Final answer:
To find the probability of drawing a four and then a five from a standard deck with replacement, multiply the probabilities of the independent events: (1/13) × (1/13) = 1/169.
Explanation:
The question involves calculating the probability of two independent events when drawing cards from a standard deck. The first event (A) is drawing a card that is a four, and the second event (B) is drawing a card that is a five. The probability of each of these events is calculated separately since the card is replaced after each draw, making the draws independent of each other.
The probability of drawing a four (P(A)) from a standard deck is 1/13, as there are four fours in a 52-card deck. Similarly, the probability of drawing a five (P(B)) is also 1/13. Since the events are independent, the combined probability is the product of the two probabilities: P(A) × P(B) = (1/13) × (1/13) = 1/169.
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
ANSWER
[tex]x = 2 \: \: or \: \: x = 15[/tex]
Or
[tex]x = - 2 \: \: or \: \: x = - 15[/tex]
EXPLANATION
The given polynomial is
[tex] f(x) = {x}^{2} + kx + 30[/tex]
where a=1,b=k, c=30
Let the zeroes of this polynomial be m and n.
Then the sum of roots is
[tex]m + n = - \frac{b}{a} = -k [/tex]
and the product of roots is
[tex]mn = \frac{c}{a} = 30[/tex]
The square difference of the zeroes is given by the expression.
[tex]( {m - n})^{2} = {(m + n)}^{2} - 4mn [/tex]
From the question, this difference is 169.
This implies that:
[tex]( { - k)}^{2} - 4(30) = 169[/tex]
[tex]{ k}^{2} -120= 169[/tex]
[tex] k^{2} = 289[/tex]
[tex] k= \pm \sqrt{289} [/tex]
[tex]k= \pm17[/tex]
We substitute the values of k into the equation and solve for x.
[tex]f(x) = {x}^{2} \pm17x + 30[/tex]
[tex]f(x) = (x \pm2)(x \pm 15)[/tex]
The zeroes are given by;
[tex] (x \pm2)(x \pm 15) = 0[/tex]
[tex]x = \pm2 \: \: or \: \: x = \pm 15[/tex]
A number cube with the numbers 1 through 6 is rolled 159 times and shows the number four 27 times. Calculate the experimental probability of rolling a four.A number cube with the numbers 1 through 6 is rolled 159 times and shows the number four 27 times. Calculate the experimental probability of rolling a four.
Answer:
Step-by-step explanation:
answer: 27/159
The experimental probability of rolling a four is [tex]27 \div 159[/tex]
Given information:A number cube with the numbers 1 through 6 is rolled 159 times and shows the number four 27 times.
Calculation of probability:The experimental probability should be [tex]27 \div 159[/tex]
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Deanna is a dog groomer. On Monday, she groomed 12 dogs in 8 hours. On Tuesday, she groomed 9 dogs in 6 hours. On Wednesday, she groomed 6 dogs in 6 hours. Which statements are true about Deanna’s workload? Check all that apply. The Wednesday ratio was equal to the Monday ratio. The Monday ratio was equal to the Tuesday ratio. The Tuesday ratio was greater than the Wednesday ratio. The Wednesday ratio was less than the Monday ratio. The Monday ratio was twice the Wednesday ratio.
Answer:
The Monday ratio was equal to the Tuesday ratio.
The Tuesday ratio was greater than the Wednesday ratio.
The Wednesday ratio was less than the Monday ratio.
Step-by-step explanation:
Using the ratio and Proportion concept, The true statements are:
The Monday ratio was equal to the Tuesday ratio.
What is Ratio?
Comparing two amounts of the same units and determining the ratio tells us how much of one quantity is in the other. Two categories can be used to categorize ratios. Part to whole ratio is one, while part to part ratio is the other. The part-to-part ratio shows the relationship between two separate entities or groupings. For instance, a class has a 12:15 boy-to-girl ratio, but the part-to-whole ratio refers to the relationship between a particular group and the entire. For instance, five out of every ten people enjoy reading. As a result, the ratio of the portion to the total is 5: 10, meaning that 5 out of every 10 persons enjoy reading.
What is Proportion?
Ratio and fractions are the main bases on which proportion is discussed. Two ratios are equal when they are expressed as a fraction in the form of a/b, ratio a:b, and then a percentage. In this case, a and b can be any two numbers. Ratio and proportion are important building blocks for understanding the numerous ideas in science and mathematics.
So, According to the question:
The ratio on Monday = [tex]\frac{12}{8}[/tex] = [tex]\frac{3}{2}[/tex]
The ratio on Tuesday = [tex]\frac{9}{6}[/tex] = [tex]\frac{3}{2}[/tex]
The ratio on Wednesday = [tex]\frac{6}{6}[/tex] = [tex]\frac{1}{1}[/tex]
So, from the above fraction, we can easily conclude that The Monday ratio was equal to the Tuesday ratio.
Hence, The Monday ratio was equal to the Tuesday ratio.
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Please!!! Help!!
Let f(x)=x2−4x−32 .
Enter the x-intercepts of the quadratic function in the boxes.
well the intercepts are (8,0) and (-4,0) its a lot of math so you need to find it i would show you but i have a quiz
im not sure tho soo
Answer:
The x-intercepts of the quadratic function are 8 and -4.
Step-by-step explanation:
The given function is
[tex]f(x)=x^2-4x-32[/tex]
Equate the function f(x) equal to 0, to find the x-intercepts of the quadratic function.
[tex]f(x)=0[/tex]
[tex]x^2-4x-32=0[/tex]
The middle term can be written as -8x+4x.
[tex]x^2-8x+4x-32=0[/tex]
[tex]x(x-8)+4(x-8)=0[/tex]
Take out the common factors.
[tex](x-8)(x+4)=0[/tex]
Using zero product property,
[tex]x-8=0\Rightarrow x=8[/tex]
[tex]x+4=0\Rightarrow x=-4[/tex]
Therefore the x-intercepts of the quadratic function are 8 and -4.
Question 2 POST MATH
Answer:
D. x > -4 or x < -8
Step-by-step explanation:
For this case we must indicate the solution of the following inequalities:
[tex]4x> -16[/tex]
We divide both sides of the inequality by 4:
[tex]x> - \frac {16} {4}\\x> -4[/tex]
On the other hand we have:[tex]6x\leq - 48[/tex]
We divide between 6 on both sides of the inequality:
[tex]x\leq - \frac {48} {6}\\x\leq- 8[/tex]
Thus, the solution will be:
[tex]x>-4[/tex] or [tex]x\leq-8[/tex]
ANswer:
Option D
The table of values represents a polynomial function f(x).
How much greater is the average rate of change over the interval [5, 7] than the interval [2, 4] ?
Answer:
336
Step-by-step explanation:
The average rate of change is Δy/Δx.
On the interval [5, 7]:
(1469 - 549) / (7 - 5) = 460
On the interval of [2, 4]:
(287 - 39) / (4 - 2) = 124
The difference is:
460 - 124
336
The endpoints of a diameter of a circle are located at (5,9) and (11,17) which is an equation of the circle?
Answer:
(x - 8)² + (y - 13)² = 25
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
The centre is located at the midpoint of the endpoints of the diameter.
Use the midpoint formula to find the centre
[[tex]\frac{x_{1}+x_{2} }{2}[/tex], [tex]\frac{y_{1}+y_{2} }{2}[/tex] ]
with (x₁, y₁ ) = (5, 9) and (x₂, y₂ ) = (11,17)
centre = ( [tex]\frac{5+11}{2}[/tex], [tex]\frac{9+17}{2}[/tex] ) = (8, 13)
The radius is the distance from the centre to either end of the diameter
Calculate r using the distance formula
r = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (8, 13) and (x₂, y₂ ) = (5, 9)
r = [tex]\sqrt{(5-8)^2+(9-13)^2}[/tex]
= [tex]\sqrt{(-3)^2+(-4)^2}[/tex]
= [tex]\sqrt{9+16}[/tex] = [tex]\sqrt{25}[/tex] = 5 ⇒ r² = 25
Hence
(x - 8)² + (y - 13)² = 25
Solve for x: -4√3x-2 +6=22
Show your work.
[tex] - 4 \sqrt{3} x - 2 + 6 = 22 \\ - 4 \sqrt{3}x + 4 = 22 \\ - 4 \sqrt{3}x = 18 \\ x = \frac{18}{ - 4 \sqrt{3} } = \frac{ - 18 \sqrt{3} }{12} = \frac{ - 3 \sqrt{3} }{2} = - 1.5 \sqrt{3} [/tex]
HOPE THIS WILL HELP YOU
The solution depends on the argument of the square root. Please be more precise and less ambiguous when writing your questions.
You could either mean:
[tex]-4\sqrt{3}x-2+6=22,\quad -4\sqrt{3x}-2+6=22,\quad -4\sqrt{3x-2}+6=22[/tex]
In the first case, we have
[tex]-4\sqrt{3}x-2+6=22 \iff -4\sqrt{3}x= 18 \iff x = -\dfrac{18}{4\sqrt{3}}[/tex]
In the second case, we have
[tex]-4\sqrt{3x}-2+6=22 \iff \sqrt{3x}=-\dfrac{9}{2}[/tex]
which has no solution, because a square root can't be negative
In the third case, we have
[tex]-4\sqrt{3x-2}+6=22 \iff -4\sqrt{3x-2}=16 \iff \sqrt{3x-2}=-4[/tex]
which again has no solution, for the same reason.
Year Population (in millions)
2002 14.5
2003 15.1
2004 15.9
2005 17
2006 19.2
2007 21
Below is a table for the population of Florida from 2002 to 2007. What is the correlation coefficient of the best fit model?
A) 0.982
B) 0.972
C) 0.992
D) 0.947
Answer:
B) 0.972
Step-by-step explanation:
To be able to calculate the correlation coefficient of the model you just have to divide the number of one year by the number of the next year. TO make it clearer you can do it with the years 2002 and 2003:
Correlation Coefficient= [tex]\frac{14.5}{15.1}[/tex]=.960 and since the closest to that number is the .972 that´s the one that is the correct answer.
Select the correct difference. -3z 5 - (-7z 5) (A)-10z5 (B)-4z5 (C)4z5 (D)4z
Answer:
Correct choice is (C). [tex]4z^5[/tex].
Step-by-step explanation:
Given expression is [tex]-3z^5-\left(-7z^5\right)[/tex].
Now we need to simplify that then select the correct difference value from the given choices.
[tex]-3z^5-\left(-7z^5\right)[/tex]
negative times negative is positive
[tex]=-3z^5+7z^5[/tex]
Combine like terms because variable z has same exponent.
[tex]=(-3+7)z^5[/tex]
[tex]=4z^5[/tex]
Hence correct choice is (C). [tex]4z^5[/tex].
According to the Rational Roots Theorem, which statement about f(x) = 25x7 – x6 – 5x4 + x – 49 is true? Any rational root of f(x) is a multiple of –49 divided by a multiple of 25. Any rational root of f(x) is a multiple of 25 divided by a multiple of –49. Any rational root of f(x) is a factor of –49 divided by a factor of 25. Any rational root of f(x) is a factor of 25 divided by a factor of –49.
Answer:
Any rational root of f(x) is a factor of -49 divided by a factor of 25
Step-by-step explanation:
The Rational Roots Theorem states that, given a polynomial
[tex]p(x) = a_nx^n+a_{n-1}x^{n-1}+\ldots+a_2x^2+a_1x+a_0[/tex]
the possible rational roots are in the form
[tex]x=\dfrac{p}{q},\quad p\text{ divides } a_0,\quad q\text{ divides } a_n[/tex]
The rational root theorem is used to determine the possible roots of a function.
The true statement about [tex]f(x) = 25x^7 - x^6 - 5x^4 + x - 49[/tex] is (c) Any rational root of f(x) is a factor of =-49 divided by a factor of 25.
For a rational function,
[tex]f(x) = px^n + ax^{n-1} + ...................... + bx + q[/tex]
The potential roots by the rational root theorem are:
[tex]Roots = \pm\frac{Factors\ of\ q}{Factors\ of\ p}[/tex]
By comparison,
p = 25, and q = -49
So, we have:
[tex]Roots = \pm\frac{Factors\ of\ -49}{Factors\ of\ 25}[/tex]
Hence, the true statement about [tex]f(x) = 25x^7 - x^6 - 5x^4 + x - 49[/tex] is (c)
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help pls :)
.
.
.
If 3x-4y=4 & x+2y=18, then evaculate x^2 +y^2 +xy=
Answer:
129Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}3x-4y=4\\x+2y=18&\text{multiply both sides by 2}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}3x-4y=4\\2x+4y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad5x=40\qquad\text{divide both sides by 5}\\.\qquad\boxed{x=8}\\\\\text{Put the value of x to the second equation:}\\\\8+2y=18\qquad\text{subtract 8 from both sides}\\2y=10\qquad\text{divide both sides by 2}\\\boxed{y=5}[/tex]
[tex]\text{Put the values of x and y to the expression}\ x^2+y^2+xy:\\\\8^2+5^2+(8)(5)=64+25+40=129[/tex]
WILL AWARD 90 POINTS
The results of a survey indicate that the true proportion of households who want a park in their neighborhood is likely in the interval (0.58, 0.84) .
What is the point estimate of the proportion of households who want a park in their neighborhood?
Enter your answer, as a decimal, in the box.
the point estimate typically is in the middle of the interval, so it would be at (1/2)(0.52+0.80) or 0.66.
The cost of a postage is determined by the following step function: How much would a package that weighs 3 ounces cost, in cents?
A) 45
B) 44
C) 43
D) 42
Answer:
I think its C) 43. Let me know what you get
Answer:
it's 43
Step-by-step explanation:
i got the answer right
Which graph represents the function f(x) = (x – 3)^2?
Answer:
Step-by-step explanation:
Please, share the possible answer choices next time.
The graph of a parabola y = x^2 has its vertex at the origin, (0, 0), and opens up. By replacing x with (x - 3), we translate the graph 3 units to the right.
Answer:
the answer is c
Step-by-step explanation:
Alan will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $55 and costs an additional $0.50 per mile driven. The second plan has no initial fee but costs $0.70 per mile driven. How many miles would Alan need to drive for the two plans to cost the same?
Answer:
275 miles
Step-by-step explanation:
Let x be the number of miles Alan has to drive to get the same cost for tha two plans.
1 plan: total cost
[tex]55+0.50x[/tex]
2 plan: total cost
[tex]0.7x[/tex]
Equate them:
[tex]55+0.5x=0.7x\\ \\55=0.2x\\ \\550=2x\\ \\x=275[/tex]
Answer:
275 miles
Step-by-step explanation:
You can express the cost of each plan as follows:
Plan 1: 55+0.50x
Plan 2: 0.70x
x is the amount of miles driven
As you need to find the amount of miles where the two plans cost the same, you can equate them and solve for x:
55+0.50x= 0.70x
55= 0.70x-0.50x
55= 0.2x
x= 55/0.2
x= 275
Alan needs to drive 175 miles for the two plans to cost the same.
An aquarium holds 11.54 cubic feet of water, and is 2.7 feet long and 1.8 feet wide. What is it's depth? Round your answer to the nearest whole number.
Answer:
2.3744 ft
Step-by-step explanation:
11.54/(2.7*1.8)
Solve the system of equations. y = 2x y = x 2 – 15
A. (–3, –6) and (–5, –10)
B. (3, 6) and (–5, –10)
C. (3, 6) and (5, 10)
D. (–3, –6) and (5, 10)
Answer:
d is your answer
Step-by-step explanation:
Answer:
Option D.
Step-by-step explanation:
The given system of equations is
[tex]y=2x[/tex] ....(i)
[tex]y=x^2-15[/tex] ...(ii)
From (i) and (ii) we get
[tex]x^2-15=2x[/tex]
[tex]x^2-2x-15=0[/tex]
[tex]x^2-5x+3x-15=0[/tex]
[tex]x(x-5)+3(x-5)=0[/tex]
[tex](x-5)(x+3)=0[/tex]
Using zero produc property we get
[tex]x-5=0\Rightarrow x=5[/tex]
[tex]x+3=0\Rightarrow x=-3[/tex]
If x=5, then
[tex]y=2(5)=10[/tex]
If x=-3, then
[tex]y=2(-3)=-6[/tex]
The solutions of the given system of equations are (-3,-6) and (5,10).
Therefore, the correct option is D.
Which system of equations can be used to find the roots of the equation 12x3-5x=2x2+x+6
Answer:
A [tex]\left\{\begin{array}{l}y=12x^3-5x\\ \\y=2x^2+x+6\end{array}\right.[/tex]
Step-by-step explanation:
The equation [tex]12x^3-5x=2x^2+x+6[/tex] have in both sides expressions [tex]12x^3-5x[/tex] and [tex]2x^2+x+6.[/tex]
Therefore, the system of two equations
[tex]\left\{\begin{array}{l}y=12x^3-5x\\ \\y=2x^2+x+6\end{array}\right.[/tex]
has the solution (x,y), where x is the solution of the equation above.
ANSWER
[tex]y = 12 {x}^{3} - 5x[/tex]
{
[tex]y= 2 {x}^{2} + x + 6[/tex]
EXPLANATION
The given equation is
[tex]12 {x}^{3} - 5x = 2 {x}^{2} + x + 6[/tex]
To find the system of equations, we just have to equate each side of the equation to y and form two different equations.
The left sides gives one equation,
[tex]y = 12 {x}^{3} - 5x[/tex]
The right side also gives,
[tex]y= 2 {x}^{2} + x + 6[/tex]
Hence the correct choice is A
Graph the opposite of the opposite of 2 on the number line.
Answer:
see below
Step-by-step explanation:
The opposite of 2 is -2. The opposite of that is -(-2) = 2. The graph shows 2 on the number line.
Answer:
-2
Step-by-step explanation:
When it comes to negatives and positives, both are the opposite of each other because they are on the opposite sides on the number line. For example, the opposite of 9 would be -9. Or, the opposite of -9 is 9.
Find the value of x, round the length to the nearest meter
ANSWER
405m
EXPLANATION
We know the opposite side of of the right triangle to be 4629m and the given angle is 85°.
Since we want to find the adjacent side which is x units, we use the tangent ratio to obtain,
[tex] \tan(85 \degree) = \frac{opposite}{adjacent} [/tex]
[tex] \tan(85 \degree) = \frac{4629}{x} [/tex]
Solve for x.
[tex]x = \frac{4629}{\tan(85 \degree)} [/tex]
x=404.985
To the nearest meter, x=405m
Answer: 405m
Step-by-step explanation:
Identify m∠CAR HELP ME ASAP!!
360 - 130 = 230
Measure of CAR = 230/2.
CAR = 115
There were 230{,}600230,600230, comma, 600 jobs available in the field of radiology in the year 201420142014. Each year, that number is expected to grow by 0.9\%0.9%0, point, 9, percent. Write a function that gives the expected number j(t)j(t)j, left parenthesis, t, right parenthesis of jobs in radiology ttt years from the year 201420142014. Do not use commas in your answer. J(t)=j(t)
Answer:
j(t)=230600(1.009)^t
Step-by-step explanation:
Increasing at a rate of 0.9\%0.9%0, point, 9, percent means the expected number of jobs keeps its 100\%100%100, percent and adds 0.9\%0.9%0, point, 9, percent more, for a total of 100.9\%100.9%100, point, 9, percent.
So each year, the expected number of jobs is multiplied by 100.9\%100.9%100, point, 9, percent, which is the same as a factor of 1.0091.0091, point, 009.
If we start with the initial number of jobs, 230{,}600230,600230, comma, 600 jobs, and keep multiplying by 1.0091.0091, point, 009, this function gives us expected number of jobs in radiology ttt years from 201420142014:
j(t)=230600(1.009)^t
Answer:
[tex]J(t) =230600(1.009)^t[/tex]
Step-by-step explanation:
Given,
The initial number of jobs ( or jobs on 2014 ), P = 230,600
Also, the rate of increasing per year, r = 0.9% = 0.009,
Thus, the number of jobs after t years since 2014,
[tex]J(t)=P(1+r)^t[/tex]
[tex]=230600(1+0.009)^t[/tex]
[tex]=230600(1.009)^t[/tex]
Which is the required function.
The surface areas of two similar figures are 64 m^2 and 169 m^2. The volume of the larger figure is 4394 m^3. What is the volume of the smaller figure?
Set up a ratio for the area.
Area is squared so find the square root of the scale
√64/169 = 0.61538
Volume is cubed so cube the scale factor:
0.61538^3 = 0.23304
Multiply that by the volume:
4394 x 0.23304 = 1024
The volume of the smaller figure is 1,024 m^3
Answer:
1024 m³Step-by-step explanation:
We know:
The ratio of the surface of two similar figures is equal to the square of the similarity scale. The ratio of the volume of two similar figures is equal to the cube of the similarity scale.
Therefore
k - similarity scale
[tex]k^2=\dfrac{64}{169}\to k=\sqrt{\dfrac{64}{169}}=\dfrac{\sqrt{64}}{\sqrt{169}}=\dfrac{8}{13}\\\\\dfrac{V}{4394}=\left(\dfrac{8}{13}\right)^3\\\\\dfrac{V}{4394}=\dfrac{512}{2197}\qquad\text{cross multiply}\\\\2197V=(512)(4394)\qquad\text{divide both sides by 2197}\\\\V=(512)(2)\\\\V=1024\ m^3[/tex]
PLEASE HELP ME!!! WILL MARK BRAINLIEST!!!
The number of chips of different colors in Amy's bag is shown below:
8 blue chips
9 pink chips
1 white chip
Amy takes out a chip from the bag randomly without looking. She replaces the chip and then takes out another chip from the bag. What is the probability that Amy takes out a pink chip in both draws?
9 over 18 multiplied by 8 over 17 equals 72 over 306
9 over 18 plus 8 over 17 equals 297 over 306
9 over 18 multiplied by 9 over 18 equals 81 over 324
9 over 18 plus 9 over 18 equals 18 over 18
(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.
In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).
The total number of chips of different colors in Amy's bag is:
8 blue chips + 9 pink chips + 1 white chip = 18 color chips
Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.
So, the probability that Amy takes out a pink chip in the first draw is:
P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:
P(B) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.
What is the probability that Amy takes out a pink chip in both draws?
P(A∩B) = P(A)P(B)
P(A∩B) = (9/18)(9/18) = 81/324
Probability of taking out pink chip in both draws is equal to [tex]9[/tex] over [tex]18[/tex]multiplied by [tex]9[/tex] over [tex]18[/tex] equals [tex]81[/tex] over [tex]324[/tex].
What is probability?" Probability is defined as the ratio of number of favourable outcomes to the total number of outcomes."
Formula used
Probability [tex]= \frac{n(F)}{n(T)}[/tex]
[tex]n(F)=[/tex] Number of favourable outcomes
[tex]n(T)=[/tex] Total number of outcomes
For independent events
[tex]P(A\cap B) = P(A) \times P(B)[/tex]
According to the question,
Given,
Total number of chips [tex]= 18[/tex]
Number of pink chips [tex]= 9[/tex]
[tex]'A'[/tex] represents the event of taking out pink chip first time
[tex]'B'[/tex] represents the event of taking out pink chip second time
Probability of taking out pink chip first time [tex]'P(A)' = \frac{9}{18}[/tex]
After replaces the chips again number of chip remain same
Probability of taking out pink chip second time [tex]'P(B)' = \frac{9}{18}[/tex]
Both the events are independent to each other
Substitute the value in the formula of probability of independent event we get,
Probability of taking out pink chip in both draw
[tex]P(A \cap B) = \frac{9}{18} \times \frac{9}{18}[/tex]
[tex]= \frac{81}{324}[/tex]
Hence, probability of taking out pink chip in both draw is equal to [tex]9[/tex] over [tex]18[/tex]multiplied by [tex]9[/tex] over [tex]18[/tex] equals [tex]81[/tex] over [tex]324[/tex].
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Find the quotient. Simplify your answer.
b + 3 3
Answer:
[tex]\frac{b+3}{3}[/tex]
Step-by-step explanation:
[tex]\frac{b+3}{b} \div\frac{3}{b}[/tex]
We need to solve the above equation.
We replace the division sign by multiplication and reciprocated the second term
[tex]=\frac{b+3}{b} *\frac{b}{3}[/tex]
Multiplying both fractions:
[tex]=\frac{(b+3)*b}{3b}[/tex]
Cancelling b from numerator and denominator.
[tex]=\frac{(b+3)}{3}[/tex]
So, answer is:
[tex]\frac{b+3}{3}[/tex]
ANSWER
[tex]\frac{b + 3}{3}[/tex]
EXPLANATION
The given expression is
[tex] \frac{b + 3}{b} \div \frac{3}{b} [/tex]
We multiply the first fraction by the multiplicative inverse of the second fraction.
[tex]\frac{b + 3}{b} \times \frac{b}{3}[/tex]
We now cancel out the common factors to get:
[tex]\frac{b + 3}{3} [/tex]
Therefore simplified form is:
[tex]\frac{b + 3}{3} [/tex]
A circular platform is to be built in a playground. The center of the structure is required to be equidistant from three support columns located at D(−2,−4), E(1,5), and F(2,0). What are the coordinates for the location of the center of the platform?
Answer:
The coordinates for the location of the center of the platform are (-1 , 2)
Step-by-step explanation:
* Lets revise the equation of the circle
- The equation of the circle of center (h , k) and radius r is:
(x - h)² + (y - k)² = r²
- The center is equidistant from any point lies on the circumference
of the circle
- There are three points equidistant from the center of the circle
- We have three unknowns in the equation of the circle h , k , r
- We will substitute the coordinates of these point in the equation of
the circle to find h , k , r
* Lets solve the problem
∵ The equation of the circle is (x - h)² + (y - k)² = r²
∵ Points D (-2 , -4) , E (1 , 5) , F (2 , 0)
- Substitute the values of x and y b the coordinates of these points
# Point D (-2 , -4)
∵ (-2 - h)² + (-4 - k)² = r² ⇒ (1)
# Point E (1 , 5)
∵ (1 - h)² + (5 - k)² = r² ⇒ (2)
# Point (2 , 0)
∵ (2 - h)² + (0 - k)² = r²
∴ (2 - h)² + k² = r² ⇒ (3)
- To find h , k equate equation (1) , (2) and equation (2) , (3) because
all of them equal r²
∵ (-2 - h)² + (-4 - k)² = (1 - h)² + (5 - k)² ⇒ (4)
∵ (1 - h)² + (5 - k)² = (2 - h)² + k² ⇒ (5)
- Simplify (4) and (5) by solve the brackets power 2
# (a ± b)² = (a)² ± (2 × a × b) + (b)²
# Equation (4)
∴ [(-2)² - (2 × 2 × h) + (-h)²] + [(-4)² - (2 × 4 × k) + (-k)²] =
[(1)² - (2 × 1 × h) + (-h)²] + [(5)² - (2 × 5 × k) + (-k)²]
∴ 4 - 4h + h² + 16 - 8k + k² = 1 - 2h + h² + 25 - 10k + k² ⇒ add like terms
∴ 20 - 4h - 8k + h² + k² = 26 - 2h - 10k + h² + k² ⇒ subtract h² and k²
from both sides
∴ 20 - 4h - 8k = 26 - 2h - 10k ⇒ subtract 20 and add 2h , 10k
for both sides
∴ -2h + 2k = 6 ⇒ (6)
- Do the same with equation (5)
# Equation (5)
∴ [(1)² - (2 × 1 × h) + (-h)²] + [(5)² - (2 × 5 × k) + (-k)²] =
[(2)² - (2 × 2 × h) + k²
∴ 1 - 2h + h² + 25 - 10k + k² = 4 - 4h + k²⇒ add like terms
∴ 26 - 2h - 10k + h² + k² = 4 - 4h + k² ⇒ subtract h² and k²
from both sides
∴ 26 - 2h - 10k = 4 - 4h ⇒ subtract 26 and add 4h
for both sides
∴ 2h - 10k = -22 ⇒ (7)
- Add (6) and (7) to eliminate h and find k
∴ - 8k = -16 ⇒ divide both sides by -8
∴ k = 2
- Substitute this value of k in (6) or (7)
∴ 2h - 10(2) = -22
∴ 2h - 20 = -22 ⇒ add 20 to both sides
∴ 2h = -2 ⇒ divide both sides by 2
∴ h = -1
* The coordinates for the location of the center of the platform are (-1 , 2)
Answer:
The coordinates for the location of the center of the platform are (-3.5,1.5)
Step-by-step explanation:
You have 3 points:
D(−2,−4)
E(1,5)
F(2,0)
And you have to find a equidistant point (c) ([tex]x_{c}[/tex],[tex]y_{c}[/tex]) from the three given.
Then, you know that:
[tex]D_{cD}=D_{cE}[/tex]
And:
[tex]D_{cE}=D_{cF}[/tex]
Where:
[tex]D_{cD}[/tex]=Distance between point c to D
[tex]D_{cE}[/tex]=Distance between point c to E
[tex]D_{cF}[/tex]=Distance between point c to D
The equation to calculate distance between two points (A to B) is:
[tex]D_{AB}=\sqrt{(x_{B}-x_{A})^2+(y_{B}-y_{A})^2)}[/tex]
[tex]D_{AB}=\sqrt{(x_{B}^2)-(2*x_{B}*x_{A})+(x_{A}^2)+(y_{B}^2)-(2*y_{B}*x_{A})+(y_{A}^2)}[/tex]
Then you have to calculate:
*[tex]D_{cD}=D_{cE}[/tex]
[tex]D_{cD}=\sqrt{(x_{D}-x_{c})^2+(y_{D}-y_{c})^2}[/tex]
[tex]D_{cD}=\sqrt{(x_{D}^2)-(2*x_{D}*x_{c})+(x_{c}^2)+(y_{D}^2)-(2*y_{D} y_{c})+(y_{c}^2)}[/tex]
[tex]D_{cD}=\sqrt{(-2^2-(2(-2)*x_{c})+x_{c}^2)+(-4^2-(2(-4) y_{c})+y_{c}^2)}[/tex]
[tex]D_{cD}=\sqrt{(4+4x_{c}+x_{c}^2 )+(16+8y_{c}+y_{c}^2)}[/tex]
[tex]D_{cE}=\sqrt{(x_{E}-x_{c})^2+(y_{E}-y_{c})^2}[/tex]
[tex]D_{cE}=\sqrt{(x_{E}^2)-(2*x_{E}*x_{c})+(x_{c}^2)+(y_{E}^2)-(2y_{E}*y_{c})+(y_{c}^2)}[/tex]
[tex]D_{cE}=\sqrt{(1^2-2(1)*x_{c}+x_{c}^2)+(5^2-2(5)+y_{c}+y_{c}^2)}[/tex]
[tex]D_{cE}=\sqrt{(1-2x_{c}+x_{c}^2)+(25-10y_{c}+y_{c}^2)}[/tex]
[tex]D_{cD}=D_{cE}[/tex]
[tex]\sqrt{((4+4x_{c}+x_{c}^2)+(16+8y_{c}+y_{c}^2))}=\sqrt{(1-2x_{c}+x_{c}^2)+(25-10y_{c}+y_{c}^2)}[/tex]
[tex](4+4x_{c}+x_{c}^2)+(16+8y_{c}+y_{c}^2)= (1-2x_{c}+x_{c}^2)+(25-10y_{c}+y_{c}^2)[/tex]
[tex]x_{c}^2+y_{c}^2+4x_{c}+8y_{c}+20=x_{c}^2+y_{c}^2-2x_{c}-10y_{c}+26[/tex]
[tex]4x_{c}+2x_{c}+8y_{c}+10y_{c}=6[/tex]
[tex]6x_{c}+18y_{c}=6[/tex]
You get equation number 1.
*[tex]D_{cE}=D_{cF}[/tex]
[tex]D_{cE}=\sqrt{(x_{E}-x_{c})^2+(y_{E}-y_{c})^2}[/tex]
[tex]D_{cE}=\sqrt{(x_{E}^2-(2+x_{E}*x_{c})+x_{c}^2)+(y_{E}^2-(2y_{E} *y_{c})+y_{c}^2)}[/tex]
[tex]D_{cE}=\sqrt{((1^2-2(1)+x_{c}+x_{c}^2)+(5^2-2(5)y_{c}+y_{c}^2)}[/tex]
[tex]D_{cE}=\sqrt{(1-2x_{c}+x_{c}^2 )+(25-10y_{c}+y_{c}^2)}[/tex]
[tex]D_{cF}=\sqrt{(x_{F}-x_{c})^2+(y_{F}-y_{c})^2}[/tex]
[tex]D_{cF}=\sqrt{(x_{F}^2-(2*x_{F}*x_{c})+x_{c}^2)+(y_{F}^2-(2*y_{F}* y_{c})+y_{c}^2)}[/tex]
[tex]D_{cF}=\sqrt{(2^2-(2(2)x_{c})+x_{c}^2)+(0^2-(2(0)y_{c}+y_{c}^2)}[/tex]
[tex]D_{cF}=\sqrt{(4-4x_{c}+x_{c^2})+(0-0+y_{c}^2)}[/tex]
[tex]D_{cE}=D_{cF}[/tex]
[tex]\sqrt{(1-2x_{c}+x_{c}^2 )+(25-10y_{c}+y_{c}^2)}=\sqrt{(4-4x_{c}+x_{c}^2 )+(0-0+y_{c}^2)}[/tex]
[tex](1-2x_{c}+x_{c}^2)+(25-10y_{c}+y_{c}^2 )=(4-4x_{c}+x_{c}^2)+(0-0+y_{c}^2)[/tex]
[tex]x_{c}^2+y_{c}^2-2x_{c}-10y_{c}+26=x_{c}^2+y_{c}^2-4x_{c}+4[/tex]
[tex]-2x_{c}+4x_{c}-10y_{c}=-22[/tex]
[tex]2x_{c}-10y_{c}=-22[/tex]
You get equation number 2.
Now you have to solve this two equations:
[tex]6x_{c}+18y_{c}=6[/tex] (1)
[tex]2x_{c}-10y_{c}=-22[/tex] (2)
From (2)
[tex]-10y_{c}=-22-2x_{c}[/tex]
[tex]y_{c}=(-22-2x_{c})/(-10)[/tex]
[tex]y_{c}=2.2+0.2x_{c}[/tex]
Replacing [tex]y_{c}[/tex] in (1)
[tex]6x_{c}+18(2.2+0.2x_{c})=6[/tex]
[tex]6x_{c}+39.6+3.6x_{c}=6[/tex]
[tex]9.6x_{c}=6-39.6[/tex]
[tex]x_{c}=6-39.6[/tex]
[tex]x_{c}=-3.5[/tex]
Replacing [tex]x_{c}=-3.5[/tex] in
[tex]y_{c}=2.2+0.2x_{c}[/tex]
[tex]y_{c}=2.2+0.2(-3.5)[/tex]
[tex]y_{c}=2.2+0.2(-3.5)[/tex]
[tex]y_{c}=2.2-0.7[/tex]
[tex]y_{c}=1.5[/tex]
Then the coordinates for the location of the center of the platform are (-3.5,1.5)
A cube with a length of 37 miles, a width of 30 miles and a depth of 2 mles can be used to model a large lake located in the Unted States of America Only 65% of the lake contans fish If there are 115,200 fish n this lake, what is the average population density of fish per cubic mile, to the nearest fish?
Find the volume of the lake:
37 x 30 x 2 = 2,220 cubic miles.
Now find 65% of the total volume:
2,220 x 0.65 = 1,443 cubic miles
Divide the number of fish by the volume of the lake:
115, 200 fish / 1,443 cubic miles = 79.83 fish per cubic mile.
Rounded to the nearest fish = 80 fish per cubic mile.
Answer:
80 fish per cubic mile.
A store sells jars of peanut butter that cost p dollars and jars of jelly that cost j dollars. Winston purchased 3 jars of peanut butter and 2 jars of jelly for $11.50. Peter purchased 2 jars of peanut butter and 4 jars of jelly for $13.00. How much does 1 jar of peanut butter cost? A. $2.00 B. $2.50 C. $3.00 D. $3.50
Answer:
The cost of 1 jar of peanut butter is $2.50 ⇒ answer B
Step-by-step explanation:
* Lets change the story problem to equations to solve it
- The cost of a jar of peanut butter is p dollars
- The cost of a jar of jelly is j dollars
- Winston purchased 3 jars of peanut butter and 2 jars of jelly for $11.50
- Peter purchased 2 jars of peanut butter and 4 jars of jelly for $13.00
* Lets write the equations
∵ The cost of a jar of peanut butter is p dollars and the cost of a jar
of jelly is j dollars
∵ Winston purchased 3 jars of peanut butter and 2 jars of jelly for $11.50
∴ 3p + 2j = 11.50 ⇒ (1)
∵ Peter purchased 2 jars of peanut butter and 4 jars of jelly for $13.00
∴ 2p + 4j = 13.00 ⇒ (2)
- Lets solve this system of equation by using elimination method
- Multiply equation (1) by -2
∴ -6p - 4j = - 23 ⇒ (3)
- Add equations (2) and (3)
∴ -4p = -10 ⇒ divide both sides by -4
∴ p = 2.5
∵ p is the cost of 1 jar of peanut butter
* The cost of 1 jar of peanut butter is $2.50
Final answer:
Using a system of equations based on the purchases of Winston and Peter, the price of one jar of peanut butter is calculated to be $2.50.
Explanation:
To determine the cost of one jar of peanut butter, we can set up a system of equations based on the information provided. Let p represent the price of one jar of peanut butter, and j represent the price of one jar of jelly.
The system of equations based on the purchases made by Winston and Peter are:
1) 3p + 2j = 11.50
2) 2p + 4j = 13.00
To solve for p, we can multiply equation 1) by 2 and equation 2) by 3 to eliminate j when we subtract one equation from the other.
2*(1): 6p + 4j = 23.00
3*(2): 6p + 12j = 39.00
Subtracting the first equation from the second, we get:
6p + 12j - (6p + 4j) = 39.00 - 23.00
8j = 16.00
j = 2.00
Now, substitute j = 2.00 into equation 1) to find p:
3p + 2(2.00) = 11.50
3p + 4.00 = 11.50
3p = 7.50
p = 2.50
Therefore, one jar of peanut butter costs $2.50, which corresponds with option B.
Which shows translation
Will give BRAINLIEST.
Can't see it very, well is it a?
The line of music which shows a translation is b.
Translation means moving.
The Second line of music shows a translation from all the lines.
What is translation?The translation is defined as the sliding of an object without changing its shape and size.
In this figure, the second option shows the exact translation operation. but the first and third line doesn't represent a translation.
In the first option, the translation does not take place, the music lines are inverted.
In the third option, the music lines are just interchanged which doesn't prove the translation.
Learn more about translation;
brainly.com/question/15487308