You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a battery. The first piece has a length L and cross-sectional area A. The second is twice as long as the first, but has the same thickness. The third is the same length as the first, but has twice the cross-sectional area. Rank the wires in order of which carries the most current (has the lowest resistance) when connected to batteries with the same voltage difference. Rank the wires from most current (least resistance) to least current (most resistance).

The size of the electric force between two objects is affected by the strength of the charge and the distance between the objects. Objects with strong positive and negative charges will have a greater electric force. As the distance between the objects decreases, the electrical force increases.

A gas heated to millions of degrees would emit mostly x-rays.

High-energy electromagnetic waves would be produced by a gas that has been heated to millions of degrees in terms of thermal radiation. The atoms and molecules included in a gas experience collisions, transitions, and ionisation processes as its temperature rises.

A wide range of electromagnetic radiation, including visible light, ultraviolet (UV) radiation, and X-rays, are produced as a result of these powerful interactions. The gas composition, temperature, and other parameters affect the precise wavelengths and intensities of the radiation that is emitted.

This effect has been seen in a variety of astrophysical settings, including high-temperature plasmas in laboratory studies, the highly hot and active areas of stars, supernovae, and accretion discs surrounding black holes.

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Answer:

Potential will be zero at two points

x = 3 cm

x = 6 cm

Explanation:

Let the first point at which potential is zero is lying between two charges

so we will have

[tex]\frac{kq_1}{x} = \frac{kq_2}{L - x}[/tex]

[tex]\frac{3nC}{x} = \frac{1nC}{4 - x}[/tex]

[tex]3(4 - x) = x[/tex]

[tex]x = 3 cm[/tex]

Let another point lies on the right side of -1 nC on x axis

so we will have

[tex]\frac{kq_1}{x} = \frac{kq_2}{x-4}[/tex]

[tex]\frac{3}{x} = \frac{1}{x-4}[/tex]

[tex]3(x - 4) = x[/tex]

[tex]x = 6 cm[/tex]

The points on x - axis in which the electric potential between the two charges is zero are 3 cm and 6 cm.

The given parameters;

q₁ = 3 nC

q₂ = -1 nC

Let the point in which the potential between the two charges equal zero, lie  between the two charges.

Let the point = x₁

         (+q₁)----------------------(x₁)------------------------(-q₂)

The electric potential of due to each charge is calculated as;

[tex]\frac{kq_1}{x_1} = \frac{kq_2}{4-x_1}[/tex]

[tex]\frac{3k}{x_1} = \frac{k}{4-x_1}\\\\3k(4-x_1) = kx_1\\\\3(4-x_1) = x_1\\\\12 - 3x_1 = x_1\\\\4x_1 = 12\\\\x_1 = \frac{12}{4} \\\\x_1 = 3 \ cm[/tex]

Since the second charge is negative, another point in which the potential between the two charges will be zero will be right of second charge;

          (+q₁)----------------------------(-q₂)------------------(x₂)

[tex]\frac{kq_1}{x_2} = \frac{kq_2}{x_2 - 4} \\\\\frac{3k}{x_2} = \frac{k}{x_2 - 4} \\\\3(x_2-4) = x_2\\\\3x_2 - 12 = x_2\\\\2x_2 = 12\\\\x_2 = \frac{12}{2} \\\\x_2 = 6 \ cm[/tex]

Thus, the points on x - axis in which the electric potential between the two charges is zero are 3 cm and 6 cm.

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B. Aluminum is possibly correct

Answer:

10,000 eV

Explanation:

Due to the law of conservation of energy, the kinetic energy of the electron at the end of its path is equal to its initial electric potential energy, given by:

[tex]U=q\Delta V[/tex]

where

q is the electron charge

[tex]\Delta V[/tex] is the potential difference

Here we have:

[tex]q=1 e[/tex] is the electron's charged

[tex]\Delta V=10 kV=10,000 V[/tex] is the potential difference

Substituting into the formula, we have

[tex]U=(1e)(10,000 V)=10,000 eV[/tex]

Final answer:

An electron accelerated through a potential difference of 10 kv gains 10,000 eV of kinetic energy, as there's a direct relationship between the potential difference in volts and the kinetic energy in electron volts.

Explanation:

The question involves an electron that is accelerated through a potential difference of 10 kv (10,000 volts) before it hits the screen, and you're asked to find the kinetic energy of the electron in electron volts (eV). The relationship between the potential difference an electron is accelerated through and the kinetic energy it gains is direct and linear. For every 1 V of potential difference, an electron gains 1 eV of kinetic energy.

Therefore, if an electron is accelerated through a potential difference of 10,000 volts (10 kv), it gains 10,000 eV of kinetic energy. This straightforward calculation is based on the basic principle that the kinetic energy gained by an electron (in eV) is numerically equivalent to the potential difference (in volts) it is accelerated through.

I believe its E.

Traveling through metal, electrons can not go the speed of light

Answer:

E. at none of the above speeds

Explanation:

When current flowing through the metal then the speed of electrons in metal is not very high.

This speed of all electrons inside metal is opposite the the electric field which is due to the applied potential difference on the metal by external battery.

As we know that

[tex]\Delta V = i R[/tex]

here for the current flowing in the metal the all the free electrons will move at drift speed which is given as

[tex]i = neAv_d[/tex]

here speed of electrons will be

[tex]v_d[/tex] = drift speed

n = number density of electrons

A = crossectional area

e = charge of an electron

in general this speed is very small and approximately of order cm/s

Answer:

pin will move in the direction of motion of ball with speed

v = 2.54 m/s

Explanation:

As we know that there is no force on the pin + bowling ball system

So we will have net momentum before and after collision will remain conserved

so we will say that

[tex]m_b v_i = m_b v_{1f} + m_p v_{2f}[/tex]

now plug in all data into the above equation

[tex]3.1(2.5) = 3.1(1.95) + 0.67 v[/tex]

[tex]3.1(2.5 - 1.95) = 0.67 v[/tex]

[tex]v = \frac{3.1(2.5 - 1.95)}{0.67}[/tex]

[tex]v = 2.54 m/s[/tex]

Here, we are required to determine how fast the pin will move after it is hit.

The pin will move with a velocity of;.

v(p) = 2.54m/s

From the question, it is evident the pin is stationary prior to the collision.

Therefore,

{m(b)×v1} + {m(p)×0} = {m(b)×v2} + {m(p)×v(p)}

We then have;

(3.1 × 2.5) = (3.1 × 1.95) + (0.67 × v(p))

Therefore; 0.67v(p) = 1.705

v(p) = 1.705/0.67

Therefore, the pin will move with a velocity of;

v(p) = 2.54m/s

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Choice A is the right answer! Buy at high altitude and sell at low altitude

Hope this helps :)

They should A- buy at a high altitude and sell at a low altitude

The three units used to express pressure are pascal (Pa), atmosphere (atm), and Hg (torr).

The three units are pascal(pa) atmosphere (atm) and hg (torr)

That's TRUE.

For example:

--  When it's Winter in Canada, the USA, and France, it's Summer in Australia, Paraguay, and Namibia.  (This is the end of December, all of January and February, and most of March.)

-- When it's Winter in Tasmania, South Africa, and Botswana, it's Summer in Germany, Israel, and Mexico.  (This is the end of June, all of July and August, and most of September.)

-- The Spring and Fall are opposite too.

Answer: true

Explanation:

Rising warm air transports thermal energy by ( water vapor).

Water vapor.

Answer:

D) 9.4 V, 0.38 A

1) Voltage in the secondary coil: 9.4 V

The transformer equation states that:

[tex]\frac{V_p}{N_p}=\frac{V_s}{N_s}[/tex]

where

Vp = 120 V is the voltage in the primary coil

Np = 1400 is the number of turns in the primary coil

Vs = ? is the voltage in the secondary coil

Ns = 110 is the number of turns in the secondary coil

Solving the formula for Vs, we find

[tex]V_s = N_s \frac{V_p}{N_p}=(110)\frac{120 V}{1400}=9.4 V[/tex]

2) Current in the secondary coil: 0.38 A

A transformer is considered to be 100% efficient: it means that there is no loss of power, so the power in input is equal to the power in output

[tex]P_i = P_o\\V_p I_p = V_s I_s[/tex]

where

Vp = 120 V is the voltage in the primary coil

[tex]I_p = 3.0\cdot 10^{-2} A[/tex] is the current in the primary coil

Vs = 9.4 V is the voltage in the secondary coil

[tex]I_s[/tex] is the current in the secondary coil

Solving the equation for [tex]I_s[/tex],

[tex]I_s = \frac{V_p I_p}{V_s}=\frac{(120 V)(3.0\cdot 10^{-2}A)}{9.4 V}=0.38 A[/tex]

I believe that it is d correct me if wrong because the higher the temperature the more active the molecules are gonna be, but the graph does not explicitly state that, so you can say the answer is d (if not the answer is c) (sorry if wrong)

The resistance is a measure of how the material impedes the flow of electrons through it. There are several factors that affect the resistance of a wire or a material.

The four main factors which affect the resistance of a material are;

The resistance of a piece of material is determined by its type of material, cross-sectional area, and length. Voltage and current are related to resistance through Ohm's law but do not determine it. Temperature can also affect resistance.

The quantities that determine the resistance of a piece of material are:

It is to be noted that the voltage across the material and the current flowing through do not determine the resistance of a material but are related to it by Ohm’s law, which states that voltage (V) is the product of current (I) and resistance (R): V = IR.

Additionally, temperature can also influence resistance, generally increasing it in conductors as temperature rises.

The speed of the water is the greatest at point B

The speed of water flowing through a pipe is greatest at the point where the pipe's diameter is smallest. So, in this scenario, the speed of water is greatest at Point A.

In fluid dynamics, a principle known as Bernoulli's Principle explains that as the cross-sectional area of a pipe changes, so does the speed of fluid flowing through it. In your scenario, water is flowing through a horizontal pipe with different diameters at Point A and Point B. As per Bernoulli's Principle, the water speed is greatest at the point where the pipe's diameter is smallest. Therefore, since Point A has a smaller diameter than Point B, the speed of the water is greatest at Point A.

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(a) 1.76 m/s^2

The centripetal acceleration of the child is given by:

[tex]a_c=\omega^2 r[/tex]

where

[tex]\omega[/tex] is the angular velocity

r is the radius of the wheel

The radius of the wheel is half the diameter:

[tex]r=\frac{d}{2}=\frac{20.0 m}{2}=10.0 m[/tex]

The wheel makes 4 revolution per minute, so the angular velocity is

[tex]\omega=4 rev/min[/tex]

Let's remind that

[tex]1 rev = 2 \pi rad[/tex]

[tex]1 min = 60 s[/tex]

So the angular velocity is

[tex]\omega=(4 rev/min) \cdot \frac{2 \pi rad/rev}{60 s/min}=0.42 rad/s[/tex]

So, the centripetal acceleration is

[tex]a_c=(0.42 rad/s)^2(10.0 m)=1.76 m/s^2[/tex]

(b) 509.1 N, upward

At the lowest point of the ride, we have the following forces:

- Normal force exerted by the seat on the child: N, upward

- Weight of the child: W = mg, downward

The resultant of these forces must be equal to the centripetal force, which is upward (towards the centre of the wheel), so we have the following equation

[tex]N-mg = ma_c[/tex]

From which we can find the normal reaction of the seat on the child:

[tex]N=m(g+a_c)=(44.0 kg)(9.81 m/s^2+1.76 m/s^2)=509.1 N[/tex]

(c) 354.2 N, upward

At the highest point of the ride, we have the following forces:

- Normal force exerted by the seat on the child: N, upward

- Weight of the child: W = mg, downward

The resultant of these forces must be equal to the centripetal force, which this time is downward (towards the centre of the wheel), so we have the following equation

[tex]mg-N = ma_c[/tex]

From which we can find the normal reaction of the seat on the child:

[tex]N=m(g-a_c)=(44.0 kg)(9.81 m/s^2-1.76 m/s^2)=354.2 N[/tex]

(d) 431.6 N, upward

When the child is halfway between the top and the bottom, the normal force exerted by the seat on the child is simply equal to the weight of the child; therefore we have:

[tex]N=mg=(44.0 kg)(9.81 m/s^2)=431.6 N[/tex]

Centripetal acceleration is towards the center. The force seat exerts on the child when the child is halfway between the top and bottom is 431.64 N.

The centripetal acceleration is caused due to change in direction of the body which is in a circular motion, the acceleration is towards the center of the circle. It is calculated using the formula,

[tex]a = \dfrac{v^2}{r}[/tex]

Given to us

Mass of the child, m = 44 kg

The angular velocity of the wheel, ω = 4 rev/ min. = 0.42 rev\sec

Diameter of the wheel, d = 20.0 m

The radius of the wheel, r = 10.0 m

A.) The centripetal acceleration of the child can be given as,

[tex]a = \dfrac{v^2}{r}[/tex]

Also, we know that the linear velocity is written as,

[tex]v = \omega \times r[/tex]

Substitute the value,

[tex]a = \dfrac{(\omega r)^2}{r} = \omega^2 r[/tex]

[tex]a = (0.42)^2 \times 10 = 1.764\ m/s^2[/tex]

B.) Force that the seat experts on the child,

At the point when the child is at the lowest point of the wheel,

there are three forces that will work on the child,

The normal force, that will act upwards on the child, N

The weight of the child that will act downwards, W = mg

The centripetal force that will act toward the center therefore upwards, [tex]F_c = m a[/tex]

Taking all the vertical forces,

[tex]\sum F_y = 0\\\\N + F_c = W\\\\N + ma = mg\\\\N = mg-ma\\\\N=m(g-a)\\\\\text{Substitute the values}\\\\N = 44(9.81-1.76)\\\\N = 354.2\ N[/tex]

C.) Force that the seat experts on the child,

At the point when the child is at the highest point of the wheel,

there are three forces that will work on the child,

The normal force, that will act upwards on the child, N

The weight of the child that will act downwards, W = mg

The centripetal force that will act toward the center therefore downwards, [tex]F_c = m a[/tex]

Taking all the vertical forces,

[tex]\sum F_y = 0\\\\N = F_c + W\\\\N = ma + mg\\\\N = mg+ma\\\\N=m(g+a)\\\\\text{Substitute the values}\\\\N = 44(9.81+1.76)\\\\N = 509.08\ N[/tex]

D.)C.) Force that the seat experts on the child,

At the point when the child is at the midway of the wheel,

there are three forces that will work on the child,

The normal force, that will act upwards on the child, N

The weight of the child that will act downwards, W = mg

The centripetal force that will act toward the center therefore Rightside, [tex]F_c = m a[/tex]

Taking all the vertical forces,

[tex]\sum F_y = 0\\\\N = W\\\\N = mg\\\\\text{Substitute the values}\\\\N = 44\times 9.81\\\\N = 431.64\ N[/tex]

Hence, the force seat exerts on the child when the child is halfway between the top and bottom is 431.64 N.

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Final answer:

The resistance when all three resistors are connected in series is 15.80 Ω. The resistance when all three resistors are connected in parallel is 1.67 Ω. For the other combinations, the same principles of series and parallel connections can be applied to calculate the resistances.

Explanation:

In a series circuit, the resistors are connected end-to-end, such that the total resistance is the sum of the individual resistances. So, in this case, the resistance when all three resistors are connected in series would be 6.50 Ω + 7.60 Ω + 1.70 Ω = 15.80 Ω.

In a parallel circuit, the resistors are connected in branches, such that the total resistance is determined by the reciprocal of the sum of the reciprocals of the individual resistances. So, in this case, the resistance when all three resistors are connected in parallel would be 1/(1/6.50 Ω + 1/7.60 Ω + 1/1.70 Ω) = 1.67 Ω.

For the other combinations, you can apply the same principles of series and parallel connections to calculate the resistances.

True.

Recycling programs in the United States have now become a major component  in today's waste management, unfortunately, recycling programs are not cost effective and are also considered to be one of most expensive ways of ridding waste.  According to author Harvey Black of the Environmental Health Perspectives Journal, in San Jose, California “it costs $28 per ton to landfill waste compared with $147 a ton to recycle” (Black 1006).

Answer:

Scientific law

Explanation:

In general, a scientific law is the description of an observed phenomenon, that is, it represents a phenomenon of nature that has proven invariably to occur whenever certain conditions exist. However, scientific law does not explain why the phenomenon exists or causes it. The explanation of the phenomenon is called scientific theory. Theories become laws after scientific research.

Answer:

Connect them in parallel

Explanation:

The energy stored by two capacitors connected to the same voltage source is given by

[tex]U=\frac{1}{2}C_T V^2[/tex]

where

[tex]C_T[/tex] is the total capacitance of the two capacitors

V is the voltage of the source

In order to maximize the energy stored U, we need to maximize [tex]C_T[/tex]. We have:

- In parallel, the total capacitance is given by the sum of the individual capacitances:

[tex]C_T(p) = C_1 + C_2[/tex]

- In series, the total capacitance is given by:

[tex]C_T(s)=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}[/tex]

Comparing the two equations, we notice that [tex]C_T(p)>C_T(s)[/tex], so the parallel configuration is the one that maximizes the energy stored.

Final answer:

To store the maximum amount of energy, capacitors should be connected in parallel as this configuration allows each capacitor to experience the same voltage as the source, maximizing the total stored charge and energy.

Explanation:

If you wish to store the maximum amount of energy in capacitors when connecting them across a voltage source, you should connect them in parallel. In a parallel configuration, each capacitor experiences the same voltage as the source. This setup ensures that the total capacitance is the sum of the individual capacitances, thus allowing for the storage of a maximum amount of energy. Capacitors in parallel have the advantage of maintaining the voltage across each capacitor equal to the source voltage, leading to a higher total charge stored in the system. Conversely, capacitors in series have a reduced total capacitance, as the voltage divides among them, making parallel connection the better choice for maximizing energy storage.

The Earth's magnetic field is believed to be generated by electric currents in the conductive iron alloys of its core, created by convection currents due to heat escaping from the core.

The solar wind is a stream of charged particles released from the upper atmosphere of the Sun, called the corona. This plasma consists of mostly electrons, protons and alpha particles with kinetic energy between 0.5 and 10 keV. Embedded within the solar-wind plasma is the interplanetary magnetic field. As Earth cruises through the black sea of space at about 67,000 mph (108,000 km/h), the planet's magnetic field pushes aside solar wind — the constant stream of plasma particles ejected by the sun — the same way the bow of a speeding motorboat pushes aside water.

The Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation.

A Van Allen radiation belt is a zone of energetic charged particles, most of which originate from the solar wind, that are captured by and held around a planet by that planet's magnetic field. Earth has two such belts and sometimes others may be temporarily created. 

An aurora (plural: auroras or aurorae), sometimes referred to as polar lights, northern lights (auroraborealis), southern lights (aurora australis), is a natural light display in the Earth's sky, predominantly seen in the high-latitude regions (around the Arctic and Antarctic). Charged particles from the sun strike atoms in Earth's atmosphere, they cause electrons in the atoms to move to a higher-energy state. When the electrons drop back to a lower energy state, they release a photon: light. This process creates the beautiful aurora, or northern lights.

Simulation of the interaction between Earth's magnetic field and the interplanetary magnetic field. Earth is largely protected from the solar wind, a stream of energetic charged particles emanating from the Sun, by its magnetic field, which deflects most of the charged particles.

What causes an aurora?

What does Earth do to the planet's magnetic fieldpushes aside solar wind?

Earth's magnetic field is created by the movement of molten iron within the Earth's outer core. This field protects the planet from the solar wind. Solar wind's interactions with the field create phenomena like the Van Allen belts and auroras.

The magnet that causes Earth’s magnetic field is not a physical magnet but rather the movement of molten iron within the Earth's outer core. This movement generates electric currents which, in turn, create a magnetic field.

Solar wind

is a stream of charged particles released from the Sun's atmosphere and when it hits the Earth’s magnetic field, it gets diverted causing a bow shock.

Yes, Earth’s magnetic field does protect the planet from the solar wind by acting as a shield that deflects the solar radiation around the planet. The Van Allen belts are zones of energized particles, trapped by Earth's magnetic field, and are essentially an extension of Earth's magnetic field into space. Aurora Borealis (Northern Lights) and Aurora Australis (Southern Lights), collectively called auroras, are caused by the interaction of the solar wind with Earth's magnetic field causing charged particles to emit light.

The principle of electromagnetism explains this interaction, as the charged particles from the solar wind have electric fields associated with them, which experience a force in Earth's magnetic field, causing them to move along the field lines. The additional questions can include: How does Earth’s magnetic field affect navigation? What are the impacts of the magnetic field flipping?

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Specific heat of a substance can be calculated using the equation q=mst, where “q” is heat applied to the system, “m” is the mass of the substance, “s” is the specific heat, and “t” is the change in temperature. In this case,

q=mst

(1495 J)=(339 g)(s)(+11 degrees C)

s=0.401 J/g•degrees C.

The specific heat of this substance is 0.401 J/g•degrees C). However, the problem is asking for the heat capacity of the metal, which is defined as C=ms using the same definitions as above. In this case, the heat capacity of the metal works out to be 135.91 J/g.

Hope this helps!

27% helium and 71% hydrogen

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

[tex]p_i = p_f\\m u_b + M u_B = (m+M)v[/tex]

where

m = 0.016 kg is the mass of the bullet

[tex]u_b = 280 m/s[/tex] is the initial velocity of the bullet

M = 3 kg is the mass of the block

[tex]u_B = 0[/tex] is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

[tex]v=\frac{m u_b}{m+M}=\frac{(0.016 kg)(280 m/s)}{0.016 kg+3 kg}=1.49 m/s[/tex]

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

[tex]K_i = \frac{1}{2}mu_b^2 = \frac{1}{2}(0.016 kg)(280 m/s)^2=627.2 J[/tex]

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

[tex]K_f = \frac{1}{2}(m+M)v^2=\frac{1}{2}(0.016 kg+3 kg)(1.49 m/s)^2=3.3 J[/tex]

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

(a) The final speed of the block after the collision is 1.485 m/s.

(b) The kinetic energy before the collision is 627.2 J and The total kinetic energy of the system after the collision is 3.33 J.

(c) The difference in the two kinetic energy is due to energy lost to frictional force during the collision.

The final speed of the block after the collision is determined by applying principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = v(m₁+ m₂)

0.016(280) + 3(0) = v(0.016 + 3)

4.48 = 3.016v

v = 4.48/3.016

v = 1.485 m/s

The kinetic energy before the collision is calculated as follows;

K.E i = ¹/₂mv²

K.Ei = 0.5 x 0.016 x 280²

K.Ei = 627.2 J

The total kinetic energy of the system after the collision is calculated as follows;

K.Ef = ¹/₂(m1 + m2) v²

K.Ef = ¹/₂(0.016 + 3) 1.485²

K.Ef = 3.33 J

The difference in the two kinetic energy is due to energy lost to frictional force during the collision.

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1) Magnitude of the force: [tex]1.6\cdot 10^{-12} N[/tex]

The magnitude of the electric force on an electric charge is:

[tex]F=qE[/tex]

where q is the charge and E the electric field. In this problem:

[tex]q = +e = +1.6\cdot 10^{-19} C[/tex] is the charge of the calcium ion

[tex]E=1.0 \cdot 10^7 N/C[/tex] is the magnitude of the electric field

Substituting,

[tex]F=(1.6\cdot 10^{-19}C)(1.0\cdot 10^7 N/C)=1.6\cdot 10^{-12} N[/tex]

2) Acceleration: [tex]2.5\cdot 10^{13} m/s^2[/tex]

The atomic mass of a calcium ion is approx. 40 a.m.u, this means that its mass is

[tex]m=40 \cdot (1.6\cdot 10^{-27}kg)=6.4\cdot 10^{-26} kg[/tex]

And so, the acceleration of the ion is given by Newton's second law:

[tex]a=\frac{F}{m}=\frac{1.6\cdot 10^{-12}N}{6.4\cdot 10^{-26} kg}=2.5\cdot 10^{13} m/s^2[/tex]

3) Yes

Explanation: a particle with same charge (+e) of the calcium ion could have the same acceleration of the calcium ion if it has exactly the same mass. In fact, the acceleration depends only on two factors: the mass and the force, so it both are the same, than the acceleration does not change.

4) The mass of the particle

In fact, the acceleration of the particle is given by:

[tex]a=\frac{F}{m}[/tex]

where F is the electric force and m the mass. Therefore, if the mass changes ,the acceleration changes as well.

A particle with the same mass and charge as calcium could have a different acceleration.

Let us recall that the electric field strength is the magnitude of the electric field at a point. Mathematically;

F = qE

F = electric force

q = charge on the +e ion

E electric field strength

F = 1.0 x 10^7 N/C x 1.6 x 10^-19 C

F = 1.6 x 10^-12 N

Since;

F =  ma

a = F/m = 1.6 x 10^-12 N/40(1.6 x 10^-27)

a = 2.5 x 10^13 ms-2

A particle with the same mass and charge as calcium could have a different acceleration. If the mass of the particle changes, the acceleration of the particle changes as also.

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answer is the color white

To determine the stopping distances for an automobile with different accelerations, we can calculate the distance traveled during the human reaction time and the deceleration distance. By adding these two distances, we can find the total stopping distance for each acceleration.

The stopping distance of an automobile can be determined by calculating the distance traveled during the human reaction time and the distance traveled during the deceleration period.

(a) For an acceleration of -5.5 m/s², the human reaction time is 1.0 s.

The distance traveled during the reaction time can be calculated using the formula: distance = initial velocity * reaction time. In this case, the initial velocity is 95 km/h, which needs to be converted to m/s.

The deceleration distance can be calculated using the formula: distance = (initial velocity²)/(2 * acceleration).

The stopping distance can be found by adding the distance traveled during the reaction time and the deceleration distance.

(b) The same process can be applied for an acceleration of -6.6 m/s².

There are 5 categories of hurricanes.

I don't know the 5 categories but i know there are 5

~Jax

Answer:

[tex]2.4\cdot 10^{-11} N[/tex]

Explanation:

Since the Earth's magnetic field is perpendicular to your direction of motion, the strength of the magnetic force exerted on your head is given by:

[tex]F=qvB[/tex]

where:

[tex]q=6\cdot 10^{-9}C[/tex] is the charge on your head

[tex]v=80 m/s[/tex] is the speed at which you are moving

[tex]B=5\cdot 10^{-5} T[/tex] is the strength of the magnetic field of the Earth

By substituting these numbers into the equation, we find the strength of the magnetic force:

[tex]F=(6\cdot 10^{-9}C)(80 m/s)(5\cdot 10^{-5} T)=2.4\cdot 10^{-11} N[/tex]