Answer:
Cubic meters is the unit of volume.
Explanation:
Volume :
Volume is the multiplication of height, width and length of the solids.
In mathematically term,
[tex]V = w\times l\times d[/tex]
Where, w = width
h = height
l = length
Put the unit into the formula
[tex]V = m\times m\times m[/tex]
[tex]V =m^3[/tex]
This is the unit of volume.
We know that,
Square meters is the unit of area.
Liters per cubic gram is the unit of density.
Gram per cubic centimeter is the unit of density in CGS.
Hence, Cubic meters is the unit of volume.
The force of gravity on a 2-kg rock is twice as great as that on a 1-kg rock. why then doesn't the heavier rock fall faster?
What happens to static and kinetic friction as mass increases?
How are the frequency and wavelength of light related?
The relationship between frequency and wavelength of light is given by:
[tex]f=\frac{c}{\lambda}[/tex]
where
f is the frequency
c is the speed of the light
[tex]\lambda[/tex] is the wavelength
Therefore, from this equation we see that frequency is inversely proportional to wavelength: the longer the wavelength, the smaller the frequency, and the shorter the wavelength, the higher the frequency.
The wavelength and frequency of light are inversely proportional to each other. The higher the frequency of light, the shorter its wavelength. Also, high-frequency waves carry more energy than lower-frequency waves.
Explanation:The wavelength and frequency of light are inversely proportional to each other. This means if the wavelength of light increases, its frequency decreases, and vice versa. This relationship can be expressed as λf = c, where λ represents wavelength, f represents frequency, and c is the speed of light. For instance, the different colors of visible light have specific frequencies and wavelengths associated with them. Radio waves, which have longer wavelengths, have lower frequencies, while visible light with shorter wavelengths have higher frequencies. This relationship remains constant irrespective of the moving source or observer.
In a given medium under fixed conditions, the higher the frequency, the smaller the wavelength. Also, waves with higher frequencies carry more energy than lower-frequency waves. This energy is delivered as elementary particles called photons. Therefore, higher-frequency waves deliver more energetic photons compared to lower-frequency waves.
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A satellite makes 16 orbits around the earth in one day. What is the period of it orbit?
if a car decelerates at a rate of 5.1 m/s, and its initial speed was 24 m/s. how long will it take the car to stop?
Final answer:
The car will take approximately 4.71 seconds to stop.
Explanation:
To find out how long it will take for the car to stop, we can use the equation:
Final velocity = initial velocity + (acceleration × time)
In this case, the final velocity is 0 m/s (since the car stops), the initial velocity is 24 m/s, and the acceleration is -5.1 m/s² (since the car is decelerating).
Plugging in these values, we have:
0 m/s = 24 m/s + (-5.1 m/s² × time)
Simplifying this equation, we get:
-5.1 m/s² × time = -24 m/s
Dividing both sides by -5.1 m/s², we find that:
time = 4.71 seconds
So, it will take approximately 4.71 seconds for the car to stop.
Does the coefficient of kinetic friction depend on the weight of the block
The coefficient of kinetic friction is independent of an object's weight and depends on the two contact surfaces. Actual frictional force increases with weight due to its dependence on the normal force. Weight influences the tension in a string due to the effect of friction on net force.
Explanation:The coefficient of kinetic friction (μk) is a value that describes how much frictional resistance is encountered by two surfaces sliding past one another. It is independent of the weight of the block and solely depends on the properties of the two contact surfaces. However, the actual frictional force, which is the product of the coefficient of kinetic friction and the normal force, does depend on the weight of the block because the normal force is equal to the weight of the block when the block is on a horizontal surface.
Given the mass (M) of the larger block and the force (F), you are looking to find the tension in the string that connects it to another block. The kinetic friction value affects the calculation of the net force and therefore influences the tension in the string.
As you move from left to right on the periodic table, what generally happens to the electronegativity? *
If you have an effusive personality, then it __________ of you. motor oil will __________ across the gravel if it spills out of the can.
Two carts, a and b, are connected by a rope 39 ft long that passes over a pulley p. the point q is on the floor h = 12 ft directly beneath p and between the carts. cart a is being pulled away from q at a speed of 3 ft/s. how fast is cart b moving toward q at the instant when cart a is 5 ft from q? (round your answer to two decimal places.)
To find the speed at which cart B is moving toward point q, we can set up a proportion using the distances and speeds of the two carts connected by a rope. By substituting the known values into the equation, we can solve for the speed of cart B.
Explanation:To find the speed at which cart B is moving toward point q, we can use the concept of relative motion. Since there is a rope connecting the carts, their speeds are related. We can set up a proportion using the distances and speeds:
(Distance traveled by cart A) / (Speed of cart A) = (Distance traveled by cart B) / (Speed of cart B)
Since we know that cart A is being pulled away from q at a speed of 3 ft/s and is 5 ft from q, we can substitute these values into the equation and solve for the speed of cart B:
(5 ft) / (3 ft/s) = (Distance traveled by cart B) / (Speed of cart B)
From here, we can solve for the speed of cart B.
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An 18.0 kg box is released on a 34.0° incline and accelerates down the incline at 0.270 m/s2. find the friction force impeding its motion. how large is the coefficient of friction?
Final answer:
The friction force impeding the box's motion is 4.24 N. The coefficient of friction is 0.106.
Explanation:
To find the friction force impeding the motion of the box, we need to use the equation:
Ffriction = μmgcosθ
Where Ffriction is the friction force, μ is the coefficient of friction, m is the mass of the box, g is the acceleration due to gravity, and θ is the angle of the incline.
Using the given values, we can substitute them into the equation:
Ffriction = (0.0300)(18.0 kg)(9.8 m/s²)cos(34.0°) = 4.24 N
So, the friction force impeding the motion of the box is 4.24 N. To find the coefficient of friction, we need to rearrange the equation:
μ = Ffriction / (mgcosθ)
Substituting the known values:
μ = 4.24 N / (18.0 kg)(9.8 m/s²)cos(34.0°) = 0.106
Therefore, the coefficient of friction is 0.106.
A car in a movie moving at 20 m/s flies off a cliff that is 74.3m tall. How long is the car in the air for and how far does the car travel before it hits the ground below?
The time the car, moving at 20 m/s, is in the air after flying off a 74.3m cliff is approximately 3.88 seconds. Within that time, it travels about 77.6 meters horizontally before hitting the ground.
Explanation:Using the concepts of gravity and projectile motion, the time the car, moving at 20 m/s, is in the air after flying off a 74.3m cliff is approximately 3.88 seconds.
To find the time the car is in the air, we use the formula for time in free fall, t = sqrt(2h/g), where h is the height the car falls, and g is the acceleration due to gravity. So, t = sqrt((2 * 74.3m) / 9.8m/s²), roughly giving t = 3.88 seconds.
To find the horizontal distance the car travels before hitting the ground, we use the formula x = vt, where v is the initial horizontal velocity and t is the time of flight. So, x = 20 m/s * 3.88 s, roughly equals 77.6 meters.
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You have landed on an unknown planet, newtonia, and want to know what objects will weigh there. you find that when a certain tool is pushed on a frictionless horizontal surface by a 12.7 n force, it moves 16.1 m in the first 2.50 s , starting from rest. you next observe that if you release this tool from rest at 10.3 m above the ground, it takes 2.88 s to reach the ground.
Final answer:
The question involves applying Newton's laws of motion and universal gravitation in a physics context to determine the gravitational acceleration and accordingly the weight of objects on an unknown planet.
Explanation:
The situation described involves calculating forces and understanding the principles of motion and gravity on an unknown planet, which falls under the subject of physics. Specifically, it looks at the application of Newton's laws of motion and universal gravitation.
Using the given information from the question, we can deduce certain characteristics of the planet's gravitational field. The force exerted, in combination with the mass of the tool and distance traveled, allows us to calculate acceleration using Newton's second law of motion, F = ma. Additionally, the time taken for the object to fall a certain distance on this planet will enable us to determine the planet's gravitational acceleration, which can be compared to Earth's acceleration due to gravity of approximately 9.80 m/s².
It is important to calculate the acceleration correctly because it impacts subsequent calculations involving force and weight. For instance, with Newton's second law, the net force on a free-falling object without air resistance is simply its weight. This relationship is crucial for determining an object's weight on the unknown planet.
To apply these principles to the scenario, it is essential to use the provided data to determine the gravitational acceleration on the unknown planet. Let's take the second part of the question, which describes an object falling from a given height in a specific amount of time. This would directly give us the gravitational acceleration of the planet, using the formula for the motion of objects under gravity: s = ut + ½at². Once we have the gravitational acceleration, we could then find the weight of objects on the planet using the formula w = mg.
(ii) a woman stands on a bathroom scale in a motionless elevator. when the elevator begins to move, the scale briefly reads only 0.75 of her regular weight. calculate the acceleration of the elevator, and find the direction of acceleration.
Final answer:
To calculate the acceleration of the elevator when a woman's weight reads 0.75 of her regular weight, we use Newton's second law, resulting in an acceleration of -2.45 m/s². This indicates that the elevator is accelerating downwards or decelerating while moving upwards.
Explanation:
If a woman standing on a bathroom scale in an elevator observes that the scale reads only 0.75 of her regular weight, it means that the net force acting on her is reduced because the elevator is accelerating.
To calculate the acceleration of the elevator, we can use Newton's second law of motion and some assumptions about gravitational acceleration (g = 9.8 m/s2).
Let's denote the woman's mass as m, her regular weight as W = mg (where g is the acceleration due to gravity), and the scale reading when the elevator accelerates as 0.75W. When the elevator is accelerating, the apparent weight (scale reading) is W' = 0.75mg.
The net force (Fnet) acting on the woman in the elevator is her apparent weight, W', minus her actual weight, W, leading to Fnet = ma. Therefore:
Fnet = W' - W
ma = 0.75mg - mg
a = 0.75g - g = -0.25g
This gives us a = -0.25(9.8 m/s2) = -2.45 m/s2. The negative sign indicates that the acceleration is directed downwards - meaning that the elevator is accelerating downward or decelerating while going up.
Randy observed that cooked onions in his food taste very differently from the raw onions that he had on his salad. He wondered why that was so. He thinks that he has an idea, but he is not sure.
What has he developed in his mind?
Answer:
Hypothesis.
Explanation:
Hypothesis is defined as the assumption or can be say that an idea that is proposed for the sake of an argument so that it can be tested or might be occur in future.
A hypothesis is basically tentative. It is usually made an assumption for the experiment to be tested.
Basically Randy made a hypothesis by which he thinks that he has an idea but he is not sure about that.
What kind of front involves three air masses of different temperatures?
An occluded front involves three air masses of different temperatures: two cold air separated by a warm air .
What is occluded front?Due to different densities, when big amounts of warm and cold air collide, they do not mix. They instead create a front that is typically hundreds of miles long. When a warm air mass is sandwiched between two cold air masses, an occluded front forms. As the cool air masses collide in the centre, the warm air mass rises. As the warm air mass is "cut off" from the earth and forced upward, the temperature decreases. Such fronts have the potential to produce violent winds and copious rain.
Typically, mature low pressure zones are where occluded fronts form.
Early occlusion of an extratropical cyclone in the Northern Hemisphere
Occlusion comes in two flavours, warm and cold:
In a cold occlusion, the cool air mass in front of the warm front is pushed aside by the cold air mass that is overtaking it because it is colder.In a warm occlusion, the warm air is lifted by the warm front's overtaking cold air mass, which is warmer than the cool air ahead of the warm front.Learn more about occluded front here:
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An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
What is the force applied to the scale by the car?
_____N
Answer:
Force, F = 9800 N
Explanation:
It is given that,
The spring constant for the industrial scale at the junkyard is, k = 39,200 N/m
The compression in the spring, x = 25 cm = 0.25 m
To find,
The force applied to the scale by the car.
Solution,
The Hooke's law gives the relation between the force and the compression in the spring. Its expression is given by :
[tex]F=-kx[/tex]
[tex]F=39200\times 0.25[/tex]
F = 9800 N
So, the force applied to the scale by the car is 9800 N.
What is the biggest source of air pollution? power plants agriculture motor vehicles industry
Answer:
Moto vehicles
Explanation:
Metamorphic rocks may generally be distinguished from igneous rocks because
An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
N=?
Answer : F = 9800 N
Explanation :
It is given that,
The spring constant for the industrial scale at the junkyard, k = 39,200 N/m
Displacement of spring, x = 25 cm = 0.25 m
According to Hooke's law, the force applied on spring is given by the following relation :
F = -k x
Negative sign shows the force is applied in opposite direction.
[tex]F = -39,200\ N/m\times 0.25\ m[/tex]
So, [tex]F=-9800\ N[/tex]
[tex]|F|=9800\ N[/tex]
Hence, this is the required solution.
Adam EvilKeynevil is a daredevil. As part of his act, Adam gets into his cannon and shoots himself at a 25.0 degrees angle at an initial velocity of 30.0 m/s. How far away from his initial position does he land?
Using the principles of projectile motion, we calculate the horizontal distance travelled by Adam using his initial velocity, launch angle, and the constant for gravitational acceleration.
Explanation:To calculate the distance Adam lands from his initial position, we need to use the principles of physics, specifically those of projectile motion. The horizontal distance (range) in a projectile motion can be calculated using the formula R = (v²sin(2θ))/g, where v is the initial velocity, θ is the launch angle, and g is the gravitational acceleration (9.8 m/s²).
Substituting the given values, we get R = ((30 m/sec)²sin(2*25))/9.8 m/s². This should give you the horizontal distance Adam travels in meters.
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Find the density of a 5 kg solid cylinder. the cylinder is 5 cm tall and has a radius of 2 cm.
When an electron falls from a higher energy level to a lower energy level how is the energy released?
Without the wheels, a bicycle frame has a mass of 8.47 kg. each of the wheels can be roughly modeled as a uniform solid disk with a mass of 0.820 kg and a radius of 0.343 m. find the kinetic energy of the whole bicycle when it is moving forward at 3.55 m/s.
To calculate the kinetic energy of the whole bicycle, use the formulas for kinetic energy of the frame and wheels. The kinetic energy of the frame is calculated using mass and velocity, while the kinetic energy of each wheel is calculated using moment of inertia and angular velocity. Sum up the kinetic energies of the frame and the wheels to get the total kinetic energy of the bicycle.
Explanation:To calculate the kinetic energy of the whole bicycle, we need to consider the kinetic energy of the frame and the kinetic energy of the wheels.
The kinetic energy of the frame can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass of the frame (8.47 kg) and v is the velocity of the bicycle (3.55 m/s).The kinetic energy of each wheel can be calculated using the formula: KE = 0.5 * I * w^2, where I is the moment of inertia of the wheel and w is the angular velocity of the wheel.The moment of inertia of a solid disk can be calculated using the formula: I = 0.5 * m * r^2, where m is the mass of the wheel (0.820 kg) and r is the radius of the wheel (0.343 m).The angular velocity of the wheel can be calculated using the formula: w = v / r, where v is the velocity of the bicycle (3.55 m/s) and r is the radius of the wheel (0.343 m).Plug in the values to calculate the kinetic energy of each wheel and sum them up with the kinetic energy of the frame to get the total kinetic energy of the bicycle.The kinetic energy of the whole bicycle when it is moving forward at 3.55 m/s is approximately 139.279 J.
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If the rock has a mass of 1 kg which is the speed of the rock after it has fallen for two seconds
If the rock has a mass of 1 kg then the speed of the rock would have been 19.6 m / s after it has fallen for two seconds.
What are the three equations of motion?There are three equations of motion given by Newton ,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem If the rock has a mass of 1 kg , we have to find out which is the speed of the rock after it has fallen for two seconds
By using the second equation of the motion for the vertical direction,
v = u + gt
v = 0 + 9.8 × 2
v = 19.6 m / s
Thus , If the rock has a mass of 1 kg then the speed of the rock would have been 19.6 m / s after it has fallen for two seconds.
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What would be a good reason to increase friction between surfaces?
Answer:
Explanation: Increasing friction between surface have so many good reasons such as - generating more heat between surfaces, avoiding slippage from smooth surfaces, reducing speed of vehicles. Friction force is the force automatically acting in opposite direction of motion. Friction can be dry friction force and fluid friction force depending upon the medium of motion of object.
A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.
Answer:
5.09 m/s
Explanation:
The velocity of the projectile the moment it was launched, rounded to the nearest hundredth, is
5.09 m/s.
Correct On EDG
What is the relationship between mass and momentum? Be specific as you describe the relationship between mass and linear momentum as well as how mass affects the moment of inertia in angular momentum.
The strength of the electric field 0.5 m from a 6 µC charge is positive N/C. (Use k = 8.99 × 109 N• and round answer to the nearest whole number.)
Answer:
[tex]2.16 \cdot 10^5 N/C[/tex]
Explanation:
The strength of the electric field produced by the single charge is given by
[tex]E=\frac{kq}{r^2}[/tex]
where
[tex]k=8.99\cdot 10^9 N m^2 C^{-2}[/tex] is the Coulomb's constant
[tex]q = 6 \mu C = 6 \cdot 10^{-6} C[/tex] is the charge
[tex]r = 0.5 m[/tex] is the distance from the charge at which we want to calculate the field strength
Substituting the numbers into the equation, we find
[tex]E=\frac{(8.99\cdot 10^9 )(6 \cdot 10^{-6} C)}{(0.5 m)^2}=2.16\cdot 10^5 N/C[/tex]
Use the equation in the sample problem on the previous page to find the area of a rectangle that is 48.5 cm long and 3.77 cm wide. Round your answer to the correct number of significant figures.
The area of a rectangle with dimensions 48.5 cm by 3.77 cm is 182.865 cm², which is rounded to 183 cm² to maintain three significant figures.
To find the area of a rectangle with the dimensions 48.5 cm in length and 3.77 cm in width, we use the formula for the area of a rectangle, which is length x width. Multiplying the length by the width, we get:
48.5 cm x 3.77 cm = 182.865 cm²
When rounding this to the correct number of significant figures, we have to consider that the length and width measurements were given to three and three significant figures, respectively. Therefore, the area should also be reported to three significant figures:
The area rounded to three significant figures is 183 cm².
Refer to Explorations in Literature for a complete version of this story. How does Lizabeth interact with Miss Lottie in "Marigolds"?
A) Lizabeth is intrigued by Miss Lottie and her marigolds, so she enjoys going by Miss Lottie's house to see her garden.
B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
C) Lizabeth knows that Miss Lottie doesn't like to be bothered, but she encourages the other children to tease the woman.
D) Lizabeth is afraid of Miss Lottie because she thinks the old woman is a witch, so she avoids her house.
The answer is: B) Lizabeth thinks Miss Lottie and her marigolds are strange, and her frustration with her own life drives Lizabeth to destroy the woman's flowers.
Lizbeth was depicted as an immature character that hates her condiiton and the place where she lived in. When she saw Miss Lottie taking care of the marigold flower, she could not understand why these poor woman had enough passion to take care of the wild flowers despite the horrid situations that she had and not miserable like her. This led her to destroy the flowers.