The correct answer is A. Sediment
Answer: A. Sediment
Eutrophication is a phenomena in which a water body gets enriched with minerals and nutrients frequently entered into water body due to run-off from the land, which facilitates dense growth of plants especially on the superficial layers of water body. Decaying organisms, fertilizers and pollution all add nutrients and minerals necessary for plant growth specifically remain floating on the superficial layers of water where plant growth takes place but sediments gets settled at the bottom of the water body, the minerals present in it remain settle at the bottom and hence, does not contribute to eutrophication.
You have 9 stones that are identical in appearance. One of these stones weighs just a bit more than the other 8. These other 8 stones are exactly the same in weight. Using a balance scale only TWICE, how can you determine exactly which stone is the heavier?
t (sec) 0.0 - 0.5 - 1.0 - 1.5 - 2.0 - 2.5 - 3.0 - 3.5 - 4.0
s (ft) 12.5 - 26 - 36.5 - 44 - 48.5 - 50 - 48.5 - 44 - 36.5
Assuming that this smooth curve represents the motion of the body, estimate the velocity at t = 1.0, t = 2.5, and t = 3.5.
A state patrol officer saw a car start from rest at a highway on-ramp. She radioed ahead to another officer 30 mi along the highway. When the car reached the location of the second officer 26 min later, it was clocked going 60 mi/hr. The driver of the car was given a ticket for exceeding the 60/mi/hr speed limit. Why can the officer conclude that the drive exceeded the speed limit?
The officer conclude that the driver exceeded the speed limit as the speed was 69mph.
speed = distance /time
speed = 30 miles / 26 minute
speed = 30 miles /26 minute x 60 minutes/1 hour
speed = 900 miles/13 hours
speed = 69 mph.
What is your maximum speed limit?the prevailing maximum pace limit for cars on expressways is a hundred and twenty km and on national highways, the maximum velocity restriction is 100 mph.
Velocity limits in India vary by way of nation and car type. In April 2018, the Union Ministry of street shipping and Highways constant the most velocity limit on expressways at a hundred and twenty km/h, for national highways at one hundred km/h, and for urban roads at 70 km/h for the M1 class of vehicles.
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Which of the following is true about melting and freezing points?
Choices:
A. The melting point is always the same as the freezing point.
B. The melting point is achieved at a higher temperature than the freezing point.
C. The freezing point is applied to liquids, whereas the melting point is applied only to gases.
Which of the following is true about melting and freezing points?
Choices:
A. The melting point is always the same as the freezing point.
B. The melting point is achieved at a higher temperature than the freezing point.
C. The freezing point is applied to liquids, whereas the melting point is applied only to gases.
Answer:
Explanation:
I agree with what the first person said
Final answer:
The correct answer is that the melting point and freezing point of a substance are always the same, illustrating the equilibrium between the solid and liquid states of that substance at a specific temperature, such as 0°C for water.
Explanation:
The correct answer to which of the following is true about melting and freezing points is: The melting point is always the same as the freezing point. This principle is crucial in understanding the thermal properties of substances. The temperature at which a substance changes from solid to liquid (melting point) is the same temperature at which it changes from liquid to solid (freezing point) when the process is reversible and under the same pressure conditions. For instance, with water (H₂O), this equilibrium occurs at 0°C, illustrating that at this temperature, the solid and liquid states of H₂O are in equilibrium (H₂O (s) = H₂O (l)).
It's essential to refute common misconceptions like the melting point being higher than the freezing point or that these concepts apply differently to liquids and gases. All materials, whether solid, liquid, or gas at room temperature, have characteristic melting/freezing points that do not depend on their state at room temperature but rather on their inherent thermal properties.
When a current is running through a coil of wire with an iron core, what is created around the wire that is carrying the current?
Answer:
A magnetic field
Explanation:
what connects neurons and what chemicals help neurons communicate
Answer:
synapses
The chemical that helps them to communicate is neurotransmitters
Explanation: synapses have a receiving end and a sending end that helps them receive signal transmitted through the neurotransmitters
Identify which sets of Quantum Numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
3,2,0,1/2
2,2,-1, 1/2
4,3,-4,1/2
1,0,0,1/2
2,2,1,-1/2
3,2,1,1
0,1,1,-1/2
3,3,1,1/2
2,-2,-2,-1/2
3,2,2,1/2
4,2,1,1/2
2,1,-1,-1/2
As the time required to run up the stairs increases, the power developed by that person
Increases, decreases, or remains the same. Is the answer decreases?
As the time to run up the stairs increases, the power developed decreases..
When analyzing the relationship between time and power, it's essential to consider the fundamental definition of power as the rate at which work is done.
In the context of running up stairs, the work done involves overcoming the gravitational force acting against the person's ascent.As time increases while climbing the stairs, it indicates a slower pace, meaning the person is taking longer to cover the same vertical distance. Since the work done (ascending against gravity) remains constant, the longer time translates to a lower rate of work done, leading to a decrease in power output.This can also be understood using the formula for power -
Power (P) = Work (W) / Time (t)
When the time (t) increases and the work (W) remains constant, the power output (P) decreases.
Thus, as the time required to run up the stairs increases, the power developed by that person decreases.
What do telescopes detect that assists astronomers making discoveries in space
Telescopes assist astronomers by detecting and analyzing light from celestial objects in great detail, enabling scientists to view distant objects and investigate their properties, including the chemistry of their atmospheres. They provide insight into the deep time and space of the universe.
Explanation:Telescopes play an integral role in astronomical discoveries as they allow us to detect and analyze light and other forms of electromagnetic radiation from celestial objects. The key components in telescopes that make this possible are their light-gathering power and high-resolution imaging capabilities.
Telescopes gather more light than the human eye, allowing them to observe dim and distant objects in more detail. They can detect images and spectra of planets and galaxies, some of which are so distant that their light has traveled for billions of years to reach us. This provides profound insight into the structure of the universe and the life cycles of celestial bodies.
Moreover, by observing the chemistry of these planets' atmospheres, telescopes enable astronomers to search for signs of extraterrestrial life. Advanced telescopes such as the Hubble Space Telescope and the Very Large Telescope in Chile provide views of deep space and deep time – periods of time deep in the past – at an unrivaled resolution.
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Describe the circumstances for which the output work would equal the input work in a machine
Why magnetic monopole does not exist? ...?
Which statement is true concerning the evidence for black holes?
Scientists can see black holes with powerful telescopes.
Scientists can see the effect of black holes on nearby stars.
Scientists can see trails left in space by black holes.
There is no evidence for black holes.
PLEASE HELP The rotating light on a lighthouse is 400 feet from a cliff. It completes one rotation every 10 seconds. The equation representing the distance, d, in feet that the center of the circle of light is from the lighthouse is d(t) = 400sec (πt/5). What is the period of d(t)? (Enter only the number.) ...?
A sign has a mass of 1050 kg, a height h = 1 m, and a width W = 4 m. It is held by a light rod of length 5 m that is perpendicular to a rough wall. A guy wire at 23° to the horizontal holds the sign to the wall. Note that the distance from the left edge of the sign to the wall is 1 m.
Suppose we rely upon friction between the wall and the rod to hold up the sign (there is no hinge attaching the rod to the wall). What is the smallest value of the coefficient of friction µ such that the sign will remain in place? ...?
What is the magnitude of the acceleration of a speck of clay on the edge of a potter’s wheel turning at 45 rpm (revolutions per minute) if the wheel’s diameter is 35 cm?
Will Upvote
Which electrons participate in chemical bonding?
A. the innermost electrons
B. valence electrons
C. any electrons
D. core electrons
B. Valence Electrons
_________________
Reason:
The valence electrons are the number of electrons in an outer shell of an atom that can participate in forming chemical bonds with other atoms. Atoms with a relatively empty outer shell will want to give up electrons.
Explain how you can tell the difference between the voices of two people if they are saying the same word.
The temperature of water in a beaker is 45°C. What does this measurement represent?
Answer:
the average kinetic energy of water particles
Explanation:
How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity
Final answer:
To find the length of a pendulum with 1.0 seconds on the Moon, we use the formula for a pendulum's period, adjust the acceleration due to gravity to the Moon's 1.63 m/s², and solve for the pendulum's length.
Explanation:
The subject question inquires about the length of a pendulum on the Moon that has a period of 1.0 seconds, taking into consideration that the Moon's gravity is 1/6th that of Earth's. The formula for the period of a simple pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
On Earth, assuming the acceleration due to gravity (g) is approximately 9.81 m/s², the length (L) for a pendulum with a period (T) of 1.0 seconds can be calculated using this formula. However, since we are interested in the situation on the Moon where g is 1/6th that of Earth's, we would have to adjust the acceleration due to gravity in our formula to be 1.63 m/s² (since 9.81 m/s² divided by 6 equals approximately 1.63 m/s²).
Accordingly, by rearranging the formula to L = T²g/(4π²), and substituting T with 1.0 second, and g with 1.63 m/s², one can compute the appropriate length of the pendulum on the Moon that would have a period of 1.0 second.
Final answer:
The length of a pendulum with a period of 1.0 second on the Moon can be calculated by rearranging the period formula for a simple pendulum, T = 2π√(L/g), and substituting in the Moon's gravity of 1.63 m/s².
Explanation:
The length of a pendulum that has a period of 1.0 second on the Moon, where gravity is 1/6th of Earth's gravity, can be found using the formula for the period of a simple pendulum, T = 2π√(L/g). On Earth, where the standard acceleration due to gravity, g, is approximately 9.81 m/s², a 1.0-second period requires a certain pendulum length. However, on the Moon, the acceleration due to gravity is only 1.63 m/s².
We can rearrange this formula to solve for the length (L) of the pendulum on the Moon: L = (T² * g) / (4π²). By substituting T for 1.0 second and g for 1.63 m/s², the length of the pendulum on the Moon can be calculated.
Using the provided formula, we get L = (1.0² seconds² * 1.63 m/s²) / (4π²) which gives us the length of the pendulum on the Moon. You would then perform the calculation to find the exact value for L.
I'LL GIVE ONE OF YOU BRAINLIEST ANSWER. PLEASE HELP ME
a) The electric field between two equally but oppositely charged parallel plates is 2.35 N/C [south]. If a charge of –2.00 C was placed at the midway point between the plates, what force (magnitude and direction) would act on the charge?
Give the direction as acting north or south. b) For another set of parallel plates, a charge of –4.00 C experiences a force of 6.00 x 10–3 N [east]. Determine the magnitude and direction of the electric field between these plates. Give the direction as east or west. (continued) 58 G r a d e 1 2 P h y s i c s Assignment 7.4: Electric Field between the Plates of a Parallel Plate Capacitor (continued) d) Label each plate in the diagram below with the appropriate polarity according to the information from part (c) above
How much force is needed to stop a 90-kg soccer player if he decelerates at 15 m/s²? A. 6 N B. 15 N C. 135 N D. 1350 N
The answer is 1350 N
White bunnies are a common sight on farms and in pet stores. Why are these domestic white rabbits uncommon in the wild?
Answer:
c
Explanation:
Which three statements about electromagnetic radiation are true?
1)Light is a kind of electromagnetic radiation.
2)Electromagnetic radiation can travel only short distances.
3)Electromagnetic radiation has no mass.
4)Electromagnetic radiation can travel through a vacuum.
5)All kinds of electromagnetic radiation are invisible.
Answers
1)Light is a kind of electromagnetic radiation.
3)Electromagnetic radiation has no mass.
4)Electromagnetic radiation can travel through a vacuum.
Explanations
Electromagnetic waves are waves that can travel through vacuum. that is they do not require material medium for propagation.
Light is in the electromagnetic spectrum.
Electromagnetic waves can travel through a long distance. For instance, radio waves are electromagnetic radiations that travel long distances.
Electromagnetic radiations carry energy with it but no mass.
Some of the electromagnetic radiations are visible such as visible light.
Which heavenly bodies are involved in causing the earths tides?
only the moon and earth.
only the earth.
the earth, moon, and sun.
all the planets plus the moon.
During an investigation, a student determines that a copper sample has a density of 8.10 g/ml. What is the students percent error of the accepted density for copper is 8.96 g/ml
Please help!
Find the tension in each cord in the figure if the weight of the suspended object is w = 210N
A) Find the tension in the cord A for system (b).
B) Find the tension in the cord B for system (b).
A) Tension in the cord A ≈ 570 Newton
B) Tension in the cord B ≈ 700 Newton
[tex]\texttt{ }[/tex]
Further explanationNewton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
[tex]\large {\boxed {F = ma }[/tex]
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
weight of the suspended object = w = 210 N
Asked:
tension in the cord A = T_A = ?
tension in the cord B = T_B = ?
Solution:
Let:
γ = 360° - 60° - 45° - 90° = 165°
α = 90° + 45° = 135°
β = 60°
[tex]\texttt{ }[/tex]
We will use Lami's Theorem in this question.
If the system is in equilibrium , then:
[tex]\large {\boxed{\frac{T_A}{\sin \alpha} = \frac{w}{\sin \gamma}}}[/tex]
[tex]T_A = w \times \frac{\sin \alpha}{sin \gamma}[/tex]
[tex]T_A = 210 \times \frac{\sin 135^o}{sin 165^o}[/tex]
[tex]T_A = 210 \times ( 1 + \sqrt{3} )[/tex]
[tex]T_A \approx 570 \texttt{ Newton}[/tex]
[tex]\texttt{ }[/tex]
[tex]\large {\boxed {\frac{T_B}{\sin \beta} = \frac{w}{\sin \gamma}}}[/tex]
[tex]T_B = w \times \frac{\sin \beta}{sin \gamma}[/tex]
[tex]T_B = 210 \times \frac{\sin 60^o}{sin 165^o}[/tex]
[tex]T_B = 210 \times \frac{1}{2}( 6 + 3\sqrt{2} )[/tex]
[tex]T_B \approx 700 \texttt{ Newton}[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441Newton's Law of Motion: https://brainly.com/question/10431582Example of Newton's Law: https://brainly.com/question/498822[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Dynamics
[tex]\texttt{ }[/tex]
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
What is the direction of the force that acts on clothes in the spin cycle of a washing machine?
a. outward
b. inward
c. up
d. down
The answer is option a.
During a washing machine's spin cycle, the force that acts on the clothes is directed outward, which is a result of the centrifugal force.
Explanation:In the context of a washing machine's spin cycle, the force that acts on the clothes is directed outward. This is due to the principle of centrifugal force, a type of inertial force that acts on an object moving in a circular path. The centrifugal force pushes the clothes against the wall of the washing machine drum when it rotates, effectively helping to draw water out of the clothes.
This centrifugal force pushes the clothes away from the center of rotation, causing them to stick to the drum's inner surface during the spin cycle.
Therefore, the answer is option a.
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Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations.
x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π
A. x^2 - y^2 = 6; -6 ≤ x ≤ 6
B. x^2 - y^2 = 36; -6 ≤ x ≤ 6
C. x^2 + y^2 = 36; -6 ≤ x ≤ 6
Final answer:
To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. The rectangular equation for the plane curve is x^2 + y^2 = 36.
Explanation:
To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. This will eliminate the parameter t and give us a rectangular equation. Let's do the calculations:
x^2 = (6 cos t)^2 = 36 cos^2 t
y^2 = (6 sin t)^2 = 36 sin^2 t
Adding the two equations together: x^2 + y^2 = 36 (cos^2 t + sin^2 t) = 36
So, the rectangular equation for the plane curve is x^2 + y^2 = 36. This means that option C is the correct answer.
10 kg cart and a 5 kg cart are placed on identical surfaces. The 10 kg cart experiences a net force of 12 N to the left, while the 5 kg cart experiences a net force of 8 N to the left. Compare and contrast the motion of the two carts.
The 10 kg cart and 5 kg cart under different net forces will move to the left but with different accelerations. Despite the larger force acting on the 10 kg cart, the lighter 5 kg cart will actually accelerate at a greater rate.
Explanation:Comparing the motion of a 10 kg cart experiencing a net force of 12 N to the left and a 5 kg cart experiencing a net force of 8 N to the left involves the principles of Newton's second law of motion, F=ma. For the 10 kg cart, the acceleration is found by dividing the force by mass(12 N / 10 kg), which equals 1.2 m/s² to the left. For the 5 kg cart, the acceleration is (8 N / 5 kg), which equals 1.6 m/s² to the left.
Therefore, despite the 10 kg cart experiencing a larger force, the 5 kg cart actually accelerates at a greater rate due to its lighter mass. This illustrates the principle that net force not only depends on the magnitude of the force but also on the mass of the object it is acting on.
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A 50.0-kg wolf is running at 10.0 m/sec. What is the wolfs kinetic energy
The kinetic energy of the wolf is 2500J.
Explanation:The kinetic energy of the wolf can be calculated using the formula: Kinetic Energy = 0.5 x mass x velocity^2. Plugging in the given values, we have: Kinetic Energy = 0.5 x 50.0 kg x (10.0 m/sec)^2. Solving this equation will give us the wolf's kinetic energy.
Given values:
- Mass (m) = 50.0 kg
- Velocity (v) = 10.0 m/s
Using the formula for kinetic energy:
Kinetic Energy (KE) = 0.5 x mass x velocity^2
Plugging in the values:
KE = 0.5 x 50.0 kg x (10.0 m/s)^2
Calculating the square of the velocity:
KE = 0.5 x 50.0 kg x 100.0 m^2/s^2
Now, calculate the product:
KE = 2500.0 kg m^2/s^2
The unit of kinetic energy is joules (J), so we can rewrite it as:
KE = 2500.0 J
Therefore, the wolf's kinetic energy is 2500.0 joules (J).
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