Answer: Answers 2, 3, and 5
Step-by-step explanation:
In finding the volume of a prism, you can use the formula V = Bh
This happens to be one of the answers here.
Before you get to V = Bh, however, you have to find the area of the base (B).
For this you can use the are of a rectangle, or A = bh.
This is also one of the answers.
(Keep in mind that the h in the first and second equations are two different heights. The height in the volume equation refers to the height of the prism whereas the height in the area equation refers to the base's height)
Plugging in the numbers:
A = bh = 9.5 × 24 = 228
V = Bh = 228 × 6 = 1368
This is the last answer.
Answer:
1, 3, 4, 5
Step-by-step explanation:
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors labeled 3, 4, 5, and 6. Spinners are spun once. How many outcomes do not show an even number on the first spinner and show a 6 on the second spinner?
Answer:
2 outcomes
Step-by-step explanation:
Let's list count all the possible outcomes:
(1,3) (1,4) (1,5) (1,6)
(2,3) (2,4) (2,5) (2,6)
(3,3) (3,4) (3,5) (3,6)
As expected, there are 12 (3x4) possible outcomes.
How many outcomes do not show an even number (so showing 1 or 3) on the first spinner and show a 6 on the second spinner?
There are two cases where 6 is on the second spinner and NOT an even number on the first spinner: (1,6) and (3,6)
The Roman cubitus is an ancient unit of measure equivalent to about 0.445 m. Convert the 1.95-m height of a basketball forward to cubiti. HINT Use the conversion factor 1 cubitus = 0.445 m. In the conversion factor 1 cubitus = 0.445 m, the term "1 cubitus" is considered to be exact so that it never limits the number of significant figures reported in the answer. cubiti
Answer:
4.382 cubiti
Step-by-step explanation:
That's a simple exercise of cross-multiplication:
[tex]\frac{x}{1.95} = \frac{1}{0.445}[/tex]
x being the measure in cubitus we're looking for. We can isolate it:
x = (1.95 m * 1 ) / (0.445 m/cubitus) = 4.382 cubiti
1.95 m = 4.382 cubiti
Which totally makes sense... since a cubitus is roughly half a meter long... and the basketball is 2 meters high... so there are roughly 4 cubiti in 2 meters.
The height of the basketball forward in cubiti is approximately 4.38.
To convert the height from meters to cubiti, we use the conversion factor provided in the question:
1 cubitus = 0.445 m
Given the height of the basketball forward is 1.95 m, we divide this value by the conversion factor to find the height in cubiti:
Height in cubiti = Height in meters / Conversion factor
Height in cubiti = 1.95 m / 0.445 m/cubitus
Now, we perform the division:
Height in cubiti ≈ 4.38 cubiti
Since the value of 1 cubitus is considered to be exact, the number of significant figures in the answer is determined by the height in meters, which is 1.95 m (three significant figures). Therefore, the answer is rounded to three significant figures as well.
One number is 3 less than twice another. If their sum is 39 find the numbers
Which of the following systems of equations represents the word problem?
Answer:
The numbers are 14 and 25
Step-by-step explanation:
Let one of the numbers be x. The second number we are told is 3 less than twice x. The second number will thus be;
2x - 3
The sum of the numbers is thus;
x + (2x - 3) = 3x - 3
But the sum of the numbers is said to be 39, therefore;
3x - 3 = 39
3x = 42
x = 14
The second number is thus;
2(14) - 3 = 28 - 3 = 25
The set of equations representing the word problem is ( x + y = 39 ) and ( x = 2y - 3 )
The correct answer is option
a).( x + y = 39 ) and ( x = 2y - 3 )
To solve this problem, let's first understand the given information.
Let's denote x as the number of one type of fruit (let's say apples) and y as the number of another type of fruit (let's say oranges). The problem states two conditions:
1. The total number of fruits is 39.
2. The number of apples (x) is either three less than twice the number of oranges (y) or it's the same as three more than twice the number of oranges.
Let's represent these conditions mathematically:
1. x + y = 39 (Equation 1)
2. x = 2y - 3 or x = 2y + 3 (Equation 2)
Now, let's compare these equations with the options provided:
a) ( x + y = 39 ) and ( x = 2y - 3 )
b) ( x - y = 39 ) and ( x = 2y - 3 )
c) ( x + y = 39 ) and ( x = 3y - 2 )
d) ( x - y = 39 ) and ( x = 3y - 2 )
Comparing Equation 1 with the options, we see that options a) and c) match.
Comparing Equation 2 with the options, we see that options a) and b) match.
Therefore, the correct system of equations is option a):
(x + y = 39) and (x = 2y - 3).
1. The first equation represents the total number of fruits, which should be 39. We add the number of apples (x) and oranges (y) to get 39.
2. The second equation represents the relationship between the number of apples and oranges. The number of apples is three less than twice the number of oranges. So, we set up the equation x = 2y - 3.
Thus, the correct answer is option a)( x + y = 39 ) and ( x = 2y - 3 )
Complete question
One number is 3 less than twice another. If their sum is 39, find the numbers?
Which of the following systems of equations represents the word problem?
a) ( x + y = 39 ) and ( x = 2y - 3 )
b) ( x - y = 39 ) and ( x = 2y - 3 )
c) ( x + y = 39 ) and ( x = 3y - 2 )
d) ( x - y = 39 ) and ( x = 3y - 2 )
A medical equipment industry manufactures X-ray machines. The unit cost c
(the cost in dollars to make each X-ray machine) depends on the number of machines made. If x machines are made, then the unit cost is given by the function
c(x)=0.6x^2-108x+19,222. What is the minimum unit cost?
Do not round your answer
Answer:
Minimum Unit Cost = $14,362
Step-by-step explanation:
The standard form of a quadratic is given by:
ax^2 + bx + c
So for our function, we can say,
a = 0.6
b = -108
c = 19,222
We can find the vertex (x-coordinate where minimum value occurs) by the formula -b/2a
So,
-(-108)/2(0.6) = 108/1.2 = 90
Plugging this value into original function would give us the minimum (unit cost):
[tex]c(x)=0.6x^2-108x+19,222\\c(90)=0.6(90)^2-108(90)+19,222\\=14,362[/tex]
Answer:
The minimum unit cost is 14,362
Step-by-step explanation:
The minimum unit cost is given by a quadratic equation. Therefore the minimum value is at its vertex
For a quadratic function of the form
[tex]ax ^ 2 + bx + c[/tex]
the x coordinate of the vertex is
[tex]x=-\frac{b}{2a}[/tex]
In this case the equation is: [tex]c(x) = 0.6x^2-108x+19,222[/tex]
Then
[tex]a= 0.6\\b=-108\\c=19,222[/tex]
Therefore the x coordinate of the vertex is:
[tex]x=-\frac{(-108)}{2(0.6)}[/tex]
[tex]x=90[/tex]
Finally the minimum unit cost is:
[tex]c(90)=0.6(90)^2-108(90)+19,222\\\\c(90)=14,362[/tex]
Model each problem as an equation, and then match to its solution.
Answer:
Part 1) The larger integer is 11
Part 2) The denominator is 5
Part 3) The positive integer is 4
The graph in the attached figure
Step-by-step explanation:
Part 1)
Let
x----> the smaller positive integer
y-----> the larger positive integer
we know that
[tex]x^{2} +y^{2} =185[/tex] -----> equation A
[tex]x=y-3[/tex] -----> equation B
substitute equation B in equation A and solve for y
[tex](y-3)^{2} +y^{2} =185\\ \\y^{2} -6y+9+y^{2}=185\\ \\2y^{2}-6y-176=0[/tex]
using a graphing calculator-----> solve the quadratic equation
The solution is y=11
[tex]x=11-3=8[/tex]
Part 2)
Let
x----> the numerator of the fraction
y-----> the denominator of the fraction
we know that
[tex]x=2y+1[/tex] ----> equation A
[tex]\frac{x+4}{y+4}=\frac{5}{3}[/tex] ----> equation B
substitute equation A in equation B and solve for y
[tex]\frac{2y+1+4}{y+4}=\frac{5}{3}[/tex]
[tex]\frac{2y+5}{y+4}=\frac{5}{3}\\ \\6y+15=5y+20\\ \\6y-5y=20-15\\ \\y=5[/tex]
[tex]x=2(5)+1=11[/tex]
Part 3)
Let
x----> the positive integer
we know that
[tex]x-\frac{1}{x}=\frac{15}{4}[/tex]
solve for x
[tex]x-\frac{1}{x}=\frac{15}{4}\\ \\4x^{2}-4=15x\\ \\4x^{2}-15x-4=0[/tex]
using a graphing calculator-----> solve the quadratic equation
The solution is x=4
suppose that 10 is less than square rooot of n which is less than 11 what is the possible value for n
Answer:
The correct answer is that a possible value for n could be all numbers from 101 to 120.
Step-by-step explanation:
Ok, to solve this problem:
You have that: [tex]10 <\sqrt{n} <11[/tex]
Then, applying the properties of inequations, the power is raised by 2 on both sides of the inequation:
[tex](10)^{2} <(\sqrt{n} )^{2} <(11)^{2}[/tex]
[tex]100<n<121[/tex]
Then, a possible value for n could be all numbers from 101 to 120.
PLEASE HURRY!!! TIMED!!! Will give brainliest!! 70 POINTS!!!
Rashid bought a piece of wood with a length less than 5 feet. The variable w represents the length. The inequality w<5 describes the length of the piece of wood. Which number could be a length of the piece of wood?
4.5
6
11.3
13
Answer: First option.
Step-by-step explanation:
You know that the meaning of the symbol of the inequality "<" is: Less than.
So, you can check each option to find the number that could be a length of this piece of wood.
Given [tex]w<5[/tex], you can substitute each number given in the options into this inequality. Then:
[tex]1)\ w<5\\\\4.5<5\ (This\ is\ true)[/tex]
[tex]2)\ w<5\\\\6<5 (This\ is\ not\ true)[/tex]
[tex]3)\ w<5\\\\11.3<5\ (This\ is\ not\ true)[/tex]
[tex]4)\ w<5\\\\13<5\ (This\ is\ not\ true)[/tex]
Therefore, a lenght of the piece of wood could be 4.5
select the graph of the solution set that would represent the following expression. (x-2)=5(x+1)
Answer:
Find the attached
Step-by-step explanation:
We have been given the following expression;
(x-2)=5(x+1)
We are required to determine the graph of the solution set. To do this we formulate the following set of equations;
y = x - 2
y = 5(x+1)
We then graph these two equations on the same cartesian plane. The solution will be the point where these two graphs intersect.
Find the attachment below;
Answer:
{-1.75}
Step-by-step explanation:
The given equation is
[tex]x-2=5(x+1)[/tex]
Let as assume f(x) be left hand side and g(x) be the right hand side.
[tex]f(x)=x-2[/tex]
[tex]g(x)=5(x+1)[/tex]
The solution set of given equation is the intersection point of f(x) and g(x).
Table of values are:
For f(x) For g(x)
x f(x) x g(x)
0 -2 0 5
2 0 -1 0
Plot these corresponding ordered pairs on a coordinate plan and connect them by straight lines
From the below graph it is clear that the intersection point of f(x) and g(x) is (-1.75,-3.75).
Therefore, the solution set of given equation is {-1.75}.
A dead body was found within a closed room of a house where the temperature was a constant 70° F. At the time of discovery the core temperature of the body was determined to be 80° F. One hour later a second measurement showed that the core temperature of the body was 75° F. Assume that the time of death corresponds to t = 0 and that the core temperature at that time was 98.6° F. Determine how many hours elapsed before the body was found. [Hint: Let t1 > 0 denote the time that the body was discovered.] (Round your answer to one decimal place.)
Answer:
1.6 hours
Step-by-step explanation:
I started off with T(t)=70+Ce^kt
then since the initial temp was 98.6 I did T(0)=98.6=70+C so C=28.6
Then T(1) = 80 = 28.6e^k + 70
k = ln (10/28.6)
Then plugged that into
T(t)=85=28.6e^ln(10/28.6)t + 70
and got t=.61
The answer says it is about 1.6 hours.
The time that has elapsed before the body was found is 1.5 hour
The given parameters;
when time, t = 0, temperature = 98.6 ⁰Fwhen time, t = 1, temperature = 75⁰when time, t = t, temperature = 80⁰Apply the Newton's method of cooling equation;
[tex]T(t) = T_{s} + (T_{o} - T_{s})e^{kt}\\\\T(t) = 70 + (98.6 - 70)e^{kt}\\\\T(t) = 70 + 28.6e^{kt}[/tex]
At the time of discovery, we have the following equation,
[tex]T_{t} = 70 + 28.6e^{kt}\\\\80 = 70 + 28.6e^{kt}\\\\10 = 28.6k^{kt}[/tex]
1 hour later, t + 1, we have the second equation;
[tex]75 = 70 + 28.6e^{kt} \\\\5 = 28.6e^{k(t+ 1)} \\\\5 = 28.6e^{kt + k} ---- (2)[/tex]
divide equation 1 by equation 2;
[tex]\frac{10}{5} = \frac{28.6e^{kt}}{28.6 e^{kt + k}} \\\\2 = e^{kt - kt - k}\\\\2 = e^{-k}\\\\-k = ln(2)\\\\k = -0.693[/tex]
The time when he dead body was discovered is calculated as;
[tex]10 = 28.6e^{kt}\\\\10= 28.6e^{-0.693t}\\\\e^{-0.693t} = \frac{10}{28.6} \\\\-0.693 t = ln(\frac{10}{28.6} )\\\\-0.693t = -1.05\\\\t = \frac{1.05}{0.693} \\\\t = 1.515 \ \\\\t \approx 1.5 \ hr[/tex]
Thus, the time that has elapsed before the body was found is 1.5 hour
Learn more here: https://brainly.com/question/15824468
Show all work to identify the discontinuity and zero of this function. 3x/x^2-9
ANSWER
Zero(s)
[tex]x = 0[/tex]
The function is discontinuous at
[tex]x = - 3 \:and \: x = 3[/tex]
EXPLANATION
The given rational function is
[tex] y = \frac{3x}{ {x}^{2} - 9 } [/tex]
For this function to be equal to zero, then the numerator must be zero.
Equate the numerator to zero and solve for x.
[tex]3x = 0[/tex]
This implies that
[tex]x = \frac{0}{3} = 0[/tex]
The rational function is discontinuous when the denominator is equal to zero.
[tex] {x}^{2} - 9 = 0[/tex]
Solve this quadratic equation using the square root method or otherwise.
[tex] {x}^{2} = \pm \sqrt{9} [/tex]
[tex]{x} = \pm 3[/tex]
There is discontinuity at
[tex]x = - 3 \:and \: x = 3[/tex]
Find the length of the rectangle. The perimeter of the rectangle is 34 inches. The width of the rectangle is 7 inches. The length of the rectangle is L. A. 10 in. B. 20 in. C. 27 in. D. 70 in.
The answer is:
The correct option is:
A. 10 in.
Why?To calculate the length of the rectangle using its perimeter and one of its sides (width), we need to remember the formula to calculate the perimeter of a rectangle.
[tex]Perimeter_{rectangle}=2width+2length[/tex]
Now, we are given the following information:
[tex]Perimeter=34in\\Width=7in[/tex]
Then, substituting and calculating, we have:
[tex]Perimeter_{rectangle}=2width+2length[/tex]
[tex]34in=2*7in+2length[/tex]
[tex]34in-14in=2length\\\\2length=20in\\\\length=\frac{20in}{2}=10in[/tex]
Hence, we have that the length of the rectangle is equal to 10 inches.
So, the correct option is:
A. 10 in.
Have a nice day!
Answer:
The correct answer is option A. 10 in
Step-by-step explanation:
Points to remember
Perimeter of rectangle = 2(Length + width)
It is given that, Perimeter = 34 inches
Width = 7 inches
To find the length of rectangle
Perimeter = 2(Length + width)
34 = 2(Length + 7)
17 = Length + 7
Length = 17 - 7 = 10 inches
Therefore the length of rectangle = 10 inches
The correct answer is option A. 10 in
What is the value of the expression |a + b| + |c| when a = –3, b = 7, and c = 1
The answer is 5 hope this helps
Answer:
5
Step-by-step explanation:
abs(a + b) + abs(c)
abs(-3 + 7) + abs(1)
abs(4) + abs(1)
4 + 1
5
Prove that for all whole values of n the value of the expression:
n(n–1)–(n+3)(n+2) is divisible by 6.
Explanation:
Multiply it out.
n^2 -n -(n^2 +5n+6)
= -6n -6
= -6(n +1)
For any integer value of n, this is divisible by 6. (The quotient is -(n+1).)
Plz help ASAP!! Explain your answer! I will mark at brainliest!!!
Part A
Yes, triangle ABC and triangle APQ are similar because of Angle-Angle similarity.
Angle BAC is congruent to Angle PAQ because of reflexive property (they share the same angle).
It is given that Segment BC is parallel to Segment PQ, so Angle ABC is congruent to Angle APQ because the corresponding angles postulate.
Part B
Segment PQ corresponds to Segment BC because they are parallel to each other.
Part C
Angle APQ corresponds to Angle B because of the corresponding angles postulate.
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Explain too please.
Taking the cubic root of a number is the same as raising that number to the power of 1/3.
Moreover, we have
[tex]64 = 2^6[/tex]
So, we have
[tex]\sqrt[3]{64} = \sqrt[3]{2^6} = (2^6)^{\frac{1}{3}} = 2^{6\cdot\frac{1}{3}} = 2^2 = 4 [/tex]
Answer:
4
Step-by-step explanation:
Since we see a cube root, we will attempt to rewrite 64 as a number with an exponent of 3.
[tex]\sqrt[3]{64}[/tex]
[tex]= \sqrt[3]{4^3}[/tex]
[tex]= 4 [/tex]
What is the third quartile of this data set?
20, 21, 24, 25, 28, 29, 35, 37, 42
Answer:
36
Step-by-step explanation:
⇒The question is on third quartile
⇒To find the third quartile we calculate the median of the upper half of the data
Arrange the data in an increasing order
20, 21, 24, 25, 28, 29, 35, 37, 42
Locate the median, the center value
20, 21, 24, 25, 28, 29, 35, 37, 42
The values 20, 21, 24, 25 ------------lower half used in finding first quartile Q1
The value 28 is the median
The vlaues 29, 35, 37, 42...............upper half used in finding 3rd quartile Q3
Finding third quartile Q3= median of the upper half
upper half= 29,35,37,42
median =( 35+37)/2 = 36
graph the solution set for this inequality -6x-3y<-18
Answer:
it is 27 because of my cacculations
Step-by-step explanation:
you would fist subtract your numbers and thne get rid of the 5
Answer:
27
Hope It Helps
Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean of 62.5 lb and a standard deviation of 2.5 lb.
Approximately how many of the Labrador retrievers weigh less than 65 lb?
Enter your answer in the box.
Answer:
[tex]N= 4543[/tex] Labrador retrievers
Step-by-step explanation:
We know that the mean [tex]\mu[/tex] is:
[tex]\mu = 62.5[/tex]
and the standard deviation [tex]\sigma[/tex] is:
[tex]\sigma=2.5[/tex]
The probability that a randomly selected Labrador retriever weighs less than 65 pounds is:
[tex]P(X<65)[/tex]
We calculate the Z-score for X =65
[tex]Z = \frac{X-\mu}{\sigma}\\\\Z =\frac{65-62.5}{65}=1[/tex]
So
[tex]P(X<65) = P(Z<1)[/tex]
Looking in the table for the standard normal distribution we have to:
[tex]P(Z<1) =0.8413[/tex].
Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:
[tex]N = P(X<65) *5400[/tex]
[tex]N = 0.8413*5400[/tex]
[tex]N= 4543[/tex] Labrador retrievers
A diameter of a circle has endpoints P(-10,-2) and Q(4,6).
A. Find the center of the circle
B. Find the radius
C. Write an equation for the circle
Check the picture below.
[tex]\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{-10}~,~\stackrel{y_1}{-2})\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{4-10}{2}~~,~~\cfrac{6-2}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{4}{2} \right)\implies \stackrel{\textit{center}}{(-3~,~2)} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{\textit{center}}{(\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})}\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-3)]^2+[6-2]^2}\implies r=\sqrt{(4+3)^2+(6-2)^2} \\\\\\ r=\sqrt{49+16}\implies r=\sqrt{65} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{2}{ k})\qquad \qquad radius=\stackrel{\sqrt{65}}{ r} \\[2em] [x-(-3)]^2+[y-2]^2=(\sqrt{65})^2\implies (x+3)^2+(y-2)^2=65[/tex]
If (3x+5)^2=ax^2+bx+c, what is the value of a+b+c?
Answer:
64
Step-by-step explanation:
The value of a+b+c is the value of the expression when x=1:
(3+5)^2 = 8^2 = 64
The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make them feel guilty (Los Angeles Times, August 15, 2012). Based on the survey results, there is a .39 probability that a randomly selected person will feel guilty about wasting food and a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. Moreover, there is a .12 probability that a randomly selected person will feel guilty for both of these reasons.a. What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both (to 2 decimals)?
The probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both is .54
Further explanationProbability is the likeliness of the occurrence of an event.
Let :
P(A) = Probability of feeling guilty about wasting food = .39
P(B) = Probability of feeling guilty about leaving lights on = .27
P(A∩B) = Probability of feeling guilty for both of these reasons = .12
The probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both is :
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = .39 + .27 - .12
P(A∪B) = .54Learn moreDifferent Birthdays: https://brainly.com/question/7567074
Dependent or Independent Events: https://brainly.com/question/12029535
Answer detailsGrade: High School
Subject: Mathematics
Chapter: Probability
Keywords: Person, Probability, Outcomes, Random, Event, Room, Wasting, Food
solve -5/3x+7=9/2 by graphing
Answer:
x = 1.5
Step-by-step explanation:
The left side of the equation is graphed as a straight line with a slope of -5/3 and a y-intercept of +7. The right side of the equation is graphed as a horizontal line at y = 4.5. The point of intersection of these lines has the x-coordinate of the solution: x = 1.5.
please respond asap!!!
The answer is:
The difference between the circle and the square is:
[tex]Difference=4\pi -8[/tex]
Why?To solve the problem, we need to find the area of the circle and the area of the square, and then, subtract them.
For the square we have:
[tex]side=2\sqrt{2}[/tex]
We can calculate the diagonal of a square using the following formula:
[tex]diagonal=side*\sqrt{2}[/tex]
So,
[tex]diagonal=2\sqrt{2}*\sqrt{2}=2*(\sqrt{2})^{2}=2*2=4units[/tex]
The area will be:
[tex]Area_{square}=side^{2}= (2\sqrt{2})^{2} =4*2=8units^{2}[/tex]
For the circle we have:
[tex]radius=\frac{4units}{2}=2units[/tex]
The area will be:
[tex]Area_{Circle}=\pi *radius^{2}=\pi *2^{2}=\pi *4=4\pi units^{2}[/tex]
[tex]Area_{Circle}=4\pi units^{2}[/tex]
Then, the difference will be:
[tex]Difference=Area_{Circle}-Area{Square}=4\pi -8[/tex]
Have a nice day!
ANSWER
[tex]4\pi - 8[/tex]
EXPLANATION
The diagonal of the square can be found
using Pythagoras Theorem.
[tex] {d}^{2} = {(2 \sqrt{2} )}^{2} + {(2 \sqrt{2} )}^{2} [/tex]
[tex]{d}^{2} = 4 \times 2+ 4 \times 2[/tex]
[tex]{d}^{2} = 8+ 8[/tex]
[tex]{d}^{2} = 16[/tex]
Take positive square root
[tex]d = \sqrt{16} = 4[/tex]
The radius is half the diagonal because the diagonal formed the diameter of the circle.
Hence r=2 units.
Area of circle is
[tex]\pi {r}^{2} =\pi \times {2}^{2} = 4\pi[/tex]
The area of the square is
[tex] {l}^{2} = {(2 \sqrt{2)} }^{2} = 4 \times 2 = 8[/tex]
The difference in area is
[tex]4\pi - 8[/tex]
The area of a playground is 64 square yards. The length of the playground is 4 times longer than its width. How can I solve this?
Answer:
If you are looking for the dimensions of the playground, they are that the width is 4 yards and the length is 16 yards
Step-by-step explanation:
We need to know 2 things here: first, the area of a rectangle which is A = l×w,
and then we need to know how to express one dimension in terms of the other, since we have way too many unknowns right now to solve for anything!
We are told that the length is 4 times the width, so if the width is "w", then the length is "4w". We know the area is 64, so let's sub in those values where they belong in the area formula:
64 = 4w(w). Multiplying to simplify we get
[tex]64=4w^2[/tex]
The easiest way to do this is to divide both sides by 4 to get
[tex]16=w^2[/tex]
and when you take the square root of 16 you get 4 and -4. However, the two things in math that will never ever be negative are distance measurements and time. So the -4 won't do. That means that w = 4. If that be the case, and the length is 4 times the width, then the length is 16. And there you go!
Which of the following functions shows an original investment of $200?
a. y=200(1.02)^x
b. y=5(200)^x
c. y=3(x)^200
d. y=2000(0.5)^x
Answer:
A shows an original investment of $200
Step-by-step explanation:
If you plug in x=0, you will get the value of the original investment
When you plug x=0 into A you get
[tex]y=200(1.02)^{0}[/tex]
This simplifies to
[tex]y=200(1)[/tex]
And finally to
[tex]y=200[/tex]
I don’t know what I’m doing please help!!
Answer:
(n -13)/(n -7)
Step-by-step explanation:
Simplify the fraction on the left, then add the two fractions.
[tex]\displaystyle\frac{n^2-10n+24}{n^2-13n+42}-\frac{9}{n-7}=\frac{(n-6)(n-4)}{(n-6)(n-7)}-\frac{9}{n-7}\\\\=\frac{n-4}{n-7}-\frac{9}{n-7}\\\\=\frac{n-4-9}{n-7}\\\\=\frac{n-13}{n-7}[/tex]
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Comment on the graph
The vertical asymptote tells you the simplified form has one zero in the denominator at x=7. That is, the denominator is x-7.
The x-intercept at 13 tells you that x-13 is a factor of the numerator.
The horizontal asymptote at y=1 tells you there is no vertical scaling, so the simplest form is ...
(n -13)/(n -7)
The hole at x=6 is a result of the factor (x-6) that is cancelled from the first fraction in the original expression. At that value of x, the fraction is undefined. So, the above solution should come with the restriction x ≠ 6.
Use substitution to solve each system of equations. y = 4x + 22 4x – 6y = –32
(–5, 2)
(2, –5)
(–8, 1)
(4, 7)
Answer:
The answer is (-5,2)
Step-by-step explanation:
So we have 2 equations and we need to solve them by substitution.
1) y = 4x + 22
2) 4x – 6y = –32
Since we already have y isolated in equation #1, we'll use that value in equation #2:
4x - 6(4x + 22) = -32
4x - 24x - 132 = -32
-20x = 100
x = -5
Then we put that value of x in the first equation:
y = 4 (-5) + 22 = -20 + 22 = 2
The answer is then (-5,2)
Answer:
(-5, 2)
Step-by-step explanation:
We have the equations:
[tex]y=4x+22[/tex] and [tex]4x-6y=-32[/tex]
Using the substitution method, with y = 4x + 22 and replace it in the equation 4x - 6y = -32
4x - 6(4x + 22) = -32
4x -24x -132 = -32
-20x = -32 + 132
x = 100/-20= -5
Substituting the value of x in the first equations of the systems to clear x.
y = 4x + 22
y = 4(-5) + 22
y= -20 + 22 = 2
Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving the plane region about the y-axis. y = x5/2 y = 32 x = 0
The volume of the solid generated by revolving the plane region about the y-axis is approximately 35,929.77 cubic units.
Here,
To use the shell method to find the volume of the solid generated by revolving the plane region bounded by the curves [tex]y = x^{(5/2)}, y = 32[/tex],
and x = 0 about the y-axis, we need to integrate the circumference of cylindrical shells along the y-axis.
The volume V can be expressed as the integral of the circumference of the cylindrical shells from y = 0 to y = 32:
V = ∫[0 to 32] 2π * x * h(y) dy
where h(y) represents the height (or thickness) of each shell, and x is the distance from the y-axis to the curve [tex]y = x^{(5/2)[/tex].
To find h(y), we need to express x in terms of y by rearranging the equation [tex]y = x^{(5/2)[/tex]:
[tex]x = y^{(2/5)[/tex]
Now, we can express the volume integral:
V = ∫[0 to 32] 2π * [tex]y^{(2/5)[/tex] * (32 - y) dy
Now, we'll evaluate the integral:
V = 2π ∫[0 to 32] ([tex]32y^{(2/5)} - y^{(7/5)[/tex]) dy
Integrate each term separately:
[tex]V = 2\pi [(32 * (5/7) * y^{(7/5)}) - (5/12) * y^{(12/5)}] | [0 to 32]\\V = 2\pi [(32 * (5/7) * (32)^{(7/5)}) - (5/12) * (32)^{(12/5)}] - [0][/tex]
Now, evaluate the expression:
[tex]V = 2\pi [(32 * (5/7) * 2^7) - (5/12) * 2^{12}][/tex]
V = 2π [(32 * 1280/7) - (5/12) * 4096]
V = 2π [81920/7 - 341.33]
V ≈ 2π * 81920/7 - 2π * 341.33
V ≈ 36608π - 678.13
The volume of the solid generated by revolving the plane region about the y-axis is approximately 35,929.77 cubic units.
To know more about integral:
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Final answer:
The shell method is used to evaluate the volume of a solid created by revolving a region around the y-axis using a vertical shell element, integrating from x=0 to the x value corresponding to y=32.
Explanation:
To use the shell method to find the volume of the solid generated by revolving the given plane region about the y-axis, we consider a vertical element or 'shell' at a certain x-value with thickness dx. Given the equations [tex]x^{5/2}[/tex], y = 32, and x = 0, these will be the bounds for our region.
The volume of each infinitesimal shell with radius x and height [tex](32 - x^{5/2})[/tex], when revolved around the y-axis, is [tex]2πx(32 -x^{5/2})dx[/tex]. To find the total volume, we integrate this expression from x=0 to where y is 32, which corresponds to the x value where [tex]x^{5/2} = 32[/tex].
Using the substitution [tex]x^{5/2}[/tex] to solve for dx, we get the integral in terms of y, which simplifies the computation. Finally, we evaluate the definite integral to find the volume of the solid of revolution.
An art student wishes to create a clay sphere as part of a sculpture. If the clay’s density is approximately 88 pounds per cubic foot and the sphere’s radius is 2 feet, what is the weight of the sphere to the nearest pound? Use 3.14 for pi, and enter the number only.
Answer:
2947 lb
Step-by-step explanation:
Find the volume of the sphere
v=4/3 ×pi×r³
r=2ft and pi=3.14
v=4/3 × 3.14×2³
v=33.49 ft³
Given that;
Density ⇒ 88 lb/ft³
Volume⇒33.49 ft³
Mass=?-------------------------------------find the mass
But we know density=mass/volume -----so mass=density × volume
Mass= 88×33.49 =2947.41 pounds
⇒2947 lb
I start with 5 oz. of 18-karat gold. It's 75% pure gold, 25% other metals. I need to make it 22-karat, which is 91.7% pure gold. How much pure gold do I need to add to make it 22-karat?
Answer:
about 10.06 oz.
Step-by-step explanation:
Let x represent the number of ounces of pure gold you need to add. Then the amount of gold in the mix is ...
100%·x + 75%·5 = 91.7%·(x+5)
8.3%·x = 5·16.7% . . . . . . subtract 91.7%·x +75%·5
x = 5 · 16.7/8.3 . . . . . . . . divide by the coefficient of x
x ≈ 10.06 . . . . oz
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Alternate solution
The amount of non-gold in the given material is 25%·5 oz = 1.25 oz. That is allowed to be 8.3% of the final mix, so the weight of the final mix will be ...
(1.25 oz)/0.083 ≈ 15.06 oz
Since that weight will include the 5 oz you already have, the amount of pure gold added must be ...
15.06 oz - 5 oz = 10.06 oz
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Comment on these answers
If you work directly with carats instead of percentages, you find the amount of pure gold you need to add is 10.00 ounces, double the amount you have.