When working properly, a machine that is used to makes chips for calculators does not produce more than 4% defective chips. Whenever the machine produces more than 4% defective chips, it needs an adjustment. To check if the machine is working properly, the quality control department at the company often takes samples of chips and inspects them to determine if they are good or defective. One such random sample of 200 chips taken recently from the production line contained 12 defective chips. Find the p-value to test the hypothesis whether or not the machine needs an adjustment. What would your conclusion be if the significance level is 2.5%

Answers

Answer 1

Answer:

The proportion of defective chips produced by the machine is more than 4% so the machine needs an adjustment.

Step-by-step explanation:

In this case we need to test whether the proportion of defective chips produced by the machine is more than 4%.

The hypothesis can be defined as follows:

H₀: The proportion of defective chips produced by the machine is not more than 4%, i.e. p ≤ 0.04.

Hₐ: The proportion of defective chips produced by the machine is more than 4%, i.e. p > 0.04.

The information provided is:

X = 12

n = 200

α = 0.025

The sample proportion of defective chips is:

[tex]\hat p=\frac{X}{n}\\\\=\frac{12}{200}\\\\=0.06[/tex]

Compute the test statistic as follows:

[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}\\\\=\frac{0.06-0.04}{\sqrt{\frac{0.04(1-0.04)}{200}}}\\\\=1.44[/tex]

The test statistic value is 1.44.

Decision rule:

We reject a hypothesis if the p-value of a statistic is lower than the level of significance α.

Compute the p-value of the test:

[tex]p-value=P(Z>1.44)\\=1-P(Z<1.44)\\=1-0.92507\\=0.07493\\\approx 0.075[/tex]

The p-value of the test is 0.075.

p-value = 0.075 > α = 0.025

The null hypothesis was failed to be rejected at 2.5% level of significance.

Thus, it can be concluded that the proportion of defective chips produced by the machine is more than 4% so the machine needs an adjustment.

Answer 2
Final answer:

To test the hypothesis whether or not the machine needs an adjustment, we can use a one-sample proportion test. Calculate the sample proportion, the standard error of the proportion, and the test statistic. Find the p-value and compare it to the significance level to make a conclusion.

Explanation:

To test the hypothesis whether or not the machine needs an adjustment, we can use a hypothesis test. The null hypothesis (H0) is that the machine is working properly and the alternative hypothesis (Ha) is that the machine needs an adjustment. We can use a one-sample proportion test since we are testing the proportion of defective chips.

Calculate the sample proportion, which is the number of defective chips divided by the sample size: p-hat = 12/200 = 0.06.Calculate the standard error of the proportion: SE = sqrt((p-hat * (1 - p-hat)) / n) = sqrt((0.06 * 0.94) / 200) = 0.0212.Calculate the test statistic, which is the difference between the sample proportion and the hypothesized proportion divided by the standard error: z = (p-hat - p) / SE = (0.06 - 0.04) / 0.0212 = 0.9434.Find the p-value associated with the test statistic using a standard normal distribution table or a calculator. In this case, the p-value is the probability of observing a test statistic as extreme as 0.9434 or more extreme if the null hypothesis is true.

If the p-value is less than the significance level (2.5%), we reject the null hypothesis and conclude that the machine needs an adjustment. If the p-value is greater than or equal to the significance level, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the machine needs an adjustment.

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Related Questions

A chef got 17 bags of onions. The red onions came in bags of 4 and the yellow onions came in bags of 6. If the chef got a total of 88 onions, how many bags of each type of onion did he get?

Answers

Answer:

7 bags red onions

10 bags yellow onions

Step-by-step explanation:

If r is the number of bags of red onions, and y is the number of bags of yellow onions, then:

r + y = 17

4r + 6y = 88

Solve the system of equations using substitution or elimination.  Using substitution:

r = 17 − y

4(17 − y) + 6y = 88

68 − 4y + 6y = 88

2y = 20

y = 10

r = 7

The chef received 5 bags of red onions and 12 bags of yellow onions.

The question involves solving a system of linear equations to find the number of bags of red onions and yellow onions the chef received. Let's denote the number of bags of red onions as R and the number of bags of yellow onions as Y. We know that:

Each bag of red onions contains 4 onions.

Each bag of yellow onions contains 6 onions.

The chef got a total of 17 bags.

The chef got a total of 88 onions.

Based on this information, we can set up the following equations:

R + Y = 17
(This represents the total number of bags.)

4R + 6Y = 88
(This represents the total number of onions.)

We can solve this system of equations using substitution or elimination. Let's use substitution. First, we can express Y as 17 - R from the first equation:

Y = 17 - R

Now, we substitute Y in the second equation:

4R + 6(17 - R) = 88

By solving this equation, we find that R = 5 and Y = 12. Therefore, the chef got 5 bags of red onions and 12 bags of yellow onions.

A private and a public university are located in the same city. For the private university, 1042 alumni were surveyed and 655 said that they attended at least one class reunion. For the public university, 796 out of 1318 sampled alumni claimed they have attended at least one class reunion. Is the difference in the sample proportions statistically significant? (Use α=0.05)

Answers

Answer:

The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that the proportion of alumni that assist to at least a one class reunion is different for privates university and public university (p-value=0.222).  

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of alumni that assist to at least a one class reunion is different for privates university and public university.  

Then, the null and alternative hypothesis are:

[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0[/tex]

where π1: proportion of private university alunmi that have attended at least one class reunion, and π2: proportion of public university alunmi that have attended at least one class reunion.

The significance level is 0.05.

The sample 1 (private), of size n1=1042 has a proportion of p1=0.6286.

[tex]p_1=X_1/n_1=655/1042=0.6286[/tex]

The sample 2 (public), of size n2=1318 has a proportion of p2=0.6039.

[tex]p_2=X_2/n_2=796/1318=0.6039[/tex]

The difference between proportions is (p1-p2)=0.0247.

[tex]p_d=p_1-p_2=0.6286-0.6039=0.0247[/tex]

The pooled proportion, needed to calculate the standard error, is:

[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{655+796}{1042+1318}=\dfrac{1451}{2360}=0.6148[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.6148*0.3852}{1042}+\dfrac{0.6148*0.3852}{1318}}\\\\\\s_{p1-p2}=\sqrt{0.00023+0.00018}=\sqrt{0.00041}=0.0202[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0247-0}{0.0202}=\dfrac{0.0247}{0.0202}=1.222[/tex]

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

[tex]P-value=2\cdot P(t>1.222)=0.222[/tex]

As the P-value (0.222) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that the proportion of alumni that assist to at least a one class reunion is different for privates university and public university.  

Final answer:

To determine if the difference in sample proportions is statistically significant, we can perform a hypothesis test.

Explanation:

To determine if the difference in sample proportions is statistically significant, we can perform a hypothesis test.

First, we need to state the hypotheses. The null hypothesis (H0) is that there is no difference in the proportions, and the alternative hypothesis (Ha) is that there is a difference in the proportions.Next, we can calculate the standard error of the difference in sample proportions using the formulas:  [tex]SE_{\text{diff}} = \sqrt{\left(\frac{p_1(1-p_1)}{n_1}\right) + \left(\frac{p_2(1-p_2)}{n_2}\right)}[/tex]where p1 and p2 are the sample proportions and n1 and n2 are the sample sizes.Then, we can calculate the test statistic using the formula: test_statistic = (p1 - p2) / SE_diffFinally, we can compare the test statistic to the critical value from the standard normal distribution to determine if the difference in sample proportions is statistically significant.

In this case, the test statistic is calculated as [tex]\frac{\frac{655}{1042} - \frac{796}{1318}}{\sqrt{\frac{655}{1042}\left(1 - \frac{655}{1042}\right)/1042 + \frac{796}{1318}\left(1 - \frac{796}{1318}\right)/1318}}[/tex]  By comparing the test statistic to the critical value at a significance level of 0.05, we can determine if the difference in sample proportions is statistically significant.

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The graph for the equation y = x minus 4 is shown below.

On a coordinate plane, a line goes through (0, negative 4) and (4, 0).

Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions?
y minus x = negative 4
y minus x = negative 2
y minus 4 = x
y + 4 x = 1

Answers

Answer:

The answer is y minus x = negative 4

Step-by-step explanation:

What is the quotient? Will give brainliest and will report absurd answers.

Answers

Answer:

D

Step-by-step explanation:

When dividing fractions, multiply the first number by the reciprocal of the second number

2/5 ÷ 1/3

First, find the reciprocal of the second number: 1/3

To find the reciprocal, flip the numerator (top number) and denominator (bottom number)

1/3-->3/1

Now, multiply 2/5 and 3/1

2/5 * 3/1

Multiply across the numerators and denominators

6/5

The perimeter of a triangle DEF is 81 units. The length of side DE is twice the length of side EF, and the length of side DF is 4 units less than the length of side DE. Let s represent the length, in units, of side EF. Write an equation that can be used to find s

Answers

Answer:

5s = 85

Step-by-step explanation:

Perimeter of our triangle = DE + EF + DF = 81 units

We know from the question that

The length of side DE is twice the length of side EF

DE = 2EF

and the length of side DF is 4 units less than the length of side DE

DF = DE - 4

We can replace EF with s in our equations

DE = 2s

And now we can replace DE from the other equation

DF = DE - 4

DF = 2s - 4

If the perimeter of our triangle = DE + EF + DF = 81 units

We will replace the sides with our new values

Perimeter = 2s + s + 2s - 4 = 81

We can put this as our answer, or we can simplify further

Simplify by adding 4 to both sides

2s + s + 2s - 4 + 4 = 81 + 4

Simplify

2s + s + 2s = 85

Simplify

5s = 85

Since the question only asked for an equation, not for us to solve it, we can stop here

(If you wanted to solve for s, just divide both sides by 5)

5s / 5 = 85 / 5

s = 17

Answer:

81 = s + 2s + (2s -4)

Step-by-step explanation:

Which two temperatures have a 0 degrees Celsius?

Answers

0°F in 0°C both of them is 0

You are dealt one card from a standard​ 52-card deck. Find the probability of being dealt a card greater than 2 and less than 5. The probability of being dealt a card greater than 2 and less than 5 is........

Answers

Final answer:

The probability of being dealt a card greater than 2 and less than 5 from a standard deck of 52 cards is 2/13.

Explanation:

The probability of being dealt a card greater than 2 and less than 5 from a standard 52-card deck means you are looking for 3s and 4s from each suit (hearts, spades, clubs, diamonds).

For each suit, there is one 3 and one 4, making a total of 8 possible cards (2 cards per suit multiplied by 4 suits). To calculate the probability, you divide the number of favorable outcomes by the number of possible outcomes. So, this probability is 8/52, which simplifies to 2/13 when reduced.

A 40% antifreeze solution is to be mixed with a 70% antifreeze solution to get 240 liters of a 64% solution. How many liters of the 40% and how many liters of the 70% solutions will be used?

Answers

Answer:

We have 40% antifreeze and 70% antifreeze and we need to make 240 liters of 64% antifreeze.

We set up 2 equations where "f" is the 40 % and "s" is the 70%

A) f + s = 240

B) .40f + .70s = (.64 * 240) (or 153.6)

To solve both equations we multiply A) by -.40

A) -.40 f  - .40 s = -96.00   then we add this to B)

B) .40f + .70s = 153.60

.30s = 57.6

s = 192

f = 48

48 liters of 40% = 19.20 liters of antifreeze

192 liters of  70% = 134.40 liters of antifreeze

That equals 153.60 liters of antifreeze in a TOTAL liquid amount of 240 liters.

Double Check

153.60 / 240 = 64% antifreeze.

Step-by-step explanation:

Let f(x)=(3)x−3. Evaluate f(0) without using a calculator.

Answers

Final answer:

To evaluate f(0) without using a calculator, simply substitute x with 0 in the function f(x) = 3x - 3 to get f(0) = -3.

Explanation:

A mathematical function is a relationship between a set of inputs (domain) and corresponding outputs (range) such that each input is associated with exactly one output. It is a rule or process that assigns a unique value to each input. Functions are fundamental in expressing and analyzing mathematical relationships.

To evaluate f(0) without using a calculator, we can simply replace x with 0 in the given function f(x) = 3x - 3.

Therefore, f(0) = 3(0) - 3 = 0 - 3 = -3.

So, f(0) = -3.

An English teacher needs to pick 9 books to put on his reading list for the next school year, and he needs to plan the order in which they should be read. He has narrowed down his choices to 19 novels, 22 plays, and 22 nonfiction books. If he wants to include an equal number of novels, plays, and nonfiction books, how many different reading schedules are possible? Express your answer in scientific notation rounding to the hundredths place.

Answers

Answer:

The total number of reading schedules is [tex]83.3927415552\cdot 10^{13}[/tex]

Step-by-step explanation:

Recall that if we have n elements, the number of ways in which we can choose k elements without minding the order is [tex]\binom{n}{k}=\frac{n!}{(n-k)! k!}[/tex].

At first, suppose that we have already chosen 9 books. If we want to number the order in which we are reading this books from 1 to 9, for position 1 we have 9 options, for position 2, we have 8 and so on. Using the multiplication principle, we have that the number of ways or arranging 9 books is 9!

Recall that we want the same amount from novels, plays and nonfiction. That is, we are choosing 3 books from each group. We can easy calculate the total number of ways of choosing the 9 books by simply multiplying the number of ways we choose 3 from each cathegory. Hence the total number of ways of choosing the 9 books is

[tex]\binom{9}{3}\cdot \binom{22}{3}\cdot \binom{22}{3}[/tex]

For each selection of 9 books, we have 9! different ways of organizing them, then the total number is

[tex]\binom{9}{3}\cdot \binom{22}{3}\cdot \binom{22}{3}\cdot 9! = 83.3927415552\cdot 10^{13}[/tex]

You are given a bag with 8 green marbles, 6 blue marbles, 14 yellow marbles, and 12 red marbles. Find the theoretical probability of each random event. (Enter your probabilities as fractions.)

(a) Drawing a green marble

(b) Drawing a red marble

(c) Drawing a marble that is not yellow

Answers

a) 8/40 = 1/5
b) 12/40 or 6/20
c) 26/40 or 13/20

The theoretical probability of drawing a green marble is 1/5, a red marble is 3/10, and a marble that is not yellow is 13/20 from a bag of 40 marbles with varying colors.

The question involves calculating the theoretical probability of drawing certain colored marbles from a bag with a mixed collection of marbles. To find the probability of each event, we can use the formula P(event) = Number of favorable outcomes / Total number of outcomes.

Drawing a green marble: There are 8 green marbles out of a total of 40 marbles. So, P(green) = 8/40 = 1/5.

Drawing a red marble: There are 12 red marbles out of a total of 40 marbles. So, P(red) = 12/40 = 3/10.

Drawing a marble that is not yellow: There are 26 marbles that are not yellow (8 green, 6 blue, and 12 red) out of a total of 40 marbles. So, P(not yellow) = 26/40 = 13/20.

The sum of 3 consecutive integers is 60. What is the value of the third integer?

Answers

Answer:

x=19

Step-by-step explanation:

The consecutive integers will be x, x+1 and x+2 since consecutive integers have a pattern.

So,  the equation is x+x+1+x+2=60

Solve:

x+x+1+x+2=60

3x+3=60

Subtract 3 on both sides:

3x+3-3=60-3

3x=57

Divide by 3

3x/3=57/3

x=19

Chen has an MP3 player called the Jumble. The Jumble randomly selects a song for the user to listen to. Chen's Jumble has 444 classical songs, 333 rock songs, and 222 rap songs on it. Chen is going to listen to 360360360 songs.
What is the best prediction for the number of times Chen will listen to a classical song?

Answers

Answer:

160160160 times

Step-by-step explanation:

(444/999)360360360=160160160

Answer:

its d

Step-by-step explanation:

its d

Someone ran 2km someone else ran 3,500 meters what would be that combined​

Answers

Answer:

5,500 meters or 5.5km

Step-by-step explanation:

1 km is = 1000 meter

2km=2000 meters

2000 +3500 =5,5000 meters

The Pew Research Center reported in 2018 that 68% of U.S. adults rated "reducing health care costs" as a national priority. This year a survey is conducted with a national sample of 1,505 U.S. adults selected by a combination of landline and cell phone random digit dials. This year's survey finds that 70% of the sample says that "reducing health care costs" is a national priority.

We test the following hypotheses:

H0: The proportion of U.S. adults this year who rate "reducing health care costs" as a national priority is still 0.68.
Ha: The proportion of U.S. adults this year who rate "reducing health care costs" as a national priority is greater than 0.68.

The P-value is 0.045. At a 5% significance level, we would reject the null hypothesis and concluded that the proportion of U.S. adults this year who rate "reducing health care costs" as a national priority is greater than 0.68.

Explain the P-value in the context of this issue.

Answers

Final answer:

A P-value of 0.045 suggests that there is a 4.5% chance of observing a sample proportion as extreme as 70% or more, assuming the null hypothesis is true. If the P-value<0.05 (usually considered a threshold), we typically reject the null hypothesis - here, indicating that more than 68% consider health care cost reduction a national priority.

Explanation:

In statistics, a P-value is a probability that provides a measure of the evidence against the null hypothesis (H₀). A P-value of 0.045, as given in this instance, indicates that if the null hypothesis were true (i.e., 68% of U.S. adults still consider reducing health care costs a national priority), there is only a 4.5% probability of observing a sample proportion as extreme as 70% or more.

Commonly, a threshold (α) is set at 0.05 or 5%. If the P-value is less than α (which it is in this case, 0.045 < 0.05), we reject the null hypothesis in favor of the alternative hypothesis. Consequently, we conclude there is sufficient evidence to suggest that the proportion of U.S. adults this year who rate 'reducing health care costs' as a national priority is higher than 68%.

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Final answer:

The P-value of 0.045 provides statistically significant evidence to reject the null hypothesis and support the alternative hypothesis that the proportion of U.S. adults who rate 'reducing healthcare costs' as a national priority has increased from the previous 68%.

Explanation:

In the context of this issue, the P-value of 0.045 represents the probability of observing a sample proportion as extreme as 70%, or more, given that the null hypothesis is true - the null hypothesis being that the true proportion of U.S. adults who rate 'reducing healthcare costs' as a national priority is 68%.

If the P-value is less than or equal to the significance level (in this case, 5% or 0.05), we reject the null hypothesis. Since 0.045 is indeed less than 0.05, we reject the null hypothesis, supporting the alternative hypothesis that the proportion of U.S. adults who view reducing healthcare costs as a national priority is greater than 68%.

Therefore, the P-value of 0.045 suggests there is statistically significant evidence to conclude that the perception of 'reducing healthcare costs' as a national priority has increased amongst U.S. adults recently.

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PLEASE HELP ME
I DONT UNDERSTAND

Answers

Answer: its letter A

Step-by-step explanation:

Answer:

145

Step-by-step explanation:

This is pretty simple, the three angles inside the triangle equal to 180 degrees, so if you add 80 and 65 and subtract that from 180, you get 35. So two angles that are connected to a single line equal to 180, so you just subtract 35 from 180 to get 145. Therefore, <1 = 145.

Timothy creates a game in which the player rolls 4 dice. What is the probability in this game of having exactly two dice or more land on a five?
A. 0.016
B. 0.132
C. 0.868
D. 0.984

Answers

Answer:

B. 0.132

Step-by-step explanation:

For each time the dice is thrown, there are only two possible outcomes. Either it lands on a five, or it does not. The probability of a throw landing on a five is independent of other throws. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Timothy creates a game in which the player rolls 4 dice.

This means that [tex]n = 4[/tex]

The dice can land in 6 numbers, one of which is 5.

This means that [tex]p = \frac{1}{6}[/tex]

What is the probability in this game of having exactly two dice or more land on a five?

[tex]P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{4,2}.(\frac{1}{6})^{2}.(\frac{5}{6})^{2} = 0.116[/tex]

[tex]P(X = 3) = C_{4,2}.(\frac{1}{6})^{3}.(\frac{5}{6})^{1} = 0.015[/tex]

[tex]P(X = 4) = C_{4,4}.(\frac{1}{6})^{4}.(\frac{5}{6})^{0} = 0.001[/tex]

[tex]P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.116 + 0.015 + 0.001 = 0.132[/tex]

So the correct answer is:

B. 0.132

The probability of having exactly two dice or more land on a five is: 0.132.

To determine the probability of having exactly two dice or more land on a five when rolling four dice, we first need to calculate the probabilities of each possible outcome involving getting at least two fives.

1: Define the basic probabilities
Each die has 6 faces, so the probability ( p ) of rolling a five on a single die is:
[tex]\[ p = \frac{1}{6} \]The probability \( q \) of not rolling a five on a single die is:\[ q = 1 - p = \frac{5}{6} \][/tex]
2: Define the number of dice rolls
We are rolling 4 dice.

3: Calculate probabilities for 0, 1, 2, 3, and 4 fives
We use the binomial distribution formula:
[tex]\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]where \( n = 4 \), \( p = \frac{1}{6} \), and \( k \)[/tex] is the number of fives rolled.
Probability of rolling exactly 0 fives (\( k = 0 \)):
[tex]\[ P(X = 0) = \binom{4}{0} \left(\frac{1}{6}\right)^0 \left(\frac{5}{6}\right)^4 = 1 \times 1 \times \left(\frac{5}{6}\right)^4 = \left(\frac{5}{6}\right)^4 \][/tex]
Probability of rolling exactly 1 five (\( k = 1 \)):
[tex]\[ P(X = 1) = \binom{4}{1} \left(\frac{1}{6}\right)^1 \left(\frac{5}{6}\right)^3 = 4 \times \frac{1}{6} \times \left(\frac{5}{6}\right)^3 \]Probability of rolling exactly 2 fives (\( k = 2 \)):\[ P(X = 2) = \binom{4}{2} \left(\frac{1}{6}\right)^2 \left(\frac{5}{6}\right)^2 = 6 \times \left(\frac{1}{6}\right)^2 \times \left(\frac{5}{6}\right)^2 \][/tex]
[tex]Probability of rolling exactly 3 fives (\( k = 3 \)):\[ P(X = 4) = \binom{4}{4} \left(\frac{1}{6}\right)^4 \left(\frac{5}{6}\right)^0 = 1 \times \left(\frac{1}{6}\right)^4 \times 1 \])^1 \]Probability of rolling exactly 4 fives (\( k = 4 \)):[/tex]
[tex]\[ P(X = 4) = \binom{4}{4} \left(\frac{1}{6}\right)^4 \left(\frac{5}{6}\right)^0 = 1 \times \left(\frac{1}{6}\right)^4 \times 1 \][/tex]
4: Sum probabilities for \( k \geq 2 \)
We need to find \( P(X \geq 2) \), which is:
[tex]\[ P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) \][/tex]
5: Perform calculations
[tex]\[P(X = 0) = \left(\frac{5}{6}\right)^4 \approx 0.4823\]\[P(X = 1) = 4 \times \frac{1}{6} \times \left(\frac{5}{6}\right)^3 = 4 \times \frac{1}{6} \times \left(\frac{125}{216}\right) \approx 0.3858\]\[P(X = 2) = 6 \times \left(\frac{1}{6}\right)^2 \times \left(\frac{5}{6}\right)^2 = 6 \times \frac{1}{36} \times \frac{25}{36} = \frac{150}{1296} \approx 0.1157\][/tex]
[tex]\[P(X = 3) = 4 \times \left(\frac{1}{6}\right)^3 \times \frac{5}{6} = 4 \times \frac{1}{216} \times \frac{5}{6} = \frac{20}{1296} \approx 0.0154\]\[P(X = 4) = \left(\frac{1}{6}\right)^4 = \frac{1}{1296} \approx 0.0008\][/tex]

6: Summing up [tex]\( P(X \geq 2) \)[/tex]
[tex]\[P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) \approx 0.1157 + 0.0154 + 0.0008 = 0.1319\][/tex]
Rounding this to three decimal places, we get 0.132.
Thus, the probability of having exactly two dice or more land on a five is:
[tex]\[ \boxed{0.132} \][/tex].

For what value of a does 9=(1/27)^2+3

Answers

Answer:

if a= (1/27)^2  + 3, then  a is about  3.00137

Step-by-step explanation:

I assume you have a typo here.

Your equation should be   a = (1/27)^2  + 3 ...

If that is so,    a =  (1/27)^2 + 3 =  3.00137...

It is recommended that adults get 8 hours of sleep each night. A researcher hypothesized college students got less than the recommended number of hours of sleep each​ night, on average. The researcher randomly sampled 20 college students and found no evidence to reject the null hypothesis at the​ 5% significance level. What is true regarding the​ p-value from this hypothesis​ test?

Answers

Answer:

Given:

Sample size, n = 20

Significance level = 5% = 0.05

Mean, u = 8

Here, the sample mean was not given.

Here the null and alternative hypothesis will be:

H0 : u = 8

H1 : u < 8

In this case, since there is no evidence to reject the null hypothesis, H0, at 0.05 level of significance, we can say that the p-value is greater than the level of significance, 0.05.

Range of f(x)=-(x-5)^2+9

Answers

Answer: (5, -9)

Step-by-step explanation:

Rewrite the equation in term of  x and y.

Study the graph of f(x) = 10x. Use the drop-down menus to identify the lines that represent the functions below. p(x) = 10(x + 4) r(x) = 10(x) + 4

Answers

Answer:

1 (line B)

2 (line A)

3 (line D)

Step-by-step explanation: We both know I don't have one.

Answer:

b , a , d

Step-by-step explanation:

edg2020

Simplify the following expression 1^9

Answers

Answer:

1

Step-by-step explanation:

Sadie wrote the following on the board find and correct her mistake 2years= 24 weeks

Answers

2 years is 52 weeks not 24 weeks

the difference of eight and twice a number

Answers

Answer:

8 - 2x

Step-by-step explanation:

Let x be the unknown number

difference is subtraction

8 - 2x

A student participates in a Coke versus Pepsi taste test. She correctly identifies which soda is which four times out of six tries. She claims that this proves that she can reliably tell the difference between the two soft drinks. You have studied statistics and you want to determine the probability of anyone getting at least four right out of six tries just by chance alone. Which of the following would provide an accurate estimate of that probability? Remember, you are trying to prove that four out of six is unusual or not unusual if one truly does not know the taste difference.
A. Repeat this experiment with a very large sample of people and calculate the percentage of people who make four correct guesses out of six tries.
B. Simulate this on the computer with the probability of 50% of guessing the correct soft drink on each try, and calculate the percent of times there are four or more correct guesses out of six trials.
C. No need to run any further tests, since 4 out of 6 is better than half of the time, we would say the student's claim is correct.D. Have the student repeat this experiment many times and calculate the percentage of times she correctly distinguishes between the brands

Answers

Answer:

A

Step-by-step explanation:

In an all boys school, the heights of the student body are normally distributed with a mean of 70 inches and a standard deviation of 5 inches. Using the empirical rule, what percentage of the boys are between 65 and 75 inches tall?

Answers

Answer:

68%

Step-by-step explanation:

Final answer:

Using the empirical rule for normal distribution, approximately 68% of the boys at the all boys school with a mean height of 70 inches and a standard deviation of 5 inches are between 65 and 75 inches tall.

Explanation:

According to the empirical rule (also known as the 68-95-99.7 rule), for a normal distribution:

Approximately 68% of the data falls within one standard deviation of the mean.

About 95% of the data falls within two standard deviations of the mean.

And around 99.7% falls within three standard deviations of the mean.

In the case of the all boys school with a mean height of 70 inches and standard deviation of 5 inches, the range between 65 inches (70 - 5) and 75 inches (70 + 5) represents one standard deviation from the mean on either side. Thus, using the empirical rule, approximately 68% of the boys are between 65 and 75 inches tall.

please help meeeee and I am stuck on this question

Answers

Answer:

b = 3

Step-by-step explanation:

the area of the parallelogram is 7*b, since we know it is 21, b = 3.

The Square root of 8^2 -7^2
The answer is the square root of 15

In studying a random sample of 20 automotive​ batteries, the confidence interval ​(0.22​,0.33​) was constructed for the population standard deviation of the​ batteries' reserve capacity in hours. This population standard deviation should be less than 0.26 hour. Does the confidence interval suggest that the variation in the​ batteries' reserve capacities is at an acceptable​ level? Explain your reasoning.

Answers

Answer:

NO.

Step-by-step explanation:

From the question, we are given a random sample of 20 automotive​ batteries, a confidence interval =(0.22​,0.33​). Also, the population standard deviation is said to be less than 0.26 hour.

The confidence interval does NOT suggest that the variation in the​ batteries' reserve capacities is at an acceptable​ level.

REASON: If you look at the confidence interval, we can see that it contains the value for the standard deviation that is 0.26 and even MORE value than 0.26.

This does not give us any suggestion that the standard deviation is less than 0.26.

Final answer:

The confidence interval suggests that the variation in the batteries' reserve capacities is not at an acceptable level because the interval (0.22, 0.33) lies above the acceptable standard deviation of less than 0.26 hour.

Explanation:

In the context of the question, a constructed confidence interval for the population standard deviation of automotive batteries' reserve capacity is (0.22, 0.33 hours). To evaluate whether the variation in the batteries' reserve capacities is at an acceptable level, we would compare the interval to the stated acceptable level of a population standard deviation which should be less than 0.26 hour. Since the lower bound of the interval is above 0.22 and the entire confidence interval lies above 0.26, this suggests that the variability may be higher than the acceptable level, hence the variation is not at an acceptable level according to the specified criteria.

As for the example related to the NeverReady batteries, it demonstrates the use of sample data to question a company's claim about product performance by calculating the probability of obtaining a sample with a mean as low as or lower than observed when assuming that the company's claim is true. If the probability is very low, it casts doubt on the claim.

The distance between two cities on a map is 13 cm. What is the actual distance between the cities if the map is drawn at a scale of 1:50,000?

Answers

Answer:

65,000

Step-by-step explanation:

because the scale is 1:50,000, so just simply multiply by 50,000.

Answer:i am not going to answer htis question 4 u but i will tell u how 2 do it first u mulitply 50,000 by 13 then you convert the number of centimeters u get into kilometers (this is where most people get wrong cuz there 2 lazy to read the question.

The domain of f(x) = 4x is The range of f(x) = 4x is

Answers

Answer:

all real numbers

y>0

Step-by-step explanation:

The range of f(x) = 4x is all real numbers.

What are domain and range?

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

Therefore, The range of f(x) = 4x is all real numbers.

To know more about the domain refer to :

https://brainly.com/question/26098895

#SPJ2

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