Answer:
Option B on edge 2020 guys
Step-by-step explanation:
:)
The diameter of a circular field is 56cm.find the length of wire required to fence it?How many times it can be fenced with 704m of wire.
Final answer:
The length of wire required to fence the circular field is found by calculating the circumference of the field. The number of times the field can be fenced with a given length of wire is found by dividing the total wire length by the circumference.
Explanation:
To find the length of wire required to fence the circular field, we need to find the circumference of the field. The formula to calculate the circumference of a circle is C = πd, where C is the circumference and d is the diameter. So, in this case, the circumference is C = π * 56 cm. Next, to find how many times the field can be fenced with 704m of wire, we divide the total length of wire by the circumference of the field. Therefore, the number of times the field can be fenced is 704 m / (π * 56 cm).
Are the following lines parallel, perpendicular or neither? 5y - x = 5 5y - x = -5 a Parallel b Perpendicular c Neither
Answer:
Parallel lines
Step-by-step explanation:
Parallel lines have equal slopes
The product of the slopes of perpendicular lines equals - 1
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
Rearrange the 2 equations into this form and compare slopes
5y - x = 5 ( add x to both sides )
5y = x + 5 ( divide all terms by 5 )
y = [tex]\frac{1}{5}[/tex] x + 1 ← in slope- intercept form
with slope m = [tex]\frac{1}{5}[/tex]
5y - x = - 5 ( add x to both sides )
5y = x - 5 ( divide all terms by 5 )
y = [tex]\frac{1}{5}[/tex] x - 1 ← in slope- intercept form
with slope m = [tex]\frac{1}{5}[/tex]
Since slopes are equal then the lines are parallel
Write a polynomial in standard form with zeroes set at 2i, -2i, 2
The polynomial equation with zeroes 2i, -2i, 2 is [tex]x^3 -2x^2 + 4x - 8 = 0[/tex]
Solution:Given that zeros of polynomial are 2i, -2i, 2
To find: polynomial equation in standard form
zeros of polynomial are 2i, -2i, 2. So we can say,
x = 2i
x = -2i
x = 2
Or x - 2i = 0 and x + 2i = 0 and x - 2 = 0
Multiplying the above factors, we get the polynomial equation
[tex](x - 2i)(x + 2i)(x - 2) = 0\\[/tex] ------- eqn 1
Using a algebraic identity,
[tex](a - b)(a + b) = a^2 - b^2[/tex]
Thus [tex](x - 2i)(x + 2i) = x^2 - (2i)^2[/tex]
We know that [tex]i^2 = -1[/tex]
[tex]Thus (x - 2i)(x + 2i) = x^2 - (2i)^2 = x^2 -4(-1) = x^2 + 4[/tex]
Substitute the above value in eqn 1
[tex](x^2 + 4)(x - 2) = 0[/tex]
Multiply each term in first bracket with each term in second bracket
[tex]x^3 -2x^2 + 4x - 8 = 0[/tex]
Thus the required equation of polynomial is found
If 2x+3y=27 and 3x-2y=8 and x-y=1. What is x+y
Answer:
11
Step-by-step explanation:
2x+3y=27
3x-2y=8
----------------
3(2x+3y)=3(27)
-2(3x-2y)=-2(8)
-----------------------
6x+9y=81
-6x+4y=-16
------------------
13y=65
y=65/13
y=5
2x+3(5)=27
2x+15=27
2x=27-15
2x=12
x=12/2
x=6
------------------
x+y=6+5=11
M A grand store offered his consumers the following: A package of 4 boxes of pencils
udded to it 5 pencils free. Karoun bought 3 packages. Use the variable n that represents
the number of pencils in each box to write an algebraic expression representing the
number of pencils Karoun bought.
How many pencils will be there in the package if there are 10 pencils in every box?
Answer:
Karoun bought 12n + 15 numbers of pencils.
40 pencils
Step-by-step explanation:
If there are n numbers of pencils in each box of the pencil then there are 4n numbers of pencils in each package of pencils.
Now, Karoun bought 3 packages of pencils and get (5 × 3) = 15 pencils free of cost.
Therefore, Karoun bought (4n × 3) + 15 = 12n + 15 numbers of pencils. (Answer)
Now, if n = 10 pencils then in each package of pencils there will be 4n i.e. (4 × 10) = 40 pencils. (Answer)
The sum of 11 and the product of 2 & a number r
Answer:
Step-by-step explanation:
The word "sum" means adding. So, we have 11 + .....
The thing that 11 is being added to is a "product" a product means two things multiplied together. The things being multiplied are the number 2 and the number "r".
A new car is purchased for 20300 dollars. The value of the car depreciates at 95% per
year. What will the value of the car be, to the nearest cent, after 11 years?
Answer:
$6770.65
Step-by-step explanation:
The purchase price is $20,300
The depreciation rate is 9.5% per year, in decimal, that is:
9.5/100 = 0.095
We want to find the value of car after 11 years. We will use the compound decay formula:
[tex]F=P(1-r)^t[/tex]
Where
F is the future value (what we want to find after 11 years)
P is the present value, purchase price (20,300 given)
r is the rate of depreciation (r = 0.095)
t is the time in years ( t = 11)
Substituting, we solve for F:
[tex]F=P(1-r)^t\\F = 20,300(1-0.095)^{11}\\F=20,300(0.905)^{11}\\F=6770.65[/tex]
Thus,
The value of the car would be around $6770.65, after 11 years
Please help !!
A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 20 child bikes and 6 adult bikes in the week. (2 points)
a
No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
b
No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100
c
Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
d
Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100
"verify the following Pythagorean identity for all values of x and y"
Step-by-step explanation:
I hope you are able to understand the answer
A student asked to verify a Pythagorean identity, which typically involves applying the Pythagorean Theorem, a² + b² = c², to trigonometric functions. However, the specific identity to be verified was not provided in the question.
Explanation:The question involves verifying a Pythagorean identity, which likely refers to an equation involving the use of the Pythagorean Theorem. The Pythagorean Theorem states that for a right-angled triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b). The theorem is expressed mathematically as a² + b² = c².
However, the student's question seems incomplete as it does not provide the specific identity they wish to verify. Common Pythagorean identities include trigonometric identities that relate sine, cosine, and tangent to one another using the Pythagorean Theorem, such as sin²(x) + cos²(x) = 1 for any angle x. To verify a Pythagorean identity, one typically substitutes the trigonometric functions with their corresponding right triangle side ratios and demonstrates that the equation holds true.
Angles ∠ABC= x and ∠CBD=(2y+4) are complementary. ∠CBD and ∠DBE=(3y+x) are supplementary.
The missing question is find x , y and the measure of each angle
The values of x and y are x = 28 and y = 30
The measures of ∠ABC is 26°, ∠CBD is 64° and ∠DBE is 116°
Step-by-step explanation:
Let us revise the meaning of complementary angles and supplementary angles
Two angles are complementary if their sum is 90°Two angles are supplementary if their sum is 180°∵ ∠ABC = x
∵ ∠CBD = 2y + 4
∵ ∠ABC and ∠CBD are complementary
- That means their sum is 90°, add their values and equate
the sum by 90
∴ x + (2y + 4) = 90
∴ x + 2y + 4 = 90
- Subtract 4 from both sides
∴ x + 2y = 86 ⇒ (1)
∵ ∠DBE = (3y + x)
∵ ∠CBD and ∠DBE are supplementary
- That means their sum is 180°, add their values and equate
the sum by 180
∵ ∠CBD = (2y + 4)
∴ (2y + 4) + (3y + x) = 180
- Add like terms
∴ x + 5y + 4 = 180
- Subtract 4 from both sides
∴ x + 5y = 176 ⇒ (2)
Now we have a system of equations to solve them
Subtract equation (1) from equation (2) to eliminate x
∵ 3y = 90
- Divide both sides by 3
∴ y = 30
- Substitute the value of y in equation (1) to find x
∵ x + 2(30) = 86
∴ x + 60 = 86
- Subtract 60 from both sides
∴ x = 26
∵ ∠ABC = x
∴ The measure of angle ABC is 26°
∵ ∠CBD = 2y + 4
∴ ∠CBD = 2(30) + 4 = 60 + 4 = 64°
∴ The measure of angle CBD is 64°
∵ ∠DBE = 3y + x
∴ ∠DBE = 3(30) + 26 = 90 + 26 = 116°
∴ The measure of angle DBE is 116°
The values of x and y are x = 28 and y = 30
The measures of ∠ABC is 26°, ∠CBD is 64° and ∠DBE is 116°
Learn more:
You can learn more about the complementary angles and supplementary angles in brainly.com/question/10483199
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The question involves using the properties of complementary and supplementary angles to form equations and solve for the variables x and y.
Explanation:This question is about solving for variables using information about complementary and supplementary angles. A pair of angles are complementary if the sum of their measures is 90 degrees, and supplementary if the sum of their measures is 180 degrees.
In this case, ∠ABC= x and ∠CBD=(2y+4) are complementary, so their sum is 90 degrees. This gives us the equation: x + 2y + 4 = 90.
Similarly, ∠CBD and ∠DBE=(3y+x) are supplementary, meaning their sum is 180 degrees. This gives us the second equation: 2y + 4 + 3y + x = 180.
By solving these two equations, we can determine the values of x and y.
Learn more about Angles here:https://brainly.com/question/33354646
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What is an equation of the line that passes through the point (-6,-2) and is parallel to the line 2x-3y=12?
Answer:
y=2/3x+2
Step-by-step explanation:
2x-3y=12
3y=2x-12
y=2/3x-12/3
y=2/3x-4
----------------
y-y1=m(x-x1)
y-(-2)=2/3(x-(-6))
y+2=2/3(x+6)
y=2/3x+12/3-2
y=2/3x+4-2
y=2/3x+2
Whats the solution 8h – 3 = 11h + 12?
Answer:
Step-by-step explanation:
8h – 3 = 11h + 12
Collecting like terms
8h - 11h = 12 + 3
- 3h = 15
h = 15/-3
h = -5
6+2+2/3+2/9+...+a6 evaluate
Answer:
8.987 (Approximate)
Step-by-step explanation:
We have to find the sum of a G.P. series up to sixth terms.
The first term of the series is 6 and common ratio is [tex]\frac{1}{3}[/tex].
So, the sum is
[tex]6 + 2 + \frac{2}{3} + \frac{2}{9} + \frac{2}{27} + \frac{2}{81}[/tex]
= [tex]6 \times \frac{1 - (\frac{1}{3})^{6}}{1 - \frac{1}{3} }[/tex]
= 8.987 (Approximate) (Answer)
We know the sum of a G.P.
a + ar + ar² + ar³ + ......... up to n terms = [tex]a\frac{1 - r^{n}}{1 - r}[/tex]
where -1 < r < 1.
6(1) = 16
6(n) = b(n − 1) + 1
Find the 2-term in the sequence.
Answer:
17
Step-by-step explanation:
Given
[tex]b(1)=16\\ \\b(n)=b(n-1)+1[/tex]
Finding the second term of the sequence means to find [tex]b(2).[/tex] To find [tex]b(2)[/tex] substitute [tex]n=2[/tex] into the second expression:
[tex]b(2)=b(2-1)+1\\ \\b(2)=b(1)+1\\ \\b(2)=16+1\\ \\b(2)=17[/tex]
if two people agree to pay half of the bills and client a pays $488 one month and client b pays $294 how much is owed to client a
Answer:
$97
Step-by-step explanation:
First, what do we know? Client A payed 488, Client B payed 294. They were supposed to pay equal amounts, but clearly that hasn't happened. If they had been fair, they would have divided the total of each bill equally between them. There is a way for us to do this, simply add the two amounts, and then divide by two.
[tex]488+294=782[/tex]
[tex]\frac{782}{2} =391[/tex]
So, both clients A and B were each supposed to pay 391. How much did client A overpay? We can find this number by looking at the difference between (or subtracting) the amount due (391) and the amount paid (488)
[tex]488-391=97[/tex]
We can verify this is correct by adding 97 to 294, to see if client B will now have paid as much as client A.
[tex]294+97=391[/tex],
which is what client B should have payed, and will have payed once he pays client A the 97 dollars owed.
Thus, client A is owed $97.
what is the first step in evaluating {[( − )]} ÷ ?
Answer:
Parenthesis
Step-by-step explanation:
The parenthesis are always the first step in the order of operations.
:)
What is the equation of the graph below?
A graph shows a parabola that opens up with a vertex at three comma negative two.
Answer:
[tex]y=(x-3)^2-2[/tex]
Step-by-step explanation:
Given vertex of parabola [tex](3,-2)[/tex]
Where [tex](h,k)[/tex] is the vertex.
[tex](h,k)=(3,-2)\\h=3\ and\ k=-2[/tex]
Also parabola opens up.
The equation of parabola with vertex [tex](h,k)[/tex]
[tex]y= a(x - h)^2 + k[/tex]
If [tex]a>0[/tex] parabola opens up.
[tex]a<0[/tex] parabola opens down.
As the parabola opens up the value of [tex]a[/tex] will greater than zero.
Plugging vertex of parabola in equation [tex]y= a(x - h)^2 + k[/tex]
[tex]y= a(x - 3)^2 -2[/tex]
Let us plug [tex]a=1[/tex]
The equation will be [tex]y= a(x - 3)^2 -2[/tex]
The prime factorizations of 16 and 24 are shown below.
Prime factorization of 18 2.2.2.2
Prime factorzation of 24 2.2.2.3
Using the p
eaconations what is the greatest common factor of 16 and 247
0 2
2
22 23
Answer:
8.
Step-by-step explanation:
If you mean the GCF of 16 and 24 , from the prime factors, it is 2*2*2
= 8.
Answer:
8
Step-by-step explanation:
Can the function f(x) = x²-4x+4 be factored? If so, write the factored form.
Answer:
f(x) = (x - 2)²
Step-by-step explanation:
f(x) = x² - 4x + 4 is a perfect trinomial.
You know a trinomial is perfect when double the square root of the first term multiplied by the square root of the last term equals the middle term.
As an equation, a trinomial in the form ax² + bx + c = 0:
2√a√c = b is a perfect trinomial.
Perfect trinomial are factored in this form:
(√a ± √c )(√a ± √c ) = (√a ± √c )²
Whether the sign is + or - depends on if the middle term is positive or negative.
In f(x) = x²-4x+4, the middle term is a negative.
The square root of the first term is 1.
The square root of the second term is 2.
The factored form is (x - 2)²
Translate
2/3y − 9 < y + 1 into a sentence.
Nine _____ than two-thirds of number is less than the number _____.
Answer:
Nine less than two-thirds of number is less than the number plus one.
Step-by-step explanation:
I jus got it right on edge.
Nine less than two-thirds of the number is less than the number plus one.
What is Algebra?Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.
The expression is given below.
2/3y − 9 < y + 1
Then complete the sentence.
Then we have
Nine less than two-thirds of the number is less than the number plus one.
More about the Algebra link is given below.
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An object is heated to 100°. It is left to cool in a room that
has a temperature of 30°. After 5 minutes, the temperature
of the object is 80°. What is the temperature of the object
after 20 minutes? When will the temperature of the object
be 35°?
Answer:
Step-by-step explanation:
Use Newton's Law of Cooling for this one. It involves natural logs and being able to solve equations that require natural logs. The formula is as follows:
[tex]T(t)=T_{1}+(T_{0}-T_{1})e^{kt}[/tex] where
T(t) is the temp at time t
T₁ is the enviornmental temp
T₀ is the initial temp
k is the cooling constant which is different for everything, and
t is the time (here, it's in minutes)
If we are looking first for the temp after 20 minutes, we have to solve for the k value. That's what we will do first, given the info that we have:
T(t) = 80
T₁ = 30
T₀ = 100
t = 5
k = ?
Filling in to solve for k:
[tex]80=30+(100-30)e^{5k}[/tex] which simplifies to
[tex]50=70e^{5k}[/tex] Divide both sides by 70 to get
[tex]\frac{50}{70}=e^{5k}[/tex] and take the natural log of both sides:
[tex]ln(\frac{5}{7})=ln(e^{5k})[/tex]
Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared). That gives us:
[tex]-.3364722366=5k[/tex]
Divide both sides by 5 to get that
k = -.0672944473
Now that we have a value for k, we can sub that in to solve for T(20):
[tex]T(20)=30+(100-30)e^{-.0672944473(20)}[/tex] which simplifies to
[tex]T(20)=30+70e^{-1.345888946}[/tex]
On your calculator, raise e to that power and multiply that number by 70:
T(20)= 30 + 70(.260308205) and
T(20) = 30 + 18.22157435 so
T(20) = 48.2°
Now we can use that k value to find out when (time) the temp of the object cools to 35°:
T(t) = 35
T₁ = 30
T₀ = 100
k = -.0672944473
t = ?
[tex]35=30+100-30)e^{-.0672944473t}[/tex] which simplifies to
[tex]5=70e^{-.0672944473t}[/tex]
Now divide both sides by 70 and take the natural log of both sides:
[tex]ln(\frac{5}{70})=ln(e^{-.0672944473t})[/tex] which simplifies to
-2.63905733 = -.0672944473t
Divide to get
t = 39.2 minutes
The temperature of the object after 20 minutes is 48.2° and temperature of body will be 35° after 39.2 minutes.
The formula can be expressed as:
[tex]\[ \frac{dT}{dt} = -k(T - T_a) \][/tex]
where:
[tex]\( T \)[/tex] is the temperature of the object at time [tex]\( t \)[/tex],
[tex]\( T_a \)[/tex] is the ambient temperature,
[tex]\( k \)[/tex] is a positive constant that depends on the characteristics of the object and the environment.
First, we need to find the constant [tex]\( k \)[/tex]. We have the following data:
Initial temperature of the object, [tex]\( T_0 = 100^\circ \)[/tex],
Temperature of the object after 5 minutes, [tex]\( T_1 = 80^\circ \)[/tex],
Ambient temperature, [tex]\( T_a = 30^\circ \)[/tex],
Time [tex]\( t_1 = 5 \)[/tex] minutes.
Using the integrated form of Newton's law of cooling, we have:
[tex]\[ T = T_a + (T_0 - T_a)e^{-kt} \][/tex]
Plugging in the values for [tex]\( T_1 \)[/tex] and [tex]\( t_1 \)[/tex], we get:
[tex]\[ 80 = 30 + (100 - 30)e^{-k \cdot 5} \][/tex]
Solving for [tex]\( k \)[/tex], we find:
[tex]\[ 50 = 70e^{-5k} \][/tex]
[tex]\[ e^{-5k} = \frac{50}{70} \][/tex]
[tex]\[ -5k = \ln\left(\frac{50}{70}\right) \][/tex]
[tex]\[ k = -\frac{1}{5}\ln\left(\frac{50}{70}\right) \][/tex]
Now that we have [tex]\( k \)[/tex], we can find the temperature after 20 minutes [tex]\( t_2 = 20 \)[/tex] minutes:
[tex]\[ T_2 = 30 + (100 - 30)e^{-k \times 20} \][/tex]
Substituting [tex]\( k \)[/tex] into the equation, we get:
[tex]\[ T_2 = 30 + (100 - 30)e^{\frac{1}{5}\ln\left(\frac{50}{70}\right) \times 20} \][/tex]
[tex]\[ T_2 = 30 + 70e^{\frac{20}{5}\ln\left(\frac{50}{70}\right)} \][/tex]
[tex]\[ T_2 = 30 + 70e^{4\ln\left(\frac{50}{70}\right)} \][/tex]
[tex]\[ T_2 = 30 + 70\left(\frac{50}{70}\right)^4 \][/tex]
[tex]\[ T_2 = 48.2^\circ[/tex]
Now, we need to solve for the time [tex]\( t_3 \)[/tex] when the temperature of the object is [tex]\( 35^\circ \)[/tex]:
[tex]\[ 35 = 30 + (100 - 30)e^{-kt_3} \][/tex]
[tex]\[ 5 = 70e^{-kt_3} \][/tex]
[tex]\[ e^{-kt_3} = \frac{5}{70} \][/tex]
[tex]\[ -kt_3 = \ln\left(\frac{5}{70}\right) \][/tex]
[tex]\[ t_3 = -\frac{1}{k}\ln\left(\frac{5}{70}\right) \][/tex]
Substituting [tex]\( k \)[/tex] into the equation, we get:
[tex]\[ t_3 = -\frac{5}{\ln\left(\frac{50}{70}\right)}\ln\left(\frac{5}{70}\right) \][/tex]
[tex]\ln\left(\frac{50}{70}\right)} = -0.336[/tex]
[tex]\ln\left(\frac{5}{70}\right) = -2.639[/tex]
[tex]|\[ t_3 = -\frac{5}{(-0.336)\right)} \times\ -2.639}|[/tex]
[tex]\ t_3 = 39.2 \text{minutes}[/tex]
which of the following expressions is equal to -x^2-4
Answer:
-(x^2+4)
Step-by-step explanation:
Answer:
(-x-2i)(x-2i)
Step-by-step explanation:
simplify sqrt (8^17)
a) 8^8 sqrt(8)
b) 8^7 sqrt(8)
c) 2^3 sqrt (8)
d) 2^5 sqrt (8^2)
Answer:
a) [tex]8^8\sqrt{8}[/tex]
Step-by-step explanation:
Given,
[tex]\sqrt{8^1^7[/tex]
We have to simplify the expression by using "The Law of Indices".
[tex]x^m\times x^n=x^m^+^n[/tex]
So we can rewrite the expression as,
[tex]\sqrt{8^1^7[/tex]=[tex]\sqrt{8^1^+^1^6} =\sqrt{8}\times \sqrt{8^1^6}[/tex]
Now according to law of indices, which is;
[tex](x^m)^n=x^m^n[/tex]
So we can rewrite the expression as
[tex]\sqrt{8}\times \sqrt{8^1^6}=\sqrt{8}\times (8^1^6)^\frac{1}{2} \ \ \ \ Or\ \ \ \sqrt{8}\times 8^{16\times\frac{1}{2}} = 8^8\sqrt{8[/tex]
Hence the final Answer is [tex]8^8\sqrt{8[/tex].
what is the equation for a line that passes through the points (3,1) and (4,-1)
Answer:
y-y/x-x
1--1/3-4
1+1/3-4
2/-1
= -2
then you plug in with any one of the points
y=mx+b
1= -2(3) + b
1 = -6 + b
b = 1+6
b = 7
so the equation is: y = -2x+7
A square tabletop has an area of
(9x2 - 90x+225) cm². The dimensions
of the tabletop have the form cx - di
where cand d are whole numbers. Write
an expression for the perimeter of the
tabletop. Then find the perimeter when
x= 25 centimeters.
s = 3x - 15 is the required expression for perimeter of table top
Perimeter of square tabletop is 240 cm
Solution:
A square tabletop has an area given as:
[tex](9x^2 - 90x+225) cm^2[/tex]
The dimensions of the tabletop have the form cx - di ,where cand d are whole numbers
To find perimeter of tabletop when x = 25 centimeters
Let us first find the length of each side of square
Given area is:
[tex]area = (9x^2 - 90x+225)[/tex]
We know that,
[tex]area = (side)^2 = s^2[/tex]
Therefore,
[tex]s^2 = (9x^2 - 90x+225)\\\\s^2 = (3x - 15)(3x - 15)\\\\s^2 = (3x - 15)^2[/tex]
Taking square root on both sides,
s = 3x - 15
The above expression is the required expression for perimeter of table top
To find perimeter when x = 25 centimeter
The perimeter of square is given as:
[tex]perimeter = 4s[/tex]
perimeter = 4(3x - 15)
Substitute x = 25
perimeter = 4(3(25) - 15)
perimeter = 4(60) = 240
Therefore perimeter of square tabletop is 240 cm
The temperature in degrees Celsius is 273.15 less than the temperature in kelvin. Andrew is conducting a science experiment where the temperature must be kept between 13.5°C and 18.5°C. Andrew wants to know the range of the temperature in kelvin.
Select all of the whole number temperatures, in kelvin, at which Andrew can conduct his experiment.
Answer:
The whole number temperatures, in kelvin, at which Andrew can conduct his experiment are 287, 288, 289,290,291.
Step-by-step explanation:
The temperature in degrees Celsius is 273.13 less than the temperature in kelvin; mathematically this means:
[tex]k=c+273.15[/tex]
Where [tex]k[/tex] is the temperature in kelvin and [tex]c[/tex] is the temperature in Celsius.
From this relationship we convert Andrew's temperature range—
13.5°c to 18.5°c—to kelvin:
[tex]k_1=13.5^oc+273.15=286.65[/tex]
[tex]k_2=18.5^oc+273.15=291.65[/tex]
Thus Andrew can conduct his experiment between 286.65 and 291.65 kelvin, and the whole number temperatures between these extremes are 287, 288, 289,290,291.
Thus the whole number temperatures, in kelvin, at which Andrew can conduct his experiment are 287, 288, 289,290,291.
Final answer:
To convert the temperature range from Celsius to Kelvin, add 273.15 to each end of the Celsius range given. The range for Andrew's experiment in Kelvin is from 287 K to 291 K, inclusive.
Explanation:
When converting temperatures from Celsius to Kelvin, one applies the simple formula: K = °C + 273.15. For Andrew's experiment, the temperature must be kept between 13.5°C and 18.5°C. Converting these to the Kelvin scale, we get:
13.5°C + 273.15 = 286.65 K18.5°C + 273.15 = 291.65 KAndrew can conduct his experiment at whole number Kelvin temperatures that fall within this range. Therefore, the range in Kelvin is from 287 K to 291 K, inclusive.
a line intersects the point (-3,-7) and has a slope of -3.What is the slope intercept equation for this line
Answer:
y = -3x -16
Step-by-step explanation:
For problems like this, I like to start with a variation of the point-slope form of the equation of a line:
y = m(x -h) +k . . . . . for a line with slope m through point (h, k)
For your given values, this is ...
y = -3(x +3) -7
y = -3x -9 -7 . . . . eliminate parentheses; next, combine terms
y = -3x -16
Answer:
-3x-16
Step-by-step explanation:
if x-1/x = 9 find the value of x +1/x
Answer:
[tex]\sqrt{85}[/tex]
Step-by-step explanation:
Given
x - [tex]\frac{1}{x}[/tex] = 9 ← square both sides
(x - [tex]\frac{1}{x}[/tex])² = 9²
x² - 2 + [tex]\frac{1}{x^2}[/tex] = 81 ( add 2 to both sides )
x² + [tex]\frac{1}{x^2}[/tex] = 83
Now
(x + [tex]\frac{1}{x}[/tex])² = x² + [tex]\frac{1}{x^2}[/tex] + 2, thus
x² + [tex]\frac{1}{x^2}[/tex] = 83 + 2 = 85
(x + [tex]\frac{1}{x}[/tex] )²= 85 ( take the square root of both sides)
x + [tex]\frac{1}{x}[/tex] = [tex]\sqrt{85}[/tex]
An escalator lifts people to the second floor of a building, 20 ft
above the first floor. The escalator rises at a 30° angle. To the
nearest foot, how far does a person travel from the bottom to
the top of the escalator?
The person has to travel 40 feet from the bottom to the top of the escalator
Solution:
Given that escalator lifts people to the second floor of a building, 20 ft
above the first floor
The escalator rises at a 30° angle
To find: Distance person travel from the bottom to the top of the escalator
The above scenario forms a right angled triangle where the escalator follows the path of the hypotenuse.
The diagram is attached below
In the right angled triangle ABC,
AC represents Distance person travel from the bottom to the top of the escalator
AB = 20 feet
angle ACB = 30 degree
We know that,
[tex]sin \theta = \frac{opposite}{hypotenuse}[/tex]
[tex]sin 30 = \frac{20}{AC}[/tex]
[tex]\frac{1}{2} = \frac{20}{AC}\\\\AC = 20 \times 2 = 40[/tex]
So the person has to travel 40 feet from the bottom to the top of the escalator
Given: Rays I and M are bisectors of the angels of triangle ABC . X is the intersection of ray’s I and M, line XD is perpendicular to line AC , line XE is perpendicular to line AB, and line XF is perpendicular to line BC. Prove love XD equals line XE ands is also equal to XF
A. ASA
B. AAS
C. SAS
D. SSS
Line XD equals line XE and is also equal to line XF that proved by using AAS postulate of congruence ⇒ B
Step-by-step explanation:
Let us revise the cases of congruence
SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right ΔIn Δ ABC
∵ Ray AL bisects ∠A ⇒ (divides it into two equal angles)
∴ m∠DAX = m∠EAX
∵ Ray BM bisects ∠B ⇒ (divides it into two equal angles)
∴ m∠EBX = m∠FBX
∵ XD ⊥ AC
∴ m∠XDA = 90°
∵ XE ⊥ AB
∴ m∠XEA = 90°
∵ XE ⊥ BC
∴ m∠XFB = 90°
Now lets prove that Δ ADX and ΔAEX are congruent
In Δs ADX and AEX
∵ m∠ADX = m∠AEX ⇒ (their measures are 90°)
∵ m∠DAX = m∠EAX ⇒ proved
∵ AX is a common side in both triangles
- By using the AAS postulate of congruence
∴ Δ ADX ≅ Δ AEX
∴ XD = XE
Let us do the same with Δ BEX and Δ BFX
In Δs BEX and BFX
∵ m∠BEX = m∠BFX ⇒ (their measures are 90°)
∵ m∠EBX = m∠FBX ⇒ proved
∵ BX is a common side in both triangles
- By using the AAS postulate of congruence
∴ Δ BEX ≅ Δ BFX
∴ XE = XF
∵ XE = XD
∵ XE = XF
- If one side is equal two other sides then the two other sides are
equal, that means the three sides are equal
∴ XD = XF
∴ XD = XE = XF
Line XD equals line XE and is also equal to line XF that proved by using AAS postulate of congruence
Learn more:
You can learn more about the congruence in brainly.com/question/6108628
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