When you throw a ball up in the air, it travels up and then stops instantaneously before falling back down. At the point where it stops and changes directions to fall back down is

Answer:

MultiTaction

Explanation:

MultiTaction is a company founded in 1997 and a top developer that specializes in advanced visualization solutions, and they are responsible for developing the collaboration software.

Developed and designed to help teams collaborate globally in real-time, Canvus Connect collaboration software that makes it possible for remote users to share, draw, manipulate, and input information in on a single board was developed by MultiTaction.

Canvus Connect is a cutting-edge collaboration software developed by MultiTaction, specifically designed to facilitate seamless global teamwork in real-time. This innovative platform empowers remote users to effortlessly share, draw, manipulate, and input information on a unified digital board.

By harnessing the power of Canvus Connect, teams scattered across the globe can now engage in productive and interactive collaboration sessions as if they were in the same physical space. This software stands out for its user-friendly interface and its ability to foster creativity and efficiency in group projects.

With Canvus Connect, MultiTaction has revolutionized the way teams work together, breaking down geographical barriers and enabling a new level of productivity in the modern era of remote and distributed work environments.

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Answer:

A capacitor

Explanation:

From experimental findings,the plates are connected to a 10Hz ac generator and a potential difference of 1.5V.The ITO is a transplant conducting material,charges accumulates on it when a voltage is applied to it.Exactly what is seen on a parallel plate capacitor

Final answer:

Meteorology is the study of the atmosphere and weather patterns, aiming to predict weather in the short term. It is different from climatology, which deals with long-term climate trends, and is a part of the broader field of atmospheric science.

Explanation:

The term meteorology refers specifically to the study of the atmosphere and its various phenomena, including weather patterns. This scientific field encompasses the processes and forces that contribute to the weather and aims to predict weather in the short term, which is crucial for numerous aspects of daily life and safety. Despite some common misconceptions, meteorology does not equate to the study of meteors, and it should not be confused with climatology, which is the study of climate, or long-term weather patterns, over extended periods such as decades, centuries, and millennia.

Climatology and meteorology both fall under the broader umbrella of atmospheric science, which combines these and other disciplines that focus on the atmosphere.

Therefore, the correct answer to the student's question would be option B: Meteorology is the study of the atmosphere and its related weather systems.

Answer

given,

time of travel = 2 hours

distance between the two car = 208 miles

one car traveled 8 miles per hour faster than other.

speed of both the car =?

Let speed of one car = x

speed of the second car = x + 8

distance = speed x time

distance = 2 x..............(1)

distance = 2(x+8)...........(2)

total distance = 208 miles

2 x + 2(x + 8) = 208 miles

2 x + 8 = 104

2x = 96

x = 48 mile/h (1st car)

x + 8  = 56 mile/hr(2nd car)

hence, speed of both the vehicle is given above.

Answer:

17.7 mm

Explanation:

Poiseuille's law can be used to solve for the radius of the pipe

Volume per seconds flowing through the pipe = 7.3 / (51 × 60 s) = 0.0239 m³ / s

volume per seconds = π R^4 ( Pi - Po) / ( 8 ηL) where R is the radius of the pipe in mm, (Pi - Po) is the pressure difference in Pa, L is the length of the pipe in meters, and η is the viscosity in Pa.s

Pi - Po = ( 7.4 - 1.01) × 10^5 since 1 atm represent atmospheric pressure and it is equal to 1.01 × 10^5

Pi -Po = 6.39 × 10^5

substitute the values into the equation

0.00239 = 3.142 × (R^4) × 6.39 × 10^5 / ( 8 × 11 × 0.934)

cross multiply

0.00239 × 8 × 11 × 0.934 = (R^4) × ( 2.01 × 10^6)

make R subject of the formula

R^4 = (0.00239 × 8 × 11 × 0.934) / ( 2.01 × 10^6)

R = [tex]\fourthroot{9.77 * 10^-8}[/tex]  

R = 0.0177 m = 17.7 mm

Answer:

D) Anytime you change lanes

Explanation:

Correct way to execute a change of direction maneuver :

1 - The driver must warn by means of optical signals any maneuver that implies a lateral or backward displacement of his vehicle, as well as his intention to immobilize it or to slow down his gear in a considerable way. Such optical warnings will be made well in advance of the start of the maneuver, and, if they are bright, they will remain in operation until the end of the maneuver.

2 - Unless the road is conditioned or signposted to perform it in another way, it will be as close as possible to the right edge of the road, if the change of direction is to the right, and to the left edge, if it is to the left and the road is One way. If it is on the left, but the road through which it circulates is two-way traffic, it will adhere to the longitudinal mark of separation between the senses or, if it does not exist, to the axis of the road, without invading the area destined to the Wrong Way; when the road is two-way traffic and 3 lanes, separated by dashed longitudinal lines, should be placed in the center. In any case, the placement of the vehicle in the appropriate place will be carried out with the necessary advance and the maneuver in the least possible space and time.

3 - If the change of direction is on the left, it will leave the center of the intersection on the left, unless it is conditioned or marked to leave it on the right .

You must give a signal either by hand and arm or by a signal device anytime changing lanes. The correct option is (D).

Traffic lights, turn signals, horn blowing, and hand gestures are examples of signals used in the context of driving and transportation to express intentions and maintain order on the road.

Providing signals while driving is important for the safety of oneself and others. Signals are a safety measure to avoid accidents.

It is crucial to give other drivers advance notice of your intended lane change in order to safeguard their safety. Other drivers can anticipate your actions and modify their driving accordingly if you signal. It is a fundamental component of prudent and secure lane switching.

Hence, You must give a signal either by hand and arm or by a signal device anytime changing lanes. The correct option is (D).

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Explanation:

As the distance between a planet and the sun increase, the following quantities will decrease.

1. The gravitational force is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

As the distance between a planet and the sun increase, the gravitational force decrease.

2. As the distance between a planet and the sun increase, it result in the decrease in its speed. Due to decrease in gravitational force, centripetal force acting on the planet should decrease. Since,

[tex]F_c=\dfrac{mv^2}{r}[/tex]

v is the tangential speed

So, the tangential speed must decrease.

3. The distance traveled in a day should decrease.

Hence, this is the required solution.

Answer:

The environmental remediation is the way to protect the environment by removing the pollutants.

Explanation:

Environment remediation is the method in which the discrimination or removal of pollution or contaminants from the various media like soil, groundwater, sediments or surface water. For this various techniques are there like containment, pump and treat, Extraction, stabilisation/ solidification, soil washing, air stripping, precipitation, vitrification, thermal desorption and biological remediation. The environmental remediation is important because it helps in reduction of the radiation exposure. The idea is just removal of the radiation sources, so as to protect the people as well as the environment from the harmful effects from the exposure to ionizing radiation.

The amount of light a telescope collects is proportional to the square of its diameter. A 2-m telescope would need four times as long to collect the same amount of light as a 4-m telescope. Therefore, it would take 40 minutes for a 2-m telescope to collect the same amount of light that a 4-m telescope can in 10 minutes.

The amount of light collected by a telescope is proportional to the square of its diameter. In other words, a telescope with twice the diameter will collect four times as much light. Hence, a 4-m telescope will collect light four times as fast as a 2-m telescope, given that everything else (including observational conditions) remains constant.

This means that to collect the same amount of light, a 2-m telescope would need four times longer than a 4-m one. So, if a 4-m telescope collects a certain amount of light in 10 minutes, a 2-m telescope would need 40 minutes to collect the same amount of light.

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Answer:False

Explanation:

Turn the key to lock is not advisable as it lock the steering wheel and may create a dangerous situation.

Following steps can be taken in this situation

Answer: Option (B) is the correct answer.

Explanation:

As we know that the temperature when the vapor pressure of liquid becomes equal to the atmospheric pressure surrounding the liquid. And, during this temperature liquid state of substance changes into vapor state.

But during this process of change in state of substance the temperature will cease to change for some time because unless and until all the liquid molecules do not convert into vapor state the temperature will not rise or change.

As the boiling point of water is [tex]100^{o}C[/tex] so the temperature ceases to change from [tex]98^{o}C[/tex] to [tex]102^{o}C[/tex].

Therefore, we can conclude that when heating water, during [tex]98^{o}C[/tex] to [tex]102^{o}C[/tex] temperature range the temperature will cease to change for some time.

Answer:

4820.9 J of work is done on the flight bag.

Explanation:

Given:

Force acting on the bag is, [tex]F=30.0\ N[/tex]

Displacement of the bag caused by the force is, [tex]S=250.0\ m[/tex]

Angle between the direction of force and direction of displacement caused is, [tex]\theta = 50\°[/tex]

Now, the formula to calculate work done on a body by a force 'F' causing displacement 'S' at an angle [tex]\theta[/tex] between the two vectors is given as:

[tex]W=FS\cos \theta[/tex]

Plug in the given values and solve for work done 'W'. This gives,

[tex]W=(30.0\ N)(250.0\ m)(\cos 50)\\W=4820.9 \textrm{ N-m or 4820.9 J}[/tex]

Therefore, the work done on the flight bag is 4820.9 J.

Answer:

-main-sequence star

-protostar with jets

-contracting cloud trapping infrared light

-molecular-cloud fragment

Explanation:

The Life of a Star of about one Solar Mass. Small stars have a mass upto  1 1/2 times that of the Sun. Stars are planetary bodies that revolve in space. They are the combination of hydrogen and helium gases

seven main stages of a star formation are

A Giant Gas Cloud. A star begins life as a large cloud of gas. ...

A Protostar Is a Baby Star. ...

The T-Tauri Phase. ...

Main Sequence Stars. ...

Expansion into Red Giant. ...

Fusion of Heavier Elements. ...

Supernovae and Planetary Nebulae.

But ranking them according to  the central temperature, from highest to lowest. will be

-main-sequence star

-protostar with jets

-contracting cloud trapping infrared light

-molecular-cloud fragment

Answer:

If the canoe heads upstream the speed is zero. And directly across the river is  8.48 [km/h] towards southeast

Explanation:

When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:

Vr = velocity of the river = 6[km/h}

Vc = velocity of the canoe = -6 [km/h]

We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.

Vt = Vr + Vc = 6 - 6 = 0 [km/h]

For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.

So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).

Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:

[tex]Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h][/tex]

When paddling upstream against a current of equal speed, the canoe remains stationary (0km/hr), as the man's paddling counteracts the downstream current. If the man were to paddle the canoe directly across the river, the speed of the canoe would be 6 km/hr, since the river's current doesn't directly impact the speed he can move perpendicular to the current.

This question deals with the concept of relative motion in Physics. When the man paddles the canoe upstream, he is going against the river current. Therefore, the effective speed of the canoe is the difference between his paddling speed and the river current speed, i.e., 6 km per hour (canoe speed) - 6 km per hour (current speed) = 0 km per hour.

When the man paddles the canoe directly across the river, the river's current doesn't directly affect his progress across the river. Thus, the speed of the canoe remains the speed with which the man paddles it, i.e., 6 km per hour. However, the path will not be straight because of the river's current. It is essential to understand these principles to solve similar problems involving relative motion.

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Final answer:

a. C = A cos(φ), S = -A sin(φ).

b. A = √(C²+S²), φ = atan2(S, C).

Explanation:

Both expressions given for the general solution of a harmonic oscillator can be related to each other by using trigonometric identities.

The first expression, x(t)=Acos(ωt+φ), involves an amplitude A and a phase shift φ, whereas the second one, x(t) = Ccos(ωt) + Ssin(ωt), includes two parameters C and S for the coefficients of cosine and sine respectively.

To convert between the two forms, we use the cosine of a sum identity, which states that:

cos(a + b) = cos(a)cos(b) - sin(a)sin(b).

For part (A), expressing Acos(ωt+φ) in the form of Ccos(ωt) + Ssin(ωt), we get:
C = A cos(φ),
S = -A sin(φ).

For part (B), deriving A and φ in terms of C and S from the second equation, we use the Pythagorean identity and the definitions of cosine and sine to get:
A = √(C²+S²),
φ = atan2(S, C).

The constants C and S can be expressed in terms of A and ϕ as C = A cos(ϕ) and S = -A sin(ϕ). Conversely, A and ϕ can be expressed in terms of C and S as A = √(C² + S²) and ϕ = tan⁻¹(-S/C).

Explanation:

Part A: Expressing C and S in terms of A and ϕ

The given forms are:

We can use the trigonometric identity for the sum of angles to rewrite A cos(ωt + ϕ):

Comparing this with x(t) = C cos(ωt) + S sin(ωt), we identify:

Part B: Expressing A and ϕ in terms of C and S

From the relationships above:

Answer:

113.7

Explanation:

maximum distance (s) = 8.9 km

reference intensity (I0) = 1 x 10^{-12} W/m^{2}

power of a juvenile howler monkey (p) = 63 x 10^{-6} W

distance (r) = 210 m

intensity (I) = power/area

where we assume the area of a sphere due to the uniformity of the output in all directions

area = 4π[tex]r^{2}[/tex] =  4π x [tex]210^{2}[/tex] = 554,176.9 m^{2}

intensity (I) = [tex]\frac{63 x 10^{-6} }{554,176.9} = 113.7 x 10^{-12}[/tex]

therefore the desired ratio I/I0 = [tex]\frac{113.7 x 10^{-12}}{1 x 10^{-12}}[/tex] = 113.7

To find the ratio of the acoustic intensity produced by the juvenile howler to the reference intensity I0, you need to calculate the acoustic intensity at a distance of 210 m. By using the formula I = P / A, you can find the acoustic intensity by calculating the power emitted by the source and the area through which the sound is passing. Then, find the ratio of the acoustic intensity produced by the juvenile howler to the reference intensity I0 by dividing the calculated acoustic intensity by I0.

To find the ratio of the acoustic intensity produced by the juvenile howler to the reference intensity I0, we need to calculate the acoustic intensity at a distance of 210 m.

Acoustic intensity is given by the formula:

I = P / A

where I is the acoustic intensity, P is the power emitted by the source, and A is the area through which the sound is passing.

First, convert the power of the juvenile howler monkey from 63 μW to watts:

P = 63 x 10^-6 W

Next, calculate the area through which the sound is passing:

A = 4πr^2

where r is the distance of 210 m.

Finally, calculate the acoustic intensity:

I = P / A

Now, find the ratio of the acoustic intensity produced by the juvenile howler to the reference intensity I0 by dividing the calculated acoustic intensity by I0:

Ratio = I / I0

Answer:

a) I = 270.18 Kg*m/s

b) F = -3216.42N

Explanation:

a) We know that:

I = [tex]P_f -P_i[/tex]

Where I is the impulse, [tex]P_f[/tex] is the final momentum and [tex]P_i[/tex] the initial momentum.

so:

I = [tex]MV_f -MV_i[/tex]

where M is the mass, [tex]V_f[/tex] is the final velocity and [tex]V_i[/tex] is the initial velocity.

First we have to find the [tex]V_i[/tex]. So, using the conservation of energy.

[tex]Mgh = \frac{1}{2}MV_i^2[/tex]

where g the gravity and h the altitude. Replacing values, we get:

[tex](79kg)(9.8m/s)(0.6m) = \frac{1}{2}(79kg)V_i^2[/tex]

solving for [tex]V_i[/tex]:

[tex]V_i[/tex]= 3.42 m/s

Now, replacing in the previus equation:

I = [tex]MV_f -MV_i[/tex]

I = [tex](79kg)(0)-(79kg)(3.42m/s)[/tex]

I = -270.18 Kg*m/s

The impulse is negative becuase it is upward.

b) We know that:

Ft = I

where F is the force, t the time and I the impulse.

so, replacing values and solving for F, we get:

F(0.084s) = -270.18 Kg*m/s

F = -3216.42N

The force is negative becuase it is upward.

Answer:

212.12 J

Explanation:

As the child starts from rest and rolls down on the incline, the potential energy of the child decreases due to decrease in the height. This drops in potential energy appears as an increase in kinetic energy of the child as it gains speed. hence kinetic energy gained by the child at the bottom is same as the potential energy of the child at the top.

[tex]m[/tex] = mass of the child = 37 kg

[tex]L[/tex] = length of the incline surface = 2.0 m

[tex]\theta[/tex] = angle of the incline from the horizontal = 17 deg

[tex]K[/tex] = kinetic energy of the child at the bottom

height of the incline surface is given as

[tex]h = L Sin\theta\\h = (2.0) Sin17.0\\h = 0.585 m[/tex]

[tex]PE[/tex] = Potential energy of the child at the top

Potential energy of the child at the top of incline is given as

[tex]PE = mgh \\PE = (37) (9.8) (0.585)\\PE = 212.12 J[/tex]

Using conservation of energy

Kinetic energy at the bottom = Potential energy at the top

[tex]K = PE\\K = 212.12 J[/tex]

To find the kinetic energy of the child at the bottom of the incline, calculate the potential energy at the top and equate it to the kinetic energy at the bottom due to energy conservation, as there is no friction.

The subject of this question is Physics, specifically focusing on the topics of energy and motion on inclines. To find the kinetic energy of the child at the bottom of the incline, you would need to calculate the potential energy at the top of the incline and assume it transforms into kinetic energy at the bottom due to conservation of energy, as there is no friction to dissipate it.

To calculate the potential energy (PE) at the top of the incline, you can use the formula: PE = mgh, where m is the mass of the child, g is the acceleration due to gravity (9.8 m/s2), and h is the height of the incline.

The height can be found using trigonometry, since h = s sin(θ), where s is the length of the incline and θ is the angle of the incline with respect to the horizontal. Once you find the PE, this will equal the kinetic energy (KE) at the bottom of the slope, so KE = PE. Plug in the values (mass of 37 kg, length of the slope 2.0 m, angle 17 degrees) to solve for the kinetic energy.

Explanation:

Following are the steps taken

1. To turn off the wave in the wave pool press the emergency turn off button (E-stop).

2. Winding of river or shutting off flow of water in the slide.

3. Dispatch of riders at speed slide is stopped.

To dry off your brakes after driving through water, you should apply them gently as you accelerate. This action will evaporate the water through heat created by the friction between the brake pads and rotors, thus restoring your brakes’ functioning.

If you drive through water, your brakes can become wet and lose their effectiveness. The best way to dry the brakes off is to C) apply your brakes gently as you accelerate. This method is preferable because it allows the heat generated by the friction between the brake pads and the rotors to evaporate the water, restoring your brakes' effectiveness. It's also important to remember that slamming on your brakes, increasing your speed, or pulling over to wait can be dangerous practices depending on your situation and may not contribute to your brakes' quick recovery.

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To dry off slippery brakes after driving through water, gently apply your brakes while accelerating. This uses frictional heat to dry the brakes gradually and safely. So , Correct option is C.) apply your brakes gently as you accelerates.

If you drive through water, your brakes may become slippery and ineffective. To dry the brakes off, apply your brakes gently as you accelerate.

When your brakes are wet, slamming on them or increasing your speed can be dangerous. Instead, gently applying the brakes while accelerating helps generate heat through friction, which effectively dries the brake components. This ensures your brakes regain their effectiveness gradually and safely.

Answer:PHARMING

Explanation:

Social engineering can be defined as an attempt to manage,change and regulate the future development and the behaviour of a society.

Common types of social engineering attack include; Watering hole, Pretexting, Phishing,Whaling attack, Baiting, PHARMING, and so on.

PHARMING is an attempt to redirect internet traffic from a legitimate site to a different identical-looking site. PHARMING is a spamming practice, a cyberattack and also, a type of phishing in which hackers use in stealing personal information from people on the internet.

PHARMING is done through the injection of malicious data or code into the victims' computer system. This injection is known as the DNS cache poisoning.

Answer:

Neptune is approximately 41 times as far from the sun as Venus

Explanation:

Estimate = distance of Neptune from the sun ÷ distance of Venus from the sun = 4.5×10^9 ÷ 1.18×10^8 = 40.9 (approximately 41)

Neptune is approximately 41 times farther from the sun than Venus.

The best estimate of how many times as far from the sun Neptune is as Venus is approximately 40 times.

To find this, you can divide the distance of Neptune from the sun by the distance of Venus from the sun:

Neptune distance / Venus distance = 4.5*10^9 km / 1.1*10^8 km = 41

Answer:

Speed of Tarzan at the bottom of the swing is 12.5 m/s.

Explanation:

Given that,

Length of the vine, L = 31 m

The swing is inclined at an angle of 42 degrees with the vertical. We need to find the speed at the bottom of the swing if he pushes off with a speed of 6.00 m/s. using the conservation of mechanical energy as :

[tex]mgh=\dfrac{1}{2}mv^2[/tex]

[tex]gh=\dfrac{1}{2}v^2[/tex]

h is the height of the height.

[tex]h=L-L\ cos\theta[/tex]

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{2gL(1-\ cos\theta)}[/tex]

[tex]v=\sqrt{2\times 9.8\times 31(1-\ cos(42))}[/tex]

v = 12.492 m/s

or

v = 12.5 m/s

So, his speed at the bottom of the swing if he pushes off with a speed of 6.00 m/s is 12.5 m/s. Hence, this is the required solution.

Option b.

By making use of the conservation of mechanical energy principle and using trigonometric relations, we find that Tarzan's final speed as he reaches the bottom of his swing is approximately 12.55 m/s, hence answer choice (B) 12.5 m/s is the closest.

To solve this problem, we need to recognize that this is a problem about the conservation of mechanical energy. Initially, Tarzan has both kinetic energy (because he pushes off with a speed of 6.00 m/s) and potential energy (because he is at a height above the lowest point of the swing). At the bottom of the swing, all of this energy will have been transformed into kinetic energy, as he is now at the lowest point of the swing, and hence has no potential energy.

The kinetic energy at the top of the swing is (1/2)*m*(6.00 m/s)^2 and the potential energy at the top of the swing is m*g*h. We can write the height 'h' in terms of the length of the vine (31.0 m) and the angle it makes with the vertical, theta (42.0°), as h = L*(1 - cos(theta)) = 31.0 m*(1 - cos(42.0°)).

As mechanical energy is conserved, the sum of kinetic and potential energy at the top of the swing will equal the kinetic energy at the bottom of the swing, which we can write as (1/2)*m*v_f^2. Equating and simplifying gives us a value of v_f = sqrt(2*g*L*(1 - cos(theta))(2*9.8 m/s^2*31.0 m*(1 - cos(42.0°)))).

Popping these numbers into a calculator gives an answer of approximately 12.55 m/s. Hence, the closest answer, and the one we should choose, is (B) 12.5 m/s.

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a) The coin reaches a maximum height of approximately 1.28 meters above the release point.

b) The coin remains in the air for approximately 1.02 seconds before returning to the release point.

We calculate the maximum height and total air time of a football coin tossed with an initial speed of 5 m/s, neglecting air resistance.

a) Maximum Height:

Use the vertical motion equation: [tex]v^2 = u^2[/tex] + 2gh, where v = 0 at the peak (no upward velocity), u = 5 m/s (initial speed), g = 9.81 m/[tex]s^2[/tex] (gravity), and h is the unknown maximum height.

Rearrange and solve for h: h = ([tex]v^2 - u^2[/tex]) / 2g ≈ 1.28 meters.

Therefore, the coin reaches a maximum height of approximately 1.28 meters above the release point.

b) Total Air Time:

Since the initial and final velocities at the release point are equal but in opposite directions, the total air time can be calculated twice the time to reach the peak.

Use the same vertical motion equation: t = u/g ≈ 0.51 seconds.

Total air time: 2t ≈ 1.02 seconds.

Therefore, the coin remains in the air for approximately 1.02 seconds before returning to the release point.

Answer: The mass number of an atom of carbon (C) represents the total number of protons in the atom. neutrons and electrons in the atom. protons and neutrons in the atom. electrons in the atom.

Answer ?

Protons and neutrons.

Explanation ??

Well, protons and neutrons are the largest particles in an atom. Electrons are not included in the mass because they are too small to make a difference in the mass.

(( Max ))

Answer:

the ratio F1/F2 = 1/2

the ratio a1/a2 = 1

Explanation:

The force that both satellites experience is:

F1 = G M_e m1 / r²       and

F2 = G M_e m2 / r²

where

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

F1/F2 = 1/2

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r    and

F2c = m2 v² / r

where

Thus,

a1 = v² / r ⇒ v² = r a1    and

a2 = v² / r ⇒ v² = r a2

Therefore,

F1c = m1 a1 r / r = m1 a1

F2c = m2 a2 r / r = m2 a2

In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,

F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

also

a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

a1/a2 = 1

1. The ratio of the gravitational force on the first 1000 kg satellite to that on the second 2000 kg satellite is 1/2.

2. The ratio of the acceleration of the first 1000 kg satellite to that of the second 2000 kg satellite is also 1/2.

The gravitational force (F) between two objects is given by the equation:

F = G * (m1 * m2) / r²

Where:

- F is the gravitational force.

- G is the universal gravitational constant.

- m1 and m2 are the masses of the two objects.

- r is the distance between the centers of the two objects.

In this case, both satellites are in the same orbit around the Earth, so their distances from the center of the Earth (r) are the same.

Let's calculate the ratio F1/F2 for the first satellite (mass m1) and the second satellite (mass m2):

F1/F2 = (G * m1 * m_Earth) / r² / (G * m2 * m_Earth) / r²

F1/F2 = (m1 * m_Earth) / (m2 * m_Earth)

Now, we have m_Earth in both the numerator and denominator, so it cancels out:

F1/F2 = m1 / m2

So, the ratio of the gravitational force on the first satellite (F1) to that on the second satellite (F2) is simply the ratio of their masses, which is:

F1/F2 = 1000 kg / 2000 kg = 1/2

Now, let's calculate the ratio a1/a2 for the accelerations of the first satellite and the second satellite. The acceleration due to gravity is given by:

a = G * (m_Earth) / r²

Since both satellites are at the same distance (r) from the center of the Earth, the ratio a1/a2 is the same as the ratio of their masses:

a1/a2 = m1 / m2 = 1000 kg / 2000 kg = 1/2

So, the ratio of the acceleration of the first satellite (a1) to that of the second satellite (a2) is also 1/2.

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Answer:

1.Reduced pedal travel

2.  Firmer pedal feel

Explanation:

A power brake booster is defined as  a device that reduces the amount of force that it takes to apply hydraulic brakes.  Power brake boosters harness manifold vacuum to accomplish this. Brake booster multiply force on the pedal to the master cylinder

Vacuum booster works by pulling the air out of the booster chamber with a pump creating a low pressure system inside. As soon as  the driver steps on the brake pedal, atmospheric pressure is pushed into the booster by the input rod booster.

The advantage of cargos hydraulic brake booster over conventional vacuum booster is reduced pedal travel and firmer pedal feel

Final answer:

The 2020 NV Cargo's hydraulic brake booster offers increased braking power, improved response time, and reduced pedal effort compared to a conventional vacuum booster.

Explanation:

The benefits of the 2020 NV Cargo's hydraulic brake booster over a conventional vacuum booster include increased braking power, improved response time, and reduced pedal effort.

The hydraulic brake booster uses hydraulic pressure generated by a motorized pump to amplify the force applied to the brake pedal, resulting in more effective stopping power.

Unlike a vacuum booster, which relies on engine vacuum, the hydraulic brake booster is independent of engine conditions, providing consistent braking performance even under challenging operating conditions.

Answer:

B. Technician B only

Answer:

The results of this experiment is that the vast majority of the particles were very little deviated,

Explanation:

Rutherford's experiment consisted of making alpha particles that are helium nucleus with two positive charges on a thin sheet of gold.

The results of this experiment is that the vast majority of the particles were very little deviated, which agrees that the charge and mass of the electrons is small, so their repulsion is very small

A few particles are strongly deviated and much less highly deviated almost  

back off, this allowed us to suggest that the positive charge and mass was concentrated in a very small area of ​​space, which I call nucleus

Answer:

The power required to stop the car =  8 × 10⁵ watt.

Explanation:

Kinetic Energy: This is the energy of a body in motion. The S.I unit of energy is Joules (J).

Power: These is defined as time rate of doing work, or it can be defined as the time rate of transfer of energy. The S.I unit of power is Watt (W).

Mathematically, power can be expressed as

Power = Energy/time

P = E/t................. Equation 1

Given: E = 8×10⁶ J, t = 10 s

Substituting these values into equation 1,

p = 8×10⁶/10

p = 8 × 10⁵ watt.

Therefore the power required to stop the car =  8 × 10⁵ watt.

The power required to stop the car along the horizontal road is 8 × 10⁵ watt.

Kinetic Energy:

It is the energy of a object or body due to its motion. It  is measured in Joules (J).

Power:

It can be defined as the time rate of transfer of energy. It  is measured in Watt (W).    

P = E/t

Where,

P - Power =

E - Energy = 8×10⁶ J

t - time = 10 s

Put the values into the formula,  

p = 8×10⁶/10  

p = 8 × 10⁵ watt.

Therefore, the power required to stop the car along the horizontal road is 8 × 10⁵ watt.

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