write an equation for each line. y intercept of -2,1, x intercept of 3.5

In slope-intercept form, y = (1/3)x + 4 can be used to represent the equation of a line with a slope of 1/3 and a y-intercept of 4.

In mathematics particularly in algebra, the equation of a line is usually formulated in the slope-intercept form, which is y = mx + b. Where m is the slope of the line and b is the y-intercept. For a line with a slope of 1/3 and y-intercept of 4, you would substitute 1/3 for m and 4 for b. Therefore, the equation of the line would be y = (1/3)x + 4

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The temperature changes by 49.2F from day to night. You calculate this by subtracting the night temperature from the day temperature and remembering to treat subtraction of a negative as addition.

The subject of your question is the calculation of temperature change, which is a simple subtraction problem in mathematics. Given a temperature of 36.6F during the day and a temperature of -12.6F at night, you can find the temperature change by subtracting the night temperature from the day temperature.

So, it will be 36.6F - (-12.6F) equals 49.2F. It's important to note here that subtracting a negative number is the same as adding a positive number which is why we add 12.6F instead of subtracting it.

This means, the temperature changes by 49.2F from day to night.

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Answer:

A. [tex]8i\sqrt{2}[/tex]

Step-by-step explanation:

We have been given a radical expression [tex]2\sqrt{-32}[/tex]. We are asked to find equivalent expression to our given expression.

Using radical rule [tex]\sqrt{-a}=\sqrt{-1}\cdot \sqrt{a}[/tex], we can write [tex]\sqrt{-32}[/tex] as product of [tex]\sqrt{-1}\cdot\sqrt{32}[/tex].

[tex]2\sqrt{-32}=2\cdot \sqrt{-1}\cdot\sqrt{32}[/tex]

Substitute [tex]\sqrt{-1}=i[/tex]:

[tex]2\sqrt{-32}=2i\cdot\sqrt{32}[/tex]

[tex]2\sqrt{-32}=2i\cdot\sqrt{2\cdot 16}[/tex]

[tex]2\sqrt{-32}=2i\cdot\sqrt{2\cdot 4^2}[/tex]

[tex]2\sqrt{-32}=2*4i\cdot\sqrt{2}[/tex]

[tex]2\sqrt{-32}=8i\sqrt{2}[/tex]

Therefore, the equivalent expression would be [tex]8i\sqrt{2}[/tex].

The expression which is equal to 2√-32 is; 8i√2

According to the question, we have been given the radical expression; 2√-32

First, the expression can be evaluated as follows;

We must recall that, In complex numbers, √-1 = i.

Therefore, the expression which is equal to 2√- 32 is:. 8i√2

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Answer:

118.

Step-by-step explanation:

To find Jane's score on the national achievement test with a given mean of 100 and standard deviation of 15, we calculate it using her z-score of 1.20 to get her score of 118.

The question asks: A national achievement test is administered annually to 3rd graders. The test has a mean score of 100 and a standard deviation of 15. If Jane's z-score is 1.20, what was her score on the test.

To find Jane score on the test, we use the formula for calculating scores from z-scores: Score = Mean + (Z-score × Standard Deviation).

Given that the mean is 100 and the standard deviation is 15, and Jane's z-score is 1.20, we can calculate her score as follows:

Therefore, Jane's score on the national achievement test was 118.

Final answer:

Betelgeuse will be either just above the horizon or at virtually the same position on the eastern horizon at 7:15 pm the next day, as stars like Betelgeuse rise in the east and set in the west, completing a rotation around the celestial sphere in about 24 hours.

Explanation:

The question pertains to the observation of the star Betelgeuse and its position relative to the horizon at a specific time from one day to the next. Since most stars rise in the east and set in the west, completing one full rotation around the celestial sphere in approximately 24 hours, we can infer that Betelgeuse will follow a similar path. However, due to Earth's rotation, any given star will appear to rise and set four minutes earlier each night, due to the Earth’s orbit around the Sun completing an extra degree each day. This might suggest that Betelgeuse would be slightly above the horizon at 7:15 pm the following night. Yet, the student should be aware that this four-minute difference can be negligible, and for practical observing purposes, Betelgeuse will be seen rising at virtually the same time, hence nearly at the same position on the horizon.

The measure of the smaller angle is 77 degrees, and the measure of the larger angle is 103 degrees.

Let's represent the measure of the smaller angle as x degrees. Since the measure of one angle is 26 degrees greater than the other angle, the measure of the larger angle can be represented as x + 26 degrees.

According to the definition of a linear pair, the sum of the measures of two angles forming a linear pair is always 180 degrees. So we can write the equation:

x + (x + 26) = 180

Solving this equation, we get: 2x + 26 = 180

2x = 180 - 26

2x = 154

x = 154/2

x = 77

Therefore, the smaller angle measures 77 degrees and the larger angle measures 77 + 26 = 103 degrees.

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Explanation of the ratios of French decimal time to standard time after the French Revolution.

Ratio of French Decimal Week to Standard Week:

1 French decimal week = 10 days, whereas 1 standard week = 7 days. So, the ratio is 10/7.

Ratio of French Decimal Second to Standard Second:

1 French decimal second = 0.01 standard second since 1 hour = 100 French decimal minutes = 100 x 0.01 = 1 standard hour.

(a) The ratio of the French decimal week to the standard week is [tex]\( \frac{10}{7} \)[/tex].

(b) The ratio of the French decimal second to the standard second is [tex]\( \frac{5}{3} \)[/tex].

To find the ratios of the French decimal week to the standard week and the French decimal second to the standard second, we'll compare the durations of these units in the French decimal system to those in the standard system.

(a) Ratio of the French decimal week to the standard week:

In the French decimal system:

- One French decimal week consists of 10 days.

In the standard system:

- One standard week consists of 7 days.

So, the ratio of the French decimal week to the standard week is:

[tex]\[ \text{Ratio} = \frac{\text{French decimal week}}{\text{Standard week}} = \frac{10 \text{ days}}{7 \text{ days}} \][/tex]

(b) Ratio of the French decimal second to the standard second:

In the French decimal system:

- One minute consists of 100 seconds.

In the standard system:

- One minute consists of 60 seconds.

So, the ratio of the French decimal second to the standard second is:

[tex]\[ \text{Ratio} = \frac{\text{French decimal second}}{\text{Standard second}} = \frac{100 \text{ seconds}}{60 \text{ seconds}} \][/tex]

Now, let's simplify these ratios:

(a) Ratio of the French decimal week to the standard week:

[tex]\[ \frac{10}{7} \][/tex]

(b) Ratio of the French decimal second to the standard second:

[tex]\[ \frac{100}{60} = \frac{5}{3} \][/tex]

So, the ratios are:

(a)  for the French decimal week to the standard week.

(b) [tex]\( \frac{5}{3} \)[/tex] for the French decimal second to the standard second.

The domain of a function is the set of all possible input values that can be inserted into the function. The domain can be numerical or non-numerical, depending on what the function describes.

In mathematics, finding the domain of a function involves identifying all possible values that can be inserted into the function. A function's domain can be a set of numerical values or a set of non-numerical values.

For example, if we have a function based on majors at a university, the domain could take form as X = {English, Mathematics, ...}, i.e., a list of all the majors offered at the university, plus undeclared, which are all possible inputs into the function.

Similarly, if we have a random variable X = hair color, then the domain of X would include all possible hair colors.

If the function is based on numerical variables, such as a Quadratic Function, the domain would be the set of all real numbers. For instance, the domain of Y = {0, 1, 2, ...} consists of the integers from zero up to a certain limit. Generally, the domain of a function is the set of all possible input values that will produce a value in the function.

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We know that:

1 mile = 5280 ft

1 minute = 60 sec

Therefore to convert this we simply use the conversion factors:

(30 ft / s) * (60 s / 1 min) * (1 mi / 5280 ft) = 0.34 mi / min

So we got 0.34 miles per minute.

Answer:

[tex]y=\dfrac{14-Ax}{2x}[/tex]

Step-by-step explanation:

The given expression is :

[tex]Ax+2xy=14[/tex].............(1)

We need to find the value of y. Subtracting "Ax" on both sides of equation (1) as :

[tex]Ax-Ax+2xy=14-ax[/tex]

[tex]2xy=14-Ax[/tex]

Dividing both sides of above equation by "2x" as :

[tex]\dfrac{2xy}{2x}=\dfrac{14-Ax}{2x}[/tex]

[tex]y=\dfrac{14-Ax}{2x}[/tex]

So, the value of y is, [tex]y=\dfrac{14-Ax}{2x}[/tex]. Hence, this is the required solution.

Answer:  11

Step-by-step explanation:

We are given that ∠E and ∠F are vertical angles with m∠E=5x+10 and m∠F=7x−12 .

We know that vertical angles are congruent, then their measures must be equal.

i.e. if ∠E and ∠F are vertical angles.

⇒ m∠E=m∠F

[tex]\Rightarrow\ 5x+10=7x-12[/tex]   [Substitute the measures of ∠E and ∠F]

Subtract 5x from both sides , we get

[tex]10=2x-12[/tex]

Add 12 on both sides , we get

[tex]22=2x[/tex]

Divide both sides by 2 , we get

[tex]11=x[/tex] or x=11

Hence, the value of x= 11

For two given functions f(x) and g(x), the composite function

(g ° f)(x) is: g(f(x))

Here we will find that the correct option is the last one:

(g°f)(x) = x²-2

To get this, we know that:

g(x) = x + 1

f(x) = x² - 3

Then:

(g°f)(x) = g(f(x))

So here we just need to evaluate g(x) in f(x):

g(f(x)) = f(x) + 1 = ( x² - 3) + 1 = x² - 3 + 1 = x² - 2

Then the correct option is 3:

(g°f)(x) = x²-2

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