FIGURE 1 shows part of a mass spectrometer. The whole arrangement is in a vacuum. Negative ions of mass 2.84 x 10-20 kg and charge -2.0 x 10-19 C are produced at S, which is at a potential difference of - 3000 V. The ions are accelerated in a narrow beam towards H, a hole in a hollow metal container. Inside the container, the negative ions enter a region where an electric field of strength E and a magnetic field of strength 0.83 T act.
Is it possible for the io
ns to exit slit P without being deflected in the fields?
Explain, with the aid of diagram.
Yes, the ions can exit slit P without being deflected, if the electric field strength is 170.6 N/C
Explanation:
When the ions are inside the container, they are subjected to two forces, with directions opposite to each other:
The force due to the electric field, whose magnitude is [tex]F_E=qE[/tex], where q is the charge of the ion and E is the strength of the electric fieldThe force due to the magnetic field, whose magnitude is [tex]F_B=qvB[/tex], where v is the speed of the ions and B is the strength of the magnetic fieldThe ions will move straight and undeflected if the two forces are equal and opposite. By using Fleming Left Hand rule, we notice that the magnetic force on the (negative) ions point upward: this means that the electric field must be also upward (so that the electric force on the ions is downward). Then, the two forces are balanced if
[tex]F_E = F_B[/tex]
which translates into
[tex]qE=qvB\\\rightarrow v = \frac{E}{B}[/tex]
Therefore, if the speed of the ions is equal to this ratio, the ions will go undeflected.
We can even calculate the value of E at which this occurs. In fact, we know that the ions are earlier accelerated by a potential difference [tex]V=-3000 V[/tex], so we have that their kinetic energy is given by the change in electric potential energy:
[tex]qV=\frac{1}{2}mv^2[/tex]
where
[tex]q=-2.0\cdot 10^{-19}C\\m=2.84\cdot 10^{-20}kg[/tex]
Solving for v, the speed,
[tex]v=\sqrt{\frac{2qV}{m}}=\sqrt{\frac{2(-2.0\cdot 10^{-19})(-3000)}{2.84\cdot 10^{-20}}}=205.6 m/s[/tex]
And since the magnetic field strength is
B = 0.83 T
The strength of the electric field must be
[tex]E=vB=(205.6 m/s)(0.83 T)=170.6 N/C[/tex]
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A girl pushes a 10.0kg sled at a constant speed by applying a force of 75N at an angle of 30 degrees with respect to the horizontal. The sled is pushed over a distance of 15 meters. How much work is done by the force of friction?
Answer
given,
mass of sled = 10 Kg
Force applied by girl = ?
angle of inclination = 30°
distance = 15 m
Sled is moving with constant speed hence acceleration will be equal to zero.
now,
F - mg sin θ - f = m a
F - mg sin θ - f = 0
F - mg sin θ = f
where f is the frictional force acting opposite to the applied force
mg sin θ is the component of the weight which is opposing the motion of the sled
now,
f = F - mg sin θ
f = 75 - 10 x 9.8 x sin 30°
f = 26 N
now,
Work done = f. s cos ∅
where ∅ is the angle between frictional force and displacement which is equal to 180°
W= 26 x 15 x cos 180°
W = -390 J
work done by frictional force is equal to W = -390 J
The work done by child to move the system is 974.25 Joules.
The work done is given by an expression shown below,
[tex]Workdone=Force*Distance*Cos\theta[/tex]
Where [tex]\theta[/tex] angle between force and direction of displacement.
Given that, [tex]Force=75N,Distance=15m,\theta=30[/tex]
Substitute in above expression.
[tex]Workdone=75*15*cos(30)\\ \\ Workdone=75*15*0.866\\ \\ Workdone=974.25Joule[/tex]
Hence, the work done by child to move the system is [tex]974.25[/tex] Joules.
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Rodney is trying out one of Santa's new games that consists of three pieces that blow apart if the wrong key is inserted into the door. The elf picks the wrong key and the board explodes. One piece of mass 2 kg goes off at an angle of 60° from the horizon at 10 m/s. A second piece of mass 1.2 kg travels at an angle of 180° and is moving at 15 m/s.
a) find the momentum of the third piece.
b) find the velocity of the third piece if it's mass is 3 kg.
a) The momentum of the third piece is 19.1 kg m/s
b) The velocity is 6.4 m/s at an angle of [tex]-65^{\circ}[/tex]
Explanation:
a)
We can solve this problem by applying the law of conservation of momentum in 2D. In fact, the total momentum of the board before the explosion must be equal to the total momentum of the 3 pieces after the explosion.
Before the explosion, the total momentum is zero, since the board is at rest. Resolving into the x- and y- components, this means that the two components of the momentum are zero:
[tex]p_x = 0\\p_y = 0[/tex]
After the explosion, we have:
[tex]p_x = (2 kg)(10 m/s)( cos 60^{\circ}) + (1.2 kg)(15 m/s)(cos 180^{\circ})+p_{3x}[/tex]
where [tex]p_{3x}[/tex] is the x-component of the momemtum of the 3rd piece. By solving,
[tex]p_x = -8+p_{3x}[/tex]
And since the x-momentum must be conserved,
[tex]0=-8+p_{3x} \rightarrow p_{3x}=8 kg m/s[/tex]
Similarly, along the y-axis,
[tex]p_y = (2 kg)(10 m/s)( sin 60^{\circ}) + (1.2 kg)(15 m/s)(sin 180^{\circ})+p_{3y}[/tex]
where [tex]p_{3y}[/tex] is the y-component of the momemtum of the 3rd piece. By solving,
[tex]p_y = 17.3+p_{3y}[/tex]
And since the y-momentum must be conserved,
[tex]0=17.3+p_{3y} \rightarrow p_{3y}=-17.3 kg m/s[/tex]
So now we can find the momentum of the third piece:
[tex]p_3 = \sqrt{p_{3x}^2+p_{3y}^2}=\sqrt{8^2+(-17.3)^2}=19.1 kg m/s[/tex]
b)
The momentum of the third piece is given by
[tex]p_3 = m v_3[/tex]
where
m = 3 kg is the mass of the piece
[tex]v_3[/tex] is the velocity
Solving for [tex]v_3[/tex], we find
[tex]v_3 = \frac{p_3}{m}=\frac{19.1}{3}=6.4 m/s[/tex]
We can also find the direction, which is identical to the direction of the momentum, by using the following equation:
[tex]\theta = tan^{-1}(\frac{p_{3y}}{p_{3x}})=tan^{-1}(\frac{-17.3}{8})=-65^{\circ}[/tex]
So, the third piece flies off at 6.4 m/s at an angle of [tex]-65^{\circ}[/tex].
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What does the slope of a Position vs. Time graph represent?
Your question asks what the slope of a Position vs. Time graph represents.
Your answer would be Velocity.
The slope of a Position vs. Time graph would represent the velocity of the object.
If the slope is positive, then the object has a positive velocity ,in which it is going forward.
If the slope is negative, then the object has a negative velocity, which means that it's going the opposite direction, or backwards.
If the slope is at a "horizontal" position, this means that the object is stopped or isn't moving at all.
The slope of a Position vs. Time graph represents velocity, specifically the instantaneous velocity at a given point in time.
Explanation:This means that when you look at a graph and see the position of an object on the y-axis and the time on the x-axis, the steepness of the curve or straight line (slope) that describes the object's motion gives you a measure of how fast the object is moving (velocity). More importantly, the slope of this graph at any particular point corresponds to the instantaneous velocity at that point in time.
To further illustrate, consider a car that is speeding up. The graph representing its position vs time would start at a lower point (indicating zero or smaller velocity) and rise to a high point (indicating a high velocity), showing it is accelerating. The actual value of the slope would give you the car's speed or velocity at any particular time.
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In which example would the amount of work done equal
zero?
A. holding a 1,000-N rock overhead Hope this helps :)
A basic substance consisting of only one kind of atom is called a(n)
ion
compound
element
molecule
Answer:
Element
Explanation:
A 20g book laying on a 40cm high table. Just before a cat knocks it off the table what is the books gravitational potential energy?
Answer:
The book gravitational potential energy is 0.0784 Joules.
Explanation:
Given:
Mass of book, m = 20 g = 20 ÷ 1000 = 0.02 kg
Table height, h = 40 cm =40 ÷ 100 = 0.4 m
To Find:
Gravitational Potential Energy = ?
Solution:
Gravitational Potential Energy :
Gravitational potential energy is energy an object possesses because of its position in a gravitational field.
Formula is given by
[tex]\textrm{Gravitational Potential Energy}= m\times g\times h[/tex]
Where,
m = mass
g = acceleration due to gravity = 9.8 m/s²
h = height
Substituting the values we get
[tex]\textrm{Gravitational Potential Energy}= 0.02\times 9.8\times 0.4\\\\\textrm{Gravitational Potential Energy}=0.0784 Joules[/tex]
The book gravitational potential energy is 0.0784 Joules.
Factors that influence Wellness
Answer:
Physical and mental factors, work, and lifestyle
Explanation:
I'm kind of taking a guess at this, but I'd assume these factors affect and influence personal wellness
John traveled East at 10 m/s for ten
seconds. He realized he had gone too
far and made a U-turn. He traveled
West at 5 m/s for six seconds. Calculate
John's displacement.
a. 30 m
b. 70 m
C. 100 m
d. 130 m
Answer:
Option D
130 m
Explanation:
From the concept of speed, distance=speed*time
When traveling East, displacement=10*10=100 m (since he takes 10 seconds while traveling at a speed of 10 m/s)
When traveling West, displacement=5*6=30 m (since John takes 6 seconds to travel at a speed of 5 m/s)
Total displacement=Displacement East+ Displacement West=100+30=130 m
vector A has a magnitude of 60 units eastward and vector
B has a magnitude of 11 units northward. What is the
magnitude of the resultant between vectors A & B?
Answer:
Resultant Vector will 71 units
Explanation:
if we draw vector A in eastward direction such that its head coincides with the tail of vector B in northward direction then the resultant vector will be equal to
Va+ Vb= 60 +11= 71 units
and its direction will be from the tail of vector A to the head of vector B
What an object at rest stays at rest and an object in motion with the same speed and in the same direction unless acted upon by an unbalanced force is newton's 1st law of motion?
True
Or
False
Answer:
True.
Explanation:
Newton's First Law of Motion states that every object continues in it's state of rest or of uniform motion in a straight line unless acted upon by an external force.
Which is the standard unit of time in the metric system?
Explanation:
Metric time is the measure of time intervals using the metric system. The modern SI system defines the second as the base unit of time, and forms multiples and submultiples with metric prefixes such as kiloseconds and milliseconds. Other units of time: minute, hour, and day, are accepted for use with SI, but are not part of it. Metric time is a measure of time intervals, while decimal time is a means of recording time of day.
Answer the question please
Answer:
B. solubility I think lmk if its wrong
One day in second grade, Chris drank chocolate milk before recess. She then played hard during recess and got sick from the heat. That was years ago, but Chris never drank chocolate milk again because even thinking about chocolate milk makes her feel sick. Chris is most likely experiencing __________. A. food aversion B. superstition C. phobia D. learned helplessness
Answer:
A. Food Aversion
It's right on ED2020, good luck!! Stay healthy and safe!!
Final answer:
Chris is experiencing food aversion, which is an associative learning process where one learns to avoid certain tastes associated with past sickness.
Explanation:
Chris is most likely experiencing a food aversion. This type of conditioning occurs when an individual associates the taste of a certain food or drink with a negative experience, such as illness, and then avoids it in the future. The event where Chris felt sick after playing hard in heat post-drinking chocolate milk exemplifies how a single adverse incident can lead to a long-lasting aversion. This aversion is a learned response when the conditioned stimulus (in Chris's case, chocolate milk) is paired with an unconditioned stimulus (feeling sick) resulting in a conditioned aversion to the food or drink.
Similar to Chris's experience with chocolate milk, taste aversion conditioning can happen when flavors associated with stomach pain or illness become avoided and disliked, an evolutionary mechanism important for animals and humans to avoid potential toxins. An example is how cancer patients may develop aversions to certain foods right before chemotherapy since the treatment often leads to nausea or sickness, strengthening the association between the flavor and the negative reaction.
Question 49 (1 point)
What kind of relationship, if any, exists between an orbit's semimajor axis length and
its period?
A direct
B inverse
Cno relationship
Answer:
Orbit's semi-major axis length and its period is directly proportional.
Explanation:
Orbital period(T) is the time taken for an celestial object to make one complete revolution in the orbit around other object
According to Kepler's laws 3rd of planetary motion stating
The square of an orbital period T of a planet is “directly proportional” to the cube of the "semi-major axis" of its orbit.
The orbital period T is given by
[tex]T=2 \pi \sqrt{\frac{a^{3}}{\mu}}[/tex]
Where
a is the semi-major axis of the orbit
µ = GM which is the standard gravitational parameter
With G is the gravitational constant and M is the mass of body.
A dog, that has a mass of 16 kgs, runs across a yard. What is the average force applied to the dog from the ground as it runs across the yard?
Answer:
156.96 N
Explanation:
F=ma where m is the mass and a is acceleration
Substituting 16 Kg for m and 9.81 m/s2 for g then
F=16*9.81= 156.96 N
Two substances were mixed and there was a color change and small flames. What can you infer happened?
A physical property was observed
A chemical change occurred
A change in state from solid to liquid
Matter was destroyed
A chemical change occurred
Explanation:
There are two types of changes, physical changes and chemical changes:
A chemical change occurs when the nature of a substance changes, and new substances are formed. This occurs when the bonds between molecules in the reactants break, and they re-form into new substance. A change in the colors of the substance involved is, for example, a sign that a chemical change occurredA physical change occurs when there is a change in state of a substance, but no new substances are formed. For instance, a physical change is the melting of ice, or the boiling of water, or the condensation of water..In this problem, two substances are mixed and there is a color change and small flames. The color change indicates the formation of new substances, so a chemical change has occurred. Moreover, the presence of small flames indicates that a chemical reaction has occurred (burning of oxygen), so a new substance has formed, so this is another indication of a chemical change.
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Carbon-14 undergoes radioactive decay in the reaction above. Determine the type of radiation emitted in this reaction and describe what is happening to the nucleus during this reaction.
A) Alpha radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a helium atom has been emitted from the nucleus.
B) Beta radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a proton, which occurs by emitting an electron.
C) Beta radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a electron, which occurs by emitting an proton.
D) Gamma radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a proton, which occurs by emitting an electron.
OPTION B
Emission of beta radiation is what's occurring in the radioactive decay of Carbon-14. This is due to a neutron decaying into a proton and giving off an electron (beta particle), causing the atomic number to increment from 6 to 7.
Explanation:In the case of Carbon-14 undergoing radioactive decay, the correct answer would be B) Beta radiation is emitted because the atomic number increases (from 6 to 7). This increase indicates that a neutron in the nucleus of Carbon-14 has decayed into a proton. This decay process emits an electron, known as a beta particle, and this is what gives this type of radioactive decay its name: beta decay. The emission of this beta particle is what causes the atomic number to increase (as the atomic number is simply the number of protons in the nucleus), and thus transforms the Carbon-14 nucleus into a Nitrogen-14 nucleus.
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Find the speed of a dog that runs .05 km in 1 min (convert to meters and seconds)
.05km= 50m
1m=60s
s= d/t
50/60
.83 m/s
please help me i dont get it
The answers are:
39:
a - 1 mile
b - 0 miles
40:
[tex]a=-4\frac{m}{s^{2} }[/tex]
41:
[tex]Displacement=3.60 miles\\Distance=5 miles[/tex]
Why?
Solving 39:
To answer the questions, we need to remember that distance and displacement are different things. Distance refers to the total "ground" covered during motion, while displacement refers to how far is the object/body from its starting point.
So,
39:
a - the total distance traveled corresponds to the length of the track which is 1 mile.
b - The displacement is equal to 0 because they finished at the starting point, the distance between the starting and the finishing point is equal to 0.
40:
We can solve the problem using one of the given equations:
[tex]a=\frac{v_f-v_i}{t}[/tex]
Since we know all the information, we just need to substitute it into the equation:
[tex]a=\frac{v_f-v_i}{t}\\\\a=\frac{2\frac{m}{s} -16\frac{m}{s} }{3.5s}=\frac{-14\frac{m}{s} }{3.5s}\\\\a=-4\frac{m}{s^{2} }[/tex]
So, the car's acceleration was -4m/s2 (the car was reducing its speed)
41:
We can solve the problem using one of the given equations (Pythagorean Theorem):
[tex]c^{2}=a^{2}+b^{2}[/tex]
[tex]Displacement=\sqrt{(3mi(North))^{2}+(2miles(East))^{2}}\\\\Displacement=\sqrt{9+4}=\sqrt{13mi^{2}}=3.60miles[/tex]
The distance will be:
[tex]Distance=3mi+2mi=5miles[/tex]
Have a nice day!
A kitten sits in a lightweight basket near the edge of a table. A person accidentally knocks the basket off the table. As the kitten and basket fall, the kitten rolls, turns, kicks, and catches the basket in its claws. The basket lands on the floor with the kitten safely inside. If air resistance is negligible, what is the acceleration of the kitten-basket system while the kitten and basket are in midair? A The acceleration is directed downward with magnitude less than g because the basket is light. B The acceleration is directed downward with magnitude equal to g because the system is a projectile. C The acceleration fluctuates because of the rolling, turning, and kicking motion of the kitten. D The acceleration cannot be determined without knowing how hard the basket is pushed.
Answer:
the answer is B
Explanation: this was actually an ap exam question a few years back. the reason for answer B is that the only force being applied to the kitten is the force of gravity after being pushed.
The acceleration of the kitten-basket system is directed downward with a magnitude equal to g because the system is a projectile, therefore the correct answer is B.
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem kitten sits in a lightweight basket near the edge of a table. A person accidentally knocks the basket off the table. As the kitten and basket fall, the kitten rolls, turns, kicks, and catches the basket in its claws. The basket lands on the floor with the kitten safely inside. If air resistance is negligible,
There is no external force acting on the kitten-basket system except the gravitational force of the earth hence we can conclude that the acceleration is directed downward with a magnitude equal to g because the system is a projectile, thus the correct answer is option B.
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What is the distance traveled between 0 s and 30 s?
Answer:
0m
Explanation:
In physics this is 0m, why?
Okay so, you moved 60 meters (in position/m) the first 10 seconds (sec) and then between 10 and 15 seconds, you took a brake and didn't move. (The graph is still because the time is constant and your motion is 0 meters).
When 15 seconds have passed, you go back where you were, exactly at 0 meters, your initial position.
In reality would this be 60 meters + 60 meters back which would be 120 meters, or 0.12km if you will. But in physics world, it's 0 meters in position.
Hope you understood!
Good luck!
Astrophysicist Dr. D
Answer:
120 m
Explanation:
The displacement from 0 s to 30 s is 0 m, since the change in position between those points is 0 m. However, we are asked to find the distance traveled, not the displacement.
The object travels 60 m forward, then 60 m backward. So the total distance traveled is 120 m.
a girl performed 50j of work lifting a heavy box it took her 5 seconds to lift the box what is her power
Answer:
10 W
Explanation:
Power is work over time.
P = W / t
P = 50 J / 5 s
P = 10 W
Answer:
It is 10 W
Explanation:
a ball is thrown downward with an initial speed of 7m/s. the balls velocity after 3 seconds is m/s
Answer: -36.4
Explanation:
It says that the initial speed is 7 and the time is 3. acceleration is -9.8 ( its always 9.8 but since its going downward its negative)
The equation you want to use is Vf = Vo + AT.
When you plug in the answers it is
0 = 7 + -9.8(3)
-9.8(3) = -29.4
Then add 7
and you get -36.4
The ball's velocity after 3 seconds is 24.4 m/s.
The ball is thrown downward with an initial speed of 7 m/s. The acceleration due to gravity is 9.8 m/s². So, the ball's velocity is increasing at a rate of 9.8 m/s^2.
After 3 seconds, the ball's velocity is 7 m/s + 3 * 9.8 m/s²
= 24.4 m/s.
Therefore, the ball's velocity after 3 seconds is 24.4 m/s.
First, we find the acceleration of the ball by multiplying the acceleration due to gravity by the time it has been falling.
Next, we add the initial velocity of the ball to the acceleration we just found to find the final velocity of the ball.
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calculate the magnitude of impulse applied to a 0.75 kilogram cart to change its velocity from 0.50 meters per second east to 2.00 meters per second east
Answer:
1.125 N s towards East
Explanation:
since both velocities are in same direction hence change in velocity is
Δ V = final - initial
= 2.00 - 0.50
= 1.50 towards East
impulse = change of linear momentum
= mass × change in velocity
= 0.75 ×1.50
= 1.125 N s towards East
A charge is moving in a magnetic field that points to the left.
What direction can the charge move and experience no
magnetic force? Check all that apply
Oup
down
O left
right
into the screen
out of the screen
The charge experiences no magnetic force when it is moving to the left or to the right
Explanation:
The force experienced by a charge moving in a magnetic field is given by the equation
[tex]F=qvB sin \theta[/tex]
where
q is the magnitude of the charge
v is its velocity
B is the strength of the magnetic field
[tex]\theta[/tex] is the angle between the directions of v and B
From the equation, we observe that:
The force is zero when the charge is moving parallel (or anti-parallel) to the field, so when the angle between v and B is zero (or 180 degrees): [tex]sin 0^{\circ} = 0[/tex] ([tex]sin 180^{\circ}=0[/tex]The force is maximum when the charge is moving perpendicular to the field, so when the angle between v and B is 90 degrees: [tex]sin 90^{\circ}=1[/tex]From the first observation, we can say therefore that the charge in the problem will experience no magnetic force when it is moving parallel (or anti-parallel) to the field. Since the magnetic field points to the left, this means that the charge will experience no force when it is moving in one of the following directions:
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Final answer:
A charge moving in the direction of the magnetic field or the exact opposite direction experiences no magnetic force. Thus, if the magnetic field points to the left, the charge can move left or right without experiencing any magnetic force.
Explanation:
A charge moving in a magnetic field experiences a magnetic force that is always perpendicular to both the velocity of the charge and the magnetic field. This force is explained by the right-hand rule, where the thumb points in the direction of the velocity of the positive charge, the fingers point in the direction of the magnetic field, and the palm indicates the direction of the force for a positive charge, and the back of the hand indicates the force direction for a negative charge.
If a charge is moving left and the magnetic field points left, then according to the right-hand rule, there is no direction for the perpendicular force to act since the velocity of the charge is parallel to the magnetic field. Thus, a charge would experience no magnetic force if it moved parallel to the magnetic field. Therefore, the correct answers are:
Left - moving parallel to the field
Right - moving parallel to the field in opposite direction
If instead, the charge moves up or down, it will experience a magnetic force because the motion is perpendicular to the magnetic field. Similarly, moving into or out of the screen would also result in the charge experiencing a magnetic force, since this is another direction perpendicular to the magnetic field.
A custodian is struggling to move a 100. kg desk on a dolly, using a rope. He is pulling on the rope at a 60. ◦ angle. (a) How much force will the custodian need to apply in order to cause the desk to accelerate horizontally at a rate of 1.0 m s 2 ? (b) You suggest that the custodian will have an easier time if he uses a longer rope, which will decrease the angle. If the longer rope results in an angle of 30. ◦ , much force will the custodian need to apply in order to cause the 100. kg desk to accelerate horizontally at 1.0 m s 2 ?
a) The custodian needs to apply 200 N of force
b) The custodian needs to apply 115.4 N of force
Explanation:
a)
We can solve this problem by applying Newton's second law: in fact, the net force along the horizontal direction must be equal to the product between the mass of the desk and the horizontal acceleration. Mathematically,
[tex]F_x = ma_x[/tex]
where
[tex]F_x = F cos \theta[/tex] is the net force on the horizontal direction, with F being the magnitude of the force applied by the custodian, and
[tex]\theta=60^{\circ}[/tex] the angle at which the force is applied
m is the mass of the desk
[tex]a_x[/tex] is the horizontal acceleration
In this problem we have:
m = 100 kg
[tex]a_x = 1.0 m/s^2[/tex]
Solving for F, we find the force that the custodian must apply:
[tex]F=\frac{ma_x}{cos \theta}=\frac{(100)(1.0)}{cos 60^{\circ}}=200 N[/tex]
b)
In this case, the rope has an angle of [tex]30^{\circ}[/tex] with the horizontal: this means that the force is applied at an angle of
[tex]\theta=30^{\circ}[/tex]
with the horizontal.
As before, we can apply Newton's second law:
[tex]F_x = ma_x[/tex]
And we have again
m = 100 kg (mass of the desk)
[tex]a_x=1.0 m/s^2[/tex] (horizontal acceleration)
This can be rewritten as
[tex]Fcos \theta = ma_x[/tex]
And solving for F, we find
[tex]F=\frac{ma_x}{cos \theta}=\frac{(100)(1.0)}{cos 30^{\circ}}=115.4 N[/tex]
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The custodian should apply 200 N of force at a 60 degree angle and approximately 115.5 N of force at a 30 degree angle to accelerate the 100 kg desk horizontally at 1 m/s^2.
Explanation:The question is asking about the force the custodian would need to apply to move a 100 kg desk on a dolly at a certain angle to accelerate it horizontally at 1 m/s^2. This concerns the application of Newton's second law in the context of force and acceleration, taking into account the angle at which the force is applied.
(a) To find the force at a 60 degrees angle, we need to use Newton's second law in the vertical component: F=ma. The force applied in the direction of movement (horizontal) would be F=100 kg * 1 m/s^2=100 N. However, because the force is applied at an angle, the horizontal component of the force is F * cos(60), which equals 100 N. Thus, the actual force applied by the custodian must be 100 N / cos(60) = 200 N.
(b) If the angle is reduced to 30 degrees, it becomes easier to move the desk because the horizontal component of the force is greater. In this case, the actual force applied would be 100 N / cos(30) = approximately 115.5 N. So, the custodian would need to apply less force to achieve the same acceleration.
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When force is applied to an object, what happens
Answer:
The force on he object can cause an object to move or speed up. It can also make it stop or change direction.
Explanation:
Which of these describes the majority of our space observations humans have utilized over the history of human space exploration?
A) Gamma ray telescope
B) radio wave telescopes
C) ultraviolet telescopes
D) visible light observatories
Gamma Ray telescopes are the one mostly used by humans for majority of space observations.
Answer: Option A
Explanation:
Since the year 1965, Gamma ray telescopes have attained a major area in space research. As gamma rays are emitted by most of the astrophysical particles like novae, black holes, dwarf stars, supernovae, neutron stars, pulsars, so it is easy to find any changes in space. Even highly energetic gamma burst can also be observed by these telescopes.
So, among the other telescopes like radio, ultraviolet, visible light observations, gamma ray telescopes are mostly preferred for space observations. As the other telescopes have low range of observations and they may have losses. But gamma rays does not interact with other particles, there will be less chance of loss of signals for gamma observations.
Answer:
d
Explanation:
visible light observations
A man can jog 10 miles in 90 minutes. What’s his speed in mph?
Answer:
hi there!
the correct answer to this question is: 6.67 mph
Explanation:
you convert minutes to hours
10 miles * 60 mins / 90 mins
Final answer:
To find the man's jogging speed in mph, divide the distance he jogs, 10 miles, by the time it takes in hours. He jogs 10 miles in 1.5 hours (90 minutes), giving him a speed of 6.67 mph.
Explanation:
To calculate the man's speed in mph (miles per hour), we need to divide the distance traveled by the time it took him to travel that distance. The man jogs 10 miles in 90 minutes. Since there are 60 minutes in an hour, we convert 90 minutes to hours by dividing by 60, which equals 1.5 hours.
To find the speed, we use the formula:
Speed = Distance ÷ Time
Speed = 10 miles ÷ 1.5 hours
Speed = 6.67 mph
This calculation shows that the man's jogging speed is 6.67 mph.