which property is a measure of the average kinetic energy of the particles in the sample of matter

The surface of a mirror is smoothly and therefore the rays of light are reflected with the same angle they hit the surface. The surface of a piece of wood on the other hand has a lot of microscopical imperfections and hence the rays of light are reflected in multiple directions.

The reflection in a mirror looks different from the reflection in wood because mirrors have smooth surfaces that reflect light at specific angles, while wood and other rough surfaces diffuse and reflect light in many different directions.

When we look at our reflection in a mirror, we see a clear and accurate representation of ourselves because mirrors have smooth surfaces that reflect light at specific angles. On the other hand, when we look at our reflection in wood or other rough surfaces, the light gets diffused and reflected in many different directions, causing distortions and a less accurate reflection.

Answer is: more L and H will be produced.

Balanced chemical reaction: B + K → L + H.

According to Le Chatelier's Principle, the position of equilibrium moves to counteract the change.

The position of equilibrium will move so that the concentration of B decreases again, by reacting more and produce L and H, reaction is going to be more in forward direction.

Answer : The concentration of the [tex]KOH[/tex] is, 0.115 M

Explanation :

Using dilution law,

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1[/tex] = basicity of an acid = 1

[tex]n_2[/tex] = acidity of a base = 1

[tex]M_1[/tex] = concentration of [tex]HClO_4[/tex] = 0.125 M

[tex]M_2[/tex] = concentration of KOH = ?

[tex]V_1[/tex] = volume of [tex]HClO_4[/tex] = 25 ml

[tex]V_2[/tex] = volume of NaOH = 27.07 ml

Now put all the given values in the above law, we get the concentration of the [tex]KOH[/tex].

[tex]1\times 0.125M\times 25ml=1\times M_2\times 27.07ml[/tex]

[tex]M_2=0.115M[/tex]

Therefore, the concentration of the [tex]KOH[/tex] is, 0.115 M

The concentration of 27.07ml of KOH solution requires to titrate 25mL of 0.125 M HClO₄ is 0.115 M.

Concentration of any solution in the titration will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ is the molarity and volume of HClO₄ and M₂ & V₂ is the molarity and volume of KOH solution. Now putting values from the question on the above equation, we get

M₂ = (0.125)(25) / (27.07) = 0.115 M

Hence required concentration of KOH is 0.115M.

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The stoichiometric equation shows that 2 moles of H2 react with 1 mole of O2. In this scenario, 48 grams of O2 is equivalent to 1.5 moles. Therefore, 1.5 moles of O2 would react with 3 moles of H2, which is equivalent to 6 grams.

To solve this question, we must first understand the stoichiometric relationship that exists between H2 and O2 according to the given equation: 2 H2 (g) + O2 (g) --> 2 H2O (l). What this equation shows is that 2 moles of H2 react with 1 mole of O2.

Next, we must convert grams of O2 to moles, using its molar mass. The molar mass of O2 is 32 g/mol, so 48 grams of O2 is equivalent to 48 g / 32 g/mol = 1.5 mol.

Then we use the stoichiometric relationship to calculate the moles of H2 needed. As per the reaction, 1 mole of O2 reacts with 2 moles of H2, hence 1.5 moles of O2 would react with 2*1.5 = 3 moles of H2. Finally, convert the moles of H2 to grams, using its molar mass (2 g/mol). So, 3 mol * 2 g/mol = 6 g. Therefore, 6 grams of H2 are needed to react with 48 grams of O2.

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The answer is A

Two covalent bonds between adjacent molecules

Hope it helps you

He arranged the first periodic table?

The electron configuration of an atom of Chlorine Cl (neutral Chlorine) is:

1s2 2s2 2p6 3s2 3p5

Now if the Chlorine becomes an ion, it becomes Cl-. So we can see that 1 electron is added therefore the new electron configuration is:

1s2 2s2 2p6 3s2 3p6

Answer:

solid

Explanation:

Answer:

In case if the pellets of the calcium chloride gets crushed.

Explanation:

When the pellets of calcium chloride get crushed it enhances the surface area of the compound. With the increase in surface area, the number of collisions in between the molecules of reactants increases. In the given case, the reactant molecules are water molecules and calcium chloride ions. In the procedure of dissolution, the calcium chloride ions get hydrated by the water molecules dipoles. As the frequency of the collision enhances, the activation energy gets lowered in order to begin the reaction.

The precautions we take to handle these solutions is to wear safety goggles, lab coat and also the hand gear (this is also important).

KOH (potassium hydroxide), which is a strong base and HCL (hydrochloric acid) which is a strong base and both these solutions dissociates completely in water. So, whenever you are working in laboratory with chemicals you must be careful.

Answer:The correct answer is option A.

Explanation

Mass of the iron pyrite= 20 grams

Volume water displaced by the iron pyrite = 4 mL

Density of iron pyrite=[tex]d_i=\frac{Mass}{Volume}=\frac{20 g}{4 mL}=5 g/mL[/tex]

[tex]d_g=4\times d_i[/tex](Given)

[tex]d_g=4\times 5 g/mL=20 g/mL[/tex]

Mass of gold = 20 g

Volume of water displaced by the 20 grams of water = V

[tex]D_g=20 g/mL=\frac{20 g}{V}[/tex]

V = 1 mL

20 grams of gold will displace 1 ml of water.So, the correct answer is option A.

Final answer:

The average energy associated with the atomic emission line of sodium with a wavelength of 590 nm is calculated using Planck's equation, resulting in an energy of approximately 3.37×10-19 Joules per photon.

Explanation:

The question asks for the calculation of the average energy (ΔE) associated with the atomic emission line of sodium, which has a wavelength of 590 nm. To calculate this, we use the Planck's equation ΔE = h⋅c / λ, where h is Planck's constant (6.626×10-34 J⋅s), c is the speed of light in a vacuum (3.00×108 m/s), and λ is the wavelength in meters.

To convert the wavelength from nanometers to meters, we use the conversion 590 nm = 590 × 10-9 m. Substituting the values into the equation gives us ΔE = (6.626×10-34 J⋅s) ⋅ (3.00×108 m/s) / (590×10-9 m), which calculates to an energy of about 3.37×10-19 Joules per photon.

Answer 1: A gun shot residue is the powdery discharge that release after the firing process of the firearm. The powdery discharge consists of unburnt or partially burnt primer, propellants, fragments of the projectiles, cartilage cases  and residues present inside the firearm.

It is important for the forensic scientists so as to detect the culprit as these residues are left on the clothes and hands after firing. It can be used to identify the direction and distance of firing.

Answer 2: The complications associated with gunshot residue are:

1. The particles are very small and may exhibit low density they are likely to blow by wind so they may not be found at some crime scene.

2. As the powdery discharge consists of explosive particles in small amounts but on testing can explode and can cause harm.