William runs at a constant speed of 8 miles per hour. Running at this constant speed, it takes William 75 seconds to run from his house to school. How many miles did William run?

Answer:

$17.35

Step-by-step explanation:

86.74*.2

Answer:

n= (-m-13)/2

Step-by-step explanation:

look @ photo

Answer: m=-2n-13

               ↗️⬆️↖️

Answer:

$5100 would be $76.50

$4876 would be $73.14

$5215 would be $78.23

$6225 would be $93.38

$5235 would be $78.53

Step-by-step explanation:

To find commissions take your sale price and multiply it by your percentage and divide by 100

Answer: $399.77

Step-by-step explanation:

Answer:

The distance of base of wire to the base of tower is 13.27 ft

Step-by-step explanation:

Given as :

The measure of wire connected between base ad antenna top = 20 ft

The wire is connected to the  antenna on tower at height h = 15 ft above the ground

Let The distance of base of wire to the base of tower = x ft

Let the angle drawn on ground = Ф

Now, According to question

In figure AOB

Sin angle = [tex]\dfrac{\textrm perpendicular}{\textrm hypotenuse}[/tex]

i.e SinФ = [tex]\dfrac{\textrm AB}{\textrm BO}[/tex]

Or,  SinФ = [tex]\dfrac{\textrm h}{\textrm 20}[/tex]

Or,  SinФ = [tex]\dfrac{\textrm 15}{\textrm 20}[/tex]

Or, SinФ = [tex]\dfrac{\textrm 3}{\textrm 4}[/tex]

or, Ф = [tex]sin^{-1}(\frac{3}{4})[/tex]

∴ Ф = 48.5°

Now, Again from figure

Tan angle = [tex]\dfrac{\textrm perpendicular}{\textrm base}[/tex]

i.e TanФ = [tex]\dfrac{\textrm AB}{\textrm OA}[/tex]

Or, Tan 48.5° = [tex]\dfrac{\textrm h}{\textrm x}[/tex]

Or, 1.13 = [tex]\dfrac{\textrm 15}{\textrm x}[/tex]

∴ x = [tex]\dfrac{\textrm 15}{\textrm 1.13}[/tex]

i.e x = 13.27 feet

So, The distance of base of wire to the base of tower = x = 13.27 ft

Hence, The distance of base of wire to the base of tower is 13.27 ft Answer

Final answer:

The other end of the wire will be located approximately √175 ft away from the base of the tower.

Explanation:

To find the distance from the base of the tower to the other end of the wire, we can use the Pythagorean theorem. The wire forms the hypotenuse of a right triangle, with one leg being the height of the antenna and the other leg being the distance from the base of the tower. Let's call this distance 'x'.

Using the Pythagorean theorem, we have:

x² + 15² = 20²

Simplifying this equation, we get:

x² = 20² - 15²

x² = 400 - 225

x² = 175

Taking the square root of both sides, we find:

x = √175

So the other end of the wire will be located approximately √175 ft away from the base of the tower.

Answer:

Step-by-step explanation:

it equals -19

Answer:

The value of the given expression [tex]-16-3=-19[/tex]

Step-by-step explanation:

Given expression is [tex]-16-3[/tex]

To find the value of the given expression:

[tex]-16-3=-16-3[/tex]

Now taking the negative sign (-) outside the terms of the above equation we get,

[tex]-16-3=-(16+3)[/tex]

Now apply the algebraic sum to  the above expression we get,

[tex]=-19[/tex]

Therefore [tex]=-19[/tex]

The value of the given expression is [tex]-16-3=-19[/tex]

Answer:

Step-by-step explanation:

Simplifying

h(x) = x2 + 3x + -18

Multiply h * x

hx = x2 + 3x + -18

Reorder the terms:

hx = -18 + 3x + x2

Solving

hx = -18 + 3x + x2

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Divide each side by 'x'.

h = -18x-1 + 3 + x

Simplifying

h = -18x-1 + 3 + x

Reorder the terms:

h = 3 + -18x-1 + x

Answer:

h(x)= (x+3/2 ) ^2  −  81/4

​

Step-by-step explanation:

Its correct :)

The portion of cake Mike ate is 1/6.

The numbers given are expressed as fractions. Fractions are numbers that consist of numerators and denominators. For example, in the fraction 2/3, 2 is the numerator and 3 is the denominator.

The first step is to determine which portion of the cake that was stored in the freezer.

Portion kept in the freezer = 2/3 x 3/4 = 1/2

The second step is to determine the amount of cake Mike ate.

2/3 - 1/2

[tex]\frac{4 - 3}{6}[/tex] = [tex]\frac{1}{6}[/tex]

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The portion of the cake that Mike ate is [tex]\frac{1}{6}[/tex].

The given parameters:

The portion of the cake that Mike wrapped and stored in the freezer is calculated as follows;

[tex]= \frac{3}{4} \times \frac{2}{3} \\\\= \frac{1}{2}[/tex]

The portion of the cake that Mike ate is calculated as follows;

[tex]remaining = original - portion \ stored\\\\remaining = \frac{2}{3} - \frac{1}{2} = \frac{4 - 3}{6} = \frac{1}{6}[/tex]

Thus, the portion of the cake that Mike ate is [tex]\frac{1}{6}[/tex].

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Answer:

Step-by-step explanation:

Remember:

If something is:

-equal to a number

-equal to or less then a number

-euqal to or greater than a number

Then you you would use a closed mark with an arrow.

Note: Don't use the arrow for the "equal to" part

If something is greater/less than a number:

Then you would use an open mark with an arrow

So since you're using the inequality q < 69.5,

You would graph it with an open mark with a left arrow, and the open mark must be on the number 69.5

The graph the solution to the given inequality on the number line plotted below.

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The given inequality is q < 69.5​.

The result can be shown in multiple forms.

Inequality Form:q<69.5

Interval Notation:(−∞,69.5)

Therefore, the graph the solution to the given inequality on the number line plotted below.

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Answer: -8y-27

Step-by-step explanation: Simplify the expression.

Hope this helps you out.

Answer:

-8y-27.

Step-by-step explanation:

3(-2y-9)-2y

= 3*-2y+3*-9 -2y

= -6y-27-2y

= -8y-27.

Answer:

D

Step-by-step explanation:

The function of the x in the table is not having a specific pattern apart from repeating 3's.

Choice A: pattern for x +1

pattern for y +1

Choice B:pattern of x -1

pattern for y +1

Choice C: pattern for x +1

pattern for y -0

Choice D:pattern for x -0

pattern for y +1

Therfore D would be the answer.

Answer:Its C

Step-by-step explanation:

ED 2023

The correct answer is provided by the third system.

To determine which system of linear inequalities includes the point (2, 1), we need to substitute this point into each inequality and check if the inequalities hold true. Let's evaluate each system step-by-step:

System 1

Evaluating at (2, 1):

The point (2, 1) does not satisfy the first inequality, so it is not in the solution set for the first system.

System 2

Evaluating at (2, 1):

The point (2, 1) does not satisfy the second inequality, so it is not in the solution set for this system either.

System 3

Evaluating at (2, 1):

The point (2, 1) satisfies both inequalities, so it is in the solution set for the third system.

System 4

Evaluating at (2, 1):

The point (2, 1) does not satisfy the first inequality, so it is not in the solution set for the fourth system.

The system of linear inequalities that includes the point (2, 1) is the third one: y [tex]\leq[/tex] -x + 3, and y [tex]\leq[/tex] 0.5x + 2.

Answer:

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572

Step-by-step explanation:

Given as :

The dimension of rectangular field

Length of rectangular field = L = 12 feet

width of rectangular field = w = 15 feet

The cost of grass per square foot = 50 cents = $0.5    ( ∵ 1 cents = $0.01 )

The cost of small fence = $8 per linear foot

Now, According to question

A ) Let The total feet needed for the fence total perimeter = A feet

∵ Perimeter of rectangular field = 2 × Length + 2 × width

Or, A = 2 × L + 2 × w

Or, A = 2 × 12 feet + 2 × 15 feet

Or, A = 24 feet + 30 feet

∴ A = 54 feet

So, The total feet needed for the fence total perimeter = A = 54 feet

B ) Let The total cost of fence = $B

So, The total cost of fence = The cost of small fence × perimeter of fence

i.e B = $8 × 54 feet

∴ B = $432

So,The total cost of fence = B = $432

C) Let the square feet of grass needed foe the total area = C square feet

∵The Area of rectangular fence = Length × width

Or, The square feet of grass needed foe the total area = Area of rectangular fence = L × w

i.e C = 12 feet × 15 feet

Or, C = 180 feet²

So,The square feet of grass needed foe the total area = C = 180 square feet

D) Let The total cost of grass = $D

∵ The cost of grass per square foot = $0.5

So,Total cost of grass = $0.5 × Area of fence

i.e D = $0.5 ×  180 feet²

Or, D = $90

So, The Total cost of grass = D = $90

E) Let the total cost of the project = $E

∵Mr. Jones spend additional $50 for tools

So, The total cost of the project =  money spent on tools + total cost of fence + Total cost of grass

i.e E = $50 + B + D

Or, E = $50 + $432 + $90

∴ E = $572

So, The total cost of the project = E = $572

Hence,

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572  Answer

To complete the Venn diagram, calculate that 48 out of 60 farms grow potatoes and the remaining 16 grow sugar beets, since the potato farms number is three times the sugar beet farms.

The question asks us to complete a Venn diagram with information about how many farms grow potatoes vs sugar beets, given that 60 farms grow one or the other, not both. 4/5 of the 60 farms grow potatoes, which is 48 farms.

Since the number of farms that grow potatoes is three times the number that grow sugar beets,

we can determine the number of sugar beet farms by dividing the number of potato farms by 3, giving us 16 farms growing sugar beets.

Here's the step-by-step solution:

Answer:

[tex]S = P(1.08)^{t}[/tex]

Step-by-step explanation:

A $10,000 deposit at the bank will double in value in 9 years.

If the interest is r% and it is compounded each year, then we can write from the formula of compound interest that

[tex]20000 = 10000(1 + \frac{r}{100})^{9}[/tex]

⇒ [tex]2 = (1 + \frac{r}{100})^{9}[/tex]

⇒ [tex]1 + \frac{r}{100} = 1.08[/tex]

⇒ r = 8%

Therefore, the formula for the accumulated amount t years after the investment is made will be  

[tex]S = P(1 + \frac{8}{100})^{t} = P(1.08)^{t}[/tex]  

where, P is the invested principal and S is the accumulated sum. (Answer)

Answer:

A. [tex]\displaystyle 10\:units[/tex]

Step-by-step explanation:

Use the Distance Formula:

[tex]\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[-3 + 2]^2 + [-6 - 4]^2} = \sqrt{[-1]^2 + [-10]^2} = \sqrt{1 + 100} = \sqrt{101} ≈ 10,04987562 ≈ 10[/tex]

Since we are talking about distance, we ONLY want the NON-NEGATIVE root.

I am joyous to assist you anytime.

Final answer:

The approximate length of a line segment connecting points A(3, 6) and B(2, -4) is found using the distance formula and it is approximately 10 units.

Explanation:

To calculate the approximate length of a line segment connecting points A and B, we use the distance formula. The distance formula is derived from the Pythagorean theorem and is:

d = \/((x2 - x1)² + (y2 - y1)²)

Given points, A(3, 6) and B(2, -4), we can plug these coordinates into the formula:

d = \/((2 - 3)² + (-4 - 6)²)

Now, calculate the squares and sum:

d = \/((-1)² + (-10)²)

d = \/(1 + 100)

d = \/(101)

The square root of 101 is approximately 10.05, which is close to 10 units.
Therefore, the approximate length of the line segment connecting points A and B is 10 units, which corresponds to option A.

Answer:

The final amount in the account after 6 years at compound interest is $1568.78 .

Step-by-step explanation:

Given as :

The principal amount in account = p = $1500

The rate of compound interest = r = 0.75 %

The time period of the loan = t = 6 years

Let The Amount in account after 6 years = $A

From Compound Interest method

Amount = Principal × [tex](1+\dfrac{\textrm rate}{100})^{\textrm time}[/tex]

I.e A = p × [tex](1+\dfrac{\textrm r}{100})^{\textrm t}[/tex]

Or, A = $1500 × [tex](1+\dfrac{\textrm 0.75}{100})^{\textrm 6}[/tex]

Or, A = $1500 × [tex](1.0075)^{6}[/tex]

Or, A = $1500 × 1.04585

Or, A = $1568.775

So, The final amount= A = $1568.78

Hence The final amount in the account after 6 years at compound interest is $1568.78 . Answer

Answer:

Graph 3.

Step-by-step explanation:

Since they need to earn $240 by selling $3 candy bars, they must sell at least 80 candy bars since 240/3 = 80.

With this in mind, selling more than 80 candy bars would be acceptable, but selling less would not which is why the third graph is correct.

Answer:

c

Step-by-step explanation:

the two solutions are approximately [tex]\( x_1 \approx 2.95 \) and \( x_2 \approx -0.042 \).[/tex]

To find the value of x that satisfies the equation [tex]\( 32x^2 - 93x - 4 = 0 \)[/tex], we can use the quadratic formula:

[tex]\[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \][/tex]

Where:

- a = 32

- b = -93

- c = -4

Now, let's plug these values into the quadratic formula:

[tex]\[ x = \frac{{-(-93) \pm \sqrt{{(-93)^2 - 4 \cdot 32 \cdot (-4)}}}}{{2 \cdot 32}} \]\[ x = \frac{{93 \pm \sqrt{{8649 + 512}}}}{{64}} \]\[ x = \frac{{93 \pm \sqrt{{9161}}}}{{64}} \]\[ x = \frac{{93 \pm 95.7}}{{64}} \][/tex]

Now, we have two possible solutions:

[tex]\[ x_1 = \frac{{93 + 95.7}}{{64}} \]\[ x_2 = \frac{{93 - 95.7}}{{64}} \]\[ x_1 \approx \frac{{188.7}}{{64}} \]\[ x_2 \approx \frac{{-2.7}}{{64}} \]\[ x_1 \approx 2.95 \]\[ x_2 \approx -0.042 \][/tex]

Therefore, the two solutions are approximately [tex]\( x_1 \approx 2.95 \) and \( x_2 \approx -0.042 \).[/tex]

The probable question maybe:

What are the solutions for x in the equation [tex]\( 32x^2 - 93x - 4 = 0 \)[/tex]?

[tex]\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4^{-\frac{11}{3}}\div 4^{-\frac{2}{3}}\implies \cfrac{4^{-\frac{11}{3}}}{4^{-\frac{2}{3}}}\implies 4^{-\frac{11}{3}}\cdot 4^{\frac{2}{3}}\implies 4^{-\frac{11}{3}+\frac{2}{3}} \\\\\\ 4^{-\frac{9}{3}}\implies 4^{-3}\implies \cfrac{1}{4^3}\implies \cfrac{1}{64}[/tex]

Answer:

$6

The drawings will help

According to Newton's Third Law of Motion, the force exerted by the door on the person who kicks it, is equal and opposite to the force the person exerts on the door, i.e., 48 Newtons.

The question asks about the force exerted by a door on a person if the person kicks the door with a certain force. This scenario illustrates Newton's Third Law of Motion, which states: 'For every action, there is an equal and opposite reaction.' So, if the person exerts a force of 48 Newtons on the door, then the door will exert an equal and opposite force of 48 Newtons on the person. Therefore, the answer is A. 48 N.

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There are no illustrations, so it is impossible to answer this question. I apologise.

Answer:

C. 2/3

Step-by-step explanation:

12 female / 18 male

Dividing by 6 we get:

2 female / 3 male

or 2/3

Answer:

C.2/3

Step-by-step explanation:

Answer: 6(4x + 5)

Step-by-step explanation: 4(6x + 5) 24x + 20

To decide whether to write a as a fraction or b as a decimal in the expression ax+bx, consider the context of the problem. If dealing with measurements or real-life quantities, write a as a decimal. If dealing with parts of a whole or ratios, write b as a fraction.

In the expression ax+bx, a is a decimal and b is a fraction. To decide whether to write a as a fraction or b as a decimal, you can consider the context of the problem or the specific instructions. If the problem involves measurements or real-life quantities, it is more appropriate to write a as a decimal. On the other hand, if the problem deals with parts of a whole or ratios, it is more appropriate to write b as a fraction.

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Whether you write 'a' as a fraction or 'b' as a decimal in the expression ax+bx depends on the context of the problem you're solving. 'a' can be converted to a fraction by expressing the decimal in fractional terms, whereas 'b' can be turned into a decimal by dividing the numerator by the denominator.

In the expression ax+bx, where 'a' is a decimal and 'b' is a fraction, deciding whether to write 'a' as a fraction or 'b' as a decimal depends largely on the problem you're solving and what format is most convenient or understandable. To convert 'a' from a decimal to a fraction, you can write the decimal in fractional form. If the denominator is not 100, convert it to a fraction with a denominator of 100, which then allows you to present it as a percentage. On the other hand, to convert 'b' from a fraction to a decimal, you can simply divide the numerator of the fraction by the denominator.

A practical example could be if a=0.5 and b=3/4 in the expression. Here, you can write 'a' as 1/2 (a fraction) and 'b' as 0.75 (a decimal). Therefore, the expression becomes 1/2x + 0.75x.

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Answer:

ax^2+bx+c=0

Step-by-step explanation:

hope this helps

Answer:

[see picture]

Step-by-step explanation:

The formula shown in the picture is the quadratic formula.

When:

[tex]ax^2+bx+c=0[/tex]

a, b, c ≠ 0

x = unknown

Answer:

The first choice.

Step-by-step explanation:

We only need to know one part of this step function to figure out the answer. The first step is y=-1 if -6<x<=-4, this knocks out the 2nd and 3rd answer choices as they don't follow this equation.

Answer: [tex]A(t)=-8t+52[/tex]

Step-by-step explanation:

The  equation of the line in Slope-Intercept form is:

[tex]y=mx+b[/tex]

Where "m" is the slope and "b" is the y-intercept.

According to the data given in the exercise, you know that:

- [tex]A(t)[/tex] represents the area to paint the Hiros' romm as a function of time.

- The rate he painted the room was 8 square meters per hour.

- The area left to paint after 3 hours was 28 m².

Therefore, based on this, you can idenfity that:

1. The slope of the line is:

[tex]m=-8[/tex]

2. One of the point on the line is:

[tex](3,28)[/tex]

So you must substitute the slope and the coordinates of that point into [tex]y=mx+b[/tex] and then solve for "b" in order to find its value:

[tex]28=-8(3)+b\\\\28+24=b\\\\b=52[/tex]

Therefore, you can determine that the function [tex]A(t)[/tex] is:

[tex]A(t)=-8t+52[/tex]