Which is the solution to the inequality |x-4|<3

Answer:

∠XBA=43°

Step-by-step explanation:

we know that

If ray BA bisect angle ∠XBY

then

∠XBA=∠XBY/2

we have

∠XBY=86°

substitute

∠XBA=86°/2=43°

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

You are solving how much miles (further along) would the second car be after 5 hours.

The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).

The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)

Subtract: 275 - 200 = 75

The second car would have averaged 75 more miles than the first car.

~

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

The "speedier" car goes 55 mph * 5 hrs = 55*5 miles

The "slower" car goes 40mph * 5   hrs = 40*5 miles

The distance between them is

55  *5 - 40*5

Answer: i cant read that m8 take a better picture

Step-by-step explanation:

Here is the set up:

Let p = percent of change

(72 - 14)/72 = p/100

Solve for p.

Answer: [tex]\bold{-\dfrac{8}{3}}[/tex]

Step-by-step explanation:

[tex]\sum \limits_{n=1}^{\infty}-4\bigg(\dfrac{-1}{2}\bigg)^{n-1}\implies a_1=-4, r=-\dfrac{1}{2}\\\\\\\text{Use the formula for the sum of an infinite geometric series:}\\S=\dfrac{a_1}{1-r}\\\\\\.\ =\dfrac{-4}{1-(-\frac{1}{2})}\\\\\\.\ =\dfrac{-4}{\frac{3}{2}}\\\\\\.\ =-4\times \dfrac{2}{3}\\\\\\.\ =\large\boxed{-\dfrac{8}{3}}[/tex]

Answer:

B

Step-by-step explanation:

5x + 3y = 15

5x = -3y +15

x = -3/5y +3

Answer:

The correct option is B) x = negative three fifths y + 3

Step-by-step explanation:

Consider the provided equation.

5x + 3y = 15

We need to solve the above equation for x.

Subtract both the side by 3y.

[tex]5x + 3y-3y = 15-3y[/tex]

[tex]5x= 15-3y[/tex]

To find the value of y, isolate the variable y:

Divide both the sides by 5.

[tex]\frac{5x}{5}= \frac{15}{5}-\frac{3y}{5}[/tex]

[tex]x= 3-\frac{3y}{5}[/tex]

[tex]x= -\frac{3y}{5}+3[/tex]

Hence, the correct option is B) x = negative three fifths y + 3

Answer:

associative property of multiplication

Step-by-step explanation:

If we have 3 numbers x, y and z the associative property of multiplication says that:

[tex]x (yz) = z (xy) = (xz)y[/tex]

This means that the result will be the same regardless of the order in which the multiplication takes place.

In this case we have the following equality

[tex]2(xy) = (2x)y[/tex]

Note that the property used is the associative property of multiplication

Answer:

(x - 10)(x + 10)

Step-by-step explanation:

x² - 100 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

Hence

x² - 100

= x² - 10² = (x - 10)(x + 10)

Answer:

P = 1.44 Watts

Step-by-step explanation:

We know that the relation between voltage and current in a simple circuit with a resistor is

V = I.R

Where

V = the voltage of the source

I = current of the circuit

R = resistance

The power is defined as

P = V.I

Which is the same as

P = V.(V/R)

P = (24 v)^2 / (400 ohm)

P = 1.44 Watts

Final answer:

To use the distributive property for the expression 5(2x - 1), multiply each term inside the parentheses by 5, resulting in the equivalent expression 10x - 5.

Explanation:

To use the distributive property to write an expression equivalent to 5(2x - 1), you simply multiply each term inside the parentheses by the factor outside, which is 5 in this case. So, you will multiply 5 by 2x and then 5 by -1.

Multiply 5 by 2x: 5 × 2x = 10x.

Multiply 5 by -1: 5 × -1 = -5.

Combine the two results to get the equivalent expression: 10x - 5.

Therefore, using the distributive property, the expression equivalent to 5(2x - 1) is 10x - 5.

The equation to determine the temperature in Bangor is 3x + 22 = 82. Solving the equation gives the temperature in Bangor as 20 degrees.

To write an equation to determine the temperature in Bangor, let's assume the temperature in Bangor is represented by the variable 'x'. The temperature in Miami is 22 degrees warmer than three times the temperature in Bangor. So, we can write the equation as follows:

3x + 22 = 82

Now, to find the temperature in Bangor, we need to solve for 'x'. We can do this by subtracting 22 from both sides:

3x = 82 - 22

3x = 60

Finally, divide both sides of the equation by 3 to solve for 'x':

x = 60 ÷ 3

x = 20

Therefore, the temperature in Bangor is 20 degrees.

Final answer:

The correct equation to find the temperature in Bangor, Maine, given the temperature in Miami, Florida, is 3x + 22 = 82. After solving, the temperature in Bangor is found to be 20 degrees Fahrenheit.

Explanation:

The temperature in Miami, Florida is given as 82 degrees Fahrenheit. According to the problem statement, this temperature is 22 degrees warmer than three times the temperature in Bangor, Maine. Thus, we can express this relationship algebraically as:

Miami temperature = 3 × Bangor temperature + 22

Substituting the known Miami temperature into the equation, we have:

82 = 3 × Bangor temperature + 22

To solve for the temperature in Bangor, we need to subtract 22 from both sides of the equation:

82 - 22 = 3 × Bangor temperature

60 = 3 × Bangor temperature

Finally, divide both sides by 3 to get the temperature in Bangor:

Bangor temperature = 60 / 3

Bangor temperature = 20 degrees Fahrenheit

Therefore, the correct equation to determine the temperature in Bangor is:

3x + 22 = 82

Answer:

True

Step-by-step explanation:

The domain of a function is the complete set of possible values of the independent variable 'x'. Therefore, the graph of funtion is defined as the set of all points (x, f(x)) where 'x' is the domain of f(x).

Hence, the statement is TRUE

Answer:

True (Please give brainliest)

Step-by-step explanation:

Answer:

9 < x

Step-by-step explanation:

5x - 47< 3(12x - 108) – 2​

Distribute

5x - 47< 36x - 324 – 2​

Combine like terms

5x - 47< 36x-326

Subtract 5x from each side

5x-5x - 47< 36x-5x-326

- 47< 31x-326

Add 326 to each side

326 - 47< 31x-326+326

279 < 31x

Divide by 31 on each side

279/31 < 31x/31

9 < x

Answer:

Choice B. sin(B)=cos(90-B)

Step-by-step explanation:

That cofunction identity is the one you looking for...choice B.

If you aren't convinced or don't know that identity, then maybe this will help:

90-B is actually the same thing as saying A for this right triangle since A+B=90.

So choice B basically says sin(B)=cos(A)

Well let's find both sin(B) and cos(A)

sin(B)=b/c

cos(A)=b/c

Those are the same ratios!

So they are equal!

Answer:

option B

Step-by-step explanation:

from the given options

a)      sin (B)  = sin (A)

b)      sin (B ) = cos (90° - B)

        cos (90° - B ) = Sin B

c)       cos  (B ) =  sin(180° - B)

         sin(180° - B) = sin (B)

d)        cos (B)  = cos(A)

so, we can clearly see from the above solution that option B is correct.

As 90° - B is in first quadrant and in first quadrant sign of cos dose not change  and 90 is multiple of odd so 'cos' changes to 'sin'

C. Function

Hope this helps.

r3t40

Answer:

The reciprocal of [tex] \frac { 7 } { 9 } [/tex] is [tex] \frac { 9 } { 7 } [/tex].

Step-by-step explanation:

We are asked about the reciprocal of the given fraction [tex] \frac { 7 } { 9 } [/tex].

We know that in mathematics, a reciprocal is the multiplicative inverse of a number.

For example, in case of a fraction, its reciprocal will be its inverse which means that we swap the places of numerator and denominator.

So the reciprocal of [tex] \frac { 7 } { 9 } [/tex] will [tex] \frac { 9 } {7 } [/tex].

Fractions are always set up with numerator on top and denominator on bottom like so:

[tex]\frac{numerator}{denominator}[/tex]

To take the reciprocal of a number you must switch the places of numerator and denominator.

Reciprocal of [tex]\frac{7}{9}[/tex] is [tex]\frac{9}{7}[/tex]

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer:

The corresponding side lengths of the figure will be proportional based on the scale factor.

Step-by-step explanation:

A dilation can either be an enlargement or reduction.  If the scale factor is less than one then the figure will be a reduction.  If the scale factor is one or larger then the figure will be an enlargement.  Since a dilation is basically multiplying the figure will always be proportional to the original figure.

answer: 4x² + 9x - 28.

multiply the factors together:

4x times x = 4x²

4x times 4 = 16x

-7 times x = -7x

-7 times 4 = 28

therefore, (4x-7) times (x+4) = 4x² + 16x -7x = 28

next, you must condense and simplify your answer:

16x -7x equals 9x

your final answer should be 4x² + 9x - 28.

Answer:

The answer is B aka 4x² + 9x - 28.

Step-by-step explanation:

Your answer would be [tex]\frac{1}{w^{35} }[/tex]

This is because (w^5)^-7 expands to give w^-35 because you multiply the exponents. When you have a negative exponent, this can also be written as a reciprocal, i.e. x^-2 = 1/x². This means that we can write w^-35 as 1/(w^35), which doesn't include any negative exponents.

I hope this helps! Let me know if you have any questions :)

The answer without using negative exponents  [tex](w^{5})^{-7}[/tex] is  [tex]\frac{1}{w^{35} }[/tex] .

The following properties of exponents are -

Given expression is [tex](w^{5})^{-7}[/tex] .

Using the properties of exponents, we have -

= [tex]w^{-35}[/tex]

= [tex]\frac{1}{w^{35} }[/tex]  which does not have any negative exponents.

Thus, the answer without using negative exponents  [tex](w^{5})^{-7}[/tex] is  [tex]\frac{1}{w^{35} }[/tex] .

To learn more about properties of exponents, refer -

https://brainly.com/question/3187898

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The solution is:: the area cross sectional area of triangle form in the cone is 80ft²

Area is the measure of a region's size on a surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.

Given in the question,

radius of cone's base = 8ft

             cone's base = base of triangle

height of cone = 10 ft

height of cone = height of triangle

Area of triangle

Area = 1/2(h)(b)

here h = height of triangle

       b = base of triangle

A = 1/2(8)(10)

A = 40ft²

Since the section is 2 similar triangles back to back around the vertical center

so the area cross sectional area of triangle form in the cone is 2(40)ft² = 80ft²

To learn more on Area click:

brainly.com/question/20693059

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complete question:

You have a cone with a radius of 8 ft and a height of 10 ft. Find the area of the triangle formed by a perpendicular cross-section through the cone’s center.

Answer:

3n=5d and 3n = 5d and 3n + 6 = 2d + 4

Step-by-step explanation:

Answer:  The correct option is

(A) [tex]5n=3d~~~\textup{and}~~~3n+6=2d+4.[/tex]

Step-by-step explanation:  Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.

We are to select the system of equations that could be used to solve the problem.

Since n denotes the numerator and m denotes the denominator of the given fraction, so we have

[tex]\dfrac{n}{d}=\dfrac{3}{5}\\\\\\\Rightarrow 5n=3d,[/tex]

and

[tex]\dfrac{n+2}{d+2}=\dfrac{2}{3}\\\\\\\Rightarrow 3(n+2)=2(d+2)\\\\\Rightarrow 3n+6=2d+4.[/tex]

Thus, the required system of equations is

[tex]5n=3d~~~\textup{and}~~~3n+6=2d+4.[/tex]

Option (A) is CORRECT.

The attachment should answer some of your guys “what does k=?” Questions

Answer:

see below

Step-by-step explanation:

x < 4

x is less than 4

Since it is less than, there is an open circle at 4

less than means the line goes to the left

Answer:

No, the power multiplied to 8.64 should havean exponent of zero.

HOPE THIS WILL HELP YOU

Answer:

No, The power multiplied to 8.64 should have an 0 exponent.

Option 2 is correct

Step-by-step explanation:

Nick found the quotient of 8.64 and 1.25 × 10⁵.

Quotient of two number is form of division.

If quotient of a and b then expression is [tex]\dfac{a}{b}[/tex]

Correct steps:

[tex]\Rightarrow \dfrac{8.64\times 10^0}{1.25\times 10^5}[/tex]

[tex]\Rightarrow (8.64\div1.25)\times 10^{0-5}[/tex]

[tex]\Rightarrow 6.912\times 10^{-5}[/tex]

Nick steps:

[tex]\Rightarrow \dfrac{8.64\times 10^1}{1.25\times 10^5}[/tex]  wrong step

[tex]\Rightarrow (8.64\div1.25)\times 10^{1-5}[/tex]

[tex]\Rightarrow 6.912\times 10^{-4}[/tex]

The power multiplied to 8.64 should have an 0 exponent.

Therefore, Nick was wrong.

Answer:

Step-by-step explanation:

1/-2

Answer:

A) -1/2

Step-by-step explanation: woof

Answer:

60.7143% decrease  or 60%

Step-by-step explanation:

The percent of change from 56 to 22 is 60%.

The percent of change from 56 to 22 is 60%.

Problem-solving is the act of defining a problem; figuring out the purpose of the trouble; identifying, prioritizing, and selecting alternatives for an answer; and imposing an answer.

Problem-solving starts with identifying the issue. As an example, a trainer may need to parent out a way to improve a scholar's overall performance on a writing talent test. To do that, the instructor will overview the writing exams looking for regions for improvement.

Learn more about Problem-solving here: brainly.com/question/13818690

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Answer:

C and E

Step-by-step explanation:

Recall that according to the complex conjugate theorem, if P(x) is a polynomial function with real coefficients, and a+bi is an imaginary root of P(x), then its conjugate (i.e a-bi) must also be a root.

Here we see that 2 of the given roots are imaginary : i and 2+i

by the theorem given above, the conjugates of these must also be roots

i.e -i and 2-i

Answer:

Step-by-step explanation:

[tex]\text{Domain:}\\\\x-4\neq0\ \wedge\ x-2\neq0\ \wedge\ x^2-6x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x^2-4x-2x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x(x-4)-2(x-4)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ (x-4)(x-2)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x-4\neq0\ \wedge\ x-2\neq0\\\\\boxed{D:x\neq4\ \wedge\ x\neq2}[/tex]

[tex]\dfrac{1}{x-4}+\dfrac{x}{x-2}=\dfrac{2}{x^2-6x+8}\\\\\dfrac{1(x-2)}{(x-4)(x-2)}+\dfrac{x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\\\\\dfrac{x-2+x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\iff x-2+x(x-4)=2\\\\x-2+(x)(x)+(x)(-4)=2\\\\x-2+x^2-4x=2\qquad\text{subtract 2 from both sides}\\\\x^2-3x-4=0\\\\x^2-4x+x-4=0\\\\x(x-4)+1(x-4)=0\\\\(x-4)(x+1)=0\iff x-4=0\ \wedge\ x+1=0\\\\x-4=0\qquad\text{add 4 to both sides}\\x=4\notin D\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\in D[/tex]