Which graph represents the solution set of the system of inequalities?

{y>−2x−2
y ≤ x+4

Which Graph Represents The Solution Set Of The System Of Inequalities?{y>2x2y X+4

Answers

Answer 1

Answer:

Its the first gragh

Step-by-step explanation:

Answer 2

Graph D is a correct choice.

We have a set of inequalities -

y > − 2x − 2

y ≤ x + 4

We have select the graph that represents the solution set of the system of inequalities.

What is an Inequality in mathematics ?

An inequality compares two values or expressions, showing if one is less than, greater than, or simply not equal to another value.

According to the question, we have -

y > − 2x − 2

Let →   y = -2x - 2

Now, plot the graph of the line → y = - 2x - 2 with a Dotted line ( > is a strict inequality).

Assume a point (0,0) -

0 > - 2 x 0 - 2

0 > -2

Which is true, hence shade the area where the point (0, 0) lies.

y ≤ x + 4

Let →   y = x + 4

Now, plot the graph of the line → y = x + 4 on the graph.

Assume a point (0,0) -

0 ≤ 0 + 4

0 ≤ 4

Which is true, hence shade the area where the point (0, 0) lies.

Refer to the image attached for final graph - the area under the Red thick line is common to both and is the solution set of  system of inequalities.

Hence, Graph D is a correct choice.

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Which Graph Represents The Solution Set Of The System Of Inequalities?{y>2x2y X+4

Related Questions

Eight times a number is not less than the sum of the number and fifty

Answers

If the number is n, then 8 times n  ≥ n+50, and by subtracting n from both sides we get 8n-n ≥ 50 and 7n ≥50. Therefore, by dividing by 7, n ≥50/7

Solve for x. x - 3/8 = - 5/8
x = 1/4
x = - 1/4
x = -1
x = 1

Answers

X= -1/4 I honestly have no idea but i hope this helps and if you get it wrong let me know and then we can see if other answers are right.

Answer:

-1/4 should be the answer

Step-by-step explanation:

Ali currently has $25. He is going to start saving $5 every week.

Which equation represents this situation?

y = 25x – 5

y = 5x + 25

y = 25x + 5

y = 5x – 25

Answers

y = 5x + 25 is the correct answer
it is y=5x+25 i hope it helped u

If m is the midpoint of pq, what is the relationship between pm and pq

Answers

m is the mid point of pq
then pm= 1/2 pq

Midpoint, as the word suggests, means the point which lies in the middle of something. If m is the midpoint of PQ then PM will be half of PQ.

What does a midpoint mean?

Midpoint, as the word suggests, means the point which lies in the middle of something. The midpoint of a line segment means a point that lies in the mid of the given line segment.

Given that m is the midpoint of PQ. Therefore, it will divide PQ into two equal parts. Therefore,  we can write,

PQ = PM + MQ

But since PM = MQ,

PQ = PM + PM

PQ = 2 PM

PM = PQ/2

Hence, if m is the midpoint of PQ then the relationship between PM and PQ will be half of PQ.

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Find the greatest common factor 46m4 22m3

Answers

46m^4 / 2m^3 = 23m
22m^3 / 2m^3 = 11

GCM = 2m^3

How to solve 16x to the 4th power y to the 3rd power divided by 2x to the 4th power?

Answers

(16(x^4)y^3/2x^4 = 8y^3
Divide 16 by 2, the x^4's cancel leaving 8y^3

The circumference of a circle is 25.12 yards. What is the radius of the circle?

Answers

the circumference is pi times diameter, so put 25.12 over pi to get the diameter. That would be 8. Then divide by 2 to get the radius. That would be 4

If ab= 37 and xy =1/37, what is the value of the product x x b x y x a

Answers

In this case, we are simply asked to find for the value of:

xbya or abxy

 

Since we know that given values of ab and xy, therefore abxy is:

abxy = 37 * (1 / 37)

abxy = 37 / 37

abxy = 1

What is 7 1/5 written as a percent

Answers

1/5= 0.2
7 1/5= 7.2

To convert from decimal to percent, move the decimal point two places to the left to divide by 100, since percent means per 100.

Final answer: 0.072
71/5 as perecent is 7.2

2.4 puzzle time how can you share five apples with seven friends

Answers

1. The algebraic property of equality that is represented is the multiplication property. The answer is letter P.



2. The algebraic property of equality that is represented is the subtraction property. The answer is letter E.


3. The algebraic property of equality that is represented is the substitution property. The answer is letter M.


4. The algebraic property of equality that is represented is the division property. The answer is letter A.


5. The algebraic property of equality that is represented is the addition property. The answer is letter A.


6. The algebraic property of equality that is represented is the distributive property. The answer is Letter E.


7. The algebraic property of equality that are represented is the transitive property. The answer is letter is E.


8. The algebraic property of equality that are represented is the symmetric property. The answer is Letter A.


9. The algebraic property of equality that are represented is the reflexive property. The answer is letter C.


10. The algebraic property of equality that are represented by is the multiplication property. The answer is letter P.


11. The algebraic property of equality that are represented is the subtraction property. The answer is letter L.



12. The algebraic property of equality that are represented is the reflexive property. The answer is letter S.


13. The algebraic property of equality that are represented is the transitive property. The answer is letter U.


14. The algebraic property of equality that are represented is the symmetric property. The answer is letter K.


The given is 3 5 14 2  4 1 10 11 6 12 8 13 9 7


Plugging in the letters we got for each number, gives us MAKE APPLESAUCE.

As the number of apples is less than the total number of friends among which the apples need to be distributed so, no one will get a complete piece of apple so, 5 apples can be shared in between 7 friends as [tex]\frac{5}{7}[/tex].

According to the question, the total number of apples are 5 and the total number of friends are 7.

So, each friend will get (bu unitary method)-

[tex]\rm{Each\;friend\;will\;get}=\dfrac{5}{7}\;\rm apples[/tex]

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3/5y=-7/25 solve for y

Answers

y= -7/15 
Hope this is good enough :D

Three friends rented a kayak. It cost $4 per hour per person to rent the kayak, plus $2 for each life jacket, and $3 to park the car. It cost $57 in all. How many hours did they spend kayaking? Write an equation and solve.

Answers

They kayaked for 12 hours :)

2,438,783 divided 893

Answers

Answer:

quotient=2,731

Remainder=0

Step-by-step explanation:

893) 2,438,783 (2,731

      - 1 786

      ---------

          6527

        - 6251

        ---------

            2768

          - 2679

         -----------

                893

             -  893

             ---------

                 0

If 3,200 cars were sold all year, how many cars were sold in the jan/feb period?

Answers

12 months per year

3200/12 = 266.66 per month

jan/feb = 2 months

266.666 x 2 = 533.33 round off to 533 cars sold

If 3,200 cars were sold all year, then approximately 533 cars were sold in the Jan/Feb period.

We need to calculate the proportion of the year that these two months represent and then apply that proportion to the total number of cars sold in the year.

Since there are 12 months in a year, the Jan/Feb period represents [tex]\(\frac{2}{12}\)[/tex] of the year. We can simplify this fraction to [tex]\(\frac{1}{6}\)[/tex] by dividing both the numerator and the denominator by 2.

To find the number of cars sold in the Jan/Feb period, we multiply the total number of cars sold in the year by the fraction representing Jan/Feb:

[tex]\[ \text{Number of cars sold in Jan/Feb} = \text{Total cars sold} \times \frac{2}{12} \][/tex]

Substituting the given total number of cars sold:

[tex]\[ \text{Number of cars sold in Jan/Feb} = 3,200 \times \frac{2}{12} \][/tex]

[tex]\[ \text{Number of cars sold in Jan/Feb} = 3,200 \times \frac{1}{6} \][/tex]

[tex]\[ \text{Number of cars sold in Jan/Feb} = \frac{3,200}{6} \][/tex]

Performing the division:

[tex]\[ \text{Number of cars sold in Jan/Feb} = 533.\overline{3} \][/tex]

[tex]\[ \text{Number of cars sold in Jan/Feb} \approx 533[/tex]

12 foot by 15 foot swimming pool has a 3 ft wide no slip surface around it what is the outer perimeter of the no slip surface

Answers

the pool is 12 x 15

 add 6ft to each dimension ( 3 feet on each side)

12+6 = 18

15+6 = 21

21 *2 = 42

18*2 = 36

42 +36 = 78 feet perimeter

Write an equation that shows the equivalency between meters and gigameters.

Answers

Below is an equation that shows the equivalency between meters andGigameters:


[tex]10 ^{9} m = 1 Gm[/tex]


The  conversion factor should be used to convert from meters toGigameters should be:

[tex] \frac{1 Gm}{10 ^{9} m } [/tex]
Final answer:

To convert between meters and gigameters, use the equation 1 Gm = 10^9 m. This relationship is important for converting units in scientific and mathematical contexts.

Explanation:

To show the equivalency between meters and gigameters, we can use the following equation:

1 gigameter (Gm) = 10⁹ meters (m).

This equation means that one gigameter is equal to one billion meters. We can use this equivalency for converting measurements from meters to gigameters or vice versa. For example, to convert 2 gigameters to meters, simply multiply 2 by 10⁹ to get 2 x 10⁹ meters.

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You are making identical gift bags using 24 candles and 36 bottles of lotion .what is the greatest number of gift bags you can make with no items left over. Show your work

Answers

12 gift bags
6×6= 36
6×4=24

Answer:  12

Step-by-step explanation:

Given : You are making identical gift bags using 24 candles and 36 bottles of lotion .

Then, the greatest number of gift bags you can make with no items left over= greatest common factor of 24 and 36

Prime factorization of 24 and 36 :_

[tex]24=2\times2\times2\times3\\\\ 36=2\times2\times3\times3[/tex]

GCF(24 , 36)= [tex]2\times2\times3=12[/tex]

Hence, the greatest number of gift bags you can make with no items left over =12

(3^-2)^4 *3^3 divided by 3^-3

Answers

The answer in exact for is 1/6561 and in decimal form the answer is 0.00015241. Hope I helped!

Give one example of an equation with variables on both sides that has all real numbers as the solution. Also give an example of an equation with variables on both sides that has no real solutions.

Answers

1) 2x + 3 = 2x + 3
This works because if you solve it, you will get either x = x or 3 = 3 which are always true, so x, can have an infinite number of solutions
2) 3(x + 4) = 3x + 11
This has no solution because if you solve it, you're gonna get 12 = 11 and that is NEVER true. Whatever x is, 11 cannot equal 12!
Final answer:

An equation with all real numbers as solutions is one that, regardless of what value a variable might have, both sides will always be equal, such as 2x+3 = 2x+3. An equation with no real solutions is a statement where the two sides cannot ever be equal, like 2x+5 = 2x+7.

Explanation:

An example of an equation with variables on both sides that has all real numbers as the solution is a statement where both sides are identical. For instance, 2x+3 = 2x+3. All real numbers can satisfy this equation for x because both sides are always equal, regardless of what your value of x is.

On the other hand, an equation with no real solutions is one where it's impossible to find any real number that satisfies the equation. An example can be 2x+5 = 2x+7. No matter what value you put in place of x, the two sides of the equation will never be equal. Hence, this equation has no real solution.

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64 ounces in 8 cups unit rate

Answers

So the unit rate is basically how many ounces in 1 cup?

So since there are 64 ounces in 8 cups, you can just divide by 8, to find how many sets of 8 there are in 64.

64 = 8

64 / 8 = 8 / 8

8 = 1

So there are 8 ounces in 1 cup, which is your unit rate.

Solve for x. 45(15x+20)−7x=56(12x−24)+6

Answers

1119/2

Equations may be true or false, just as word sentences may be true or false. The equation:

3 + x = 7

will be false if any number except 4 is substituted for the variable. The value of the variable for which the equation is true (4 in this example) is called the solution of the equation. We can determine whether or not a given number is a solution of a given equation by substituting the number in place of the variable and determining the truth or falsity of the result.

Example 1 Determine if the value 3 is a solution of the equation

4x - 2 = 3x + 1

Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand member.

4(3) - 2 = 3(3) + 1

12 - 2 = 9 + 1

10 = 10

Ans. 3 is a solution.

The first-degree equations that we consider in this chapter have at most one solution. The solutions to many such equations can be determined by inspection.

Example 2 Find the solution of each equation by inspection.

a. x + 5 = 12
b. 4 · x = -20

Solutions a. 7 is the solution since 7 + 5 = 12.
b. -5 is the solution since 4(-5) = -20.

675×+900-7×=112×-1344+6
668×+900=112×-1338
556×=-2238
x=1119/278
x=4.025

given the functon g(x)= (1/4)^x, determine the y-intercept and the equation of the asymptote.

a. the y-intercept is (0, 0.25) and the asymptote is at y=0
b. the y-intercept is (1,0) and the asymptote is at y=0. the y-intercept is (1,0) and the asymptote is at y=1
c. the y-intercept is (0,1) and the asymptote is at y=0
d. the y-intercept is (1,1) and the asymptote is at y= 1.

Answers

Hello.

The y-intercept is the point where  x = 0.

Therefore, let us make this in the function.

g(0) = (1/4) ^ 0

g(0) = 1.

The y-intercept is in (0, 1).

To calculate the asymptote, we will take the limit when x→∞.

  lim    (1/4)^x
x→+∞

We know that this limit is 0 because 1/4 < 1, so the powers of (1/4) will decrease as x grows.

The asymptote is, therefore, at y = 0.

Alternative C

The y-intercept of the function g(x) = (1/4)^x is (0,1), and the horizontal asymptote is at y=0.

The correct option is (c).

Given the function g(x) = (1/4)^x, we need to find the y-intercept and the equation of the horizontal asymptote.

The y-intercept occurs where x = 0. Substituting 0 for x in g(x), we get:

g(0) = (1/4)^0 = 1

So the y-intercept is at the point (0,1).

For horizontal asymptotes, we look at the behavior of the function as x goes to positive or negative infinity. In this case, as x goes to infinity, (1/4)^x approaches 0. Therefore, the horizontal asymptote of g(x) is at y = 0.

The correct answer is c. The y-intercept is (0,1) and the asymptote is at y=0.

Identify the fraction as proper, improper, or mixed . (If the fraction is equivalent to 1, choose "one" in the blank.)

Answers

Proper fractions are those whose numerator is less than the denominator.

These are examples of proper fractions:

1/10, 1/9, 1/4, 1/2, 7/8, 221/225, 100/2000.

Improper fractions are those whos numerator is greater than the denominator.

These are examples of improper fractions:

10/3, 9/5, 8/7, 100/99, 5/4, 125/35.

Mixed fractions are made up of one whole number and a fraction (normallly a proper fraction).

These are examples of mixed fractions:

1 1/4 (which is read one and one quarter)

3 2/3 (which is read three and 2 thirds)

10 1/5 (which is read ten and one fith)

3 1/8 (which is read 3 and 1 eigth)

Fractions equivalent to one are those whose numerator is equal to the denominator.

With that information you have the tools to identify your fractions, given that you did not attached them.

An art store offers prints in two sizes. The store earns $15 on each small print sold and $25 on each large print sold. The owner needs to make a daily profit of at least $700 in order to cover costs. Due to equipment limitations, the number of small prints made must be more than three times the number of large prints. Given that x represents the number of small prints sold and y represents the number of large prints sold, determine which inequalities represent the constraints for this situation. x + y ≤ 60 15x + 25y < 700 x > 3y 15x + 25y ≥ 700 y > 3x x + 3y ≥ 60 Which combinations of small prints and large prints satisfy this system? (45,10) (35,15) (30,10) (40,5)

Answers

The answer definitely 15x + 25y >= 700 for the inequality . So the number of small prints is more than 3 times the large prints . We can also have here the number of small prints : x = 3y . So the equation we have is 15(3y) + 25y >= 700 . We take the least amount to solve :
15(3y) + 25y = 700
=> 45y + 25y = 700
=> 70y = 700
=> y = 10 .
So the amount of large prints is 10
The amount of small prints is 10x3 = 30
So it would be ( 30,10 )
Final answer:

The constraints for this problem are represented by the inequalities x > 3y and 15x + 25y ≥ 700. The combinations that satisfy the constraints is (45,10) as it meets both conditions.

Explanation:

The constraints for the art store situation are represented by the inequalities x > 3y and 15x + 25y ≥ 700. The first inequality, x > 3y, represents the condition that the number of small prints made must be more than three times the number of large prints sold. The second inequality, 15x + 25y ≥ 700, characterizes the fact the store needs to make a daily profit of at least $700 in order to cover costs.

With these inequalities, we can determine which pairs of small print and large print quantities satisfy this system of constraints. Checking each pair, we find that the combination (45,10) satisfies both inequalities as 45 is more than three times 10, and 15*45 + 25*10 = $775, which is greater than $700. Thus, selling 45 small prints and 10 large prints will satisfy the constraints.

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How do you find the measures of the angles in a rhombus with the given angle 54 degrees?

Answers

In a rhombus, the opposite angles are equal. So if one angle is 54 degrees and the opposite angle is the same,, you have 54 + 54 = 108. All of the angles in a rhombus always add up to a total of 180 degrees, so subtract 108 from 180 to get 72 degrees. This means that the other two angles add up to 72, and since we know that opposite angles are equal, we divide 72 by 2 to get 36. This means that the measure of the angle that is adjacent to the 54 degree angle is 72 degrees. 

Hope it is helpful!
one angle is 54 degrees and the opposite angle is the same you add both of them together and that=108. So do 180-54 =72. This means that the other two angles add up to 72, divide 72 by 2 to get 36.   Its that easy hope that works for you. :)

How can you find the measure of a distance that you cannot measure directly?

Answers

By using porportions, such as the pythagorean therum (a squared plus b squared equals c squared) Good luck!

Problem page the perimeter of a rectangular garden is 274 feet. if the width of the garden is 63 feet, what is its length?

Answers

hello : 
 the perimeter of a rectangular garden is :  P = 2(L+W)
L : the length       W : the width
274 = 2( L +63)
L+63 = 274/2 =
L+63 = 137
L= 137-63
L= 74

Which is farther 200km or 200mi

Answers


200mi one mile is the same are 1.609 kilometers

Answer:

200 mi.

Step-by-step explanation:

200 mi. is more or greater than 200 km. Because, 200 mi. in km will be 321 km so that is greater than 200 km.  

I hope this helps you.

Enter an inequality that represents the graph in the box.

PLEASE HELP ME!

Answers

the line is solid so we have either ≤ or ≥

find the equation of the line

ok, a y intercept if -1
sllope=rise/run=3/1=3

y=mx+b
m=slope
b=y intercept

y=3x-1 is the equaton

now find if it's y≥3x-1 or y≤3x-1

test a point
we see (0,0) Is not in in it
test it in y≥3x-1
0≥3(0)-1
0≥-1
false,
so this is the equation because (0,0) is not a valid solution for this equation


answer is y≥3x-1

its actually y=>3x-1 because it's shaded below the line.

below the line: < or <=

above the line: > or>=

what is 100/6 as a decimal

Answers

In order to find the "[tex]decimal [/tex]" of this [tex]fraction [/tex] (or any [tex]fraction [/tex] ) you can [tex]divide [/tex] the [tex]numerator [/tex] from the [tex]denominator [/tex]

So,[tex] \frac{100}{6} [/tex] as a [tex]decimal [/tex],  [tex]would [/tex]  most likely [tex]be [/tex]: [tex]16.67 [/tex]

Good luck on your assignment and enjoy your day!

~[tex]MeIsKaitlyn:)[/tex]
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