Which cells or organs are considered to be part of both the immune and lymphatic systems? Select all that apply.


arteries


lymph nodes


capillaries


tonsils and adenoids


veins


thymus

Answer:

Identify arrows pointing to bonding electrons.

✔ a, b, d

Identify arrows pointing to nonbonding electrons.

✔ c

Identify arrows pointing to structures containing sigma bonds.

✔ a, b, d

Identify arrows pointing to structures containing pi bonds.

✔ a

Explanation:

On edg 2020

Answer:

Net force = 3640 N

Explanation:

From first equation of motion

V = U + at

4.5 = 22 + 6.75a

( 4.5-22) ÷ 6.75 = a

acceleration (a) = -2.6m/s^2 ( negative sign shows deceleration, but actual acceleration is 2.6)

But Force = mass × acceleration

Force = 1400 × 2.6

Force = 3640 N

Answer:

35 N

Explanation:

Force, F = ma where m = mass = 7 kg and a = acceleration = 5 m/s².

So, F = ma = 7 kg × 5 m/s² = 35 N

Final answer:

To find the unknown force applied to an object with a mass of 7 kg accelerating at 5 m/s², use the formula F = ma to calculate it as 35 N.

Explanation:

The unknown force applied to the object with a mass of 7 kg can be calculated using the formula F = ma.

Given mass (m) = 7 kg and acceleration (a) = 5 m/s²

Substitute the values into the formula:  F = (7 kg) (5 m/s²) = 35 N

Therefore, the unknown force applied to the object is 35 Newtons.

Answer:

Work done is 12.3 J

Explanation:

We have,

Mass of puck, m = 0.35 kg

Force of friction acting on the puck when it slides is 0.15 N

Distance travelled by the puck is 82 m.

It is required to find the work done on the puck. Finally the puck comes to rest and the force of friction is acting on it. It means the applied force is 0.15 N. Work done is given by

[tex]W=Fd\\\\W=0.15\times 82\\\\W=12.3\ J[/tex]

The work done on the puck is 12.3 J.

Answer:

Fundamental frequency is 70.12 m

Explanation:

For an open organ pipe, the fundamental frequency is given by :

[tex]f=\dfrac{nv}{2l}[/tex]

n = 1 for fundamental frequency

v is speed of sound in air, v = 345 m/s

l is length of open organ pipe, l = 2.46 m

Substituting values in above formula. So,

[tex]f=\dfrac{1\times 345}{2\times 2.46}\\\\f=70.12\ Hz[/tex]

So, the fundamental frequency of this pipe is 70.12 m.

Final answer:

The fundamental frequency of a 2.46 m long open organ pipe, with air speed 345 m/s, is approximately 70.12 Hz.

Explanation:

To find the fundamental frequency of an open organ pipe, we can use the formula for the fundamental frequency of a pipe that is open at both ends, which is f1 = v / (2*L), where f1 is the fundamental frequency, v is the speed of sound in the pipe, and L is the length of the pipe.

In this case, the organ pipe is 2.46 meters long, and the speed of the air in the pipe is given as 345 meters per second. Plugging these values into the formula, we get:

f1 = 345 m/s / (2 * 2.46 m) = 345 m/s / 4.92 m = 70.12 Hz

Therefore, the fundamental frequency of this 2.46 m long open organ pipe is approximately 70.12 Hz.

Answer:

6/3 LI

Explanation:

The average speed is 1.54 miles per hour.

As we know that,

              Average speed [tex]=\frac{Distance}{time}[/tex]

Given that Timmy and Sarah travel 5 miles in  three hours and 15 minutes.

Time [tex]=3+\frac{15}{60} =\frac{13}{4}hours[/tex]

    Average speed [tex]=5\div \frac{13}{4} =5*\frac{4}{13}=1.54 miles/hour[/tex]

Thus, The average speed is 1.54 miles per hour.

Learn more:

https://brainly.com/question/4931057

Answer:

25 W

Explanation:

Power: This can be defined as the rate at which work is done. The S.I unit of power is Watt (W).

The expression of power is given as

Power = work output/time

P = W/t................ Equation 1

Given: W = 25 J. t = 1s

Substitute into equation 1

P = 25/1

P = 25 W

Hence the output power of the motor is 25 W

Answer:

The power is 25 W

Explanation:

Given;

work done by motor output. E = 25 J

Time taken to complete this task, t = 1 s

Power is the amount of work done per unit time or energy per unit time.

The amount of power developed by the motor, can be calculated as follows using the formula below;

[tex]Power = \frac{Energy}{time} = \frac{25}{1} = 25 \ W[/tex]

Therefore, the amount of power developed by the motor in the given time is 25 W.

Answer:

uekdjdbrjrnkfkdkfkff

Explanation:

E=mc(tetha)

=15(3.4x105)(0)

=0joules

Answer:

The energy of a photon is directly proportional to it's frequency

Answer:

B. The energy of the photon is directly proportional to frequency.

Explanation:

Faster to hit the ground because if so yes?

Answer:

the object is kept away from the focus of a convex lens. it form a real but inverted image of the object on the opposite side of the lens.

Mechanical Energy = PE + KE

PE: mgh = 200 x 9.8 x 18 = 35280

PE: 35280 Joules

KE: 1/2mv^2 = 1/2 x 200 x 16^2 = 25600

KE: 25600 Joules

ME: 35280 + 25600

ME: 60,880J

Answer:

1) Charge chord resistance is 75 Ω

2) Charge chord resistance is 6.33 Ω

Explanation:

1) To answer the question, we note that the the formula voltage is found as follows;

V = IR

Therefore,

[tex]R = \frac{V}{I} = \frac{120}{1.6} = 75 \, \Omega[/tex]

2) Where the voltage, V = 19.5 V and the current, I = 3.33 A, we have;

Initial resistance R₁ = 19.5 V/(3.33 A) = 5.86 Ω

However, to reduce the current to 1.6 A, we have;

[tex]R_T = \frac{19.5}{1.6} = 12.1875 \ \Omega[/tex]

Therefore, where the resistance is found by the sum of the total resistance we have;

[tex]R_T[/tex] = R₁ + Charge chord resistance

∴ 12.1875 = 5.86 + Charge chord resistance

Hence, charge chord resistance = 6.33 Ω

(1) The resistance in the charge cord at the given standard voltage is 75 ohms.

(2) The resistance in the cord that accomplishes the given voltage and current is 6.33 ohms.

The given parameters;

The resistance in the charge cord at the given standard voltage is calculated as follows;

[tex]V = IR\\\\R = \frac{V}{I} \\\\R = \frac{120}{1.6} \\\\R = 75 \ ohms[/tex]

The initial resistance when the voltage is 19.5 V and current is 3.33 A;

[tex]R = \frac{V}{I} \\\\R = \frac{19.5}{3.33} \\\\R = 5.86 \ ohms[/tex]

The total resistance when the current in cord is calculated as;

[tex]R = \frac{V}{I} \\\\R = \frac{19.5}{1.6} \\\\R = 12.19 \ ohms[/tex]

The internal resistance is calculated as;

[tex]r = 12.19 - 5.86\\\\r = 6.33 \ ohms[/tex]

Learn more here:https://brainly.com/question/21369482

Answer:

same as the potential energy possessed at top

= 0.5×9.8×8

= 39.2 joules

Answer: The answer is 40 J.

Explanation: I did it just now.

The smallest size plane mirror he can use is 3 feet tall, ensuring he can see his entire image reflected in the mirror

To see his entire image in a plane mirror, the mirror needs to be at least as tall as the man's height. However, since only half of his height is required for the mirror, the smallest size plane mirror he can use is half his height.

Given that the man is 6 feet tall, the smallest size plane mirror he can use to see his entire image would be [tex]\( \frac{6}{2} = 3 \)[/tex] feet tall. Therefore, the smallest size plane mirror he can use is 3 feet tall.

Answer:

The flow of fluid molecules in fluid mechanics is synonymous to the flow of electrons in electricity.

Explanation:

The flow of fluid molecules in fluid mechanics is synonymous to the flow of electrons in electricity. Water, when it is falling by the force of gravity, can be used to turn turbines and generators that produce electricity.

A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy. Hydroelectric power plants are the most efficient means of producing electric energy.

Discussing gravity and fluid flows is beneficial when learning about electricity due to the analogies between these phenomena, which aid in understanding the behavior of electric charges and circuits. These comparisons help visualize electrical concepts and deepen comprehension of various electrical phenomena and technologies.

Discussing gravity and fluid flows when learning about electricity is crucial due to the similarities in the concepts governing all these phenomena. For instance, electricity is often taught through the analogy of water flow in pipes, where electric current, voltage, and resistance are likened to the flow rate, pressure difference, and pipe size in fluid dynamics. This analogy helps students visualize and understand how electric charges behave in circuits, just as water flows through a system under the influence of gravity. Moreover, the concept of gravitational potential energy in physics is analogous to electric potential energy in electromagnetism, where masses and charges experience forces due to their respective fields. Understanding these analogies deeply enriches the comprehension of electrical phenomena and leads to insights into the behavior of electricity in various mediums, such as solids, liquids, and gases.

Examples such as lightning, the formation of bluish crust on car battery terminals, and the need for electrolytes in sports drinks can be understood better by studying the flow of charged particles. These particles, like fluid in the presence of a gravitational field, respond to electric fields by moving from areas of high potential to low potential, analogous to water flowing downward due to gravity. This comparison between electric and gravitational fields lays a solid foundation for exploring more complex electrical behaviors and technologies.

Answer:

it increases too as it bend away from the normal line

Answer:

Force, F = 622.28 N

Explanation:

It is given that,

Torque, [tex]\tau=100\ N-m[/tex]

Angle between force and displacement, [tex]\theta=40^{\circ}[/tex]

Distance, d = 25 cm = 0.25 m

We need to find the force required to produce the torque. Torque produced by an object is given by :

[tex]\tau=Fd\sin\theta[/tex]

F is force required to produce torque

[tex]F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N[/tex]

So, applied force is 622.28 N.

The net rate of energy flow from the tungsten sphere can be calculated using the modified Stefan-Boltzmann equation, taking into account the sphere's emissivity, surface area and temperature, as well as the temperature of the surroundings. After calculating, we have the net rate of heat transfer.

The net flow rate of energy from an object, in this case a tungsten sphere, can be calculated using the modified Stefan-Boltzmann equation which is suitable for net rate of heat transfer by radiation. The formula used is Qnet = σeA(T₁⁴ - T₂⁴), where σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ J/s.m².K⁴), e is the emissivity (0.35 for tungsten), A is the surface area of the sphere (πr² with r being the radius of the sphere), and T₁ and T₂ are the temperatures of the sphere and the surroundings respectively, converted to Kelvin.

First, we convert the Celsius temperatures to Kelvin by adding 273.15 to each temperature, making T₁ = 298.15 K and T₂ = 268.15 K. Then, finding the surface area, we get A = 4πr² = 4.90 m² with r = 0.25 m. Substituting these values into the equation gives us Qnet = (5.67 × 10⁻⁸ J/s.m².K⁴)(0.35)(4.90 m²)[(298.15 K)⁴ - (268.15 K)⁴] which, when calculated, gives the net rate of heat transfer by radiation from the tungsten sphere.

https://brainly.com/question/34117184

#SPJ11

Final answer:

The net flow rate of energy from a tungsten sphere in a cooler room can be calculated using the Stefan-Boltzmann law; accounting for emissivity, surface area, and the difference in the fourth powers of the absolute temperatures of the sphere and its surroundings.

Explanation:

The student's question regarding the net flow rate of energy out of a tungsten sphere enclosed in a room with cooler walls can be answered using the Stefan-Boltzmann law for thermal radiation which states that the power radiated from an object is proportional to its emissivity (e), the Stefan-Boltzmann constant (σ), the surface area of the object (A), and the fourth power of its absolute temperature (T) in kelvins. For our purposes, the net power radiated is the difference in power radiated by the sphere and the power absorbed from the surroundings. To find the surface area (A) of the sphere we use the formula 4πr2 where r is the radius of the sphere. Then, we transform the temperatures from Celsius to Kelvins and plug our values into the equation P = eσA(T4 - T04) to find the net flow rate of energy out of the sphere.

Answer:

Nitrogen

Explanation:

Answer:

D

Explanation:

I will use my guess because I can. Unless you're the same person just spamming their question but if not, don't worry about it. they will crash at 5 m/s.

Final answer:

To analyze an elastic collision, one should use the momentum and kinetic energy conservation equations, simplifying them if one object is initially at rest. Inelastic collisions involve the conservation of momentum only and require experimental measures to determine energy dissipation.

Explanation:

An elastic collision is a type of collision where both momentum and kinetic energy are conserved. To solve a problem involving an elastic collision, one must use two independent equations: the conservation of momentum equation and the conservation of kinetic energy equation. If one of the objects is initially at rest, as stated in the question, the equations become simpler. We can set the initial velocity of the second object to zero, and then combine the equations algebraically to solve for the final velocities of both objects.

In the case of an inelastic collision, only momentum is conserved, and some kinetic energy is transformed into other forms of energy, such as heat or sound. To analyze changes in kinetic energy for an inelastic collision, one could modify an experiment to measure velocities before and after the collision and then calculate the kinetic energy to determine the fraction of mechanical energy dissipated.

In summary, analyzing an elastic collision typically involves mathematical calculations of velocities and kinetic energy, while an inelastic collision would be explored through experiments and calculations focusing on energy dissipation. If making graphical representations, one would plot momentum and kinetic energy before and after the collision to verify these relationships.

Answer:

Explanation:

hope this provides you with some clarity :)

To find the equivalent resistance of a series circuit consisting of resistors with values 1.1 ohms, 11 ohms, 110 ohms, and 1100 ohms, simply add the values together, resulting in an equivalent resistance of 1222.1 ohms.

The question involves calculating the equivalent resistance of a series circuit containing four resistors with the specified values of 1.1 ohms, 11 ohms, 110 ohms, and 1100 ohms. In a series circuit, the total or equivalent resistance can be found by simply adding up all the resistance values of the individual resistors.

To find the equivalent resistance of the circuit, we add the values of the resistors:

The sum of these values gives us the total resistance:

1.1 + 11 + 110 + 1100 = 1222.1 ohms.

Therefore, the equivalent resistance of the series circuit is 1222.1 ohms.

Answer:

The distance between charges is 0.33 m.

Explanation:

We have,

The charge on each sphere is [tex]2.5\times 10^{-6}\ C[/tex]

Force between charges is 0.5 N

It is required to find the distance between spheres. The force between two charges is called electrical force. The force between them is given by :

[tex]F=\dfrac{kq^2}{r^2}[/tex]

r is distance between charges

[tex]r=\sqrt{\dfrac{kq^2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times (2.5\times 10^{-6})^2}{0.5}} \\\\r=0.33\ m[/tex]

So, the distance between charges is 0.33 m.

Final answer:

To find the distance between two spheres with identical charges of 2.5×10-6 C experiencing a 0.50 N force, use Coulomb's Law and rearrange it to solve for the distance, which is the square root of the product of Coulomb's constant, the magnitude of the charges, divided by the force.

Explanation:

The distance between two spheres, each with a charge of 2.5×10-6 C, when the force between them is 0.50 N, can be calculated using Coulomb's Law. The formula for Coulomb's Law is F = k × (|q1×q2|) / r2, where F is the force between the charges, k is Coulomb's constant (approximately 8.99×109 N·m2/C2), q1 and q2 are the charges, and r is the distance between the centers of the two charges.

By rearranging the formula to solve for r, we get r = √(k × (|q1×q2|) / F). Plugging in the values we have:

The charge on each sphere is 2.5* 10^(-6)\ C

Force between charges is 0.5 N

It is required to find the distance between spheres. The force between two charges is called electrical force. The force between them is given by :

F=(kq^2)/(r^2)

r is distance between charges

r=\sqrt{(kq^2)/(F)} \n\nr=\sqrt{(9* 10^9* (2.5* 10^(-6))^2)/(0.5)} \n\nr=0.33\ m

So, the distance between charges is 0.33 m.

Answer:Mercury, Venus, Earth and Mars.

Explanation: The surfaces of asteroids and the rocky, ice covered moons of the outer gas planets are cratered as well.

Answer:

red light > electron > proton > baseball > person > car

Explanation:

To calculate the wavelength associated to each object, you use the Broglie's relation:

[tex]\lambda=\frac{h}{mv}\\\\[/tex]

h: Planck,s constant = 6.62*10^-34 Js

m: mass

v: velocity

For each object you use an average values of its mass.

person:

mass = 80kg

[tex]\lambda=\frac{6.62*10^{-34}Js}{(80kg)(4.5m/s)}=1.83*10^{-36}m[/tex]

electron:

mass = 9.1*10^{-31}kg

[tex]\lambda=\frac{6.62*10^{-34}Js}{(9.1*10^{-31}kg)(0.01c)}\\\\\lambda=\frac{6.62*10^{-34}Js}{(9.1*10^{-31}kg)(0.01(3*10^{8}m/s))}\\\\\lambda=2.42*10^{-10}m[/tex]

red light:

In this case you use the following formula:

[tex]\lambda=\frac{c}{f}=\frac{3*10^8m/s}{4.3*10^{14}Hz}=6.97*10^{-7}m\approx700nm[/tex]

proton:

mass = 1.67*10^{-27}kg

[tex]\lambda=\frac{6.62*10^{-34}Js}{(1.67*10^{-27}kg)(0.01(3*10^8m/s))}\\\\\lambda=1.32*10^{-13}m[/tex]

car:

mass = 1500kg

[tex]\lambda=\frac{6.62*10^{-34}Js}{(1500kg)(27m/s)}=1.63*10^{-38}m[/tex]

baseball:

mass = 0.145kg

[tex]\lambda=\frac{6.62*10^{-34}Js}{(0.145kg)(41m/s)}\\\\\lambda=1.11*10^{-34}m[/tex]

hence, by comparing the wavelengths of the objects you have:

red light > electron > proton > baseball > person > car

Answer:

expected acceleration= 68.7/38.7=1.77 m/s^2

witnessed acceleration = 1.44/3.81 = 0.37 m/s^2

difference = 1.4m/s^2

so friction = 38.7× 1.4= 54.18 N

The magnitude of force does friction evert on the mower is 54.07 N.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given parameters:

Mass of the lawnmower: M = 38.7 kg.

Force applied on it: F = 68.7 N.

Final speed of the lawnmower: v = 1.44 m/s.

Time taken: t = 3.81 s.

Then, acceleration of the lawnmower: a = increase in speed/time

= 1.44/3.81 m/s² = 0.38 m/s².

Hence, resisting friction force = applied force - ma

= 68.7 N - 38.7 × 0.38 N

=  54.07 N.

Hence, the magnitude of force does friction evert on the mower is 54.07 N.

Learn more about speed here:

https://brainly.com/question/28224010

#SPJ2