Which object would a geologist date using carbon-14 dating?

Which Object Would A Geologist Date Using Carbon-14 Dating?

Answers

Answer 1

Answer:

Your answer is the rock pillar, the second image.

Explanation:

I'm an edg user too.


Related Questions

A triangle with equal sides of length 14 cm has -2.5-nC charged objects at each corner.

Part A
Determine the direction of the electrical force exerted on the object at the top corner due to the two objects at the horizontal base of the triangle.

A) vertically downward
B) horizontally rightward
C) horizontally leftward
D) vertically upward

Part B
Determine the magnitude of the electrical force exerted on the object at the top corner due to the two objects at the base of the triangle.

Answers

Final answer:

The electrical force exerted on the object at the top corner of the triangle is horizontally leftward, and its magnitude is approximately 3.487 N.

Explanation:

Part A: The direction of the electrical force exerted on the object at the top corner due to the two objects at the horizontal base of the triangle is horizontally leftward. Since the charges at the corners of the triangle are negative and the charges at the base are also negative, the electrical force will repel the top object in the opposite direction.

Part B: To determine the magnitude of the electrical force, we can use Coulomb's Law. The formula for Coulomb's Law is F = k * (q1 * q2) / r^2, where F is the force, k is the electric constant, q1 and q2 are the charges, and r is the distance between them.

In this case, both charges at the base of the triangle are -2.5 nC, and the distance between them and the top corner is 14 cm. Plugging in the values, we get F = (9 * 10^9 Nm^2/C^2) * ((-2.5 * 10^-9 C) * (-2.5 * 10^-9 C)) / (0.14 m)^2 ≈ 3.487 N.

A student finds an unlabeled bottle of liquid under
his kitchen sink. Which investigation would BEST
help him identify the unknown liquid as acidic,
basic, or neutral?
healing the unknown liquid to its boiling point
B. cooling the unknown liquid to its freezing point
C adding some of the unknown liquid to red litmus
paper
D. adding an equal amount of water to the
unknown liquid

Answers

Answer:

C. Adding some of the unknown liquid to red litmus paper.

Explanation:

Since the student doesn't know what the liquid is, it is not safe to experiment with it by boiling, cooling, or adding water to it. The safest option would be to add a small bit of the liquid to the litmus paper, which will identify the liquid as neutral, basic, or acidic.

The answer is C. Adding some of the unknown liquid to red litmus paper.

a spring is used to launch a ball vertically into the air. the spring has a spring constant of 200N/m and is compressed by 5 cm. if a ball of 10g is placed above the spring, what is the height reached by the ball assuming all the elastic potential energy is converted to gravitational potential energy?​

Answers

Answer:

2.55 m

Explanation:

Elastic energy = gravitational energy

½ kx² = mgh

h = kx² / (2mg)

h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)

h = 2.55 m

The height that the ball will assume is equal to 2.55 m

What is energy conservation?

This is called the Law of Conservation of Energy. In the case of a hydroelectric plant, for example, water flows in the river at a certain speed and falls from a certain height, turning like turbines, which transform mechanical energy into electrical energy.

So, this is Elastic energy = gravitational energy, making the calculus we have:

[tex](1/2)kx^2 = mgh\\h = kx^2 / (2mg)\\h = (200 N/m) (0.05 m)^2 / (2 * 0.010 kg * 9.8 m/s^2)\\h = 2.55 m[/tex]

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6. Which of the following is an example of a vector quantity?

Answers

Answer:

can I have a picture or like options

Explanation:

please , if you send them I'll edit answer

Velocity is an example of a vector quantity.

What is velocity ?

velocity is defined as rate of change of displacement of the object with respect to rate of change in time. In mathematics It is written as :

                                        [tex]\begin{aligned}v&=\frac{d_{2}-d{1}}{t_{2}-t_1}\end{aligned}[/tex]

velocity is nothing but speed in particular direction. That is velocity is vector quality having both magnitude and direction where as speed is just the magnitude of velocity.

Therefore, velocity is an example of a vector quantity and all other are scaler quality.

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heat energy on earth escapes into space . which heat transfer ?

Answers

Explanation:

I know that if the sun stopped shining, Earth would lose it's heat and we'd all freeze and die. On the other hand, we don't keep increasing temperature when the sun shines because heat escapes to space. But how does the heat leave earth's atmosphere if space is a vacuum and vacuums don't conduct heat except through waves

Earth would lose it's heat and we'd all freeze and die. On the other hand, we don't keep increasing temperature when the sun shines because heat escapes to space. But how does the heat leave earth's atmosphere if space is a vacuum and vacuums don't conduct heat except through waves

Explanation:

Object is going 22m/s and is 3kg find momentum

Answers

Answer:

66 kgm/s

Explanation:

We are given;

Velocity of the object as 22 m/sMass of the object as 3 kg

We are required to determine the momentum of the object;

We need to know that momentum is the product of mass and velocity of an object.Therefore; Momentum = Velocity × Mass

In this case;

Momentum = 22 m/s × 3 kg

                  = 66 kgm/s

Thus, the momentum of the object is 66 kgm/s

An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance does the object traverse while accelerating?

Answers

Answer: 90m

Explanation:

Use Equation for distance:

S=a*t²/2

use eqation for acceleraton a=(Vf-Vs)/t

Vs- starting speed

Vf - final speed

a-accelaration

---------------------------------

a=5m/s²

Vs=0m/s

Vf=30m/s

use

a=(Vf-Vs)/t

to find time

t=(Vf-Vs)/a

t=30m/s/5m/s²

t=6s

Now calculate distance that object travel using:

S=(a*t²)72

s=(5m/s²*(6s)²)/2

S=90m

If an object initially at rest accelerates at 5 meters per second² until it attains a speed of 30 meters per second, then the distance traveled by the object would be 90 meters.

What are the three equations of motion?

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem an object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second.

By using the third equation of motion given by newton

v² - u² = 2×a×s

30² - 0² = 2*5*s

10s = 900

s = 900 / 10

  =90 meters

Thus,If an object initially at rest accelerates at 5 meters per second² until it attains a speed of 30 meters per second, then the distance traveled by the object would be 90 meters.

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the earths gravity pulls on the moon and keeps it in its orbit. the moons gravity will then___.?
a pull on smaller objects such as astroids but has no effect on the earth
b pull back on earth
c push the moon away from the earth
d affect nothing

Answers

Answer:

The best options from the answer choises above would be Opption B.

Explanation:

Gravitational forces are equal in both directions.

good luck.

Kgms^-1 ÷ m× (ms^-1)^2
Can u simplify this

Answers

Answer:

[tex]\displaystyle \frac{Kg\ m^2}{s^3}[/tex]

Explanation:

Physic Units

Physic magnitudes are expressed in international units in different systems. The most used by this modern times is the SI (International System of Units) which expressed length in meters, time in seconds and mass in kg, just to mention some of the most-used magnitudes.

The given expression is a composition of basic units:

[tex]\displaystyle \frac{Kg\ m\ s^{-1}}{m}(m\ s^{-1})^2[/tex]

Converting negative in positive powers:

[tex]\displaystyle \frac{Kg\ m\ }{m\ s}\left ( \frac{m}{s} \right )^2[/tex]

Expanding the square

[tex]\displaystyle \frac{Kg\ m\ }{m\ s}\left ( \frac{m^2}{s^2} \right )[/tex]

Simplifying by m and multiplying like factors

[tex]\displaystyle \frac{Kg\ m^2}{s^3}[/tex]

When Mr. Peterson first met his teenaged granddaughter, he thought she was
self-centered and silly. After spending more time with her, however, he now
thinks she is a great person. This is an example of the:

Answers

Question: when Mr. Peterson first met his teenage granddaughter, he thought she was self-centered and silly. after spending more time with her, however, he now thinks she is a great person. this is an example of:

A. fundamental attribution error

B. Mere exposure effect

C. Cognitive dissonance

D. Scapegoat theory

Answer:

when Mr. Peterson first met his teenage granddaughter, he thought she was self-centered and silly. after spending more time with her, however, he now thinks she is a great person. this is an example of:  Mere exposure effect

Explanation:

The mere exposure effect is something on first exposure you dislike it, but after being spending more time with it you will start liking it. Moreover spending time with something or someone getting aware of that person make you believe that you have started liking it, despite the initial aversion. It is psychological phenomenon which with time build up a preference for the thing after getting familiar to them. Also, called as familiarity principle.

Answer: mere exposure effect

Explanation:

The force of the players head on the ball is 1.5N upward, What is the force of the ball on the players head?

Answers

The force is 1.5N acting downward or -1.5N.

Why?

To answer this question, we need to remember the Newton's Third Law. This Law states that for every force applied upon an object, there is an equal force acting in the opposite direction. This Law is also called "action-reaction Law".

So, if the force of the players heads applied on the ball is equal to 1.5N (upward), the force applied by the force on the players heads will be exactly equal, but with opposite direction, or -1.5N (downward).

Have a nice day!

two 2.5 kg balls move away from each other one traveling 3 m/s to the right the other 4 m/s to the left what is the magnitude of the total momentum of the system? answer in units​

Answers

Answer:

2.5 kg.m/s

Explanation:

Taking left side as positive while right side direction as negative then

Momentum, p= mv where m is the mass of the object and v is the velocity of travel

Momentum for ball moving towards right side=mv=2.5*-3=-7.5 kg.m/s

Momentum for the ball moving towards the left side=mv=2.5*4=10 kg.m/s

Total momentum=-7.5 kg.m/s+10 kg.m/s=2.5 kg.m/s

Final answer:

The total momentum of the two 2.5 kg balls moving in opposite directions is 2.5 kg×m/s, calculated by using the principle of conservation of momentum.

Explanation:

The question you're asking involves the conservation of momentum in physics. Momentum is defined as the product of the mass and velocity of an object. In a closed system where no external forces are involved, the total momentum of the objects before the event (collision, separation, etc.) is equal to the total momentum after the event.

In this case, two 2.5 kg balls are moving in opposite directions, one at 3 m/s and the other at 4 m/s. You can calculate the total momentum by adding together the momentum of each ball, taking into account their respective directions.

To find the magnitude of the total momentum of the system, you can use the formula: Total Momentum = Mass Ball 1 × Velocity Ball 1 (direction1) + Mass Ball 2 × Velocity Ball 2 (direction2). Since one ball is moving to the right and the other is moving to the left, we treat these directions as positive and negative respectively.

Therefore, the total momentum is: (2.5 kg × 3 m/s) - (2.5 kg × 4 m/s) = 7.5 kg×m/s - 10 kg×m/s = -2.5 kg × m/s. But, you're asking for the magnitude, so we take it as positive, which is 2.5 kg × m/s.

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which measurement is the most precise??
27 m
27.7 m
27.791 m
27.79 m​

Answers

Answer: 27.791 meters

Explanation: The precision of a measure depends on the number of significative decimals that it has, so the number that is most exact is the one with more numbers after the decimal point, in this case, is the third option: 27.791 m

This one is the most exact because you know that the lenght is:

27 meters, 7 centimetrs and 9.1 milimeters

If a space ship is traveling with a constant acceleration of 75 m/s^2 and travels for three weeks, how far did it travel and what was it's velocity before it stopped?

Answers

Answer:

The final velocity of the ship is, v = 136050000 m/s

The total distance covered, s = 6.94 x 10¹⁷ m

Explanation:

Given data,

The constant acceleration of the space ship, a = 75 m/s²

The time period of the space ship acceleration is t = 3 weeks

                                                                                   t = 1.814 x 10⁶ s

The initial velocity of the ship is u = 0 m/s

The final velocity of the ship is,

                                    v = u + at

                                       = 0 + 75 (1.814 x 10⁶)

                                       = 136050000 m/s

The distance space ship traveled, can be calculated from the second equation of motion.

                                   s = ut + ½ at²

                                      = 0 + ½ 75 (136050000)²

                                       = 6.94 x 10¹⁷ m

Hence, the total distance covered, s = 6.94 x 10¹⁷ m

Two men decide to use their cars to pull a truck stuck in mud. They attach ropes and one pulls with a force of 821 N at an angle of 32◦ with respect to the direction in which the truck is headed, while the other car pulls with a force of 1140 N at an angle of 26◦ with respect to the same direction.
What is the net forward force exerted on the truck in the direction it is headed?

Answers

Answer:

1737.8 N

Explanation:

Given information

[tex]F_1= 821 N[/tex]

[tex]F_2= 1140 N[/tex]

[tex]\theta_1=32^{\circ}[/tex]

[tex]\theta_2=26^{\circ}[/tex]

Net force, [tex]F_{net}=F_1 cos \theta_1+F_2 cos \theta_2=821cos 32^{\circ}+ 1140 cos 26^{\circ}=1737.833662 N \approx 1737.8 N[/tex]

whar are the phenotypes for FF Ff ff

Answers

Answer:

F, F, f (if I'm understanding the question correctly)

Explanation:

Phenotypes are the physical trait shown. In FF, Ff, ff a capital letter means that the gene is dominant and therefore always shows when paired with either another of itself or a recessive (lowercase). So, for FF, you see F as the phenotype shown, and for Ff, you see F as the phenotype because F is dominant over the recessive f. In ff, however, since you have two recessives, only then can you see f as the phenotype because you have no dominant traits.

How much work can you do using a 600 watt stove and oven for 10 minutes

Answers

Answer:

360 kJ

Explanation:

Energy = power × time

E = 600 J/s × (10 min × 60 s/min)

E = 360,000 J

E = 360 kJ

Using a 600 watt stove and oven for 10 minutes results in an energy consumption of 0.1 kilowatt-hours (kWh),

Using the formula:

Energy (in watt-minutes) = Power (in watts)× Time (in minutes)

For a 600 watt stove:

Power = 600 wattsTime = 10 minutes

Energy = 600 watts× 10 minutes

= 6000 watt-minutes

However, energy consumption is usually expressed in kilowatt-hours (kWh). To convert watt-minutes to kilowatt-hours, use the following conversion:

1 watt-minute = 1/60,000 kilowatt-hour

Therefore:

Energy = 6000 watt-minutes× (1/60,000) kWh/watt-minute

= 0.1 kWh

The 600 watt stove and oven can do 0.1 kWh of work in 10 minutes.

in a hydraulic press the small cylinder has a diameter 10.0cm while the large has 25cm if the force of 600N is applied to the small cylinder. find the force exacted on the large cylinder

Answers

Answer:

3750 N

Explanation:

Pressure on the small cylinder = pressure on the large cylinder

P₁ = P₂

F₁ / A₁ = F₂ / A₂

F₁ / (π d₁² / 4) = F₂ / (π d₂² / 4)

F₁ / d₁² = F₂ / d₂²

600 N / (10.0 cm)² = F / (25.0 cm)²

F = 3750 N

Answer:

3751.34N

Explanation:

Pressure in large piston = pressure in smaller piston

P2 = P1

Pressure = Force / Area

Area = pi * r²

r1= d1/2 = 10/ 2 = 5cm = 0.05m

Area(A1) = 22/7 * (0.05)² = 0.00785m²

r2 = d2 / 2 = 25/2 = 12.5cm = 0.125m

Area(A2) = 22/7 * (0.125)² = 0.04908m²

Pressure = Force / Area

F1/A1 = F2/A2

600 / 0.00785 = F2 / 0.04908

F2 = (600 * 0.04908) / 0.00785

F2 = 3751.34N

Gravitational force of attraction “F” exists between two point masses A and B when a fixed distance separates them. After mass A is tripled and mass B is halved, the gravitational attraction between the two masses is

1/6 F
2/3 F
3/2 F
6 F

Answers

Answer:

the new gravitational force between the two masses is [tex]\frac{3}{2}[/tex] of the original force (third option in the provided list)

Explanation:

Recall the expression for gravitational force : [tex]F_g=G\,\frac{m_A*\,m_B2}{d^2}[/tex], where [tex]m_A[/tex] and [tex]m_B[/tex] are the point masses, d the distance between them, and G the universal gravitational constant.

I our problem, the distant between the particles stays unchanged, and we need to know what happens with the magnitude of the force as mass A is tripled, and mass B is halved.

Initial force expression: [tex]F_i=G\,\frac{m_A\,m_B}{d^2}[/tex]

Final force expression: [tex]F_f=G\,\frac{3*m_A\,m_B/2}{d^2}\\F_f=G\,\frac{m_A\,m_B\,*\,3/2}{d^2}\\F_f=G\,\frac{m_A\,m_B}{d^2}\,*\frac{3}{2} \\F_f=F_i\,*\frac{3}{2}[/tex]

Where we have recognized the expression for the initial force between the particles, and replaced it with [tex]F_i[/tex] to make the new relation obvious.

Therefore, the new gravitational force between the two masses is [tex]\frac{3}{2}[/tex] of the original force.

Answer:

3/2 F is the Answer

As ocean waves approach shore, their velocity decreases. How does a decrease in velocity affect the frequency and wavelength of the waves entering the shallow water?

A. frequency increases and wavelength decreases

B. frequency decreases and wavelength increases

C. frequency stays the same and wavelength increases

D. frequency stays the same and wavelength decreases

Answers

Answer:

D

Explanation:

The relationship between velocity, frequency and wavelength is given by v=fλ

The ocean wave approach the shore at a constant frequency

From the relationship a decrease in velocity will also decrease the wavelength and vice versa.

As ocean waves approach shore, their velocity decreases. How does a decrease in velocity affect the frequency and wavelength of the waves
entering the shallow water?
A
frequency increases and wavelength decreases
B. frequency decreases and wavelength increases
C. frequency stays the same and wavelength increases
D.
frequency stays the same and wavelength decreases

Answers

Final answer:

OPTION D

As ocean waves reach shallower water and velocity decreases, the frequency remains the same and the wavelength decreases to adhere to the wave equation.

Explanation:

As ocean waves approach shore, their velocity decreases due to the interaction with the shallower sea floor. However, the frequency of the waves does not change because it is determined by the original energy source that created the waves, such as wind or seismic activity, and it remains consistent. Instead, when the velocity decreases, the wavelength of the waves must also decrease to maintain the same frequency. This phenomenon is described by the wave equation v = f × λ, where v is the velocity, f is the frequency, and λ (lambda) is the wavelength. Consequently, if the wave velocity decreases and the frequency remains constant, the equation dictates that the wavelength must also decrease. Therefore, the correct answer to the question is D: frequency stays the same and wavelength decreases.

Final answer:

As ocean waves approach the shore and slow down, the frequency remains unchanged and the wavelength decreases. The relationship is described by the equation v = fλ, where velocity decreases and frequency cannot change due to the wave's existing conditions.

Explanation:

As ocean waves approach the shore and their velocity decreases due to the shallower water, their frequency remains unchanged because it is determined by the original conditions that generated the wave. However, because the speed of the wave (or velocity) is the product of its frequency and wavelength, a decrease in velocity while maintaining the same frequency necessitates a corresponding decrease in wavelength. Therefore, the correct answer to how a decrease in velocity affects the frequency and wavelength of the waves entering shallow water is D. frequency stays the same and wavelength decreases.

Regarding other relationships between wave properties, it’s important to note that the frequency and wavelength of a wave are inversely related, as shown by the wave equation v = fλ, where v is the wave speed, f is the frequency, and λ (lambda) is the wavelength. Therefore, if the wave's speed decreases and its frequency cannot change due to the wave already being in existence, the wavelength must decrease. The idea that the frequency of the wave doesn't change when the wave moves from one medium to another is also true in other contexts, such as light traveling from air into water or glass.

Which of the following factors would affect the weather patterns of a region?
A)Latitude
B)Altitude
C)Near by bodies of water
D)All of these

Answers

Answer:

D) All of those

Explanation:

You can use "LOWER Near water" to remember that factors which affect the weather patterns of a region.

Latitude. It tends to be hotter when closer to the equator.

Ocean currents. The temperature of the ocean can come from far away and affect the temperature of the air in a new location.

Wind and air mass. Air masses, blown by the wind, change the weather in an area depending on where it was formed.

Elevation, which is the same as altitude. It tends to be colder higher up.

Relief. When mountains block wind and precipitation on one side, making the other side have "relief" on the leeward side.

Near water. Temperature is more moderate because water does not change temperature as fast.

It would be all of them

To be a healthy family, which of the statements below is TRUE:
A.
Family members need to be perfect.
B.
Family members must include a mom, dad, and children.
C.
Family members try to work out differences together.
D.
Family members must never disagree.

Answers

C. Is the most important

A 30.9 kg rocket has an engine
that creates a 790 N upward force
("thrust"). What is its acceleration?
(Don't forget its weight!)
(Unit = m/s)

Answers

Answer:

acceleration = 15.8 m/s^2

Explanation:

Weight of rocket which acts downward is W = mass × acceleration due to gravity

w = 30.9 × 9.81

W = 303.129 N

force of 790 N acts upward and it is greater than W hence acceleration is in upward direction and is given by Newton's second law of motion as

790 - W = mass × acceleration

790 - 303.129 = 30.9 × acceleration

486.871  = 30.9 × acceleration

acceleration = 486.871 / 30.9

acceleration = 15.756 m/s^2

acceleration = 15.8 m/s^2

A 0.0427 kg racquet-ball is moving
22.3 m/s when it strikes a
stationary box. The ball bounces
back at 11.5 m/s, while the box
moves forward at 1.53 m/s. What
is the mass of the box?
(Unit = kg)​

Answers

Answer:

Mass of the box = 0.9433 kg

Explanation:

Mass of racket-ball [tex](m_1)[/tex] = 0.00427 kg

Velocity of racket-ball before collision [tex](v_{1i})[/tex] = 22.3 m/s

Velocity of racket-ball after collision with box [tex](v_{1f})[/tex] = -11.5 m/s

[Since ball is bouncing back, so velocity is taken negative.]

Velocity of the box before collision [tex]v_{2i}[/tex] = 0 m/s

[Since the box is stationary, so velocity is taken zero]

Velocity of box moving forward after collision [tex]v_{2f}[/tex]= 1.53 m/s

To find the mas of the box [tex]m_2[/tex].

By law of conservation of momentum we have:

Momentum before collision = Momentum after collision

This can be written as:

[tex]p_i=p_f[/tex]

[tex]m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}[/tex]

We can plugin the given value to find [tex]m_2[/tex]

[tex](0.0427\times 22.3)+(m_2\times 0)=(0.0427\times (-11.5))(m_2\times 1.53)[/tex]

[tex]0.9522+0=-0.4911+1.53m_2[/tex]

Adding both sides by 0.4911

[tex]0.9522+0.4911=-0.4911+0.4911+1.53m_2[/tex]

[tex]1.4433=1.53m_2[/tex]

Dividing both sides by 1.53.

[tex]\frac{1.4433}{1.53}=\frac{1.53m_2}{1.53}[/tex]

[tex]0.9433=m_2[/tex]

∴ [tex]m_2=0.9433[/tex] kg

Mass of the box = 0.9433 kg (Answer)

Answer:

0.9433

Explanation:

Which statement best describes insulators? Free electrons can move to other atoms Electrons within their atoms are strongly held by the nuclei Permits charged particles to move freely through it Most electrons within their atoms are unpaired

Answers

Answer:

The statement that best describes insulators is "Electrons within their atoms are strongly held by the nuclei"

Explanation:

Atoms are constituted by a nucleus with positive charge (protons and neutrons), around which negative charges (electrons) revolve.

Substances that have a huge amount of "free electrons" that can move through the material are called conductors. This is due to the low resistance to the movement of the load or electric current.

Materials that do not conduct electricity are called insulators. In this case the electrons are strongly bound to the nucleus and cannot move freely. In this way a great resistance to the flow of electric current is offered.

Finally, semiconductors are the materials that can have electrical properties of conductors or insulators.

So the statement that best describes insulators is "Electrons within their atoms are strongly held by the nuclei"

Answer:

it has a high resistivity because it opposes the movement of electrons

Explanation:

A golf club hits a 0.0459 kg golf ball
at rest. Afterwards the ball leaves
at 63.9 m/s. What impulse was
given to the ball?
(Unit = kg*m/s)​

Answers

Answer:

2.933 kg m/s

Explanation:

impulse = change in momentum

impulse = mass ( final velocity - initial velocity )

              = 0.0459 ( 63.9 - 0 )

               = 0.0459 × 63.9

                = 2.93301 kg m/s

or              = 2.933 kg m/s up to 4 significant figures

The impulse given to the golf ball is [tex]2.9331 kgm/s[/tex].

calculated as the change in momentum from rest to [tex]63.9 m/s[/tex] using the golf ball's mass.

To determine the impulse given to the golf ball, we need to use the formula:

[tex]Impulse (J) = Change in Momentum (Δp)[/tex]

First, we calculate the initial momentum:

[tex]Initial momentum (pinitial) = mass (m) * initial velocity (vinitial)[/tex]
Since the golf ball is at rest initially, initial velocity [tex](vinitial) = 0 m/s:[/tex]

[tex]pinitial = 0.0459 kg * 0 m/s = 0 kgm/s[/tex]

Next, we calculate the final momentum:

Final momentum [tex](pfinal) = mass (m) * final velocity (vfinal)[/tex]
[tex]vfinal = 63.9 m/s:[/tex]

[tex]pfinal = 0.0459 kg * 63.9 m/s = 2.9331 kgm/s[/tex]

Now, we find the impulse by calculating the change in momentum:

[tex]Impulse (J) = Δp = pfinal - pinitial[/tex]
Impulse (J) = [tex]2.9331 kgm/s - 0 kgm/s = 2.9331 kgm/s[/tex]

Thus, the impulse given to the ball is [tex]2.9331 kgm/s.[/tex]

Which of the following correctly describes the number of protons and electrons in an atom?

The number of protons is higher than the number of electrons

The number of protons is equal to the number of neutrons

The number of electrons is higher than the number of protons

When protons are present electrons are absent

Answers

The number of protons equal to the number of electrons but to find the number of neutrons you need to subtract the mass number from the atomic number

(O). The number of protons is equal to the number of electrons. None of the options is correct.

What are atoms?

Atoms are the basic building blocks of matter. They are the smallest particles of an element that retain the chemical properties of that element. An atom consists of a nucleus, which is composed of positively charged protons and neutral neutrons, surrounded by a cloud of negatively charged electrons.

Atoms are electrically neutral, which means that the number of positively charged protons in the nucleus is equal to the number of negatively charged electrons in the electron cloud surrounding the nucleus. This balance of charges results in an overall neutral charge for the atom. The number of neutrons in an atom can vary, but it is not directly related to the number of protons and electrons. Neutrons are neutral particles that help to stabilize the nucleus, but they do not contribute to the overall charge of the atom.

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How does the nitrogen enter the food web?

Answers

When bacteria in the soil takes nitrogen from the air it becomes nitrates it can finally move through the food chain in this form.

Nitrogen enters the food web by means of nitrogen-fixing bacteria and algae in the soil.

Nitrogen is an important component of living organisms. The atoms of nitrogen are found in all strands of DNA and protein. The atmosphere nitrogen gas N₂ is converted into ammonia by bacteria. Ammonia is the usable product of nitrogen gas, utilized by plants. When animals eat the plants, they acquire nitrogen into usable compounds and hence, the nitrogen enters into the food web.

Nitrogen gas from the atmosphere is fixed into organic nitrogen by using nitrogen-fixing bacteria. This organic nitrogen enters into the terrestrial food webs. It leaves the food webs as the nitrogenous wastes in the soil. The nitrogen compounds present in soil by algae is the process called Eutrophication. Hence, the bacteria play a vital role in the conversion of nitrogen into ammonia.

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How long will the ball be in the air if the cliff is 120 m tall and the ball falls to the base of the cliff?

Answers

Answer:

For 5 s the ball will remain in air.

Explanation:

Given:

Displacement of the ball is equal to height of cliff, [tex]S=120\ m[/tex]

Acceleration of the ball is acceleration due to gravity, [tex]a=g=9.8\ m/s^2[/tex]

Assuming the ball is dropped from the top.

Hence, initial velocity of the ball is, [tex]u=0\ m/s[/tex]

Let 't' be the time the ball takes to reach the base of cliff.

Now, we have to use the Newton's equations of motion that relates displacement, initial velocity, acceleration and time.

So, we use the following equation of motion:

[tex]S=ut+\frac{1}{2}at^2[/tex]

Plug in the given values and solve for 't'. This gives,

[tex]120=0+\frac{1}{2}(9.8)t^2\\120=4.9t^2\\\frac{120}{4.9}=t^2\\t^2\approx25\\t=\sqrt{25}=5\ s[/tex]

Therefore, the time till the ball is in air is approximately 5 s.

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