What is a 3 letter (all lowercase) word that sits in the middle of the Milky Way? {Planets rotate and revolutionize around it...}
What is the magnitude of the electric field due to the dipole at location a, a distance d?
The resistivity of a silver wire with a radius of 5.04 × 10–4 m is 1.59 × 10–8 ω · m. if the length of the wire is 3.00 m, what is the resistance of the wire?
The resistivity of a silver wire is 5.98 x 10^-2 ohms.
How do find the resistivity of a silver wire?Resistance is defined as: R = r*l/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire.
Substituting into the formula, the known values, including the area of a circle being pi*r^2, gives:
R = 1.59x[tex]10^{-8}[/tex] * 3.00 / ([tex]\pi[/tex] * (5.04 x [tex]10^{-4}[/tex])²)
R = (4.77 x[tex]10^{-8}[/tex]) / (pi * 2.54016 x [tex]10^{-7}[/tex])
R = (4.77 x [tex]10^{-8}[/tex]) / (7.98015 x [tex]10^{-7}[/tex])
R = 5.98 x [tex]10^{-2}[/tex] ohms
The wire has a resistance of 5.98 x 10^-2 ohms.
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Help me please
The velocity of an object increases from -10m/s to -15m/s in 2.0s what is the average acceleration of the object?
-2.5m/s^2
+2.5m/s^2
+12.5m/s^2
-12.5m/s^2
To find the average acceleration of an object, subtract the initial velocity from the final velocity and divide it by the time taken. In this case, the average acceleration is -2.5 m/s².
The average acceleration of an object can be calculated by using the formula:
acceleration = (change in velocity) / (time taken)
In this case, the change in velocity is -15 m/s - (-10 m/s) = -5 m/s and the time taken is 2.0 s. So, acceleration = (-5 m/s) / (2.0 s) = -2.5 m/s² which means the correct answer is -2.5 m/s².
Therefore, the first option is correct.
A 1200-kg car starts from rest and accelerates with constant acceleration, traveling 200 m in 9.00 s. what is the force of the road on the car during this acceleration?
First calculate the acceleration using the formula:
d = v0 t + 0.5 a t^2
where d is distance = 200 m, v0 = initial velocity = 0, t is time = 9s, a = acceleration (?)
200 = 0 + 0.5 * a * 9^2
a = 4.94 m/s^2
Force is mass times acceleration, therefore:
F = m a = 1200 kg * 4.94 m/s^2
F = 5,925.93 N
To calculate the force exerted on the car by the road, we first find the acceleration of the car using the formula: a = Δv/Δt. After calculating the acceleration to be approximately 9.88 m/s², we then use Newton's second law, F = ma, which results in the force being approximately 11856 N.
Explanation:In physics, to find the force exerted, we need to apply Newton's second law of motion which states that the force acting on an object is equal to the mass of that object multiplied by its acceleration (F = ma). Given the mass of the car (1200 kg) and the need to find acceleration, we can use the formula for acceleration: a = Δv/Δt, where Δv is the change in velocity and Δt is the change in time. Initially, the car is at rest so initial velocity is zero and the final velocity can be calculated as v = a*t. Now substituting the values into the equation, 200m = 0.5*a*(9s)^2, we find acceleration a=9.88 m/s². Then, applying Newton's second law F = 1200kg * 9.88m/s² we get the force exerted on the car by the road is approximately 11856 N.
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The nucleus of any atom has which kind of charge?
Answer:
positive charge
The nucleus contains protons, which have a positive charge equal in magnitude to the electron's negative charge. The nucleus may also contain neutrons, which have virtually the same mass but no charge.
Explanation: