I believe it's hypoxia for your tissues and hypoxemia for your blood.
Answer:
Anemia
Explanation:
Edge 2021
About what is Rigel's surface temperature?
Answer:
it is bigger than, a higher temperature , and 11,000
Explanation:
Rigel is a star with a surface temperature of about 12,100 Kelvin, yielding a blue-white color due to its high surface temperature.
Explanation:The surface temperature of Rigel, a supergiant star, is approximately 12,100 Kelvin. This temperature contributes to Rigel's blue-white color, as higher surface temperatures in stars result in shorter wavelength light, which falls towards the blue end of the color spectrum.
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Physics question, please help?
A cue ball with mass 170 g hits the stationary number 8 ball, which has mass 160 g. The cue ball and the 8 ball move with a speed of 0.2 m/s and 0.3 m/s respectively after the collision. What was the speed of the cue ball before the collision?
A) 0.2502 m/s
B) 0.4823 m/s
C) 0.5008 m/s
D) 0.5319 m/s
0.4823 m/s
The initial velocity u1 of the ball=0
From the law of conservation of linear momentum.
m1u1+m2u2=m1v1+m2v2
(160×0)+(170×u1)=(160×0.3)+(170×0.2)
u1=0.4823m/s
The speed of the cue ball before the collision is approximately 0.5319 m/s.
Explanation:Before the collision, we can use conservation of momentum to find the speed of the cue ball. In an isolated system, the total momentum before the collision is equal to the total momentum after the collision.
Let's denote the initial velocity of the cue ball as v1 and the initial velocity of the 8 ball as v2. The momentum before the collision is given by:
(mass of cue ball) x (velocity of cue ball) + (mass of 8 ball) x (velocity of 8 ball)
The total momentum after the collision is:
(mass of cue ball + mass of 8 ball) x (velocity of cue ball + velocity of 8 ball)
Using the given values, we know that the cue ball and 8 ball move with speeds of 0.2 m/s and 0.3 m/s, respectively, after the collision. Plugging these values into the equations, we can solve for v1 to find the speed of the cue ball before the collision.
The speed of the cue ball before the collision is approximately 0.5319 m/s.
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Which shows the correct reflected ray? Question options: A B C D
I think the answer is D because the law of reflection is the angle of incidence is equal to the angle of reflection.
Answer:
D
Explanation:
The law of reflection states that:
- The incident ray and the reflected ray lie on the same plane
- The angle of reflection is equal to the angle of incidence
The angle of incidence is the angle between the direction of the incident ray and the normal to the surface, while the angle of reflection is the angle between the direction of the reflected ray and the normal to the surface.
From the figure, we see that the only situation where the angle of reflection is equal to the angle of incidence is ray D.
The law of reflection states that the angle of reflection is equal to the angle of incidence, with these angles measured relative to a line perpendicular to the reflecting surface. Mirrors adhere precisely to this law, reflecting light at specific angles. Your choice, D, is correct if it shows the reflected light ray making the same angle with the normal as the incident light ray.
Explanation:You are correct in thinking that the answer is D. The law of reflection stipulates that the angle of incidence (the angle at which incoming light hits a surface) is equal to the angle of reflection (the angle at which light is reflected). These angles are always measured relative to a line perpendicular to the surface, called the normal. In your case, the correct answer would be an option where the reflected ray is at the same angle to the normal as the incident ray. If D shows that, then D is indeed the correct answer.
Mirrors, having smooth surfaces, adhere to this law of reflection perfectly, reflecting light at specific angles. Rough surfaces, on the other hand, diffuse light, causing it to scatter in many directions. This is why we can see clearly in mirrors but not on rough surfaces.
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At what age is the human brain fully developed?
25 is the correct answer
The brain is fully developed at the age of 25
Study the image below. What interaction causes the water to spread as they pass through the rock opening?
absorption
diffraction
reflection
refraction
diffraction ;-)
When water passes through small hole this type of phenomena happens.
diffraction interaction causes the water to spread as they pass through the rock opening. Hence option B is correct.
What is diffraction ?Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the aperture or obstruction. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise measurements of the phenomena in 1660.
On the registration plate, an infinite number of spots (three are illustrated) along length d project phase contributions from the wavefront, resulting in a continually changing intensity theta.
The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomena in classical physics. When a wave from a certain direction, the distinctive bending pattern is most obvious.
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A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60cm apart. The string is observed to form a standing wave with three antinodes when driven at a frequency of 420 Hz. What are (a) the frequency of the fifth harmonic of this string and (b) the tension in the string?
(a) 700 Hz
For standing waves on a string, the number of antinodes (n) corresponds to the order of the harmonic. So, three antinodes corresponds to the third harmonic. Also, the frequency of the nth-harmonic is the nth-integer multiple of the fundamental frequency, so we have:
[tex]f_3 = 3 f_1 = 420 Hz[/tex]
where [tex]f_1[/tex] is the fundamental frequency. Solving for f1, we find
[tex]f_1 = \frac{420 Hz}{3}=140 Hz[/tex]
And so now we can find the frequency of the 5th-harmonic:
[tex]f_5 = 5 f_1 = 5 (140 Hz)=700 Hz[/tex]
(b) 56.4 N
The fundamental frequency of a string is given by:
[tex]f_1 = \frac{1}{2L} \sqrt{\frac{T}{\mu}}[/tex]
where we have:
L = 60 cm = 0.60 m is the length of the string
[tex]\mu = 2.0 g/m = 0.002 kg/m[/tex] is the linear density
T = ? is the tension in the string
Solving the formula for T and using the fundamental frequency, f1=140 Hz, we find
[tex]T=\mu (2Lf_1)^2=(0.002 kg/m)(2(0.60 m)(140 Hz))^2=56.4 N[/tex]
The frequency of the fifth harmonic of the string is 700 Hz, and the tension in the string is 56.448 N.
Explanation:The question pertains to harmonic frequencies and tension in instruments, particularly a guitar string. Using the information given, we will apply the principles of standing waves on the string, wave speed derived from linear mass density and tension, and harmonic frequencies.
(a) If you're looking for the frequency of the fifth harmonic, note that the frequency of a particular harmonic is that harmonic number times the fundamental frequency. In this case, the string shows a standing wave with three antinodes, which refers to the third harmonic. So, the third harmonic frequency is 420 Hz; thus, the fundamental frequency is 420 Hz / 3 = 140 Hz. So, the frequency of the fifth harmonic is 5 times the fundamental frequency = 5*140 Hz = 700 Hz.
(b) To determine the tension in the string, you must first calculate the wave speed. The wave speed (Vw) can be derived from the formula for the frequency of a string, Vw=2Lf, where L is the length of the string in meters and f is the fundamental frequency. Here, L=0.6 m and f= 140 Hz, hence Vw = 2*(0.6m)*(140Hz) = 168 m/s. Given that wave speed is also calculated via the square root of tension (T) divided by linear mass density (μ), you can rearrange this formula to solve for T. This gives you T = (Vw)^2 * μ . The linear density is given as 2.0 g/m, but we need to convert it to kg/m to match the wave speed unit, so μ = 0.002 kg/m. Plugging in the values we find the tension: T = (168 m/s)^2 * 0.002 kg/m = 56.448 N.
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According to recent Kepler mission results, how common are planets around other stars?
After 9 years of spectacular findings, NASA shut down the Kepler space telescope at the end of last October (2018).
From 2009 to 2018, the Kepler mission found more than 2,600 planets in other "solar systems" ... in orbit around other stars besides our Sun. AND, at the time the mission ended, (5 months before the night I'm writing this), there were still more than 2,000 sets of data still to be analyzed.
The results suggest that having a family of planets is really not an unusual thing for a star. Indeed, the rare, unusual stars may be the few that don't have planets orbiting them.
Planets around other stars are probably so common that they are the rule, and not the exception to the rule.
A plane is flying east at 135 m/s. The wind accelerates it at 2.18 m/s2 directly northeast. After 18.0 s, what is the direction of the displacement of the plane?
the plane was flying at 2,691. 33 m at 5.32°
What are beats? A. periodic fluctuations in the velocity of sound waves B. periodic fluctuations in the wavelength of sound waves C. periodic fluctuations in the intensity of sound waves D. periodic fluctuations in the frequency of sound waves
The answer is
C. periodic fluctuations in the intensity if sound waves.
Answer:
D. periodic fluctuations in the frequency of sound waves
Explanation:
Beat is referred to the phenomena that occurs when to sound waves interfer with each other and they have different frequencies.
This difference is what creates a beating, wich in sound waves manifest as high and low sounds, this as a result of the oscilating frequency .
When a system is heated, heat is _______________ by the system. The amount of heat added is given a _______________ sign. When a system is cooled, heat is _______________ by the system. The amount of heat is given a _______________ sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done _______________ the system and is given a _______________ sign. If a gas is compressed, then work is done _______________ the system. This work is given a _______________ sign.
First of all, we need to write the First Law of thermodynamics assigning the correct sign convention:
[tex]\Delta U = Q+W[/tex]
where
[tex]\Delta U[/tex] is the change in internal energy of the system
Q is the heat absorbed/released
W is the work done
and the signs are assigned based on whether there is an increase in the internal energy or not. Therefore:
Q is positive if it is absorbed by the system (because internal energy increases)
Q is negative if it is released by the system (because internal energy decreases)
W is negative if it is done by the system on the surrounding (because internal energy decreases)
W is positive if it is done by the surrounding on the system (because internal energy increases)
Using these definitions, we can now fill the text of the question:
When a system is heated, heat is ABSORBED by the system. The amount of heat added is given a POSITIVE sign. When a system is cooled, heat is RELEASED by the system. The amount of heat is given a NEGATIVE sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done BY the system and is given a NEGATIVE sign. If a gas is compressed, then work is done ON the system. This work is given a POSITIVE sign.
Answer:
When a system is heated, heat is ABSORBED by the system. The amount of heat added is given a POSITIVE sign. When a system is cooled, heat is RELEASED by the system. The amount of heat is given a NEGATIVE sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done BY the system and is given a NEGATIVE sign. If a gas is compressed, then work is done ON the system. This work is given a POSITIVE sign.
Explanation:
What type of device is a car engine?
A.A heat pump that uses heat to do work
B.A heat engine that uses work to move heat
C.A heat pump that uses work to move heat
D.A heat engine that uses heat to do work
B.A heat engine that uses work to move heat
Explanation;A heat engine involves a thermodynamic process that converts the heat supply in it into mechanical work.A heat engine makes use of the properties of thermodynamics to transform heat into work. Gasoline and diesel engines, jet engines, and steam turbines that generate electricity are all examples of heat engineA horizontal force of magnitude 46.7 N pushes a block of mass 4.35 kg across a floor where the coefficient of kinetic friction is 0.635. (a) How much work is done by that applied force on the block-floor system when the block slides through a displacement of 2.96 m across the floor? (b) During that displacement, the thermal energy of the block increases by 35.0 J. What is the increase in thermal energy of the floor? (c) What is the increase in the kinetic energy of the block?
(a) 138.2 J
Since the applied force is parallel to the displacement of the block, the work done by the force is given by:
[tex]W=Fd[/tex]
where
F = 46.7 N is the magnitude of the force
d = 2.96 m is the displacement of the block
Substituting the numbers into the equation, we find
[tex]W=(46.7 N)(2.96 m)=138.2 J[/tex]
(b) 45.1 J
In order to calculate the total energy dissipated among the floor and the block as thermal energy, we have to calculate the work done by the frictional force, which is
[tex]W_f = F_f d = (-\mu mg)d[/tex]
where[tex]\mu=0.635[/tex] is the coefficient of friction
m = 4.35 kg is the mass of the block
g = 9.8 m/s^2
d = 2.96 m is the displacement
and the negative sign is due to the fact that the frictional force has opposite direction to the displacement.
Substituting, we find
[tex]W_f =-(0.635)(4.35 kg)(9.8 m/s^2)(2.96 m)=-80.1 J[/tex]
The magnitude of this work is equal to the sum of the thermal energy dissipated between the floor and the block:
[tex]W_f = E_{floor}+E_{block}[/tex]
And since we know
[tex]W_f = 80.1 J\\E_{floor}=35.0 J[/tex]
we find
[tex]E_{floor}=W_f-E_{block}=80.1 J-35.0 J=45.1 J[/tex]
(c) 58.1 J
According to the work-energy theorem, the increase in kinetic energy of the block must be equal to the work done by the applied force minus the work done by friction (which becomes wasted thermal energy):
[tex]\Delta K=W-W_f[/tex]
Substituting
[tex]W=138.2 J\\W_f = 80.1 J[/tex]
We find
[tex]\Delta K=138.2 J-80.1 J=58.1 J[/tex]
What is the speed of sound in air at 42.0 ºC?
= 356.2 m/s
Explanation;The speed of the wave is dependent on temperature of the medium;
The equation to use will be;
Speed = 331 + 0.6 T ; where T is the temperature in degrees Celsius.
T = 42 °C
Therefore;
speed = 331 + 0.6 × 42
= 356.2 m/s
Compared to a main-sequence star with a short lifetime, a main-sequence star with a long lifetime is __________.
The answer would be less luminous, cooler, smaller, and less massive.
A main-sequence star with a long lifetime is typically characterized by lower mass, cooler temperature and less luminosity, compared to a star with a short lifetime. They consume their nuclear fuel at a slower rate, allowing them to have a longer lifespan in the main-sequence phase, such as red dwarfs.
Explanation:Compared to a main-sequence star with a short lifetime, a main-sequence star with a long lifetime is typically less massive, cooler, and emits less light. The lifetime of a star is directly related to its mass. Stars with larger mass burn through their nuclear fuel at a quicker rate, leading to a shorter main-sequence lifetime. Conversely, stars with smaller mass, such as red dwarfs, consume their fuel more slowly and thus have longer main-sequence lifetimes.
For example, the Sun, a moderate mass star, is expected to remain in the main-sequence stage for about 10 billion (10¹0) years. This is much longer than a more massive star, like a blue giant, which might only last a few million years in the main sequence stage.
However, less massive stars, commonly known as red dwarfs, with masses less than half that of the Sun, can have main sequence lifetimes that stretch into the trillions of years, due to their efficient use of nuclear fuel.
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Please help me with this Physics question?
A 12.0 kg Steel block is resting on a horizontal table. The coefficient of static friction is 0.70. Find the minimum force needed to start the block moving.
A) 35.3 N
B) 80.4 N
C) 82.4 N
D) 86.4 N
C 82.4 N sorry man if i am wrong but don't even think about reporting my answer
Final answer:
The minimum force needed to start a 12.0 kg steel block moving, with a coefficient of static friction of 0.70, is slightly greater than 82.32 N. The closest given option is 82.4 N (Option C).
Explanation:
To find the minimum force needed to start the 12.0 kg Steel block moving on a surface with a coefficient of static friction of 0.70, we need to calculate the force of friction that must be overcome. This force of friction is given by Fs = μs * N, where Fs is the static friction force, μs is the coefficient of static friction, and N is the normal force. The normal force is equal to the weight of the block, which is the mass of the block times the acceleration due to gravity (9.8 m/s²).
First, calculate the normal force:
N = mass * gravity = 12.0 kg * 9.8 m/s² = 117.6 N
Next, calculate the force of static friction:
Fs = μs * N = 0.70 * 117.6 N = 82.32 N
Therefore, the minimum force needed to start the block moving is slightly greater than 82.32 N. Out of the given options, the closest value is 82.4 N (Option C).
The earth's crust is _____. thicker under the oceans than under the continents in motion because of convection currents in the mantle mostly made of iron and nickel made of one large piece called the crustal plate
In motion because of convection currents in the mantle.
A 2.0-m-tall man is 5.0 m from the converging lens of a camera. His image appears on a detector that is 50 mm behind the lens. How tall is his image on the detector?
Answer:
20 cm
Explanation:
We can solve the problem by using the magnification equation:
[tex]M=\frac{h_i}{h_o}=-\frac{q}{p}[/tex]
where
[tex]h_i[/tex] is the size of the image
[tex]h_o = 2.0 m[/tex] is the height of the real object (the man)
[tex]q=50 mm =0.050 m[/tex] is the distance of the image from the lens
[tex]p = 5.0 m[/tex] is the distance of the object (the man) from the lens
Solving the formula for [tex]h_i[/tex], we find
[tex]h_i = -\frac{q}{p}h_o=-\frac{0.050 m}{5.0 m}(2.0 m)=-0.02 m = -20 cm[/tex]
And the negative sign means the image is inverted.
The height of the image on the detector is 100 mm.
Explanation:To determine the height of the image on the detector, we can use the lens equation:
1/f = 1/di - 1/do
Where f is the focal length of the lens, di is the image distance, and do is the object distance.
In this case, the focal length of the lens is 50 mm, the object distance is 5.0 m, and the image distance is 50 mm (since the detector is located 50 mm behind the lens).
Substituting these values into the equation, we can solve for di:
1/50 = 1/di - 1/5000
Simplifying, we get:
di = 100 mm
This means that the height of the image on the detector is 100 mm, since the image distance is equal to the height of the image.
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If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforce applied to the car is directed to the left.the netforce applied to the car is zero.there isexactly one force applied to the car.
Answer:
the net force applied to the car is zero.
Explanation:
According to Newton's second law, the acceleration of an object (a) is directly proportional to the net force applied (F):
[tex]a=\frac{F}{m}[/tex]
where m is the object's mass.
In this problem, the car is moving with constant velocity: this means that the acceleration is zero, a = 0. Therefore, according to the previous equation, the net force must also be zero: F = 0. So, the correct answer is
the net force applied to the car is zero.
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.50 × 10 4 1.50×104 rad/s to an angular speed of 3.35 × 10 4 3.35×104 rad/s. In the process, the bit turns through 2.02 × 10 4 2.02×104 rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 6.90 × 10 4 6.90×104 rad/s, starting from rest?
Answer:
0.32 s
Explanation:
Initial angular speed: [tex]\omega_i = 1.50 \cdot 10^4 rad/s[/tex]
Final angular speed: [tex]\omega_f = 3.35\cdot 10^4 rad/s[/tex]
Angular rotation: [tex]\theta=2.02\cdot 10^4 rad[/tex]
The angular acceleration of the drill can be found by using the equation:
[tex]\omega_f^2 - \omega_i^2 = 2 \alpha \theta[/tex]
Re-arranging it, we find [tex]\alpha[/tex], the angular acceleration:
[tex]\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}=\frac{(3.35\cdot 10^4 rad/s)^2-(1.50\cdot 10^4 rad/s)^2}{2(2.02\cdot 10^4 rad)}=22,209 rad/s^2[/tex]
Now we want to know the time t the drill takes to accelerate from
[tex]\omega_i =0[/tex]
to
[tex]\omega_f = 6.90\cdot 10^4 rad/s[/tex]
This can be found by using the equation
[tex]\omega_f = \omega_i + \alpha t[/tex]
where [tex]\alpha[/tex] is the angular acceleration we found previously. Solving for t,
[tex]t=\frac{\omega_f - \omega_i}{\alpha}=\frac{22,209 rad/s^2}{6.90\cdot 10^4 rad/s}=0.32 s[/tex]
Which process causes Earth’s surface to warm?
answer :the radiation of the Sun’s electromagnetic waves
The radiation of the sun's electromagnetic waves
Explanation;The energy that drives the climate system comes from the Sun. When the Sun's energy reaches the Earth it is partially absorbed in different parts of the climate system. The absorbed energy is converted back to heat, which causes the Earth to warm up and makes it habitable.Energy from the sun heats Earth's surface, warms the atmosphere, provides energy for photosynthesis, causes evaporation, drives the weather and water cycles, and powers the ocean currents.Answer:
the radiation
Explanation:
The electric-power industry is interested in finding a way to store electric energy during times of low demand for use during peak-demand times. One way of achieving this goal isto use large inductors.a)What inductance L would be needed to store energy E = 3.0 kWh (kilowatt-hours) in a coil carrying current I = 300A?
Answer:
240 H
Explanation:
The energy stored in an inductor is given by:
[tex]E=\frac{1}{2}LI^2[/tex]
where
L is the inductance of the inductor
I is the current
In this problem, we know:
[tex]I=300 A[/tex] is the current in the inductor
[tex]E=3.0 kWh = 3000 Wh[/tex] is the energy stored. We need to convert it into Joules:
[tex]E=3000 Wh=3000 Wh \cdot (3600 s/h)=1.08\cdot 10^7 J[/tex]
So, we can now solve the equation to find L, the inductance:
[tex]L=\frac{2E}{I^2}=\frac{2(1.08\cdot 10^7 J)}{(300 A)^2}=240 H[/tex]
The inductance needed to store 3.0 kWh of energy in a coil carrying a current of 300A is 240H.
Explanation:The energy stored in an inductor is given by the equation Eind = 1/2LI². To find the inductance need to store a specific amount of energy, we can rearrange this equation to solve for L (inductance): L = 2E/I². First, we must convert the energy from kilowatt-hours to a compatible SI unit which is joules: E = 3.0 kWh * 3600000 (conversion factor) = 10800,0000J. Substituting in the given values, L = (2 * 10800000) / (300²), it becomes L = 240H. Hence, the inductance needed to store 3.0 kWh of energy in a coil carrying a current of 300A is 240H.
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1. 412.9 g of dry ice sublimes at room temperature. a. What’s changing? --- sublimation b. What constant will you use? ----- 25.2 kJ c. What equation will you use? ------ Q=m(sublimation) d. Is energy being absorbed or released by the dry ice? ------- absorbed e. How much energy is being transferred? 2. Steam – specifically 72.9 g of steam – condenses. a. What’s changing? b. What constant will you use? c. What equation will you use? d. Is energy being absorbed or released by the steam? e. How much energy is being transferred? 3. A silver ring with a mass of 39.2 g is heated from 25.9 °C to 412.9 °C. a. What’s changing? b. What constant will you use? c. What equation will you use? d. Is energy being absorbed or released by the silver? e. How much energy is being transferred? 4. An ice cube with a mass of 156.3 g melts (starting at its freezing point) and then warms up to 56.232 °C. a. What’s changing? b. What constant will you use? c. What equation will you use? d. Is energy being absorbed or released by the ice cube? e. How much energy is being
1. 236 kJ
a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)
b. The enthalphy of sublimation, given by: [tex]\lambda=571 J/g[/tex]
c. The equation to use will be [tex]Q=m\lambda[/tex], where m is the mass of dry ice and [tex]\lambda[/tex] is the enthalpy of sublimation
d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.
e. The amount of energy being transferred is
[tex]Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ[/tex]
2. 165 kJ
a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)
b. The latent heat of vaporisation of water, given by [tex]\lambda=2260 J/g[/tex]
c. The equation to use will be [tex]Q=m\lambda[/tex], where m is the mass of steam that condenses and [tex]\lambda[/tex] is the latent heat of vaporisation
d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released
e. The amount of energy being transferred is
[tex]Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ[/tex]
3. 3.64 kJ
a. Only the temperature of the substance (which is increasing)
b. The specific heat capacity of silver, which is [tex]C_s = 0.240 J/gC[/tex]
c. The equation to use will be [tex]Q=m C_s \Delta T[/tex], where m is the mass of silver, Cs is the specific heat capacity and [tex]\Delta T[/tex] the increase in temperature
d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings
e. The amount of energy being transferred is
[tex]Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ[/tex]
4. 89 kJ
a. Both the phase of the substance (from solid to liquid) and then the temperature
b. The latent heat of fusion of ice: [tex]\lambda=334 J/g[/tex] and the specific heat capacity of water: [tex]C_s=4.186 J/gC[/tex]
c. The equation to use will be [tex]Q=m\lambda + m C_s \Delta T[/tex], where m is the mass of ice, [tex]\lambda[/tex] the latent heat of fusion of ice, Cs is the specific heat capacity of water and [tex]\Delta T[/tex] the increase in temperature
d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water
e. The amount of energy being transferred is
[tex]Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ[/tex]
Kirchhoff's loop rule for circuit analysis is an expression of which of the following? Conservation of charge Conservation of energy Ampere's law Ohm's law Faraday's law
Final answer:
Kirchhoff's loop rule for circuit analysis expresses the conservation of energy, stating that the sum of all voltage gains and drops in a closed circuit loop must be zero. This rule, pivotal in analyzing complex electrical circuits, ensures that energy within the circuit is conserved, aligning with the principle that the total energy supplied equals the total energy used.
Explanation:
Kirchhoff's loop rule for circuit analysis is an expression of the conservation of energy. This rule, also known as Kirchhoff's second law or voltage law, asserts that the sum of all voltage drops and rises around any closed circuit loop must equal zero. It effectively ensures that energy is conserved within an electrical circuit, reflecting the principle that the total energy supplied in the circuit equals the total energy used.
Kirchhoff's rules, including both the loop rule and the junction rule (which reflects the conservation of charge), are fundamental in analyzing electrical circuits. They allow for the calculation of potential differences and currents within complex circuits, making them pivotal tools in circuit analysis. Kirchhoff's loop rule is a simplification of Faraday's law of induction and holds true under the assumption that there is no fluctuating magnetic field linking the closed loop.
This simplicity makes the loop rule a powerful tool for analyzing circuits in a wide variety of situations, regardless of the circuit's composition and structure. By applying these rules, currents in the circuit can be related through the junction rule, and a system of equations can be generated using the loop rule to solve for each current value, thus conserving energy throughout the circuit.
Please help on this one?
I believe A. I'm so sorry if it's wrong! but it's the most best answer to me since it makes sense to me.
During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapults that are made with surgical hose mounted on a window frame. A balloon filled with dyed water is placed in a pouch attached to the hose, which is then stretched through the width of the room. Assume that the stretching of the hose obeys Hooke's law with a spring constant of 92.0 N/m. If the hose is stretched by 3.20 m and then released, how much work does the force from the hose do on the balloon in the pouch by the time the hose reaches its relaxed length?
Answer:
294.4 N
Explanation:
Since the hose obeys Hooke's law, the force it exerts on the balloon in the pouch is given by:
[tex]F=kx[/tex]
where
k is the spring constant
x is the stretching
In this problem,
k = 92.0 N/m
x = 3.20 m
Therefore, the force exerted is
[tex]F=(92.0 N/m)(3.20 m)=294.4 N[/tex]
when a physical change occurs what can not be affected as well?
A) size
B) shape
C) density
D) composition
A) Size
hope this helps
A( size like what the other person said
A ball is thrown upward with an initial velocity of 12.1 m/s. How long will it take to reach a velocity of -24.5 m/s?
= 3.73 seconds
Explanation;Using the equation;
v = u + at
where v is the final velocity, u is the initial velocity and a is the acceleration due to gravity (-g) and t is the time taken.
Therefore;
v = u - gt
Thus;
v = 24.5 m/s, u = 12.1 m/s, a = -g = 9.8 m/s²
-24.5 m/s = 12.1 - 9.8 × t
36.6 = 9.8 t
t = 36.6/9.8
= 3.73 seconds
What medium do seismic waves travel through?
Answer:
They travel along the surface of the Earth and through the earth.
an airplane takes off from Dallas Texas to fly to new york city traveling ne for 2,760 km the Same plane returns that day to Dallas the airplane spent 2 hours on the trip to new york city and the return trip took 2 1/2 hours what is the airplanes speed for the round trip
1,104
1,227
1,300
1104 km/hour
ExplanationDistance between Dallas Texas to New York = 2760 km
Time the plane took from Dallas to New York = 2 hours
Time the plane took from New York back to Dallas = 2.5 hours
Formula to use
distance = speed x timeSpeed the plane took from Dallas to New York
2760 = 2 x speed
speed = 2760 / 2
= 1380 km/hour
Speed the plane took from New York to Dallas (ROUND TRIP)
2760 = 2.5 x speed
speed = 2760 / 2.5
= 1104 km/hour
Answer: The speed of airplane is 1227 km/hr
Explanation:
Average speed is defined as the ratio of total distance traveled to the total time taken.
To calculate the average speed of the airplane, we use the equation:
[tex]\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}[/tex]
We are given:
Total distance traveled = (2760 + 2760) km = 5520 km (Round trip)
Total time taken = (2 + 2.5) hr = 4.5 hr
Putting values in above equation, we get:
[tex]\text{Average speed of airplane}=\frac{5520km}{4.5hr}=1227km/hr[/tex]
Hence, the speed of airplane is 1227 km/hr
Pedro is planning to model how changes in weather affect evaporation from lakes. For his second experiment, he wants to test how winds affect the evaporation rate. He places one beaker with 300 mL of water in an area away from any fans, and he places another beaker with 300 mL of water near a small fan.
What is the dependent variable in Pedro's experiment?
A. Volume of water
B. Evaporation rate
C. Temperature
D. Movement of air