Answer:
All dwarf planets likely contain a mixture of rock and ice
Explanation:
The true statement about dwarf planets is that Pluto was the first to be discovered. Dwarf planets share common features like orbiting the sun and having a near-spherical shape but have not cleared their orbits of other objects.
The true statement about dwarf planets is that Pluto was the first dwarf planet to be discovered. Dwarf planets are celestial bodies that meet two of the three criteria set by the International Astronomical Union (IAU) for being a planet: they orbit the sun and have sufficient mass for a nearly spherical shape, but they have not cleared their orbits of other objects. While not all dwarf planets are beyond the outer planets (Ceres, for example, is located in the asteroid belt between Mars and Jupiter), all discovered dwarf planets have a mixture of rock and ice, and with the exception of Ceres, they are found beyond Neptune. Pluto, which was initially classified as one of the major planets, became known as a dwarf planet due to the redefinition of what constitutes a planet in 2006.
A positive charge Q is distributed uniformly along the positive y-axis between y=0 and y=a. A negative point charge, -q, lies on the positive x-axis, a distance x from the origin. Calculate the x and y components of the E-field produced by the charge distribution Q at points on the positive x axis.
The electric field components at points on the x-axis are determined concerning a positive charge Q uniformly distributed along the y-axis and a negative charge -q on the x-axis. The x-component is caused only by -q and the y-component is determined by integrating the electric field due to Q over y=0 to y=a.
Explanation:The electric field created by a point negative charge -q on the positive x-axis and a positive charge Q spread evenly along the positive y-axis is the subject of the problem set. The x-component and y-component for the E-field need to be determined.
Given the distribution of positive charge Q along the y-axis between y=0 and y=a, the electric field at any point y on the y-axis due to this distribution is E1 = kQ/y²
where 'k' is Coulomb's constant. The electric field E2 on the x-axis for the negative charge -q is equal to -kq/x² at any distance x from it. The total x-component, being only due to the negative charge, is -kq/x². The y-component, due to the positive charge, will be integrated over the limit y=0 to y=a, ∫kQ/y² dy from 0 to a.
This integral gives the total y-component of the electric field.
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What happens during the intake and compression strokes of a four stroke engine?
In a four stroke engine, the intake stroke pulls in air mixed with fuel as the piston expands, then the compression stroke rapidly compresses this mixture in a nearly adiabatic process with the valves closed, causing the fuel-air mixture's temperature to rise.
Explanation:The intake and compression strokes are the first two phases of the four-stroke cycle in an internal combustion gasoline engine, often explained in terms of the Otto cycle. During the intake stroke, air is mixed with fuel in the combustion chamber as the piston expands. This causes an increase in the volume of the cylinder and draws in a mixture of gasoline and air.
In the second phase, the compression stroke, the air-fuel mixture is rapidly compressed in a nearly adiabatic process. The piston rises, with the valves closed, causing the temperature of the mixture to rise. Work is done on the gas during this stage as the piston compresses it from the expanded volume to a smaller volume. This prepares the mixture for ignition, which will occur in the succeeding phases of the four-stroke cycle. These processes convert chemical potential energy in the fuel into thermal energy and eventually into work, as part of the cyclical operation of the engine.
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A current of 8.0 A flows through a resistor when a potential difference of 20.0 V is applied to the resistor. What is the resistance of the resistor?
Which best contrasts the weak force and the electromagnetic force??
The weak nuclear force is weaker than the electromagnetic force but still stronger than gravity, operating at very short ranges and playing a key role in processes like beta decay, while the electromagnetic force has a longer-range impact and is responsible for holding atoms together.
Explanation:The key contrasts between the weak force and the electromagnetic force can be understood in terms of their strength, range, and the roles they play in the universe. The weak nuclear force is significantly weaker than the electromagnetic force but still much stronger than gravity. It is responsible for processes such as beta decay, acting at very short distances within atomic nuclei. In comparison, the electromagnetic force is not only stronger but also operates over larger distances, holding atoms together and resulting in electromagnetic radiation that allows us to study the universe.
Both the weak nuclear force and the electromagnetic force act at the subatomic level, but the electromagnetic force is responsible for a much wider range of phenomena due to its comparatively long-range influence. The two forces behave differently but can unify under certain conditions, such as those found in high-energy particle accelerators. However, such energies required for unification with the strong nuclear force are far beyond our current technological capabilities.
a fire hose held near the ground shoots water at a speed of 6.5 m/s. at what angle(s) should the nozle point in order that the water land 2.0 m away, why are there two different angles?
in the diagram, the hose is held straight up at theta degrees going at 6.5 m/s and with water falling down.. the distance between initial and final water displacement is 2m.. a fire hose held near the ground shoots water at a speed of 6.5 m/s. at what angle(s) should the nozle point in order that the water land 2.0 m away, why are there two different angles?
...?
The fire hose, shooting water at 6.5 m/s, should be angled at [tex]\(\frac{1}{2} \sin^{-1}\left(\frac{gR}{v^2}\right)\)[/tex] to achieve a 2.0 m range. Two angles exist due to the symmetrical nature of projectile motion.
To find the angles at which the water from the fire hose lands 2.0 m away, we can use the projectile motion equations. The horizontal distance (range) can be calculated using the formula:
[tex]\[ R = \frac{v^2 \sin(2\theta)}{g} \][/tex]
where:
R is the range (2.0 m),
v is the initial velocity of the water (6.5 m/s),
[tex]\( \theta \)[/tex] is the angle of projection,
g is the acceleration due to gravity (approximately 9.8 m/s²).
Rearranging the equation to solve for [tex]\( \theta \)[/tex], we get:
[tex]\[ \theta = \frac{1}{2} \sin^{-1}\left(\frac{gR}{v^2}\right) \][/tex]
Plugging in the given values, we find two possible angles: one for the first quadrant and another for the second quadrant. This is because the sine function has the same value in the first and second quadrants. Therefore, there are two solutions for [tex]\( \theta \)[/tex].
It's important to note that for a given range, there are two launch angles that result in the same range due to the symmetrical nature of the projectile motion. These angles are complementary, meaning their sum is 90 degrees. Therefore, two possible angles will yield the water landing 2.0 m away.
A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child continues moving forward at the original speed. This is an example of
The best answer would be, Newton's first law of motion.
In J. J. Thomson's experiments with electricity, he showed that an electrical current can be
A. made to flow from a positive site to a negative site
B. made to bend if it is deflected by encountering a positive charge
C. prevented from flowing in a vacuum In J. J. Thomson's experiments with electricity, he showed that an electrical current can be
A. made to flow from a positive site to a negative site
B. made to bend if it is deflected by encountering a positive charge
C. prevented from flowing in a vacuum
Answer:
B. made to bend if it is deflected by encountering a positive charge
Explanation:
J J Thomson's experiment is basically related to the discovery of the electron.
Thomson proved from his Cathode ray tube experiment that the cathode ray were actually a stream of electrons. In his Cathode ray tube experiment, he used the fact that the electric force and the magnetic force will be in equilibrium and that in such a situation, the electron does not deflect. He showed that charged particles can be deflected .
who wins a tug-of-war one who pushes harder at the ground or pulls harder at the rope
Every year, new records in track and field events are recorded. Let's take a historic look back at some exciting races.
On August 20, 1989, in Cologne, West Germany, Said Aouita of Morocco also established a world record when he ran the 3000. m run in 7.00 minutes, 29.45 seconds. What was his average speed (in m/s) for the race? Remember to include your data, equation, and work when solving this problem.
The complex power of a load is 50 j37.5 kva. find the power factor of this load
find the magnitude: || 5-3i || ...?
On earth you have a mass of 70 kg and a weight of approximately 700 N. The planet Mars has an acceleration due to gravity that is approximately 0.38 times as much as the earth (3.7 ms 2 ). Which statement would be true if you were on Mars?
A) Your mass would be 26.6 kg.
B) Your weight would be 266 N.
C) Your weight would be 1842 N.
D) Your mass would be 184.2 kg.
On Mars, your mass would be 26.6 kg.
Explanation:On Mars, the weight of an object is calculated by multiplying its mass by the acceleration due to gravity on Mars, which is approximately 0.38 times the acceleration due to gravity on Earth. Since your mass remains the same at 70 kg, the weight on Mars would be 70 kg multiplied by 0.38, which equals 26.6 kg. Therefore, statement A, which says that your mass would be 26.6 kg on Mars, is true.
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What are two ways to increase the acceleration of an object?
The ______ and _______ are used to calculate magnitude and direction of a resultant vector.
The magnitude and direction of a resultant vector can be calculated using the horizontal and vertical components.
Explanation:The magnitude and direction of a resultant vector can be calculated using the horizontal and vertical components. The horizontal component is denoted as Ax and the vertical component as Ay. To find the magnitude of the resultant vector, measure its length with a ruler and use the Pythagorean theorem to calculate it. To find the direction of the resultant vector, use a protractor to measure the angle it makes with the reference direction (e.g., the x-axis) and use trigonometry to calculate it.
A trailer mechanic pushes a 2500 kg car, home to a speed v, performing a job during the 5000 J. In this process, the car moves 25 m. Neglecting friction between the car and roadway:
(A) What is the final velocity v of the car? (B) What horizontal force exerted on the car?
Final velocity [tex]V_{f}[/tex] of the car will be 2 meters per second
Horizontal force exerted on the car will be = 200 newtons
What will be the final speed and horizontal force of the car ?
It is given that mass= 2500 kg
Total energy =5000 j
Car distance = 25 m
So the change in KE [tex]=\dfrac{1}{2} mv_{f} ^{2} -\dfrac{1}{2} mv_{i} ^{2}[/tex]
[tex]=\dfrac{1}{2} mv_{f} ^{2}[/tex] Since [tex]V_{ i} =0[/tex]
[tex]=\dfrac{1}{2} \times2500\times v_{f} ^{2}[/tex]
[tex]5000=\dfrac{1}{2} \times2500\times v_{f} ^{2}[/tex]
[tex]V_{f} =2 \dfrac{m}{s}[/tex]
Now the Total change in energy = Work done
[tex]=F\times d[/tex]
[tex]5000= F\times 25[/tex]
[tex]F= 200 N[/tex]
Hence
Final velocity [tex]V_{f}[/tex] of the car will be 2 meters per second
Horizontal force exerted on the car will be = 200 newtons
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When comparing two circuits, you note that circuit one has twice the voltage and half the resistance of circuit two. This means that
Answers:
1. both circuits will have the same current.
2. both circuits will have alternating current.
3. circuit two will have more current.
4. circuit one will have more current.
...?
Answer: option 4: circuit one will have more current.
Explanation:
Ohm's law states that the current in a circuit is proportional to voltage.
[tex]I \propto V \\ \Rightarrow I=\frac{V}{R}[/tex]
Let the current in the first circuit be I, voltage be V and resistance be R, the,
[tex]I_1=\frac{V_1}{R_1}[/tex]
The voltage in the second circuit is
[tex]V_2=\frac{V_1}{2}[/tex]
The resistance in the second circuit is:
[tex]R_2=2R_1[/tex]
[tex]\Rightarrow I_2=\frac{V_2}{R_2}=\frac{V_1/2}{2R_1}=\frac{I_1}{4}[/tex]
Hence, circuit one has 4 times more current than circuit two.
Which of the following parts of an organism is most likely to become fossilized? A.)tooth B.)skin C.)heart D.)Lung
a train is travelling up an a 3.73 degrees incline at a speed of 3.25m/s when the last car breaks free and begins to coast without friction.
How long does it take for the last car to come to rest momentarily?
The train car's stopping time on a 3.73-degree incline at a speed of 3.25 m/s can be found using kinematic equations in physics after calculating the component of gravitational acceleration along the incline.
Explanation:To determine how long it takes for the last car of a train to come to rest when traveling up a 3.73 degrees incline at 3.25 m/s, we can use kinematics, a subdivision of mechanics in physics. The force pulling the train car back down the incline is due to gravity, which creates an acceleration opposite to the movement of the car.
First, find the acceleration due to gravity along the incline using the equation a = g * sin(θ), where g is the acceleration due to gravity (9.81 m/s²) and θ is the incline angle. In this case, a = 9.81 m/s² * sin(3.73 degrees).
Then, we can calculate the time it takes for the train car to come to rest using the kinematic equation v = u + at, where v is the final velocity (0 m/s), u is the initial velocity (3.25 m/s), a is the acceleration found previously, and t is the time. Rearrange to find t: t = -u/a.
Completing these calculations gives us the time the train car will take to come to rest momentarily.
A net force of 125 N accelerates a 25.0 kg mass. What is the resulting acceleration?
Answer: [tex]a=5 m/s^2[/tex]
Explanation:
The acceleration of an object can be calculated by using Newton's second law:
[tex]F=ma[/tex]
where
F is the net force applied on the object
m is the mass of the object
a is its acceleration
In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:
[tex]a=\frac{F}{m}=\frac{125 N}{25.0 kg}=5 m/s^2[/tex]
two forces have the same magnitude F, what is the angle between the two vectors if their sum has a magnitude of (a) 2F? (b) sqrt of 2F (c) zero? Sketch the three vectors in each case. ...?
The angle between two equal forces depends on the resultant force when these two are added. It's 0 degrees if their sum is 2F (same direction), 90 degrees if their sum is sqrt of 2F (perpendicular), and 180 degrees if their sum is zero (opposite directions).
Explanation:The angle between the two forces with the same magnitude F depends on the resultant force when the two forces are added vectorially.
If the magnitude of their sum is 2F, the two forces are in the same direction, meaning the angle between them is 0 degrees. If the magnitude of their sum is sqrt of 2F, the two forces are perpendicular to each other, meaning the angle between them is 90 degrees. If the magnitude of their sum is zero, the two forces are in opposite directions, meaning the angle between them is 180 degrees. Learn more about Vector Addition of Forces here:
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Which of these help create radio waves?
changing electric and magnetic fields applied at right angles
longitudinal waves traveling along the horizontal direction
compressions traveling along the vertical direction
transverse waves traveling at different speeds
Answer:
A. changing electric and magnetic fields applied at right angles
Explanation:
what is slab pull i need help asap
The CORRECT answer is:
Cooler, denser crust sinks into the mantle
I know this because I am an online student, this was a question on my quiz which I got wrong. One I submitted the quiz, it gave me the correct answers to anything I get wrong.
You're welcome.
Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
______ m/s2
Answer: accelration=changespeed/changetime
changetime=8
changespeed=45-5=40
40/8=5
5m/s^2 is acceleration
Explanation:
Which of these is true about legos? XD (please don`t use google) A. They are for adults (XD)
B. They are made out of plastic
C. They are awesome (XD)
Answer:
B
Explanation:
Since all objects are ‘weightless’ for an astronaut in orbit, is it possible for astronauts to tell whether an object is heavy or light? Think about it, think of newton’s laws, the equations and then explain your reasoning.
Astronauts in orbit experience apparent weightlessness due to free-fall, but can still tell the difference between lighter and heavier objects by the force needed to change their motion. Their mass can be measured through exertion of a known force and observation of resulting acceleration, taking into account microgravity affects on the spacecraft.
Astronaut Perception of Weight in Orbit
Astronauts in orbit experience apparent weightlessness because they are in free-fall along with the spacecraft that surrounds them. In other words, the spacecraft and the astronaut accelerate towards Earth at the same rate due to gravity, which gives the impression of weightlessness. However, mass and inertia still apply to objects in orbit, meaning that astronauts can discern between heavier and lighter objects based on the force required to change their motion.
Measuring Mass in Orbit
To measure an astronaut's mass in orbit, a known force can be applied to them and their acceleration can be measured. According to Newton's second law of motion (F = ma), the mass can be calculated using the equation m = F/a, where F is the known force exerted on the astronaut, and a is the measured acceleration.
Effects of Forces in Microgravity
In the microgravity environment of orbit, exerting a force on an object will often produce a reaction that can affect the stability or position of other objects, including the spacecraft itself. Proposing methods to minimize these reactions, such as anchoring or using equal and opposite forces, is essential to accurate measurements in microgravity conditions.
What property must a refrigerant of a cooling system have? Why?
Refrigeration compressors turn gases into high-pressure and -temperature gases, are also used to maintain a low boiling point.
a toy car moves 8 m in 4 s at the constant velocity. whats the car's velocity?
The velocity of the toy car is 2m/s.
HOW TO CALCULATE VELOCITY:
The velocity of a body, also called its average speed, can be calculated by dividing the distance traveled by that body by the time taken. That is;Velocity (m/s) = Distance (m) ÷ time (s)
According to this question, a toy car moves 8m in 4s. The velocity of the toy car can be calculated as follows:Velocity = 8m ÷ 4s
Velocity = 2m/s.
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The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength of 0.6 meters?
5.52 × 102 hertz
2.56 × 102 hertz
459 × 102 hertz
675 × 102 hertz
990 × 102 hertz
Answer:
[tex]5.52 \cdot 10^2[/tex] Hz
Explanation:
For a wave, the relationship between velocity, wavelength and frequency is given by the wave equation:
[tex]v=f\lambda[/tex]
where
v is the velocity
f is the frequency
[tex]\lambda[/tex] is the wavelength
For the sound wave in this problem, we have:
v = 331 m/s
[tex]\lambda=0.6 m[/tex]
Solving the equation for f, we find the frequency:
[tex]f=\frac{v}{\lambda}=\frac{331}{0.6}=5.52\cdot 10^2 Hz[/tex]
Explain how high-pressure and low pressure systems are different
An object falls freely from rest near the surface of Earth. What is the speed of the object after having fallen a distance at 4.90 meters?
(1) 4.90 m/s
(2) 9.80 m/s
(3) 24.0 m/s
(4) 96.1 m/s
Answer:
v = 9.8 m/s
Explanation:
It is given that,
Distance covered by the object, s = 4.9 m
Initial speed of the object, u = 0 (at rest)
It is moving under the action of gravity such that a = g. Using the equation of kinematics as :
[tex]v^2-u^2=2gs[/tex]
[tex]v=\sqrt{2gs}[/tex]
[tex]v=\sqrt{2\times 9.8\times 4.9}[/tex]
v = 9.8 m/s
So, the speed of the object after having fallen is 9.8 m/s. Hence, this is the required solution.