Which of the following selections completes the following nuclear reaction?

Try B-momentum that is what I think that it is

Answer: 1. high-energy

2. deposition

3. Silt

4. limestone

5. soluble

6. tectonic forces

7. before

8. faunal succession

9. nondeposition

10. coarser

Explanation:

Answer: (1) Fluvial environment

(2) Deposition

(3) Limestone

(4) Sandstone

Explanation:

Gravity force causes the clouds of dust and gas to form a protostar. As this attraction force is responsible for gathering and compressing the existing elements in the cloud of gas and dust, heating them during this process.

Then, when the amount of material accumulated by gravitational contraction is large enough, and the temperature and pressure reached high enough, the nuclear fusion process will begin.

To understand it better: The hydrogen nuclei will begin to fuse, generating helium nuclei in the process and releasing huge amounts of energy.

It should be noted that the protostars radiate half of the energy contributed by the gravitational collapse and the other half is invested in heating its core.

Answer:

Transformers are used to increase or decrease the voltage of AC currents

Explanation:

A transformer is a device consisting of two coils (called primary and secondary coil) wrapped at the two sides of a soft iron core. When an AC current is present in the primary coil, it induces a magnetic field inside the core, and the presence of this changing magnetic field induces a voltage (and a current) into the secondary coil.

The voltages in the primary and the secondary coil are related by the transformer equation:

[tex]\frac{V_p}{V_s}=\frac{N_p}{N_s}[/tex]

where

Vp, Vs are the voltages in the primary and secondary coil

Np, Ns are the number of turns in the primary and secondary coil

There are two types of transformers:

- Step-up transformers: these have [tex]N_s > N_p[/tex], so that [tex]V_s > V_p[/tex], which means that they increase the voltage. They are used to increase the voltage of the AC current produced by the power plants, before being sent into the transmission lines.

- Step-down transformers: these have [tex]N_s < N_p[/tex], so that [tex]V_s < V_p[/tex], which means that they decrease the voltage. They are used at the end of the transmission lines, before the houses, in order to decrease the voltage and allow the household appliances to work properly (in fact, household appliances need lower voltages to work)

Answer:BRAIN

Explanation:

Answer:

75 m

Explanation:

The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.

The horizontal component of the velocity of the projectile is

[tex]v_x = 15 m/s[/tex]

and it is constant during the motion;

the total time of flight is

t = 5 s

Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:

[tex]d= v_x t =(15 m/s)(5 s)=75 m[/tex]

The horizontal displacement of a projectile can be calculated using the formula x = Vx*t. Given an initial horizontal velocity of 15 m/s and a flight time of 5 seconds, the horizontal displacement is 75 meters.

In physics, the path a projectile takes is composed of both horizontal and vertical components. Both these are independent of one another and have their own distinct characteristics. For the given scenario, the horizontal displacement, which tells us how far the projectile travels horizontally, can be found using the formula x = Vx*t, where Vx represents the initial horizontal velocity and t is the total time of flight.

In this case, Vx equals 15 meters per second and t equals 5 seconds. Substituting these values into the formula gives us x = 15 m/s * 5 s, which results in a horizontal displacement of 75 meters.

Please remember that this calculation assumes there's no air resistance and the object is launched and lands at the same height. Any alterations in these factors, like a taller launch height or the presence of air resistance, will affect the outcome.

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4.  A. Increase

The magnitude of the electric force between two charges is given by Coulomb's law:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

q_1 and q_2 are the two charges

r is the separation between the two charges

As we see from the formula, the strength of the electric force is:

- directly proportional to the two charges q1 and q2

- inversely proportional to the square of the distance r

Therefore, we can conclude that:

- if the magnitude of the charges increases, then the magnitude of the force will increases as well

- if the separation between the charges increases, then the magnitude of the force will decrease

5. A. Increase by the same factor

Again, the magnitude of the electric force between the two charges is given by Coulomb's law:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

we have said that the force F is directly proportional to the two charges q_1 and q_2.

Let's assume now that charge q_1 is increases by a certain factor A. Then the electric force will change as follows:

[tex]F'=k\frac{(A q_1) q_2}{r^2}=A(k\frac{q_1 q_2}{r^2})=A\cdot F[/tex]

so, the magnitude of the electric force has increased by the same factor.

6. A. The electric force would decrease.

This part is similar to part 5, however this time the charge q_1 is decreased.

This means that we can rewrite the new charge q1 as

[tex]q_1 ' = \frac{q_1}{A}[/tex]

where A > 1. Let's see how the electric force changes:

[tex]F'=k\frac{(\frac{q_1}{A}) q_2}{r^2}=\frac{1}{A}(k\frac{q_1 q_2}{r^2})=\frac{F}{A}[/tex]

This means that the magnitude of the electric force has decreased by the same factor.

A) Francium-223

In an alpha decay, a nucleus decay emitting an alpha particle, which corresponds to a nucleus of helium: so, it consists of 2 protons and 2 neutrons.

[tex]X \rightarrow X' + \alpha[/tex]

This means that in the decay:

- The original nucleus loses 2 protons --> so its atomic number Z decreases by 2 units

- The original nucleus loses 2 nucleons (2 protons and 2 neutrons) --> so its mass number A decreases by 4 units

In this example, the original nucleus is Ac (Actinium), with

Z = 89

A = 227

After the decay, it must be

Z - 2 = 89 - 2 = 87

A - 4 = 227 - 4 = 223

We see from the periodict table, Z=87 corresponds to Francium (Fr), so the final nucleus will be francium-223 (the isotope of francium with 223 nucleons).

B) Polonium-211

In a beta-minus decay, a neutron in the nucleus turns into a proton, emitting a fast-moving electron (the beta particle) and an anti-neutrino.

[tex]n \rightarrow p + e^- + \bar{\nu}[/tex]

Therefore, in this process:

- The original nucleus gains 1 protons, so its atomic number Z increases by 1 unit

- The original nucleus does not lose/gain nucleons, so its mass number A remains the same

In this example, the original nucleus is Bi (bismuth)-211, with

Z = 83

A = 211

So After the decay, it will be

Z + 1 = 83 + 1 = 84

A = 211

So, the nucleus will be Polonium (Z=84), isotope with 211 nucleons.

C) Neon-22

In a beta-plus decay, a proton in the nucleus turns into a neutron, emitting a fast-moving positron (the beta particle) and a neutrino.

[tex]p \rightarrow n + e^+ +\nu[/tex]

Therefore, in this process:

- The original nucleus loses 1 protons, so its atomic number Z decreases by 1 unit

- The original nucleus does not lose/gain nucleons, so its mass number A remains the same

In this example, the original nucleus is Na (sodium)-22, with

Z = 11

A = 22

So After the decay, it will be

Z - 1 = 11 - 1 = 10

A = 22

So, the nucleus will be Neon (Z=10), isotope with 22 nucleons.

D) Technetium-98

In a gamma decay, an unstable nucleus emits a gamma ray:

[tex]X' \rightarrow X + \gamma[/tex]

In this process, only energy is released (in the form of gamma ray), so there is no gain/loss of protons/neutrons in the process. This means that:

- The atomic number Z remains constant

- The mass number A remains constant

In this example, we have a nucleus of Tc (Technetium)-98, with

Z = 43

A = 98

These numbers will not change during the decay: this means that after the decay, we will still have a nucleus of Technetium-98.

Answer:

yes

Explanation:

Here, the formula for gravity is,

g=GM/R^2

so, to change gravity, either we have to change mass(M) or radius(R) of the planet.

similarly, the formula for electrical force is,

F= kq1q2 / r^2

and to change the electrical force, either we have to change the magnitude of charge(q) or the distance between the two charges(r).

Answer:

Not necessarily, if the air masses are not strong enough, a stationary front is caused

Explanation:

A front is a block of separation between two air masses at different temperatures. They can be classified as cold, warm, stationary and occluded fronts. When a front is formed, a collision occurs between the two masses, generating a very dynamic activity, with electrical storms, gusts of wind and downpours.

A stationary front is one where neither of the two air masses are strong enough to replace the other. On such a front can generate atmospheric conditions such as prolonged rainfall and high cloudiness.

After several days, the stationary fronts may dissipate or become a cold or warm front. .

1) Temperate Grasslands-Have hot summers and cold winters.

2) Chaparral-A hot coastal biome.

3) Rainforests-A lot of rain, average temperatures, nutrient-poor soil, and have many exotic animals.

4) Aquatic ecosystems-Is an ecosystem in a body of water where many communities of organisms are dependent on each other and their environment.

Answer:

They are the same

Explanation:

Electromagnetic waves consist of perpendicular oscillations of electric and magnetic field, which oscillate perpendicularly to the direction of motion of the wave (transverse wave). One property of the electromagnetic waves is that they travel in a vacuum always at the same speed, called speed of light:

[tex]c=3.0\cdot 10^8 m/s[/tex]

Electromagnetic waves are classified into 7 different types according to their frequency; from highest to lowest frequency, we have:

Gamma rays

X-rays

Ultraviolet

Visible light

Infrared

Microwaves

Radio waves

We see that both visible light and gamma rays are electromagnetic waves, so they both travel in a vacuum at the same speed, the speed of light.

The highest parts of a transverse wave are called "crests."

When a wave travels through a medium, its particles oscillate back and forth around their equilibrium positions. In a transverse wave, the motion of the particles is perpendicular to the direction of the wave propagation.

These waves have crests and troughs. The highest points, where the particles are at their maximum displacement upwards from their rest position, are known as "crests."

Conversely, the lowest points, where the particles are at their maximum displacement downwards from their rest position, are known as "troughs."

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Answer:

After the colision, the stationary electron's momentum is given as:

P = 2.7328 x 10^(-25) kg m/s

The direction of momentum is the same as the direction of velocity of the electron.

Explanation:

In an Isolated system, when an object moving at some velocity v collides head on with a stationary object of equal mass. There velocities are exchanged.

This means that the first electron will become stationary and the electron which was stationary initially will start moving at a velocity of 3*10^(5)m/s in the same direction as the first electron.

Post collision momentum of the stationary electron:

V = 3 x 10^5 m/s

m = 9.1093 x 10^(-31) kg

Momentum = P = mV =  9.1093 x 10^(-31) x 3 x 10^5

P = 2.7328 x 10^(-25) kg m/s

The direction of momentum is the same as the velocity of the electron.

Answer:

273.279 × 10-25 kg.m/s, in the same direction as the incident electron

Explanation:

The momentum of the stationary electron post collision will be 273.279 × 10-25 kg.m/s, in the same direction as the incident electron.

Momentum of the incident electron = mv

= 9.1093 × 10-31 × 3 × 105

= 273.279 × 10-25 kg.m/s

In the collision of the electrons, the total momentum is conserved. Since it is an elastic collision, the momentum of the incident electron is completely transferred to the stationary electron. So it will have the same momentum as the incident electron. It will also move in the direction of the incident electron.

The Lituya Bay tsunami occurred on July 9th, 1958, northeast of the Gulf of Alaska. It was as a consequence of a strong earthquake of magnitude 8.3 on the Ritchter scale along the Fairweather Fault in the Alaskan Panhandle, which caused a landslide in a fjord in Lituya Bay, collapsing an entire mountain and generating a gigantic wave that rose to 524 meters, the highest recorded so far.

It should be noted that despite its great magnitude and having uprooted all the trees and vegetation of the place, this mega-tsunami claimed only five lives because the area was not as inhabited as the large cities are.

The largest tsunami recorded was the result of the magnitude 9.0 earthquake off Japan's coast in 2011, producing waves over 130 feet high, while the 2004 Indian Ocean earthquake generated a tsunami causing approximately 283,000 fatalities.

The largest tsunami ever recorded occurred on March 11, 2011, following a magnitude 9.0 earthquake off the eastern coast of northern Japan. This earthquake, which is the strongest to ever hit Japan, caused a tsunami with waves that reached heights of more than 130 feet. The massive waves resulted in extensive damage and the loss of life, with over 15,500 fatalities. Another catastrophic event was the Indian Ocean tsunami in 2004, caused by a 9.0 magnitude earthquake that generated waves killing around 283,000 people across 11 countries.

These events illustrate the devastating impact of tsunamis, which are large ocean waves typically triggered by underwater earthquakes or volcanic eruptions. The severity of the damage can be exacerbated in areas with nuclear power plants, as seen in the 2011 Japan tsunami, which knocked out cooling systems and resulted in nuclear meltdowns and radiation exposure.

Answer:

44.7 N

Explanation:

The gravitational force between the objects is given by:

[tex]F=G\frac{mM}{r^2}[/tex]

where

G is the gravitational constant

m and M are the masses of the two objects

r is the distance between the centres of the two objects

In this problem, we have:

[tex]m=5.0 kg[/tex] is the mass of the sphere

[tex]M=5.98\cdot 10^{24} kg[/tex] is the Earth's mass

[tex]R=6370 km[/tex] is the Earth's radius, while h=310 km is the altitude of the sphere, so the distance of the sphere from Earth's centre is

[tex]r=6370 km+310 km=6680 km=6.68\cdot 10^6 m[/tex]

Substituting into the equation, we find

[tex]F=(6.67\cdot 10^{-11})\frac{(5.0 kg)(5.98\cdot 10^{24} kg)}{(6.68\cdot 10^6 m)^2}=44.7 N[/tex]

To calculate the gravitational force on a 5.0 kg sphere inside the space shuttle, you can use the formula F = mg. However, since the sphere is inside the space shuttle and not on the surface of the Earth, you need to calculate the acceleration due to gravity using the formula g = G(M/R^2). Plugging in the values, you can find the gravitational force on the sphere.

The gravitational force on a 5.0 kg sphere inside the space shuttle can be determined using the formula F = mg, where F is the gravitational force, m is the mass of the object, and g is the acceleration due to gravity. In this case, since the sphere is inside the space shuttle and not on the surface of the Earth, the acceleration due to gravity will be different. The acceleration due to gravity is given by g = G(M/R^2), where G is the gravitational constant, M is the mass of the Earth, and R is the distance between the object and the center of the Earth.

Given that the space shuttle orbits 310 km above the surface of the Earth, we need to convert this distance into meters (1 km = 1000 m). So the distance R becomes 310,000 m.

Plugging in the values into the formula, the gravitational force on the sphere inside the space shuttle is:

Using these calculations, you can find the gravitational force on the 5.0 kg sphere inside the space shuttle. Don't forget to include the appropriate units in your answer!

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Answer: it increases

Explanation: .

Beta rays . . . No.  These are streams of negatively charged electrons.

Alpha rays . . . No.  These are streams of pairs of positively charged protons, identical to nucleii of Helium atoms.

Gamma rays (A) . . . Yes.  These are electromagnetic waves, not composed of charged particles.

Gamma rays are radiation that has no electric charge associated with it, as they are electromagnetic waves created from energy transitions in atomic nuclei.

Among the options given, gamma rays have no electric charge associated with them. Alpha rays are helium nuclei consisting of 2 protons and 2 neutrons and carry a positive charge. Beta rays are high-energy electrons or positrons and carry a negative or positive charge respectively. However, gamma rays are electromagnetic waves, similar to light or X-rays, and do not carry a charge because they are created from energy transitions in the atomic nucleus.

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Answer: SBb

On 1930 the astronomer Edwin Hubble classified the galaxies based on their visual appearance into elliptical, spiral and irregular, being the first two classes the most frequent.  

So, according to this classification, the Milky Way is a barred spiral galaxy (SBb in Hubble's notation system) because it has a central bar-shaped structure of bright stars that spans from one side of the galaxy to the other. In addition, its spiral arms seem to emerge from the end of this "bar".

Scientifics considered this, after measuring the the disk and central bulge region of the galaxy, and the conclusion is the Milky Way fulfills these conditions, because is a galaxy that orbits on its same axis and with this rotation its arms are twisted in opposite directions around the mentioned axis.

Answer:

A gas expands spontaneously to fill its container.

Explanation:

A gas would always expand spontaneously in any container to fill it up. Gas moves unaided to assume the volume of the space they are put into. Gas molecules are more random and posses more kinetic energy to drive their movements from one place to another. Gases would not require any energy input to make them move.

The volume of a container would then be the same as the volume of the gas that occupies it. Also, when pressure is applied to a gas, the volume reduces considerably according to "Boyle's law".

A homogeneous mixture would have their constituents existing in just one phase. Regardless of any chemical properties of gases, they form homogeneous mixtures.

Answer:

As the can heats, the compressed gases will expand, causing the can to explode

Explanation:

We know that the gases in the aerosol can would assume the shape and volume of the can. The volume of the can would be the volume of the compressed gas.

As heat is added to the can, the aerosol gases would gain kinetic energy and their speed would increase. The gases would begin to expand and would require more space in order to move. This would indirectly increase the pressures between gas molecules and the walls of the can as collisions soars.  

A point would eventually be reached where the gas agitation would lead to an explosion.

Overheated aerosol cans would explode.

Answer:

protons and neutrons

Explanation:

Answer:

A.25.096m

B.10m/s

V=22.189m/s

Explanation:

Part A The ball's maximum height above the ground. Part B The ball's speed as it passes the window on its way down. Part C The speed of impact on the ground.

newton's equation of motion

V^2= u^2+2as

a=-g since it is going against gravity

S=h s= distance travelled

h=height

V=final velocity

U=initial velocity

V=o

u=10m/s

0=100+2(-9.81)h

h=100/19.62

h=5.096m

The maximum height above ground level=

Height from thr window to the maximum the ball reached before coming downward+ height from the window to the ground level

H=h+h1

H=5.096+20

25.096m

2.part b

The final velocity as it reach its maximum height upward becomes zero and then the final velocity upward= the initial velocity when coming down

V=U =0

v^2=u^2+2ah

V^2=0+2(9.81)(5.096)

V=9.99917596605

V=10m/s

3. Speed of its impact on the ground

v^2=u^2+2ah

V^2=0+2(9.81)(25.096)

V^2=492.38352

V=22.189m/s

Using the conversion of energy to resolve the questions

Given data :

initial speed of ball = 10 m/s

Distance of ball from ground ( h ) = 20 m

A) Determine the ball's maximum height above ground

we will apply the Newton's motion equation

V² = u² + 2as ------ ( 1 )

where ; u = 0 m/s, v = 0 m/s ,  a = -9.81 m/s² ,   s = ?

Insert values into equation ( 1 )

0 = 100 + 2(-9.81 ) * s

s = 5.1 m

∴ Ball's maximum height ( H ) = s + h = 5.1 + 20 =  25.1 m

B) Determine the Ball's speed as it passes the window on its way down

V² = u² + 2as

where ; V = ? , u = 0 , a = 9.81 m/s² , s = 5.1 m

Hence ; V² = 0 + 2 ( 9.81 ) * 5.1 m

∴ V = 10 m/s

C) Determine the speed of impact on the ground

V² = u² + 2aH

where ; V = ? , u = 0,  a = 9.81 m/s²,   H = 25.1 m

insert values into equation above

V² = 0 + 2( 9.81 ) * 25.1

V = √(0 + 2( 9.81 ) * 25.1 )

    = 22.19 m/s

Hence we can conclude that The ball's maximum height above ground = 25.10 m, The ball's speed on its way down = 10 m/s , The impact speed on the ground = 22.19 m/s.

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Answer:

The stratosphere

Answer:youre moms pssy is sweet is the nswer to this question

Explanation:

7. It’s just a question of keeping the ratios the same.

Adiabatic free expansion, no heat transfers and no work on the system. Adiabatic compression would increase the internal energy of the system. In an adiabatic compression, 200 J of work is done on a gas.

Final answer:

The work done by the system in an adiabatic process where the internal energy decreases by 34,000 J is also -34,000 J.

Explanation:

In an adiabatic process, where no heat is exchanged with the surroundings, the change in internal energy (ΔU) of a system is equal to the work done (W) by the system. Therefore, if the internal energy of a system decreases by 34,000 J, the work done by the system on the surroundings is also -34,000 J (the negative sign indicates that work is done by the system). This is based on the first law of thermodynamics, which in the adiabatic case simplifies to ΔU = W, since the heat transfer (Q) is zero.

The medium is the main factor that differentiates a mechanical wave from an electromagnetic wave, since the first can not propagate without its existence, while the second can propagate regardless of whether the medium exists or not.

In addition, it is the medium that will define, the propagation speed of the wave, according to its specific physical characteristics.

Therefore, the correct answer is a.

Answer:

[tex]1.6\cdot 10^{-12}N[/tex]

Explanation:

The electric force on a charged particle is given by

[tex]F=qE[/tex]

where

q is the charge of the particle

E is the strength of the electric field

In this problem, we have

[tex]E=1.0\cdot 10^7 N/C[/tex] is the electric field strength

[tex]q=+e=+1.6\cdot 10^{-19}C[/tex] is the charge of the calcium ion

Therefore, the electric force exerted on the calcium ion is

[tex]F=(1.6\cdot 10^{-19}C)(1.0\cdot 10^7 N/C)=1.6\cdot 10^{-12}N[/tex]

Answer:

6

Explanation:

The rate of change in this scenario corresponds to the number of inches that Ree grows every year. Basically, Ree's height can be written as a linear equation as follows:

[tex]y=mx+q[/tex]

where

x is the number of years after the first birthday

y is the height in inches

q = 27 is the height of Ree on her first birthday

m = 6 is the inches gained by Ree at each birthday

So the equation can also be rewritten as

y = 6x + 27

Answer:

6

Explanation: