Which expression is equivalent to x3 • x2?

A.) (x + x)5
B.) x5
C.) x-1
D.) x6

The average temperature range in Newport, Oregon is between 45 and 65 degrees.

The average yearly temperature T in degrees for Newport, Oregon is given by: |T−55|≤10. This means that the temperature T is within 10 degrees of 55 degrees. To find the average temperature range, we consider the range between 55+10 = 65 degrees and 55-10 = 45 degrees.

Therefore, the average temperature range in Newport, Oregon is 45 to 65 degrees.

Answer:

The mean is  

✔ 89

The median is  

✔ 92

The mean of Miriam's test scores is 89 and the median is 92.

"It is the average of a data set. "

"It is the middle value in a list ordered from smallest to largest."

For given question,

Total number of test scores = 9

The sum of all the test scores would be,

96 + 81 + 82 + 99 + 94 + 92 + 95 + 82 + 80 = 801

So, the mean would be,

[tex]\bar{X}=\frac{801}{9} \\\\\bar{X}=89[/tex]

So, the mean of Miriam's test scores is 89.

If we arrange the test scores in ascending order then it would be,

80, 81, 82, 82, 92, 94, 95, 96, 99

The middle value is 92

So, the median is 92.

Therefore, the mean of Miriam's test scores is 89 and the median is 92.

Learn more about the mean and median here:

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Answer:

[tex]\displaystyle b = 11[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Functions

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                     [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Area of a Region Formula:                                                                                     [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

g(x) = 4x

Interval [1, b]

A = 240

Step 2: Solve for b

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

The cube root of -27 is -3, which cannot be graphed in the first quadrant of the complex plane. When considering complex roots, the angles of these roots do not lie in the first quadrant either, contradicting the given requirement.

The cube root of -27 that graphs in the first quadrant in complex form can be represented as 3(cos Θ + i sin Θ), where Θ is the angle in degrees. To find a cube root that lies in the first quadrant, we look for an angle Θ whose cosine is positive and sine is positive, which corresponds to angles between 0° and 90°. However, the cube root of -27 is actually a negative real number, which is -3.

Since we cannot graph a negative real number (-3) in the first quadrant of the complex plane, which only contains positive real and imaginary numbers, the question seems to be a bit contradictory. Nonetheless, if we interpret the cube root in terms of complex numbers, we find that the complex roots of -27 are -3, 3ε², and 3ε⁴, where ε² = e²πi/3 and ε⁴ = e⁴πi/3, correspond to angles of 120° and 240° respectively, which do not lie in the first quadrant.

Answer:

[tex]12\frac{3}{16} \text{inches}[/tex]

Step-by-step explanation:

Given : The city is [tex]2 \frac{7}{16}[/tex] inches across on the map

To Find:On the map, what is the distance across the actual city?

Solution:

Distance on map = [tex]2 \frac{7}{16}=\frac{39}{16} inches[/tex]

Scale: 1 inch = 5 miles

So, [tex]\frac{39}{16} inches=\frac{39}{16} \times 5[/tex]

[tex]\frac{39}{16} inches=\frac{195}{16} =12\frac{3}{16} [/tex]

Thus ,the distance across the actual city is [tex]12\frac{3}{16} inches[/tex]

So, option C is correct.

Answer:

46 2/3% of 28 is 13.06

Step-by-step explanation:

Hello,

thank you very much for asking this here in brainly, I think I can help you with this one

Let's remember

[tex]a\frac{b}{c} =\frac{(a*c)+b}{c}\\[/tex]

Step 1

[tex]46\frac{2}{3} =\frac{(46*3)+2}{3} =\frac{140}{3} =46.67[/tex]

so 46 2/3% =46.67%

Step 2

using a rule of three

define the relationships

if

28⇒ 100%

x?  ⇒46.67%

[tex]\frac{28}{100}=\frac{x}{46.67} \\[/tex]

isolating x

[tex]\frac{28}{100}=\frac{x}{46.67}  \\x=\frac{28*46.67}{100}\\x=\frac{1306.67}{100} \\x=13.06[/tex]

46 2/3% of 28 is 13.06

I hope it helps, have a great day

3x3 = 9

2x6 = 12

12+9 = 21+1 =22

 score would be 22 points

Answer:

The Giants' score will be 22 points.

Step-by-step explanation:

Consider the provided information.

It is given that tom predicted that the Giants would score three 3-point field goals. Which can be written as:

3 × 3 = 9

Total score by field goals is 9 points.

If he score two 6-point touchdowns, this can be written as:

2 × 6 = 12

Total score by touchdown is 6 points.

And 1 extra point.

Now add all the points as shown below:

Total score is: 9 + 12 + 1 = 22 points

Hence, the Giants' score will be 22 points.

x=heavy equipment

y= general labor

x+y=38

x=38-y

134x + 92y=4756

134(38-y)+92y =4756

5092-134y+92y=4756

-42y = -336

y = -336/-42 = 8

x=38-8=30

check 30*134 =4020

8*92 = 736

4020+736 = 4756

 8 general laborers

30 heavy equipment operators

Answer:

[tex]x+y\geq 36[/tex]

[tex]2x+0.6y<40[/tex]

Step-by-step explanation:

The magnets are on sale for 60 cents each.

The key chains cost $2 each.

Katie must purchase at least 36 gifts but has to spend less than $40.

Now let x represent the amount of key chains.

Let y represent the amount of magnets.

So, the system of inequalities that form are:

[tex]x+y\geq 36[/tex]

And

[tex]2x+0.6y<40[/tex]

The binomial distribution of the number of women (out of six) who could be an interest in baseball is found by using the binomial probability formula. Probabilities range from 0.027 for zero women interested, to 0.002 for all six women interested.

In this problem, we are constructing a binomial distribution for the number of women (out of six) who might consider themselves fans of professional baseball. This involves using the formula for a binomial probability, which is: P(x) = nCx * [tex](p^x) * ((1-p)^(^n^-^x^)[/tex]). Here, n represents the number of trials (in this case, 6 women), p represents the probability of success (here, a woman being a baseball fan, which is 0.36 or 36%), and x represents the number of successful outcomes we're interested in.

Each of these values rounds to the thousandth place

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To construct a binomial distribution, we use the formula P(x) = nCx * p^x * (1-p)^(n-x), where n is the number of trials, p is the probability of success, x is the number of successes, and nCx is the combination formula.

To construct a binomial distribution, we use the formula P(x) = nCx * p^x * (1-p)^(n-x), where n is the number of trials, p is the probability of success, x is the number of successes, and nCx is the combination formula.

The random variables X and P' represent the number of women who consider themselves fans of professional baseball and the probability of a woman considering herself a fan, respectively.

We should use the binomial distribution for this problem.

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a. Rate law expression: [tex]\(\text{rate} = kxyz\)[/tex]

b. [tex]\[ \text{Rate factor} \approx 3.16 \times 10^3 \][/tex]

**Part A: Rate Law Expression**

Given that the reaction is first order in [tex]\( (IO_3)^- \)[/tex], first order in [tex]\( (SO_3)^{2-} \)[/tex], and first order in [tex]\( H^+ \)[/tex], the rate law for the reaction can be expressed as:

[tex]\[ \text{rate} = k \cdot [(IO_3)^-]^1 \cdot [(SO_3)^{2-}]^1 \cdot [H^+]^1 \][/tex]

Simplifying this, we get:

[tex]\[ \text{rate} = kxyz \][/tex]

Here, [tex]\( x \), \( y \), and \( z \)[/tex] are the concentrations of [tex]\( (IO_3)^- \), \( (SO_3)^{2-} \), and \( H^+ \)[/tex], respectively. [tex]\( k \)[/tex] is the rate constant.

**Part B: Rate Change with pH**

The pH of a solution is a measure of its hydrogen ion concentration [tex](\( [H^+] \))[/tex]. As the reaction is first order in [tex]\( H^+ \)[/tex], a change in pH will directly impact the rate. The relationship between pH and [tex]\( [H^+] \)[/tex] is logarithmic:

[tex]\[ \text{pH} = -\log[H^+] \][/tex]

To calculate the rate change factor when the pH decreases from 5.50 to 2.00, we need to consider the relationship between pH and [tex]\( [H^+] \)[/tex]:

[tex]\[ \text{pH} = -\log[H^+] \][/tex]

1. **At pH 5.50:**

  [tex]\[ [H^+] = 10^{-\text{pH}} = 10^{-5.50} \][/tex]

2. **At pH 2.00:**

  [tex]\[ [H^+] = 10^{-\text{pH}} = 10^{-2.00} \][/tex]

Now, calculate the rate factor:

[tex]\[ \text{Rate factor} = \frac{\text{rate at pH 2.00}}{\text{rate at pH 5.50}} = \frac{[H^+]_{\text{pH 2.00}}}{[H^+]_{\text{pH 5.50}}}\][/tex]

[tex]\[ \text{Rate factor} = \frac{10^{-2.00}}{10^{-5.50}} \][/tex]

[tex]\[ \text{Rate factor} \approx \frac{0.01}{3.16 \times 10^{-6}} \][/tex]

[tex]\[ \text{Rate factor} \approx 3.16 \times 10^3 \][/tex]

Expressing the answer numerically using two significant figures, the rate change factor is approximately [tex]\(3.2 \times 10^3\).[/tex]

The question probable maybe:

Part A:

The reaction is found to be first order in [tex](IO_3)^-[/tex], first order in [tex](SO_3)^2^-[/tex], and first order in H^+.
If [[tex](IO_3)^-[/tex]] = x, [[tex](SO_3)^2^-[/tex]] = y and [[tex]H^+[/tex]]=z, what is the rate law for the reaction in terms of x, y, and z and the rate constant k?
Express the rate in terms of k, x, y, and (e.g., kxy^3z^2).

▸ View Available Hint(s)

rate= kx^1y^1z

Part B:

By what factor will the rate of the reaction change if the ph decreases from 5.50 to 2.00? express your answer numerically using two significant figures.

This question has following choices to choose the answer from:

The larger sample would have a center closer to the true population parameter.

The larger sample would have less sampling variability.

The smaller sample would have less sampling variability.

The statistics of the smaller sample have more chance for bias than those of the larger sample.

I believe that the correct answer from the 4 choices would be the last one:

"The statistics of the smaller sample have more chance for bias than those of the larger sample."

This is because in a smaller sample, there is a high probability that not all parts or portion of the sample population is represented hence resulting in bias. This is especially true for distribution types of data wherein extreme values exist. Following that bias would already be effect on the center and the sampling variability. So bias always comes first.

At (1,1) and (-1,-1) there is minimum value and at (0,0) is the saddle point.

Given-

Given function is-

[tex]f(x,y)=x^4+y^4-4xy+1[/tex]

Locate the critical points,(use the derivation with respect to x and y)

[tex]f'(x)=4x^3-4y\\\\f'(y)=4y^3-4x[/tex]

Equate the above partial derivatives to the zero, we get.]

[tex]4x^3-4y=0\\\\x^3=y[/tex]

The value of x is obtained. Solve the equation two and put this value of x in that equation, we get,

[tex]4y^3-4x=0\\y^3-x=0[/tex]

Put the value of x, we get,

[tex]x^9-x=0[/tex]

[tex]x(x^8-1)=0[/tex]

from above equation we get one value of [tex]x[/tex] is zero.

[tex]x^8-1=0[/tex]

To the above equation we can rewrite,

[tex]x^2-1=0[/tex]

[tex](x-1)(x+1)=0[/tex]

hence we get three values of the [tex]x[/tex] (0,1,-1)

From the equation of partial derivative equation, we get that

[tex]x=0; y=0[/tex]

[tex]x=1;y=1[/tex]

[tex]x=-1;y=-1[/tex]

Thus three critical points are (0,0),(1,1) nd(-1,-1). Now calculate second partial derivative and D(x,y).

[tex]f"(x)=12x^2-0[/tex]

[tex]f'(xy)=-4[/tex]

[tex]f"(y)=12y^2-1[/tex]

[tex]D(x,y)=f"(x)f"(y)-f'(xy)^2[/tex]

[tex]D(x,y)=144x^2y^2-16[/tex]

Check at critical points,

[tex]D(0,0)=-16<0[/tex]

thus no local minima or maxima at point (0,0). this is the saddle point.

[tex]D(1,1)=12>0[/tex]

so (1, 1) is a local minimum.

[tex]D(-1,-1)=12>0[/tex]

so (-1, -1) is a local minimum.

Hence at (1,1) and (-1,-1) there is minimum value and at (0,0) is the saddle point.

For more about the maxima and minima follow the link given below-

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The Taylor series for [tex]\( \sin(x) \)[/tex] centered at [tex]\( a = \pi \)[/tex] is:[tex]\[ \sin(x) = \sum_{n=0}^{\infty} \frac{(-1)^n}{(2n + 1)!}(x - \pi)^{2n + 1} \][/tex]

The radius of convergence of this Taylor series is infinite, meaning it converges for all values of ( x ).

To find the Taylor series for [tex]\( f(x) = \sin(x) \)[/tex] centered at [tex]\( a = \pi \),[/tex] we first need to find the derivatives of \( \sin(x) \) and evaluate them at \( x = \pi \). Then, we'll write out the Taylor series using the formula:

[tex]\[ f(x) = f(a) + f'(a)(x - a) + \frac{f''(a)}{2!}(x - a)^2 + \frac{f'''(a)}{3!}(x - a)^3 + \cdots \][/tex]

Let's find the derivatives of [tex]\( \sin(x) \)[/tex] and evaluate them at [tex]\( x = \pi \):[/tex]

1. [tex]\( f(x) = \sin(x) \)[/tex]

2. [tex]\( f' (x) = \cos(x) \)[/tex]

3.[tex]\( f''(x) = -\sin(x) \)[/tex]

4.[tex]\( f'''(x) = -\cos(x) \)[/tex]

Now, evaluate these derivatives at \( x = \pi \):

1. [tex]\( f(\pi) = \sin(\pi) = 0 \)[/tex]

2. [tex]\( f'(\pi) = \cos(\pi) = -1 \)[/tex]

3.[tex]\( f''(\pi) = -\sin(\pi) = 0 \)[/tex]

4. [tex]\( f'''(\pi) = -\cos(\pi) = 1 \)[/tex]

Now, plug these values into the Taylor series formula:

[tex]\[ \sin(x) = 0 - 1(x - \pi) + \frac{0}{2!}(x - \pi)^2 + \frac{1}{3!}(x - \pi)^3 + \cdots \][/tex]

Simplify:

[tex]\[ \sin(x) = -\sum_{n=0}^{\infty} \frac{(-1)^n}{(2n + 1)!}(x - \pi)^{2n + 1} \][/tex]

So, the Taylor series for [tex]\( \sin(x) \)[/tex] centered at [tex]\( a = \pi \)[/tex] is:

[tex]\[ \sin(x) = \sum_{n=0}^{\infty} \frac{(-1)^n}{(2n + 1)!}(x - \pi)^{2n + 1} \][/tex]

The radius of convergence of this Taylor series is infinite, meaning it converges for all values of ( x ).

Answer:

12

Step-by-step explanation:

Given that a two pound box of fruit snacks contains 24 packets

We have to find the unit rate per pound

This is a question of direct variation.

[tex]2 pounds = 24 packets\\1 pount= 12 packet[/tex]

i.e. unit rate is 12 packets per pound

to turn a percent into a decimal, move the decimal point 2 places to the left

84.3% = 0.843