Wich element is likely to be the most reactive

Answers

Answer 1

Answer:

Fluorine

Explanation:

Fluorine is the most reactive and most electronegative element in the periodic table. It can react with glass so it is impossible to find fluorine in its pure form. It exists in gaseous form even at room temperature and it is the most oxidizing agent. It is a non metal, in metals cesium is the most reactive.

Answer 2

The element that is likely to be the most reactive is hydrogen. The correct option is A.

The most reactive element of the ones listed is probably hydrogen (H). It is extremely reactive due to the fact that its outermost shell contains just one electron.

Oxygen, halogens, and metals are just a few of the substances that hydrogen can interact with quickly.

Covalent bonds can be formed with nonmetals like oxygen, resulting in substances like water. In redox reactions, such as the synthesis of acids and bases, hydrogen also takes part.

Its low atomic mass, which permits quicker diffusion and more frequent collisions with other atoms, further increases its reactivity.

Overall, the electrical structure of hydrogen and its capacity to create stable bonds with other elements are what cause it to be so reactive.

Thus, the correct option is A.

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Your question seems incomplete, the probable complete question is:

Which of the following elements is likely to be the most reactive?

A) Hydrogen (H)

B) Oxygen (O)

C) Neon (Ne)

D) Argon (Ar)


Related Questions

The level of water in an olympic size swimming pool (50.0 meters long, 25.0 meters wide, and about 2.00 meters deep) needs to be lowered 6.50 cm. if water is pumped out at a rate of 4.20 liters per second, how long will it take to lower the water level 6.50 cm

Answers

We need to start by finding the surface area of the pool.
50 meters multiplied by 25 meters gives us 1250 square meters.
1250 square meters multiplied by .065 (6.5 cm in meters) gives us a volume of 81.25 cubic meters of water that needs to be pumped out of the pool.

There are 1000 liters in a cubic meter so this is 81250 liters. Divide by 4.2 to find the number of seconds required to pump out this much water and we get 19345.2 seconds. This equals approximately 5.37 hours.
Final answer:

First, the cubic volume of water to be removed is calculated by multiplying length, width, and reduced depth of the pool. This equates to 81.25 cubic meters, which is 81250 liters. The time is then calculated by dividing total volume by pump rate, equating to 19345 seconds or approximately 5.40 hours.

Explanation:

The subject of this question is related to applied mathematics, specifically about volume and rates.

In order to determine how long it will take to lower the water level in the pool, first, we need to calculate the volume of the water to be removed. The volume can be calculated by multiplying the length, width, and height of the swimming pool. However, since we want the height to be 6.50 cm or 0.065 m, we use that as our height.

Volume = length x width x height = 50.0 m x 25.0 m x 0.065 m = 81.25 cubic meters. Since 1 cubic meter is equivalent to 1000 liters, the volume of water to be removed is 81250 liters.

Given that the pump removes water at a rate of 4.20 liters per second, we can determine the time by dividing the total volume by the rate of the pump.

Time = volume / rate = 81250 liters / 4.20 liters/sec = 19345 seconds or approximately 5.40 hours.

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In what way do acids affect your body?

Answers

everyway, if it touch your skin it can damage it

a ball is thrown straight up it passes a 2.00 m high window 7.5 meters off the ground on its path up it takes 1.3 s to go past the window. what was the balls initial velocity?

Answers

Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s

Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).

Final answer:

The initial velocity of the ball is approximately 14.9 m/s, found using kinematic equations considering the ball's upward motion against gravity over 1.3 seconds to pass a 2.00 m high window.

Explanation:

To determine the initial velocity of a ball thrown straight up, we can use the kinematic equations for uniformly accelerated motion. The ball passes a 2.00 m high window that starts 7.5 meters above the ground, and it takes 1.3 seconds to pass by the window. We'll use the following kinematic equation:

s = ut + 1/2at²

where s is the displacement (the height of the window), u is the initial velocity we want to find, t is the time (1.3 seconds), and a is the acceleration due to gravity (approximately -9.81 m/s², since it's upwards).

Plugging in the values, we have:

2.00 m = u(1.3 s) + 1/2(-9.81 m/s²)(1.3 s)²

Solving for u, the initial velocity of the ball is calculated to be the positive root of the resulting quadratic equation. After performing the algebraic manipulation, we find that the initial velocity is approximately 14.9 m/s.

Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky, the box does not slide around the truck when this happens.What direction is the force acting on the box due to the truck?

Answers

Final answer:

The force acting on a box in the back of a pickup truck, which accelerates forward, is due to static friction and is directed forward. This force ensures the box accelerates at the same rate as the truck, preventing it from sliding.

Explanation:

When a pickup truck accelerates forward, the force acting on a box due to the truck is directed forward. This force is the result of static friction between the box and the bed of the truck. The static friction force prevents the box from slipping by providing the necessary force to accelerate the box at the same rate as the truck. If the truck accelerates to the right, the frictional force acting on the box is also to the right. This force is a reaction to the box's tendency to remain in its state of rest, according to Newton's first law of motion, which says that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

The calculation of the maximum distance the truck can travel without the box sliding involves determining the static frictional force and using it to find the acceleration of the box. Given the coefficient of static friction (μ) is 0.24, and assuming the acceleration of gravity (g) is approximately 9.8 m/s², we use the equation for static friction F_s = μ N, where N is the normal force, equivalent to the weight of the box if we assume a horizontal surface and neglect air resistance.

The key to understanding this problem lies in recognizing the role of static friction in causing the box to accelerate together with the truck, rather than sliding. If the bed of the truck provides sufficient friction, it enables the box to move as one with the vehicle, demonstrating the practical application of Newton's laws of motion.

The force acting on the box due to the truck is directed to the right.

When the pickup truck accelerates to the right, a force is exerted on the box due to the truck bed's friction. Since the bed of the truck is sticky, the box does not slide. The direction of the frictional force acting on the box is also to the right, in the same direction as the truck's acceleration.

Here's a step-by-step explanation:

The truck accelerates to the right.The surface of the truck bed exerts a frictional force on the bottom of the box to prevent it from sliding.This frictional force acts to the right, matching the truck's acceleration direction.According to Newton's third law of motion, every action has an equal and opposite reaction, so the box exerts a force back on the truck bed, but this doesn’t change the direction of the frictional force acting on the box.

Therefore, the force acting on the box due to the truck is to the right.

What is the acceleration of a ball rolling down a ramp that starts from rest and travels 0.9 m in 3 s?

Answers

Given:
u = 0, initial velocity
s 0.9 m, distance traveled.
t = 3 s, the time taken.

Let a =  the acceleration. Then
s = ut + (1/2)*a*t²
(0.9 m) = 0.5*(a m/s²)*(3 s)²
0.9 = 4.5a
a = 0.2 m/s²

Answer: 0.2 m/s²

Final answer:

The acceleration of the ball rolling down the ramp is 0.2 m/s^2, calculated using the equation of motion for uniformly accelerated movement without initial velocity.

Explanation:

To calculate the acceleration of a ball that starts from rest and travels a certain distance down a ramp over a known time period, we can use the equations of motion for uniformly accelerated motion. It is given that the ball travels 0.9 meters in 3 seconds from rest.

The equation that relates distance (s), initial velocity (u), time (t), and acceleration (a) is:


s = ut + \frac{1}{2}at^2

Since the initial velocity u is 0 m/s (because the ball starts from rest), the equation simplifies to:


s = \frac{1}{2}at^2

Rearranging this equation to solve for acceleration yields:


a = \frac{2s}{t^2}

Plugging in the given values:


a = \frac{2 * 0.9 m}{(3 s)^2} = \frac{1.8 m}{9 s^2} = 0.2 m/s^2

Therefore, the acceleration of the ball is 0.2 m/s2.

A 2​-liter ​[l] soda​ bottle, made of​ pet, will fail at approximately 207 ​pound-force per square inch​ [psi] of pressure. if you were to dive straight down into the ocean with a 2​-liter bottle, at what depth in units of feet​ [ft] would the bottle​ fail? assume the specific gravity of ocean water is 1.0251

Answers

I like to solve first in SI units. So convert pressure into Pascal.

P = 207 psi = 1.427x10^6 Pa

 

The formula for hydrostatic pressure is:

P = ρ g h

where ρ is density of ocean water = 1025.1 kg/m^3, g is gravity = 9.81 m/s^2, h is height or depth

1.427x10^6 = 1025.1 * 9.81 * h

h = 141.92 m

Convert meters to inches:

h = 141.92 m = 5587.4 inches

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm.

Answers

Assuming you want the new pressure, PV/T = PV/T , so by extension you'd have (1.9 atm)(12.8 L)/ 365 K = x atm (9.9L)/ 285 K  x= 1.918 atm

Atoms that are alike combine to form the next stage of matter, which is a(n) ____

Answers

Molecule. The answer is molecule. Alike atoms combine to form molecules. An example is Hydrogen molecule which is H₂. Another example is O₂ which is an oxygen molecule. Hope I helped. Good luck

A rocket car is traveling at a constant speed of 250 km/h on a salt flat. the driver gives the car a reverse thrust, and the car experiences a continuous and constant deceleration of 8.25 m/s2. how much time elapses until the car is 175 m from the point where the reverse thrust is applied?

Answers

3.086 seconds.

First, convert 250 km/h into m/s by multiplying by 1000 (to convert km to m) and dividing by 3600 to convert per hour to per second. Doing 250 * 1000 / 3600 gives you a speed of 69.4444 m/s.

Now under constant acceleration, the formula for distance is:

1/2 A T^2

Since A = -8.25 (negative since it's deceleration) we get

1/2 * (-8.25) * T^2

giving

-4.125 T^2

The total distance traveled then becomes the original velocity multiplied by the time plus the distance for the acceleration, giving

69.4444 T - 4.125 T^2 = 175

Doing a bit of reordering, we get a standard looking quadratic equation

-4.125 T^2 + 69.4444 T - 175 = 0

Plugging the values of A = -4.125, B = 69.4444, C=-175 into the quadratic formula gives you two solutions.

First solution is 3.086 seconds

and the second solution is 13.750 seconds.

The physical interpretation of those 2 answers is that 3.086 seconds after the reverse thrust is applied, the vehicle is 175 meters from the spot where the thrust was applied. The vehicle continues to decelerate until it comes to a complete stop. Then the vehicle goes into reverse and after a total of 13.75 seconds, once again is at a point 175 meters from where it had applied the reverse thrust. We can use that information to double check our answer. Namely at the mid point between 3.086 seconds and 13.75 seconds, the rocket car should be motionless. Let's check if that's correct.

(3.086 + 13.75) / 2 = 8.418 seconds

Given a velocity of 69.44444 m/s and a deceleration of 8.25 m/s^2, the vehicle should stop after

69.44444 / 8.25 = 8.418 seconds

Since those two independent calculations of when the vehicle would stop the match, it's a good check that the math is correct.

A mountaintop is a height y above the level ground. A woman measures the angle of elevation of the
mountaintop to be θ when she is a horizontal distance x from the mountaintop. After walking a
distance d closer to the mountain, she measures the angle of elevation of the mountaintop to be φ.
Neglecting the height of the woman’s eyes above the ground, draw a well-labelled diagram
representing this situation and find an expression for the height of the mountain, y, in terms of d, φ,
and θ. Note that your expression cannot contain x.

Answers

Refer to the diagram shown below.
We want to find y in terms of d, φ and θ.

By definition,
[tex]tan (\theta) = \frac{y}{x} \\\\ tan( \phi) = \frac{y}{x-d} [/tex]

Therefore
y = x tan(θ)                   (1)
y = (x - d) tan(φ)           (2)

Equate (1) and (2).
[tex](x - d) \, tan(\phi) = x \, tan(\theta) \\ x[tan(\phi) - tan(\theta)] = d \, tan(\phi) \\ x= \frac{d tan(\phi)}{tan(\phi)-tan(\theta)} [/tex]

From (1), obtain the required expression for y.

Answer:
[tex]y= \frac{d \, tan(\phi) \, tan(\theta)}{tan(\phi)-tan(\theta)} [/tex]

Each of the three plates has a mass of 10 kg. if the coefficients of static and kinetic friction at each surface of contact are μs = 0.3 and μk = 0.2 , respectively, determine the acceleration of each plate when the three horizontal forces are applied.

Answers

Even though you forgot to include the diagram of the problem, I found a similar problem as shown in the top of the picture. The diagrams at the bottom are force diagrams of each plate.

For plate D, the forces acting on it are the horizontal force 18 N, and the opposite frictional force which is equal to uk*W = 0.2(10 kg)(9.81 m/s²) = 19.62 N.
F = ma
19.62 N - 18 N = 10 kg(a)
a = 0.162 m/s²

For plate C, the forces acting on it are: horizontal 100 N, and the two opposite frictional forces from the top and bottom plates D and B.
F = ma
100 N - 2(19.62 N) = (10 kg)(a)
a = 6.076 m/s²

For plate B, because A is not moving, we use us instead of uk.
F = ma
0.3(10 kg)(9.81 m/s²) - 15 N = (10 kg)(a)
a = 2.943 m/s²

Final answer:

To calculate the acceleration of each plate, first find the force of kinetic friction using the mass of the plates and coefficients of friction. The acceleration can then be found by applying Newton's second law, considering the net force on each plate after friction is taken into account.

Explanation:

To determine the acceleration of each plate when three horizontal forces are applied, we first need to understand the role of static and kinetic friction. Given each plate has a mass of 10 kg, we can calculate the normal force (N) exerted by each plate, which is necessary for finding frictional forces. The normal force is equal to the weight of the plate, calculated as N = mg, where m is the mass and g is the acceleration due to gravity (9.8 m/s2). Thus, for a 10 kg plate, N = 10 kg × 9.8 m/s2 = 98 N.

The maximum static friction force that must be overcome to start moving the plate is calculated using Fₛ(max) = μsN, where μs is the coefficient of static friction (0.3). Therefore, Fₛ(max) = 0.3 × 98 N = 29.4 N. Once motion begins, the kinetic friction force applies, calculated using Fₘ = μkN, where μk is the coefficient of kinetic friction (0.2). Therefore, Fₘ = 0.2 × 98 N = 19.6 N. To find the acceleration of each plate, we apply Newton's second law of motion (F = ma), subtracting the kinetic friction force from the applied force, and solving for a.

Without specific values for the applied forces in the question, we've laid out the framework to calculate the acceleration. It's important to subtract the kinetic friction force from the applied force to find the net force before applying Newton's second law.

Category 5e twisted pair can run farther than 100 meters from its source to its final destination, as long as the signal is regenerated at least every ____ meters.

Answers

Cat 5e must be regerated every 100 meters to stay within specification.

When people use plastic combs on their hair, the combs become negatively charged. Which statements about this situation are true?


The comb loses electrons.

The comb gains electrons.

The hair loses electrons.

The hair gains protons.

The hair loses protons.


those above are the choices

Answers

The answer would be:
The comb gains electrons.
The hair loses electrons.

In chemistry, the charge depends on the electrons and protons. The electron will give negative charge and proton will give the positive charge. Proton is located in the nucleus of the atoms so it won't easily move like electron which located in the orbit in the atoms perimeter. So, ignore the option with the proton.
If the combs become negatively charged, that means it gain some electron. Since something gain electron, that means another thing is losing an electron. That electron comes from the hair.

Final answer:

When a plastic comb is run through hair, the comb gains electrons and becomes negatively charged due to the transfer of electrons, which is a result of static electricity caused by friction. The hair loses electrons but does not gain protons or lose protons, as protons do not move freely like electrons.

Explanation:

When people use plastic combs on their hair, the combs can become negatively charged due to static electricity. This happens due to the transfer of electrons from one object to another. In this case, the true statements about the situation are:

The comb gains electrons.

The hair loses electrons.

Protons are not exchanged in static electricity because they are located within the atomic nucleus and do not move freely. Therefore, it is the gain or loss of electrons that causes the static charge. The friction between the comb and the hair can cause electrons to be transferred from the hair to the comb, which is why the comb becomes negatively charged.

Is your textbook the kind of idealized object (described in section on radiation laws) that absorbs all the radiation falling on it? explain. how about the black sweater worn by one of your classmates?

Answers

In the textbook the kind of idealized object that described in section on radiation laws that it absorbs all the radiation falling for it because it is not giving off any radiation on its own. And about the black sweater worn by one of your classmates it goes the same.

A ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. What is the average speed of the ball as it rolls the 10 meters? 1) 2.5m/s 2) 10m/s 3) 12.5m/s 4) 15m/s (Please show calculation)

Answers

Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m

The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²

The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s

The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s

Answer: 12.5 m/s

The average speed of the ball cannot be accurately determined without the total time or rate of deceleration. However, if we are simply looking for the average of the initial and final speeds, it would be 12.5 m/s.

The question involves calculating the average speed of a ball given its initial and final speeds. However, there is a discrepancy in the question as it initially mentions the ball rolls 6.0 meters but then asks for the average speed over 10 meters. Assuming the correct distance is 6.0 meters, the calculation of average speed requires us to know the total distance traveled and the total time taken.

To find the average speed, we use the formula:

Average Speed = Total Distance ÷ Total Time

The total distance traveled by the ball is given as 6.0 meters. Since we do not have the total time, we cannot calculate the average speed directly. Additionally, it's said that the ball's speed changes from 15 m/s to 10 m/s, which means that it is decelerating. However, with the information provided, we cannot accurately determine the ball's average speed without additional details such as the rate of deceleration or the time taken.

Assuming a typo in the question and that it's asking for the average of the initial and final speeds instead, we could simply calculate it by:

Average Speed = (Initial Speed + Final Speed) ÷ 2

In this case:

Average Speed = (15 m/s + 10 m/s) ÷ 2 = 12.5 m/s

However, this calculation assumes a linear change of speed, which might not be the case in a real-world scenario.

What wave phenomenon is responsible for the sunlight shown in this diagram? A.)Diffraction, because light is bent around the clouds B.)Refraction, because the light bends through the clouds C.)Absorption, because the sunlight is absorbed by the clouds D.)Transmission, because the sunlight travels through the clouds

Answers

A) DIFFRACTION, because light is bent around the clouds" is the correct answer.

A.)Diffraction, because light is bent around the clouds

A ball is thrown upward from the ground with an initial speed of 22.0 m/s; at the same instant, another ball is dropped from a building 16 m high. after how long will the balls be at the same height

Answers

they will  be together in 8 minutes

Four 8.5 kg spheres are located at the corners of a square of side 0.52 m. calculate the magnitude and direction of the gravitational force exerted on one sphere by the other three. magnitude

Answers

3.4x10^-8 N of force directly towards the sphere in the opposite corner of the square. The gravitational attraction of two masses towards each other is F = G(m1m2/r^2) where G = gravitational constant m1,m2 = masses r = distance between the centers of the masses. So the force being exerted by the masses alone an edge of the square would be F = 6.674x10^-11 N(m/kg)^2 * ((8.5 kg)^2)/((0.52m)^2) F = 6.674x10^-11 N(m/kg)^2 * (72.25 kg^2)/(0.2704 m^2) F = 6.674x10^-11 N(m/kg)^2 * 267.1967 (kg/m)^2 F = 1.78327x10^-8 N There are 2 masses that affect a mass on a corner so that the sum of their vectors will result in a 3rd vector aiming towards the mass in the diagonal corner. So sqrt(2(1.78327x10^-8 N)^2) = 2.52193x10^-8 N The mass in the diagonal corner will also be attracting. The distance to that mass is sqrt(2*(0.52m)^2) = 0.735391052 m F = 6.674x10^-11 N(m/kg)^2 * ((8.5 kg)^2)/(2*(0.52m)^2) F = 6.674x10^-11 N(m/kg)^2 * (72.25 kg^2)/(0.5408 m^2) F = 6.674x10^-11 N(m/kg)^2 * 133.5984 (kg/m)^2 F = 8.916355x10^-9 N This vector will be along the same line as the combined vector from the other 2 masses, so they'll add directly. F = 8.916355x10^-9 N + 2.52193x10^-8 N = 3.4136x10^-8 N Since we have 2 significant figures in our data, the result rounded to 2 significant figures is 3.4x10^-8 N
Final answer:

The magnitude of the gravitational force exerted on one sphere by the other three can be calculated using Newton's Law of Universal Gravitation. Using the given information, the magnitude of the gravitational force is approximately 2.97 x 10^-8 N.

Explanation:

The magnitude of the gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation:



Fg = (G * m1 * m2) / r2



Where Fg is the gravitational force, G is the gravitational constant (approximately 6.67 x 10-11 Nm2/kg2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.



In this case, the mass of each sphere is 8.5 kg and the distance between their centers is 0.52 m.



Calculating the gravitational force between one of the spheres and the three others, we use the formula and plug in the values:



Fg = (6.67 x 10-11 * 8.5 kg * 8.5 kg) / (0.52 m)2



Calculating the result, the magnitude of the gravitational force exerted on one sphere by the other three is approximately 2.97 x 10-8 N.

If the mirror can be moved horizontally to the left or right, what is the greatest possible distance d from the mirror to the point where the reflected rays meet?

Answers

The greatest possible distance from the mirror to the point where the reflected rays meet is infinite for a flat mirror, as the reflected rays never actually converge, creating a virtual image.

The greatest possible distance d from the mirror to the point where the reflected rays meet would be when the object distance do approaches the focal length f of the mirror from the right side, causing the image distance d to approach negative infinity, indicating that the reflected rays would never converge in real space. This situation describes the formation of a virtual image where the rays appear to come from. In a flat mirror, the focal length is technically at infinity since parallel rays remain parallel after reflection and never actually converge. Therefore, in a practical sense, when considering a flat mirror, the reflected rays appear to converge at a distance behind the mirror equal to the object's distance in front of the mirror, which is defined as d = -do.

The greatest possible distance (d) from the mirror to the point where the reflected rays meet is [tex]\( \frac{L}{2} \)[/tex], which is the focal length of the mirror when it is at the center of the spherical surface.

To understand why the greatest possible distance (d) from the mirror to the point where the reflected rays meet is [tex]\( \frac{L}{2} \)[/tex], let's consider the behavior of light rays reflecting off a mirror.

When a light ray reflects off a mirror, the angle of incidence is equal to the angle of reflection. This means that the path of the light ray before and after reflection are symmetric with respect to the normal to the mirror surface at the point of incidence.

For the reflected rays to meet at a point, they must converge. The best way to visualize this is to consider a light ray that travels parallel to the mirror's surface. After reflection, this ray will appear to come from a point behind the mirror, known as the focal point. The distance from the mirror to this focal point is the focal length of the mirror.

In the case of a flat mirror, the focal length is infinite because parallel rays remain parallel after reflection and do not converge to a single point. However, if we consider a spherical mirror, the focal length (f) is finite and is related to the radius of curvature (R) of the mirror by the equation [tex]\( f = \frac{R}{2} \)[/tex].

Now, let's consider the scenario where the mirror can be moved horizontally. The greatest possible distance (d) from the mirror to the point where the reflected rays meet would occur when the mirror is at the center of the spherical surface it is a part of. At this point, the focal point of the mirror would be at a distance equal to the focal length (f) from the mirror's surface.

Given that the length of the mirror is (L), and the radius of curvature (R) is equal to (L) (since the mirror is a segment of a sphere), we can substitute (R) with (L) in the focal length equation. Thus, the focal length (f) is [tex]\( \frac{L}{2} \)[/tex].

The peripheral nervous system consists of __________ that link the central nervous system with all parts of the body.

Answers

Answer- Communication Lines

The maximum theoretical flow rate (slug/s) through a supersonic nozzle is

Answers

The maximum theoretical flow rate (slug/s) through a supersonic noozzle is
M(max)=2.38(AtP0/v(T0))
Where At (ft^2) is the nozzle throat area, P0 (psi) is the tank pressure, and T0 (0R) is the tank temperature. Is this equation dimensionally correct? If not, find the units of 2.38 term. Write the equation in SI units.

The maximum theoretical flow rate through a supersonic nozzle is determined by the nozzle's design and the properties of the fluid flowing through it.

What is maximum theoretical flow rate?

In supersonic flow, the flow properties change drastically, and the flow behavior is described by compressible fluid dynamics equations, including the Mach number.

The maximum Mach number that can be achieved in a supersonic flow is 1, also known as Mach 1.

Any Mach number greater than 1 corresponds to supersonic flow. The design of the nozzle, specifically its converging and diverging sections, determines how well the flow can be accelerated to supersonic speeds and how efficiently it can expand to match the downstream pressure.

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What is the question that Maria and Elena want to answer by performing an experiment

Answers

might be hypothesis

hopthesis: is a question u find the answer too when you perform an expirment.

:)

Answer:

If there is no text attached. Generally, the answer is Hypothesis.

Explanation:

A hypothesis or system of hypothesis is the core of a research. It's the possible solution to a problem that researchers established when looking for theories or events to prove it.

What is the least amount of time required for a given point on this wave to move from y = 0 to y = 12cm?

Answers

Final answer:

The least amount of time required for a point on a wave to move from y = 0 to y = 12 cm is 12 seconds.

Explanation:

To determine the least amount of time required for a point on a wave to move from y = 0 to y = 12 cm, we need to consider the wave's velocity. Since the wave velocity is constant, the distance the wave travels is the wave velocity times the time interval. Therefore, we can calculate the time required by dividing the distance by the wave velocity.

In this case, we can assume the wave travels 12 cm in the positive y-direction. Let's say the wave velocity is 1 cm/s. To reach 12 cm, it would take 12 / 1 = 12 seconds. So, the least amount of time required for the point on the wave to move from y = 0 to y = 12 cm is 12 seconds.

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If a 50microAmps current is flowing then how many electrons pass a point each minute to 2 sig figs? Please add an explanation as I'm completely lost.

Answers

The equation you need to use is [tex]Q=IT[/tex] where Q is the charge in C, I is the current in Amps and T is the time in seconds.

So we have T = 60s
I = [tex]50 \times 10^-^6[/tex]A
let's work out Q
[tex]Q=IT = (50\times 10^{-6}) \times 60 = 3 \times 10^-^3 [/tex]C
this is the total charge passing a point in a minute so divide by the charge of one electron ([tex]1.6 \times 10^{-19}[/tex]) to find the number of electrons passing the point in a minute which equals [tex]1.875 \times 10^{16}[/tex]
Final answer:

The number of electrons flowing in a current can be found by multiplying the current by the time, and then dividing by the charge of a single electron. Use the value of 50 microamps for current, 60 seconds for time, and 1.6x10^-19 Coulombs for the charge of an electron.

Explanation:

To answer this question, we first need to understand a couple key concepts such as electric current and the charge of an electron. Electric current is defined as the rate at which charge is flowing, and in this case, 50 microamperes microamps) means that there are 50 microCoulombs of charge flowing each second. The charge of an electron is approximately 1.6x10^-19 Coulombs.

Now, we can use these values to calculate how many electrons are flowing in a minute. The first step is to convert minutes to seconds, giving us 60 seconds. Multiply the current (50 microCoulombs or 50x10^-6 Coulombs per second) by the time in seconds (60 seconds). This will tell you how much charge flows in one minute. Finally, divide the total charge by the charge of a single electron (1.6x10^-19 Coulombs) to find the number of electrons. Remember to round your final answer to two significant figures as requested.

Learn more about Electric Current and Charge here:

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At what temperature will the steam start to condense when the container is cooled?

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lower than 100°C, as it is not boiling point

consider a rabbit that is at x=8.1 m a t=0 and moves with a constant velocity of -1.6 m/s. what is the equation of motion for the rabbit?

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Since the rabbit is moving at constant velocity, therefore the acceleration is zero, hence the increase in distance over time would simply be:

x = v t

where v is velocity and t is time, x is distance

 

Since we are starting at x = 8.1 m, the equation of motion would therefore be:

x = 8.1 – 1.6 t

If earth had no landmasses, then the idealized zonal precipitation pattern would have _______.

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If the planet earth has no land masses, the idealized zonal precipitation pattern would likely have regions that are wet in the equator and there will be more of mid-latitudes if the earth has no land masses at all and it does not exist.

Matter's resistance to a change in motion is called _____ and is directly proportional to the mass of an object. For an object to change its state of motion, a force must be applied to it?

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Inertia

A bowling ball has a higher inertia than bowling pins, as it weighs significantly more than the pins.
Inertia is your answer that goes in the blank space

The current in a hair dryer measures 17 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?

Answers

voltage is 238 volts

What's the steady state theory

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Answer:

A theory explaining the model of the Universe.

Explanation:

Steady State theory, proposed in 1948 by Sir Hermann Bondi, Thomas Gold, and Sir Fred Hoyle, suggests that the universe is always expanding while maintaining a constant average density. This is achieved as matter is continuously created to form new stars and galaxies at the same rate as that of old ones becoming non-observable. This occurs as a consequence of increasing distance and velocity of recession of old stars and galaxies.

As per this theory, Universe has no beginning and no end in time. If looked at it from a grand scale, the arrangement of galaxies and average density remain same.

Later observation of the Universe gave results contradictory to Steady State Theory. This has led to increase in support of Big Bang Model of the Universe.

The steady state theory in systems theory means state variables do not change over time, and in chemical kinetics, it refers to the steady-state approximation where an intermediate's concentration is assumed constant, aiding in the analysis of complex reactions.

The steady state theory refers to a concept in systems theory where a system or process is said to be in a steady state if its state variables, which define the behavior of the system, are not changing over time. In the context of chemical kinetics, this often pertains to the steady-state approximation, where the concentration of an intermediate in a reaction is assumed to be constant over time because its formation rate is equal to its consumption rate. This approximation simplifies the mathematical analysis of complex reactions and is particularly useful in enzyme kinetics, as proposed by Briggs & Haldane in 1925.

The steady-state assumption does not imply that the system is static or that there is an absence of reaction fluxes. Rather, it means that even though reactions are occurring and products are being formed, the internal metabolite concentrations and the fluxes (input and output fluxes) are maintained constant over time. This is a critical simplification that aids in metabolic modeling and the analysis of enzymatic reactions.

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