Where are metals located on the periodic table?

Answer:

There are three possible chemical equations for the combustion of sulfur:

Explanation:

Combustion is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.

Sulfur iis a nonmetal, so the oxide formed is a nonmetal oxide.

The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.

The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).

Then you have three different equations for sulfur combustion:

1) Oxidation number +2:

Which when balanced is: 2S(g) + O₂(g) → 2SO(g)

2) Oxitation number +4:

That equation is already balanced.

3) Oxidation number +6:

Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)

The balanced equation for the combustion of sulfur is [tex]\[ \text{S}(s) + \text{O}_2(g) \rightarrow \text{SO}_2(g) \][/tex]

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Sulfur (S) is present as a diatomic molecule [tex](S_2)[/tex] when it reacts with oxygen [tex](O_2)[/tex] to form sulfur dioxide [tex](SO_2)[/tex]. The balanced equation considering the diatomic nature of sulfur is:

[tex]\[ \text{S}_2(s) + \text{O}_2(g) \rightarrow 2\text{SO}_2(g) \][/tex]

Here's the step-by-step process to balance the equation:

1. Start by writing the unbalanced equation with the correct formulas for the reactants and products:

[tex]\[ \text{S}_2 + \text{O}_2 \rightarrow \text{SO}_2 \][/tex]

2. Count the number of atoms of each element on both sides of the equation:

On the left side, there are 2 sulfur (S) atoms and 2 oxygen (O) atoms.

On the right side, there is 1 sulfur (S) atom and 2 oxygen (O) atoms.

3. To balance the sulfur atoms, we need to have the same number of sulfur atoms on both sides. Since there are 2 sulfur atoms on the left, we need to multiply the sulfur dioxide [tex](SO_2)[/tex] by 2 on the right side:

[tex]\[ \text{S}_2 + \text{O}_2 \rightarrow 2\text{SO}_2 \][/tex]

4. Now, count the number of oxygen atoms again. There are 2 oxygen atoms on the left and 4 on the right (2 molecules of [tex]SO_2[/tex], each with 2 oxygen atoms).

 5. To balance the oxygen atoms, we need to have 4 oxygen atoms on the left side as well. Since we already have 2 oxygen atoms in one [tex]O_2[/tex] molecule, we need to add another [tex]O_2[/tex] molecule:

[tex]\[ \text{S}_2 + 2\text{O}_2 \rightarrow 2\text{SO}_2 \][/tex]

6. Finally, count the atoms on both sides to confirm that the equation is balanced:

Left side: 2 S atoms and 4 O atoms.

Right side: 2 S atoms (2 molecules of [tex]SO_2[/tex], each with 1 S atom) and 4 O atoms (2 molecules of [tex]SO_2[/tex], each with 2 O atoms).

The equation is now balanced with 2 sulfur atoms and 4 oxygen atoms on both sides."

Answer:

Explanation:

Endothermic means that the process makes that the system (substance) absorbs heat energy from the surroundings. In this case the heat is supplied to the ice (from a flame for example). So, the ice is absorbing this heat.

In general, the phase change from solid (ice) to liquid is endothermic because the solid substance has a lower kinetic energy than the liquid particles. So, the solid must gain energy (which is supplied in the form of heat) to become liquid.

The reason why the solid particles have lower kinetic energy than liquid ones is that the particles vibrate and translates quicker in the liquid state than in the solid state.

Answer:

slant

Explanation:

Answer:

Explanation:

The half life of a radioactive atom is the time taken for half of the radioactive nuclei to disintegrate. The shorter the half life, the faster a radioactive nuclei decays.

Half life is often expressed as:

                               Half life = [tex]\frac{0.693}{λ}[/tex]

Where λ is the decay constant.

Answer:

The net ionic equation is: 3CO₃²⁻(aq) + 2Fe³⁺(aq) → Fe₂(CO₃)₃(s).

Explanation:

3(NH₄)₂CO₃(aq) + 2Fe(NO₃)₃(aq) → Fe₂(CO₃)₃(s) + 6NH₄NO₃(aq)

6NH₄⁺(aq) + 3CO₃²⁻(aq) + 2Fe³⁺(aq) + 6NO₃⁻ → Fe₂(CO₃)₃(s) + 6NH₄⁺(aq) + 6NO₃⁻(aq).

NH₄⁺(aq) and NO₃⁻(aq) are spectator ions that are not changed through the reaction and still dissolved in the medium, so they can be omitted to get the net ionic equation.

3CO₃²⁻(aq) + 2Fe³⁺(aq) → Fe₂(CO₃)₃(s).

Final answer:

The reaction between ammonium carbonate and iron(III) nitrate forms solid iron(III) carbonate and a solution of ammonium nitrate. The net ionic equation for this precipitation reaction is CO3^2-(aq) + Fe^3+(aq) → Fe2(CO3)3(s), which indicates the formation of the insoluble iron(III) carbonate.

Explanation:

When ammonium carbonate is combined with iron(III) nitrate, a reaction occurs where a solid precipitate and a solution of another compound are formed. According to the solubility rules, certain combinations of reactants will lead to the formation of an insoluble product, known as a precipitate. In this case, iron(III) carbonate is the precipitate, and ammonium nitrate remains in the solution.

To write the net ionic equation for this reaction, we must first write the balanced molecular equation and then the complete ionic equation. We can then identify and remove the spectator ions, which are ions that appear on both sides of the equation without undergoing a chemical change, to finally derive the net ionic equation.

The molecular equation is:

(NH4)2CO3(aq) + Fe(NO3)3(aq) → Fe2(CO3)3(s) + 3NH4NO3(aq)

The complete ionic equation is:

2NH4+(aq) + CO32-(aq) + Fe3+(aq) + 3NO3-(aq) → Fe2(CO3)3(s) + 3NH4+(aq) + 3NO3-(aq)

After identifying that the ammonium (NH4+) and nitrate (NO3-) ions are spectator ions, they can be eliminated from the equation, resulting in the net ionic equation:

CO32-(aq) + Fe3+(aq) → Fe2(CO3)3(s)

This net ionic equation represents the formation of the insoluble iron(III) carbonate precipitate from the aqueous reactants.

Answer:

H₂0[tex]_{(s)}[/tex]  +  heat  →  H₂O[tex]_{(l)}[/tex]  

Explanation:

An ENDOTHERMIC reaction is a chemical reaction in which heat is absorbed by the reactants. As such the product is usually cooler than the products. In the equation above (the answer), heat is on the reactant side of the equation thus indicating that heat is absorbed by the reactants.

On the other hand, in the first equation heat is on the product side of the equation which is consistent with an Exothermic reaction.

Answer:

[tex]\boxed{\text{A) Acceleration}}[/tex]

Explanation:

m/s is the unit for speed, so (m/s)/s is the rate of change of speed.  

The rate of change of speed is acceleration.

B), C), and D) are wrong. They all have the units of m/s.

Answer:

0.8 mol.

Explanation:

2Al + 3FeO → 3Fe + Al₂O₃,

It is clear that 2 mol of Al react with 3 mol of FeO to produce 3 mol of Fe and 1 mol of Al₂O₃.

Using cross multiplication:

2 mol of Al needs → 3 mol of FeO, from stichiometry.

??? mol of Al needs → 1.2 mol of FeO.

∴ The no. of moles of Al are needed to react completely with 1.2 mol of FeO = (2 mol)(1.2 mol)/(3 mol) = 0.8 mol.

Considering the reaction stoichiometry, 0.8 moles of aluminum are needed to react completely with 1.2 moles of FeO.

The balanced reaction is:

2 Al + 3 FeO → 3 Fe + Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Then you can apply the following rule of three:  if by stoichiometry 3 moles of FeO react with 2 moles of Al, 1.2 moles of FeO react with how many moles of Al?

[tex]amount of moles of Al= \frac{1.2 moles of FeOx2 moles of Al}{3 moles of FeO}[/tex]

amount of moles of Al= 0.8 moles

Finally, 0.8 moles of aluminum are needed to react completely with 1.2 moles of FeO.

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Answer:

1.332 g.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

∴ (n) of CO₂ = (n) of C₂H₆

∵ n = mass/molar mass

∴ (mass/molar mass) of CO₂ = (mass/molar mass) of C₂H₆

mass of CO₂ = 1.95 g, molar mass of CO₂ = 44.01 g/mol.

mass of C₂H₆ = ??? g, molar mass of C₂H₆ = 30.07 g/mol.

∴ mass of C₂H₆ = [(mass/molar mass) of CO₂]*(molar mass) of C₂H₆ = [(1.95 g / 44.01 g/mol)] * (30.07 g/mol) = 1.332 g.

The mass of 1 liter of C2H6 gas at the same temperature and pressure as the CO2 can be calculated using Avogadro's principle and the proportionality of molar masses. You set up a proportion using the molar masses of CO2 and C2H6 and the given weight of CO2 to solve for the weight of C2H6 gas.

First, you need to understand the concept of molar mass and Avogadro's principle. Avogadro's principle states that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules.

The molar mass of CO2 is approximately 44.01 g/mol. Given that one liter of CO2 gas weighs 1.95g, we can calculate the molar volume of a gas at the given temperature and pressure. Because the weights will be proportional, we can use the molar mass of C2H6 to find the weight of 1 liter of C2H6 gas.

Since the molar mass of C2H6 (ethane) is approximately 30.07 g/mol, you can set up the proportion as follows: 44.01 / 1.95 = 30.07 / X. Solving this equation gives you the weight of C2H6.

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Answer:

Explanation:

Thermally isolated system means that the system does not exchange thermal energy with the surroundings.

Hence, any thermal exchange, in virtue of the temperature difference of the aluminum and copper pieces, is between them.

In consequence, the law of conservation of energy states that the heat lost by the hot substance will be gained by the cold matter.

In equations, that is:

Now, the gain or loss or heat of a substance, Q, is related with the mass (m), the specific heat (Cs), and the cahnge of temperature (ΔT), per the equation:

∴ Q lost by aluminum = Q  gained copper ⇒

Under the reasoning assumption that the masses of aluminum and copper are equal, the equations is simplified to:

In words, since it is stated that  the specific heat of aluminum is more than double that of copper,  in order to keep the equality, ΔT of copper shall be more than double ΔT of aluminum.

Hence, the conclusion is that the object that experiences the greater temperature change is copper (the one with the lower specific heat), under the assumption that both objects have the same amount of matter (mass).

In the thermally isolated system, the copper experiences a greater temperature change than the aluminum because copper has a lower specific heat. It means that copper requires less energy to change its temperature compared to aluminum.

In a thermally isolated system like the one you've asked about, energy isn't gained or lost, but it does transfer among parts of the system until all parts are at the same temperature, which we call thermal equilibrium. Given that copper has a lower specific heat than aluminum, the same amount of heat transfer will cause a larger temperature change in the copper. This is due to the way specific heat works: substances with higher specific heat require more energy to change their temperature, while those with lower specific heat require less.

It's like running a race: if the specific heat is the distance of the race, the runner (or heat energy) with a shorter race (lower specific heat) will finish (change temperature) more quickly than a runner with a longer race (higher specific heat).

Specific heat is the amount of heat per unit mass required to raise the temperature of a substance by one degree Celsius. In this case, the aluminum, with a higher specific heat, would need more energy (heat) to alter its temperature. Since the energy is transferred from the aluminum (hot) to the copper (cold), the copper, with a lower specific heat, experiences more temperature change until thermal equilibrium is reached.

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Answer:

4 mol of KOH would produce 116.6 g of Mg(OH)₂

Explanation:

According to the following balanced equation:

One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.

using cross multiplication  

2 mol of KOH → 1 mol of Mg(OH)₂.

4 mol of KOH → ?? mol of Mg(OH)₂.

no of moles of  Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol

Now we can convert moles of  Mg(OH)₂ to grams using the formula

mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g

Answer:

0.139

Explanation:

First find how many moles of h2o give you 10g then use the mole ratio to find what mole of c3h8 is required to get you that number of moles

Answer:

0.139 moles of C3H8 must be reacted to form exactly 10.0 g of H2O

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

[tex]x=\frac{c*b}{a}[/tex]

It is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) and the rule of three to determinate the moles of C₃H₈ that must be reacted to form exactly 10.0 g of H₂O.  But first you must know the amount of moles that represent the 10 g of H₂O.

You know that:

Then,  the mass of H₂O is 2*1 g/mol + 16 g/mol= 18 g/mol

Then it is possible to apply a rule of three: if 1 mole of H₂O contains 18 grams, how many moles will contain 10 grams?

[tex]moles of H2O=\frac{10 grams*1 mole}{18 grams}[/tex]

moles of H₂O=0.556

Then, to determine the moles of C₃H₈ that must react to form exactly 10.0 g of H₂O it is possible to use a rule of three, as previously mentioned: if by stoichiometry 4 moles of H₂O are formed from 1 moles of C₃H₈, when are formed 0.55 moles of H₂O How many moles of C₃H₈ will be needed?

[tex]moles of C3H8=\frac{0.556molesofH2O*1molesofC3H8}{4molesofH2O}[/tex]

moles of C₃H₈= 0.139

Finally, 0.139 moles of C3H8 must be reacted to form exactly 10.0 g of H2O

To calculate the moles in 5L of hydrogen gas at STP, divide the volume in liters by the volume occupied by one mole of any gas at STP, which is 22.4 L/mol.

To calculate the number of moles in 5L of hydrogen gas at standard temperature and pressure (STP), you can apply the ideal gas law. To set up the calculation, use that at STP, 1 mole of a gas occupies 22.4 L. Use the following mathematical expression for your conversion:

Number of moles = Volume of gas (L) / Volume of 1 mole at STP (L/mol)

For your specific question:

Number of moles of H2 = 5 L / 22.4 L/mol

Make sure to leave your answer as a math expression with the correct units of L for liters and mol for moles.

Answer:

false

Explanation:

Answer:

Nitrogen

Explanation:

Because of its high solubility, water is considered to be a universal solvent.

A substance that displaces most compounds is known as a universal solvent. Because it dissolves more chemicals than any other solvent, water is known as the universal solvent. But no solvent, not even water, can dissolve all chemicals. According to the principle of "like dissolves like," polar solvents typically dissolve polar compounds, such as salts.

Nonpolar solvents may dissolve organic molecules like lipids and other nonpolar substances. Because of its polar nature, which gives each molecule a hydrophobic (water-fearing) and hydrophilic (water-loving) side, water dissolves more compounds than any other solvent.

The oxygen atom has a tiny negative electrical charge, whereas the side of the molecules with two hydrogen atoms carries a slight positive electrical charge. Water's polarisation makes it possible for it to draw in a wide variety of molecules. Water is able to split the substance into its ions due to the strong attraction to ionic molecules like sodium chloride or salt.

Therefore, water is considered a universal solvent.

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Answer:

c) 220 Fr

Explanation:

castle learning

The radioisotope which emits particles having the greatest mass will be 220Fr.

The radioactive isotopes of just an element are known as radioisotopes. Atoms with an unbalanced mixture of neutrons as well as protons, with extra energy in their nucleus, are also known as neutron-proton atoms.

The quantity of matter in a thing is measured by its mass.

When only the 3 most prevalent forms of ionizing radiation are considered, alpha particles get the most mass. The mass of an alpha particle is four times that of a proton as well a neutron, as well as the weight of a beta particle, is roughly 8,000 times that of a proton or neutron.

Therefore, 220 Fr will be having the greatest mass.

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Answer:

Strong acids.

Explanation:

HA + H₂O → H₃O⁺ + A⁻.

HA + H₂O ⇄ H₃O⁺ + A⁻.

Answer: strong acids

Explanation: for one the substance dissolves completely and acids only produce hydronium ions just like acids produce hydroxide ions.

Final answer:

OPTION A.

Using Charles's Law, the temperature of the balloon is converted to Kelvin and the law is applied to find the new volume when the temperature is increased from 60°C to 120°C. The new volume is approximately 118 cm³.

Explanation:

The question involves applying Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is constant. To find the new volume after an increase in temperature, we convert the temperatures from Celsius to Kelvin by adding 273. The initial temperature (T1) is thus 60°C + 273 = 333K and the final temperature (T2) is 120°C + 273 = 393K. The initial volume (V1) is 100 cm³.

Charles's Law is given by the formula V1/T1 = V2/T2, where V2 is the final volume. Applying this formula, we get:

V1/T1 = V2/T2
(100 cm³) / (333K) = V2 / (393K)

Multiplying both sides by 393K, we find the final volume V2:

V2 = (100 cm³) * (393K) / (333K)

This results in:

V2 ≈ 118 cm³

Therefore, the new volume of the balloon, after increasing the temperature from 60°C to 120°C, will be approximately 118 cm³.

Answer:

4.811 atm.

Explanation:

where, P is the pressure of the gas in atm (P = ?? atm).

V is the volume of the gas in L (V = 2.5 L).

n is the no. of moles of the gas in mol (n = 0.5 mol).

R  is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 20°C + 273 = 293 K).

∴ P = nRT/V = (0.5 mol)(0.0821 L.atm/mol.K)(293 K)/(2.5 L) = 4.811 atm.

1 -> theory

2-> law

3->  hypothesis

Answer:

12mLd

Explanation:

Given parameters:

Concentration of base, NaOH = 2.0M

Volume of acid, HCl = 24mL = 24 x 10⁻³L = 0.024L

Concentration of HCl = 1.0M

Unknown parameter

Volume of NaOH = ?

The equation of the reaction is NaOH + HCl → NaCl + H₂O

Method

1. Starting the known values, we find the number of moles of acid used. From the reaction equation , we know that:

            1 mole of NaOH reacts with 1 mole of HCl

We use the above to find the number of moles of base used

2. From the number of moles of base, we plug it into the equation below:

              Volume of NaOH = [tex]\frac{number of moles of NaOH}{concentration of NaOH}[/tex]

Solution

Number of moles of acid = concentration of acid x volume of acid

Number of moles = 1M x 0.024L = 0.024mol

              From the balanced equation we know that:

                   1 mole of NaOH reacts with 1 mole of HCl

                   Therefore, the number of moles of NaOH is 0.024mol

Using the equation below, we have:

Volume of NaOH = [tex]\frac{number of moles of NaOH}{concentration of NaOH}[/tex]

Volume of NaoH = [tex]\frac{0.024mol}{2.0M}[/tex]

Volume of NaOH = 0.012L = 12mL

Answer : The correct option is, [tex]\frac{10g\text{ of solute}}{100ml\text{ of solution}}\times 100\%[/tex]

Explanation :

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

[tex]\text{Percent solution by volume}=\frac{\text{Amount of solute}}{\text{Amount of solution}}\times 100\%[/tex]

Or,

[tex]\text{Percent solution by volume}=\frac{10g\text{ of solute}}{100ml\text{ of solution}}\times 100\%[/tex]

Hence, the correct option is, [tex]\frac{10g\text{ of solute}}{100ml\text{ of solution}}\times 100\%[/tex]

Answer:

Explanation:

You can calculate the oxidation number of most elements following some simple rules.

This is how you do it for chromium in K₂Cr₂O₇.

1) Rule: in a neutral compound the net oxidation number is zero (0).

Hence, sum of the oxidation numbers of K, Cr and O in K₂Cr₂O₇ is 0.

2) Rule: The most common oxidation number of oxygen in compounds, except in peroxides, is  2 ⁻ (negative 2).

3) Rule: the most common oxidation state of alkali metals is 1⁺ (positive 1)

4) Rule: multiply each oxidation state by the corresponding number of atoms in the compound (the subscripts)

          ↑         ↑       ↑

          K        Cr      O

Hence, the oxidation number of chromium in this compound is 6⁺.

The oxidation number of chromium in K2Cr2O7 (potassium dichromate) is +6. This is determined by knowing that potassium has an oxidation number of +1, oxygen has an oxidation number of -2, and the sum of the oxidation numbers of the chromium atoms must balance the charge contributed by potassium and oxygen to make the compound neutral.

The oxidation number of chromium in K2Cr2O7 requires some calculation using the rules of oxidation states. Firstly, potassium (K) has an oxidation number of +1, and each oxygen (O) has an oxidation number of -2. In the compound K2Cr2O7, there are two potassium atoms contributing a total of +2 to the charge of the compound. There are seven oxygen atoms each contributing -2, for a total of -14. Since the compound is neutral overall, the sum of the oxidation numbers of the chromium atoms must balance the negative charge contributed by the oxygen. Therefore, the total oxidation state for the two Cr atoms must be +12 in order to have a net charge of zero when added to the oxidation states of potassium and oxygen. Dividing this by two, since there are two chromium atoms, gives an oxidation number of +6 for each chromium atom.

Additionally, in the reduction half-reaction, Cr2O72- is reduced to Cr3+ with each chromium atom being in the +6 oxidation state initially. The chemical reaction involving the conversion of Fe2+ to Fe3+ supported by potassium dichromate provides further evidence that each chromium atom has an initial oxidation state of +6.

Answer:

A chemical reaction is a process that changes one set of chemicals into another set of chemicals. The elements or compounds that enter into the reaction are the ► reactants. The elements or compounds produced by the reaction are the ► products.

Mn’s oxidation number is +4 because the overall compound is neutral/has a 0 charge. So since O always has a -2 oxidation number except in special cases (ex: H2O2) and since oxidation numbers add up to the compound’s charge, x + -2(2) = 0 which means x = 4. thus the oxidation number is 4.

Final answer:

The oxidation number of Mn in MnO2 is +4. This is determined by balancing the total negative charge of -4 from the two oxygen atoms with the positive charge from manganese which must balance to zero in a neutral compound.

Explanation:

The oxidation number of Mn in MnO2 is +4. When determining oxidation numbers, remember that the sum of oxidation numbers in a neutral compound must equal zero. Since each oxygen atom has an oxidation number of -2, and there are two oxygen atoms totaling -4, manganese must have an oxidation number of +4 to balance the charge.

MnO2 is manganese(IV) oxide, indicating that manganese is in the +4 oxidation state. The formula reflects that there are four total electrons that have been transferred to oxygen atoms in this compound, making it less paramagnetic than when manganese is in the +3 state, as seen in manganese(III) oxide, Mn2O3.

Answer:

[tex]\boxed{\text{30 mL}}[/tex]

Explanation:

Step 1. Calculate the moles of NaOH

[tex]n = \text{60.0 kg} \times \dfrac{\text{0.0010 mol}}{\text{1 kg}} = \text{0.0600 mol}[/tex]

Step 2. Calculate the volume of NaOH

[tex]V = \text{0.0600 mol} \times \dfrac{\text{1 L}}{\text{2.0 mol}} = \text{0.030 L} = \text{30 mL}\\\\\text{The lethal volume of NaOH is } \boxed{\textbf{30 mL}}[/tex]

Final answer:

To find the lethal volume of a 2.0M NaOH solution for a 60kg person, calculate the total lethal dose (0.060 mol) and then divide by the concentration (2.0M), resulting in 30 mL.

Explanation:

The question involves calculating the lethal volume of a 2.0M NaOH solution for a 60kg person based on the lethal dose (LD50) of NaOH, which is 0.0010 mol/kg. First, we need to determine the total lethal dose of NaOH for the person:

Therefore, the lethal volume of a 2.0M NaOH solution for a 60kg person is 30 mL.

Answer:

0.616 m.

Explanation:

m = (no. of moles of solute)/(mass of the solvent (kg))

m = (mass/molar mass) NaCl / (mass of the solvent (kg))

mass of NaCl = 3.6 g, molar mass of NaCl = 58.44 g/mol, mass of water = 100.0 g = 0.1 kg.

m = (mass/molar mass) NaCl / (mass of the solvent (kg)) = (3.6 g / 58.44 g/mol) / (0.1 kg) = 0.616 m.

The molality of a solution if a chemist adds 3.6 grams of sodium chloride to 100.0 g of water is 0.615m.

Molality is defined as the no. of moles of solute dissolved in a 1.0 kg of the solvent.

m = no. of moles of solute ÷ mass of the solvent (kg)

no of moles of NaCl = 3.6g ÷ 58.5g/mol = 0.0615mol

Molality = 0.0615mol ÷ 0.1kg

Molality = 0.615m

Therefore, the molality of a solution if a chemist adds 3.6 grams of sodium chloride to 100.0 g of water is 0.615m.

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Answer:

Reaction A:

Reaction B:

Explanation:

Here are some common rules for assigning oxidation states.

For this question, only the rule about neutral compounds, oxygen, and group one metals (K in this case) are needed.

Oxidation states in KNO₃:

Similarly, for KNO₂:

Oxygen is the only element in O₂. As a result,

[tex]\rm\stackrel{+1}{K}\stackrel{\bf +5}{N}\stackrel{\bf -2}{O}_3 \to \stackrel{+1}{K}\stackrel{\bf+3}{N}\stackrel{\bf -2}{O}_2 + \stackrel{\bf 0}{O}_2[/tex].

The oxidation state on two oxygen atoms in KNO₃ increases from -2 to 0. These oxygen atoms are oxidized. KNO₃ is also the reducing agent.

The oxidation state on the nitrogen atom in KNO₃ decreases from +5 to +3. That nitrogen atom is reduced. As a result, KNO₃ is also the oxidizing agent.

Apply these steps to reaction A.

H₂:

O₂:

H₂O:

[tex]\rm \stackrel{}{2}\; \stackrel{\bf 0}{H}_2 + \stackrel{\bf 0}{O}_2\stackrel{}{\to} \stackrel{}{2}\;\stackrel{\bf +1}{H}_2\stackrel{\bf -2}{O}[/tex].

The oxidation state on oxygen atoms decreases from 0 to -2. Those oxygen atoms are reduced. O₂ is thus the oxidizing agent.

The oxidation state on hydrogen atoms increases from 0 to +1. Those hydrogen atoms are oxidized. H₂ is thus the reducing agent.

In the reaction 2H₂(g) + O₂(g) → 2H₂O(l), hydrogen is oxidized and acts as the reducing agent, while oxygen is reduced and acts as the oxidizing agent. Option A is correct.

To identify which species is oxidized and which is reduced in the given reaction 2H₂(g) + O₂(g) → 2H₂O(l), we start by assigning oxidation numbers. Hydrogen is usually +1 (except in metal hydrides, where it is -1), and oxygen is usually -2 (except in peroxides, where it is -1, and in compounds with fluorine, where it is positive). In molecular hydrogen (H₂) and molecular oxygen (O₂), the oxidation numbers are 0 since they are elemental forms.

In water (H₂O), hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2. Going from 0 in H₂ to +1 in H₂O, hydrogen is oxidized (loses electrons), and going from 0 in O₂ to -2 in H₂O, oxygen is reduced (gains electrons).

Therefore, hydrogen is the reducing agent (it itself gets oxidized), and oxygen is the oxidizing agent (it itself gets reduced).

Hence, A. is the correct option.

The answer is in the photo, but a 0,168 M HCN doesn’t have a pH of 3,15, but 5. HCN real Ka is 6,17*10^(-10).

Answer:

The real answer is 3.00x10^-6

Explanation:

Fill in 3.00 and then -6