Who first proposed the existence of antimatter

ok interesting what is you question

option B open system

because in open system energy and mass can escape from the system or can be added to it.

Answer:

13 Hz

Explanation:

The frequency of a wave is given by the equation:

[tex]f=\frac{v}{\lambda}[/tex]

where

f is the frequency

v is the speed of the wave

[tex]\lambda[/tex] is the wavelength

In this problem, we have:

v = 5.2 m/s is the speed of the wave

[tex]\lambda=0.40 m[/tex] is the wavelength (distance between two adjacent crests)

Substituting into the formula, we find the frequency of the wave:

[tex]f=\frac{5.2 m/s}{0.40 m}=13 Hz[/tex]

Answer:

D.13 Hz

Explanation:

A

p

e

x

Answer:

[tex]R_3 < R_1 < R_2[/tex]

Explanation:

The resistance of a wire is given by:

[tex]R=\frac{\rho L}{A}[/tex]

where

[tex]\rho[/tex] is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

1) The first wire has length L and cross-sectional area A. So, its resistance is:

[tex]R_1=\frac{\rho L}{A}[/tex]

2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is

[tex]R_2=\frac{2\rho L}{A}[/tex]

3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is

[tex]R_3=\frac{\rho L}{2A}[/tex]

By comparing the three expressions, we find

[tex]R_3 < R_1 < R_2[/tex]

So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).

Answer:

radio waves, microwaves, infrared, visible, UV, X-rays, gamma rays

Explanation:

Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves travel in a vacuum with a speed of [tex]c=3.0\cdot 10^8 m/s[/tex] (speed of light), and they are classified into 7 different types according to their wavelength.

From longer to shorter wavelength, these types are:

Radio waves (wavelength > 30 cm)

Microwaves (30 cm - [tex]5 \mu m[/tex])

Infrared ([tex]5 \mu - 750 nm[/tex])

Visible light (750 nm - 380 nm)

UV radiation (380 nm - 8 nm)

X-rays (8 nm - 6 pm)

Gamam rays (< 6 pm)

(a) 392 N/m

Hook's law states that:

[tex]F=k\Delta x[/tex] (1)

where

F is the force exerted on the spring

k is the spring constant

[tex]\Delta x[/tex] is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

[tex]F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N[/tex]

- The stretching of the spring is

[tex]\Delta x=15 cm-10 cm=5 cm=0.05 m[/tex]

Solving eq.(1) for k, we find the spring constant:

[tex]k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m[/tex]

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

[tex]F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N[/tex]

And so, the stretch of the spring is

[tex]\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm[/tex]

And since the initial lenght of the spring is

[tex]x_0 = 10 cm[/tex]

The final length will be

[tex]x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm[/tex]

(a) The spring constant of the spring is 392 N/m

(b) Length of the spring is 17.5 cm

[tex]\texttt{ }[/tex]

Hooke's Law states that the length of a spring is directly proportional to the force acting on the spring.

[tex]\boxed {F = k \times \Delta x}[/tex]

F = Force ( N )

k = Spring Constant ( N/m )

Δx = Extension ( m )

[tex]\texttt{ }[/tex]

The formula for finding Young's Modulus is as follows:

[tex]\boxed {E = \frac{F / A}{\Delta x / x_o}}[/tex]

E = Young's Modulus ( N/m² )

F = Force ( N )

A = Cross-Sectional Area ( m² )

Δx = Extension ( m )

x = Initial Length ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial length of spring = Lo = 10 cm

mass of object = m = 2.0 kg

extension of the spring = x = 15 - 10 = 5 cm = 0.05 m

mass of second object = m' = 3.0 kg

Asked:

a. spring constant of the spring = k = ?

b. length of spring = L = ?

Solution:

[tex]F = kx[/tex]

[tex]mg = kx[/tex]

[tex]k = mg \div x[/tex]

[tex]k = 2.0 ( 9.8 ) \div 0.05[/tex]

[tex]\boxed {k = 392 \texttt{ N/m}}[/tex]

[tex]\texttt{ }[/tex]

[tex]F' = kx'[/tex]

[tex]m' g = k x'[/tex]

[tex]x' = ( m' g ) \div k[/tex]

[tex]x' = ( 3.0 (9.8) ) \div 392[/tex]

[tex]x' = 0.075 \texttt{ m} = 7.5 \texttt{ cm}[/tex]

[tex]\texttt{ }[/tex]

[tex]L = Lo + x'[/tex]

[tex]L = 10 + 7.5[/tex]

[tex]\boxed {L = 17.5 \texttt{ cm}}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: College

Subject: Physics

Chapter: Elasticity

A process occurs in which a system's potential energy increases while the environment does work on the system. The kinetic energy of a system decreases while its potential energy and thermal energy are unchanged.

Kinetic energy is the energy which is present in the body of an object which is under motion. Kinetic energy of an object transforms into potential energy and in the form of work when the object changes its state of motion to rest.

When a process occurs, the potential energy of the system increases while the environment does some work on the system. In this case, the kinetic energy of the object decreases while the potential energy and thermal energy of the system remains unchanged. This is because kinetic energy is used in doing work.

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Your question is incomplete, most probably the complete question is:

A process occurs in which a system's potential energy increases while the environment does work on the system. Does the system's KINETIC energy increase, decrease, or stay the same?

Answer:

10 m/s

Explanation:

The speed of a wave is given by

[tex]v=\lambda f[/tex]

where

[tex]\lambda[/tex] is the wavelength

f is the frequency

For the wave in this problem,

- The frequency is given by the number of oscillations per second, so

[tex]f=\frac{2 cycles}{1 s}=2 Hz[/tex]

- The wavelength is

[tex]\lambda=5 m[/tex]

So, the wave speed is

[tex]v=(5 m)(2 Hz)=10 m/s[/tex]

The speed of the water wave is calculated using the formula speed = frequency × wavelength. With a frequency of 2 Hz and a wavelength of 5 meters, the wave speed is 10 m/s.

The student's question is about calculating the speed of a water wave based on the given wavelength and the frequency of an object oscillating on the water's surface. To find the wave speed, we can use the formula speed = frequency × wavelength. Given that the object completes 2 cycles per second (which is the frequency), and the wavelength is 5 meters, we simply multiply the two values.

Speed = Frequency × Wavelength = 2 Hz × 5 m = 10 m/s

Therefore, the speed of the water wave is 10 meters per second (m/s).

The advancements in television and communication technologies during the 1950s and 1960s revolutionized entertainment, news consumption, and long-distance communication by the creation of a shared experience and offering better and cheaper services.

One of the major results of technological advancements like television and satellites revolutionizing life in the 1950s and 1960s was a transformation in modes of communication and entertainment. With the accessibility and popularity of television soaring during this period, there was a shift in the way people consumed news, entertainment and information. In the early 1950's, only around 9 percent of U.S households had a TV which rocketed to approximately 65 percent in just five years. This widespread distribution of television sets played an instrumental role in uniting people through shared experiences whether it was news broadcasts or popular TV shows. A sense of a national, and even global, community was formed through these shared experiences in real-time.

Another crucial impact was the innovations in communication technologies such as microwave transmission and satellites, allowing phone calls to be made in a wireless mode. More affordable and superior quality telephonic communication, especially for long-distance calls, was facilitated. Therefore, the technology of this era not only influenced entertainment and news consumption but also significantly improved communication.

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Answer:

[tex]4.7\cdot 10^6 Pa[/tex]

Explanation:

The total force exerted by the man on the chair is equal to his weight:

[tex]F=W=mg[/tex]

where m=95.0 kg is the man's mass and g=9.8 m/s^2. Substituting,

[tex]F=(95.0 kg)(9.8 m/s^2)=931 N[/tex]

Since there are 4 legs, we can assume that the force is equally distributed over the 4 legs; so the force supported by each leg is

[tex]F=\frac{931 N}{4}=232.8 N[/tex]

The radius of each leg is [tex]r=0.400 cm=0.004 m^2[/tex], so the area of each leg is

[tex]A=\pi r^2 = \pi (0.004 m)^2=5\cdot 10^{-5} m^2[/tex]

And the pressure exerted on each leg is equal to the ratio between the force supported by each leg and the area:

[tex]p=\frac{F}{A}=\frac{232.8 N}{5\cdot 10^{-5} m^2}=4.7\cdot 10^6 Pa[/tex]

The pressure on each leg is 4655kNm-2.

The term pressure is defined as the ratio of force per unit area. Firts we have to find the force acting on the chair and the area covered by the force.

The force acting on the ground is the weight of the man and the chair.

F = W = mg = 95.0 kg * 9.8 ms-2 = 931 N.

Since this force is evenly distributed, the force on each leg = 931/4 = 232.75 N

The area of each leg = πr^2 = 3.142 * (0.4 * 10^-2)^2 = 5 * 10^-5 m^2

Pressure = force/area = 232.75 N/ 5 * 10^-5 m^2 = 4655kNm-2

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(a) [tex]4.26\cdot 10^5 V/m[/tex]

In a velocity selector, the speed of the beam is related to the magnitude of the electric field and of the magnetic field by the formula:

[tex]v=\frac{E}{B}[/tex]

where

E is the magnitude of the electric field

B is the magnitude of the magnetic field

In this problem, we have

[tex]B=0.115 T[/tex] (magnetic field)

[tex]v=3.7\cdot 10^6 m/s[/tex] (speed of the particles)

Solving the equation for E, we find the electric field:

[tex]E=vB=(3.7\cdot 10^6 m/s)(0.115 T)=4.26\cdot 10^5 V/m[/tex]

(b) 3.2 kV

The relationship between electric field and potential difference between the two plates is:

[tex]V=Ed[/tex]

where, in this problem:

[tex]E=4.26\cdot 10^5 V/m[/tex] is the magnitude of the electric field

[tex]d=0.75 cm=0.0075 m[/tex] is the separation between the plates

Substituting into the equation, we find the potential difference:

[tex]V=(4.26\cdot 10^5 V/m)(0.0075 m)=3195 V=3.2 kV[/tex]

A large elliptical galaxy

Answer:

A Super Massive black hole

Explanation:

Answer:

The current halves

Explanation:

The relationship between voltage, current and resistance in a circuit is given by Ohm's law:

[tex]V=RI[/tex]

where

V is the voltage

R is the resistance

I is the current

We can rewrite the formula as

[tex]I=\frac{V}{R}[/tex]

we see that I is directly proportional to V and inversely proportional to R.  In this problem, V is held constant while R is doubled:

[tex]R'=2R[/tex]

so, the new current in the circuit will be

[tex]I'=\frac{V}{R'}=\frac{V}{2R}=\frac{1}{2}I[/tex]

So, the current halves.

The answer is B

Bimetallic strip is used to create a bimetallic coil for a thermometer which reacts to the heat from a lighter, by uncoiling and then coiling back up when the lighter is removed.

A Bimetallic Coil is formed from two pieces of different metals stuck together lengthwise.

Option A

Explanation:

It is formed with two metal pieces that are stuck together in proper length. It is also called bimetallic strip which is mainly used for converting temperature into mechanical displacement. This coil or strip is consist of two different metal that are "steel and copper" or "steel and brass". With "riveting", welding and brazing the strip in the metals are joined length wise together. The displacement in the sideways of strips is more than smaller length ways expansion. The effect produced is used is basically used in mechanical and electrical devices.

Answer:

2639 N

Explanation:

The impulse on the baseball is given by:

[tex]I=F \Delta t[/tex] (1)

where F is the force exerted on the ball and [tex]\Delta t[/tex] the contact time between the bat and the ball.

The impulse is also equal to the change in momentum of the ball:

[tex]I=\Delta p = m (v-u)[/tex] (2)

where m is the ball's mass, v is its final velocity, u is its initial velocity.

By using (1) and (2) simultaneously we can write an expression for F, the force exerted on the ball:

[tex]F=\frac{m(v-u)}{\Delta t}[/tex]

where:

m = 0.145 kg

u = 35.0 m/s

v = -56.0 m/s

[tex]\Delta t=5.00 \cdot 10^{-3}s[/tex]

Substituting,

[tex]F=\frac{(0.145 kg)((-56.0 m/s)-35.0 m/s)}{5.00\cdot 10^{-3} s}=-2639 N[/tex]

and the negative sign means that the force is simply in the opposite direction to the ball's initial direction.

Answer:

[tex]8.4\cdot 10^{-13} N[/tex]

Explanation:

The magnitude of the magnetic force on the proton is given by:

[tex]F=qvB sin \theta[/tex]

where:

[tex]q=1.6\cdot 10^{-19} C[/tex] is the proton charge

[tex]v=4.2\cdot 10^6 m/s[/tex] is the proton velocity

[tex]B=2.5 T[/tex] is the magnetic field

[tex]\theta=30^{\circ}[/tex] is the angle between the direction of v and B

Substituting into the formula, we find

[tex]F=(1.6\cdot 10^{-19}C)(4.2\cdot 10^6 m/s)(2.5 T) sin 30^{\circ}=8.4\cdot 10^{-13} N[/tex]

Answer:

KE = 0.16 J

Explanation:

As we know that total energy is always remains conserved

so here we can say that initial potential energy stored in the spring is equal to the kinetic energy of the object when it comes to relaxed state

So here we have

[tex]U = \frac{1}{2}kx^2[/tex]

here we know that

[tex]k = 125 N/m[/tex]

x = 0.05 m

now from above equation

[tex]U = \frac{1}{2}(125)(0.05)^2[/tex]

[tex]U = 0.16 J[/tex]

so total potential energy here is same as the final kinetic energy which is 0.16 J

Answer:

1. 5.12068 × 1011 N/C away from the proton

Explanation:

The electric field produced by a single point charge is given by:

[tex]E=k\frac{q}{r^2}[/tex]

where

k is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

[tex]q=1.6\cdot 10^{-19}C[/tex] is the charge of the proton

[tex]r=5.3\cdot 10^{-11} m[/tex] is the distance at which we want to calculate the field

[tex]k=8.99\cdot 10^9 Nm^2C^{-2}[/tex] is the Coulomb's constant

Substituting into the formula,

[tex]E=(8.99\cdot 10^9 Nm^2C^{-2})\frac{1.6\cdot 10^{-19}C}{(5.3\cdot 10^{-11}m)^2}=5.12068\cdot 10^{11} N/C[/tex]

And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is

1. 5.12068 × 1011 N/C away from the proton

The magnitude of the electric field set up by the proton at the position of the electron in a hydrogen atom is approximately 5.14 x 10¹¹ N/C. This is based on the formula for the electric field E = kQ/r². The direction of the electric field is away from the proton.

The electric field created by a charge is given by the formula E = kQ/r², where Q is the charge, r is the distance, and k is the Coulomb constant. In this case the magnitude of the charge of a proton (Q) is +1.602 x 10⁻¹⁹ C, the average distance (r) between a proton and an electron in a hydrogen atom is 5.3 x 10⁻¹¹ m, and the Coulomb constant (k) is 8.99 x 10⁹ N.m²/C².

Using these values in the formula gives E = (8.99 x 10⁹ N.m²/C²)(1.602 x 10⁻¹⁹ C)/(5.3 x 10⁻¹¹ m)² = 5.14 x 10¹¹ N/C. Therefore, the magnitude of the electric field set up by the proton at the position of the electron is approximately 5.14 x 10¹¹ N/C.

As for the direction of the electric field, electric field lines point in the direction that a positive test charge would move if placed in the field. Since the proton has a positive charge, the field lines (and hence the direction of the electric field) point away from the proton. So, the correct answer is ~5.14 x 10¹¹ N/C away from the proton.

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Answer:

255.4 N/m

Explanation:

We can consider the system eyeball-attached to the musculature as a mass-spring system in simple harmonic motion, whose frequency of oscillation is given by

[tex]f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}[/tex]

where in this case, we know:

f = 29 Hz is the frequency of oscillation

k is the spring constant, which is unknown

m = 7.7 g = 0.0077 kg is the mass of the eyeball

Solving the equation for k, we find the spring constant of the musculature attached to the eyeball:

[tex]k=(2\pi f)^2 m=(2 \pi (29 Hz))^2 (0.0077 kg)=255.4 N/m[/tex]

To find the effective spring constant of the musculature attached to the eyeball, use the formula k = (4π²m)/(frequency²)

To determine the effective spring constant of the musculature attached to the eyeball, we can use the formula for the resonant frequency of a mass-spring system:

frequency = 1 / (2π√(m/k))

where m is the mass of the eyeball and k is the spring constant. Rearranging the formula, we can solve for k:

k = (4π2m)/(frequency2)

Plugging in the values, we have m = 7.7 g and frequency = 29 Hz:

k = (4π2(7.7 g))/(29 Hz)2

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To calculate the electromagnetic energy contained in a given space just above the Earth's surface, multiply the intensity of the sunlight by the volume of the space. In this case, the energy is 8.40 × 10^3 W.

The electromagnetic energy contained in a given space can be calculated by multiplying the intensity of the sunlight by the volume of the space.

Given that the intensity of sunlight is 1.40 × 10^3 W/m² and the volume of the space is 6.00 m³, we can calculate the electromagnetic energy as follows:

Energy = Intensity × Volume

Energy = (1.40 × 10^3 W/m²) × (6.00 m³)

Energy = 8.40 × 10^3 W

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To begin to lift the car, a hydraulic jack must produce more than 9,800N of force.

To keep the car in position once it is lifted, the jack must produce exactly 9,800N of force.

Answer:

To begin to lift the car, a hydraulic jack must produce more than 9,800N of force.

To keep the car in position once it is lifted, the jack must produce exactly 9,800N of force.

I shall draw this out as these tend to be answered best visually

A pure substance because it cannot be separated into parts

Answer:

The Biot-Savart law

Explanation:

Answer:

The Biot-Savart law

Explanation:

Answer:

[tex]2.6 ^{\circ}C[/tex]

Explanation:

First of all, we need to calculate the penny's kinetic energy before hitting the ground. This is given by

[tex]K=\frac{1}{2}mv^2[/tex]

where m = 5.25 g = 0.00525 kg is the penny's mass and v = 3.27 m/s is its speed. Substituting,

[tex]K=\frac{1}{2}(0.00525 kg)(3.27 m/s)^2=0.028 J[/tex]

When the penny hits the ground, all this energy is converted into internal energy of the penny and the ground. If only half is converted into penny's internal energy, its increase in internal energy is

[tex]\Delta U= \frac{0.028 J}{2}=0.014 J[/tex]

And its formula is

[tex]\Delta U=m C_s \Delta T[/tex]

where m is the penny's mass, Cs its specific heat capacity (2.03 J/gC) and [tex]\Delta T[/tex] the increase in temperature. Solving for the last term,

[tex]\Delta T=\frac{\Delta U}{m C_s}=\frac{0.028 J}{(0.00525 kg)(2.03 J/gC)}=2.6 ^{\circ}C[/tex]

This is chemical energy the substance that makes it glow are chemicals.

Answer:

Chemical .

Explanation:

On Halloween, you take a glow stick, crack the capsule inside and shake it until it glows. This is an example of light energy being created from ___________________ energy

From the principle of the conservation of energy which states that energy can neither be created nor destroyed but can converted from one form to another

Phenyl oxalate ester is responsible for the luminescence in a glow stick.When it reacts with hydrogen peroxide, the liquid inside a glow stick to glow.

therefore we can say that chemical energy is been converted to light energy

the glow lights are by no means radioactive. it can be made to glow again by putting it in a freezer.

Given the data in the question;

Electricity used; [tex]E = 1000kWh = 36*10^8J[/tex]

Time; [tex]t = 1 month = 2.592 * 10^6s[/tex]

Voltage;  [tex]V = 120V[/tex]

Calculate the average rms current to the house.

First we determine the power

Power is the amount of energy transferred per unit time:

[tex]Power = \frac{E}{t}[/tex]

So we substitute in our values

[tex]Power = \frac{36*10^8J}{2.592*10^6s}\\\\Power = 1.388 * 10^3 J/s \\\\Power = 1.388 * 10^3 W[/tex]

Next we Calculate the Current

From Ohms Law:

[tex]P = I * V[/tex]

We substitute in our values

[tex]1.388*10^3W = I \ *\ 120V \\\\I = \frac{1.388*10^3W}{120V} \\\\I = 11.57 W/V\\\\I = 12A[/tex]

Therefore, the average rms current in the power line to the house is 12A

The resistance of a household

From Ohm's Law:

[tex]R = \frac{V}{I}[/tex]

We substitute in our values

[tex]R = \frac{120V}{12A}\\\\R = 10ohms[/tex]

Therefore, The average resistance of a household is 10Ω.

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Answer:

= 3.869 × 10^-6 J/m³

Explanation:

Intensity is given as W/m^2 which is equivalent to J/ (s*m^2)

Speed of light is 2.99792 × 10^8 m/s.

Therefore;

Electromagnetic energy per cubic meter = Intensity/speed of light

      = 1160 J/ (s*m³)/ 2.99792 × 10^8 m/s.

      = 3.869 × 10^-6 J/m³

Answer;

30.6 m

Explanation;

All objects accelerate at the constant rate in the Earth's gravitational field. The gravitational acceleration, g = 9.8 m/s².

Distance traveled by an object falling down under a constant acceleration will be given the formula;

s = ut² + 1/2(gt²); but u the initial velocity is o

thus;

S =1/2(gt²)

  = 0.5 × 9.81 × 2.5 ²

  = 30.65

  ≈ 30.6 m

Answer:

612.2 m

Explanation:

The work needed to lift the object is equal to its increase in gravitational potential energy:

[tex]W=\Delta U=mg \Delta h[/tex] (1)

where

m = 1.0 kg is the mass

g = 9.8 m/s^2

[tex]\Delta h[/tex] is the vertical distance

The power provided is

[tex]P=0.10 kW = 100 W[/tex]

In one minute (t = 1 min = 60 s), the work provided is

[tex]W=Pt=(100 W)(60 s)=6000 J[/tex]

Substituting this into (1) and solving for [tex]\Delta h[/tex], we find

[tex]\Delta h=\frac{W}{mg}=\frac{6000 J}{(1.0 kg)(9.8 m/s^2)}=612.2 m[/tex]

The amount of energy needed to power a 0.10-kW bulb for one minute is equivalent to the work done in lifting a 1.0 kg object through a vertical distance. The distance is calculated using the formula Work = Force * Distance. The distance is found to be 0.61 meters.

The amount of energy needed to power a 0.10-kW bulb for one minute is 6 Joules. This energy is equivalent to the work done in lifting a 1.0 kg object through a vertical distance. To calculate the distance, we can use the formula:

Work = Force * Distance

In this case, the force is equal to the weight of the object, which is 1.0 kg * 9.8 m/s² (acceleration due to gravity). So, the distance is equal to:

Distance = Work / (Force * Acceleration due to gravity)

Substituting the values, we get:

Distance = 6 J / (1.0 kg * 9.8 m/s²) = 0.61 meters

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