Which statements about Earth’s atmosphere are correct? Check all that apply. helpppp

The most abundant gas in the atmosphere is oxygen.
Carbon dioxide in the atmosphere is important for plants.
The troposphere shields Earth from chunks of rock from space.
The stratosphere is located 50 to 80 kilometers from Earth’s surface.
The troposphere gets colder the higher you go.
The ozone in the stratosphere protects us from ultraviolet radiation.
The amount of water vapor in the air is nearly constant.

Awnser: Work

Explanation:  

work is the act of using force

ideal gas equation ...pv=nrT ... n=2 ... r is gas constant T=10^4x1/8.3

Answer :  B

Final answer:

The reason why tides occur every 12 hours and 25 minutes is that the Earth takes 24 hours and 50 minutes to align again with the Moon due to the Moon's orbit, requiring Earth to rotate a bit more each day. Option B is the correct answer.

Explanation:

Tides occur due to the gravitational pull primarily of the Moon and, to a lesser extent, the Sun on Earth's oceans. High tides occur approximately every 12 hours and 25 minutes. This is because the Moon takes 24 hours and 50 minutes to rotate once around the Earth, meaning the Earth has to rotate a little bit more each day to align with the Moon again. Since tides occur twice a day, the extra time divided by two gives us the 12 hours and 25 minutes between successive high tides.

The correct answer to why tides occur every 12 hours and 25 minutes is that the Earth has to rotate an additional distance for a location to re-align with the Moon's position due to the Moon's orbit around Earth. Therefore, option B is correct: It takes 24 hours and 50 minutes for the Earth to make a complete rotation relative to the Moon.

Dan's velocity is calculated by dividing his total displacement of 15 km west by the total time of 45 minutes, which is equivalent to 0.75 hours, hence his velocity is 20 km/h west.

The student asks about Dan's velocity after biking 10 km west and then another 5 km west in a total time of 45 minutes. To find the average velocity, we need to calculate the total displacement over the total time. Since Dan's travel direction is consistent (west), the total displacement is simply the sum of the two distances. So, his displacement is 10 km + 5 km = 15 km west. To get the velocity, we divide the displacement by the time in hours. First, we convert 45 minutes into hours by dividing by 60, which gives us 0.75 hours. Hence, Dan's velocity is 15 km / 0.75 h = 20 km/h west.

Given data

Power = 12 KW ,

mass (m) = 1000 kg ,

Force (F) = 2000 N ,

time (t) = 2.75 s

Determine

              1. Velocity (v) = ?

              2. Work (W) = ?

We know that  Power (P) =  Rate of doing work

                                           = ( Work ÷time) KW

  Also we know that Work = F × displacement

                                   Force = m.a     N

                                 => 2000 = 1000   ×  a

                                 => a = 2 m/s²

                And we know that acceleration (a) = rate of change of velocity

                                                                           = v ÷ t

                                                                       => v = a × t

                                                                              = 2 × 2.75

                                                                             = 5.5 m/s

                    Now determine the Power P = Work done ÷ time

                                                                12 = W ÷ 2.75

                                                                 W= 12 ×2.75

                                                                     =  33 KJ

                                                                     = 33000 J

Answer: 9 m

Explanation:

Work is said to be done when an unbalanced force causes displacement of the body.

Force is the product of mass (m) and acceleration (a).

Work = Force × Displacement

⇒W = F.s = ma.s

It is given that mass of the dresser is, m = 250 kg

work done, W = 126 J

Force acting on the dresser, F = 14 N

we need to find displacement, s

⇒126 J = 14 N × s

⇒ s = 126 J/ 14 N = 9 m

Hence, Laurie is able to move the dresser to about 9 m.

Answer:

9 m

Explanation:

When an object moves or displaces along the direction of the applied force application of force, it is said that work is done.

We know the formula of work:

Work = force x displacement

where force = mass x acceleration

So this formula can be further broken down to :

Work = mass x acceleration x d

Putting in the given values to get:

126 = 14 x d

d = 126/14

d = 9 m

Therefore, the dresser was moved by 9m.

Non-foliated metamorphic rocks are rocks that have been changed by heat and pressure into rocks with a non-layered or banded appearance. Some examples of non-foliated metamorphic rocks include quartzite, marble, amphibolite and hornfels.

Non-foliated metamorphic rocks are rocks that have been changed by heat and pressure into rocks with a non-layered or banded appearance. Some examples of non-foliated metamorphic rocks include quartzite, marble, amphibolite and hornfels.

Answer:

It is the SI unit of force.

Explanation:

The rate of change of momentum in the body is directly proportional to the force applied on the body. It is the second law of motion.

The mathematical form of Newton's second law is

F = m x a

where, m is the mass and a be the acceleration.

If a body of mass 1 kilogram having an acceleration of 1 m/s^2, it means the force applied on the body is 1 newton.

p=m•v=3•15=45 kg•m/s

Answer:

4441 J

Explanation:

The amount of energy needed to change the ethyl alcohol from liquid to gas state is given by

[tex]Q=m \lambda_v[/tex]

where

m = 5.20 g is the mass of the alcohol

[tex]\lambda_v = 854 J/g[/tex] is the latent heat of vaporization of the substance

Substituting the numbers into the formula, we find:

[tex]Q=(5.20 g)(854 J/g)=4,441 J[/tex]

Answer:

4441

Explanation:

Answer:

The pressure on the ground is about 9779.5 Pascal.

The pressure can be reduced by distributing the weight over a larger area using, for example, a thin plate with an area larger than the circular area of the barrel's bottom side.  See more details further below.

Explanation:

Start with the formula for pressure

(pressure P) = (Force F) / (Area A)

In order to determine the pressure the barrel exerts on the floor area, we need the calculate the its weight first

[tex]F_g = m \cdot g[/tex]

where m is the mass of the barrel and g the gravitational acceleration. We can estimate this mass using the volume of a cylinder with radius 30 cm and height 1m, the density of the water, and the assumption that the container mass is negligible:

[tex]V = h\pi r^2=1m \cdot \pi\cdot 0.3^2 m^2\approx 0.283m^3[/tex]

The density of water is 997 kg/m^3, so the mass of the barrel is:

[tex]m = V\cdot \rho = 0.283 m^3 \cdot 997 \frac{kg}{m^3}= 282.151kg[/tex]

and so the weight is

[tex]F_g = 282.151kg\cdot 9.8\frac{m}{s^2}=2765.08N[/tex]

and so the pressure is

[tex]P = \frac{F}{A} = \frac{F}{\pi r^2}= \frac{2765.08N}{\pi \cdot 0.3^2 m^2}\approx 9779.5 Pa[/tex]

This answers the first part of the question.

The second part of the question asks for ways to reduce the above pressure without changing the amount of water. Since the pressure is directly proportional to the weight (determined by the water) and indirectly proportional to the area, changing the area offers itself here. Specifically, we could insert a thin plate (of negligible additional weight) to spread the weight of the barrel over a larger area. Alternatively, the barrel could be reshaped (if this is allowed) into one with a larger diameter (and smaller height), which would achieve a reduction of the pressure.  

Answer B) 3

Explanation:

Answer:

oxbow lake  

Mark as brainliest, please!?

Explanation:

The two types of wave interference are constructive and destructive.

These both describe what happens when waves combine

Constructive interference is when 2 waves combine to form a wave with a larger amplitude, but this is only if both waves are both positive or both negative.

Destructive interference is when the two waves are opposite, one is negative, one is positive. They subtract forming the combined wave that has a lower amplitude.

I hope that helps u out!! :)

1).  This graph reveals exponential decay.  As time goes on (moving left to right across the graph), the maximum excursion of the pendulum's swing becomes smaller and smaller.  On a graph of exponential growth, it would get larger and larger as time goes on.

2).  The first time the pendulum's maximum height dipped below 1 inch was on the 4th swing.

Answer:

4 swings

Explanation:

The gravitational force between two objects depends on both their masses and the distance between them. It is possible for the gravitational force between two like masses to be less than that between unequal masses if the like masses are farther apart.

The question asks whether it's possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 50 kg object and a 5 kg object. The answer to this depends on the distance between the objects, because the gravitational force is directly proportional to the mass of the objects and inversely proportional to the square of the distance between them, according to Newton's Law of Universal Gravitation. So, if the distance between the two 50-kg objects is significantly larger than between the 50 kg and 5 kg objects, then the gravitational force between the 50-kg pair could indeed be less.

Newton's law of Universal Gravitation equation is:

F = G * (m1 * m2) / r²

Where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two masses.

Therefore, if the two 50-kg objects are far apart, the r value in the equation will be large, reducing the value of F, the gravitational force. Meanwhile, if the 50 kg and 5 kg objects are very close, the r value will be smaller, and the force F could be larger despite the smaller mass of one of the objects.

Answer:

4 Ohms

Explanation

(This is seriously not as hard as it looks :)

You only need two types of calculations:

I am attaching a drawing showing the process of stepwise replacement of two resistances at a time (am using rectangles to represent a resistance). The left-most image shows the starting point, just a little bit "warped" to see it better. The two resistances (6 Ohm next to each other) are in parallel and are replaced by a single resistance (3 Ohm, see formula above) in the top middle image. Next, the two resistances (9 and 3 Ohm) are nicely in series, so they can be replaced by their sum, which is what happened going to the top right image. Finally we have two resistances in parallel and they can be replaced by a single, final, resistance as shown in the bottom right image. That (4 Ohms) is the equivalent resistance of the original circuit.

Using these two transformations you will be able to solve step by step any  problem like this, no matter how complex.  

Answer ; 2.5  (C)

From the given figure it is cleat that the wave length (λ) = 2.5 cm

It is a "measure of distance between two identical crests  or identical troughs in a wave.

In the figure, high points are crests and low points are troughs.

Answer:

8.2 m/s

Explanation:

The horizontal component of the velocity is given by:

[tex]v_x = v cos \theta[/tex]

where

v = 10 m/s is the magnitude of the velocity

[tex]\theta=35^{\circ}[/tex] is the angle at which the ball has been thrown, with respect to the horizontal

Substituting the values into the equation, we get

[tex]v_x=(10 m/s)(cos 35^{\circ})=8.2 m/s[/tex]

Final answer:

The horizontal component of velocity of a ball thrown at 35° and 10 m/s is 8.2 m/s.

The horizontal component of the velocity of a ball thrown at an angle of 35° and a speed of 10 m/s can be found using trigonometry. The horizontal component is given by the formula:

Horizontal velocity (Vx) = Initial velocity (V0) * cos(angle)

Substituting the given values:

Vx = 10 m/s * cos(35°)

Vx ≈ 10 m/s * 0.819

Vx ≈ 8.19 m/s

Therefore, the horizontal component of velocity is approximately 8.2 m/s.

F=m•a=1000•3=3000 N=3kN

The force of impact during the collision of a stunt car with a tree, given a mass of 1000 kg and an acceleration of 3 m/s^2, is 3000 Newtons (N), calculated using Newton's second law of motion.

To find the force of impact of the collision on a stunt car that crashes into a tree, we can use Newton's second law of motion, which states that the force acting on an object equals its mass times its acceleration (F = ma). In this case, the mass (m) of the car is given as 1000 kg, and the acceleration (a) during the collision is mistakenly referred to as '3 m', which seems like a typo for '3 m/s2'. Assuming the acceleration is indeed 3 m/s2, the calculation would be:

F = 1000 kg × 3 m/s2 = 3000 N.

Hence, the force of impact during the collision would be 3000 Newtons (N). This calculation essentially applies Newton's second law to determine the net force acting on the car due to its acceleration towards the obstacle (in this case, a tree), providing a fundamental understanding of the dynamics involved in car crashes.

Because the paint over the iron of the car helps to keep the iron from coming in contact with air, and that's why cars in junkyards are usually rusted, because the paint is chipped or gone.

Iron rusts because it can be contacted by water-or the moisture in the air- and the metal takes the oxygen from the water forming iron oxide-rust. Paint or plating (like chrome plating) prevents the H2O molecules from reaching the surface of the metal so it can't get the oxygen.

Answer:

The kinetic energy is 16 Joules.

Explanation:

Use the formula for the kinetic energy:

[tex]E_k=\frac{1}{2}mv^2 = \frac{1}{2}2.0kg\cdot 4.0^2 \frac{m^2}{s^2}=16J[/tex]

A: w=mg    w=13(9.8)    w= 127.4

B: 13kg

C: w=mg    w=13(1.6)    w= 20.8

D: The force of gravity is less on the moon than on earth therefore making the dog weigh less.

The dog weighs 127.4N on Earth and 20.8N on the Moon while its mass remains a constant 13kg in both places. The difference in weight is because of the difference in gravitational pull, with Earth having a larger 'g' value due to its greater mass than the Moon.

a. The dog's weight on Earth can be calculated by the formula w = mg, where m is mass and g is gravity. Thus, it weighs 13kg × 9.8m/s² = 127.4N on Earth.

b. The mass of an object is constant, regardless of location. So, the mass of the dog on the Moon is still 13kg.

c. The dog's weight on the moon can be calculated with the same formula, but using the Moon’s gravity. Thus, it weighs 13kg × 1.6m/s² = 20.8N on the Moon.

d. The acceleration due to gravity, 'g', is different for the Earth and the Moon because it depends on the size and mass of the celestial body. The Earth has a much greater mass than the Moon, resulting in a greater gravitational pull and hence a larger value for 'g'.

https://brainly.com/question/2124323

#SPJ3

B

Let me know if I'm correct

I'm pretty sure it's B

Answer:

Answer:

0.49

Explanation:

There are two forces acting on the block in the direction parallel to the surface of the inclined plane:

- The component of the weight of the block parallel to the incline:

[tex]mg \sin \theta[/tex]

where m = 8.0 kg is the mass of the block, g=9.8 m/s^2 and [tex]\theta=31^{\circ}[/tex] is the angle of the ramp

- The frictional force, given by:

[tex]\mu mg cos \theta[/tex]

where [tex]\mu[/tex] is the coefficient of friction.

The two forces act in opposite direction, and according to Newton's second law, their resultant is equal to the product of the mass of the block (m) and its acceleration (a):

[tex]mg sin \theta - \mu mg cos \theta = ma[/tex]

Since we knw that [tex]a=0.9 m/s^2[/tex], we can re-arrange the equation to find the coefficient of friction:

[tex]\mu = \frac{g sin \theta -a}{ g cos \theta}=\frac{(9.8 m/s^2)(sin 31^{\circ})-0.9 m/s^2}{(9.8 m/s^2)(cos 31^{\circ})}=0.49[/tex]

C. Elastic collision. A perfect elastic collision is on that doesn't result in any k.e loss during the collision.

Elastic collision is the correct answer C.

Final answer:

A steel needle or paper clip can float on the surface of water even though steel is denser than water. This is due to surface tension, which creates an upward force that counteracts the force of gravity.

Explanation:

Although steel is denser than water, a steel needle or paper clip placed carefully lengthwise on the surface of still water can be made to float. This is possible because of a phenomenon called surface tension. Surface tension is the force that acts on the surface of a liquid and tends to minimize its area.

When a small object like a steel needle or paper clip is placed on the surface of water, the surface tension of the water molecules pulls on the object from all sides, creating an upward force that counteracts the force of gravity. As a result, the object floats on the surface of the water.

This demonstrates that density alone does not determine whether an object will float or sink. Other factors, such as surface tension, can play a significant role in determining whether an object will float or sink.

Katlyn pours hot water into the flavored gelatin powder and stirs.

Gelatin powder is the solute. Water is the solvent.  (D)

The correct answer is D. Gelatin powder is the solute and water is the solvent in the gelatin dessert that Katlyn makes. Water is the component in the larger amount and is responsible for dissolving the gelatin powder.

When Katlyn makes a gelatin dessert, she is creating a solution by mixing two substances. In this context, the gelatin powder is the solute, which is the substance that gets dissolved, and the hot water is the solvent, which is the substance that does the dissolving. Therefore, the correct answer to the question is D. Gelatin powder is the solute. Water is the solvent.

Solvents are typically the component of a solution that is present in the larger amount and usually determines the phase (solid, liquid, or gas) of the solution. In Katlyn's case, the solvent - water - is a liquid, which then forms a gel upon cooling, as the dispersed gelatin molecules create a three-dimensional network in the cooled dessert.