Which heat transfer method is used to capture the sun's energy?

Final answer:

The atomic nucleus, located at the center of an atom, consists of positively charged protons and neutral neutrons. Electrons orbit this nucleus, and while protons and neutrons give the atom most of its mass, electrons define its size and chemical properties. Thus the sentence is - At the center of each atom lies the atomic nucleus which consists of protons and neutrons.

Explanation:

At the center of each atom lies the atomic nucleus which consists of protons and neutrons.

The nucleus is a positively charged region at the center of the atom. It is composed of protons, which have a positive electric charge, and neutrons, which are neutral. This nucleus is very dense and contains the vast majority (99.97%) of an atom's mass. Surrounding the nucleus is mostly empty space, where negatively charged particles called electrons orbit the nucleus. The structure of an atom is such that the protons and neutrons form the nucleus in the center, while the electrons move around the nucleus in varying energy levels, known as electron shells.

In most atoms, the number of protons and neutrons is the same, giving the atom a balanced, neutral charge overall. The key exception to this is the most common isotope of hydrogen, which consists of only one proton and one electron, with no neutrons in the nucleus. Atomic structure determines the chemical properties of an element, and the arrangement and number of basic particles—protons, neutrons, and electrons—shape these properties.

Mitosis results in daughter cells that are in the 'Interphase' of the cell cycle. During this phase, cells prepare for division by duplicating their DNA and growing in size. This phase contains the sub-phases G1, S, and G2 during which cell growth and DNA replication occur.

The process of cell division, known as mitosis, results in daughter cells that are in the Interphase. This phase represents the period between cell divisions and is the phase in which cells typically spend the most time. During Interphase, the cell prepares for division by duplicating its DNA and increasing its volume in preparation for cell division. The nucleus is visible and contains a nucleolus. The Interphase is categorized into three sub-phases: G1 (gap 1) phase, S (synthesis) phase, and G2 (gap 2) phase. Cell growth occurs during the G1 and G2 phases, while DNA replication occurs during the S phase.

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circle graph

Explanation:

Explanation :

It is given that :

Initial velocity, [tex]v_0=50\ m/s[/tex]

Launching angle, [tex]\theta_0=36.9^0[/tex]

The motion followed by this object is called as its projectile motion.

the horizontal component is given by:

[tex]x_t=x_0+v_0cos\theta_0t[/tex].......(1)

Put all values in equation (1)

For t = 0, [tex]x_t=0[/tex]

For t = 1 s, [tex]x_1=0+50\ cos(36.9)\ 1=39.95\ m[/tex]

For t = 2 s, [tex]x_2=0+50\ cos(36.9)\ 2=79.9\ m[/tex]

For t = 3 s, [tex]x_3=0+50\ cos(36.9)\ 3=119.85\ m[/tex]

For t = 4 s, [tex]x_3=0+50\ cos(36.9)\ 4=159.8\ m[/tex]

For t = 5 s, [tex]x_4=0+50\ cos(36.9)\ 5=199.75\ m[/tex]

For t = 6 s, [tex]x_3=0+50\ cos(36.9)\ 6=239.7\ m[/tex]

Hence, this is the required solution.

A decomposition reaction would be the electrolysis.

2 H+ + 2e− → H2

2 H2O → O2 + 4 H+ + 4e−

Then you should add them up. In order for the equation to be balanced, the first equation has to be added twice:

2 H+ + 2e− + 2 H+ + 2e−+2 H2O → H2+ H2 + O2 + 4 H+ + 4e−

4 H+ + 4e− +2 H2O → 2H2 + O2 + 4 H+ + 4e−

Then you should cancel the substances which are both in reactives and in products, and also the electrons:

2 H2O → 2H2 + O2

And there you have the overall equation for electrolysis.

Electrolysis does not happen naturally – you have to provide electric energy for it to happen.

A synthesis reaction would be the opposite reaction, which would be called: electrosyntesis.

2H2 + O2 → 2 H2O

Answer:answer is twice as much

Explanation:

Answer:

To answer this question, we need to recur to the law of inertia.

The law of inertia states "if a body is at rest, or moving at a constant speed in a straight line, it will remain that state until a force act on the body".

So, in this case, the jet is traveling at a speed of 600 km/h, which means that all bodies inside the jet are also traveling at this speed, because they are in it.

Also, if we apply the law of inertia here, imagine that somebody falls from the jet, that person will travel at a speed near to 600km/h, if we discard the wind, following a constant trajectory.

The same phenomenon happens with the pillow, when it falls from an overhead rack, if the passanger is passing under the trajectory of the pillow, it will slam her, because due to intertia, the pillow will continue its movement until something stop it, which can be the person's body.

I believe there are two things which we asked to find here:

1. its speed just as it left the ground

2. find its maximum height

Solutions:

1. We use the formula:

ΔKE = - ΔPE

where KE is kinetic energy = ½ mv^2, and PE is potential energy = m g h, Δ = change

Therefore:

½ m (v2^2 – v1^2) = m g (h1 – h2)

at initial point, point 1: h1 = 0, v1 = ?

at final point, point 2: h2 = 15.4 m, v2 = 24.2 m/s

½ (24.2^2 – v1^2) = 9.8 (0 – 15.4)

585.64 – v1^2 = -301.84

-v1^2 = 887.48

v1 = 29.8 m/s

So the rock was travelling at 29.8 m/s as it left the ground.

2. The maximum height (hmax) reached is calculated using the formula:

v1^2 = 2 g hmax

Rewriting in terms of hmax:

hmax = v1^2 / 2 g

hmax = (29.8)^2 / (2 * 9.8)

hmax = 45.3 m

Therefore the rock reached a maximum height of 45.3 meters.

This high school physics question discusses the principles of kinematics and energy conservation. Given the speed and height of a rock thrown vertically upwards, it asks to determine the initial speed of the rock. We calculate this using the given values and the formula for kinetic energy & gravitational potential energy conservation, getting the initial velocity as approximately 16.88 m/s.

The subject of this question pertains to physics, specifically the application of the principles of kinematics and energy conservation in studying projectile motion. Neglecting air resistance, the speed of a projectile (like a rock) thrown vertically upwards at a certain height from the ground can be calculated using energy considerations. From the given, the rock is starting from ground level with a certain velocity upwards and it is observed that at a height of 15.4 m, its speed is 24.2 m/s. Let's denote the initial speed when the rock was thrown as v0.

Using the equation v = √(2gh + v0²), where g is the acceleration due to gravity (9.8 m/s²) and h is the height (15.4 m), we can find the initial velocity of the rock. Plugging in the known values, we get v0 as √[(24.2 m/s)² - 2*(9.8 m/s²)×15.4 m] = √(585.64-301.6) m/s = √284.04 m/s = 16.88 m/s.

This calculation tells us the initial speed required to achieve the observed height and speed. This information can be crucial in physical scenarios involving projectiles.

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Answer:

Reducing the normal force against the ground will reduce the amount of friction force, you can do this reducing the weight or mass of the object that you want to move.

Smoothing down the surface, for example, on a wet floor, the water fills some of the little imperfections in the ground, so the coefficient of dynamic friction in the ground is reduced.

The box is moving at constant speed, so acceleration=0 and the equation of the forces acting on the box along the ramp becomes:

[tex]F-F_f-W_p = 0[/tex] (1)

where F=200 N is the force that pushes the box, Ff is the frictional force, and Wp is the component of the weight parallel to the ramp.

The frictional force can be written as

[tex]F_f = \mu m g cos \theta[/tex]

where [tex]\mu=0.18[/tex] is the coefficient of friction, m is the mass of the box, [tex]g=9.8 m/s^2[/tex] is the frictional force and [tex]\theta=30^{\circ}[/tex] is the angle of the ramp.

The component of the weight along the ramp is

[tex]W_p = mg sin \theta[/tex]

Substituting this into eq.(1), we have

[tex]F-\mu mg cos \theta- mg sin \theta=0[/tex]

and we can find the mass of the box:

[tex]m=\frac{F}{\mu g cos \theta + g sin \theta}=\frac{200 N}{(0.18)(9.8 m/s^2)(cos 30^{\circ})+(9.8 m/s^2)(sin 30^{\circ})}=31.1 kg[/tex]

Now we can also find the work done on the box. this is given by the gain in potential energy of the box, since there is no change in kinetic energy (the speed of the box is constant). Since the box has risen vertically by 1 m, the gain in potential energy (and the work done) is

[tex]W=\Delta U=mg \Delta h=(31.1 kg)(9.8 m/s^2)(1 m)=304.8 J[/tex]

So, the two answers are

(a) 304.8 J

(b) 31.1 kg

The physics concept of work and forces were used to answer this question. The work done was calculated to be 200 Joules and the mass was determined using the given force, angle, and coefficient of friction.

Let's solve this problem using the concepts of physics. First, we need to find how much work was done. Work done (W) = Force (F) x Distance (d) x cos (theta), where theta is the angle between the force and the direction of displacement. Here, as the force was directed up the slope and the box moved up the slope too, the angle (theta) is 0 degrees. Cos 0 = 1, so the equation reduces to W = F x d.

Given, Force (F) = 200 N and Distance (the vertical height) (d) = 1 m (Remember, the work done is equal to the force multiplied by the distance moved in the direction of the force). So, the work done = 200 N x 1 m = 200 Joules.

Next, we need to determine the mass of the box. The forces acting on the body will be gravity (mg), friction (fr) and the applied force (F). According to the information given, the box moved up the slope at a constant speed. This means the net force acting on the box should be zero. Therefore, F - fr - mg*sin(theta) = 0. Given is the coefficient of friction as 0.18, so fr = mu*N = mu*mg*cos(theta), where N = mg*cos(theta) is the normal force. Substituting fr into the net force equation, we can solve for mass (m) = F/(g*(mu*cos(theta) + sin(theta))). Substituting the known values, we get the mass of the box.

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The question involves the Physics concept of projectile motion. By substituting g the given values into the relevant equations for horizontal distance and time, we conclude that the football will travel 60m before hitting the ground.The correct answer is option A.

This question is about a fundamental concept in Physics: projectile motion. To find the horizontal distance a projectile travels, we can use the following formula.

Here, the horizontal distance (d) is given by the equation d = (vi × t × cos(θ)), where vi is the initial velocity (20m/s), t is the time the football is in the air, and cos(θ) is the cosine of the angle of projection (30°).

The time the ball is in the air can be found by using the equation t = 2×vi×sin(θ) / g, where g is the gravity constant (9.8 m/s2).

Substituting the known values into these equations, we conclude that the football will travel 60m before it hits the ground, thus the answer is a.60 m.

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Final answer:

The power output of the second motor that drives the elevator is 9,810 watts or 9.81 kilowatts, calculated by dividing the work done (which is the change in gravitational potential energy) by the time taken.

Explanation:

To calculate the power output of the second motor that drives the elevator, we need to use the formula for power: P = W/t, where P is power, W is work done, and t is time taken.

Since the work done by the motor in lifting the elevator is equal to the change in gravitational potential energy, W = mgh, where m is the mass of the elevator, g is acceleration due to gravity (9.81 m/s²), and h is the height the elevator is lifted. For the second elevator, the mass m is 1,000 kg, height h is 10 meters, and the time taken t is 10 seconds.

First, calculate the work done:

Now, calculate the power:

Therefore, the power output of the second motor is 9,810 watts or 9.81 kilowatts (kW).

Answer:

A) 19.3

Explanation:

As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object

so it is given by

[tex]Specific \gravity = \frac{weight \: of \: object}{weight \: of \: water\: displaced}[/tex]

now we have

weight of the object = (density)(volume)g

weight of object = [tex](19.3 g/cm^3)(2 mL)g[/tex]

now weight of the liquid displaced is given by

weight of water displaced = [tex](1 g/cm^3)(2 mL)g[/tex]

now we have

specific gravity = [tex]\frac{(19.3)(2mL)g}{(1)(2 mL)g}[/tex]

specific gravity = 19.3

Final answer:

To determine the percent decrease in the stool's leg length under a man's weight, additional information such as the original leg length and material properties are required. Using Hooke's law or relevant formulas, we could then calculate the strain and convert it to a percentage.

Explanation:

To calculate by what percent the length of the legs of a stool decrease when an 85 kg man sits on it, we need certain information that is not provided in this scenario, such as the original length and material properties of the stool's legs (e.g., the Young's modulus if we assume the legs are cylindrical rods), as well as the assumption that each leg bears the same load.

Without this additional information, we cannot calculate the exact percentage change in length. If this information were available, we would use Hooke's law, which is commonly used to determine the deformation caused by applying a force on a spring. We would also consider the modulus of elasticity for materials that are not springs. The change in length (ΔL) divided by the original length (L0) gives the strain, which can be multiplied by 100 to find the percentage deformation.

The length of the stool's legs decreases by approximately 0.00083% when a 85 kg man sits on it.

Calculating Deformation of Stool Legs

To determine the percent decrease in the length of the legs of a stool when a 85 kg man sits on it, we can use the formula for linear deformation:

[tex]\Delta L = (F \times L) / (A \times Y)[/tex]

Where:

Assuming each of the stool’s four legs equally shares the weight of the man, the force per leg due to the man’s weight is:

[tex]F = (85 kg \times 9.81 m/s^2) / 4 = 208.42 N[/tex]

Let’s assume the original length (L) of the legs is 0.5 meters and the radius of the legs is 0.02 meters. The cross-sectional area (A) can be calculated using the formula for the area of a circle: [tex]A = \pi \times r^2[/tex]

Thus, the cross-sectional area is:

[tex]A = \pi \times (0.02 m)^2 = 1.2566 \times 10^{-3} m^2[/tex]

Assuming the legs are made of a material with Young's modulus (Y) of [tex]2 \times 10^{10} N/m^2[/tex], the change in length (ΔL) is:

[tex]\Delta L = (208.42 N \times 0.5 m) / (1.2566 \times 10^{-3} m^2 \times 2 \times 10^{10} N/m^2) = 4.15 \times 10^{-6} meters[/tex]

To find the percent decrease in length:

[tex]\text{Percent Decrease} = (\Delta L / L) \times 100 = (4.15 \times 10^{-6} m / 0.5 m) \times 100 = 0.00083\%[/tex]

Therefore, the length of the stool's legs decreases by approximately 0.00083% when the 85 kg man sits on it.

Answer: Option (D) is the correct answer.

Explanation:

The given elements Li, C and F are all second period elements. So, when we move from left to right across a period then there occurs increase in number of valence electrons as there occurs increase in total number of electrons.

So, it means more electrons are added to the same energy level.

Thus, we can conclude that a property of valence electrons for each element is located in the same energy level is common in the given elements.

Answer:

the answer is d

Explanation:

i did the usa test prep

Answer: d. identify the problem

Explanation:

Identify the problem is the correct option this is because of the fact that the natural environment may experience disturbance due human intervention like burning of fossil fuels, pollution or due to natural calamity like earthquakes, landslides and volcanic eruptions. To solve these problems detection of problem should be the first step that can lead to mitigation. These problems exerts negative influence over the ecosystem hence are detectable.