1. What is the weight of this objects?
Weight is simply the product of mass and gravitational acceleration. Therefore the weight is:
w = 20 kg * 9.81 m/s^2
w = 196.2 kg m/s^2 = 196.2 N
2. After 5 seconds, how has the object fallen and what is its speed at this instant?
We can use the formula:
y = v0 t + 0.5 g t^2
v = v0 + g t
where v0 = 0 since the object starts from rest, y is the distance it fell, t is time
y = 0 + 0.5 * 9.81 * 5^2 = 122.625 m
v = 0 + 9.81 * 5 = 49.05 m/s
What is another name for the introitus? psych 230?
The introitus, or vaginal opening, is the external entrance to the vagina in the female reproductive system.
The term "introitus" specifically refers to an opening or entrance into a canal or cavity of the body. In the context of human anatomy, particularly in discussions of human sexuality and reproduction, another name for the «introitus» is the vaginal opening. This is the external opening to the vagina, which is part of the female reproductive system.
A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the same spot and travels in a circle, the work the seat performs on her in one complete rotation is
In a circular motion with constant speed, such as a child on a merry-go-round, the work done over one complete rotation is zero, as there is no change in kinetic energy.
Explanation:The question is regarding the concept of work done in a circular motion in the context of a merry-go-round. In the system described, the child has a constant speed on the circular path which indicates that the net work done by the forces acting on the child, including the seat, over a complete round of the merry-go-round is zero. This is consistent with the fact that work done is change in kinetic energy and since the child's speed is constant, there is no change in kinetic energy.
The child's inertia plays a role in maintaining her circular path but it does not contribute to work done, as it is a quantity of mass' resistance to change in motion and does not imply a force.
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A spelunker is surveying a cave. she follows a passage 170 m straight west, then 250 m in a direction 45â east of south, and then 280 m at 30â east of north. after a fourth unmeasured displacement, she finds herself back where she started.
A primitive air-conditioning unit for the use in places where electrical power is unavailable can be made by hanging up strips of linen soaked in water. the evaporation of the water cools the air. calculate the heat required to evaporate 5.00 l of water at 0c
Final answer:
The heat required to evaporate 5.00 liters of water at 0°C is 11300 kJ, calculated by multiplying the mass of the water (5.00 kg) by the heat of vaporization (2260 kJ/kg).
Explanation:
The student is asking about the heat required to evaporate 5.00 liters of water at 0°C. This is a question related to thermochemistry, specifically the heat of vaporization of water. The heat of vaporization is the amount of energy required for liquid water to turn into water vapor. To calculate the heat required, we use the formula:
Q = m × hv
where Q is the heat required, m is the mass of water, and hv is the heat of vaporization. The heat of vaporization for water is approximately 2260 kJ/kg at 0°C.
First, we convert 5.00 liters to kilograms as the density of water is about 1 kg/L, which makes the mass 5.00 kg. Then we calculate the heat required:
Q = 5.00 kg × 2260 kJ/kg = 11300 kJ
Therefore, the heat required to evaporate 5.00 liters of water at 0°C is 11300 kJ.
What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 500 nm ? the index of refraction of the film is 1.32, and there is air on both sides of the film?
According to Plato what is the highest principle in reality
If your front lawn is 17.0 feet wide and 20.0 feet long,and each square foot of lawn accumulates 1050 new snow flakes every minute, how much snow in kilograms accumulates on your lawn per hour? assume an average snow flake has a mass of 1.90mg.
A 1100kg car pulls a boat on a trailer. (a) what total force resists the motion of the car, boat,and trailer, if the car exerts a 1900n force on the road and produces an acceleration of 0.550 m/s2? the mass of the boat plus trailer trailer is 700kg. (b) what is the force in the hitch betweenthe car and the trailer if 80% of the resisting forces are experienced by the boat and trailer?
What radius should the satellite move at in its orbit? (measured frrom the center of mars.)?
To determine the radius at which a satellite should move in its orbit around Mars, you can use Newton's Law of Universal Gravitation and the centripetal force equation. By setting the gravitational force equal to the centripetal force, you can solve for the radius of the orbit.
Explanation:The radius at which a satellite should move in its orbit around Mars can be determined using Newton's Law of Universal Gravitation and the centripetal force equation. The centripetal force required for the satellite to stay in orbit is provided by the gravitational force between the satellite and Mars. To find the radius, you can set the gravitational force equal to the centripetal force and solve for the radius.
Step-by-step:
Identify the known quantities: the mass of Mars (M), the radius of Mars (r), and the period of the satellite's orbit (T).Use the centripetal force equation: Fc = (mv2)/r, where Fc is the centripetal force, m is the mass of the satellite, v is the satellite's velocity, and r is the radius of the orbit.Use Newton's Law of Universal Gravitation: Fg = (GMm)/r2, where Fg is the gravitational force between the satellite and Mars, G is the gravitational constant, and M is the mass of Mars.Set the centripetal force equal to the gravitational force: (mv2)/r = (GMm)/r2.Cancel out the common factors: v2/r = (GM)/r2.Solve for r: v2 = GM/r.Substitute the known values and solve for r: r = (GM/v2).Learn more about Satellite orbit around Mars here:https://brainly.com/question/33396540
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Jennifer works for an automaker and tests the safety performance of cars. She watches a 2,000-kilogram car crash into a wall with a force of 30,000 newtons. What’s the acceleration of the car at impact? Use .
Answer:
15 meters/second^2
Explanation:
I got this question on a test and this was the right answer
The position function x(t) of a particle moving along an x axis is x 4.0 6.0t 2 , with x in meters and t in seconds. (a) at what time and (b) where does the particle (momentarily) stop? at what (c) negative time and (d) positive time does the particle pass through the origin?
The particle crosses the origin at t = 2.0 seconds, and the displacement from t = 3.0 s to t = 6.0 s is -6 meters.
The position function of a particle moving along an x-axis is described as x(t) = 4.0 - 2.0t meters. To determine (a) when the particle crosses the origin, we set the position function equal to zero (x(t) = 0) and solve for t, which gives us t = 2.0 seconds. For part (b), the displacement of the particle between t = 3.0 s and t = 6.0 s is calculated by finding the difference in position at these two times: x(6.0) - x(3.0), which results in a displacement of -6 meters.
If you drop a ball, and then one second later drop a ball identical in mass, size and shape, what happens to the distance between them as they fall?
Final answer:
As two identical balls are dropped with a one-second interval, the distance between them increases because the first ball accelerates for a longer time and achieves a higher velocity than the second ball at the instant it is dropped.
Explanation:
The question involves the concepts of gravity and acceleration as related to two identical falling objects. When a ball is dropped and then a second identical ball is dropped one second later, the distance between them increases as they fall. This is because the first ball has already been accelerating due to gravity for one second longer than the second ball, and thus it has a higher velocity at the moment the second ball is released. Therefore, the first ball continues to pull away from the second ball as they both fall towards the Earth.
Wich element is likely to be the most reactive
Answer:
Fluorine
Explanation:
Fluorine is the most reactive and most electronegative element in the periodic table. It can react with glass so it is impossible to find fluorine in its pure form. It exists in gaseous form even at room temperature and it is the most oxidizing agent. It is a non metal, in metals cesium is the most reactive.
The element that is likely to be the most reactive is hydrogen. The correct option is A.
The most reactive element of the ones listed is probably hydrogen (H). It is extremely reactive due to the fact that its outermost shell contains just one electron.
Oxygen, halogens, and metals are just a few of the substances that hydrogen can interact with quickly.
Covalent bonds can be formed with nonmetals like oxygen, resulting in substances like water. In redox reactions, such as the synthesis of acids and bases, hydrogen also takes part.
Its low atomic mass, which permits quicker diffusion and more frequent collisions with other atoms, further increases its reactivity.
Overall, the electrical structure of hydrogen and its capacity to create stable bonds with other elements are what cause it to be so reactive.
Thus, the correct option is A.
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Your question seems incomplete, the probable complete question is:
Which of the following elements is likely to be the most reactive?
A) Hydrogen (H)
B) Oxygen (O)
C) Neon (Ne)
D) Argon (Ar)
"what shape are the pebble-sized particles that make up the rock?"
What is the volume of a rock with a density of 3.00 g/cm3 and a mass of 600g?
Which of the following buildings would be least likely to be damage after a very large earthquake
Soft-story buildings are least likely to withstand large earthquakes compared to well-designed structures that comply with modern building codes. Building codes are meant to reduce damage through various levels of seismic activity, but they only apply to new or significantly renovated structures. The type of ground and construction materials also significantly impacts a building's earthquake resilience.
Among various building types, soft-story buildings are least likely to withstand a very large earthquake due to their vulnerability to horizontal forces. Such structures, which include two- or three-car garages with a living space above, can fail catastrophically during an earthquake because of less bracing in the open areas compared to standard walls. In contrast, well-designed buildings that adhere to modern building codes and consider earthquake resilience are more likely to sustain only minor damage, even during severe shaking. Understanding building performance during earthquakes is essential, especially in regions where adherence to building codes might be poor and materials used might be inadequate, leading to increased structural vulnerability.
Building codes play a crucial role in dictating how well a structure can survive an earthquake. The codes are designed to ensure that buildings resist minor ground motion without damage, moderate shaking without structural damage, and major motion with an intensity equivalent to the region's maximum considered earthquake without collapse, despite possible structural damage. However, the effectiveness of these codes is limited to new constructions or major renovations. Buildings built before the establishment of stringent earthquake-related standards, such as old unreinforced masonry buildings or non-ductile reinforced concrete frames, tend to suffer the most damage. Moreover, buildings constructed on unconsolidated sediments are likely to experience more severe earthquake damage than those on solid rock due to the amplification of seismic waves. In addition to the type of ground, the materials and construction methods used also determine a building's seismic performance. Brittle structures like unreinforced masonry and nonductile concrete frames perform poorly during earthquakes due to their susceptibility to sheer and collapse.
A laser pulse with wavelength 520 nm contains 4.40 mj of energy. how many photons are in the laser pulse?
To calculate the number of photons in a laser pulse, use the formula energy per photon = Planck's constant x speed of light / wavelength. Plugging in the values and dividing the total energy by the energy per photon, we find that the laser pulse contains approximately 2.65 x 10^19 photons.
Explanation:To calculate the number of photons in a laser pulse, we can use the formula:
energy per photon = Planck's constant x speed of light / wavelength
In this case, the energy per photon is 4.40 mJ = 4.40 x 10-3 J, the wavelength is 520 nm = 520 x 10-9 m, Planck's constant is 6.63 x 10-34 J·s, and the speed of light is 3.00 x 108 m/s. Plugging these values into the formula, we can find the energy per photon. Then, we can divide the total energy of the laser pulse (4.40 mJ) by the energy per photon to calculate the number of photons in the pulse.
The number of photons in the laser pulse is approximately 2.65 x 1019 photons.
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What is the setting of the story in "the pedestrian"?
a.a space station orbiting mars
b.a deserted neighborhood street
c.a lonely road in the countryside
d.a large metropolis?
Answer:
b.a deserted neighborhood street
Explanation:
ap3x
The setting of the story in "the pedestrian" is a large metropolis. The correct option is D.
"The Pedestrian" is a short story by Ray Bradbury that was first published in 1951. The story is set in the future in the year 2053 in a large metropolis where people spend their evenings indoors watching television or communicating through advanced technology.
The main character, Leonard Mead, is an exception to this pattern. He enjoys taking long walks through the city streets at night, something that is seen as strange and suspicious by the society around him. One evening, he is stopped by a police car and questioned about his activities. The police officers are suspicious of him and don't understand why he would want to walk when he could stay inside and be entertained.
After a brief conversation, the police let Leonard go and he continues his walk. However, he soon realizes that he is the only person outside in the entire city. He reflects on the society he lives in and how it has become so obsessed with technology that people have lost the ability to appreciate the simple pleasures of life. As he continues his walk, he is suddenly surrounded by a bright light and taken away by the police, who see his activities as a threat to society.
The story is a critique of the growing influence of technology and its impact on human interaction and personal freedoms. It highlights the danger of becoming too dependent on technology and losing sight of the things that truly make life worth living.
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A Federation starship (8.5 ✕ 106 kg) uses its tractor beam to pull a shuttlecraft (1.0 ✕ 104 kg) aboard from a distance of 14 km away. The tractor beam exerts a constant force of 4.0 ✕104 N on the shuttlecraft. Both spacecraft are initially at rest. How far does the starship move as it pulls the shuttlecraft aboard?
By applying conservation of momentum and kinematic equations, we find the distance the starship moves as a result of exerting a force on the shuttlecraft via a tractor beam. The steps involve calculating the acceleration of the shuttlecraft, determining the time to cover the initial distance, and then using the momentum relation to find the velocity and distance moved by the starship.
Explanation:The question involves applying the concept of conservation of momentum to find out how far the starship moves as it pulls a shuttlecraft on board. Since both spacecraft are initially at rest and the force is exerted for the same amount of time on both, their momenta are equal and opposite. We can set up the equation based on conservation of momentum:
m1⋅v1 = m2⋅v2
Where m1 and v1 are the mass and velocity of the starship, and m2 and v2 are the mass and velocity of the shuttlecraft, respectively. Because the tractor beam exerts a constant force, we can calculate the acceleration of the shuttlecraft (a = F/m), and then using the kinematic equation, determine the time (t) it takes for the shuttle to cover the distance:
s = 0.5⋅a⋅t^2
With t known, we can calculate the velocity of the shuttlecraft (v2) at the moment it reaches the starship:
v2 = a⋅t
Using the velocities and rearranging the conservation of momentum equation, we find:
m1⋅v1 = m2⋅(a⋅t)
Finally, we solve for the distance the starship moves (d1) using the velocity we found for v1, and the time:
d1 = 0.5⋅(v1⋅t)
This provides the answer to how far the starship moves as a result of pulling in the shuttlecraft with its tractor beam.
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A machine has an efficiency of 80%. How much work must be done on the machine so to make it do 50,000 J of output work?
Answer:
62,500 Joules
Explanation:
A 2300 kg truck has put its front bumper against the rear bumper of a 2500 kg suv to give it a push. with the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 n.
Answer:
Acceleration = a = 3.75 m/s^2
Explanation:
Mass of truck1 = m1 = 2300 kg
Mass of truck2 = m2 = 2500 kg
Total mass = m = m1 + m2 = 2300 + 2500 = 4800 kg
Force exerted by truck1 = F = 18000 N
As both trucks are joint together so, behaving as single object. The acceleration can be found by Newton’s second law of motion.
F = ma
a = F/m = 18000/4800
a = 3.75 m/s^2
True or False A scientific theory generally is accepted as false until it is proved?
walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity?
If walt ran 5 kilometers in 25 minutes, going eastward. His average velocity is: 0.2 kilometers per minute.
What is the average velocity?
To determine Walt's average velocity divide the distance traveled by the time it took him.
We can use the formula:
Average velocity = Distance / Time
Plugging in the values:
Average velocity = 5 kilometers / 25 minutes
Average velocity = 0.2 kilometers per minute
Therefore Walt's average velocity is 0.2 kilometers per minute, meaning that he was running at a speed of 0.2 kilometers every minute in the eastward direction.
Explain the relationship between resistance and the velocity of shortening.
What is meant by the terms composition and structure when referring to matter?
The expression CaCO3 → CaO + CO2 is an example of a reactant. product. chemical equation. chemical progression.
By definition, the expression CaCO₃ → CaO + CO₂ is an example of a chemical equation.
Definition of chemical reactionA chemical reaction is any process in which at least the atoms, molecules, or ions of one substance are changed into atoms, molecules, or ions of another chemical substance.
Definition of chemical equationA chemical equation is a symbolic description used to describe the identities and relative quantities of the reactants and products involved in a chemical reaction.
The information contained in the chemical equation allows us to determine the substances that are transformed or modified in a reaction, called reactants or reagents, and the new substances that originate in a chemical reaction, called products.
In order to represent what happens in a chemical reaction by means of an equation, it must comply with the Law of conservation of matter and with the Law of conservation of energy. That is, the equation must indicate that the number of atoms of the reactants and products is equal on both sides of the reaction and that the charges are also equal. In other words, you must have a balanced equation.
SummaryFinally, the expression CaCO₃ → CaO + CO₂ is an example of a chemical equation.
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Answer:
chemical equation
Explanation:
Describing Chemical Reactions quiz on edg
6 A small rock is thrown vertically upward with a speed of 14.0 m/s from the edge of the roof of a 30.0 m tall building. The rock doesn't hit the building on its way back down and lands in the street below. Air resistance can be neglected.
A)What is the speed of the rock just before it hits the street?
B)How much time elapses from when the rock is thrown until it hits the street?
The gas tank of a certain luxury automobile holds 22.3 gallons according to the owner’s manual. if the density of gasoline is 0.8206 g/ml, determine the mass in kilograms and pounds of the fuel in a full tank.
The mass of the fuel in the tank can be calculated by multiplying the volume in full tank to the density of the gasoline. First convert 22.3 gallons to ml by multiplying it with 3785.412 since the conversion factor is 1 gallon= 3785.412 ml. Then multiply the volume with the density. Since the density is in g/ml, you would get a value in grams so convert it to kg by dividing it with 1000. The convert the value in kg to lb multiply the value by 2.2. The values are 69.27 kg and 152.72 lb.
The mass of the fuel in a full 22.3-gallon tank of gasoline, given a density of 0.8206 g/mL, is approximately 69.211 kg or 152.497 lb.
Explanation:To determine the mass of the fuel in a full tank, you first need to convert the volume from gallons to milliliters (mL), since the density of gasoline is given in grams per mL.
One gallon is approximately 3785.41 mL. Therefore, a 22.3-gallon tank would hold 22.3 * 3785.41 = 84392.263 mL of fuel.
The mass of the fuel can then be calculated using the formula density = mass/volume. Rearranging the formula gives mass = density * volume. By subbing in the values, we get mass = 0.8206 g/mL * 84392.263 mL = 69211.294528 g.
To convert the mass to kilograms, we divide by 1000 (since there are 1,000 grams in a kilo). This gives us approximately 69.211 kg.
To convert the mass to pounds, we multiply by 2.20462 (since there are 2.20462 pounds in a kilo). This gives us approximately 152.497 lb.
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Does the force of kinetic friction depend on the weight of the block? explain.
The force of kinetic friction is determined by surface properties and the normal force, not the weight of the object. Thus, objects with different weights experience the same kinetic friction on the same surface.
The force of kinetic friction does not depend on the weight of the block. Kinetic friction is the force that opposes the relative motion of two surfaces in contact when they are sliding past each other. It is determined by the nature of the surfaces and the normal force, which is the force exerted by a surface to support the weight of an object resting on it.
The weight of an object (or the force of gravity acting on it) affects the normal force, but it does not directly impact the coefficient of kinetic friction between the surfaces. The coefficient of kinetic friction remains constant for a given pair of materials, regardless of the weight of the object.
In simpler terms, if you have two objects made of the same material and they are sliding on the same surface, the force of kinetic friction will be the same for both objects, even if they have different weights. This is because the frictional force depends on the properties of the surfaces in contact, not the mass or weight of the objects involved.
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A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly.
In order to get the best results, the student should: