Write two mixed numbers between 3 and 4 that have the product between 9 and 12???

PLZ HELP!!!

Let

a--------> the total cost in dollars of [tex]6[/tex] ounces of coconut oil

b--------> the total cost in dollars of [tex]5[/tex] ounces of beeswax

we know that

[tex]a=0.50 \frac{\$}{ounce}*6=\$3[/tex]

[tex]b=2.00 \frac{\$}{ounce}*5=\$10[/tex]

therefore

the answer is

the total cost in dollars of [tex]6[/tex] ounces of coconut oil is [tex]a=\$3[/tex]

the total cost in dollars of [tex]5[/tex] ounces ofbeeswax is [tex]b=\$10[/tex]

Answer: [ 7,1 ]

Step-by-step explanation:

this is the answer on odyssey ware.

The point that satisfies the equation 2x+3y=8 is (1,4).

To find the point that satisfies the equation 2x + 3y = 8, we can substitute the x and y values from each option into the equation and see which option makes the equation true.

Let's try option A, (-1,3): 2(-1) + 3(3) = -2 + 9 = 7, which is not equal to 8.

Continuing this process for options B, C, and D, we find that the point (1,4) satisfies the equation 2x + 3y = 8.

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Answer:

32

Step-by-step explanation:

Let X be the number of bacteria at the initial time.

At 12 minutes = 2 X

At 24 minutes = 4X

At 36 minutes = 8X

At 48 minutes = 16X

At 60 minutes = 32X

The ratio between the final and the initial instant will be: 32X / X = 32

Final answer:

An acrostic poem for the word 'triangle' is a creative way to convey various attributes of the geometric shape or to create a poem with each line starting with the corresponding letter. The poem can be directly related to the properties of a triangle or more abstract.

Explanation:

An acrostic poem uses the first letter of each line to spell out a word vertically. For the word 'triangle', an acrostic poem might be a creative way to describe the characteristics of a triangle, or it could be abstract, using each letter to begin a line that doesn't necessarily relate to the shape but instead creates a coherent poem.

Here is an example of an acrostic poem for the word 'triangle':

Three sides enclosing space,

Reminder of structure and base,

In geometry, an essential grace,

Angles acute, obtuse, or right,

Nestled within, points of light,

Guiding principles of design,

Lines intersect by plan divine,

Eternally, three lines combine.

Remember, while writing an acrostic for 'triangle', you may also use the opportunity to incorporate into your poem mnemonics for the relationships between the sides and angles of a right triangle, such as 'SOHCAHTOA', or explore the figurative and metaphorical implications of the shape as referenced in literary examples or the sciences.

The simplified form of the expression [tex]8a+4b-3a+5b[/tex] is [tex]\boxed{5a+9b}[/tex].

Further explanation:

The given expression is [tex]8a+4b-3a+5b[/tex].

The given expression consists of [tex]2[/tex] different variables [tex]a[/tex] and [tex]b[/tex]. These variables can take any values since, its value is not fixed.

An algebraic expressions are formed if different variables and are added, subtracted, multiplied and divided.

The given expression is obtained when the variable [tex]a[/tex] and variable [tex]b[/tex] is added and subtracted with multiplication with different integers.

In the given expression there are [tex]4[/tex] terms with each term having different coefficients.

Like terms in the given expression are those whose algebraic factors are same that is [tex]8a[/tex] and [tex]-3a[/tex] are like terms and [tex]4b[/tex] and [tex]5b[/tex] are like terms.

The given expression is a binomial since, it have two unlike terms.

To simplify the given expression first we have to identify the like and unlike terms.

The like terms are [tex]8a[/tex] and [tex]-3a[/tex] and other set of like terms are [tex]4b[/tex] and [tex]5b[/tex]

Since, [tex]a[/tex] and [tex]b[/tex] are variable and they are numbers they can be added or subtracted using distributive property.

[tex]8a[/tex] and [tex]-3a[/tex] are subtracted as follows:

[tex]\begin{aligned}8a-3b&=(8\cdot a)-(3\cdot a)\\&=(8-3)\cdot a\\&=5\cdot a\\&=5a\end{aligned}[/tex]  

[tex]4b[/tex] and [tex]5b[/tex] are added as follows:

[tex]\begin{aligned}4b+5b&=(4\cdot b)+(5\cdot b)\\&=(4+5)\cdot b\\&=9\cdot b\\&=9b\end{aligned}[/tex]  

Therefore, simplified form of the given expression is [tex]5a+9b[/tex] since both are positive terms.

Thus, the simplified form of the expression [tex]8a+4b-3a+5b[/tex] is [tex]\boxed{5a+9b}[/tex].

Learn more:

1. Learn more about equations https://brainly.com/question/1473992

2. Learn about solving equation https://brainly.com/question/5723059

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Algebraic expressions

Keywords:  Simplify, 8a+4b-3a+5b, expression, 5a+9b, terms, coefficients, like, unlike, addition, subtraction, variables, values, distributive property, like terms, unlike terms.

The slope-intercept form of equation of the line that has slope -6 and y-intercept (0, 2) is y=-6x+2.

The slope intercept form of a straight line is one of the most common forms used to represent the equation of a line. The slope intercept formula can be used to find the equation of a line when given the slope of the straight line and the y-intercept.

The standard form of the slope intercept form is y=mx+c.

Given that, the line that has slope -6 and y-intercept (0, 2).

The y-intercept is the point where a graph crosses the y-axis. In other words, it is the value of y when x=0.

Here, m=-6 and c=2

Substitute m=-6 and c=2 in y=mx+c, we get

y=-6x+2

Therefore, the slope-intercept form of equation of the line that has slope -6 and y-intercept (0, 2) is y=-6x+2.

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The temperature was -20 in the afternoon.

The arithmetic operators are addition, subtraction, multiplication and division. The arithmetic operators are applied between two or more numbers or quantities.

Given that, the temperature was 8 below zero in the morning and dropped 12 degrees during the afternoon.

We need to find the temperature late in the afternoon.

We know,

8 below zero is -8 degrees.

Now it is saying that the temperature dropped by 12 degrees,

Therefore,

-8 -12

-8 + (-12) = -20

Hence the temperature was -20 in the afternoon.

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To find the probability that exactly two of the five will take the same test, we use combinations. The probability is 2/3 or 0.667. To find the probability that the two women will take the same test, we use combinations. The probability is 1/2 or 0.500.

To find the probability that exactly two of the five will take the same test, we can use the concept of combinations. There are six different tests, and we need to choose two of them to be taken by two people. The total number of ways to select two tests out of six is given by the combination formula C(6,2) = 6!/(2!(6-2)!) = 15. Now, for each of these two selected tests, there are two people (either two men or two women) who can take the test, resulting in a total of two possibilities. Therefore, the number of favorable outcomes is 2 * 15 = 30. Finally, the probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes, which is 6!/(2!3!) = 15. So the probability is 30/15 = 2/3 or 0.667 (rounded to three decimal places).

To find the probability that the two women will take the same test, we can use similar reasoning. There are six different tests, and we need to choose one of them to be taken by both women. The total number of ways to choose one test out of six is given by the combination formula C(6,1) = 6!/1!(6-1)! = 6. Now, for the chosen test, there are three possible ways both women can take it, since they can be the first two applicants, the last two applicants, or the middle two applicants. Therefore, the number of favorable outcomes is 3. The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes, which is also 6. So the probability is 3/6 = 1/2 or 0.500 (rounded to three decimal places).

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Final answer:

The probability that exactly two of the five will take the same test is 0.00463. The probability that the two women will take the same test is 1.167.

Explanation:

To find the probability that exactly two of the five will take the same test, we can use combinations. There are 6 different tests and we want to select 2 of them for the same test. Since order doesn't matter, we can use combinations. The number of ways to choose 2 tests out of 6 is 6 choose 2 = 15.

Now, for each pair of tests, we have 5 people who can take those tests. The probability that exactly 2 of the five will take the same test is the probability that exactly 2 people are randomly assigned to the same test out of the 5 people. The total number of possible outcomes is 6^5 since each person has 6 choices for which test to take, and there are 5 people.

So, the probability that exactly two of the five will take the same test is 15/6^5, which is approximately 0.00463.

To find the probability that the two women will take the same test, we consider the different possibilities. The two women can take the same test out of the 6 tests, or they can take different tests.

If they take the same test, there are 5 possible tests for them to choose from. The probability of this happening is 5/6.

If they take different tests, there are 5 possible tests for each of them to choose from. The probability of this happening is (5/6) * (4/5) = 2/3.

Therefore, the probability that the two women will take the same test is (5/6) + (2/3) = 7/6, which is approximately 1.167.

Height of water in hexagonal prism vase = 384 inches, given equal volume of water and wet portion.

Let's denote the height of the water in the vase as [tex]\( h \)[/tex] inches.

The volume of a hexagonal prism can be calculated using the formula:

[tex]\[ V = \frac{3\sqrt{3}}{2}a^2h \][/tex]

where [tex]\( a \)[/tex] is the length of one side of the hexagon (which represents the base of the prism), and [tex]\( h \)[/tex] is the height of the prism.

Since the base of the vase is a hexagon, we need to find the side length of this hexagon.

The area of a regular hexagon can be calculated using the formula:

[tex]\[ A = \frac{3\sqrt{3}}{2}a^2 \][/tex]

Given that the volume of water in the vase is 512 cubic inches, and the wet portion's volume and its height are equal, we have:

[tex]\[ 512 = \frac{3\sqrt{3}}{2}a^2h \][/tex]

We are also given that the wet portion's volume is numerically equal to its height, so:

[tex]\[ h = 512 \][/tex]

Substituting this value of [tex]\( h \)[/tex] into the volume equation, we have:

[tex]\[ 512 = \frac{3\sqrt{3}}{2}a^2(512) \][/tex]

Now, we can solve for [tex]\( a \).[/tex]

[tex]\[ a^2 = \frac{512}{\frac{3\sqrt{3}}{2} \times 512} \]\[ a^2 = \frac{512}{\frac{3\sqrt{3}}{2} \times 512} \]\[ a^2 = \frac{2}{3\sqrt{3}} \]\[ a^2 = \frac{2\sqrt{3}}{9} \]\[ a = \sqrt{\frac{2\sqrt{3}}{9}} \]\[ a = \frac{\sqrt{2\sqrt{3}}}{3} \][/tex]

Now, let's find the height of the water by substituting the value of [tex]\( a \)[/tex]into the volume equation:

[tex]\[ 512 = \frac{3\sqrt{3}}{2}\left(\frac{\sqrt{2\sqrt{3}}}{3}\right)^2h \]\[ 512 = \frac{3\sqrt{3}}{2}\left(\frac{2\sqrt{3}}{9}\right)h \]\[ 512 = \frac{3\sqrt{3}}{2}\left(\frac{2\sqrt{3}}{9}\right)h \]\[ 512 = \frac{4}{3}h \]\[ h = \frac{512 \times 3}{4} \]\[ h = 384 \][/tex]

So, the height of the water in the vase is 384 inches.

The unknown length YZ can be found through the ratios of corresponding sides in similar figures ABCD and WXYZ. Given AD=12, DC=3, WZ=35, the equation 3/YZ = 12/35 is formed. Solving for YZ, we find that YZ is 8.75.

In the given question, ABCD and WXYZ are similar figures which mean the ratio of corresponding sides are equal. So, the ratio AD/WZ equals to the ratio DC/YZ. Given, AD=12, DC=3 and WZ=35. The length of YZ can be found by cross multiplying these ratios.

So, DC/YZ = AD/WZ.

By substituting the given values:

3/YZ = 12/35.

To find YZ, we simply cross-multiply and solve for YZ:

3 × 35 = 12 × YZ,

Hence, YZ = (3 × 35) / 12, which is 8.75 units.

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1.5x+2.5y=21.50

x+y=9

8 people ordered chicken sandwich