what factors determine the magnitude of the electric force between two particles ?
a. charge and distance
b. mass and distance
c. charge and density
d. mass and charge
Answer: Charge and distance
Explanation:
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 800.0 K?
Strontium-85 has a half-life of 65 days. how long will it take for the radiation level of strontium-85 to drop to one-fourth of its original level?
Answer:
130 days
Explanation:
Strontium-85 has a half-life of 65 days. how long will it take for the radiation level of strontium-85 to drop to one-fourth of its original level?
Strontium-85 is a radioactive element. so it takes 65days for one strontium of a particular mass to decrease to half of its initial size
Half life is the time taken for a radioactive element to decrease to half of its initial size. it decays by half every 65 days.
from 1 to 1/2 = 65 days
from 1/2 to 1/4 =65 days
from 1/4 to 1/8 = 65 days
from 1/8 to 1/16 = 65 days
total time taken to decay from original amount to 1/4 is two half lives =
65+65=130 days
The time it will take for the radiation level of Strontium-85 to drop to one-fourth of its original level is 130 days.
To calculate the time it will take for Strontium-85 to drop to one-fourth of its original value, we use the formula below.
Formula:
R = [tex]2^{a/n}[/tex](R')................ Equation 1Where:
R = Original amount of Strontium-85R' = Amount of Strontium-85 left after decaya = Total timen = half-life.From the question,
Given:
n = 65 daysAssuming,
R = y R' = y/4Substitute the given values and the assumed values into equation 1
y = y/4([tex]2^{a/65}[/tex])Solve for a
y(4/y) = [tex]2^{a/65}[/tex]4 = [tex]2^{a/65}[/tex]2² = [tex]2^{a/65}[/tex]Equating the base,
2 = a/65a = 65×2a = 130 days.Hence, The time it will take for the radiation level of Strontium-85 to drop to one-fourth of its original level is 130 days.
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Discuss how electromagnets have been created that are strong enough to pick up cars in a wrecking yard and are able to be switched off, dropped the cars onto a scrap pile to be crushed.
An inductor is just a coil of wire with magnetic properties. It is a device that stores electromotive force or energy in the form of magnetic field. A current yields a magnetic field around it through a conductor. The pattern of flux for this magnetic field would be the number of concentric circle perpendicular to the detection of current. The capacity of the inductor is affected by the number of coils which would give more inductance, the material that is used for the coil, the cross sectional area of the coil and the length of the coil. For instance you have an 8 meters diameter coil with seven loops of wire. You place the coil on an area where there is a parked car. The inductance of the coil will be much larger compared to the coil without a parked car nearby because of the presence of the steel from the car. It changes the magnetic field of the coil because it acts as a core of the inductor.
When photons with a wavelength of 310. nm strike a magnesium plate, the maximum velocity of the ejected electrons is 3.45 105 m/s. calculate the binding energy of electrons to the magnesium surface?
The binding energy of electrons to the magnesium surface can be calculated using the equation KE = hf - BE, where KE is the kinetic energy of the ejected electrons, hf is the energy of the incident photons, and BE is the binding energy. Given that the maximum velocity of the ejected electrons is 3.45 × 10^5 m/s, we can calculate the kinetic energy using the equation KE = (1/2)mv^2. Using the given wavelength of the photons (310 nm), we can calculate the energy of the photons using the equation E = hc/λ, where h is Planck's constant (6.63 × 10^-34 J.s), c is the speed of light (3.00 × 10^8 m/s), and λ is the wavelength in meters. By rearranging the equation to solve for the binding energy, we find that the binding energy is equal to the energy of the incident photons minus the kinetic energy of the ejected electron.
Explanation:The binding energy of electrons to the magnesium surface can be calculated using the equation KE = hf - BE, where KE is the kinetic energy of the ejected electrons, hf is the energy of the incident photons, and BE is the binding energy. Given that the maximum velocity of the ejected electrons is 3.45 × 10^5 m/s, we can calculate the kinetic energy using the equation KE = (1/2)mv^2.
Using the given wavelength of the photons (310 nm), we can calculate the energy of the photons using the equation E = hc/λ, where h is Planck's constant (6.63 × 10^-34 J.s), c is the speed of light (3.00 × 10^8 m/s), and λ is the wavelength in meters.
By rearranging the equation to solve for the binding energy, we find that the binding energy is equal to the energy of the incident photons minus the kinetic energy of the ejected electrons.
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The binding energy of electrons to the magnesium surface is calculated to be approximately 0.62 eV.
To determine the binding energy of electrons ejected from a magnesium plate by photons with a wavelength of 310 nm, we use the photoelectric effect equation:
Binding Energy (Eb) = Energy of Photon (E(photon)) - Kinetic Energy (Ke)Calculate the energy of the photon (E(photon)):
E(photon) = hc/λGiven:
h = 6.626 × 10⁻³⁴ J·s (Planck's constant)Convert the photon energy from joules to electron volts (eV):
Since 1 eV = 1.602 × 10⁻¹⁹ J, E(photon) ≈ 6.41 × 10⁻¹⁹ J / 1.602 × 10⁻¹⁹ J/eV E(photon)≈ 4.00 eVCalculate the kinetic energy (Ke) of the ejected electrons:
Ke = 0.5 * m * v₂m = 9.11 × 10⁻³¹ kg (mass of electron)Convert the kinetic energy into electron volts (eV):
Ke ≈ 5.42 × 10⁻¹⁹ J / 1.602 × 10⁻¹⁹ J/eV Ke≈ 3.38 eVCalculate the binding energy (Eb):
Binding Energy (Eb) = E(photon) - KeEb ≈ 4.00 eV - 3.38 eV Eb≈ 0.62 eVTherefore, the binding energy of electrons to the magnesium surface is approximately 0.62 eV.
A bird flew16 km west in 5 hours, then flew 20 km east in 6 hours. what was the birdâs velocity?
To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.
speed = distance/time
Which moon of uranus has the greatest variety of landforms of any body yet examined?
Miranda is the right answer
A dog has a mass of 12 kg. What is its weight? Round your answer to the nearest whole number. The dog weighs ___ N.
A 1400 kg car is approaching the hill shown in (Figure 1) at 11 m/s when it suddenly runs out of gas. Neglect any friction.
The car, running out of gas and hence momentum, will convert its initial kinetic energy into gravitational potential energy as it moves uphill. In the absence of friction, it will ascend approximately 6.27 meters up the hill before it stops.
Explanation:The subject of the question is related to physics, particularly to the principle of conservation of energy. When the car runs out of gas, its initial kinetic energy is converted into potential energy as it goes uphill. The initial kinetic energy of the car is given by 1/2*m*v^2 kg (where m is the mass and v is the velocity of the car) which equals 1/2*1400*11^2 = 85,800 Joules.
The car will continue to move up the hill until all this kinetic energy is converted into gravitational potential energy, given by m*g*h = 1400*9.8*h, where g is the acceleration due to gravity and h is the height the car reaches up the hill. Setting these two equations equal allows us to determine how high the car will go: 85,800 = 1400*9.8*h, which gives h = 85,800/(1400*9.8) = 6.27 meters. Therefore, in the absence of friction, the car will move approximately 6.27 meters up the hill before coming to a stop.
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The car can climb a hill approximately 6.17 meters in height before coming to a complete stop due to its kinetic energy. This is calculated using the principles of energy conservation and the formulas for kinetic and potential energy.
Explanation:This physicist question is about the concept of conservation of energy. The 1400 kg car runs out of gas, but it maintains its kinetic energy. This kinetic energy will then be converted into potential energy as the car climbs the hill. The calculation of how high the car will climb can be done using the formula for kinetic energy, which is 0.5*m*v2, and the formula for gravitational potential energy, m*g*h.
First, we determine the initial kinetic energy of the car, which comes out to be 0.5*1400 kg*(11 m/s)2 = 85,250 Joules. This will be equal to the potential energy at the peak of the hill; thus, we have the equation 1400 kg*9.8 m/s2*h = 85,250 Joules, so solving for height, we find h = 85,250/ (1400*9.8) = approximately 6.17 meters. So, the car should be able to climb a hill of approximately 6.17 meters before it comes to a stop.
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Which formula can be used to find the tangential speed of an orbiting object?
Answer:
The answer on ED is A
Explanation:
A tennis ball traveling horizontally at 22.0 m/s suddenly hits a vertical brick wall and bounces back with a horizontal velocity of 18.0 m/s
Part A: Make a free-body diagram of this ball just before it hits the wall.
The only force acting on the ball is the pull of the Earth, this is its weight; so the diagram is a vertical vector downwards.
Part B: Make a free-body diagram of this ball just after it has bounced free of
the wall.
Again, the only force acting on the ball is the pull of the Earth, its weight, and the free-body diagram is identical to that of the part A.
Part C: Make a free-body diagram of this ball while it is in contact with the
wall.
Slow pain originating from an internal organ is often perceived as coming from an area of the body totally unrelated to the source. this is known as
Calculate the buoyant force due to the surrounding air on a man weighing 700 n . assume his average density is the same as that of water. suppose that the density of air is 1.20 kg/m3. express your answer to two significant figures and include the appropriate units.
Buoyant force due to the surrounding air on a man is 0.84 Newton
[tex]\texttt{ }[/tex]
Further explanationThe basic formula of pressure that needs to be recalled is:
Pressure = Force / Cross-sectional Area
or symbolized:
[tex]\large {\boxed {P = F \div A} }[/tex]
P = Pressure (Pa)
F = Force (N)
A = Cross-sectional Area (m²)
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
Density of Air = ρ_air = 1.20 kg/m³
Weight of the man = w = 700 N
Density of the man = ρ = 1000 kg/m³
Asked:
Buoyant Force = F = ?
Solution:
We will use Archimedes' principle to solve the problem as follows:
[tex]F = \rho_{air} g V[/tex]
[tex]F = \rho_{air} g \frac{m}{\rho}[/tex]
[tex]F = \rho_{air} g \frac{w}{g\rho}[/tex]
[tex]F = \rho_{air} \frac{w}{\rho}[/tex]
[tex]F = 1.20 \times \frac{700}{1000}[/tex]
[tex]F = 0.84 \texttt{ Newton}[/tex]
[tex]\texttt{ }[/tex]
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Answer detailsGrade: High School
Subject: Physics
Chapter: Pressure
[tex]\texttt{ }[/tex]
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure
The buoyant force due to the surrounding air on a man weighing 700 N is approximately 0.84 N. The ratio of the buoyant force to his weight is approximately 0.00120, which shows the buoyancy effect in air is minimal compared to his weight.
Explanation:To calculate the buoyant force due to the surrounding air on a man weighing 700 N (equivalent to a mass of approximately 71.4 kg assuming g = 9.81 m/s2), we can use Archimedes' principle. This principle states that the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. Since the man's average density is the same as that of water (about 1000 kg/m3), his volume V can be calculated using the formula:
V = mass / density = 71.4 kg / 1000 kg/m3 = 0.0714 m3.
The buoyant force (Fb) in air can then be calculated with the density of air (1.20 kg/m3):
Fb = density of air × volume × g = 1.20 kg/m3 × 0.0714 m3 × 9.81 m/s2 ≈ 0.841 N.
Therefore, the buoyant force is approximately 0.84 N.
To find the ratio of the buoyant force to the man's weight, we divide the buoyant force by the weight:
Ratio = Fb / weight = 0.841 N / 700 N ≈ 0.00120.
So, the ratio of the buoyant force to the man's weight is approximately 0.00120, which implies the effect of buoyancy in air is quite small compared to the weight of the man.
The inner planets—mercury, venus, earth, and mars—are believed to have been formed by _____. answers
Answer: These planets are formed by rocks.
Explanation:
There are 2 types of planets in Our Solar System:
1. Inner planets: There are 4 planets which are considered as inner planets, these are Mercury, Venus, Earth and Mars. These planets are small and have rocky surface. Their time of revolution around the Sun is less than the outer ones. These planets have maximum number of moon till 2.
2. Outer planets: There are 4 planets which are considered as outer planets, these are Jupiter, Saturn, Uranus and Neptune. These planets are large and gaseous planets. Their time of revolution around the Sun is more than the inner ones. These planets have many moon.
Hence, the inner planets are believed to be formed of rocks.
The cold protective response may be activated when a person's face is submerged in water that is less than ________ degrees fahrenheit.
If the distance between two asteroids is doubled, the gravitational force they exert on each other will.
The gravitational force the asteroids exert on each other will be one fourth of their initial force.
What is gravitational force?Any two bodies will be attracted to one another by the force of gravity, also known as gravity. There is an attraction between every thing in the cosmos, but most of the time it is too faint to be noticed due to the extreme distance between the objects. Furthermore, although the influence of gravity is weaker as objects are moved away, its range is infinite.
We know that, gravitational force acting between two bodies,
F=[tex]\frac{ G m_1 m_2}{r^2}[/tex]
Where, G = universal gravitational constant
m₁ and m₂ are masses of the two bodies and r is distance between them.
Let, the masses of the two asteroids are M₁ and M₂ and initial distance between them is R.
Hence, gravitational force they exert on each other, F₁ =[tex]\frac{ G M_1 M_2}{R^2}[/tex]
Now, when the distance between two asteroids is doubled, that is 2R, the gravitational force they exert on each other will, F₂ = [tex]\frac{ G M_1 M_2}{(2R)^2}[/tex] = [tex]\frac{1}{4}[/tex] [tex]\frac{ G M_1 M_2}{R^2}[/tex] = [tex]\frac{1}{4}[/tex] F₁
Hence, the final gravitational force is one-fourth of the initial one.
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Visit this website and locate the element mercury, whose chemical symbol is Hg. Click on the square to read about the history, properties, and uses of mercury. Name three uses for mercury.
Answer: Mercury is used for making thermometers, barometers, diffusion pumps, and other laboratory instruments. It can also be used to make mercury-vapor lamps, advertising signs, and mercury switches as well as pesticides, dental preparations, batteries, and catalysts.
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Explain how the bonds between water molecules affect its properties
"The White Shark" allows riders to start from rest on a tube and then slide down a 44 meter slide. It takes the rider 6.2 seconds to reach the bottom. What is the average acceleration of the ride?
A. 2.3 m/s^2 B. 3.4 m/s^2 C. 4.2 m/s^2 D. 5.0 m/s^2
I did (44 - 0)/6.2 but that's not any of the answers??
By what factor must the sound intensity be increased to increase the sound intensity level by 12.5 db ?
If your vehicle bounces a lot after a bump or is hard to control on turns, you may have a problem with __________ system.
whats an example of flexible thinking?
(02.01)triangle xyz slides 2 units left and 1 unit down on the coordinate plane. if the original measure of angle x was 40 degrees, what is the measure of angle x'?
Let us say that triangle XYZ has sides of XY, YZ, and ZX.
Each of the corners X, Y, and Z are located at their own (x, y) points.
If all of the triangle are transformed through translation by a movement of 2 units left and 1 unit down on the coordinate plane then we generate a triangle X’Y’Z’.
Then each of the corners X’, Y’ and Z’ are now located at (x – 2, y – 1) coordinates.
Since all of the corners were moved then we can also say that:
XY is congruent to X’Y’
YZ is congruent to Y’Z’
ZX is congruent to Z’X’
Since all sides are congruent, therefore all angles are also congruent.
Therefore the measure of angle x’ is equal to the measure of angle x.
Answer:
40 degrees
Which is the best example of Newton's Second Law of Motion?
A student has on roller skates and he decides to push against the railing. He immediately begins to roll backwards.
A small, lightweight ball and a large, heavy ball are dropped off of a roof. They both strike the ground at the same time.
A baseball player hits a baseball that is pitched to him. The ball immediately soars back in the direction of the pitcher.
You are riding in a car that makes a quick right turn. You immediately slide across the back seat.
The baseball player hitting a baseball is the best example of Newton's Second Law of Motion, as the force exerted on the ball causes it to move in the opposite direction with the same magnitude.
Explanation:The best example of Newton's Second Law of Motion is the baseball player hitting a baseball that is pitched to him. When the player hits the ball, the force exerted on the ball causes it to move in the opposite direction with the same magnitude. This is known as the law of action and reaction, which is a part of Newton's Second Law of Motion.
Another example of Newton's Second Law is a student on roller skates pushing against a railing and immediately rolling backwards. The force exerted by the student on the railing causes an equal but opposite force on the student, resulting in the backward motion.
Lastly, the example of a car making a quick right turn and the passenger sliding across the back seat can be considered an example of Newton's Second Law. The passenger tends to continue moving in a straight line due to inertia but is pushed to the side due to the force of the car turning.
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Calculate number of photons from energy and wavelength
Can something have energy without having momentum? explain. can something have momentum without having energy? defend your answer
A motorboat approaches you head-on and sounds one short blast. how do you signal that you agree to let it pass on your port (left) side?
How to separate sand and finely ground polystyrene foam?
How much heat energy is required to raise the temperature of 5 kilograms of coal from 20°C to 220°C? A. 314 J B. 6,573 J C. 1,314,718 J D. 4,187,000 J
Answer:
C. 1,314,718 J
Explanation:
The heat energy needed to raise the temperature of the coal is given by:
[tex]Q=m C_s \Delta T[/tex]
where:
m = 5 kg is the mass of the coal
[tex]C_s = 1314 J/kg ^{\circ}C[/tex] is the specific heat of coal
[tex]\Delta T= 220^{\circ}C-20^{\circ}C=200^{\circ}C[/tex] is the increase in temperature
Substituting into the formula, we find
[tex]Q=(5 kg)(1314 J/kg ^{\circ}C )(200^{\circ}C)=1,314,000 J[/tex]
So, the closest option is
C. 1,314,718 J
Why does helium exhibit more visible emission lines than hydrogen?
The helium atom exhibit more visible emission lines than hydrogen atom as hydrogen has one electron per atom, while helium atom has two electrons per atom.
What are emission lines?
Emission lines are generally used to determine the atoms and the molecules.
A emission line is formed when a electron falls behind the low-level state of energy by freeing a photon.
Difference between the helium visible emission lines and hydrogen visible emission lines-
Main difference between the helium visible emission lines and hydrogen visible emission lines, that the helium visible emission exhibit more lines.These emission lines are the formations of wavelength of electromagnetic radiation, emitted by the helium and hydrogen atom.This is because hydrogen has one electron per atom, while helium atom has two electrons per atom.Hence, the helium atom exhibit more visible emission lines than hydrogen atom as hydrogen has one electron per atom, while helium atom has two electrons per atom.
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Helium exhibits more visible emission lines than hydrogen due to its complex electron energy level structure. As helium has two electrons and more possible transitions, it results in more visible lines in its emission spectrum compared to hydrogen.
Explanation:Helium exhibits more visible emission lines than hydrogen due to the complexity of its electron energy level structure. When energy is absorbed by an atom, electrons get excited and move to higher orbitals. When these electrons transition back to lower energy levels, they emit energy in the form of light at specific frequencies, which are visible as emission lines in an emission spectrum.
For Hydrogen, in its ground state, no electrons are in the higher-energy levels required to produce either emission or absorption lines in the visible part of the Balmer series, therefore, the spectral features of hydrogen in the visible range are limited primarily to the Balmer line that only excited hydrogen atoms produce.
Helium, on the other hand, has two electrons in different energy levels. As such, there are more possible transitions and hence more lines visible in its emission spectrum.
This concept is fundamental to our understanding of interstellar mediums and the chemical composition of celestial bodies. Recognizing the unique spectral features in visible light allows us to decode the mysteries of the universe.
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