ANSWER
36,-36
EXPLANATION
The given function is:
[tex]f(x) = {x}^{2} + 12x + 6[/tex]
To write this function in vertex form;
We need to add and subtract the square of half the coefficient of x.
The coefficient of x is 12.
Half of it is 6.
The square of 6 is 36.
Therefore we add and subtract 36.
Hence the zero pair is:
36, -36.
The correct answer is D.
Answer:
Last option: 36,-36
Step-by-step explanation:
The vertex form of the function of a parabola is:
[tex]y=a(x-h)^2+k[/tex]
Where (h,k) is the vertex.
To write the given function in vertex form, we need to Complete the square.
Given the Standard form:
[tex]y=ax^2+bx+c[/tex]
We need to add and subtract [tex](\frac{b}{2})^2[/tex] on one side in order to complete the square.
Then, given [tex]y=x^2+12x+6[/tex], we know that:
[tex](\frac{12}{2})^2=6^2=36[/tex]
Then, completing the square, we get:
[tex]y=x^2+12x+(36)+6-(36)[/tex]
[tex]y=(x+6)^2-30[/tex] (Vertex form)
Therefore, the answer is: 36,-36
Use the table above to answer the question.
Ed Employee had $70,000 in taxable income. What was his tax?
Tax = $______
Answer:
$16,479
Step-by-step explanation:
The table tells you Ed's tax is ...
14,138.50 + 0.31×(70,000 -62,450) = 16,479 . . . . dollars
The conversion factor relating feet to meters is 1 ft=0.305 m. Keep in mind that when using conversion factors, you want to make sure that like units cancel leaving you with the units you need. You have been told that a certain house is 164 m2 in area. How much is this in square feet?
Answer:
1763 ft²
Step-by-step explanation:
Using the given conversion factor, ...
(164 m²)(1 ft/(.305 m))² = 165/.093025 ft² ≈ 1763 ft²
_____
The exact conversion factor is 1/0.3048, so the area is closer to 1765 ft². For a 4-significant digit answer, you need to use a conversion factor accurate to 4 significant digits.
To convert square meters to square feet, you must square the feet to meter conversion factor, resulting in approximately 10.764 sq ft/sq m. You then multiply this by the square meter measurement to get the equivalent in square feet. Therefore, the house's area, which was provided as 164 square meters, translates to approximately 1765.736 square feet.
Explanation:The measure of the area in square feet can be derived using the conversion factor for feet to meters, 1 ft = 0.305 m. However, when you deal with areas, you must square the conversion factor. We then apply the conversion factor to the known area in reference, which in our case is 164 square meters.
So our conversion factor becomes (1/0.305)² sq ft/sq m = 10.764 sq ft/sq m.
To use the conversion factor, we multiply it by the metric unit measurement, like this: 164 m²*(10.764 ft²/m²) = 1765.736 square feet.
So, the house's area is approximately 1765.736 square feet.
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A club has 50 members, 10 belonging to the ruling clique and 40 second-class members. Six members are randomly selected for free movie tickets. What is the probability that 3 or more belong to the ruling clique?
Answer: The probability that 3 or more belong to the ruling clique is 0.34.
Step-by-step explanation:
Since we have given that
Number of total members = 50
Number of belonging to ruling clique = 10
Number of belonging to second class member = 40
We need to find the probability that 3 or more belong to the ruling clique.
Let X be the number of outcomes belong to ruling clique.
So, it becomes,
P(X≥3)=1-P(X<3)
[tex]P(X\geq 3)=1-P(X=1)-P(X=2)\\\\P(X\geq 3)=1-\dfrac{^{10}C_1\times ^{40}C_5}{^{50}C_6}-\dfrac{^{10}C_2\times ^{40}C_4}{^{50}C_6}\\\\P(X\geq 3)=1-0.41-0.25\\\\P(X\geq 3)=0.34[/tex]
Hence, the probability that 3 or more belong to the ruling clique is 0.34.
The probability of selecting 3 or more members from the ruling clique when choosing 6 members randomly from a club of 50 members (10 in ruling clique, 40 second-class) is 8.56%.
Explanation:This probability problem can be solved using the concepts of Combinations and Binomial Theorem. You need to determine the number of ways to choose 3, 4, 5, or 6 members from the ruling clique (10 members) and the remaining from the second-class members (40 members). For each case, divide by the total number of ways to choose 6 members from all 50 members to get the probability. Sum up all the probabilities for each case to get the total probability of having 3 or more from the ruling clique.
Calculations:1. Number of ways of choosing 3 from the ruling clique and 3 from the second class: C(10,3)*C(40,3) = 120*9880 = 1,185,600 ways
2. Number of ways of choosing 4 from the ruling clique and 2 from the second class: C(10,4)*C(40,2) = 210*780 = 163,800 ways
3. Number of ways of choosing 5 from the ruling clique and 1 from the second class: C(10,5)*C(40,1) = 252*40 = 10,080 ways
4. Number of ways of choosing 6 from the ruling clique and 0 from the second class: C(10,6)*C(40,0) = 210*1 = 210 ways
Total ways to choose 3 or more from the ruling clique: 1,185,600 + 163,800 + 10,080 +210 = 1,359,690 ways
From 50 members, the total ways to choose 6: C(50,6) = 15,890,700 ways
The Probability of 3 or more from the ruling clique = 1,359,690 / 15,890,700 = 0.0856 or 8.56%
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find the solution of the following system of equations -5+2y=9 3x+5y=7
The solution to the system of equations is [tex]\(x = -1\) and \(y = 2\)[/tex].
To solve the system of equations:
[tex]\[ \begin{cases} -5x + 2y = 9 \\ 3x + 5y = 7 \end{cases} \][/tex]
We can use either the substitution method or the elimination method. Let's use the elimination method here.
First, let's rewrite the equations in standard form:
Equation 1: [tex]\( -5x + 2y = 9 \)[/tex]
Equation 2: [tex]\( 3x + 5y = 7 \)[/tex]
To eliminate one of the variables, let's multiply Equation 1 by 3 and Equation 2 by 5 to make the coefficients of x the same:
[tex]\[ \begin{cases} -15x + 6y = 27 \\ 15x + 25y = 35 \end{cases} \][/tex]
Now, let's add the two equations:
[tex]\[ (-15x + 6y) + (15x + 25y) = 27 + 35 \]\[ -15x + 6y + 15x + 25y = 62 \]\[ 31y = 62 \][/tex]
Now, let's solve for y:
[tex]\[ y = \frac{62}{31} \][/tex]
y=2
Now that we have found the value of y, let's substitute it back into one of the original equations to find x. Let's use Equation 1:
[tex]\[ -5x + 2(2) = 9 \]\[ -5x + 4 = 9 \]\[ -5x = 9 - 4 \]\[ -5x = 5 \]\[ x = \frac{5}{-5} \][/tex]
[tex]\[ x = -1 \][/tex]
Complete question: Find the solution of the following system of equations
-5x+2y=9
3x+5y=7
\[ x = -\frac{28}{3} \] and \( y = 7 \) are the solutions to the system of equations.
To solve the system of equations:
1. -5 + 2y = 9
2. 3x + 5y = 7
We can start by solving equation 1 for [tex]\( y \):[/tex]
[tex]\[ -5 + 2y = 9 \][/tex]
Add 5 to both sides:
[tex]\[ 2y = 9 + 5 \]\[ 2y = 14 \][/tex]
Divide both sides by 2:
[tex]\[ y = \frac{14}{2} \]\[ y = 7 \][/tex]
Now that we have the value of [tex]\( y \)[/tex], we can substitute it into equation 2 and solve for [tex]\( x \):[/tex]
[tex]\[ 3x + 5(7) = 7 \]\[ 3x + 35 = 7 \][/tex]
Subtract 35 from both sides:
[tex]\[ 3x = 7 - 35 \]\[ 3x = -28 \][/tex]
Divide both sides by 3:
[tex]\[ x = \frac{-28}{3} \][/tex]
So, the solution to the system of equations is [tex]\( x = -\frac{28}{3} \) and \( y = 7 \).[/tex]
The speed of cars on a stretch of road is normally distributed with an average 48 miles per hour with a standard deviation of 5.9 miles per hour. What is the probability that a randomly selected car is violating the speed limit of 50 miles per hour? (a) 0.37 (b) 0.48 (c) 0.21 (d) 0.63
Answer: (a) 0.37
Step-by-step explanation:
Given: The speed of cars on a stretch of road is normally distributed with an average 48 miles per hour with a standard deviation of 5.9 miles per hour.
i.e. Mean : [tex]\mu = 48\text{ miles per hour} [/tex]
Standard deviation : [tex]\sigma = 5.9\text{ miles per hour}[/tex]
The formula to calculate z is given by :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For the probability that a randomly selected car is violating the speed limit of 50 miles per hour (X≥ 50).
For x= 80
[tex]z=\dfrac{50-48}{5.9}=0.338983050847\approx0.34[/tex]
The P Value =[tex]P(z>0.34)=1-P(z<0.34)=1-0.6330717\approx0.3669283\approx0.37[/tex]
Hence, the probability that a randomly selected car is violating the speed limit of 50 miles per hour =0.37
An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 lb. The new population of pilots has normally distributed weights with a mean of 125 lb and a standard deviation of 28.1 lb.
a)If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 lb.The probability is approximately?
b. If 36 different pilots are randomly selected, find the probability that their mean weight is between 120 lb and 161 lb. The probability is approximately?
c. When redesigning the ejection seat, which probability is more relevant? . Part (b) because the seat performance for a single pilot is more important. B. Part (b) because the seat performance for a sample of pilots is more important. C. Part (a) because the seat performance for a sample of pilots is more important. D. Part (a) because the seat performance for a single pilot is more important.
let f(x) = -2x/(x^2-x-5) There are 2 numbers that are not in the domain of f. Give the larger value to 2 decimal places.
Answer:
Step-by-step explanation:
The 2 numbers that are not in the domain of the function are the 2 numbers that cause the denominator of the function to equal 0. In order to find those 2 numbers, we have to factor the quadratic that is in the denominator. When you factor, you get x = 2.79 and x = -1.79
Those are the values of x that cause the denominator to equal 0, which of course is NEVER allowed in math!
Line m is parallel to line n. The measure of angle 2 is 74°. What is the
measure of angle 5?
OA) 74°
O B) 120
OC) 106°
OD) 86°
Answer:
C. 106
Step-by-step explanation:
Angles 2 and 6 are corresponding angles so they're both 74. So you just subtract 74 from 180 to get 106.
Answer:
C. 106 is the answer
Step-by-step explanation:
angle 3 = angle 2 (vertically opp. angle)
angle 3+ angle 5 = 180
74+ angle 5 = 180
angle 5 = 106
Use a proof by contradiction to prove that underroot 3 is irrational.
Let assume that [tex]\sqrt3[/tex] is rational. Therefore we can express it as [tex]\dfrac{a}{b}[/tex] where [tex]a,b\in \mathbb{Z}[/tex] and [tex]\text{gcd}(a,b)=1[/tex].
[tex]\dfrac{a}{b}=\sqrt3\\\dfrac{a^2}{b^2}=3\\a^2=3b^2[/tex]
It means that [tex]3|a^2[/tex] and so also [tex]3|a[/tex].
Therefore [tex]a=3k[/tex] where [tex]k\in\mathbb{Z}[/tex].
[tex](3k)^2=3b^2\\9k^2=3b^2\\b^2=3k^2[/tex]
It means that [tex]3|b^2[/tex] and so also [tex]3|b[/tex].
If both [tex]a[/tex] and [tex]b[/tex] are divisible by 3, then it contradicts our initial assumption that [tex]\text{gcd}(a,b)=1[/tex]. Therefore [tex]\sqrt3[/tex] must be an irrational number.
Solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.
Square root of x-2+8=x
ANSWER
Extraneous solution: x=6
Real solution: x=11
EXPLANATION
The given expression is
[tex] \sqrt{x - 2} + 8 = x[/tex]
Add -8 to both sides:
[tex]\sqrt{x - 2} + 8 + - 8= x + - 8[/tex]
[tex] \implies\sqrt{x - 2} = x - 8[/tex]
Square both sides.
[tex]\implies(\sqrt{x - 2} )^{2} =( x - 8)^{2} [/tex]
[tex]x - 2=( x - 8)^{2} [/tex]
We expand the to get
[tex]x - 2 = {x}^{2} - 16x + 64[/tex]
Write in standard quadratic form.
[tex] {x}^{2} - 16x - x + 64 + 2 = 0[/tex]
[tex] {x}^{2} - 17x + 66 = 0[/tex]
Factor to get:
[tex](x - 6)(x - 11) = 0[/tex]
[tex]x = 6 \: or \: \: x = 11[/tex]
We check for extraneous solutions by substituting each value of x into the original equation.
When x=6
[tex]\sqrt{6 - 2} + 8 = 6[/tex]
[tex]\sqrt{4} + 8 =6[/tex]
[tex]2 + 8 = 10 \ne8[/tex]
Hence x=6 is an extraneous solution.
When x=11
[tex]\sqrt{11- 2} + 8 = 11[/tex]
[tex]\sqrt{9} + 8 = 11[/tex]
[tex]3 + 8 = 11[/tex]
This statement is true.
Hence x=11 is the only solution.
Find the point, P, at which the line intersects the plane. x equals 7 plus 9 t, y equals 3 minus 7 t, z equals 7 minus 5 t; 5 x minus 6 y minus 9 z equals negative 1 \
Answer:
The point of intersection [tex]P\left(\dfrac{1133}{122},\dfrac{149}{122},\dfrac{699}{122}\right)[/tex]
Step-by-step explanation:
Equation of line:
[tex]x=7+9t[/tex]
[tex]y=3-7t[/tex]
[tex]z=7-5t[/tex]
Equation of plane:
[tex]5x-6y-7z=-1[/tex]
We need to find the point of intersection of line and plane.
Point of intersection: When both line and plane meet at single point.
So, put the value of x, y and z into plane.
[tex]5(7+9t)-6(3-7t)-7(7-5t)=-1[/tex]
[tex]35+45t-18+42t-49+35t=-1[/tex]
[tex]122t=-1+32[/tex]
[tex]t=\dfrac{31}{122}[/tex]
Substitute the value of t into x, y and z
[tex]x=7+9\cdot \dfrac{31}{122}=\dfrac{1133}{122}[/tex]
[tex]y=3-7\cdot \dfrac{31}{122}=\dfrac{149}{122}[/tex]
[tex]z=7-5\cdot \dfrac{31}{122}=\dfrac{699}{122}[/tex]
Point of intersection:
[tex]\left(\dfrac{1133}{122},\dfrac{149}{122},\dfrac{699}{122}\right)[/tex]
Hence, The point of intersection [tex]P\left(\dfrac{1133}{122},\dfrac{149}{122},\dfrac{699}{122}\right)[/tex]
x^2+y^2=25 Find the distance of point (x,y) from origin.
Answer:
5 units
Step-by-step explanation:
This is a circle with a center of (0, 0). The square root of 25 represents the radius of the circle which is 5. The radius represents the distance that the outside of the circle is from the center.
The mean number of words per minute (WPM) read by sixth graders is 93 with a standard deviation of 22.If 30 sixth graders are randomly selected, what is the probability that the sample mean would be greater than 97.95 WPM? (Round your answer to 4 decimal places)
Answer: 0.1093
Step-by-step explanation:
Given: Mean : [tex]\mu=93[/tex]
Standard deviation : [tex]\sigma = 22[/tex]
Sample size : [tex]n=30[/tex]
The formula to calculate z-score is given by :_
[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]
For x= 97.95, we have
[tex]z=\dfrac{97.95-93}{\dfrac{22}{\sqrt{30}}}\approx1.23[/tex]
The P-value = [tex]P(z>1.23)=1-P(z<1.23)=1-0.8906514=0.1093486\approx0.1093[/tex]
Hence, the probability that the sample mean would be greater than 97.95 WPM =0.1093
A coin is tossed 30 times it lands 12 times on heads and 18 times on tails what is experimental probability of the coin landing on tails?
Answer:
3/5
Step-by-step explanation:
Total tossed : 30
# of times landed on tails : 18
Experimental probability of tails = 18/30 = 3/5
please help asap!!!!!
Answer:
The volume of the prism is 27√3/2
Step-by-step explanation:
* Lets revise the triangular prism properties
- The triangular prism has five faces
- Two bases and three side faces
- The two bases are triangles
- The three side faces are rectangles
- The rule of its volume is Area of its base × its height
* Lets solve the problem
- The triangular prism has two bases which are equilateral triangles
- The length of each side of the triangular base is 3"
- The height of the prism is 6"
∵ The volume of the prism = area of the base × its height
∵ The base is equilateral triangle of side length 3"
- The area of any equilateral triangle is √3/4 s²
∴ The area of the base of the prism = √3/4 × (3)² = 9√3/4
∵ The length of the height of the prism is 6"
∴ The volume of the prism = 9√3/4 × 6 = 27√3/2
* The volume of the prism is 27√3/2
A car was valued at $39,000 in the year 1995. The value depreciated to $11,000 by the year 2003.
A)What was the annual rate of change between 1995 and 2003? (Round to 4 decimal places)
B)What is the correct answer to part A written in percentage form?
C)Assume that the car value continues to drop by the same percentage. What will the value be in the year 2007?
Please help ASAP the homework is due Monday!!! :(
Answer:
14.6328% , $5836.03
Step-by-step explanation:
Here we are going to use the formula
[tex]A_{0}(1-r)^n = A_{n}[/tex]
[tex]A_{0}[/tex] = 39000
r=?
[tex]A_{8}[/tex] = 11000
n=8
Hence
[tex]39000(1-r)^8 = 11000[/tex]
[tex](1-r)^8 = \frac{11000}{39000}[/tex]
[tex](1-r)^8 = 0.2820[/tex]
[tex](1-r) = 0.2820^{\frac{1}{8}[/tex]
[tex](1-r) = 0.2820^{0.125}[/tex]
[tex](1-r) = 0.8536[/tex]
[tex](1-0.8536=r[/tex]
[tex]r = 0.1463[/tex]
Hence r= 0.1463
In percentage form r = 14.63%
Now let us see calculate the value of car in 2003 that is after 12 years
we use the main formula again
[tex]A_{0}(1-r)^n = A_{n}[/tex]
[tex]A_{0}[/tex] = 39000
r=0.1463
[tex]A_{12}[/tex] = ?
n=12
[tex]39000(1-0.14634)^{(12} = A_{12}[/tex]
[tex]39000(0.8536)^{12} = A_{12}[/tex]
[tex]39000*0.1497 = A_{12}[/tex]
[tex]A_{12}=5840.34[/tex]
Hence the car's value will be depreciated to $5840.34 (approx) by 2003.
The annual rate of change between 1995 and 2003 is -0.1463
The annual rate of change between 1995 and 2003 is -14.63%
The value of the car in 2007 would be $5,844.24
The value of the car decreases as the years go by. This is referred to as depreciation. Depreciation is the decline in value of an asset as a result of wear and tear.
In order to determine the annual rate of change, use this formula:
g = [tex](FV / PV) ^{\frac{1}{n} } - 1[/tex]
Where:
g = depreciation rate
FV = value of the car in 2003 = $11,000
PV = value of the car in 1995 = $39,000
n = number of years = 2003 - 1995 = 8
[tex](11,000 / 39,00)^{\frac{1}{8} } - 1[/tex] = -0.1463 = -14.63%
The value of car in 7 years can be determined using this formula:
FV = P (1 + g)^n
$39,000 x (1 - 0.1463)^12
$39,000 x 0.8537^12 = $5,844.24
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Fewer young people are driving. In 1983, 87% of 19-year-olds had a driver’s license. Twenty-five years later that percentage had dropped to 75% (University of Michigan Transportation Research Institute website, April 7, 2012). Suppose these results are based on a random sample of 1200 19-year-olds in 1983 and again in 2008.
a. At 95% confidence, what is the margin of error and the interval estimate of the number of 19-year-old drivers in 1983?
b. At 95% confidence, what is the margin of error and the interval estimate of the number of 19-year-old drivers in 2008?
c. Is the margin of error the same in parts (a) and (b)? Why or why not?
Answer: the answer to this question is B
Step-by-step explanation: Hope This Helps
Formula to find the margin of error :
[tex]E=z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex] , where n= sample size , [tex]\hat{p}[/tex] is the sample proportion and z*= critical z-value.
Let p be the proportion of 19-year-olds had a driver’s license.
A) As per given , In 1983
[tex]\hat{p}=0.87[/tex]
n= 1200
Critical value for 95% confidence level is 1.96 (By z-table)
So ,Margin of error : [tex]E=(1.96)\sqrt{\dfrac{0.87(1-0.87)}{1200}}\approx0.019[/tex]
Interval : [tex](\hat{p}-E , \ \hat{p}+E)=(0.87-0.019 ,\ 0.87+0.019)[/tex]
[tex]=(0.851,\ 0.889)[/tex]
B) In 2008 ,
[tex]\hat{p}=0.75[/tex]
Margin of error : [tex]E=(1.96)\sqrt{\dfrac{0.75(1-0.75)}{1200}}\approx0.0245[/tex]
Interval : [tex](\hat{p}-E, \hat{p}+E)=(0.75-0.0245,\ 0.75+0.0245)[/tex]
[tex]=(0.7255,\ 0.7745)[/tex]
c. The margin of error is not the same in parts (a) and (b) because the sample proportion of 19-year-olds had a driver’s license are not same in both parts.
8. Write three other proportions for each given proportion. 35 miles/2 hours=87.5 miles/5 hours
Answer:
218.75 miles / 12.5 hours
437.5 miles / 25 hours
656.25 miles / 37.5 hours
Step-by-step explanation:
35 miles / 2 hours = 87.5 miles / 5 hours
This is the ratio of 2.5. So, the other proportions are
87.5 x 2.5 miles / 5 x 2.5 hours = 218.75 miles / 12.5 hours
87.5 x 5 miles / 5 x 5 hours = 437.5 miles / 25 hours
87.5 x 7.5 miles / 5 x 7.5 hours = 656.25 miles / 37.5 hours
a theater has two screens and shows its movies continuously. a 30 minute documentary is shown on one. a 120 minute film is shown on the other. If both showings start at noon, how many minutes will pass before both movies begin again at the same time?
The volume of water flowing through a pipe varies directly wlth the square of the radius of the pipe. If the water flows at a rate of 80 liters per minute through a pipe with a radlus of 4 cm, at what rate would water flow through a pipe with a radius of 3 cm? (Rigorous) (Competency 007) 11. A) 45 liters per minute B) 6.67 liters per minute C) 60 liters per minute D) 4.5 liters per minute
Answer:
A
Step-by-step explanation:
Volume varies directly with the square of the radius, so:
V = k r²
When V = 80, r = 4.
80 = k (4)²
k = 5
V = 5r²
When r = 3:
V = 5 (3)²
V = 45
The flow is 45 L/min.
State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes products A and B. Product A takes 2 hours each on machine M; product B takes 4 hours on L and 3 hours on M. Machine L can be used for 8 hours and M for 6 hours. Profit on product A is $9 and $7 on B. Maximize profit.
Final answer:
The problem requires formulating a linear programming model to maximize the profit function Z = 9x + 7y with constraints on machine time for product A and B (2x + 3y ≤ 6 for machine M and 4y ≤ 8 for machine L) and the non-negativity restrictions (x, y ≥ 0).
Explanation:
The linear programming problem can be stated in mathematical terms with an objective function and constraints for a firm making products A and B. The objective is to maximize profit, which is the sum of 9 dollars per unit of product A and 7 dollars per unit of product B. Let the number of products A and B produced be represented by variables x and y, respectively.
The objective function to maximize is Z = 9x + 7y.
Constraints:
Machine M's availability limits product A to 2 hours each, and product B to 3 hours each, with a total available time of 6 hours: 2x + 3y ≤ 6.Machine L can be used for 8 hours and is only required for product B, which takes 4 hours: 4y ≤ 8.Non-negativity constraints: x ≥ 0 and y ≥ 0, since the number of products cannot be negative.a figure has a vertex at (-1,-3). if the figure has a line symmetry about x-axis , what are the coordinates of another vertex of the figure?
a. (3,1)
b. (-1,3)
c. (-3,-1)
d. (1,-3)
Answer:
b. (-1,3)
Step-by-step explanation:
the image of the point (x ; y) by symmetry about x-axis is : ( x ;- y)
so the answer "b" : (-1,3)
if cos θ = -0.6, and 180° < θ < 270°, find the exact value of sin 2θ.
Answer:
sin(2θ) = 0.96
Step-by-step explanation:
In the third quadrant, both sin(θ) and cos(θ) are negative. Then the double-angle trig identity tells us ...
sin(2θ) = 2·sin(θ)·cos(θ) = -2cos(θ)√(1 -cos(θ)²) . . . . using the negative root
Filling in the given value, we have
sin(2θ) = -2·(-0.6)(√(1-(-0.6)²) = 2·0.6·0.8 = 0.96
A large school district in southern California asked all of its eighth-graders to measure the length of their right foot at the beginning of the school year, as part of a science project. The data show that foot length is approximately Normally distributed, with a mean of 23.4 cm and a standard deviation of 1.7 cm. Suppose that 25 eighth-graders from this population are randomly selected. Approximately what is probability that the sample mean foot length is less than 23 cm?
Answer:
The probability of the sample mean foot length less than 23 cm is 0.120
Step-by-step explanation:
* Lets explain the information in the problem
- The eighth-graders asked to measure the length of their right foot at
the beginning of the school year, as part of a science project
- The foot length is approximately Normally distributed, with a mean of
23.4 cm
∴ μ = 23.4 cm
- The standard deviation of 1.7
∴ σ = 1.7 cm
- 25 eighth-graders from this population are randomly selected
∴ n = 25
- To find the probability of the sample mean foot length less than 23
∴ The sample mean x = 23, find the standard deviation σx
- The rule to find σx is σx = σ/√n
∵ σ = 1.7 and n = 25
∴ σx = 1.7/√25 = 1.7/5 = 0.34
- Now lets find the z-score using the rule z-score = (x - μ)/σx
∵ x = 23 , μ = 23.4 , σx = 0.34
∴ z-score = (23 - 23.4)/0.34 = -1.17647 ≅ -1.18
- Use the table of the normal distribution to find P(x < 23)
- We will search in the raw of -1.1 and look to the column of 0.08
∴ P(X < 23) = 0.119 ≅ 0.120
* The probability of the sample mean foot length less than 23 cm is 0.120
PLEASE ANSWER WITH AN EXPLANATION! THANK YOU
Answer:
[tex]\large\boxed{A=153\ cm^2}[/tex]
Step-by-step explanation:
Look at the picture.
We have
square with side length a = 9
trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6
right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6
The formula of an area of a square
[tex]A=a^2[/tex]
Substitute:
[tex]A_I=9^2=81\ cm^2[/tex]
The formula of an area of a trapezoid:
[tex]A=\dfrac{b_1+b_2}{2}\cdot h[/tex]
Substitute:
[tex]A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2[/tex]
The formula of an area of a right triangle:
[tex]A=\dfrac{l_1l_2}{2}[/tex]
Substitute:
[tex]A_{III}=\dfrac{(9)(6)}{2}=\dfrac{54}{2}=27\ cm^2[/tex]
The area of the shape:
[tex]A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2[/tex]
Random samples of size 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively. The distribution of the population is unknown. The mean and the standard error of the distribution of the sample mean are
Answer: The mean and the standard error of the distribution of the sample mean are 200 and 2.
Step-by-step explanation:
Given: Sample size : n= 81
Mean of infinite population : [tex]\mu=200[/tex]
We know that the mean of the distribution of the sample mean is same as the mean of the population.
i.e. [tex]\mu_x=\mu=200[/tex]
The standard error of the distribution of the sample mean is given by :-
[tex]S.E.=\dfrac{\sigma}{\sqrt{n}}[/tex]
[tex]\Rightarrow\ S.E.=\dfrac{18}{\sqrt{81}}=\dfrac{18}{9}=2[/tex]
Hence, the mean and the standard error of the distribution of the sample mean are 200 and 2.
The mean of the sample mean distribution for a random sample of size 81 from a population with a mean of 200 and a standard deviation of 18 is 200, and the standard error is 2.
Explanation:The question is about determining the mean and the standard error of the distribution of the sample mean. According to the Central Limit Theorem, regardless of the distribution of the original population, the distribution of the sample mean tends to form a normal distribution as the sample size increases. In this case, the mean of the sample mean distribution is the same as the population mean, which is 200.
The standard error of the mean is calculated as the population standard deviation divided by the square root of the sample size. So, the standard error in this scenario would be 18/√81 = 2.
Therefore, in a random sample of size 81 taken from an infinite population with a mean of 200 and a standard deviation of 18, the mean of the sample mean distribution is 200, and the standard error is 2.
Learn more about Sample Mean Distribution here:https://brainly.com/question/31520808
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Write the standard equation of a circle with center (-4 0) and radius 3 brainly
I need help with math work!!
Answer:
(g-h)=x^2+5-8-x
=x^2-x-3
(g-h)(-9) means x= -9
x^2-x-3
=(-9)^2-(-9)-3
=81+9-3
=90-3
=87
Six customers enter a three-floor restaurant. Each customer decides on which floor to have dinner. Assume that the decisions of different customers are independent, and that for each customer, each floor is equally likely. Find the probability that exactly one customer dines on the first floor.
The probability that exactly one customer dines on the first floor is:
0.26337
Step-by-step explanation:We need to use the binomial theorem to find the probability.
The probability of k success in n experiments is given by:
[tex]P(X=k)=n_C_k\cdot p^k\cdot (1-p)^{n-k}[/tex]
where p is the probability of success.
Here p=1/3
( It represents the probability of choosing first floor)
k=1 ( since only one customer has to chose first floor)
n=6 since there are a total of 6 customers.
This means that:
[tex]P(X=1)=6_C_1\times (\dfrac{1}{3})^1\times (1-\dfrac{1}{3})^{6-1}\\\\\\P(X=1)=6\times (\dfrac{1}{3})\times (\dfrac{2}{3})^5\\\\\\P(X=1)=0.26337[/tex]
Using the binomial distribution, it is found that there is a 0.2634 = 26.34% probability that exactly one customer dines on the first floor.
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For each customer, there are only two possible outcomes, either they dine on the first floor, or they do not. The probability of a customer dining on the first floor is independent of any other customer, which means that the binomial probability distribution is used to solve this question.
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Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of a success on a single trial.
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Six customers, thus [tex]n = 6[/tex].They are equally as likely to dine on any of the three floors, thus [tex]p = \frac{1}{3} = 0.3333[/tex].----------------
The probability that exactly one customer dines on the first floor is P(X = 1), thus:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 1) = C_{6,1}.(0.3333)^{1}.(0.6667)^{5} = 0.2634[/tex]
0.2634 = 26.34% probability that exactly one customer dines on the first floor.
A similar problem is given at https://brainly.com/question/13036444
........Help Please.......
Answer:
b = 1.098
Step-by-step explanation:
Each year, the GDP is 9.8% higher than the year before, so the multiplier each year is 1 + 9.8% = 1.098. This is the value of b.
b = 1.098