Write 2 ones and 5 hundredths as a decimal

Answer:

1) b. an experimental study

2) a. μ1=μ2=μ3

3) a. MSE

4) MSTR =85.735

5) value of the F-statistics =7.472

6) b. 0.004

7) a. We reject the null hypothesis

8) b. Yes

Step-by-step explanation:

See the attached image

Answer:

61/495

Step-by-step explanation:

To determine whether there is enough evidence to reject the claim of the state Department of Transportation, a hypothesis test needs to be performed. The null hypothesis (H0) is that the mean wait time is 6 minutes or less, while the alternative hypothesis (H1) is that the mean wait time is greater than 6 minutes. Using a one-sample t-test, the test statistic is calculated and compared to the critical value obtained from the t-distribution table or calculator. In this case, the test statistic is greater than the critical value, indicating that there is enough evidence to reject the null hypothesis.

To determine whether there is enough evidence to reject the claim of the state Department of Transportation, we need to perform a hypothesis test.

Hypotheses:

Let:

μ be the mean wait time for various services at different locations.

The null hypothesis (H0) is that the mean wait time (μ) is 6 minutes or less:

H0: μ ≤ 6
The alternative hypothesis (H1) is that the mean wait time (μ) is greater than 6 minutes:

H1: μ > 6

Test statistic:

We will use a one-sample t-test since the population standard deviation is unknown.

The test statistic (t) is calculated using the formula:

t = (Xbar - μ)/(s/√(n))

Where:

Xbar is the sample mean - 10.3 minutes,

μ is the claimed mean - 6 minutes,

s is the sample standard deviation - 8.0 minutes, and

n is the sample size - 34.

Critical value:

To find the critical value, we need to determine the rejection region using the significance level (alpha) of 0.01 and the degrees of freedom (df) which is n - 1 = 33.

From the t-distribution table or calculator, the critical value for a one-tailed test at alpha = 0.01 and df = 33 is approximately 2.449.

Conclusion:

The test statistic (t) = (10.3 - 6)/(8.0/√(34)) = 3.720.

Since the test statistic (t) = 3.720 > 2.449 (the critical value), we have enough evidence to reject the null hypothesis.

Therefore, we can conclude that there is sufficient evidence to reject the claim of the state Department of Transportation at alpha = 0.01.

Answer:

-6

Step-by-step explanation:

simplify

Answer:

D. reproduction

Step-by-step explanation:

If there is no reproduction involved, then the species will go extinct

Answer:

D. reproduction

Step-by-step explanation:

Answer:

x=3, y=5

Step-by-step explanation:

To find x:

Because opposite sides of a parallelogram are congruent, we can set up the equation 2x+5=12x-25. Solving the equation will show that x=3.

To find y:

Using the same method as x, we can find that y=5.

Hope this helped!

Answer:

$51.75

Hope this helps!

(Please mark brainliest!)

Answer:

Step-by-step explanation:

A. $51.75

Answer:

We conclude that the mean number of thunder days is less than 92.

Step-by-step explanation:

We are given that Historically, a certain region has experienced 92 thunder days annually.

Over the past fifteen years, the mean number of thunder days is 72 with a standard deviation of 38.

Let [tex]\mu[/tex] = mean number of thunder days.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \geq[/tex] 92 days     {means that the mean number of thunder days is more than or equal to 92}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 92 days     {means that the mean number of thunder days is less than 92}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

                       T.S. =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean number of thunder days = 72

             s = sample standard deviation = 38

            n = sample of years = 15

So, test statistics  =  [tex]\frac{72-92}{\frac{38}{\sqrt{15} } }[/tex]  ~ [tex]t_1_4[/tex]

                               =  -2.038

The value of z test statistics is -2.038.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.

Since our test statistics is less than the critical value of t as -2.038 < -1.761, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean number of thunder days is less than 92.

Answer:

The value of w is 11 when c = 2

Step-by-step explanation:

Since c = 2, then we can just plug it into the given equation to find w.

[tex]w=(2)+9[/tex]

[tex]w=11[/tex]

Answer:

b. sqrt(a+2)^2+(b-5)^2+(c-6)^2

Step-by-step explanation:

Use distance formula

sqrt (a-(-2)^2 + (b-5)^2 + (c-6) ^2

sqrt (a+2)^2 +(b+5)^2 + (c-6)^2

Answer:

B

Step-by-step explanation:

took it on edge, it's the right answer :)

Answer:

The standard deviation of the sampling distribution of x overbarx​, denoted sigma Subscript x overbarσx​, is called the​ standard error of the mean . The standard deviation of the sampling distribution of x overbarx​, denoted sigma Subscript x overbarσx​, is called the standard distribution of the sample.

Step-by-step explanation:

The standard error (SE) of a statistic is the standard deviation of its sampling distribution or an estimate of that standard deviation. It is called the standard error of the mean (SEM) if the parameter or the statistic is the mean.

Answer:

16 cakes

Step-by-step explanation:

If you do 6 divided by 3/8, you would get 16, which is the amount of cakes that Kevin will be able to make.

Answer:

  70 minutes

Step-by-step explanation:

We assume that the time is proportional to the area and inversely proportional to the number of members.

Then the time for the second job will be the first job's time multiplied by ...

  20/9 . . . the inverse of the ratio of members painting

  4200/4800 = 7/8 . . . the ratio of area being painted

The time it would take is ...

  (36 min)(20/9)(7/8) = 70 min

It will take the smaller team 70 minutes to paint a 4200 ft² wall.

Answer:

95

Step-by-step explanation:

yeah

Answer:

Step-by-step explanation:

answer 76800

length- 20

width- 12

20x12=240

240x320(people)= 76800

The population of given Rectangleville is 76800.

The area of Rectangle is length times of width.

Given that Rectangleville's limits form a perfectly rectangular shape whose length is 20 kilometers and width is 12 kilometers

length is 20 km

width is 12 km

Area of rectangleville = Length × width

=20x12

=240 square kilometer.

Now  It has a population density of 320 people per square kilometer

We need to find the population.

To find this we need to multiply two hundred forty with three hundred twenty.

240x320

= 76800

Hence, the population of given Rectangleville is 76800.

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Answer:

Check the explanation

Step-by-step explanation:

Cost of over reserving full cost tickets, Co = $440 ( empty seats as we cannot get even the discounted revenue)

Cost of under reserving Cu = 770-440 = $330 ( because you sell more discounted tickets)

Now critical ratio = Cu / (Cu+Co) = 330/770 = 0.42857

Now for above critical ratio ,z = -0.18 ( refer standard normal distribution table)

Optimal protection level = mean +z*standard deviation = 100-0.18*25 = 95.5 = 96

The possible costs include: all the above. You may need to provide compensation to passenger and make alternative travel arrangements. Also passenger won't be happy by over booking and their will be loss of good will.

Answer:

Step-by-step explanation:

6 /2

=3

Good luck honey!

Answer: -2x+1

Step-by-step explanation:

Slope formula. -3-3/2- -1 = -6/3=-2=m

Y=mx+b use(-1,3) -1=x 3=y

3=-2(-1)+b

3=2+b

Subtract 2

1=b

Answer:

  4 cm

Step-by-step explanation:

The area of the net is 6 times the area of one square, so one square has an area of ...

  (96 cm^2)/6 = 16 cm^2

The side length (s) is the square root of this value:

  s = √(16 cm^2)

 s = 4 cm

Step-by-step explanation:

Let me know if it's all right! Good luck

Answer:

51.02 metres

Step-by-step explanation:

The pictorial representation of the problem is attached.

We are required to find the distance from the worker to the top of the pole, |DA| in the diagram.

In Triangle ABC

[tex]Tan 68^\circ =\frac{|AB|}{|BC|}\\Tan 68^\circ =\frac{|AB|}{31}\\|AB|=31 X Tan 68^\circ=72.73m[/tex]

In Triangle BCD

[tex]Tan 35^\circ =\frac{|BD|}{|BC|}\\Tan 35^\circ =\frac{|BD|}{31}\\|BD|=31 X Tan 35^\circ=21.71m[/tex]

The distance, |DA| =|AB|-|BD|

=72.73-21.71

=51.02 metres

The distance from the worker to the top of the pole is 51.02 metres.

Answer:

4

Step-by-step explanation:

1 mile = 1.6 km

1 km = 1000 m

1.6 * 1000 = 1600, So to swim 1 mile, she must swim 1600 m

She has already swam 60 lengths which is 1500 m because 60 (the number of lengths)*25 (the length of the pool) = 1500.

1600 (the amount she needs to swim) - 1500 (the amount she has already swam) = 100.

She needs to swim 100 m more, which is 4 lengths because 100/25 = 4.

To find the values of the two numbers, we can set up a system of equations based on the given information and then solve for x and y. The first number is 16 and the second number is 22.

Let's represent the first number as x and the second number as y.

We can set up two equations based on the given information.

The first equation is: x = y - 6

The second equation is: 6x = 4y + 8

Now we can solve this system of equations to find the values of x and y.

Substituting the first equation into the second equation, we get: 6(y - 6) = 4y + 8

Simplifying, we get: 6y - 36 = 4y + 8

Bringing like terms together, we have: 6y - 4y = 8 + 36

Combining like terms, we get: 2y = 44

Dividing both sides by 2, we have: y = 22

Now substitute y = 22 back into the first equation: x = 22 - 6

Simplifying, we get: x = 16

Therefore, the first number is 16 and the second number is 22.

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Answer:

A quadratic function can have up to two x-intercepts.

An x-intercept of a quadratic function is also called a zero of the function.

Step-by-step explanation:

None needed.

The true statement is

An x-intercept of a quadratic function is also called a zero of the function.

A quadratic function can have up to two x-intercepts.

A quadratic polynomial function has one or more variables and a variable with a maximum exponent of two. It is also known as the polynomial of degree 2 because the second-degree component in a quadratic function is the biggest degree term. A quadratic function must contain at least one term of the second degree. It possesses algebraic qualities.

we have,

The x-intercepts of quadratic functions,

The standard form of quadratic equation is

ax² + bx + c = 0

The zeroes of the quadratic functions are the values of x, which is also known as the x-intercept.

Because the degree of the polynomial is 2, there will be at least two x-intercept values.

The x-intercept is the x position at which the value of y is zero.

Let x = a be an x-intercept, and the function factor is (x - a).

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Answer:

B…

Step-by-step explanation:

Answer:

0.8

Step-by-step explanation:

the opposite of a negative is the positive version of the number

Answer:

the opposite of -0.8 is 0.8

Step-by-step explanation:

opposite of a negative number is the same number but positive or vice verse

Answer:

The answers below ._.

Step-by-step explanation:

A secant is a line that intersects a circle in exactly two points. When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.

The formation of secant lines that intersect within a circle is related when a secant and a tangent or two tangents intersect each other outside a circle.

A secant line is a straight line that connects two points on a curve. The secant line approaches a tangent line when the two points are drawn together.

So, If a tangent and a secant, or two tangents intersect at the exterior side of a circle, the angle created has a measure equal to one-half the positive difference between the intercepted arcs' measures.

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Answer:

Hello dear, your question might not be complete, but if you want to know the expanded notation form for the numbers given, here they are;

(1). 20 + 3.

(2). 10 + 9.

(3). 100 + 0 + 0

Step-by-step explanation:

Expanded notation can simply be defined as the depiction of numbers or digits for what they are really are that is to say the representation of the values of numbers or digits. The numbers can be shown or represented from ones, through to hundreds and many more.

For the numbers given in this question, below are the expanded notation form;

(1). 20 × 1 + 3 × 1 = Expanded Factors Form.

20 + 3 = Expanded Notation Form.

(2). 10 ×1 + 9 × 1 = Expanded Factors Form.

10 + 9 = Expanded Notation Form.

(3). 100 × 1 + 0 × 10 + 0 × 1 = Expanded Factors Form.

100 + 0 + 0 = Expanded Notation Form.

The length of side DE in the right triangle shown is 4.24 units.

We can use the Pythagorean Theorem to solve for the length of DE, since we know the lengths of the other two sides.

The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse of the triangle is DE, and the other two sides are DF and EF. We know that DF = EF = 3 units. Therefore, we can set up the following equation:

[tex]DE^2 = DF^2 + EF^2[/tex]

Substituting in the known values, we get:

[tex]DE^2 = 3^2 + 3^2[/tex]

[tex]DE^2 = 9 + 9[/tex]

[tex]DE^2 = 18[/tex]

Taking the square root of both sides, we get the length of DE:

DE = √18

DE ≈ 4.24 units

Therefore, the length of side DE in the right triangle shown is 4.24 units.

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