- They require a physical medium to propagate.
- They can be described in terms of frequency, wavelength, and amplitude.
- They can be refracted, reflected, and diffracted.
- They can transfer energy from one point to another.
which of the following objects can you use to roughly visualize a length of 1 meter? the length of an ant on a sidewalk? the length of a 2 liter bottle of soda pop? the height of a kitchen counter? the length of a football field?
The frequency of a wave is the inverse of the wave's _______?
period
velocity
amplitude
wavelength.
The frequency of a wave is the inverse of the wave's period.
(Instead of "inverse", the word "reciprocal" is more appropriate.
It means that [ frequency = 1/period ], and [ period = 1/frequency ].
The easiest way to remember both of these is to just remember that (frequency) x (period) = 1 .)
Answer:
period
Explanation:
answer to question 4
(A) is the answer for #4
A box of mass 50 kg is pushed hard enough to set it in motion across a flat surface. Then a 99-N pushing force is needed to keep the box moving at a constant velocity. What is the coefficient of kinetic friction between the box and the floor?
0.23
0.20
0.18
0.17
Answer:
0.20
Explanation:
The box is moving at constant velocity, which means that its acceleration is zero; so, the net force acting on the box is zero as well.
There are two forces acting in the horizontal direction:
- The pushing force: F = 99 N, forward
- The frictional force: [tex]F_f=\mu mg[/tex], backward, with
[tex]\mu[/tex] coefficient of kinetic friction
m = 50 kg mass of the box
g = 9.8 m/s^2 gravitational acceleration
The net force must be zero, so we have
[tex]F-F_f = 0[/tex]
which we can solve to find the coefficient of kinetic friction:
[tex]F-\mu mg=0\\\mu = \frac{F}{mg}=\frac{99 N}{(50 kg)(9.8 m/s^2)}=0.20[/tex]
If you comb your hair and the comb becomes negatively charged, your hair becomes?
A positive charge cause dosent your hair static up when that happens or no?
The negative charges transfer from your hair to the comb, this leads the comb to be negatively charged and your hair to become positively charged.
11. How many times could Haley fly between the two flowers in 1 minute (60 seconds)?
Without additional information on Haley's flying speed and the distance between flowers, we cannot calculate the number of times she could fly between the two flowers in one minute.
Explanation:To determine how many times Haley could fly between the two flowers in 1 minute, we need additional information such as the distance between the flowers and the speed at which Haley flies. Since this information is not provided, we cannot accurately calculate the number of times Haley could make the trip. We can however provide information on how to approach the problem once the relevant data is available.
If we knew the flight time for one trip between the flowers, we could divide 60 seconds by that flight time to find out how many trips could be made in a minute. For example, if it takes Haley 5 seconds to fly between two flowers, then she could make 12 trips in one minute (60 seconds divided by 5 seconds per trip).
A ball is dropped from the roof of a building. If it takes 2.6s to reach the ground how tall is the building
To find the height of the building, we use the free-fall equation s = ut + ½ at² with the time of fall (2.6s), resulting in a height of approximately 33.18 meters.
To calculate the height of the building given that a ball is dropped and takes 2.6 seconds to reach the ground, we can use the equations of motion for an object in free fall. Assuming the initial velocity (u) is 0 m/s (since the ball is dropped) and acceleration (a) is due to gravity (g = 9.81 m/s²), the equation we use is:
s = ut + ½ at²
Where:
Plugging in the values, we have:
s = 0 m/s (2.6 s) + ½ (9.81 m/s²)(2.6 s)²
s = ½ (9.81 m/s²)(6.76 s²)
s = 4.905 m/s² × 6.76 s²
s = 33.1763 m
Therefore, the height of the building is approximately 33.18 meters.
When an object is lifted 12 meters off the ground, it gains a certain amount of potential energy. If the same object is lifted 36 meters off the ground, its potential energy is
Final answer:
Lifting an object to a greater height increases its gravitational potential energy. The potential energy is calculated as the product of the object's mass, gravitational acceleration, and height. Tripling the height triples the potential energy.
Explanation:
When an object is lifted higher off the ground, it gains gravitational potential energy proportional to its height above the ground. This potential energy (PE) depends on the mass of the object (m), the acceleration due to gravity (g), and the height (h) above the ground. For the given 1360 kg automobile, the potential energy can be calculated using the equation PE = mgh. If we know the car gains a certain amount of potential energy at a height of 12 meters, lifting it to 36 meters, or three times that height, will result in three times the potential energy. To demonstrate, let's say the car is lifted to 36.6 m, the potential energy will be PE = 1360 kg × 9.81 m/s² × 36.6 m.
What is the equation for calculating the electrical force, Fe, between two charges?
When 2 electric charges are place close to each other they experience a force between them. This force may be repulsive or attractive depending on the type of charges involved.
The magnitude of this force depend on the quantity of individual charges and the distance between them.
The force is defined by the Coulomb's law states that: The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.
The formula for calculating the force between 2 electric charges is ;
F = (kq₁q₂)/d²
Where k is the proportionality constant known as Coulomb's constant,
q₁ and q₂ are the charges and
d is the distance between q₁ and q₂.
Answer:
C
Explanation:
I did the test kinda sorta and I got this.
What two element is present in biotite mica that is not present in muscovite mica?
Potassium iron magnesium aluminum silicate hydroxide and Potassium magnesium aluminum silicate hydroxide.
The two elements present in biotite mica but absent in muscovite mica are iron (Fe) and magnesium (Mg). This difference is observable in the chemical formulas of the two minerals. Both types are phyllosilicate minerals but have different chemical compositions.
Explanation:The two elements present in biotite mica that are not present in muscovite mica are iron (Fe) and magnesium (Mg). Biotite mica is a type of phyllosilicate mineral that contains these two elements. On the other hand, muscovite mica, although also a type of phyllosilicate mineral, does not contain iron and magnesium.
In chemical terms, the formulas for these minerals summarize their differences. Biotite's formula is K(Mg,Fe)3AlSi3O10(OH)2, while muscovite's formula is KAl2(AlSi3O10)(OH,-F)2. In the formulas, you can clearly see that both contain potassium (K), aluminum (Al), silicon (Si), and oxygen (O), but only biotite has iron and magnesium.
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A particle of mass 13 g and charge 45 μC is released from rest when it is 77 cm from a second particle of charge −11 μC. Determine the magnitude of the initial ac- celeration of the 13 g particle.
Answer:
[tex]577.7 m/s^2[/tex]
Explanation:
First of all, we need to calculate the electric force exerted on the particle. This is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
k is the Coulomb's constant
[tex]q_1 = 45 \mu C=45 \cdot 10^{-6}C[/tex] is the charge of the particle
[tex]q_2 = -11 \mu C = -11 \cdot 10^{-6}C[/tex] is the charge of the second particle
[tex]r=77 cm=0.77 m[/tex] is the initial separation between the particles
Substituting,
[tex]F=(9\cdot 9 Nm^2C^{-2})\frac{(45\cdot 10^{-6}C)(-11 \cdot 10^{-6}C)}{(0.77 m)^2}=-7.51 N[/tex]
where the negative sign tells us that it is an attractive force. We can ignore it since we are only interested in the magnitude of the acceleration, which is given by
[tex]a=\frac{F}{m}[/tex]
where
m = 13 g = 0.013 kg is the mass of the particle
Substituting, we find
[tex]a=\frac{7.51 N}{0.013 kg}=577.7 m/s^2[/tex]
During a skydiving landing, a parachute deploys from the back of the diver as it taxis back down to the Earth. The parachute helps the diver slow down before landing. How does the parachute help during this process? * 1 point It increases the weight of the shuttle. It increases the potential energy of the shuttle. It increases heat transfer by radiation. It increases friction by air resistance.
Your answer would be - It increases friction by air resistance.
Hope this helps you:)
Feel free if you want me to clarify something!
A parachute slows a skydiver's descent by increasing air resistance, acting against the skydiver's downward momentum. The parachute's increased surface area amplifies this resistance, significantly reducing speed for a safer landing.
Explanation:A parachute assists a skydiver during landing by increasing air resistance, which slows the skydiver's descent by increasing the upwards force of air pushing against the diver. The open canopy of the parachute expands the surface area against which the air pushes, thereby increasing the air resistance. Initially, the skydiver is in free fall, attaining a maximum or 'terminal' velocity depending on body position. For instance, terminal velocity can be as high as 350 km/h in a headfirst position. The deployment of the parachute dramatically reduces this speed due to the increased air resistance.
It's like dropping a baseball and a tennis ball from the same height at the same time; the baseball will hit the ground first due to less air resistance compared to the lighter tennis ball.
The parachute's role is essential to slow a skydiver's fall, reducing the risk of injury upon landing by decreasing the skydiver's change in momentum on impact.
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The graph above represents an object moving with a __________________. A) constant velocity Eliminate B) constant acceleration C) constant positive acceleration D) constant negative acceleration
The answer is D
Answer:
D) constant negative acceleration
Explanation:
Acceleration is defined as the ratio of changing of the velocity per unit time:
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where v is the velocity and t the time.
In a velocity-time graph, as the one above, the ratio between change in velocity and change in time corresponds to the slope of the curve. In fact, the slope of the curve is defined as
[tex]m=\frac{\Delta y}{\Delta x}[/tex]
where
[tex]\Delta y[/tex] is the increment in the y-variable, which corresponds to the change in the velocity, [tex]\Delta v[/tex]
[tex]\Delta x[/tex] is the increment in the x-variable, which corresponds to the change in the time, [tex]\Delta x[/tex]
So, since the slope in this case is 1) constant and 2) negative, this means that the acceleration is also constant and negative.
Answer:
It’s c. Constant positive acceleration
Explanation:
what will not affect strength of a electromagnet?
Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
What is electromagnet?Electromagnet is a form of magnet which has a magnetic field that is produced by an electric current. Electromagnets usually consist of wire wound into a coil.
Therefore, Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
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Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
What is electromagnet?Electromagnet is a form of magnet which has a magnetic field that is produced by an electric current. Electromagnets usually consist of wire wound into a coil.
The wire turns are often wound around a magnetic core made from a ferromagnetic or ferrimagnetic material such as iron; the magnetic core concentrates the magnetic flux and makes a more powerful magnet.
Electromagnets are widely used as components of other electrical devices, such as motors, generators, electromechanical solenoids, relays, loudspeakers, hard disks, MRI machines, scientific instruments
Therefore, Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
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A substance has a half-life of 10,000 years and an initial mass of 1,000 grams. How many years will pass before only 250 grams of the substance's parent material is left?
A. 20,000
B.25,000
C. 30,000
D.40,000
➷ After 10,000 years the mass will be:
1,000 / 2 = 500
After 20,000 years the mass will be:
500/2 = 250
As you can see, the correct answer would be A. 20,000 years
✽➶ Hope This Helps You!
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Answer:
A). [tex]t = 20,000 years[/tex]
Explanation:
Half life is the total time after which the substance will decay and remains only half of the initial amount
So here we will say that
initial amount is 1000 gram
Now after one half life only half of the amount will remain
so it is
[tex]m_1 = 1000/2 = 500 gram[/tex]
now again after another half life it will remain half of the initial amount
so it is
[tex]m_2 = 500/2 = 250 gram[/tex]
so it took two half lives
[tex]t = 10,000 + 10,000[/tex]
[tex]t = 20,000 years[/tex]
In which order would the the rocket pass through the layers of the atmosphere
A rocket ascending from Earth passes through the atmosphere in the following order: troposphere, stratosphere, mesosphere, thermosphere, and then the exosphere.
Explanation:The question pertains to the order in which a rocket would pass through the layers of Earth's atmosphere. The layers of the atmosphere, starting from the surface of Earth moving outward into space, are the troposphere, stratosphere, mesosphere, thermosphere, and finally the exosphere. As a rocket ascends from Earth's surface on its journey into space, it first moves through the troposphere, where weather phenomena occur, then into the stratosphere, known for its ozone layer that absorbs and scatters the sun's ultraviolet radiation. Following the stratosphere, the rocket enters the mesosphere, where meteors burn up upon entry. The journey continues through the thermosphere, the largest layer, where auroras occur and temperatures increase significantly with altitude due to solar radiation absorption. Finally, the rocket reaches the exosphere, the outermost layer where Earth's atmosphere merges into the vacuum of space.
the mass of the sled 329 kg, V=34m/s. What is the magnitude of the centripetal force that acts on the sled during the turn with radius of 33.0m?
Hello
The formula for centripetal force is:
Fc = m*[(V^2)/r]
Where
m = 329000 g
V = 34 m/s
r = 33 m
Then
Fc = (329000)*[(34^2)/33]
Fc = 11.524.969,7
Best regards
A person weighs 650 N. What is the mass of the person?
1 KG=9.8 newtons.
Thus ,
[tex]650N*\frac{1 KG}{9.8N}=around 66.3[/tex]
A person weighs 650 N and weight is the product of mass and acceleration due to gravity, so the mass of the person will be 66.32 kg.
What is the acceleration due to gravity?Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational force. It has the SI unit meter per second square. Indeed a direction and a magnitude are present. It is therefore a vector field.
We use the letter G to denote gravitational acceleration. Its normal value for the earth's surface at sea level is 9.8 m/s². Based on Newton's Second Law of Motion and Law of Universal Gravitation, its calculation.
Given information according to the question is,
Weight, w = 650 N
[tex]Weight(w) = Mass(m)*Acceleration\ due\ to\ gravity(g)[/tex]
650 N = m × 9.8 m/s²
m = 650 / 9.8
m = 66.32 kg.
Therefore, the mass of the person is 66.32 kg.
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The molar mass of a gas
Answer:
dependent on the type of gas and the mass of a mole of the gas
Explanation:
You add 500ml of water at 10celsius to a 100ml of water at 70 Celsius. What is the most likely final temperature of the mixture?
A.10c
B.20c
C.80c
D.60c
I wanna say it’s C.
Answer:
C. 20c
Explanation:
Please need help on this
C would be the answer
the process of restoring land that has been mined so I guess the answer would be C.
A skier (68kg) starts from rest but then begins to move downhill with a net force of 92 N for 8.2 s. The hell levels out for 3.5 seconds. On this part of the hill, the net force on the skier is 22 N backwards.
(a) calculate the speed of the skier after 8.2 s
(b) Calculate the speed of the skier at the end of the section where the hill levels out
(c) Calculate the total distance travelled by the skier before coming to rest
(a) 11.1 m/s
The acceleration of the skier is given by:
[tex]a=\frac{F}{m}[/tex]
where F = 92 N is the net force and m = 68 kg. Substituting,
[tex]a=\frac{92 N}{68 kg}=1.35 m/s^2[/tex]
After 8.2 s, the speed of the skier is
[tex]v=at[/tex]
where
a = 1.35 m/s^2 is the acceleration
t = 8.2 s is the time
Substituting,
[tex]v=(1.35 m/s^2)(8.2 s)=11.1 m/s[/tex]
(b) 10.0 m/s
In this section of the hill, the net force is F = -22 N backwards. So, the acceleration of the skier is
[tex]a=\frac{F}{m}=\frac{-22 N}{68 kg}=-0.32 m/s^2[/tex]
When starting this section, the skier is moving at u = 11.1 m/s. So, the final speed will be:
[tex]v=u+at[/tex]
And substituting t=3.5 s, we find
[tex]v=11.1 m/s+(-0.32 m/s^2)(3.5 s)=10.0 m/s[/tex]
(c) 237.9 m
The distance travelled by the skier in the downhill section is
[tex]d=\frac{1}{2}at^2[/tex]
where a = 1.35 m/s^2 and t = 8.2 s. Substituting,
[tex]d=\frac{1}{2}(1.35 m/s^2)(8.2 s)^2=45.4 m[/tex]
The distance travelled by the skier in the levelled out section is given by
[tex]v^2 - u^2 = 2ad[/tex]
where
v = 0 is the final speed
u = 11.1 m/s is the initial speed
a = -0.32 m/s^2 is the acceleration
d is the distance
Solving for d,
[tex]d=\frac{v^2-u^2}{2a}=\frac{0-(11.1 m/s)^2}{2(-0.32 m/s^2)}=192.5 m[/tex]
So, the total distance is
d = 45.4 m + 192.5 m = 237.9 m
A coin placed at a focal point of a converging lens. is an image is formed? what is its nature?
A converging lens is a type of optical lens that is thicker at the center than at its edges; this type of lens concentrate or converge (that is why its name) at a point the rays of light that pass through it.
If we talk about the formation of the image, its location and nature will depend on where the object is located with respect to the focal length of the lens. So, in general:
- If the object is considerable away from the focal point, a real image (which can be projected on a screen) will be formed, inverted and smaller than the object.
-If the object is very close to the focal point, a virtual image will be observed (it is given this name because the image can not be projected on a screen) upright and bigger than the object.
Now, if the object is placed right at the focal point, the image would be formed at infinity (therefore, we would not see it) and its nature would be virtual.
According to this, the image of the coin will not be seen.
If the object is positioned at the focal point, the image is formed at infinity and its nature is virtual.
What is a lens?The term lens refers to any refracting surface. Recall that refraction is the bending of the light ray at the interval between two media.
The nature of the image formed by a lens depends on the position of the object. If the object is positioned at the focal point, the image is formed at infinity and its nature is virtual.
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What causes the phases of our moon
sunlight, and the position of the earth
How do you answer this. Need help ASAP. Offering 20 points !!!
in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.
your temp should be converted in kelvin
variables:
p1=3.0×10^6 n/m^2
t1= 270k
just add 273 to your celcius
p2= ? your solving for this
t2= 315k
then you set up the equation
(3.0×10^6)/270= (x)(315)
you then cross multiply
(3.0×10^6)315=270x
distribute the 315 to the pressure.
9.45×10^8=270x then you divide 270 o both sides to get
answer
3.5×10^6 n/m^2
Lindsay has placed on object to the left of the lens, indicated by the bold line to project its image onto a screen. What actions would provide a clear image that is larger?
A)Move the object and image to the left.B)Move the object and image to the right.C)Move the object to the left and the screen to the right.D)Move the object to the right and the screen to the left.
b.Move the object and image to the right.
To obtain a clear image that is larger, Lindsay should move the object to the left and the screen to the right. Option C is correct.
What is the lens?A lens is a clear object made of glass or plastic that can bend (refract) and focus light.
When an object is placed to the left of a converging lens, a real and inverted image is produced on the other side of the lens. The size and position of the image are determined by the distance between the object and the lens, as well as the distance between the lens and the image.
To obtain a larger image, move the object closer to the lens or move the screen further away from the lens.. Moving the object and image to the right would make the image smaller, and moving the object and image to the left would not necessarily make the image larger or clearer.
Therefore, option C) Move the object to the left and the screen to the right is the correct answer to obtain a clear image that is larger.
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Which of the following will increase if the voltage in a circuit is increased? check all that apply
a.) Current
b.) Resistance
c.) Heat produced by the circuit
d.) Magnetic force
When the voltage in the circuit is increased, the following will happen: The correct choices are: a, c, and d.
Current will increase. (a)Heat produced by the circuit will increase. (c)Magnetic force will increase. (d)Current (a): According to Ohm's Law, which is given by the formula (where is voltage, is current, and is resistance), if the voltage () increases and the resistance () remains constant, the current () will increase. This happens because current is directly proportional to voltage. So, an increase in voltage leads to an increase in current.
Resistance (b): Resistance in a circuit is typically a property of the materials involved and does not change with the voltage applied. For most materials and simple circuits, the resistance remains constant regardless of changes in voltage. Therefore, increasing the voltage does not increase the resistance.
Magnetic force (d): Magnetic force generated in a circuit, particularly around conductors, depends on the current flowing through the circuit. Since increasing the voltage (with constant resistance) leads to an increase in current, the magnetic force would also increase as a result.
How is data not actually obtained from the experiment represented in a line graph?
with a double line
with only dots
with a colored line
with a broken line
20 POINTS!
With a broken line????????
Answer:
broken line
Explanation:
A 10.0g piece of copper wire, sitting in the sun reaches a temperature of 80.0 C. how many Joules are released when the copper cools to 40.0 C? The specific heat capacity of copper is 0.377 j/(g.C)
Answer:
150.8 J
Explanation:
The heat released by the copper wire is given by:
[tex]Q=mC_s \Delta T[/tex]
where:
m = 10.0 g is the mass of the wire
Cs = 0.377 j/(g.C) is the specific heat capacity of copper
[tex]\Delta T=40.0 C - 80.0 C=-40.0 C[/tex] is the change in temperature of the wire
Substituting into the equation, we find
[tex]Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J[/tex]
And the sign is negative because the heat is released by the wire.
A conductor wire with length of 0.20 m and weight of 1.47 N is oriented perpendicularly to a magnetic field. If the current of 1.75A flows to the north, the net force on the wire is measured using a balance and found to be zero. What is the magnitude and direction of the magnetic field?
1. Magnitude: 4.4 T
The net force on the wire is zero, therefore the magnetic force must be equal to the weight of the wire:
[tex]F_M = W = 1.47 N[/tex]
Where the magnetic force is
[tex]F_M = IBL sin \theta[/tex]
where
I = 1.75 A is the current
B is the magnetic field
L = 0.20 m is the length of the wire
[tex]\theta=90^{\circ}[/tex] is the angle between the direction of L and B
Solving the formula for B, we find the magnitude of the magnetic field:
[tex]B=\frac{F_M}{ILsin \theta}=\frac{1.47 N}{(1.75 A)(0.20 m)(sin 90^{\circ})}=4.2 T[/tex]
2. Direction: westward
The direction is given by the right's hand rule. We know that:
- thumb --> magnetic force (upward)
- index finger --> current (north)
- middle finger --> direction of magnetic field: so, it must be westward.
- middle