given mass of Fe}}{\text{ molar mass of Fe}}= \frac{36.76g}{56g/mole}=0.65moles[/tex]
Moles of S = \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{21.11g}{32g/mole}=0.65moles
[/tex]
Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.13g}{16g/mole}=2.63[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Fe = [tex]\frac{0.65}{0.65}=1[/tex]
For S = [tex]\frac{0.65}{0.65}=1[/tex]
For O =[tex]\frac{2.63}{0.65}=4[/tex]
The ratio of Fe : S : O= 1 : 1 : 4
Hence the empirical formula is [tex]Fe_{1}S_{1}O_4[/tex]
list 2 extensive properties and 3 intensive properties of a 5.0g, 1 cm3 cube of silver
Properties of matter can be broadly classified into two categories:
Physical properties which usually involve a change in the state of matter and Chemical properties which involve a change in the chemical composition of matter.
Now, physical properties can be further classified as:
Extensive: these depend on the amount of the substance, eg: mass, volume
Intensive: these do not depend on the amount of the substance eg: density, color, melting point, boiling point
Here we are given a 5.0 g and 1 cm3 silver cube :
Therefore:
Extensive properties are-
1) Mass of silver = 5.0 g
2) Volume of silver = 1 cm3
Intensive properties are:
1) Density of silver = mass/volume = 5.0 g/ 1 cm3 = 5.0 g/cm3
2) Melting point of silver = 962 C
3) Color = white/gray
If a sample of pure silver (Ag) contains 3.35 x 1022 atoms of silver, how many moles of silver are in the sample?
A) 17.9 mol
B) 2.82 mol
C) 0.180 mol
D) 0.0556 mol
the answer is D 0.0556 mol
divide the given number of atoms 3.35x10^22 by 6.02x10^23 Avogadro's number(the number of atoms in one mol of anything) to get the total number of Moles. It's merely a fraction of a whole. 3.35/60.2 if you cancel out the tens. 1.0 mol mercury(the molar mass is the mass number on a periodic table) It couldn't possibly be so few atoms is to be gold or atoms of mercury as there are 6.02x10^23 atoms in a 0.0556 mol.
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Carbon monoxide is formed when fuels are burned:
with sulfur impurities
without enough oxygen
at high temperatures
that contain lead
Answer:
Without enough oxygen.
Step-by-step explanation:
In the presence of excess oxygen, the combustion of fuel produces carbon dioxide. For example, propane burns according to the equation
C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O
In the presence of a limited amount of oxygen, carbon monoxide is also formed.
C₃H₈ + ⁷/₂O₂ ⟶ 3CO + 4H₂O
The process is called incomplete combustion.
(a) is wrong. Sulfur impurities cause the formation of sulfur dioxide.
(c) is wrong. High temperatures usually lead to more complete combustion.
(d) is wrong. Lead compounds inhibit knocking in gasoline engines, but they do not affect the formation of carbon monoxide.
The reactants of two chemical equations are listed.
Equation 1: AgNO3 + Zn
Equation 2: AgNO3 + MgCl2
Based on the type of reaction, which reaction can be used to extract silver metal from silver nitrate solution?
Equation 1, because Zn being more reactive, replaces N from AgNO3
Equation 1, because Zn being more reactive, replaces Ag from AgNO3
Equation 2, because Mg being more reactive, exchanges position with Ag in AgNO3
Equation 2, because Mg being more reactive, exchanges position with N in AgNO3
Equation 1, because Zn being more reactive, replaces Ag from AgNO3
Zn being highly reactive can replace Ag from AgNO3 and produce Ag metal.
Equation 1: 2AgNO3(aq) + Zn(s) → 2Ag(s) + Zn(NO3)2
This equation is the right one to extract silver metal from silvernitrate solution as its single displacement reaction.
Answer:
Equation 1, because Zn being more reactive, replaces Ag from AgNO3
Explanation:
The preferential activity of one metal to displace the other in a chemical reaction can be deduced based on the reactivity or activity series.
The elements at the top of the series are highly reactive and can displace metals that fall below them. Both Zn and Mg appear above Ag in the reactivity series and can displace silver from silver nitrate.
1) AgNO3 + Zn → ZnNO3 + Ag
Metallic silver can be extracted through the above single displacement reaction.
2) 2AgNO3 + MgCl2 → 2AgCl + Mg(NO3)2
This is double displacement reaction which instead forms a precipitate of AgCl
Which formula below is the correct combination when nitrogen and hydrogen bond covalently? A. N3H B. NH3 C. NH2 D. NH
N and H covalently bond to form the correct formula NH3.
A. N3H
B. NH3
C. NH2
D. NH
Balance the equation with the correct coefficients __KCIO3 -> __KCI + ___O2
Answer: The balanced chemical reactions:
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
Explanation:
[tex]aKClO_3\rightarrow bKCl+cO_2[/tex]
The given reaction is an unbalanced reaction
Let 'a','b' and 'c' be the coefficient of [tex]KClO_3, KCl \text{ and } O_2[/tex] respectively.
So, in order to balance this given chemical equation:
a = 2, b = 2, c = 3
[tex]2KClO_3\rightarrow 2KCl+3O_2[/tex]
Answer:
2
2
3
in that order
Explanation:
Determine the value for the following reaction.
2HI(g) + 2.4 kcal → H2(g) + l2(g)
ΔH = _____
2.4 kcal
-2.4 kcal
0.0024 kcal
-0.0024 kcal
Answer:
ΔH = + 2.4 kcal
Step-by-step explanation:
2HI(g) + 2.4 kcal ⇌ H₂(g) + I₂(g)
Energy is on the left-hand side of the equation, so it is being absorbed by the system.
The thermodynamic convention is that energy going into a system is positive. Thus,
ΔH = + 2.4 kcal
Answer: 2.4 kcal
Explanation:
Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and [tex]\Delta H[/tex] for the reaction comes out to be positive.
For the given reaction:
[tex]2HI+2.4kcal\rightarrow H_2(g)+I_2(g)[/tex]
Enthalpy change is the net heat absorbed or released during a chemical reaction.
As heat is added to reactants, energy is being absorbed and thus enthalpy for the reaction will be positive and the value will be +2.4 kcal.