When a system is heated, heat is _______________ by the system. The amount of heat added is given a _______________ sign. When a system is cooled, heat is _______________ by the system. The amount of heat is given a _______________ sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done _______________ the system and is given a _______________ sign. If a gas is compressed, then work is done _______________ the system. This work is given a _______________ sign.

The position compared to that of home is a reference to displacement, I believe.

Displacement = x total - x initial

So I believe the answer is 5 blocks due north (if you’re walking linearly from your home), unless the questions is referring to relative displacement, in which then you’d need to use the Pythagorean theorem to find the hypotenuse between both positions. And then you’d have to find theta for the degrees between the south direction and the other unmentioned direction. But I don’t think that’s the case.

Distance refers to x total and doesn’t care for direction, as this refers to a scalar quantity opposed to a vector. Thus the equation is just

d = x

So 8 blocks + 3 blocks = a distance of eleven blocks walked total

Given in the question,

mass of foul ball = 0.140 kg

initial speed with which ball was hit with the bat = 30 m/s

final speed  = 40 m/s

According to the scenario the whole scene is making a right angle triangle

So, to the solve the question we will use pythagorus theorem

Here,

Hypotenuse= Magnitude of impulse

Base = 1st change of momentum

height = 2nd change of momentum

1st impulse (1st change of momentum)

p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s

2nd impulse (2nd change of momentum)

p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s

Magnitude of impulse (hypotenuse of triangle)

impulse² = (5.6)² + (4.2)²

impulse² = 31.36 + 17.64

impulse² = 49

impulse² = √49

impulse = 7.0 N s

The magnitude of the impulse delivered to the baseball by applying the impulse-momentum theorem is calculated to be 9.8 kg.m/s.

The magnitude of the impulse delivered to the baseball can be found by applying the impulse-momentum theorem. The theorem asserts that the change in momentum of an object equals the impulse imposed on it. In the context of this question, the momentum change is the final momentum minus the initial one (m*(vf) - m*(vi)). This equals 0.140 Kg * 30.0 m/s - (-0.140 Kg * 40.0 m/s). Calculating this we get 9.8 kg.m/s as the magnitude of the impulse delivered to the baseball.

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The answer would be B) Bulk.

I'm not completely sure what you mean by his "trip".

You've described three trips that day:

==> from home to school

==> from school to the club, and

==> from the club to home.  

You also clearly listed the distance for each of those trips, so I don't think that's what you're asking.

I think you're asking about Jorge's total distance for the day, after he finished all three trips.

That distance is (5mi + 1mi + 6mi)  =  12 miles. (choice-D)

The axis of the Earth's rotation is tilted relative to the plain of the Earth's revolution around the Sun.

The question is worded very poorly, but you'd have to say it's TRUE.  

True. The tilt of the axis is what leads to varying seasons around the year.

A) 1.55

The speed of light in a medium is given by:

[tex]v=\frac{c}{n}[/tex]

where

[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

[tex]v=1.94\cdot 10^8 m/s[/tex]

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

[tex]n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55[/tex]

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

[tex]\lambda=\frac{\lambda_0}{n}[/tex]

where

[tex]\lambda[/tex] is the wavelenght in quartz

[tex]\lambda_0[/tex] is the wavelength in air

n is the refractive index

For the light in this problem, we have

[tex]\lambda=355 nm\\n=1.55[/tex]

Therefore, we can re-arrange the equation to find [tex]\lambda_0[/tex], the wavelength in air:

[tex]\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm[/tex]

Final answer:

The index of refraction of quartz at the given wavelength is approximately 1.55. The wavelength of the same light in air would be approximately 549 nm.

Explanation:

Part A: Index of Refraction of Quartz

The index of refraction (n) is given by the formula n = c/v, where c is the speed of light in a vacuum, and v is the speed of light in the material. Here, we are given the speed of light in a quartz (v_quartz) as 1.94×108 m/s. Using the speed of light in a vacuum (c) as 3.00×108 m/s, we can calculate the index of refraction of quartz as follows:

n_quartz = c / v_quartz
n_quartz = (3.00×108 m/s) / (1.94×108 m/s)
n_quartz = 1.55

Part B: Wavelength in Air

Since the frequency of light remains constant when transitioning between mediums, its wavelength in air (λ_air) can be found using the same frequency. Using the formula λ = v/f, where v_air is the speed of light in air and f is the frequency, we get:

λ_air = c / f
Since c = v_air and n_quartz = c / v_quartz,
we can write
f = v_quartz / λ_quartz

Now, plug the value of f back into the first equation:

λ_air = v_air / (v_quartz / λ_quartz)
λ_air = (3.00×108 m/s) / (1.94×108 m/s) × 355 nm
λ_air ≈ 549 nm

Solid

Answer: Solid

Explanation:

because solids particles close together making it harder for them to move.

there is no motion in the direction of the force, then no work is done by that force. ... But the work done on the box is zero since by moving in a straight line at constant speed, its energy is remaining the same.

Work can be performed on a system without observable motion. An example of this is potential energy, where work is spent to change an object's state even if it doesn't result in movement. However, in general physics, work is defined as force multiplied by displacement.

Yes, work can be done on a system even if there is no observable motion. This is often the case when an object is experiencing balanced forces, meaning it remains static or in a state of Static Equilibrium. For instance, if you push a wall, you are exerting energy and doing 'work' but since the wall doesn't move, there is no physical work done.

Another example is potential energy, which is considered as 'stored energy'. It can be associated with the work done to change the position or state of an object, like stretching a spring or lifting a boulder; in these cases work is done even if there isn't resultant motion.

However, in physics, work is technically defined as the product of the force applied to an object and the distance over which that force is applied. Thus, if there is no movement or displacement, then no work is done according to the work-energy theorem. So, defining 'work' might be dependent on the context or specifics of a given problem.

Learn more about Work here:

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(a) 263 nm

First of all, let's convert the work function for silver from eV to Joules:

[tex]\phi = 4.73 eV \cdot (1.6\cdot 10^{-19} J/eV)=7.57\cdot 10^{-19} J[/tex]

The energy of the incoming photon is given by:

[tex]E=\frac{hc}{\lambda}[/tex]

where h is the Planck constant, c is the speed of light, [tex]\lambda[/tex] is the photon's wavelength.

The cutoff wavelength is the minimum wavelength for which the photon has enough energy to extract the photoelectron from the material: that means, the wavelength at which the energy of the photon is at least equal to the work function of the material,

[tex]E=\phi[/tex]

Substituting and solving for the wavelength,

[tex]\frac{hc}{\lambda}=\phi\\\lambda=\frac{hc}{\phi}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{7.57\cdot 10^{-19} J}=2.63\cdot 10^{-7} m = 263 nm[/tex]

(b) [tex]1.14\cdot 10^{15}Hz[/tex]

The lowest frequency of light incident on silver that releases photoelectrons from its surface is the frequency corresponding to the wavelength we found at point (a); using the relationship between frequency and wavelength:

[tex]f = \frac{c}{\lambda}[/tex]

And substituting numbers, we find

[tex]f = \frac{3\cdot 10^8 m/s}{2.63\cdot 10^{-7} m}=1.14\cdot 10^{15}Hz[/tex]

(c) 1.68 eV

The equation for the photoelectric effect is:

[tex]E=\phi + K_{max}[/tex]

where

E is the energy of the incoming photon

[tex]\phi[/tex] is the work function

[tex]K_max[/tex] is the maximum kinetic energy of the photoelectrons

Since

E = 6.41 eV

[tex]\phi = 4.73 eV[/tex]

The maximum kinetic energy of the photoelectrons is

[tex]K_{max}=E-\phi=6.41 eV-4.73 eV=1.68 eV[/tex]

B. trail mix

because you can easily take all the peaces out unlike water you cant physically take the oxygen out

please make me the brainliest

Answer: True

Explanation:

Participating in team sports can lead to the development of healthy fellowship and brotherhood behavior among the participants. It induces team spirit and allows to lead a healthy competition. It can be a good recreational activity which can be used for removing the emotional and physiological stress. Hence, can improve positivity in all aspects of life.

It becomes a positive ion

The correct answer is - c. escape.

The word ''escape'' means to get away from something. This word can be used for multiple different situations, and it can refer to both physical and psychological matters.

In a physical sense it can be used to escape from certain unpleasant, or dangerous situation. Example: I have to escape from this prison.

In a psychological sense it can be used to escape, move away, from a certain state of mind. Example: I have to find an escape from my depressive thoughts.

Answer:

i have no clue

Explanation:

What type of heat transfer occurs when particles bump into each other?

A.Convection

B.Insulation

C.Thermal Conduction

D.Thermal Radiation

Thermal conduction.

The particles bump into nearby particles and make them vibrate more which passes through the substance from the hot end to the cold end

Entropy is the measure of the disorder of a system and is a function of state. That is, it depends only on the state of the system.

In this sense, in the gaseous state is where the greatest entropy occurs, since in a gas the particles acquire greater freedom and kinetic energy to move.

Another aspect that influences the increase in entropy is the increase in temperature. This is because, when raising the temperature, the kinetic energy of the molecules, atoms or ions increases, and, therefore, they move more.

Answer:

Number of protons = Number of electrons

Protons = positively charged atoms

Electrons = negatively charged atom

Neutrons = no charge atoms

The number of protons = electrons because the charge can cancel themselves out

Number of electrons = Determines boiling/ melting point

Lots of electrons = High boiling/ melting point

Low number of electrons = low boiling/ melting point

Explanation:

On 1930 the astronomer Edwin Hubble classified the galaxies into elliptical, spiral and irregular, being the first two classes the most frequent.  

However, it should be noted that this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.  

The classification is as follows:  

Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.  

They are symbolized by the letter E and subdivided into eight classes, from E0 with zero eccentricity (spherical) to E7 (called husiform).  

They have the shape of flattened disks containing some old stars and also a large population of young stars, enough gas and dust, and molecular clouds that are the birthplace of the stars.  

They are symbolized with the letter S and depending on the minor or major development that each arm possesses, it is assigned a letter: a, b or c (for example: Sa, Sb, Sc, SBa, SBb, SBc).  

These galaxies, are also divided into two types:  

-Lenticular galaxies  

-Barred spiral galaxies

They are symbolized by the letter I (or IR), although they are usually dwarf or rare and do not have well-defined structure and symmetry.  

They are classified in:  

-Irregular type 1 (Magellanic), which contain large numbers of young stars and interstellar matter.  

-Regular type 2, less frequent and whose content is difficult to identify.  

This type of irregular galaxies are generally located close to larger galaxies, and usually contain large amounts of young stars, gas and cosmic dust.

Nuclei outside the band of stability undergo radioactive decay, transforming into more stable isotopes. Instability does not necessarily mean rapid decay, as exemplified by uranium-238. Unstable nuclides like those experiencing beta decay transform into other elements or isotopes through the process of radioactive transformation.

Nuclei that lie outside the band of stability undergo spontaneous radioactive decay. These unstable nuclei that are to the left or to the right of the band on the chart of nuclides will transform into other nuclei that are in, or closer to, a state of stability. This decay changes the number of protons and neutrons in the nucleus, resulting in a different element or isotope that is more stable.

It's important to note that being "unstable" does not necessarily imply a substance will decay quickly. For instance, uranium-238 is a prime example of an unstable nucleus due to its ability to decay over a stretched period; while it is unstable, it does not instantly decompose.

All forms of beta decay are a consequence of the parent nuclide's instability, leading to a transformation that results in a subsequent product of decay. Terms like "radioactive transformation" may be more accurate than "decay," since the process involves the original nucleus splitting into new nuclei rather than vanishing entirely.

Answer:

a) When fast particles rise to the top.

Explanation:

Heat is a form of energy that can be studied through the thermal agitation of the molecules that a material involves. When heat is delivered to a body, its temperature increases, the mobility of its molecules increases. In this way, the system is not in thermal equilibrium: the temperature at each point of the body is different and the variations over time.

There are three forms of heat transmission: conduction, convection and radiation. In conduction, heat is transferred only because of molecular movement and shocks between fast and slow molecules, without displacement of matter. Convection is due to the global movement of matter and is only important in liquids and gases. Radiation is an electromagnetic interaction between bodies and does not require the existence of a material means to transmit heat from one to another. The conduction of heat in a medium can be more or less favorable according to the material.

when the average speed of particles is the same throughout the liquid

Explanation:

its a i just have to type more but its a

The answer is B) 2 times what it is now.

is there any multiple choice answers

Answer:

e) 0.099

Explanation:

For an adiabatic expansion:

[tex]P_1 V_1^{\gamma} = P_2 V_2^{\gamma}[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

[tex]\gamma[/tex] is the adiabatic index (which is [tex]\frac{5}{3}[/tex] for an ideal monoatomic gas

In this problem, we have

[tex]V_2 = 4 V_1[/tex] since the volume increases by a factor 4

We can re-write the equation to find by what factor the pressure changes:

[tex]\frac{P_2}{P_1}=(\frac{V_1}{V_2})^{\gamma}=(\frac{V_1}{4V_1})^{5/3}=(\frac{1}{4})^{5/3}=0.099[/tex]

Answer:

Airplane wings must be designed to ensure that air molecules move more rapidly over the top surface of the wing, creating a region of lower pressure.

Explanation:

Answer:

Airplane wings must be designed to ensure that air molecules move more rapidly over the top surface of the wing, creating a region of lower pressure.

Explanation:

Swiss physicist Daniel Bernoulli proposed a principle for fluid flow, which can be stated as follows: "If the speed of a fluid particle increases as it flows along a current line, the fluid pressure must decrease and vice versa".

This knowledge allows us to understand why airplanes are able to fly. In the upper part of the wing the air velocity is higher (the particles travel a greater distance at the same time), therefore, the pressure on the upper surface is less than on the lower surface, which ends up creating a holding force from below to up.

With this principle, we can say that the wings of the airplane must be designed to ensure that air molecules move more quickly over the upper surface of the wing, creating a region of less pressure.

Answer:

The volume charge density of the sphere is [tex]7.64\times 10^{-4}\ C/m^3[/tex].

Explanation:

It is given that,

Charge, [tex]q=6.3\times 10^{-8}\ C[/tex]

Radius of the sphere, r = 2.7 cm = 0.027 m

Total charge contained divided by its volume is called volume charge density. Mathematically, it is given by :

[tex]\rho=\dfrac{Q}{V}[/tex]

[tex]\rho=\dfrac{Q}{4/3\pi r^3}[/tex]

[tex]\rho=\dfrac{6.3\times 10^{-8}}{4/3\pi (0.027)^3}[/tex]

[tex]\rho=7.64\times 10^{-4}\ C/m^3[/tex]

So, the volume charge density of the sphere is [tex]7.64\times 10^{-4}\ C/m^3[/tex]. Hence, this is the required solution.

(a) [tex]5.45\cdot 10^{-4} m^2[/tex]

According to Pascal's principle, the pressure on the first piston is equal to the pressure on the second piston:

[tex]p_1 = p_2\\\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex] (1)

where

F1 = 250 N is the input force

A1 = ? is the area of the input piston

F2 is the output force

A2 is the area of the output piston

The output force is just the weight of the car:

[tex]F_2 = mg =(1170 kg)(9.8 m/s^2)=11,466 N[/tex]

The radius of the output piston is half the diameter: [tex]r=d/2=18 cm/2 = 9 cm =0.09 m[/tex], so its area is

[tex]A_2 = \pi r^2 = \pi (0.09 m)^2=0.025 m^2[/tex]

So we can solve eq.(1) for A1, the area of the first piston:

[tex]A_1 = A_2 \frac{F_1}{F_2}=(0.025 m^2)\frac{250 N}{11,466 N}=5.45\cdot 10^{-4} m^2[/tex]

(b) 1491 J

The work done in lifting the car 13 cm is equal to the gravitational potential energy gained by the car:

[tex]W=\Delta U=mg \Delta h[/tex]

where:

m = 1170 kg is the mass of the car

g = 9.8 m/s^2

[tex]\Delta h=13 cm=0.13 m[/tex] is the increase in height of the car

Substituting,

[tex]W=\Delta U=(1170 kg)(9.8 m/s^2)(0.13 m)=1491 J[/tex]

(c) 0.0028 m

Assuming the machine is 100% efficient and there is no waste of energy, the input work is equal to the output work:

[tex]W_i = W_o\\F_1 d_1 = F_2 d_2[/tex]

where

F1 = 250 N is the input force

d1 = 13 cm = 0.13 m is the displacement of the input piston

F2 = 11,466 N is the output force (the weight of the car)

d2 is the displacement of the output piston

Solving for d2,

[tex]d_2 =d_1 \frac{F_1}{F_2}=(0.13 m)\frac{250 N}{11466 N}=0.0028 m[/tex]

(d) 46 strokes

In order to lift the car up 13 cm (0.13 m), we have to divide this value by the displacement of the car for each stroke, so we have:

[tex]n=\frac{0.13 m}{0.0028 m}=46.4 \sim 46[/tex]

(e) 1491 J

The work done during all of the strokes is equal to the gravitational potential energy gained by the car while being lifted 13 cm, so it is equal to the value found in part b):

W = 1491 J

The conservation laws of energy, momentum, and kinetic energy are used to determine pre-collision and post-collision velocities of two balls, as well as their maximum heights after an elastic collision.

The student has asked about the velocities of two balls before and after an elastic collision and the maximum height they reach after the collision. Assuming no air resistance, the conservation of energy principle can be used to find the initial velocity of the lighter ball by equating potential energy at 60° to kinetic energy at the point just before impact.

Afterward, the conservation of momentum and kinetic energy can be used to determine the velocities of both balls post-collision. The final velocities can then be used with the conservation of energy again to find the maximum height each ball reaches after the elastic collision.

It's important to remember that, for an elastic collision, both conservation of momentum and conservation of kinetic energy hold true. So, the total kinetic energy before and after the collision remains constant, as well as the total momentum of the system. Applying these laws yields the final velocities for each mass, and subsequently, energy conservation can determine the maximum heights.

Entropy generation in an ideal Brayton cycle is zero since all processes are reversible and there are no irreversibilities within the system to generate entropy.

The student's question relates to finding the rate of entropy generation for an ideal Brayton cycle using argon as the working fluid. However, the Brayton cycle, as an ideal cycle, does not lead to entropy generation within the system because all processes are reversible. Entropy may change as heat crosses the system boundaries, but this is not the same as entropy generation due to irreversibilities. Calculating entropy changes in an actual Brayton cycle requires knowledge of each process's irreversibilities, which cannot be determined without additional data on the components' efficiencies and the specific entropy values of argon at the given states. Further calculations for ideal processes can be simplified using the assumption of adiabatic and isentropic compression and expansion.

From the information given about the topic I would say that the molecules will move more quickly.

The molecules will move more slowly

Answer:

Visible light

X rays

ultraviolet radiation

gamma rays

microwave radiation

Explanation:

Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves have all same speed in a vacuum ([tex]c=3.0\cdot 10^8 m/s[/tex], known as speed of light) and are classified into 7 different types according to their frequency and wavelength. This classification is called electromagnetic spectrum.

From lowest to highest wavelength, the 7 types are:

Gamma rays

X-rays

Ultraviolet radiation

Visible light

Infrared radiation

Microwaves

Radio waves

Sound waves, on the contrary, do not belong to the electromagnetic spectrum, since they are another type of wave called mechanical waves (which consist of vibrations of the particles in a medium).