Answer:
[tex]\boxed{\text{2700 J}}[/tex]
Explanation:
HCl + NaOH ⟶ NaCl + H₂O
There are two energy flows in this reaction.
Heat of reaction + heat to warm water = 0
q₁ + q₂ = 0
q₁ + mCΔT = 0
Data:
m(HCl) = 50 g
m(NaOH) = 50 g
T₁ = 22 °C
T₂ = 28.87 °C
C = 4.18 J·°C⁻¹g⁻¹
Calculations:
m = 50 + 50 = 100 g
ΔT = 28.87 – 22 = 6.9 °C
q₂ = 100 × 4.18 × 6.9 = 2900 J
q₁ + 2900 = 0
q₁ = -2900 J
The negative sign tells us that the reaction produced heat.
The reaction produced [tex]\boxed{\textbf{2900 J}}[/tex].
The reaction between HCl and NaOH in the situation described produced 2.87 kJ of heat.
Explanation:The question is asking how much heat is produced by the reaction between 1.00 M hydrochloric acid (HCl) and 1.00 M sodium hydroxide (NaOH) in a coffee cup calorimeter when the initial temperature is 22ºC and the final temperature is 28.87ºC. The heat released in a chemical reaction can be calculated from the formula q = mcΔT, where q is heat, m is mass, c is specific heat, and ΔT is the change in temperature. In this case, the mass of the solution is 100g (50g HCl + 50g NaOH), the specific heat of the solution is given as 4.18 J/gºC, and the change in temperature is 28.87ºC - 22ºC = 6.87ºC.
Applying the numbers in the formula we get:
q = 100g * 4.18 J/gºC * 6.87ºC = 2872.6 J
Since the question requires the answer in kJ, we divide the result by 1000: Q = 2.87 kJ. The reaction between HCl and NaOH in the calorimeter produced 2.87 kJ of heat.
Learn more about Heat of Reaction here:https://brainly.com/question/30464598
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Why does alkali elements react vigorously with water?
Answer:
Explanation:
Because the alkali metal is really willing to give up its electron much more so than Hydrogen.
The redox reaction looks like this
K ===> K+ + 1 e- The reduction vo is very high which means that the K really does want to give up that electron.
2H+ +2e- ====> H2 The oxidation vo is almost 0 but the Hydrogen is the perfect recipient for the 2 electrons.