Why is it important to form sparingly soluble salt in gravimetric analysis?

Final answer:

To find the mass of barium in a 620 mg tablet of barium sulfate, multiply the tablet's mass by the percentage of barium (58.8%). The calculation yields approximately 364.56 mg of barium in the tablet.

Explanation:

The question is asking to calculate the mass of barium present in a 620 mg tablet of barium sulfate, a compound known for its use in medical imaging. Given that barium sulfate is 58.8% barium by mass, we can calculate the mass of barium in the tablet by multiplying the total mass of the tablet by the percentage of barium.

To find the amount of barium, we use the following calculation:

Mass of barium = (mass of barium sulfate tablet) x (percentage of barium) / 100%

Mass of barium = (620 mg) x (58.8%) / 100

Mass of barium = 620 mg x 0.588

Mass of barium ≈ 364.56 mg

Therefore, a 620 mg tablet of barium sulfate contains approximately 364.56 mg of barium.

The formula weight of a compound is simply equal to the total molar mass.

The molar mass of each elements are:

Mg = 24.305 g/mol

N = 14.0067 g/mol

O = 15.999 g/mol

So the total molar mass is:

formula weight = 24.305 + 2 (14.0067) + 6 (15.999)

formula weight = 148.3 g/mol

Final answer:

The formula weight of magnesium nitrate, Mg(NO3)2, is 148.341 g/mol when calculated using the atomic weights of magnesium, nitrogen, and oxygen and summing them up according to the numbers of atoms in the compound.

Explanation:

The formula weight of magnesium nitrate, Mg(NO3)2, is calculated by adding together the atomic weights of all the atoms in the compound.

The atomic weight of magnesium (Mg) is 24.305 g/mol, nitrogen (N) is 14.007 g/mol, and oxygen (O) is 15.999 g/mol. Given that there are two nitrate groups, we multiply the weights of nitrogen and oxygen accordingly.

Therefore, the formula weight of magnesium nitrate is 148.341 g/mol, expressed to four significant figures with the appropriate units (g/mol).

Answer:

I would use calorimetry to determine the specific heat.

I would measure the mass of a sample of the substance.

I would heat the substance to a known temperature.

I would place the heated substance into a coffee-cup calorimeter containing a known mass of water with a known initial temperature. I would wait for the temperature to equilibrate, then calculate temperature change. I would use the temperature change of water to determine the amount of energy absorbed. I would use the amount of energy lost by substance, mass, and temperature change to calculate specific heat.

Explanation:

Answer on Edg 21'

Precautions must be considered when introducing a mixture of compounds onto a liquid chromatography column to ensure accurate separation.

When introducing a mixture of compounds onto a liquid chromatography column, there are several precautions that must be taken to ensure accurate separation. First, the sample should be introduced as a narrow band at the top of the column. This helps to maintain the initial concentration profile and prevent broadening of the bands. Second, the solvents used in the mobile phase should be compatible with the stationary phase and solutes to avoid any interactions that could affect separation. Finally, the column should be equilibrated with the mobile phase before introducing the sample to ensure consistent separation.

To solve for the number of molecules, we need to first find the number of moles. Assuming ideal gas, we use the formula:

n = PV / RT

where P is pressure = 780 mmHg, V is volume = 300 mL = 0.3 L, T is temperature = 135°C = 408.15 K, R is gas constant = 62.36367 L mmHg / mol K

n = (780 mmHg) (0.3 L) / (62.36367 L mmHg / mol K) (408.15 K)

n = 9.19 x 10^-3 mol

Using Avogadros number, we calculate the number of molecules.

molecules = 9.19 x 10^-3 mol * 6.022 x 10^23 molecules / mol

molecules = 5.54 x 10^21 molecules

[tex]\boxed{{5{.4 \times 1}}{{\text{0}}^{{\text{21}}}}\;{\text{molecules}}}[/tex] of nitrogen are present in a 300 mL container at 780 mm Hg and [tex]135\;^\circ{\text{C}}[/tex].

Further Explanation:

An ideal gas contains a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is considered as the equation of state for any hypothetical gas. Here, we assume nitrogen to be an ideal gas. So the expression for the ideal gas equation of nitrogen is as follows:

[tex]{\text{PV}} = {\text{nRT}}[/tex]                                    ......(1)

Here, P is the pressure of nitrogen.

V is the volume of nitrogen.

T is the absolute temperature of nitrogen.

n is the number of moles of nitrogen.

R is the universal gas constant.

Rearrange equation (1) to calculate the number of moles of nitrogen.

[tex]{\text{n}} = \frac{{{\text{PV}}}}{{{\text{RT}}}}[/tex]        ......(2)

Firstly, the temperature is to be converted into K. The conversion factor for this is,

[tex]{\text{0 }}^\circ {\text{C}} = {\text{273 K}}[/tex]

So the temperature of nitrogen is calculated as follows:

[tex]\begin{aligned}{\text{Temperature}}\left( {\text{K}}\right)&=\left({135 + 273} \right)\;{\text{K}}\\&=408\;{\text{K}}\\\end{aligned}[/tex]

Also, the volume is to be converted into L. The conversion factor for this is,

[tex]{\text{1 mL}}={\text{1}}{{\text{0}}^{ - 3}}{\text{ L}}[/tex]

So the volume of nitrogen is calculated as follows:

[tex]\begin{aligned}{\text{Volume}}\left({\text{L}}\right)&=\left({{\text{300 mL}}} \right)\left({\frac{{{{10}^{ - 3}}{\text{L}}}}{{{\text{1 mL}}}}}\right)\\&=0.3\;{\text{L}}\\\end{aligned}[/tex]

The pressure of nitrogen is 780 mm Hg.

The volume of nitrogen is 0.3 L.

The temperature of nitrogen is 408 K.

The universal gas constant is 62.36367 L mmHg/mol K.

Substitute these values in equation (2).

[tex]\begin{aligned}{\text{n}}&=\frac{{\left({{\text{780 mm Hg}}}\right)\left({{\text{0}}{\text{.3 L}}} \right)}}{{\left({{\text{62}}{\text{.3637 L mm Hg/K mol}}}\right)\left( {{\text{408 K}}}\right)}}\\&={\text{0}}{\text{.009196 mol}}\\&\approx {\text{0}}{\text{.009 mol}}\\\end{aligned}[/tex]

According to Avogadro law, one mole of any substance contains  [tex]{\text{6}}{\text{.022}}\times{\text{1}}{{\text{0}}^{{\text{23}}}}[/tex] molecules.

So the number of molecules of nitrogen is calculated as follows:

[tex]\begin{aligned}\text{Number of molecules of nitrogen}&=\left(0.009\text{ mol}\right)\left(\dfrac{6.022\times 10^{23}\text{molecules}}{1\text{mol}}\right)\\&=5.4198\times 10^{21}\text{ molecules}\\&\bf \approx5.4\times 10^{21}\text{\bf molecules} \end{aligned}[/tex]

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas, pressure, volume, absolute temperature, equation of state, hypothetical, universal gas constant, moles of nitrogen, 780 mm Hg, pressure of nitrogen, 780 mm Hg, volume of nitrogen, 0.3 L, temperature of nitrogen, 408 K, universal gas constant, 62.36367 L mmHg/mol K.

This reaction is most likely to fall under SN2 because the thing called carbonication does not occur in SN1. The carbon forms a partial bond with the nucleophile during the intermediate phase and the leaving group. So for this question the reaction will fall under SN2.

Substitution reactions are characterized by the replacement of one or more hydrogen atoms in an alkane with different atoms or groups, without breaking carbon-carbon bonds. These reactions can demonstrate first order behavior and can also be involved in the process of preparing insoluble salts from soluble ones.

The subject of this discussion is a type of chemical reaction known as a substitution reaction. In this type of reaction, one or more of an alkane's hydrogen atoms are replaced by a differing atom or group of atoms, without altering any carbon-carbon bonds. An example of this can be found in the reaction between ethane and molecular chlorine.

The stoichiometry of a homogeneous reaction like this outlines the rates for the consumption of reactants and the formation of products. This process could potentially represent a unimolecular elementary reaction. Interestingly, the rate law derived from this compares to the rate law derived experimentally for the overall reaction, which exhibits first-order behavior.

Substitution reactions can also involve soluble salts to prepare insoluble salts. An example of this is seen with the covalent oxides of the transition elements reacting with hydroxides to form salts containing oxyanions of the transition elements.

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Answer is: Solid is represented when pulled slowly, liquid when pulled fast, gas when pulled vigorously.

For example, nitrogen molecules have weakest intermolecular bonds in gas phase and move fast and without order.

Cooling is change from liquids to solids. In solid state (for example ice) movement of molecules is more slow than movement of molecules in liquids (for example water).

In solid, molecules are closely packed, stiff and do not changes of shape or volume. Solid object (for example iron) does not take on the shape of its container.  

Liquids have definite volume, but no fixed shape.  

Gases (for example nitrogen and neon) not have definite volume and fixed shape, it depends on its container.

Answer:

Solid is represented when pulled slowly, liquid when pulled fast, gas when pulled vigorously.

Explanation:

Hello,

The three states of matter could be distinguished via their molecular both arrangement and movement, in such a way, solids have an organized assembly of molecules that slightly and slowly move with respect to their equilibrium position, that is why the solid is represented when the string is pulled slowly, besides of their well-defined shape.

Secondly, liquids have a widespread longer distance between molecules and faster molecular movements which cause the liquid to have an indefinite shape, thus, the liquid is represented when the string is pulled fast.

Finally, the molecular arrangement in gases is "messy" as long as the molecules are in constant rapid motion causing both the crashing to each other and the indefiniteness of their shape. In such a way the gas is represented when the string is pulled vigorously.

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Crucible tongs are mandatory to handle hot crucibles to avoid skin burns and accidents during experimental procedures. Crucible tongs work with the crucible; their shape was designed to firmly hold it to avoid spills.

Touching the magnesium metal can actually contaminate it and bring with it impurities which may not be removed by heating. So this leads to error in weighing.

There are two reasons not to touch the crucible tong with bare hands:

1. The crucible tong is used during firing so it is extremely hot and may burn your hands

2. Any impurities in your hand may contaminate the tong hence leading to error just like the case for the magnesium metal

The BF3 molecule forms a trigonal planar configuration because boron, the central atom, is surrounded by three fluorine atoms. As a result, the bond angles in this molecule are exactly 120 degrees.

The bond angles in a BF3 molecule, or boron trifluoride, are determined by its molecular structure. This molecule is arranged in a trigonal planar configuration, and hence the bond angles are exactly 120 degrees.

Let's dive a bit deeper - in geometry any three points in a plane can form an equilateral triangle if they are equidistant from each other. Similarly, in BF3 molecule, the boron atom is at the center and the three fluorine atoms are located at the corners of an equilateral triangle.

Since all angles in an equilateral triangle are 60 degrees and the bond angle is the angle between two consecutive sides, it is twice as much, or 120 degrees.

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The bond angles in BF3 are 120°; the molecule's geometry is trigonal planar and highly symmetrical, resulting in a dipole moment of zero. BF3 also tends to bond with a fluoride ion to form BF4-, which is more stable.

The value of the bond angles in BF3 is 120°, which corresponds to the molecular geometry known as trigonal planar. Each fluorine atom is positioned at the vertices of an equilateral triangle around the central boron atom, and all bonds are equal in length, and the molecule is highly symmetrical.

Additionally, BF3 has a net dipole moment of zero due to this symmetry. However, BF3 often forms a bond with a fluoride ion, resulting in the formation of BF4−, which completes boron's octet and is more stable.

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The triple bond is present in hydrocarbons alkyne.The shape of a molecule with triple bond is linear shape. Therefore, option B is correct.

The triple bond contain three covalent bond. A covalent bond of bond order is 3, it is consisting of six electrons. Therefore, one pair in a sigma bond and the other pairs in pi bonds present in it.

Alkynes are hydrocarbons in which carbon-carbon triple bonds are present. Their general formula is CnH2n-2 for molecules with one triple bond. Atoms form triple bonds with one another by sharing three pairs of electrons.

Triple-bonded carbons are sp-hybridized, and they have linear shapes. And its bond angle is 180° to each other.

Thus, The shape of a molecule with triple bond is linear shape, option B is correct.

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Final answer:

The speed of an electron in the nth Bohr orbit of hydrogen is shown to be αc/n by equating the centripetal force to the Coulomb force. This principle extends to hydrogen-like atoms, where the speed becomes Zαc/n for a nucleus with charge Ze.

Explanation:

To demonstrate that the speed of an electron in the nth Bohr orbit of hydrogen is αc/n, where α is the fine structure constant, we start from the principle that the centripetal force required for an electron to move in a circular orbit is provided by the Coulomb force. For a hydrogen-like atom with a nucleus of charge Ze, the centripetal force is given by mev²/rn and the Coulomb force by k(Ze)(e)/rn². By setting these two forces equal, mev²/rn = k(Ze)(e)/rn², we can cancel rn and one charge e to find an expression for v, the electron speed.

To find the speed of an electron in a hydrogen-like atom with nuclear charge Ze, the same process is followed, but with Z = 1 replaced by the actual Z value. Noting that α = ke²/(hc) and rearranging the terms, we determine that the electron speed v = αc/n for a hydrogen atom (Z=1). For a hydrogen-like atom with a nuclear charge of Ze, the speed would be v = Zαc/n.

Inside the framework of electrochemistry, the Nernst equation is used to calculate the theoretical cell voltage difference. The Nernst equation shows the variation of cell potential from its standard state and uses the ion concentration values of cell #5 and cell #3.

The calculation of the theoretical cell voltage difference between cells #5 and #3 can be understood within the context of electrochemistry where the Nernst equation becomes a cornerstone.

The Nernst equation, written as Ecell = Ecell - (0.0257/n)*logQ, explains the variations in redox potentials (cell potentials) from the standard state values, where n denotes the number of electrons transferred, and Q represents the reaction quotient. This equation is used in practice to calculate Ecell, the potential of a redox system, which differs from its standard state value.

First, you'll need to know the ion concentration values for cells #3 and #5. Then, input those values into the expression. After computing, the resulting value represents the theoretical cell voltage difference between cells #5 and #3.

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A tsunami is a sequence of ocean waves that often originate from the massive volume of water being moved by an underwater earthquake or volcanic eruption.

Undersea disturbance: An underwater earthquake frequently serves as a tsunami's first cause. Strong seismic waves can be produced when tectonic plates in the Earth's crust move or clash.

Displacement of water: The ocean floor frequently moves vertically during an underwater earthquake. A significant volume of water above the bottom is displaced when it rises or falls. This abrupt movement triggers the development of a tsunami.

Tsunami wave generation: Waves propagate outward from the disturbance's epicenter as a result of the water's displacement. These waves have large wavelengths and are initially rather modest, thus they can travel hundreds of kilometres over the ocean.

Wave propagation: The tsunami waves may move quickly, frequently topping hundreds of kilometres per hour, as they spread across the ocean. Yet, they are difficult to spot in the open ocean because to their typically tiny height, which is frequently less than a metre.

Approaching shallow water: The behaviour of tsunami waves alters drastically as they get closer to shallow coastal regions. The waves are slowed down by the shallower water, and the energy that was once dispersed along the wavefront is now concentrated in a smaller area.

Amplification of wave height: The tsunami wave is compressed when it approaches shallow water, raising the height of the wave. The wave may develop into a massive wall of water from a lengthy, almost unnoticeable swell. One of the riskiest characteristics of a tsunami is the abrupt rise in wave height.

Inundation: The tsunami may inflict extensive destruction when it reaches the coast. The wave's strong momentum and substantial water volume have the potential to flood low-lying coastal communities, destroy buildings, and completely destroy anything in its path.

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Potential energy is the stored energy present in an object due to its position. The energy of the ball after reduction will be 0.98 joules due to the conversion of potential energy into kinetic energy.

Potential is the stored amount of energy possessed by an object relevant to its height or position, whereas kinetic energy is due to the motion possessed by the object.

According to the conservational energy, the potential energy will be equivalent to the kinetic energy and is calculated as,

Given,

m = 0.5 kilograms

g = 9.8  m/s²

h = 2.0 - 1.8 = 0.2m

ΔPE = -ΔKE

mgh = -ΔKE

0.5 x 9.8 (1.8 - 2) = -ΔKE

-0.98 J = -ΔKE

Therefore, kinetic energy is 0.98 J.

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