Answer:
A, B and C
Step-by-step explanation:
Jack purchases 12 gallons of gas on Monday. He uses 2/3 of the amount purchased commuting to and from work during the week and an additional 2 gallons running errands. How many gallons of gas does john use from work and errands?
Answer: Using operations with fractions, John uses 10 gallons from work and errands.
Solution:
Jack purchases 12 gallons of gas on Monday.
He uses 2/3 of the amount purchased commuting to and from work during the week:
(2/3)(12)=(2/3)(12/1)=(2*12)/(3*1)=24/3=8
Then John uses 8 gallons commuting to and from work during the week.
And an additional 2 gallons running errands.
John uses in total from work and errands= 8 gallons+2 gallons
John uses in total from work and errands= 10 gallons
Which table shows a linear function?
Thank you!
Which trigonometric function would be used to find the length of this triangle's hypotenuse?
The cosine function is used to find the length of the hypotenuse of a triangle by utilizing the Pythagorean theorem.
The trigonometric function used to find the length of the hypotenuse of a triangle is the cosine function. In a right triangle, the cosine function is defined as the ratio between the length of the adjacent side to the length of the hypotenuse.
To find the length of the hypotenuse, you can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the hypotenuse.
For example, if the lengths of the shorter sides are 9 blocks and 5 blocks, then the length of the hypotenuse would be √(9² + 5²) = √(81 + 25) = √106 = 10.3 blocks.
Simplify.
(-5.12) - (-4.7) + (7.021)
6.79
6.601
-2.799
an artist is cutting pieces of ribbon to use in a project. Each piece he cuts measures 7/8 inch. The aritst cuts off 5 pieces. How many total inches of ribbon has he cut off?
The artist has cut off a total of 4 and 3/8 inches of ribbon for his project by multiplying the length of one piece (7/8 inch) by the total number of pieces cut (5).
Explanation:The question involves a straightforward arithmetic operation of multiplication. Each piece of ribbon the artist cuts measures 7/8 inch, and he cuts off 5 pieces in total. To find the total length of ribbon cut off, we multiply the length of one piece (7/8 inch) by the number of pieces cut (5).
Calculation: \(\frac{7}{8} \text{ inch} \times 5 = \frac{35}{8} \text{ inches} = 4 \frac{3}{8} \text{ inches}\)
Therefore, the artist has cut off a total of 4 and 3/8 inches of ribbon for his project. This example demonstrates a practical application of multiplication in a real-world context, specifically within arts and crafts projects.
Which is an equivalent equation solved for y ?
Answer:
4th Option is correct.
Step-by-step explanation:
Given:
x and y are the half length of the largest and smallest diameter of the ellipse.
Area of the Ellipse , a = πxy
To find: Equivalent Equation for y.
Consider,
a = πxy
πxy = a
(πx)y = a
transpose πx to RHS,
[tex]y=\frac{a}{\pi x}[/tex]
y = a ÷ ( πx )
Therefore, 4th Option is correct.
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Select each correct answer.
(0, −3)
(2, −2)
(1, −4)
(6, 1)
(−3, 0)
we have
[tex]2y-x\leq -6[/tex]
we know that
if a ordered pair is a solution of the inequality
then
the ordered pair must satisfy the inequality
we will proceed to verify each case to determine the solution of the problem
case A) [tex](0,-3)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-3)-0\leq -6[/tex]
[tex]-6\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](0,-3)[/tex] is a solution of the inequality
case B) [tex](2,-2)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-2)-2\leq -6[/tex]
[tex]-6\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](2,-2)[/tex] is a solution of the inequality
case C) [tex](1,-4)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(-4)-1\leq -6[/tex]
[tex]-9\leq -6[/tex] -------> Is True
therefore
the ordered pair [tex](1,-4)[/tex] is a solution of the inequality
case D) [tex](6,1)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(1)-6\leq -6[/tex]
[tex]-4\leq -6[/tex] -------> Is False
therefore
the ordered pair [tex](6,1)[/tex] is not a solution of the inequality
case E) [tex](-3,0)[/tex]
Substitute the value of x and y in the inequality, if the inequality is true, then the ordered pair is a solution of the inequality
so
[tex]2*(0)-(-3)\leq -6[/tex]
[tex]3\leq -6[/tex] -------> Is False
therefore
the ordered pair [tex](-3,0)[/tex] is not a solution of the inequality
therefore
the answer is
[tex](0,-3)[/tex]
[tex](2,-2)[/tex]
[tex](1,-4)[/tex]
Write all the factors of 8
what are the domain range and asymptote of h(x)=(1.4)^x+5
domain: {x | x is a real number}; range: {y | y > 5}; asymptote: y = 5
Change each fraction to a decimal. If the division doesn’t end, round your answer to the nearest hundredth. a. 3⁄4 b. 7⁄16 d. 3⁄5 e. 7⁄40 f. 51⁄20
Answer:
the other person forgot to answer c
Step-by-step explanation:
a 0.75
b 0.44
c 0.6
d 0.6
e 0.18
Solve for b in the formula 3 a + 2 b = c .
A. b=c-3a
B. b=c-2/3a
C. b=c-3a/2
D. b=2c/3a
The value of b from the given equation is (c-3a)/2. Therefore, option C is the correct answer.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
The given equation is 3a+2b=c.
Now, 2b=c-3a
b= (c-3a)/2
The value of b from the given equation is (c-3a)/2. Therefore, option C is the correct answer.
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Which of the following statements is true?
All trapezoids are parallelograms.
All parallelograms are trapezoids.
All rectangles are squares.
All rhombuses are rectangles.
Answer:
The answer is B. All parallelograms are trapezoids.
Step-by-step explanation:
The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure. That makes the opposite of facing sides are parallel to each other. The the definition of trapezoid is a convex quadrilateral with at least one pair of parallel sides. Therefore, all parallelograms are trapezoids.
The true statement among the given options is, B. All parallelograms are trapezoids.
A trapezoid is a quadrilateral with at least one pair of parallel sides, but it doesn't require all sides to be parallel. Therefore, not all trapezoids are parallelograms. (Statement A is false)
A parallelogram is a quadrilateral with both pairs of opposite sides parallel. Every trapezoid has at least one pair of parallel sides, so it can be considered a special case of a parallelogram. Therefore, all trapezoids are parallelograms. (Statement B is true)
A rectangle is a quadrilateral with all four angles equal to 90 degrees. It has opposite sides that are parallel and equal in length. A square is a special type of rectangle with all sides of equal length. However, not all rectangles have all sides of equal length, so statement C is false.
A rhombus is a quadrilateral with all four sides of equal length. It has opposite sides that are parallel, making it a parallelogram. Since a rectangle is a parallelogram with right angles, and a rhombus is a parallelogram with equal sides. Therefore, statement D is also false.
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There is an average of 3.5×10−2 kilograms of dissolved salt in each liter of seawater. The Pacific Ocean contains approximately 6.6×1020 liters of seawater. About how many kilograms of dissolved salt are in the Pacific Ocean? Enter your answer, in scientific notation, in the boxes. ×× 10 kg
Quick Answer:
2.31 x 10^19 kg
Help with this question !
Let f(x)equals=33xminus−1, h(x)equals=startfraction 7 over x plus 5 endfraction 7 x+5 . find (hcircle◦f)(66).
Solve for x.
89(54x−36)+2=−34(−40+16x)+90x
Which of the following is an example of gameplay in a video game
A: the art of a game
B: the player interacting with the game world and game mechanics
C: the personalities of all the characters
D:all of the above
Answer:
B: the player interacting with the game world and game mechanics
Step-by-step explanation:
Front-row tickets for a concert cost $60. After every 5 rows, the ticket price goes down by $5. What is the total amount of money generated by a full house? Info: There are 20 rows that increase by 3 seats each time starting with 18.
What is 55 x 10 to the power of 4 in scientific notation
Leanne is trying to choose between two party dresses that originally cost $120 one dress is on 1/4 off and the $40 what is the price of less expensive dress
$8 euros were worth $9 and $24 euros were worth $27 write an equation of the form y=kx to show the relationship between the number of euros and the value in dollars.
A street that is 270m long is covered in snow. city workers are using a snowplow to clear the street. a tire on the snowplow has to turn 45 times in traveling the length of the street. what is the diameter of the tire?
How many possible outcomes, including both main effects and interaction effects, are possible for a factorial design with three independent variables?
Hiram sells kites to various corporations. To maintain his business, he must sell an average of 50 kites per month. After 5 months, Hiram has sold 30, 42, 77, 90, and 52 kites in each of the 5 months. How many kites would Hiram have to sell in the 6th month for him to meet his average of 50 kites?
In how many ways can i arrange the 6 letters a, b, c, d, e, f?
Nine friends will equally share 12 glasses of punch how many glasses of punch will each friend get A.3/4 B.1/3 C.4/3 D.3
7(2+5v)=3v+14 can anyone help???
The solution to the equation is v = 0.
We have,
To solve the equation 7(2 + 5v) = 3v + 14, we can simplify and isolate the variable v.
Expanding the left side of the equation:
7(2 + 5v) = 14 + 35v
Now we have:
14 + 35v = 3v + 14
Next, we can combine like terms:
35v - 3v = 14 - 14
32v = 0
To solve for v, we divide both sides of the equation by 32:
v = 0/32
v = 0
Therefore,
The solution to the equation is v = 0.
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Solve an equation to answer the question
Jose bought 2 movie tickets and a box of popcorn. The popcorn cost $6, and he spent a total of $24. How much did each ticket cost? Use m to represent the cost of each movie ticket.
A. 6m+2=24 m=3 ; each ticket cost $3.
B. 2m+6=24 m=9 ; each ticket cost $9.
C. 2m+6=24 m=15 ; each ticket cost $15.
D. 6m+2=24 m=4 ; each ticket cost $4.
Answer:
B) 2m+6=24 m=9 ; each ticket cost $9.
Step-by-step explanation:
Given: Jose bought 2 movie tickets and a box of popcorn. The popcorn cost $6, and he spent a total of $24.
Here "m" represents the cost of each movie ticket.
Now let's form an equation.
2m + box of popcorn = $24
Box of popcorn cost $6
So,
2m + 6 = 24
Now, we have to solve for m.
Subtract 6 from both sides, we get
2m + 6 - 6 = 24 - 6
2m = 18
Dividing both sides by 2, we get
2m/2 = 18/2
m = 9
So, the cost of movie ticket is $9 each.
Therefore, the answer is B) 2m+6=24 m=9 ; each ticket cost $9.
What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to finish.
Use the straightedge to draw FD ¯ ¯ ¯ ¯ ¯ and FE ¯ ¯ ¯ ¯ ¯ .
Keeping the same compass width, place the compass on point E and draw an arc in the interior of ∠DBE to intersect the previously drawn arc. Label the point of intersection as point F.
Use a straightedge to draw line t and label a point on the line as point B.
Without changing the compass width, place the compass point on point D and draw an arc in the interior of ∠DBE .
With the compass open to the desired side length of the square, place the compass point on point B and draw an arc on line t and an arc on BC ← → . Label the points of intersection as points D and E.
Construct a line perpendicular to line t through point B. Label a point on this line as point C.
Answer:
See explanation below.
Step-by-step explanation:
To construct a square using only a compass and a straightedge first we need to:
Use a straightedge to draw a line (we will name the line t) and label a point on the line as point B.Then, you will draw a perpendicular line to the segment that passes through point B ( To remember how to draw a perpendicular line through a segment see the note at the end of the explanation), label a point on this line as point C.With the compass open to the desired side length of the square (meaning the measure of the side of the square you need), place the compass point on point B and draw an arc on line t and an arc on BC. Label the points of intersection as points D and E.Without changing the compass width, place the compass point on point D and draw an arc in the interior of ∠DBE .Keeping the same compass width, place the compass on point E and draw an arc in the interior of ∠DBE to intersect the previously drawn arc. Label the point of intersection as point F.Finally, use the straightedge to draw FD and FE (the other two sides of the square are DB and DE)*Note: To draw a perpendicular line through a segment follow the next steps:
Place the compass point at point B Draw an arc of ANY size that crosses line t twice (one to the left of point B and one to the right)Stretch the compass larger than you first did and place the point at one of the points where the previous arc crossed the line. Draw an arc above the line.Using the same width you used on step 3, place the compass point at the other point in the line.From there draw an arc above the line that crosses the other arc from step 4.Using your straightedge draw a line from the intersection of both arcs and point B and this line will be perpendicular to the line and it will pass through point B.HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Drag an answer to each box to complete this paragraph proof.
Given: ∠PQR and ∠RQS are supplementary angles and m∠PQR=115°
Prove: ∠RQS is an acute angle.
It is given that ∠PQR and ∠RQS are supplementary angles. So, m∠PQR+m∠RQS=180° using the ________ . It is also given that m∠PQR=115° . Using the substitution property of equality, ________ + m∠RQS=180° . Using the subtraction property of equality, m∠PQR=65° . Therefore, ∠RQS is an acute angle by ________ .
A. definition of complementary angles
B. definition of supplementary angles
C. definition of acute angle
D. definition of obtuse angle
E. 180°
F. 115°
Image uploaded below:
V V V
Answer: The correct options for blank 1,2 and 3 are B, F and C respectively.
Explanation:
It is given that the ∠PQR and ∠RQS are supplementary angles and ∠PQR=115°.
The two angles are called supplementary angles if they are lies on the same arc of a straight line and their sum is 180 degree.
Since it is given that ∠PQR and ∠RQS are supplementary angles, so by the definition of supplementary angles we can say that their sum is 180 degree.
[tex]\angle PQR+\angle RQS=180^{\circ}[/tex] .... (1)
Therefore, the correct option for first blank is option B.
It is given that ∠PQR=115°.
Using the substitution property of equality, the equation (1) can be written as,
[tex]115^{\circ}+\angle RQS=180^{\circ}[/tex]
Therefore, the correct option for second blank is option F.
Using the subtraction property of equality, ∠PQR=65° .
An angle less that 90 degree is called an acute angle and the an angle more than 90 degree but not more that 180 degree is called an obtuse angle.
Since 65 is less than 90, so by the definition of acute angle the ∠RQS is an acute angle.
Therefore, the correct option for third blank is option C.